This document provides a lesson on ratio and proportion from Holt Geometry. It includes examples of writing ratios, using ratios to solve problems, writing and solving proportions using the cross products property, and applying proportions to solve real-world problems. Key concepts covered are ratios, proportions, extremes, means, and cross products. Worked examples demonstrate how to set up and solve proportions to find missing values.

1. Holt Geometry
7-1 Ratio and Proportion7-1 Ratio and Proportion
Holt Geometry
Warm UpWarm Up
Lesson PresentationLesson Presentation
Lesson QuizLesson Quiz

2. Holt Geometry
7-1 Ratio and Proportion
Warm Up
Find the slope of the line through each
pair of points.
1. (1, 5) and (3, 9)
2. (–6, 4) and (6, –2)
Solve each equation.
3. 4x + 5x + 6x = 45
4. (x – 5)2
= 81
5. Write in simplest form.
2
x = 3
x = 14 or x = –4

3. Holt Geometry
7-1 Ratio and Proportion
Write and simplify ratios.
Use proportions to solve problems.
Objectives

4. Holt Geometry
7-1 Ratio and Proportion
ratio
proportion
extremes
means
cross products
Vocabulary

5. Holt Geometry
7-1 Ratio and Proportion
The Lord of the Rings movies transport viewers to
the fantasy world of Middle Earth. Many scenes
feature vast fortresses, sprawling cities, and
bottomless mines. To film these images, the
moviemakers used ratios to help them build
highly detailed miniature models.

6. Holt Geometry
7-1 Ratio and Proportion
A ratio compares two numbers by division. The ratio
of two numbers a and b can be written as a to b, a:b,
or , where b ≠ 0. For example, the ratios 1 to 2,
1:2, and all represent the same comparison.

7. Holt Geometry
7-1 Ratio and Proportion
In a ratio, the denominator of the fraction cannot be
zero because division by zero is undefined.
Remember!

8. Holt Geometry
7-1 Ratio and Proportion
Example 1: Writing Ratios
Write a ratio expressing the slope of l.
Substitute the
given values.
Simplify.

9. Holt Geometry
7-1 Ratio and Proportion
Check It Out! Example 1
Given that two points on m are C(–2, 3) and
D(6, 5), write a ratio expressing the slope of m.
Substitute the
given values.
Simplify.

10. Holt Geometry
7-1 Ratio and Proportion
A ratio can involve more than two numbers. For
the rectangle, the ratio of the side lengths may be
written as 3:7:3:7.

11. Holt Geometry
7-1 Ratio and Proportion
Example 2: Using Ratios
The ratio of the side lengths of a triangle is
4:7:5, and its perimeter is 96 cm. What is the
length of the shortest side?
Let the side lengths be 4x, 7x, and 5x.
Then 4x + 7x + 5x = 96 . After like terms are
combined, 16x = 96. So x = 6. The length of the
shortest side is 4x = 4(6) = 24 cm.

12. Holt Geometry
7-1 Ratio and Proportion
Check It Out! Example 2
The ratio of the angle measures in a triangle is
1:6:13. What is the measure of each angle?
x + y + z = 180°
x + 6x + 13x = 180°
20x = 180°
x = 9°
y = 6x
y = 6(9°)
y = 54°
z = 13x
z = 13(9°)
z = 117°

13. Holt Geometry
7-1 Ratio and Proportion
A proportion is an equation stating that two ratios
are equal. In the proportion , the values
a and d are the extremes. The values b and c
are the means. When the proportion is written as
a:b = c:d, the extremes are in the first and last
positions. The means are in the two middle positions.

14. Holt Geometry
7-1 Ratio and Proportion
In Algebra 1 you learned the Cross Products
Property. The product of the extremes ad and the
product of the means bc are called the cross
products.

15. Holt Geometry
7-1 Ratio and Proportion
The Cross Products Property can also be stated
as, “In a proportion, the product of the extremes
is equal to the product of the means.”
Reading Math

16. Holt Geometry
7-1 Ratio and Proportion
Example 3A: Solving Proportions
Solve the proportion.
Cross Products Property
Simplify.
Divide both sides by 56.
7(72) = x(56)
504 = 56x
x = 9

17. Holt Geometry
7-1 Ratio and Proportion
Example 3B: Solving Proportions
Solve the proportion.
Cross Products Property(z – 4)2
= 5(20)
Simplify.(z – 4)2
= 100
Find the square root of both sides.(z – 4) = ±10
(z – 4) = 10 or (z – 4) = –10 Rewrite as two eqns.
z = 14 or z = –6 Add 4 to both sides.

