The document defines slope as the ratio of the rise (change in y-values) to the run (change in x-values) between two points on a line. It provides the exact formula for calculating slope as the change in y-values divided by the change in x-values. Examples are given to demonstrate calculating the slopes of various lines, with positive slopes for lines passing through Quadrants I and III and negative slopes for lines passing through Quadrants II and IV.
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This Gasta posits a strategic approach to integrating AI into HEIs to prepare staff, students and the curriculum for an evolving world and workplace. We will highlight the advantages of working with these technologies beyond the realm of teaching, learning and assessment by considering prompt engineering skills, industry impact, curriculum changes, and the need for staff upskilling. In contrast, not engaging strategically with Generative AI poses risks, including falling behind peers, missed opportunities and failing to ensure our graduates remain employable. The rapid evolution of AI technologies necessitates a proactive and strategic approach if we are to remain relevant.
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Exploiting Artificial Intelligence for Empowering Researchers and Faculty, In...Dr. Vinod Kumar Kanvaria
Exploiting Artificial Intelligence for Empowering Researchers and Faculty,
International FDP on Fundamentals of Research in Social Sciences
at Integral University, Lucknow, 06.06.2024
By Dr. Vinod Kumar Kanvaria
Model Attribute Check Company Auto PropertyCeline George
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Synthetic fiber production is a fascinating and complex field that blends chemistry, engineering, and environmental science. By understanding these aspects, students can gain a comprehensive view of synthetic fiber production, its impact on society and the environment, and the potential for future innovations. Synthetic fibers play a crucial role in modern society, impacting various aspects of daily life, industry, and the environment. ynthetic fibers are integral to modern life, offering a range of benefits from cost-effectiveness and versatility to innovative applications and performance characteristics. While they pose environmental challenges, ongoing research and development aim to create more sustainable and eco-friendly alternatives. Understanding the importance of synthetic fibers helps in appreciating their role in the economy, industry, and daily life, while also emphasizing the need for sustainable practices and innovation.
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2024.06.01 Introducing a competency framework for languag learning materials ...Sandy Millin
http://sandymillin.wordpress.com/iateflwebinar2024
Published classroom materials form the basis of syllabuses, drive teacher professional development, and have a potentially huge influence on learners, teachers and education systems. All teachers also create their own materials, whether a few sentences on a blackboard, a highly-structured fully-realised online course, or anything in between. Despite this, the knowledge and skills needed to create effective language learning materials are rarely part of teacher training, and are mostly learnt by trial and error.
Knowledge and skills frameworks, generally called competency frameworks, for ELT teachers, trainers and managers have existed for a few years now. However, until I created one for my MA dissertation, there wasn’t one drawing together what we need to know and do to be able to effectively produce language learning materials.
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June 3, 2024 Anti-Semitism Letter Sent to MIT President Kornbluth and MIT Cor...Levi Shapiro
Letter from the Congress of the United States regarding Anti-Semitism sent June 3rd to MIT President Sally Kornbluth, MIT Corp Chair, Mark Gorenberg
Dear Dr. Kornbluth and Mr. Gorenberg,
The US House of Representatives is deeply concerned by ongoing and pervasive acts of antisemitic
harassment and intimidation at the Massachusetts Institute of Technology (MIT). Failing to act decisively to ensure a safe learning environment for all students would be a grave dereliction of your responsibilities as President of MIT and Chair of the MIT Corporation.
This Congress will not stand idly by and allow an environment hostile to Jewish students to persist. The House believes that your institution is in violation of Title VI of the Civil Rights Act, and the inability or
unwillingness to rectify this violation through action requires accountability.
Postsecondary education is a unique opportunity for students to learn and have their ideas and beliefs challenged. However, universities receiving hundreds of millions of federal funds annually have denied
students that opportunity and have been hijacked to become venues for the promotion of terrorism, antisemitic harassment and intimidation, unlawful encampments, and in some cases, assaults and riots.
The House of Representatives will not countenance the use of federal funds to indoctrinate students into hateful, antisemitic, anti-American supporters of terrorism. Investigations into campus antisemitism by the Committee on Education and the Workforce and the Committee on Ways and Means have been expanded into a Congress-wide probe across all relevant jurisdictions to address this national crisis. The undersigned Committees will conduct oversight into the use of federal funds at MIT and its learning environment under authorities granted to each Committee.
