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International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056
Volume: 07 Issue: 02 | Feb 2020 www.irjet.net p-ISSN: 2395-0072
© 2020, IRJET | Impact Factor value: 7.34 | ISO 9001:2008 Certified Journal | Page 1123
COMMUTING GRAPH OF BOUNDEDLY GENERATED REGULAR SEMIGROUP
DR. R. PUNITHA1, S. HINGIS2, S.K. VIJAY AMRTHA3, V. KRISHNA VENI4
1research Supervisor and Head of the Department, Thassim Beevi Abdul Kader College for Women, Tamilnadu, India.
2,3,4STUDENTS, Department of Mathematics, Thassim Beevi Abdul Kader College for Women, Tamilnadu, India.
----------------------------------------------------------------------------***--------------------------------------------------------------------------
Abstract: Tower Bauer and Be’eri Greenfeld pose several problems concerning the construction of commuting graph of boundedly
generated semigroup. Before that Araujo Kinyon and Koniecxny construct the arbitrary graph of semigroup. We observe that
every star free graph is the commuting graph of some semigroup. Now we construct the commuting graph of boundedly generated
regular semigroup.
Keywords:
Commuting graph, Semigroup, Star free graph, Boundedly generated semigroup, Regular semigroup.
I. Introduction
The commuting graph of a finite non-commutative semigroup denoted by is a simple graph whose vertices are
the non-central elements of S and two distinct vertices x and y are adjacent if . We have to denote the center of a
semigroup by , so the center of the regular semigroup by . The commuting graph of regular semigroup is denoted by
is simple whose vertex set is where two vertices are connected by an edge if their corresponding elements in
is commute. Since the semigroup is commute. Tomer Bauer and Be’erl Greenfeld proved that the clique, diameter and degree
of the commuting graph of semigroup.
II. Preliminaries
2.1. Group:
A group is a set, together with an operation that combines any two elements and to form another element,
denoted or .
To qualify as a group, the set and operation must satisfy four requirements known as the group axioms.
Closure:
For all , in , the result of the operation is also in .
Associativity:
For all , and in , .
Identity element:
There exists an element in such that, for every element in , the equation holds.
Inverse element:
For each in , there exists an element in , commonly denoted , such that , where is the identity
element.
2.2. Semigroup:
A semigroup is a set together with a binary operation satisfies the associative property.
For all the equation holds.
International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056
Volume: 07 Issue: 02 | Feb 2020 www.irjet.net p-ISSN: 2395-0072
© 2020, IRJET | Impact Factor value: 7.34 | ISO 9001:2008 Certified Journal | Page 1124
2.3. Regular semigroup:
A regular semigroup is a semigroup in which every element is regular. i.e., for each element , there exists an
element such that .
2.4. Nilpotent:
An element of a ring is called nilpotent if there exists some positive integer such that .
2.5. Clique:
A clique in an undirected graph is a subset of vertices, , such that every two distinct vertices are
adjacent.
2.6. Chromatic number:
The chromatic number of a graph is the smallest number of colors needed to color the vertices of so that no two
adjacent vertices share the same color.
2.7. Connected:
A graph is said to be connected if there is a path between every pair of vertices. From every vertex to any other
vertex, there should be some path to traverse.
2.8. Diameter:
The diameter of a graph is the length of the longest shortest path between any two vertices
where is a graph distance.
2.9. Independent number:
The independence number is the cardinality of the largest independent vertex set. i.e., the size of a maximum
independent vertex set. The independence number is most commonly denoted by
2.10. Solvable:
A group is called solvable if it has a subnormal series whose factor groups are all abelian, that is, if there are
subgroups such that is normal in and is an abelian group, for .
2.11. Suzuki group:
Suzuki groups, denoted by or form an infinite family of groups of Lie
type, that are simple for These simple groups are the only finite non-abelian ones with orders not divisible by .
2.12. Null union:
For any set , the null set is a union of . since the union of two sets is the set of all elements in both
sets and the null set has no elements, all of the elements in both sets are only the elements in .
2.13. Star:
Star, is defined as a set of line segments with a common midpoint.
2.14. Note:
If is a commutative semigroup, then is the empty graph.
