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MATH 1220 Summary of Convergence Tests for Series
      ∞

Let   ∑a
      n=1
            n   be an infinite series of positive terms.
                ∞

The series      ∑a
                n=1
                      n   converges if and only if the sequence of partial sums,
                                                                                      ∞
S n = a1 + a 2 + a3 +  a n , converges. NOTE: lim S n = ∑a n
                                               n→∞
                                                                                     n=1



                                                                         ∞

Divergence Test: If n → ∞ an ≠ 0 , the series
                    lim                                                  ∑a    n   diverges.
                                                                         n=1

                                                                                            n                      1
                              ∞
                                        n                                          lim              = lim                   =1
Example: The series          ∑                      is divergent since             n→ ∞
                                                                                           n2 + 1       n→ ∞
                                                                                                                1+ 1
                             n =1   n +12
                                                                                                                       n2
This means that the terms of a convergent series must approach zero. That is, if ∑ n
                                                                                  a

converges, then lim an = 0. However, lim a n = 0 does not imply convergence.
                      n →∞                                        n →∞

Geometric Series: THIS is our model series A geometric series
a + ar + ar 2 +  + ar n −1 +  converges for − 1 < r < 1 .
             an +1                                                             a
Note: r =                  If the series converges, the sum of the series is      .
              an                                                             1 −r
                                                n
                               ∞
                                 7                         35        7
Example: The series          ∑5 8  converges with a = a1 = 8 and r = 8 . The sum of the
                             n=1   
series is 35.

Integral Test: If f is a continuous, positive, decreasing function on [1, ∞ with
                                                                           )
                                            ∞
 f ( n) = an , then the series          ∑a
                                        n=1
                                                    n   converges if and only if the improper integral
∞

∫ f ( x)dx converges.
1
                                                         ∞
Remainder for Integral Test: If                         ∑a
                                                        n=1
                                                                  n   converges by the Integral Test, then the
                                                              ∞

remainder after n terms satisfies Rn ≤∫ f ( x)dx
                                                              n



                              ∞
                                    1
p-series: The series         ∑n
                             n=1
                                    p       is convergent for p > 1 and diverges otherwise.
                               ∞                                                                    ∞
                                        1                                                               1
Examples: The series          ∑n
                              n=1
                                        1.001       is convergent but the series                ∑n
                                                                                                n=1
                                                                                                               is divergent.
∞                    ∞
Comparison Test: Suppose                       ∑a
                                                n=1
                                                       n   and   ∑b
                                                                 n=1
                                                                         n   are series with positive terms.
          ∞                                                                               ∞

(a) If   ∑b
          n=1
                   n   is convergent and an ≤ bn for all n, then
                                                                                    n=1
                                                                                       ∑a         n   converges.
           ∞                                                                       ∞

(b) If   ∑b
          n=1
                   n   is divergent and an ≥ bn for all n, then                    ∑a
                                                                                   n=1
                                                                                              n   diverges.
The Comparison Test requires that you make one of two comparisons:
   • Compare an unknown series to a LARGER known convergent series (smaller
      than convergent is convergent)
   • Compare an unknown series to a SMALLER known divergent series (bigger
      than divergent is divergent)
                       ∞             ∞       ∞
                               3n        3n      1
Examples:          ∑n
                   n =2
                               2
                                   > ∑ 2 = 3∑ which is a divergent harmonic series. Since the
                                − 2 n =2 n  n =2 n

original series is larger by comparison, it is divergent.
                  ∞               ∞
                       5n            5n 5 ∞ 1
We have         ∑ 2n 3 + n 2 + 1 n=1 2n 2 n=1 n
                n =1
                                < ∑ 3 = ∑ 2 which is a convergent p-series. Since the

original series is smaller by comparison, it is convergent.
                                                           ∞                 ∞

Limit Comparison Test: Suppose                             ∑a
                                                           n=1
                                                                 n   and     ∑b
                                                                             n=1
                                                                                    n     are series with positive terms. If
     an
lim     = c where 0 < c < ∞ , then either both series converge or both series diverge.
n →∞ b
      n
(Useful for p-series)
Rule of Thumb: To obtain a series for comparison, omit lower order terms in the
numerator and the denominator and then simplify.
                                                                                   ∞                  ∞
                                          ∞                                                   n              1
Examples: For the series ∑ 2
                                  n
                         n =1 n + n + 3
                                        , compare to                               ∑n         2
                                                                                                  =∑             3       which is a
                                                                                   n =1               n =1   n       2

convergent p-series.
                   πn + n
                                                                                          n
                           ∞              ∞
                                              πn    ∞
                                                        π 
For the series ∑ n        2 , compare to ∑ n
                                                 = ∑  which is a divergent geometric
               n =1 3 + n                n =1 3    n =1  3 

series.
Alternating Series Test: If the alternating series
 ∞

∑( −1)
           n −1
                  bn = b1 − b2 + b3 − b4 + b5 − b6 + 
n =1

satisfies (a) bn > bn +1 and (b) n →∞ bn = 0 , then the series converges.
                                 lim
Remainder:                 Rn = s − sn ≤ bn +1