• The Committee on Education and the Workforce has been investigating your institution since December 7, 2023. The Committee has broad jurisdiction over postsecondary education, including its compliance with Title VI of the Civil Rights Act, campus safety concerns over disruptions to the learning environment, and the awarding of federal student aid under the Higher Education Act.
• The Committee on Oversight and Accountability is investigating the sources of funding and other support flowing to groups espousing pro-Hamas propaganda and engaged in antisemitic harassment and intimidation of students. The Committee on Oversight and Accountability is the principal oversight committee of the US House of Representatives and has broad authority to investigate “any matter” at “any time” under House Rule X.
• The Committee on Ways and Means has been investigating several universities since November 15, 2023, when the Committee held a hearing entitled From Ivory Towers to Dark Corners: Investigating the Nexus Between Antisemitism, Tax-Exempt Universities, and Terror Financing. The Committee followed the hearing with letters to those institutions on January 10, 202
3. Definition of Slope
Let (x1, y1) and (x2, y2) be two points on a line,
(x1, y1)
(x2, y2)
About Slopes
4. Definition of Slope
Let (x1, y1) and (x2, y2) be two points on a line,
then the slope m of the line is
Δy
Δxm =
(x1, y1)
(x2, y2)
About Slopes
5. Definition of Slope
Let (x1, y1) and (x2, y2) be two points on a line,
then the slope m of the line is
Δy
Δx
y2 – y1
x2 – x1
m = =
(x1, y1)
(x2, y2)
About Slopes
6. Definition of Slope
Let (x1, y1) and (x2, y2) be two points on a line,
then the slope m of the line is
Δy
Δx
y2 – y1
x2 – x1
m = =
Geometry of Slope
(x1, y1)
(x2, y2)
About Slopes
7. Definition of Slope
Let (x1, y1) and (x2, y2) be two points on a line,
then the slope m of the line is
Δy
Δx
y2 – y1
x2 – x1
m = =
(x1, y1)
(x2, y2)
Δy=y2–y1=rise
Geometry of Slope
Δy = y2 – y1 = the difference
in the heights of the points.
About Slopes
8. Definition of Slope
Let (x1, y1) and (x2, y2) be two points on a line,
then the slope m of the line is
Δy
Δx
y2 – y1
x2 – x1
m = =
(x1, y1)
(x2, y2)
Δy=y2–y1=rise
Δx=x2–x1=run
Geometry of Slope
Δy = y2 – y1 = the difference
in the heights of the points.
Δx = x2 – x1 = the difference
in the runs of the points.
About Slopes
9. Definition of Slope
Let (x1, y1) and (x2, y2) be two points on a line,
then the slope m of the line is
Δy
Δx
y2 – y1
x2 – x1
m = =
(x1, y1)
(x2, y2)
Δy=y2–y1=rise
Δx=x2–x1=run
Geometry of Slope
Δy = y2 – y1 = the difference
in the heights of the points.
Δx = x2 – x1 = the difference
in the runs of the points.
Δy
Δx
=Therefore m is the ratio of the “rise” to the “run”.
About Slopes
10. Definition of Slope
Let (x1, y1) and (x2, y2) be two points on a line,
then the slope m of the line is
Δy
Δx
y2 – y1
x2 – x1
m = =
rise
run=
(x1, y1)
(x2, y2)
Δy=y2–y1=rise
Δx=x2–x1=run
Geometry of Slope
Δy = y2 – y1 = the difference
in the heights of the points.
Δx = x2 – x1 = the difference
in the runs of the points.
Δy
Δx
=Therefore m is the ratio of the “rise” to the “run”.
m =
Δy
Δx
y2 – y1
x2 – x1
=
About Slopes
11. Definition of Slope
Let (x1, y1) and (x2, y2) be two points on a line,
then the slope m of the line is
Δy
Δx
y2 – y1
x2 – x1
m = =
rise
run=
(x1, y1)
(x2, y2)
Δy=y2–y1=rise
Δx=x2–x1=run
Geometry of Slope
Δy = y2 – y1 = the difference
in the heights of the points.
