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CCOOUURRSSEE:: CCEE 220011 ((SSTTAATTIICCSS)) 
LLEECCTTUURREE NNOO..:: 0077 
FFAACCUULLTTYY:: DDRR.. SSHHAAMMSSHHAADD 
AAHHMMAADD DDEEPPAARRTTMMEENNTT:: CCIIVVIILL 
EENNGGIINNEEEERRIINNGG 
UUNNIIVVEERRSSIITTYY:: KKIINNGG FFAAHHDD UUNNIIVVEERRSSIITTYY OOFF 
PPEETTRROOLLEEUUMM 
&& MMIINNEERRAALLSS,, DDHHAAHHRRAANN,, SSAAUUDDII 
AARRAABBIIAA
TTEEXXTT BBOOOOKK:: EENNGGIINNEEEERRIINNGG MMEECCHHAANNIICCSS--SSTTAATTIICCSS 
bbyy RR..CC.. HHIIBBBBEELLEERR,, PPRREENNTTIICCEE HHAALLLL
LLEECCTTUURREE NNOO.. 77 
EEQQUUIILLIIBBRRIIUUMM OOFF AA PPAARRTTIICCLLEE AANNDD FFRREEEE--BBOODDYY 
DDIIAAGGRRAAMM 
OObbjjeeccttiivveess:: 
► TToo ddeeffiinnee tthhee eeqquuiilliibbrriiuumm ooff aa ppaarrttiiccllee 
► TToo eexxppllaaiinn tthhee ccoonnddiittiioonn ffoorr eeqquuiilliibbrriiuumm ooff aa 
ppaarrttiiccllee 
► To eexxppllaaiinn tthhee ccoonncceepptt ooff ffrreeee--bbooddyy ddiiaaggrraamm 
ffoorr 
aa particle
DDEEFFIINNIITTIIOONN OOFF EEQQUUIILLIIBBRRIIUUMM OOFF AA 
PPAARRTTIICCLLEE 
A particle is said to be in equilibrium: 
1. provided it is at rest if originally at rest, or 
2. particle has constant velocity if originally in 
motion
CCOONNDDIITTIIOONNSS FFOORR EEQQUUIILLIIBBRRIIUUMM OOFF AA 
PPAARRTTIICCLLEE 
According to the Newton’s First Law, which 
states that “a particle originally at rest will 
remain in rest condition if resultant force acting 
on the particle is zero”, the condition for 
equilibrium can be obtained by summing up all 
the forces algebraically and equating the sum to 
zero, as follows: ΣF = 0
CCOONNNNEECCTTIIOONNSS OOFFTTEENN 
EENNCCOOUUNNTTEERREEDD IINN PPAARRTTIICCLLEE 
EEQQUUIILLIIBBRRIIUUMM PPRROOBBLLEEMMSS 
(i) Springs 
When a force (F) is applied to a linear elastic spring 
having stiffness k (also called spring constant), there 
will be change in the length of spring (s) in direct 
proportion to the applied force, as follows: F = ks 
For example, the force required to stretch or 
compress the spring, as shown in the following figure, 
is given as: F = ks = 500 × 0.2 = 100 N
CCOONNNNEECCTTIIOONNSS OOFFTTEENN 
EENNCCOOUUNNTTEERREEDD IINN PPAARRTTIICCLLEE 
EEQQUUIILLIIBBRRIIUUMM PPRROOBBLLEEMMSS 
(ii) Cables and Pulleys 
Let us consider a cable subjected to tension T and 
passing over a pulley, as shown in the following 
figure: 
For the cable and pulley system, as shown in the 
above figure, the following points may be noted: 
• Cable is assumed to have negligible weight and 
they cannot stretch 
• A cable may support only a tensile force, T, and 
this force always acts in the direction of the cable 
• For any θ value, the cable is subjected to a 
constant tensile force T throughout its length.
PPRROOCCEEDDUURREE FFOORR 
DDRRAAWWIINNGG AA FFRREEEE--BBOODDYY 
DDIIAAGGRRAAMM 
Free-body diagram of a given system is required to apply 
the equilibrium conditions for analysis of the system. 
Following steps are adopted for drawing free-body 
diagrams: 
• Draw outlined shape of the given system 
• Isolate or cut “free” the particle from its surroundings and 
the sketch of the particle 
Show all known and unknown forces 
• Indicat 
e 
all the forces acting on the particle, on the sketch 
each force
• Label the magnitudes and the directions of all the known 
and unknown forces acting on the particle
PPRROOBBLLEEMM SSOOLLVVIINNGG:: EExxaammppllee 
## 11
PPRROOBBLLEEMM SSOOLLVVIINNGG:: EExxaammppllee 
## 22
PPRROOBBLLEEMM SSOOLLVVIINNGG:: EExxaammppllee 
## 33
Multiple Choice Problems 
1. A 0.7 m long spring having stiffness k = 400 N/m 
is subjected to tensile force of 200 N. The length 
of the spring after applying load will be 
(a) 0.2 m (b) 0.5 m 
(c) 0.7 m (d) 1.2 m 
Ans: (d) 
Feedback: 
For a spring, we have: 
F = ks 
⇒ s = 
F 
k = 
200 
400 = 0.5 m 
The length of the spring after applying load 
= 0.7 + 0.5 = 1.2 m
Multiple Choice Problems 
2. If angle θ is 30° for the cable passing over a pulley, 
as shown in the figure below, the tension T in the 
cable will be 
(a) 0 (b) 600 N 
(c) 693 N (d) 1200N 
Ans: (b) 
Feedback: 
Since the same cable is passing over a pulley, the 
tension at any location of the cable will remain 
same irrespective of the orientation of the cable.