Absolute convergence simply means that the series converges without alternating (all
signs and terms are positive).
                                    ∞
                                          ( −1) n
Examples: The series               ∑
                                   n =0       n +1
                                                      is convergent but not absolutely convergent.

                                                   (− ) n
                                                     1                       ∞
Alternating p-series: The alternating p-series ∑ p converges for p > 0.
                                               n=1  n
∞
                             ( −1) n                                        ∞
                                                                               ( −1) n
Examples: The series   ∑
                       n=1      n
                                       and the Alternating Harmonic series ∑
                                                                           n=1    n
                                                                                       are
convergent.
∞
                               an +1                                                                  an +1
                   lim
Ratio Test: (a) If n →∞
                                an
                                     < 1 then the series           ∑a
                                                                   n=1
                                                                         n                     lim
                                                                             converges; (b) if n →∞
                                                                                                       an
                                                                                                            >1

the series diverges. Otherwise, you must use a different test for convergence.

This says that if the series eventually behaves like a convergent (divergent) geometric
series, it converges (diverges). If this limit is one, the test is inconclusive and a different
test is required. Specifically, the Ratio Test does not work for p-series.

POWER SERIES

                                                                                                ∞
Radius of Convergence: The radius of convergence for a power series                           ∑c
                                                                                               n =0
                                                                                                      n   ( x − a) n

              cn
is R = n →∞
       lim         . The center of the series is x = a. The series converges on the open
             cn +1
interval ( a − R, a + R ) and may converge at the endpoints. You must test each series
that results at the endpoints of the interval separately for convergence.

                              ∞
                                    ( x + 2) n
Example: The series          ∑ (n +1)
                             n =0
                                            2    is convergent on [-3,-1] but the series
 ∞
       (−1) n ( x − 3) n
∑
n =0     5n    n +1
                           is convergent on (-2,8].

Taylor Series: If f has a power series expansion centered at x = a, then the power series
                      ∞
                          f ( n ) (a)
is given by f ( x) = ∑                ( x − a) n . Use the Ratio Test to determine the interval of
                     n =0     n!
convergence.
                                                   (n + )
Taylor’s Inequality (Remainder): If f
                                                       1
                                                          ( x ) ≤ M for x − ≤d , then
                                                                           a
                 M          n +1
 Rn ( x) ≤             x −a      for         x −a ≤d      . Note that d < R (the radius of convergence)
              ( n +1)!
                                                          ( n+ )
                                                              1
and think of M as the maximum value of f                           ( x ) on the interval [x,a] or [a,x].