Δx = x2 – x1 = the difference
in the runs of the points.
Δy
Δx
=Therefore m is the ratio of the “rise” to the “run”.
m =
Δy
Δx
y2 – y1
x2 – x1
=
easy to
memorize
About Slopes
12. Definition of Slope
Let (x1, y1) and (x2, y2) be two points on a line,
then the slope m of the line is
Δy
Δx
y2 – y1
x2 – x1
m = =
rise
run=
(x1, y1)
(x2, y2)
Δy=y2–y1=rise
Δx=x2–x1=run
Geometry of Slope
Δy = y2 – y1 = the difference
in the heights of the points.
Δx = x2 – x1 = the difference
in the runs of the points.
Δy
Δx
=Therefore m is the ratio of the “rise” to the “run”.
m =
Δy
Δx
y2 – y1
x2 – x1
=
easy to
memorize
the exact
formula
About Slopes
13. Definition of Slope
Let (x1, y1) and (x2, y2) be two points on a line,
then the slope m of the line is
Δy
Δx
y2 – y1
x2 – x1
m = =
rise
run=
(x1, y1)
(x2, y2)
Δy=y2–y1=rise
Δx=x2–x1=run
Geometry of Slope
Δy = y2 – y1 = the difference
in the heights of the points.
Δx = x2 – x1 = the difference
in the runs of the points.
Δy
Δx
=Therefore m is the ratio of the “rise” to the “run”.
m =
Δy
Δx
y2 – y1
x2 – x1
=
easy to
memorize
the exact
formula
geometric
meaning
About Slopes
14. Example A. Find the slope of each of the following lines.
About Slopes
15. Example A. Find the slope of each of the following lines.
Two points are
(–3, 1), (4, 1).
About Slopes
16. Example A. Find the slope of each of the following lines.
Two points are
(–3, 1), (4, 1).
Δy = 1 – (1) = 0
About Slopes
17. Example A. Find the slope of each of the following lines.
Two points are
(–3, 1), (4, 1).
Δy = 1 – (1) = 0
Δx = 4 – (–3) = 7
About Slopes
18. Example A. Find the slope of each of the following lines.
Two points are
(–3, 1), (4, 1).
Δy = 1 – (1) = 0
Δx = 4 – (–3) = 7
About Slopes
m =
Δy
Δx
=
0
7
= 0
19. Example A. Find the slope of each of the following lines.
Two points are
(–3, 1), (4, 1).
Δy = 1 – (1) = 0
Δx = 4 – (–3) = 7
About Slopes
m =
Δy
Δx
=
0
7
Horizontal line
Slope = 0
= 0
20. Example A. Find the slope of each of the following lines.
Two points are
(–2, –4), (2, 3).
Two points are
(–3, 1), (4, 1).
Δy = 1 – (1) = 0
Δx = 4 – (–3) = 7
About Slopes
m =
Δy
Δx
=
0
7
Horizontal line
Slope = 0
= 0
21. Example A. Find the slope of each of the following lines.
Two points are
(–2, –4), (2, 3).
Δy = 3 – (–4) = 7
Two points are
(–3, 1), (4, 1).
Δy = 1 – (1) = 0
Δx = 4 – (–3) = 7
About Slopes
m =
Δy
Δx
=
0
7
Horizontal line
Slope = 0
= 0
22. Example A. Find the slope of each of the following lines.
Two points are
(–2, –4), (2, 3).
Δy = 3 – (–4) = 7
Δx = 2 – (–2) = 4
Two points are
(–3, 1), (4, 1).
Δy = 1 – (1) = 0
Δx = 4 – (–3) = 7
About Slopes
m =
Δy
Δx
=
0
7
Horizontal line
Slope = 0
= 0
23. Example A. Find the slope of each of the following lines.
Two points are
(–2, –4), (2, 3).
Δy = 3 – (–4) = 7
Δx = 2 – (–2) = 4
m =
Two points are
(–3, 1), (4, 1).
Δy = 1 – (1) = 0
Δx = 4 – (–3) = 7
About Slopes
Δy
Δx
=
7
4
m =
Δy
Δx
=
0
7
Horizontal line
Slope = 0
= 0
24. Example A. Find the slope of each of the following lines.
Two points are
(–2, –4), (2, 3).