International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056
Volume: 07 Issue: 02 | Feb 2020 www.irjet.net p-ISSN: 2395-0072
© 2020, IRJET | Impact Factor value: 7.34 | ISO 9001:2008 Certified Journal | Page 1125
III. Main Results
Lemma 3.1:
If be a star free graph, then there exist a (monomial) regular semigroup such that . Moreover, if
has vertices then there exists a (monomial) regular semigroup with such that is generated by elements and
the order is .
Proof:
Let us consider the vertices of to generate free semigroup with zero and the quotient semigroup as,
{ }
It is clear that the center consist of all elements of the form . It is now evident that why .Also, an easy
calculation shows that if has vertices then this semigroup has precisely elements.
Lemma 3.2
Let be a regular graph on vertices, then rank
Proof:
Let us consider any subset of almost vertices of .We know that rank .Now we have to show that
rank That is, enough to prove that rank
Let us consider a vertex in and also consider another vertex , which is connected to all vertices of except
itself.Let be the regular semi group such that Suppose that the elements of plus some elements of generate
. Then must lie in So rank
Theorem 3.3
Let be a semigroup generated by elements. Suppose it has a non-central ideal such that If
is connected, then its diameter satisfies
Proof:
Pick We claim that for every we have that Indeed, write and compute
Since and are central.
Let be two vertices. If , then a path of length can be found between them, as
commutes with both of them. Suppose only one of say is not contained in . Note that ,
because is generated by elements. Then by connectivity a shortest path can be found between and some vertex .
As the path is minimal, its length does not exceed , which is the number of generators. We can now concatenate this path to
resulting in a path of length at most , connecting and .
We now assume that both . We can find shortest paths from to some respectively and
denote the lengths of these paths by As before, minimality implies that consists of precisely vertices from .
But , for otherwise the pigeonhole principle would imply that some vertex from appears in both so a
path between and can be found of length atmost .Hence the path obtained by
concatenating has length atmost .
International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056
Volume: 07 Issue: 02 | Feb 2020 www.irjet.net p-ISSN: 2395-0072
© 2020, IRJET | Impact Factor value: 7.34 | ISO 9001:2008 Certified Journal | Page 1126
Definition.3.4
Let be a semigroup a path in is called right path if and for every
. If contains a right path then the knit degree of is defined to be the length of the shortest right path in
Example.3.5:
The following regular semigroup has knit degree
With the relation,
{
One may verify that the graph is a path graph on four vertices.
P4 P3 P2 P1
The relations ensure that is a right path.
Theorem 3.6
For any regular semigroup as given . The maximum and minimum degrees of
are
( ) and ( )
Proof:
Let us consider the vertex of . It is clear that for any as . By the definition of
we get , . Thus, we have ( ) .
On the other hand, let us consider the vertex of . The equality satisfies only if Nevertheless, for
every , we have .That means the unique vertex is only connected to the vertex
, which implies ( ) , as required.
Example 3.7
Consider the graph ( ), wit te vertex set ( ( )) .It is clear that the vertex of is
pendent and so the diameter can be figured out by considering the distance between this vertex and one of the other vertices
in the vertex set. Therefore, is only connected with the vertex and since is adjacent to all other vertices (i.e.,)
.we finally get ( ( )) , by the definition of , since , and .
We then have which implies the result .And the above theorem, we certainly have ( ( )) ,
( ( )) , ( ( )) , ( ( )) .
International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056
Volume: 07 Issue: 02 | Feb 2020 www.irjet.net p-ISSN: 2395-0072
© 2020, IRJET | Impact Factor value: 7.34 | ISO 9001:2008 Certified Journal | Page 1127
Theorem 3.8
The rank of in is atleast .
Proof:
Suppose let us assume that rank of is .clearly every generating subset contain atleast two non-central generators
say and they must lie on non-adjacent vertices of then every other vertex would have corresponded to the central
element which leads to contradiction. Hence there must at least generator but the three again commutes with all generators
so generators say are needed likewise the rank of is at least by induction,
The rank of is atleast .
REFERENCES:
[1] A. Abdollahi, S. Akbari, and H. R. Maimani. Non-commuting graph of a group. J. Algebra, 298(2):468–492, 2006.
