Padeye design calculation
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The document provides guidelines for padeye design and calculations for lifting attachments. It states that padeyes shall be designed for at least 5% of the design load applied laterally and that permissible stresses shall follow AISC standards with additional requirements limiting through-thickness stresses to 0.2 times the yield strength if the material does not have through-thickness properties. It then provides examples of calculations for padeye design including shear stress, tension stress, weld shear stress, and dimensional requirements.
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Padeye calculation example
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DESIGN OF A MODEL HAULAGE TECHNIQUE FOR WATER FLOODING CAISSON ASSEMBLY.
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. Secondly, by providing solutions to sea fastening for the caisson on the deck of the crane barge, which was modeled using STAADPRO, which involved support designs and loss of support designs, so as to accommodate for the hydrodynamic effect while the caisson is being transported by the crane barge, having in mind that the crane barge chosen will adequately accommodate the caisson because of the deck space required to fit the 63m long caisson, from the analysis the Caisson is supported by steel beams spaced at 10 m interval which is fastened with the aid of a clamp as seen in the detailed drawings, this caisson and beam supports are modeled with staadpro software and support reactions obtained. These supports are now spaced at 20 m intervals and analyzed to simulate a situation where there is a loss of support reaction during transportation of the caisson. A saddle clamp is to joined to a H beam for support to hold it to the deck at varying length and at the starting point a pivot made from a pad eye joined with a pin to connect the saddle clamp to allow for easy lifting of the caisson when it is at 25m to the FPSO.
Determination of Contact Stress Distribution in Pin Loaded Orthotropic Plates
This document summarizes the analysis and results of determining stress distribution in an orthotropic plate loaded by a pin. The analysis considers the plate to be orthotropic and accounts for clearance between the pin and plate as well as friction. Contact angle, stresses, and their variation with materials, friction, and clearance are determined and presented. Key conclusions are that contact angle and stresses are affected by friction and clearance.
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- Initial results show an LI over 1, indicating risk of back pain. The layout is revised by adjusting task variables like shorter distances and lower frequency.
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(1) The document provides calculations to determine the required base plate thickness for a column base connection according to Eurocode standards. It includes input parameters such as column forces, material properties, bolt sizes and locations.
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(3) The calculated pressure and bolt tension exceed design values, requiring a redesign of the base plate length/width or use of higher strength concrete.
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Tutorial #1 - SACS Basic
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Padeye design calculation
- 2. PTS 34.19.10.30 ( Appendix IX ) • In lifting attachment design load the padeye shall be designed for lateral load of a least 5% of this load. • Permissible stresses shall be as defined in AISC with following additional requirements : - Transfer of stresses through the thickness of the plate shall not be allowed unless the material has through thickness properties. In this instance through thickness stresses shall be limited to 0.2 Fy. TOPSIDE
- 3. 1.1 Design Calculation Example1 = (MBL / Sling MBL) TOPSIDE
- 4. O.75 X Use min value 35 : 45 O.75 X TOPSIDE Use min value 25 : 26.25
- 5. =((radius of main plate-(pin hole/2))*(tm) +(radius cheekplate1-(pin hole/2))*tce*2+(radius cheekplate2 -(pin hole/2))*tc2e*2)*2 = shear stress / Allowable shear stress =2*(2* radius of cheekplate(1)* tce)+2*(2* radius of cheek plate(2)* tc2e)+(radius of main plate*2* (tm))-2* pin hole* (tm) = Max static sling load *1000/ Area at tension failure =Tension stress / Allowable tensile stress =(tce/((tm) +2* tce+2* tc2e))* Max static sling load = F * 1000 / Aw = 0.7* (tc) = shear stress at weld / Allowable shear stress = ([B]-((tm) +2* 0.75tm+2* tc2e))/2 = 0.1*[B] = 0.2*[B]
- 6. TOPSIDE
- 7. TOPSIDE