Δy = 3 – (–4) = 7
Δx = 2 – (–2) = 4
m =
Two points are
(–3, 1), (4, 1).
Δy = 1 – (1) = 0
Δx = 4 – (–3) = 7
About Slopes
Δy
Δx
=
7
4
m =
Δy
Δx
=
0
7
Horizontal line
Slope = 0
Tilted line
Slope = 0
= 0
25. Example A. Find the slope of each of the following lines.
Two points are
(–2, –4), (2, 3).
Δy = 3 – (–4) = 7
Δx = 2 – (–2) = 4
m =
Two points are
(–3, 1), (4, 1).
Δy = 1 – (1) = 0
Δx = 4 – (–3) = 7
Two points are
(–1, 3), (6, 3).
About Slopes
Δy
Δx
=
7
4
m =
Δy
Δx
=
0
7
Horizontal line
Slope = 0
Tilted line
Slope = 0
= 0
26. Example A. Find the slope of each of the following lines.
Two points are
(–2, –4), (2, 3).
Δy = 3 – (–4) = 7
Δx = 2 – (–2) = 4
m =
Two points are
(–3, 1), (4, 1).
Δy = 1 – (1) = 0
Δx = 4 – (–3) = 7
Two points are
(–1, 3), (6, 3).
Δy = 3 – 3 = 0
About Slopes
Δy
Δx
=
7
4
m =
Δy
Δx
=
0
7
Horizontal line
Slope = 0
Tilted line
Slope = 0
= 0
27. Example A. Find the slope of each of the following lines.
Two points are
(–2, –4), (2, 3).
Δy = 3 – (–4) = 7
Δx = 2 – (–2) = 4
m =
Two points are
(–3, 1), (4, 1).
Δy = 1 – (1) = 0
Δx = 4 – (–3) = 7
Two points are
(–1, 3), (6, 3).
Δy = 3 – 3 = 0
Δx = 6 – (–1) = 7
About Slopes
Δy
Δx
=
7
4
m =
Δy
Δx
=
0
7
Horizontal line
Slope = 0
Tilted line
Slope = 0
= 0
28. Example A. Find the slope of each of the following lines.
Two points are
(–2, –4), (2, 3).
Δy = 3 – (–4) = 7
Δx = 2 – (–2) = 4
m =
Two points are
(–3, 1), (4, 1).
Δy = 1 – (1) = 0
Δx = 4 – (–3) = 7
Two points are
(–1, 3), (6, 3).
Δy = 3 – 3 = 0
Δx = 6 – (–1) = 7
About Slopes
Δy
Δx
=
7
4
m =
Δy
Δx
=
0
7
m =
Δy
Δx
=
7
0
Horizontal line
Slope = 0
Tilted line
Slope = 0
= 0 (UDF)
29. Example A. Find the slope of each of the following lines.
Two points are
(–2, –4), (2, 3).
Δy = 3 – (–4) = 7
Δx = 2 – (–2) = 4
m =
Two points are
(–3, 1), (4, 1).
Δy = 1 – (1) = 0
Δx = 4 – (–3) = 7
Two points are
(–1, 3), (6, 3).
Δy = 3 – 3 = 0
Δx = 6 – (–1) = 7
About Slopes
Δy
Δx
=
7
4
m =
Δy
Δx
=
0
7
m =
Δy
Δx
=
7
0
Horizontal line
Slope = 0
Vertical line
Slope is UDF
Tilted line
Slope = 0
= 0 (UDF)
30. Lines that go through the
quadrants I and III have
positive slopes.
About Slopes
31. Lines that go through the
quadrants I and III have
positive slopes.
About Slopes
III
III IV
32. Lines that go through the
quadrants I and III have
positive slopes.
Lines that go through the
quadrants II and IV have
negative slopes.
About Slopes
III
III IV
33. Lines that go through the
quadrants I and III have
positive slopes.
Lines that go through the
quadrants II and IV have
negative slopes.
About Slopes
III
III IV
III
III IV
34. Lines that go through the
quadrants I and III have
positive slopes.