[2] Beck I: Coloring of commutating ring. J. Algebra 1988, 116: 208–226. 10.1016/0021-8693(88)90202-5

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IRJET- Commuting Graph of Boundedly Generated Regular Semigroup

  • 1. International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056 Volume: 07 Issue: 02 | Feb 2020 www.irjet.net p-ISSN: 2395-0072 © 2020, IRJET | Impact Factor value: 7.34 | ISO 9001:2008 Certified Journal | Page 1123 COMMUTING GRAPH OF BOUNDEDLY GENERATED REGULAR SEMIGROUP DR. R. PUNITHA1, S. HINGIS2, S.K. VIJAY AMRTHA3, V. KRISHNA VENI4 1research Supervisor and Head of the Department, Thassim Beevi Abdul Kader College for Women, Tamilnadu, India. 2,3,4STUDENTS, Department of Mathematics, Thassim Beevi Abdul Kader College for Women, Tamilnadu, India. ----------------------------------------------------------------------------***-------------------------------------------------------------------------- Abstract: Tower Bauer and Be’eri Greenfeld pose several problems concerning the construction of commuting graph of boundedly generated semigroup. Before that Araujo Kinyon and Koniecxny construct the arbitrary graph of semigroup. We observe that every star free graph is the commuting graph of some semigroup. Now we construct the commuting graph of boundedly generated regular semigroup. Keywords: Commuting graph, Semigroup, Star free graph, Boundedly generated semigroup, Regular semigroup. I. Introduction The commuting graph of a finite non-commutative semigroup denoted by is a simple graph whose vertices are the non-central elements of S and two distinct vertices x and y are adjacent if . We have to denote the center of a semigroup by , so the center of the regular semigroup by . The commuting graph of regular semigroup is denoted by is simple whose vertex set is where two vertices are connected by an edge if their corresponding elements in is commute. Since the semigroup is commute. Tomer Bauer and Be’erl Greenfeld proved that the clique, diameter and degree of the commuting graph of semigroup. II. Preliminaries 2.1. Group: A group is a set, together with an operation that combines any two elements and to form another element, denoted or . To qualify as a group, the set and operation must satisfy four requirements known as the group axioms. Closure: For all , in , the result of the operation is also in . Associativity: For all , and in , . Identity element: There exists an element in such that, for every element in , the equation holds. Inverse element: For each in , there exists an element in , commonly denoted , such that , where is the identity element. 2.2. Semigroup: A semigroup is a set together with a binary operation satisfies the associative property. For all the equation holds.
  • 2. International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056 Volume: 07 Issue: 02 | Feb 2020 www.irjet.net p-ISSN: 2395-0072 © 2020, IRJET | Impact Factor value: 7.34 | ISO 9001:2008 Certified Journal | Page 1124 2.3. Regular semigroup: A regular semigroup is a semigroup in which every element is regular. i.e., for each element , there exists an element such that . 2.4. Nilpotent: An element of a ring is called nilpotent if there exists some positive integer such that . 2.5. Clique: A clique in an undirected graph is a subset of vertices, , such that every two distinct vertices are adjacent. 2.6. Chromatic number: The chromatic number of a graph is the smallest number of colors needed to color the vertices of so that no two adjacent vertices share the same color. 2.7. Connected: A graph is said to be connected if there is a path between every pair of vertices. From every vertex to any other vertex, there should be some path to traverse. 2.8. Diameter: The diameter of a graph is the length of the longest shortest path between any two vertices where is a graph distance. 2.9. Independent number: The independence number is the cardinality of the largest independent vertex set. i.e., the size of a maximum independent vertex set. The independence number is most commonly denoted by 2.10. Solvable: A group is called solvable if it has a subnormal series whose factor groups are all abelian, that is, if there are subgroups such that is normal in and is an abelian group, for . 2.11. Suzuki group: Suzuki groups, denoted by or form an infinite family of groups of Lie type, that are simple for These simple groups are the only finite non-abelian ones with orders not divisible by . 2.12. Null union: For any set , the null set is a union of . since the union of two sets is the set of all elements in both sets and the null set has no elements, all of the elements in both sets are only the elements in . 2.13. Star: Star, is defined as a set of line segments with a common midpoint. 2.14. Note: If is a commutative semigroup, then is the empty graph.
