Chapter 2          Stress and Strain


         -- Axial Loading
Statics – deals with undeformable bodies (Rigid bodies)
Mechanics of Materials – deals with deformable bodies
       -- Need to know the deformation of a boy under
              various stress/strain state
       -- Allowing us to computer forces for statically
              indeterminate problems.
The following subjects will be discussed:

• Stress-Strain Diagrams
• Modulus of Elasticity
• Brittle vs Ductile Fracture
• Elastic vs Plastic Deformation
• Bulk Modulus and Modulus of Rigidity

• Isotropic vs Orthotropic Properties
• Stress Concentrations
• Residual Stresses
2.2 Normal Strain under Axial Loading


                         δ
     ε = normal strain =
                         L

For variable cross-sectional area A,
strain at Point Q is:

               ∆δ d δ
    ε = lim       =
        ∆x → 0 ∆x   dx

 The normal Strain is dimensionless.
2.3 Stress-Strain Diagram
Ductile Fracture   Brittle Fracture
Some Important Concepts and Terminology:

  1. Elastic Modulus

  2. Yield Strength – lower and upper Y.S. -- σ y

          0.2% Yield Strength
  3. Ultimate Strength, σ ut

  4. Breaking Strength or Fracture Strength

  5. Necking

  6. Reduction in Area

  7. Toughness – the area under the σ-ε curve

  8. Percent Elongation
  9. Proportional Limit
2.3 Stress-Strain Diagram

                               LB − Lo
     Percent elongation = 100%
                                 Lo
                                 A0 − AB
Percent reduction in area = 100%
                                    Ao
2.4 True Stress and True Strain

Eng. Stress = P/Ao       True Stress = P/A
    Ao = original area    A = instantaneous area

                δ
Eng. Strain =            True Strain =   ε t = Σ∆ε = Σ( ∆L / L)
                Lo
  Lo = original length        L = instantaneous length



         dL
         L       L
εt = ∫      = ln           (2.3)
       Lo L      Lo
2.5 Hooke's Law: Modulus of Elasticity



    σ = Eε                            (2.4)

           Where E = modulus of elasticity or Young’s



            modulus
Isotropic = material properties do not vary with


Anisotropic = material properties vary with direction or
direction or orientation.

E.g.: metals E.g.: wood, composites
orientation.
2.6 Elastic Versus Plastic Behavior of a Material




        2
Some Important Concepts:

  1. Recoverable Strain
  2. Permanent Strain – Plastic Strain
  3. Creep

  4. Bauschinger Effect:   the early yielding behavior in the
                           compressive loading
2.7 Repeated Loadings: Fatigue


Fatigue failure generally occurs at a stress level that is much

lower than σ y
 The σ -N curve = stress vs life curve

The Endurance Limit = the stress for which fatigue failure
                      does not occur.
2.8 Deformations of Members under Axial Loading

      σ = Eε                      (2.4)

          σ     P
      ε =    =                    (2.5)
          E    AE
      δ = εL                      (2.6)

          PL
      δ =               (For Homogeneous rods)
          AE
                Pi Li
      δ =   ∑
            i   A Ei
                               (For various-section rods)
                 i


                   Pdx
      d δ = ε dx =                    (For variable cross-section rods)
                   AE
P
L   Pdx
          ∫
                          (2.9)
 δ =
           o      AE

                     PL
δ B/ A   = δB − δA =              (2.10)
                     AE
2.9 Statically Indeterminate Problems

A. Statically Determinate Problems:
        -- Problems that can be solved by Statics, i.e. ΣF = 0
                           and ΣM = 0 & the FBD

B. Statically Indeterminate Problems:
        -- Problems that cannot be solved by Statics
       -- The number of unknowns > the number of equations
       -- Must involve “deformation”


Example 2.02:
Example 2.02




               δ1 = δ 2
Superposition Method for Statically
Indeterminate Problems

  1. Designate one support as redundant support

  2. Remove the support from the structure & treat it as
        an unknown load.
  3. Superpose the displacement

  Example 2.04
Example 2.04
δ = δL + δR = 0
2.10   Problems Involving Temperature Changes

 δ T = α ( ∆T ) L   2(.21)


   α = coefficient of thermal
         expansion


               δT + δP = 0

                    ε T = α∆T       δ T = α ( ∆T ) L
                                           PL
                                    δP   =
                                           AE
                                             PL
                δ = δ T + δ P = α ( ∆T ) L +    =0
                                             AE
Therefore:

         P = − AEα ( ∆T )

           P
        σ = = − Eα ( ∆T )
           A
2.11 Poisson 's Ratio


        εx =σx / E

                          lateral strain
υ = Poisson ' s Ratio = −
                           axial strain
         εy   εz
     υ= − = −
         εx   εx

