13. A geometric series is the indicated sum of the
terms of a geometric sequence. The formula for
the partial sum , ππ of a geometric series are
ππ =
π1(1βππ)
1βπ
, r β 1 and ππ =
π1βππ‘π
1βπ
Geometric Series
14. Where n is the number of terms, π1 is the
first term, r is the common ratio, and ππ is the
last term
15. Example 1: Find the sum of the eleven terms of the geometric
series -5, -10, -20
Solution:
r =
β10
β5
=
β20
β10
= 2 Find the common ratio.
ππ =
π1(1βππ)
1βπ
Use the formula.
π11 =
βπ (1β211)
1β2
Substitute n = 11 π1= -5, r = 2
π11 = β10,235
The sum of the first eleven
terms is β10,235.
16. Example 2: In geometric series π1= 2, π7 = 1,458, r = 3. Find π7.
Solution:
ππ =
π1 β ππ‘π
1 β π
Use the formula.
π7 =
2β3(1,458)
1β3
Substitute π1= 2 π‘7= 1,458, r=3.
π7 = 2,186
The sum of the first seven terms
is 2,186.
17. Example 3: How many terms of geometric progression 2, 6, 18,β¦
must be taken so that their sum is 6,560?
Solution:
6,560 =
2(1β3π)
1β3
Substitute ππ= 6,560 π‘1= 2, r=3.
-13,120 = 2 β 2(3π)
6,561 =3π
38
= 3π
8 = n
Solve for the n.
The number of term is 8.
18. Example 4: A cell divides into two every 50 seconds. There are
10 cells at the start of the experiment. How many cells will be there
be at the end of 5 minutes
Solution:
n=
5(60)
50
= 6
r =
20
10
= 2
Find n, the number of times the
cells will divide after 5
minutes. Find r.
ππ =
π1(1βππ)
1βπ
Use the formula.
π6 =
ππ (1β26)
1β2
Substitute n = 6, r = 2 π1= 10.
π6 = 630
There will be 360 cells at the
end of 5 minutes.
19. Activity: Test your knowledge.
Find the indicated term sum of each geometric series.
(Page 28)
Assignment: Test your skill.
a. Find the indicated sum of each geometric series.
b. Find the specified value using the given information
about the geometric series.