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8-1 Similarity in Right Triangles
8-1 Similarity in Right Triangles

Warm Up
Lesson Presentation
Lesson Quiz

Holt Geometry
Holt Geometry
8-1 Similarity in Right Triangles
Warm Up
1. Write a similarity statement
comparing the two triangles.
∆ADB ~ ∆EDC
Simplify.
2.

3.

Solve each equation.
4.

Holt Geometry

5. 2x2 = 50

±5
8-1 Similarity in Right Triangles

Objectives
Use geometric mean to find segment lengths
in right triangles.
Apply similarity relationships in right triangles
to solve problems.

Holt Geometry
8-1 Similarity in Right Triangles

Vocabulary
geometric mean

Holt Geometry
8-1 Similarity in Right Triangles

In a right triangle, an altitude drawn from the vertex of the
right angle to the hypotenuse forms two right triangles.

Holt Geometry
8-1 Similarity in Right Triangles

Holt Geometry
8-1 Similarity in Right Triangles
Example 1: Identifying Similar Right Triangles
Write a similarity statement
comparing the three triangles.
Sketch the three right triangles with the angles of
the triangles in corresponding positions.
W

Z

By Theorem 8-1-1, ∆UVW ~ ∆UWZ ~ ∆WVZ.
Holt Geometry
8-1 Similarity in Right Triangles
Check It Out! Example 1
Write a similarity statement comparing
the three triangles.
Sketch the three right triangles with the
angles of the triangles in corresponding
positions.

By Theorem 8-1-1, ∆LJK ~ ∆JMK ~ ∆LMJ.
Holt Geometry
8-1 Similarity in Right Triangles

Consider the proportion
. In this case, the
means of the proportion are the same number, and
that number is the geometric mean of the extremes.
The geometric mean of two positive numbers is the positive
square root of their product. So the geometric mean of a and b is
the positive number x such

that

Holt Geometry

, or x2 = ab.
8-1 Similarity in Right Triangles
Example 2A: Finding Geometric Means
Find the geometric mean of each pair of numbers. If
necessary, give the answer in simplest radical form.
4 and 25

Let x be the geometric mean.
x2 = (4)(25) = 100
x = 10

Holt Geometry

Def. of geometric mean
Find the positive square root.
8-1 Similarity in Right Triangles
Example 2B: Finding Geometric Means
Find the geometric mean of each pair of numbers. If
necessary, give the answer in simplest radical form.
5 and 30

Let x be the geometric mean.
x2 = (5)(30) = 150

Def. of geometric mean
Find the positive square root.

Holt Geometry
8-1 Similarity in Right Triangles
Check It Out! Example 2a
Find the geometric mean of each pair of numbers. If
necessary, give the answer in simplest radical form.
2 and 8
Let x be the geometric mean.
x2 = (2)(8) = 16
x=4

Holt Geometry

Def. of geometric mean
Find the positive square root.
8-1 Similarity in Right Triangles
Check It Out! Example 2b
Find the geometric mean of each pair of numbers. If
necessary, give the answer in simplest radical form.
10 and 30
Let x be the geometric mean.
x2 = (10)(30) = 300

Def. of geometric mean
Find the positive square root.

Holt Geometry
8-1 Similarity in Right Triangles
Check It Out! Example 2c
Find the geometric mean of each pair of numbers. If
necessary, give the answer in simplest radical form.
8 and 9
Let x be the geometric mean.
x2 = (8)(9) = 72

Def. of geometric mean
Find the positive square root.

Holt Geometry
8-1 Similarity in Right Triangles
You can use Theorem 8-1-1 to write proportions comparing
the side lengths of the triangles formed by the altitude to the
hypotenuse of a right triangle.
All the relationships in red involve geometric means.

Holt Geometry
8-1 Similarity in Right Triangles

Holt Geometry
8-1 Similarity in Right Triangles
Example 3: Finding Side Lengths in Right Triangles
Find x, y, and z.

62 = (9)(x)
x=4

y2 = (4)(13) = 52

6 is the geometric mean of 9
and x.
Divide both sides by 9.

y is the geometric mean of 4
and 13.
Find the positive square root.

z2 = (9)(13) = 117

Holt Geometry

z is the geometric mean of
9 and 13.
Find the positive square root.
8-1 Similarity in Right Triangles

Helpful Hint
Once you’ve found the unknown side lengths, you can
use the Pythagorean Theorem to check your answers.

