
Presented By:
Sunny Khatana
Computer Science Engg.
University Of Gujrat

 A reduction in the value of an asset with the passage
of time, due in particular to wear and tear.
Defination
Here The Four Methods are described:
 Straight Line Method
 MACR’S Method
 Double Decline Method
 Sum Of The Year Method
Methods

Cost of Asset=10,500
Salvage Value/Residual Value=500
Life years=5
Straight Line Method

10,000 cost - 500 salvage value/5 = 2000 per year
year cost Depreciation Accumulated Book
Expense Depreciation Value
 1 10,500 2,000 2,000 8,500
 2 10,500 2,000 4,000 6,500
 3 10,500 2,000 6,000 4,500
 4 10,500 2,000 8,000 2,500
 5 10,500 2,000 10,000 0

cost =2,50,000
year cost Depreciation Accumulated Book
Expense Dep value
 1 250000*35% 87,500 87,500 162500
 2 250000*15% 37500 12500 125000
 3 250000*20% 50000 175000 75000
 4 250000*15% 37500 212500 37500
 5 250000*15% 37500 250000 0
MACR’S(Modified Accelerated cost Recovery System)

Here
Year= 6
n=6
n(n+1)/2= 6(6+1)/2= 42/2 =21
Cost= 2,50,000
Also
6+5+4+3+2+1=21
Sum Of the Year By Digit
Method
Cost Depreciation Accumulated Book
Dep value
250000*6/21 71428.57 71428.57 178571.43
250000*5/21 59523.80 130952.37 119047.63
250000*4/21 47619.04 178571.41 71428.59
250000*3/21 35714.28 214285.69 3571.31
250000*2/21 23809.52 238095.21 11904.76
250000*1/21 11904.76 2,50,000 0

Cost of asset = $100,000
Estimated residual value = $10,000
Estimated useful life of asset = 5 years
Depreciation rate = (1/useful life) x 200%
= 1/5 x 200% = 20% x 2 = 40%
Double Declining Balance
Method

Cost Depreciation Accumulated Book
Dep value
100000*40% 40000 40000 60000
60,000*40% 24000 64000 36000
36000*40% 14400 78400 21600
21600*40% 8640 87040 12960
12960*40% 2960(*) 90000 10000
(*)
Depreciation stops when book value=Residual value

Depreciation methods

  • 2.
     Presented By: Sunny Khatana ComputerScience Engg. University Of Gujrat
  • 3.
      A reductionin the value of an asset with the passage of time, due in particular to wear and tear. Defination
  • 4.
    Here The FourMethods are described:  Straight Line Method  MACR’S Method  Double Decline Method  Sum Of The Year Method Methods
  • 5.
     Cost of Asset=10,500 SalvageValue/Residual Value=500 Life years=5 Straight Line Method
  • 6.
     10,000 cost -500 salvage value/5 = 2000 per year year cost Depreciation Accumulated Book Expense Depreciation Value  1 10,500 2,000 2,000 8,500  2 10,500 2,000 4,000 6,500  3 10,500 2,000 6,000 4,500  4 10,500 2,000 8,000 2,500  5 10,500 2,000 10,000 0
  • 7.
     cost =2,50,000 year costDepreciation Accumulated Book Expense Dep value  1 250000*35% 87,500 87,500 162500  2 250000*15% 37500 12500 125000  3 250000*20% 50000 175000 75000  4 250000*15% 37500 212500 37500  5 250000*15% 37500 250000 0 MACR’S(Modified Accelerated cost Recovery System)
  • 8.
     Here Year= 6 n=6 n(n+1)/2= 6(6+1)/2=42/2 =21 Cost= 2,50,000 Also 6+5+4+3+2+1=21 Sum Of the Year By Digit Method
  • 9.
    Cost Depreciation AccumulatedBook Dep value 250000*6/21 71428.57 71428.57 178571.43 250000*5/21 59523.80 130952.37 119047.63 250000*4/21 47619.04 178571.41 71428.59 250000*3/21 35714.28 214285.69 3571.31 250000*2/21 23809.52 238095.21 11904.76 250000*1/21 11904.76 2,50,000 0
  • 10.
     Cost of asset= $100,000 Estimated residual value = $10,000 Estimated useful life of asset = 5 years Depreciation rate = (1/useful life) x 200% = 1/5 x 200% = 20% x 2 = 40% Double Declining Balance Method
  • 11.
     Cost Depreciation AccumulatedBook Dep value 100000*40% 40000 40000 60000 60,000*40% 24000 64000 36000 36000*40% 14400 78400 21600 21600*40% 8640 87040 12960 12960*40% 2960(*) 90000 10000 (*) Depreciation stops when book value=Residual value