Lines that go through the
quadrants II and IV have
negative slopes.
About Slopes
The formula for slopes requires geometric information,
i.e. the positions of two points on the line.
III
III IV
III
III IV
35. Lines that go through the
quadrants I and III have
positive slopes.
Lines that go through the
quadrants II and IV have
negative slopes.
About Slopes
The formula for slopes requires geometric information,
i.e. the positions of two points on the line.
However, if a line is given by its equation instead, we may
determine the slope from the equation directly.
III
III IV
III
III IV
36. Given a linear equation in x and y, solve for the variable y if
possible, we get y = mx + b
About Slopes
37. Given a linear equation in x and y, solve for the variable y if
possible, we get y = mx + b
the number m is the slope and b is the y-intercept.
About Slopes
38. Given a linear equation in x and y, solve for the variable y if
possible, we get y = mx + b
the number m is the slope and b is the y-intercept.
This is called the slope intercept form and this can be done
only if the y-term is present.
About Slopes
39. Given a linear equation in x and y, solve for the variable y if
possible, we get y = mx + b
the number m is the slope and b is the y-intercept.
This is called the slope intercept form and this can be done
only if the y-term is present.
About Slopes
a. 3x = –2y + 6
Example B. Write the equations into the slope intercept form,
list the slopes, the y-intercepts and draw the lines.
40. Given a linear equation in x and y, solve for the variable y if
possible, we get y = mx + b
the number m is the slope and b is the y-intercept.
This is called the slope intercept form and this can be done
only if the y-term is present.
About Slopes
a. 3x = –2y + 6 solve for y
Example B. Write the equations into the slope intercept form,
list the slopes, the y-intercepts and draw the lines.
41. Given a linear equation in x and y, solve for the variable y if
possible, we get y = mx + b
the number m is the slope and b is the y-intercept.
This is called the slope intercept form and this can be done
only if the y-term is present.
About Slopes
a. 3x = –2y + 6 solve for y
2y = –3x + 6
Example B. Write the equations into the slope intercept form,
list the slopes, the y-intercepts and draw the lines.
42. Given a linear equation in x and y, solve for the variable y if
possible, we get y = mx + b
the number m is the slope and b is the y-intercept.
This is called the slope intercept form and this can be done
only if the y-term is present.
About Slopes
a. 3x = –2y + 6 solve for y
2y = –3x + 6
y =
2
–3 x + 3
Example B. Write the equations into the slope intercept form,
list the slopes, the y-intercepts and draw the lines.
43. Given a linear equation in x and y, solve for the variable y if
possible, we get y = mx + b
the number m is the slope and b is the y-intercept.
This is called the slope intercept form and this can be done
only if the y-term is present.
About Slopes
a. 3x = –2y + 6 solve for y
2y = –3x + 6
y =
2
–3 x + 3
Hence the slope m is –3/2
Example B. Write the equations into the slope intercept form,
list the slopes, the y-intercepts and draw the lines.
44. Given a linear equation in x and y, solve for the variable y if
possible, we get y = mx + b
the number m is the slope and b is the y-intercept.
This is called the slope intercept form and this can be done
only if the y-term is present.
About Slopes
a. 3x = –2y + 6 solve for y
2y = –3x + 6
y =
2
–3 x + 3
Hence the slope m is –3/2
and the y-intercept is (0, 3).
Example B. Write the equations into the slope intercept form,
list the slopes, the y-intercepts and draw the lines.
45. Given a linear equation in x and y, solve for the variable y if
possible, we get y = mx + b
the number m is the slope and b is the y-intercept.
This is called the slope intercept form and this can be done
only if the y-term is present.
About Slopes
Example B. Write the equations into the slope intercept form,
list the slopes, the y-intercepts and draw the lines.
a. 3x = –2y + 6 solve for y
2y = –3x + 6
y =
2
–3 x + 3
Hence the slope m is –3/2
and the y-intercept is (0, 3).
Set y = 0, we get the x-intercept
(2, 0).
46. Given a linear equation in x and y, solve for the variable y if
possible, we get y = mx + b
the number m is the slope and b is the y-intercept.
This is called the slope intercept form and this can be done
only if the y-term is present.
