Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall.
Section 7.4
Trigonometric Identities
Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall.
Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall.
Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall.
Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall.
Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall.
tan
(a) Simplify by rewriting each trigonometric function in terms of sine and cosine functions.
sec
sin 1 cos
(b) Show that by multiplying the numerator and denominator by 1 cos
1+cos sin
θ
θ
θ θ
θ
θ θ
−
= −
sin
tan sin coscos(a) sin
1sec cos 1
cos
θ
θ θ θθ θ
θ θ
= = × =
( )
( ) ( )
sin 1 cossin
(b)
1 cos 1 cos 1 cos
θ θθ
θ θ θ
−
=
+ + −
( )
2
sin 1 cos
1 cos
θ θ
θ
−
=
−
( )
2
sin 1 cos
sin
θ θ
θ
−
=
1 cos
sin
θ
θ
−
=
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(a) Simplify
1
1− sinu
+
1
1+ sinu
by rewriting the expression over a common denominator.
(b) Simplify
1− cos2
v
sinv + cosvsinv
by factoring.
( )
( ) ( )
( )
( ) ( )
1 sin 1 sin
1 sin
1 1
(a)
1 sin 1 si sn 1 in
u u
uu u u
+ −
+ −
+
− + 2
1 sin 1 sin
1 sin
u u
u
+ + −
=
−
=
2
cos2
u
= 2sec2
u
( ) ( )
( )
2
1 cos 1 cos1 cos
(b)
sin cos sin sin 1 cos
v vv
v v v v v
+ −−
=
+ +
1 cos 1 cos
csc cot
sin sin sin
v v
v v
v v v
−
= = − = −
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Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall.
( )sin cot tan secθ θ θ θ+ =
( )
cos sin
sin cot tan sin
sin cos
θ θ
θ θ θ θ
θ θ
 
+ = + ÷
 
2 2 2
sin cos sin
cos
cos cos
θ θ θ
θ
θ θ
+
= + =
1
sec
cos
θ
θ
= =
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sin
csc cot
1 cos
θ
θ θ
θ
− =
+
1 cos
sin
θ
θ
−
=
1 cos
csc cot
sin sin
θ
θ θ
θ θ
− = −
( ) ( )
( )
1 cos 1 cos
sin 1 cos
θ θ
θ θ
− +
=
+ ( )
2
1 cos
sin 1 cos
θ
θ θ
−
=
+
( )
2
sin
sin 1 cos
θ
θ θ
=
+
sin
1 cos
θ
θ
=
+
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2
2
2
sin tan
tan
cos cot
θ θ
θ
θ θ
−
=
−
2
2
2
2
sin
sin
sin tan cos
coscos cot cos
sin
θ
θ
θ θ θ
θθ θ θ
θ
−
−
=
− −
2
2
sin cos sin
cos
sin cos cos
sin
θ θ θ
θ
θ θ θ
θ
−
=
−
2
2
sin cos sin sin
cos sin cos cos
θ θ θ θ
θ θ θ θ
−
= ×
−
( )
( )
2
2
sin sin cos 1
cos sin cos 1
θ θ θ
θ θ θ
−
=
−
2
2
2
sin
tan
cos
θ
θ
θ
= =
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cos 1 sin
1 sin cos
θ θ
θ θ
+
=
−
( )
( ) ( )
cos 1 sincos
1 sin 1 sin 1 sin
θ θθ
θ θ θ
+
=
− − +
( )
2
cos 1 sin
1 sin
θ θ
θ
+
=
−
( )
2
cos 1 sin
cos
θ θ
θ
+
=
1 sin
cos
θ
θ
+
=
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2 csc sin
cot
sin
θ θ
θ
θ
−
=
1
sin
csc sin sinsin
sin sin sin
θ
θ θ θθ
θ θ θ
 
− ÷−  
=  ÷ ÷
  ÷
 
2 2
2
2 2
1 sin cos
cot
sin sin
θ θ
θ
θ θ
−
= = =
Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall.
3 2
1 csc sin cosθ θ θ− =
3
3 sin
1 csc sin 1
sin
θ
θ θ
θ
− = −
2 2
1 sin cosθ θ= − =
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Section 7.4 trigonometric identities