Holt Geometry
8-1 Similarity in Right Triangles
Check It Out! Example 3
Find u, v, and w.
92 = (3)(u)

9 is the geometric mean of
u and 3.

u = 27

Divide both sides by 3.

w2 = (27 + 3)(27) w is the geometric mean of
u + 3 and 27.
Find the positive square root.

v2 = (27 + 3)(3)

Holt Geometry

v is the geometric mean of
u + 3 and 3.
Find the positive square root.
8-1 Similarity in Right Triangles
Example 4: Measurement Application

To estimate the height of a
Douglas fir, Jan positions herself
so that her lines of sight to the
top and bottom of the tree form a
90º angle. Her eyes are about 1.6
m above the ground, and she is
standing 7.8 m from the tree.
What is the height of the tree to
the nearest meter?

Holt Geometry
8-1 Similarity in Right Triangles
Example 4 Continued
Let x be the height of the tree above eye level.
(7.8)2 = 1.6x
x = 38.025 ≈ 38

7.8 is the geometric mean of
1.6 and x.
Solve for x and round.

The tree is about 38 + 1.6 = 39.6, or 40 m tall.

Holt Geometry
8-1 Similarity in Right Triangles
Check It Out! Example 4

A surveyor positions himself so
that his line of sight to the top of a
cliff and his line of sight to the
bottom form a right angle as
shown.
What is the height of the cliff to
the nearest foot?

Holt Geometry
8-1 Similarity in Right Triangles
Check It Out! Example 4 Continued
Let x be the height of cliff above eye level.
(28)2 = 5.5x
x

142.5

28 is the geometric mean of
5.5 and x.
Divide both sides by 5.5.

The cliff is about 142.5 + 5.5, or 148 ft
high.

Holt Geometry
8-1 Similarity in Right Triangles
Lesson Quiz: Part I

Find the geometric mean of each pair of numbers. If
necessary, give the answer in simplest radical form.
1. 8 and 18
2. 6 and 15

Holt Geometry

12
8-1 Similarity in Right Triangles
Lesson Quiz: Part II
For Items 3–6, use ∆RST.

3. Write a similarity statement comparing the three

triangles.