About Slopes
a. 3x = –2y + 6 solve for y
2y = –3x + 6
y =
2
–3 x + 3
Hence the slope m is –3/2
and the y-intercept is (0, 3).
Set y = 0, we get the x-intercept
(2, 0). Use these points to draw
the line.
Example B. Write the equations into the slope intercept form,
list the slopes, the y-intercepts and draw the lines.
47. Given a linear equation in x and y, solve for the variable y if
possible, we get y = mx + b
the number m is the slope and b is the y-intercept.
This is called the slope intercept form and this can be done
only if the y-term is present.
About Slopes
a. 3x = –2y + 6 solve for y
2y = –3x + 6
y =
2
–3 x + 3
Hence the slope m is –3/2
and the y-intercept is (0, 3).
Set y = 0, we get the x-intercept
(2, 0). Use these points to draw
the line.
Example B. Write the equations into the slope intercept form,
list the slopes, the y-intercepts and draw the lines.
50. b. 0 = –2y + 6 solve for y
2y = 6
y = 3
About Slopes
51. b. 0 = –2y + 6 solve for y
2y = 6
y = 3
y = 0x + 3
About Slopes
52. b. 0 = –2y + 6 solve for y
2y = 6
y = 3
y = 0x + 3
Hence the slope m is 0.
About Slopes
53. b. 0 = –2y + 6 solve for y
2y = 6
y = 3
y = 0x + 3
Hence the slope m is 0.
The y-intercept is (0, 3).
About Slopes
54. b. 0 = –2y + 6 solve for y
2y = 6
y = 3
y = 0x + 3
Hence the slope m is 0.
The y-intercept is (0, 3).
There is no x-intercept.
About Slopes
55. b. 0 = –2y + 6 solve for y
2y = 6
y = 3
y = 0x + 3
Hence the slope m is 0.
The y-intercept is (0, 3).
There is no x-intercept.
About Slopes
56. b. 0 = –2y + 6 solve for y
2y = 6
y = 3
y = 0x + 3
Hence the slope m is 0.
The y-intercept is (0, 3).
There is no x-intercept.
c. 3x = 6
About Slopes
57. b. 0 = –2y + 6 solve for y
2y = 6
y = 3
y = 0x + 3
Hence the slope m is 0.
The y-intercept is (0, 3).
There is no x-intercept.
c. 3x = 6
About Slopes
The variable y can’t be
isolated because there is no y.
58. b. 0 = –2y + 6 solve for y
2y = 6
y = 3
y = 0x + 3
Hence the slope m is 0.
The y-intercept is (0, 3).
There is no x-intercept.
c. 3x = 6
About Slopes
The variable y can’t be
isolated because there is no y.
Hence the slope is undefined
and this is a vertical line.
59. b. 0 = –2y + 6 solve for y
2y = 6
y = 3
y = 0x + 3
Hence the slope m is 0.
The y-intercept is (0, 3).
There is no x-intercept.
c. 3x = 6
About Slopes
The variable y can’t be
isolated because there is no y.
Hence the slope is undefined
and this is a vertical line.
Solve for x
3x = 6 x = 2.
60. b. 0 = –2y + 6 solve for y
2y = 6
y = 3
y = 0x + 3
Hence the slope m is 0.
The y-intercept is (0, 3).
There is no x-intercept.
c. 3x = 6
About Slopes
The variable y can’t be
isolated because there is no y.
Hence the slope is undefined
and this is a vertical line.
Solve for x
3x = 6 x = 2.
This is the vertical line x = 2.
61. b. 0 = –2y + 6 solve for y
2y = 6
y = 3
y = 0x + 3
Hence the slope m is 0.
The y-intercept is (0, 3).
There is no x-intercept.
c. 3x = 6
About Slopes
The variable y can’t be
isolated because there is no y.
Hence the slope is undefined
and this is a vertical line.
Solve for x
3x = 6 x = 2.
This is the vertical line x = 2.
62. Two Facts About Slopes
I. Parallel lines have the same slope.
About Slopes
63. Two Facts About Slopes
I. Parallel lines have the same slope.
II. Slopes of perpendicular lines are the negative reciprocal of
each other.