  • 3. International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056 Volume: 07 Issue: 02 | Feb 2020 www.irjet.net p-ISSN: 2395-0072 © 2020, IRJET | Impact Factor value: 7.34 | ISO 9001:2008 Certified Journal | Page 1125 III. Main Results Lemma 3.1: If be a star free graph, then there exist a (monomial) regular semigroup such that . Moreover, if has vertices then there exists a (monomial) regular semigroup with such that is generated by elements and the order is . Proof: Let us consider the vertices of to generate free semigroup with zero and the quotient semigroup as, { } It is clear that the center consist of all elements of the form . It is now evident that why .Also, an easy calculation shows that if has vertices then this semigroup has precisely elements. Lemma 3.2 Let be a regular graph on vertices, then rank Proof: Let us consider any subset of almost vertices of .We know that rank .Now we have to show that rank That is, enough to prove that rank Let us consider a vertex in and also consider another vertex , which is connected to all vertices of except itself.Let be the regular semi group such that Suppose that the elements of plus some elements of generate . Then must lie in So rank Theorem 3.3 Let be a semigroup generated by elements. Suppose it has a non-central ideal such that If is connected, then its diameter satisfies Proof: Pick We claim that for every we have that Indeed, write and compute Since and are central. Let be two vertices. If , then a path of length can be found between them, as commutes with both of them. Suppose only one of say is not contained in . Note that , because is generated by elements. Then by connectivity a shortest path can be found between and some vertex . As the path is minimal, its length does not exceed , which is the number of generators. We can now concatenate this path to resulting in a path of length at most , connecting and . We now assume that both . We can find shortest paths from to some respectively and denote the lengths of these paths by As before, minimality implies that consists of precisely vertices from . But , for otherwise the pigeonhole principle would imply that some vertex from appears in both so a path between and can be found of length atmost .Hence the path obtained by concatenating has length atmost .
  • 4. International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056 Volume: 07 Issue: 02 | Feb 2020 www.irjet.net p-ISSN: 2395-0072 © 2020, IRJET | Impact Factor value: 7.34 | ISO 9001:2008 Certified Journal | Page 1126 Definition.3.4 Let be a semigroup a path in is called right path if and for every . If contains a right path then the knit degree of is defined to be the length of the shortest right path in Example.3.5: The following regular semigroup has knit degree With the relation, { One may verify that the graph is a path graph on four vertices. P4 P3 P2 P1 The relations ensure that is a right path. Theorem 3.6 For any regular semigroup as given . The maximum and minimum degrees of are ( ) and ( ) Proof: Let us consider the vertex of . It is clear that for any as . By the definition of we get , . Thus, we have ( ) . On the other hand, let us consider the vertex of . The equality satisfies only if Nevertheless, for every , we have .That means the unique vertex is only connected to the vertex , which implies ( ) , as required. Example 3.7 Consider the graph ( ), wit te vertex set ( ( )) .It is clear that the vertex of is pendent and so the diameter can be figured out by considering the distance between this vertex and one of the other vertices in the vertex set. Therefore, is only connected with the vertex and since is adjacent to all other vertices (i.e.,) .we finally get ( ( )) , by the definition of , since , and . We then have which implies the result .And the above theorem, we certainly have ( ( )) , ( ( )) , ( ( )) , ( ( )) .
  • 5. International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056 Volume: 07 Issue: 02 | Feb 2020 www.irjet.net p-ISSN: 2395-0072 © 2020, IRJET | Impact Factor value: 7.34 | ISO 9001:2008 Certified Journal | Page 1127 Theorem 3.8 The rank of in is atleast . Proof: Suppose let us assume that rank of is .clearly every generating subset contain atleast two non-central generators say and they must lie on non-adjacent vertices of then every other vertex would have corresponded to the central element which leads to contradiction. Hence there must at least generator but the three again commutes with all generators so generators say are needed likewise the rank of is at least by induction, The rank of is atleast . REFERENCES: [1] A. Abdollahi, S. Akbari, and H. R. Maimani. Non-commuting graph of a group. J. Algebra, 298(2):468–492, 2006. [2] Beck I: Coloring of commutating ring. J. Algebra 1988, 116: 208–226. 10.1016/0021-8693(88)90202-5