∆RST ~ ∆RPS ~ ∆SPT

4. If PS = 6 and PT = 9, find PR.

4

5. If TP = 24 and PR = 6, find RS.

6. Complete the equation (ST)2 = (TP + PR)(?).
Holt Geometry

TP

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Right triangle similarity

  • 1. 8-1 Similarity in Right Triangles 8-1 Similarity in Right Triangles Warm Up Lesson Presentation Lesson Quiz Holt Geometry Holt Geometry
  • 2. 8-1 Similarity in Right Triangles Warm Up 1. Write a similarity statement comparing the two triangles. ∆ADB ~ ∆EDC Simplify. 2. 3. Solve each equation. 4. Holt Geometry 5. 2x2 = 50 ±5
  • 3. 8-1 Similarity in Right Triangles Objectives Use geometric mean to find segment lengths in right triangles. Apply similarity relationships in right triangles to solve problems. Holt Geometry
  • 4. 8-1 Similarity in Right Triangles Vocabulary geometric mean Holt Geometry
  • 5. 8-1 Similarity in Right Triangles In a right triangle, an altitude drawn from the vertex of the right angle to the hypotenuse forms two right triangles. Holt Geometry
  • 6. 8-1 Similarity in Right Triangles Holt Geometry
  • 7. 8-1 Similarity in Right Triangles Example 1: Identifying Similar Right Triangles Write a similarity statement comparing the three triangles. Sketch the three right triangles with the angles of the triangles in corresponding positions. W Z By Theorem 8-1-1, ∆UVW ~ ∆UWZ ~ ∆WVZ. Holt Geometry
  • 8. 8-1 Similarity in Right Triangles Check It Out! Example 1 Write a similarity statement comparing the three triangles. Sketch the three right triangles with the angles of the triangles in corresponding positions. By Theorem 8-1-1, ∆LJK ~ ∆JMK ~ ∆LMJ. Holt Geometry
  • 9. 8-1 Similarity in Right Triangles Consider the proportion . In this case, the means of the proportion are the same number, and that number is the geometric mean of the extremes. The geometric mean of two positive numbers is the positive square root of their product. So the geometric mean of a and b is the positive number x such that Holt Geometry , or x2 = ab.
  • 10. 8-1 Similarity in Right Triangles Example 2A: Finding Geometric Means Find the geometric mean of each pair of numbers. If necessary, give the answer in simplest radical form. 4 and 25 Let x be the geometric mean. x2 = (4)(25) = 100 x = 10 Holt Geometry Def. of geometric mean Find the positive square root.
  • 11. 8-1 Similarity in Right Triangles Example 2B: Finding Geometric Means Find the geometric mean of each pair of numbers. If necessary, give the answer in simplest radical form. 5 and 30 Let x be the geometric mean. x2 = (5)(30) = 150 Def. of geometric mean Find the positive square root. Holt Geometry
  • 12. 8-1 Similarity in Right Triangles Check It Out! Example 2a Find the geometric mean of each pair of numbers. If necessary, give the answer in simplest radical form. 2 and 8 Let x be the geometric mean. x2 = (2)(8) = 16 x=4 Holt Geometry Def. of geometric mean Find the positive square root.
  • 13. 8-1 Similarity in Right Triangles Check It Out! Example 2b Find the geometric mean of each pair of numbers. If necessary, give the answer in simplest radical form. 10 and 30 Let x be the geometric mean. x2 = (10)(30) = 300 Def. of geometric mean Find the positive square root. Holt Geometry
  • 14. 8-1 Similarity in Right Triangles Check It Out! Example 2c Find the geometric mean of each pair of numbers. If necessary, give the answer in simplest radical form. 8 and 9 Let x be the geometric mean. x2 = (8)(9) = 72 Def. of geometric mean Find the positive square root. Holt Geometry
  • 15. 8-1 Similarity in Right Triangles You can use Theorem 8-1-1 to write proportions comparing the side lengths of the triangles formed by the altitude to the hypotenuse of a right triangle. All the relationships in red involve geometric means. Holt Geometry
  • 16. 8-1 Similarity in Right Triangles Holt Geometry
  • 17. 8-1 Similarity in Right Triangles Example 3: Finding Side Lengths in Right Triangles Find x, y, and z. 62 = (9)(x) x=4 y2 = (4)(13) = 52 6 is the geometric mean of 9 and x. Divide both sides by 9. y is the geometric mean of 4 and 13. Find the positive square root. z2 = (9)(13) = 117 Holt Geometry z is the geometric mean of 9 and 13. Find the positive square root.
  • 18. 8-1 Similarity in Right Triangles Helpful Hint Once you’ve found the unknown side lengths, you can use the Pythagorean Theorem to check your answers. Holt Geometry
  • 19. 8-1 Similarity in Right Triangles Check It Out! Example 3 Find u, v, and w. 92 = (3)(u) 9 is the geometric mean of u and 3. u = 27 Divide both sides by 3. w2 = (27 + 3)(27) w is the geometric mean of u + 3 and 27. Find the positive square root. v2 = (27 + 3)(3) Holt Geometry v is the geometric mean of u + 3 and 3. Find the positive square root.
  • 20. 8-1 Similarity in Right Triangles Example 4: Measurement Application To estimate the height of a Douglas fir, Jan positions herself so that her lines of sight to the top and bottom of the tree form a 90º angle. Her eyes are about 1.6 m above the ground, and she is standing 7.8 m from the tree. What is the height of the tree to the nearest meter? Holt Geometry
  • 21. 8-1 Similarity in Right Triangles Example 4 Continued Let x be the height of the tree above eye level. (7.8)2 = 1.6x x = 38.025 ≈ 38 7.8 is the geometric mean of 1.6 and x. Solve for x and round. The tree is about 38 + 1.6 = 39.6, or 40 m tall. Holt Geometry
  • 22. 8-1 Similarity in Right Triangles Check It Out! Example 4 A surveyor positions himself so that his line of sight to the top of a cliff and his line of sight to the bottom form a right angle as shown. What is the height of the cliff to the nearest foot? Holt Geometry
  • 23. 8-1 Similarity in Right Triangles Check It Out! Example 4 Continued Let x be the height of cliff above eye level. (28)2 = 5.5x x 142.5 28 is the geometric mean of 5.5 and x. Divide both sides by 5.5. The cliff is about 142.5 + 5.5, or 148 ft high. Holt Geometry
  • 24. 8-1 Similarity in Right Triangles Lesson Quiz: Part I Find the geometric mean of each pair of numbers. If necessary, give the answer in simplest radical form. 1. 8 and 18 2. 6 and 15 Holt Geometry 12
  • 25. 8-1 Similarity in Right Triangles Lesson Quiz: Part II For Items 3–6, use ∆RST. 3. Write a similarity statement comparing the three triangles. ∆RST ~ ∆RPS ~ ∆SPT 4. If PS = 6 and PT = 9, find PR. 4 5. If TP = 24 and PR = 6, find RS. 6. Complete the equation (ST)2 = (TP + PR)(?). Holt Geometry TP