About Slopes
64. Two Facts About Slopes
I. Parallel lines have the same slope.
II. Slopes of perpendicular lines are the negative reciprocal of
each other.
Example C.
a. The line L is parallel to 4x – 2y = 5, what is the slope of L?
About Slopes
65. Two Facts About Slopes
I. Parallel lines have the same slope.
II. Slopes of perpendicular lines are the negative reciprocal of
each other.
Example C.
a. The line L is parallel to 4x – 2y = 5, what is the slope of L?
Solve for y for 4x – 2y = 5
About Slopes
66. Two Facts About Slopes
I. Parallel lines have the same slope.
II. Slopes of perpendicular lines are the negative reciprocal of
each other.
Example C.
a. The line L is parallel to 4x – 2y = 5, what is the slope of L?
Solve for y for 4x – 2y = 5
4x – 5 = 2y
About Slopes
67. Two Facts About Slopes
I. Parallel lines have the same slope.
II. Slopes of perpendicular lines are the negative reciprocal of
each other.
Example C.
a. The line L is parallel to 4x – 2y = 5, what is the slope of L?
Solve for y for 4x – 2y = 5
4x – 5 = 2y
2x – 5/2 = y
About Slopes
68. Two Facts About Slopes
I. Parallel lines have the same slope.
II. Slopes of perpendicular lines are the negative reciprocal of
each other.
Example C.
a. The line L is parallel to 4x – 2y = 5, what is the slope of L?
Solve for y for 4x – 2y = 5
4x – 5 = 2y
2x – 5/2 = y
So the slope of 4x – 2y = 5 is 2.
About Slopes
69. Two Facts About Slopes
I. Parallel lines have the same slope.
II. Slopes of perpendicular lines are the negative reciprocal of
each other.
Example C.
a. The line L is parallel to 4x – 2y = 5, what is the slope of L?
Solve for y for 4x – 2y = 5
4x – 5 = 2y
2x – 5/2 = y
So the slope of 4x – 2y = 5 is 2.
Since L is parallel to it , so L has slope 2 also.
About Slopes
70. Two Facts About Slopes
I. Parallel lines have the same slope.
II. Slopes of perpendicular lines are the negative reciprocal of
each other.
Example C.
a. The line L is parallel to 4x – 2y = 5, what is the slope of L?
Solve for y for 4x – 2y = 5
4x – 5 = 2y
2x – 5/2 = y
So the slope of 4x – 2y = 5 is 2.
Since L is parallel to it , so L has slope 2 also.
About Slopes
b. What is the slope of L if L is perpendicular to 3x = 2y + 4?
71. Two Facts About Slopes
I. Parallel lines have the same slope.
II. Slopes of perpendicular lines are the negative reciprocal of
each other.
Example C.
a. The line L is parallel to 4x – 2y = 5, what is the slope of L?
Solve for y for 4x – 2y = 5
4x – 5 = 2y
2x – 5/2 = y
So the slope of 4x – 2y = 5 is 2.
Since L is parallel to it , so L has slope 2 also.
About Slopes
b. What is the slope of L if L is perpendicular to 3x = 2y + 4?
Solve for y to find the slope of 3x – 4 = 2y
72. Two Facts About Slopes
I. Parallel lines have the same slope.
II. Slopes of perpendicular lines are the negative reciprocal of
each other.
Example C.
a. The line L is parallel to 4x – 2y = 5, what is the slope of L?
Solve for y for 4x – 2y = 5
4x – 5 = 2y
2x – 5/2 = y
So the slope of 4x – 2y = 5 is 2.
Since L is parallel to it , so L has slope 2 also.
About Slopes
b. What is the slope of L if L is perpendicular to 3x = 2y + 4?
Solve for y to find the slope of 3x – 4 = 2y
x – 2 = y2
3
73. Two Facts About Slopes
I. Parallel lines have the same slope.
II. Slopes of perpendicular lines are the negative reciprocal of
each other.
Example C.
a. The line L is parallel to 4x – 2y = 5, what is the slope of L?
Solve for y for 4x – 2y = 5
4x – 5 = 2y
2x – 5/2 = y
So the slope of 4x – 2y = 5 is 2.
Since L is parallel to it , so L has slope 2 also.
