MS. G. MARTIN
To find the sum of the first n terms of a geometric series, we use the following
formulas:
Sn =
A1 (1 – rn )
1 – r
, r ≠ 1 and Sn =
A1 − rXn
1 – r
, r ≠ 1
Where A1 = first term
An = nth term
r = common ratio
Sn = sum of the first n terms
Example 1.
Find the sum of the first 12 terms of the geometric sequence 4, 16, 64, …...
Steps Solution
1. Enumerate the given information. Here A1 = 4
2. Find the common ratio using the
formula r =
An
An − 1
r =
16
4
= 4
Steps Solution
3. Solve for the sum of the first 12 terms
using the formula
Sn =
A1 (1 – rn )
1 – r
, r ≠ 1
Sn =
A1 (1 – rn )
1 – r
, r ≠ 1
S12 =
4 (1 – 412 )
1 − 4
, r ≠ 1
=
4(1 – 16,777,216)
−3
=
4( –16,777,215 )
−3
= 4(5, 592, 405)
S12 = 22,369,620
Example 2.
Find the sum of the first seven terms of the geometric sequence
-1, -5, -25, -125,…..
Steps Solution
1. Enumerate the given information. Here A1 = -1
2. Find the common ratio. r =
−5
−1
= 5
Steps Solution
3. Solve for the sum of the first seven
terms using the formula
Sn =
A1 (1 – rn )
1 – r
, r ≠ 1
Sn =
A1 (1 – rn )
1 – r
, r ≠ 1
S7 =
−1 (1 – 57 )
1 – 5
,
S7 =
−1 ( 1 – 78,125 )
−4
S7 =
−1 (–78,124)
−4
=
𝟕𝟖,𝟏𝟐𝟒
−𝟒
S7 = -19,531
Example 3. Find the sum of the first ten terms of the geometric sequence
whose first term is
1
2
and whose fourth term is 4.
Steps Solution
1. Enumerate the given information. Here, A1 =
1
2
and A4 = 4
2. Find the common ratio.
If A1 =
1
2
and A4 = 4, we have
An = A1rn-1
A4 = A1r4-1
4 =
1
2
r3
4
1
2
= 4 .
2
1
= 8
8 = r3 ;
3
8 = r
2 = r
Steps Solution
3. Solve for the sum of the first ten terms
using the formula
Sn =
A1 (1 – rn )
1 – r
, r ≠ 1
If A1 =
1
2
, A4 = 4, r = 2, n = 10, we have
S10 =
1
2
(1 – 210 )
1 – 2
S10 =
1
2
(1 – 1,024)
−1
S10 =
1(−1,023)
2
÷ -1
S10 =
−1,023
2
÷ -1
S10 =
𝟏,𝟎𝟐𝟑
𝟐
Activity
Find the needed term of the given geometric sequence
1. 5, 10, 20, 40, …, find S10
Steps Solution
1. Enumerate the given information. A1 = 5 ; n = 10 ; r =
10
5
= 2
2. Solve for the sum of the first ten
terms using the formula
Sn =
A1 (1 – rn )
1 – r
, r ≠ 1
S10 =
5(1 – 210 )
1 – 2
S10 =
5(1 – 1,024 )
−1
S10 =
5(−1,023 )
−1
=
−5,115
−1
S10 = 5,115
2. 960, 240, 60, 15, …, find S5
Steps Solution
1. Enumerate the given information. A1 = 960 ; n = 5 ; r =
240
960
=
1
4
2. Solve for the sum of the first five
terms using the formula
Sn =
A1 (1 – rn )
1 – r
, r ≠ 1
S5 =
960(1 – ( 1
4
)5
1 – 1
4
S5 =
960(1 – 1
1,024
)
3
4
S5 =
𝟓,𝟏𝟏𝟓
𝟒
Geometric series

Geometric series

  • 1.
  • 2.
    To find thesum of the first n terms of a geometric series, we use the following formulas: Sn = A1 (1 – rn ) 1 – r , r ≠ 1 and Sn = A1 − rXn 1 – r , r ≠ 1 Where A1 = first term An = nth term r = common ratio Sn = sum of the first n terms
  • 3.
    Example 1. Find thesum of the first 12 terms of the geometric sequence 4, 16, 64, …... Steps Solution 1. Enumerate the given information. Here A1 = 4 2. Find the common ratio using the formula r = An An − 1 r = 16 4 = 4
  • 4.
    Steps Solution 3. Solvefor the sum of the first 12 terms using the formula Sn = A1 (1 – rn ) 1 – r , r ≠ 1 Sn = A1 (1 – rn ) 1 – r , r ≠ 1 S12 = 4 (1 – 412 ) 1 − 4 , r ≠ 1 = 4(1 – 16,777,216) −3 = 4( –16,777,215 ) −3 = 4(5, 592, 405) S12 = 22,369,620
  • 5.
    Example 2. Find thesum of the first seven terms of the geometric sequence -1, -5, -25, -125,….. Steps Solution 1. Enumerate the given information. Here A1 = -1 2. Find the common ratio. r = −5 −1 = 5
  • 6.
    Steps Solution 3. Solvefor the sum of the first seven terms using the formula Sn = A1 (1 – rn ) 1 – r , r ≠ 1 Sn = A1 (1 – rn ) 1 – r , r ≠ 1 S7 = −1 (1 – 57 ) 1 – 5 , S7 = −1 ( 1 – 78,125 ) −4 S7 = −1 (–78,124) −4 = 𝟕𝟖,𝟏𝟐𝟒 −𝟒 S7 = -19,531
  • 7.
    Example 3. Findthe sum of the first ten terms of the geometric sequence whose first term is 1 2 and whose fourth term is 4. Steps Solution 1. Enumerate the given information. Here, A1 = 1 2 and A4 = 4 2. Find the common ratio. If A1 = 1 2 and A4 = 4, we have An = A1rn-1 A4 = A1r4-1 4 = 1 2 r3 4 1 2 = 4 . 2 1 = 8 8 = r3 ; 3 8 = r 2 = r
  • 8.
    Steps Solution 3. Solvefor the sum of the first ten terms using the formula Sn = A1 (1 – rn ) 1 – r , r ≠ 1 If A1 = 1 2 , A4 = 4, r = 2, n = 10, we have S10 = 1 2 (1 – 210 ) 1 – 2 S10 = 1 2 (1 – 1,024) −1 S10 = 1(−1,023) 2 ÷ -1 S10 = −1,023 2 ÷ -1 S10 = 𝟏,𝟎𝟐𝟑 𝟐
  • 9.
  • 10.
    Find the neededterm of the given geometric sequence 1. 5, 10, 20, 40, …, find S10 Steps Solution 1. Enumerate the given information. A1 = 5 ; n = 10 ; r = 10 5 = 2 2. Solve for the sum of the first ten terms using the formula Sn = A1 (1 – rn ) 1 – r , r ≠ 1 S10 = 5(1 – 210 ) 1 – 2 S10 = 5(1 – 1,024 ) −1 S10 = 5(−1,023 ) −1 = −5,115 −1 S10 = 5,115
  • 11.
    2. 960, 240,60, 15, …, find S5 Steps Solution 1. Enumerate the given information. A1 = 960 ; n = 5 ; r = 240 960 = 1 4 2. Solve for the sum of the first five terms using the formula Sn = A1 (1 – rn ) 1 – r , r ≠ 1 S5 = 960(1 – ( 1 4 )5 1 – 1 4 S5 = 960(1 – 1 1,024 ) 3 4 S5 = 𝟓,𝟏𝟏𝟓 𝟒