  • 1.
    Copyright © 2012Pearson Education, Inc. Publishing as Prentice Hall. Section 7.4 Trigonometric Identities
  • 2.
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  • 3.
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  • 4.
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  • 5.
    Copyright © 2012Pearson Education, Inc. Publishing as Prentice Hall.
  • 6.
    Copyright © 2012Pearson Education, Inc. Publishing as Prentice Hall. tan (a) Simplify by rewriting each trigonometric function in terms of sine and cosine functions. sec sin 1 cos (b) Show that by multiplying the numerator and denominator by 1 cos 1+cos sin θ θ θ θ θ θ θ − = − sin tan sin coscos(a) sin 1sec cos 1 cos θ θ θ θθ θ θ θ = = × = ( ) ( ) ( ) sin 1 cossin (b) 1 cos 1 cos 1 cos θ θθ θ θ θ − = + + − ( ) 2 sin 1 cos 1 cos θ θ θ − = − ( ) 2 sin 1 cos sin θ θ θ − = 1 cos sin θ θ − =
  • 7.
    Copyright © 2012Pearson Education, Inc. Publishing as Prentice Hall. (a) Simplify 1 1− sinu + 1 1+ sinu by rewriting the expression over a common denominator. (b) Simplify 1− cos2 v sinv + cosvsinv by factoring. ( ) ( ) ( ) ( ) ( ) ( ) 1 sin 1 sin 1 sin 1 1 (a) 1 sin 1 si sn 1 in u u uu u u + − + − + − + 2 1 sin 1 sin 1 sin u u u + + − = − = 2 cos2 u = 2sec2 u ( ) ( ) ( ) 2 1 cos 1 cos1 cos (b) sin cos sin sin 1 cos v vv v v v v v + −− = + + 1 cos 1 cos csc cot sin sin sin v v v v v v v − = = − = −
  • 8.
    Copyright © 2012Pearson Education, Inc. Publishing as Prentice Hall.
  • 9.
    Copyright © 2012Pearson Education, Inc. Publishing as Prentice Hall. ( )sin cot tan secθ θ θ θ+ = ( ) cos sin sin cot tan sin sin cos θ θ θ θ θ θ θ θ   + = + ÷   2 2 2 sin cos sin cos cos cos θ θ θ θ θ θ + = + = 1 sec cos θ θ = =
  • 10.
    Copyright © 2012Pearson Education, Inc. Publishing as Prentice Hall. sin csc cot 1 cos θ θ θ θ − = + 1 cos sin θ θ − = 1 cos csc cot sin sin θ θ θ θ θ − = − ( ) ( ) ( ) 1 cos 1 cos sin 1 cos θ θ θ θ − + = + ( ) 2 1 cos sin 1 cos θ θ θ − = + ( ) 2 sin sin 1 cos θ θ θ = + sin 1 cos θ θ = +
  • 11.
    Copyright © 2012Pearson Education, Inc. Publishing as Prentice Hall. 2 2 2 sin tan tan cos cot θ θ θ θ θ − = − 2 2 2 2 sin sin sin tan cos coscos cot cos sin θ θ θ θ θ θθ θ θ θ − − = − − 2 2 sin cos sin cos sin cos cos sin θ θ θ θ θ θ θ θ − = − 2 2 sin cos sin sin cos sin cos cos θ θ θ θ θ θ θ θ − = × − ( ) ( ) 2 2 sin sin cos 1 cos sin cos 1 θ θ θ θ θ θ − = − 2 2 2 sin tan cos θ θ θ = =
  • 12.
    Copyright © 2012Pearson Education, Inc. Publishing as Prentice Hall. cos 1 sin 1 sin cos θ θ θ θ + = − ( ) ( ) ( ) cos 1 sincos 1 sin 1 sin 1 sin θ θθ θ θ θ + = − − + ( ) 2 cos 1 sin 1 sin θ θ θ + = − ( ) 2 cos 1 sin cos θ θ θ + = 1 sin cos θ θ + =
  • 13.
    Copyright © 2012Pearson Education, Inc. Publishing as Prentice Hall. 2 csc sin cot sin θ θ θ θ − = 1 sin csc sin sinsin sin sin sin θ θ θ θθ θ θ θ   − ÷−   =  ÷ ÷   ÷   2 2 2 2 2 1 sin cos cot sin sin θ θ θ θ θ − = = =
  • 14.
    Copyright © 2012Pearson Education, Inc. Publishing as Prentice Hall. 3 2 1 csc sin cosθ θ θ− = 3 3 sin 1 csc sin 1 sin θ θ θ θ − = − 2 2 1 sin cosθ θ= − =
  • 15.
    Copyright © 2012Pearson Education, Inc. Publishing as Prentice Hall.