Okay, let's solve this step-by-step: * Jogger generates 8.0x105 J of heat in 0.5 hours = 3,600 seconds * Jogger's mass is 65 kg * Specific heat capacity of the human body is 3500 J/(kg°C) * Use the heat equation: Q = cmΔT * Plug in the values: 8.0x105 J = (65 kg) x (3500 J/(kg°C)) x ΔT * Solve for ΔT: ΔT = 8.0x105 J / (65 kg x 3500 J/(kg°C)) = 1°C Therefore, if the heat were