The surprising flavour of
Infinite geometric series
Let’s consider the sum …
•
1
2
+
1
4
+
1
8
+
1
16
+
1
32
+ ⋯
• What is this equal to?
Let’s watch this video to get an idea
So this sum is actually equal to 1!
We can also visualise this in a square!
How do we calculate the sum?
• We can prove that the sum of the infinite
geometric series exists if the ratio is a number
between (but not including) -1 and 1, and r
should not be equal to 0. The sum is given by
the formula:
𝑘=0
∞
𝑎𝑟 𝑘
= 𝑎 + 𝑎𝑟 + 𝑎𝑟2
+ 𝑎𝑟3
+ ⋯ =
𝑎
1 − 𝑟
Can we use our knowledge to
examine whether
0.999… is actually equal to 1?
Does 0.999… equal 1 ?
• We can write a recurring decimal as a sum like
this:
• 0.999… = 0.9 + 0.09 + 0.009 + …
= 9×0.11
+9×0.12
+ 9×0.13
+ ⋯
= 9×(0.11
+ 0.12
+ 0.13
+ ⋯)
this is an infinite geometric series
with first term 0.1 and ratio 0.1
= 9 ×
0.1
1−0.1
= 9 ×
0.1
0.9
=
0.9
0.9
= 1
So YES!
0.999…. = 1

Infinite geometric series

  • 1.
    The surprising flavourof Infinite geometric series
  • 2.
    Let’s consider thesum … • 1 2 + 1 4 + 1 8 + 1 16 + 1 32 + ⋯ • What is this equal to?
  • 3.
    Let’s watch thisvideo to get an idea
  • 4.
    So this sumis actually equal to 1!
  • 5.
    We can alsovisualise this in a square!
  • 6.
    How do wecalculate the sum? • We can prove that the sum of the infinite geometric series exists if the ratio is a number between (but not including) -1 and 1, and r should not be equal to 0. The sum is given by the formula: 𝑘=0 ∞ 𝑎𝑟 𝑘 = 𝑎 + 𝑎𝑟 + 𝑎𝑟2 + 𝑎𝑟3 + ⋯ = 𝑎 1 − 𝑟
  • 7.
    Can we useour knowledge to examine whether 0.999… is actually equal to 1?
  • 8.
    Does 0.999… equal1 ? • We can write a recurring decimal as a sum like this: • 0.999… = 0.9 + 0.09 + 0.009 + … = 9×0.11 +9×0.12 + 9×0.13 + ⋯ = 9×(0.11 + 0.12 + 0.13 + ⋯) this is an infinite geometric series with first term 0.1 and ratio 0.1 = 9 × 0.1 1−0.1 = 9 × 0.1 0.9 = 0.9 0.9 = 1
  • 9.