18. Holt Geometry
7-1 Ratio and Proportion
Check It Out! Example 3a
Solve the proportion.
Cross Products Property
Simplify.
Divide both sides by 8.
3(56) = 8(x)
168 = 8x
x = 21

19. Holt Geometry
7-1 Ratio and Proportion
Check It Out! Example 3b
Solve the proportion.
Cross Products Property
Simplify.
Divide both sides by 8.
2y(4y) = 9(8)
8y2
= 72
y2
= 9
Find the square root of both sides.y = ±3
Rewrite as two equations.y = 3 or y = –3

20. Holt Geometry
7-1 Ratio and Proportion
Check It Out! Example 3c
Solve the proportion.
Cross Products Property
Simplify.
Divide both sides by 2.
d(2) = 3(6)
2d = 18
d = 9

21. Holt Geometry
7-1 Ratio and Proportion
Check It Out! Example 3d
Solve the proportion.
Cross Products Property(x + 3)2
= 4(9)
Simplify.(x + 3)2
= 36
Find the square root of both sides.(x + 3) = ±6
(x + 3) = 6 or (x + 3) = –6 Rewrite as two eqns.
x = 3 or x = –9 Subtract 3 from both sides.

22. Holt Geometry
7-1 Ratio and Proportion
The following table shows equivalent forms of the
Cross Products Property.

23. Holt Geometry
7-1 Ratio and Proportion
Example 4: Using Properties of Proportions
Given that 18c = 24d, find the ratio of d to c in
simplest form.
18c = 24d
Divide both sides by 24c.
Simplify.

24. Holt Geometry
7-1 Ratio and Proportion
Check It Out! Example 4
Given that 16s = 20t, find the ratio t:s in
simplest form.
16s = 20t
Divide both sides by 20s.
Simplify.

25. Holt Geometry
7-1 Ratio and Proportion
Example 5: Problem-Solving Application
11 Understand the Problem
The answer will be the length of the room
on the scale drawing.
Marta is making a scale drawing of her
bedroom. Her rectangular room is 12 feet
wide and 15 feet long. On the scale drawing,
the width of her room is 5 inches. What is the
length?

26. Holt Geometry
7-1 Ratio and Proportion
Example 5 Continued
22 Make a Plan
Let x be the length of the room on the scale
drawing. Write a proportion that compares
the ratios of the width to the length.

27. Holt Geometry
7-1 Ratio and Proportion
Solve33
Example 5 Continued
Cross Products Property
Simplify.
Divide both sides by 12.5.
5(15) = x(12.5)
75 = 12.5x
x = 6
The length of the room on the scale drawing
is 6 inches.

28. Holt Geometry
7-1 Ratio and Proportion
Look Back44
Example 5 Continued
Check the answer in the original problem. The
ratio of the width to the length of the actual
room is 12 :15, or 5:6. The ratio of the width
to the length in the scale drawing is also 5:6.
So the ratios are equal, and the answer is
correct.

29. Holt Geometry
7-1 Ratio and Proportion
Check It Out! Example 5
What if...? Suppose the special-effects team
made a different model with a height of 9.2 m
and a width of 6 m. What is the height of the
actual tower?
11 Understand the Problem
The answer will be the height of the tower.

30. Holt Geometry
7-1 Ratio and Proportion
Check It Out! Example 5 Continued
22 Make a Plan
Let x be the height of the tower. Write a
proportion that compares the ratios of the
height to the width.

31. Holt Geometry
7-1 Ratio and Proportion
Solve33
Check It Out! Example 5 Continued
Cross Products Property
Simplify.
Divide both sides by 6.
9.2(996) = 6(x)
9163.2 = 6x
1527.2 = x
The height of the actual tower is 1527.2 feet.

32. Holt Geometry
7-1 Ratio and Proportion
Look Back44
Check the answer in the original problem.
The ratio of the height to the width of the
model is 9.2:6. The ratio of the height to the
width of the tower is 1527.2:996, or 9.2:6.
So the ratios are equal, and the answer is
correct.
Check It Out! Example 5 Continued

33. Holt Geometry
7-1 Ratio and Proportion
Lesson Quiz
1. The ratio of the angle measures in a triangle is
1:5:6. What is the measure of each angle?
Solve each proportion.
2. 3.
4. Given that 14a = 35b, find the ratio of a to b in
simplest form.
5. An apartment building is 90 ft tall and 55 ft
wide. If a scale model of this building is 11 in.
wide, how tall is the scale model of the building?
15°, 75°, 90°
3 7 or –7
18 in.