About Slopes
b. What is the slope of L if L is perpendicular to 3x = 2y + 4?
Solve for y to find the slope of 3x – 4 = 2y
x – 2 = y
Hence the slope of 3x = 2y + 4 is .
2
3
2
3
74. Two Facts About Slopes
I. Parallel lines have the same slope.
II. Slopes of perpendicular lines are the negative reciprocal of
each other.
Example C.
a. The line L is parallel to 4x – 2y = 5, what is the slope of L?
Solve for y for 4x – 2y = 5
4x – 5 = 2y
2x – 5/2 = y
So the slope of 4x – 2y = 5 is 2.
Since L is parallel to it , so L has slope 2 also.
About Slopes
b. What is the slope of L if L is perpendicular to 3x = 2y + 4?
Solve for y to find the slope of 3x – 4 = 2y
x – 2 = y
Hence the slope of 3x = 2y + 4 is .
So L has slope –2/3 since L is perpendicular to it.
2
3
2
3
75. Summary on Slopes
How to Find Slopes
I. If two points on the line are given, use the slope formula
II. If the equation of the line is given, solve for the y and get
slope intercept form y = mx + b, then the number m is
the slope.
Geometry of Slope
The slope of tilted lines are nonzero.
Lines with positive slopes connect quadrants I and III.
Lines with negative slopes connect quadrants II and IV.
Lines that have slopes with large absolute values are steep.
The slope of a horizontal line is 0.
A vertical lines does not have slope or that it’s UDF.
Parallel lines have the same slopes.
Perpendicular lines have the negative reciprocal slopes of
each other.
rise
run=m =
Δy
Δx
y2 – y1
x2 – x1
=
76. Exercise A. Identify the vertical and the horizontal lines by
inspection first. Find their slopes or if it’s undefined, state so.
Fine the slopes of the other ones by solving for the y.
1. x – y = 3 2. 2x = 6 3. –y – 7= 0
4. 0 = 8 – 2x 5. y = –x + 4 6. 2x/3 – 3 = 6/5
7. 2x = 6 – 2y 8. 4y/5 – 12 = 3x/4 9. 2x + 3y = 3
10. –6 = 3x – 2y 11. 3x + 2 = 4y + 3x 12. 5x/4 + 2y/3 = 2
Exercise B.
13–18. Select two points and estimate the slope of each line.
13. 14. 15.
About Slopes
77. 16. 17. 18.
Exercise C. Draw and find the slope of the line that passes
through the given two points. Identify the vertical line and the
horizontal lines by inspection first.
19. (0, –1), (–2, 1) 20. (1, –2), (–2, 0) 21. (1, –2), (–2, –1)
22. (3, –1), (3, 1) 23. (1, –2), (–2, 3) 24. (2, –1), (3, –1)
25. (4, –2), (–3, 1) 26. (4, –2), (4, 0) 27. (7, –2), (–2, –6)
28. (3/2, –1), (3/2, 1) 29. (3/2, –1), (1, –3/2)
30. (–5/2, –1/2), (1/2, 1) 31. (3/2, 1/3), (1/3, 1/3)
32. (–2/3, –1/4), (1/2, 2/3) 33. (3/4, –1/3), (1/3, 3/2)
About Slopes
78. Exercise D.
34. Identify which lines are parallel and which one are
perpendicular.
A. The line that passes through (0, 1), (1, –2)
D. 2x – 4y = 1
B. C.
E. The line that’s perpendicular to 3y = x
F. The line with the x–intercept at 3 and y intercept at 6.
Find the slope, if possible of each of the following lines.
35. The line passes with the x intercept at x = 2,
and y–intercept at y = –5.
About Slopes
79. 36. The equation of the line is 3x = –5y+7
37. The equation of the line is 0 = –5y+7
38. The equation of the line is 3x = 7
39. The line is parallel to 2y = 5 – 6x
40. the line is perpendicular to 2y = 5 – 6x
41. The line is parallel to the line in problem 30.
42. the line is perpendicular to line in problem 31.
43. The line is parallel to the line in problem 33.
44. the line is perpendicular to line in problem 34.
About Slopes
Find the slope, if possible of each of the following lines