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2 handouts-lecture-7

  • 1. CCOOUURRSSEE:: CCEE 220011 ((SSTTAATTIICCSS)) LLEECCTTUURREE NNOO..:: 0077 FFAACCUULLTTYY:: DDRR.. SSHHAAMMSSHHAADD AAHHMMAADD DDEEPPAARRTTMMEENNTT:: CCIIVVIILL EENNGGIINNEEEERRIINNGG UUNNIIVVEERRSSIITTYY:: KKIINNGG FFAAHHDD UUNNIIVVEERRSSIITTYY OOFF PPEETTRROOLLEEUUMM && MMIINNEERRAALLSS,, DDHHAAHHRRAANN,, SSAAUUDDII AARRAABBIIAA
  • 2. TTEEXXTT BBOOOOKK:: EENNGGIINNEEEERRIINNGG MMEECCHHAANNIICCSS--SSTTAATTIICCSS bbyy RR..CC.. HHIIBBBBEELLEERR,, PPRREENNTTIICCEE HHAALLLL
  • 3. LLEECCTTUURREE NNOO.. 77 EEQQUUIILLIIBBRRIIUUMM OOFF AA PPAARRTTIICCLLEE AANNDD FFRREEEE--BBOODDYY DDIIAAGGRRAAMM OObbjjeeccttiivveess:: ► TToo ddeeffiinnee tthhee eeqquuiilliibbrriiuumm ooff aa ppaarrttiiccllee ► TToo eexxppllaaiinn tthhee ccoonnddiittiioonn ffoorr eeqquuiilliibbrriiuumm ooff aa ppaarrttiiccllee ► To eexxppllaaiinn tthhee ccoonncceepptt ooff ffrreeee--bbooddyy ddiiaaggrraamm ffoorr aa particle
  • 4. DDEEFFIINNIITTIIOONN OOFF EEQQUUIILLIIBBRRIIUUMM OOFF AA PPAARRTTIICCLLEE A particle is said to be in equilibrium: 1. provided it is at rest if originally at rest, or 2. particle has constant velocity if originally in motion
  • 5. CCOONNDDIITTIIOONNSS FFOORR EEQQUUIILLIIBBRRIIUUMM OOFF AA PPAARRTTIICCLLEE According to the Newton’s First Law, which states that “a particle originally at rest will remain in rest condition if resultant force acting on the particle is zero”, the condition for equilibrium can be obtained by summing up all the forces algebraically and equating the sum to zero, as follows: ΣF = 0
  • 6. CCOONNNNEECCTTIIOONNSS OOFFTTEENN EENNCCOOUUNNTTEERREEDD IINN PPAARRTTIICCLLEE EEQQUUIILLIIBBRRIIUUMM PPRROOBBLLEEMMSS (i) Springs When a force (F) is applied to a linear elastic spring having stiffness k (also called spring constant), there will be change in the length of spring (s) in direct proportion to the applied force, as follows: F = ks For example, the force required to stretch or compress the spring, as shown in the following figure, is given as: F = ks = 500 × 0.2 = 100 N
  • 7. CCOONNNNEECCTTIIOONNSS OOFFTTEENN EENNCCOOUUNNTTEERREEDD IINN PPAARRTTIICCLLEE EEQQUUIILLIIBBRRIIUUMM PPRROOBBLLEEMMSS (ii) Cables and Pulleys Let us consider a cable subjected to tension T and passing over a pulley, as shown in the following figure: For the cable and pulley system, as shown in the above figure, the following points may be noted: • Cable is assumed to have negligible weight and they cannot stretch • A cable may support only a tensile force, T, and this force always acts in the direction of the cable • For any θ value, the cable is subjected to a constant tensile force T throughout its length.
  • 8. PPRROOCCEEDDUURREE FFOORR DDRRAAWWIINNGG AA FFRREEEE--BBOODDYY DDIIAAGGRRAAMM Free-body diagram of a given system is required to apply the equilibrium conditions for analysis of the system. Following steps are adopted for drawing free-body diagrams: • Draw outlined shape of the given system • Isolate or cut “free” the particle from its surroundings and the sketch of the particle Show all known and unknown forces • Indicat e all the forces acting on the particle, on the sketch each force
  • 9. • Label the magnitudes and the directions of all the known and unknown forces acting on the particle
  • 13. Multiple Choice Problems 1. A 0.7 m long spring having stiffness k = 400 N/m is subjected to tensile force of 200 N. The length of the spring after applying load will be (a) 0.2 m (b) 0.5 m (c) 0.7 m (d) 1.2 m Ans: (d) Feedback: For a spring, we have: F = ks ⇒ s = F k = 200 400 = 0.5 m The length of the spring after applying load = 0.7 + 0.5 = 1.2 m
  • 14. Multiple Choice Problems 2. If angle θ is 30° for the cable passing over a pulley, as shown in the figure below, the tension T in the cable will be (a) 0 (b) 600 N (c) 693 N (d) 1200N Ans: (b) Feedback: Since the same cable is passing over a pulley, the tension at any location of the cable will remain same irrespective of the orientation of the cable.