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Review of series

  • 1. MATH 1220 Summary of Convergence Tests for Series ∞ Let ∑a n=1 n be an infinite series of positive terms. ∞ The series ∑a n=1 n converges if and only if the sequence of partial sums, ∞ S n = a1 + a 2 + a3 +  a n , converges. NOTE: lim S n = ∑a n n→∞ n=1 ∞ Divergence Test: If n → ∞ an ≠ 0 , the series lim ∑a n diverges. n=1 n 1 ∞ n lim = lim =1 Example: The series ∑ is divergent since n→ ∞ n2 + 1 n→ ∞ 1+ 1 n =1 n +12 n2 This means that the terms of a convergent series must approach zero. That is, if ∑ n a converges, then lim an = 0. However, lim a n = 0 does not imply convergence. n →∞ n →∞ Geometric Series: THIS is our model series A geometric series a + ar + ar 2 +  + ar n −1 +  converges for − 1 < r < 1 . an +1 a Note: r = If the series converges, the sum of the series is . an 1 −r n ∞ 7  35 7 Example: The series ∑5 8  converges with a = a1 = 8 and r = 8 . The sum of the n=1   series is 35. Integral Test: If f is a continuous, positive, decreasing function on [1, ∞ with ) ∞ f ( n) = an , then the series ∑a n=1 n converges if and only if the improper integral ∞ ∫ f ( x)dx converges. 1 ∞ Remainder for Integral Test: If ∑a n=1 n converges by the Integral Test, then the ∞ remainder after n terms satisfies Rn ≤∫ f ( x)dx n ∞ 1 p-series: The series ∑n n=1 p is convergent for p > 1 and diverges otherwise. ∞ ∞ 1 1 Examples: The series ∑n n=1 1.001 is convergent but the series ∑n n=1 is divergent.
  • 2. ∞ Comparison Test: Suppose ∑a n=1 n and ∑b n=1 n are series with positive terms. ∞ ∞ (a) If ∑b n=1 n is convergent and an ≤ bn for all n, then n=1 ∑a n converges. ∞ ∞ (b) If ∑b n=1 n is divergent and an ≥ bn for all n, then ∑a n=1 n diverges. The Comparison Test requires that you make one of two comparisons: • Compare an unknown series to a LARGER known convergent series (smaller than convergent is convergent) • Compare an unknown series to a SMALLER known divergent series (bigger than divergent is divergent) ∞ ∞ ∞ 3n 3n 1 Examples: ∑n n =2 2 > ∑ 2 = 3∑ which is a divergent harmonic series. Since the − 2 n =2 n n =2 n original series is larger by comparison, it is divergent. ∞ ∞ 5n 5n 5 ∞ 1 We have ∑ 2n 3 + n 2 + 1 n=1 2n 2 n=1 n n =1 < ∑ 3 = ∑ 2 which is a convergent p-series. Since the original series is smaller by comparison, it is convergent. ∞ ∞ Limit Comparison Test: Suppose ∑a n=1 n and ∑b n=1 n are series with positive terms. If an lim = c where 0 < c < ∞ , then either both series converge or both series diverge. n →∞ b n (Useful for p-series) Rule of Thumb: To obtain a series for comparison, omit lower order terms in the numerator and the denominator and then simplify. ∞ ∞ ∞ n 1 Examples: For the series ∑ 2 n n =1 n + n + 3 , compare to ∑n 2 =∑ 3 which is a n =1 n =1 n 2 convergent p-series. πn + n n ∞ ∞ πn ∞ π  For the series ∑ n 2 , compare to ∑ n = ∑  which is a divergent geometric n =1 3 + n n =1 3 n =1  3  series. Alternating Series Test: If the alternating series ∞ ∑( −1) n −1 bn = b1 − b2 + b3 − b4 + b5 − b6 +  n =1 satisfies (a) bn > bn +1 and (b) n →∞ bn = 0 , then the series converges. lim Remainder: Rn = s − sn ≤ bn +1 Absolute convergence simply means that the series converges without alternating (all signs and terms are positive). ∞ ( −1) n Examples: The series ∑ n =0 n +1 is convergent but not absolutely convergent. (− ) n 1 ∞ Alternating p-series: The alternating p-series ∑ p converges for p > 0. n=1 n
  • 3. ( −1) n ∞ ( −1) n Examples: The series ∑ n=1 n and the Alternating Harmonic series ∑ n=1 n are convergent.
  • 4. an +1 an +1 lim Ratio Test: (a) If n →∞ an < 1 then the series ∑a n=1 n lim converges; (b) if n →∞ an >1 the series diverges. Otherwise, you must use a different test for convergence. This says that if the series eventually behaves like a convergent (divergent) geometric series, it converges (diverges). If this limit is one, the test is inconclusive and a different test is required. Specifically, the Ratio Test does not work for p-series. POWER SERIES ∞ Radius of Convergence: The radius of convergence for a power series ∑c n =0 n ( x − a) n cn is R = n →∞ lim . The center of the series is x = a. The series converges on the open cn +1 interval ( a − R, a + R ) and may converge at the endpoints. You must test each series that results at the endpoints of the interval separately for convergence. ∞ ( x + 2) n Example: The series ∑ (n +1) n =0 2 is convergent on [-3,-1] but the series ∞ (−1) n ( x − 3) n ∑ n =0 5n n +1 is convergent on (-2,8]. Taylor Series: If f has a power series expansion centered at x = a, then the power series ∞ f ( n ) (a) is given by f ( x) = ∑ ( x − a) n . Use the Ratio Test to determine the interval of n =0 n! convergence. (n + ) Taylor’s Inequality (Remainder): If f 1 ( x ) ≤ M for x − ≤d , then a M n +1 Rn ( x) ≤ x −a for x −a ≤d . Note that d < R (the radius of convergence) ( n +1)! ( n+ ) 1 and think of M as the maximum value of f ( x ) on the interval [x,a] or [a,x].