          σ                      υσ
      ε =    X
                        ε =ε = −      X

        x
          E              y   z
                                  E
2.12 Multiaxial Loading: Generalized Hooke's Law




   • Cubic → rectangular parallelepiped

   • Principle of Superposition:
           -- The combined effect = Σ (individual effect)

   Binding assumptions:
          1. Each effect is linear
          2. The deformation is small and does not
   change         the overall condition of the body.
2.12 Multiaxial Loading: Generalized Hooke's Law

Generalized Hooke’s Law

         σ x υσ y υσ z
  εx = +     −     −
          E     E     E
         υσ x σ y υσ z
  εy = −      +    −                   (2.28)
          E     E     E
         υσ x υσ y σ z
  εz = −      −     +
          E      E    E

 Homogeneous Material -- has identical properties at all points.

 Isotropic Material -- material properties do not vary with
 direction                         or orientation.
2.13 Dilation: Bulk Modulus
Original volume = 1 x 1 x 1 = 1

Under the multiaxial stress: σ x, σ y, σ z

The new volume =     υ = (1 + ε x )(1 + ε y )(1 + ε z )


Neglecting the high order terms yields:

           υ =1+ εx + ε y + εz

 e = the hange of olume = υ − 1 = 1 + ε x + ε y + ε z − 1


      ∴e = ε x + ε y + εz                    ( 2.30)
e = dilation = volume strain = change in volume/unit volume

 Eq. (2.28) → Eq. (2-30)

    σ X + σy + σz   2υ (σ X + σ y + σ z )
e =               −                                               (2.31)
          E                  E

   1 − 2υ
e=        (σ X + σ y + σ z )
      E
Special case: hydrostatic pressure -- σx, σy, σz = p
          3(1 − 2υ )                             E
   e= −              p         Define: κ =                    (2.33)
              E                              3(1 − 2υ )
        p
   e= −              (2.33)
        κ
   κ = bulk modulus = modulus of compression              +
E
Since κ = positive,
                                    κ=
                                       3(1 − 2υ )

  (1 - 2υ) > 0              1>2υ              υ <½

  Therefore, 0 < υ < ½

                       3               E
       υ= 0       e= −
                       E
                         p          κ=
                                       3
                       3(1 − 2υ )                    κ =∞   e=0
       υ =½       e= −
                           E
                                  p    =0
             -- Perfectly incompressible materials
2.14 Shearing Strain

  If shear stresses are present




  Shear Strain =       γ xy       (In radians)
         τ xy = G γ xy                           (2.36)

         τ yz = G γ yz τ zx = G γ zx             (2.37)
The Generalized Hooke’s Law:

              σ X υσ y υσ z
       εx = +     −     −
               E     E     E
              υσ X σ y υσ z
       εy = −      +    −
               E     E     E
              υσ X υσ y σ z
       εz = −      −     +
               E      E    E

                τ xy            τ yz            τ zx
       γ xy   =        γ yz   =        γ zx   =
                 G               G               G
2.18 Further Discussion of Deformation under Axial Loading:
              Relation Among E, υ, and G


            E
              =1+υ
           2G


                  E
            G=
               2(1 + υ )
Saint-Venant’s Principle:
      -- the localized effects caused by any load acting on the
               body will dissipate or smooth out within region
               that are sufficiently removed form the location of
               he load.
2.16 Stress-Strain Relationships for Fiber-Reinforced
              Composite Materials

     -- orthotropic materials

                    εy                   εz
           υ xy = −         and υ xz = −
                    εx                   εx

                  σ X υ xyσ y υ zxσ z
           εx = +    −       −
                  Ex    Ey      Ez
                  υ xyσ X σ y υ zxσ z
           εy = −        +    −
                    Ex     Ey   Ez
                  υ xyσ X υ yzσ y σ z
           εz = −        −       +
                    Ex      Ey     Ez
υ xy υ yx υ yz υ zy υ zx υ xz
    =         =         =
E x E y E y Ez Ez E x


         τ xy        τ yz        τ zx
γ xy   =      γ yz =      γ zx =
          G           G           G
2.17 Stress and Strain Distribution Under Axial Loading:
       Saint-Venant's Principle


 If the stress distribution is uniform:

                               P
           σ y = (σ y )ave   =
                               A

 In reality:
2.18 Stress Concentrations
    -- Stress raiser at locations where geometric discontinuity occurs




                σ max
             K=               = Stress Concentration Factor
                σ ave
2.19 Plastic Deformation

  Elastic Deformation → Plastic Deformation

                        →Elastoplastic behavior


          σ
         σy    Y    C
                                Rupture




                                   ε
          A    D
For σ max < σ Y
         σ max                  σ max
    K=                σ ave =
         σ ave                   K
                      σ max A
    P = σ ave A =
                        K

For σ max = σ Y

            σY A
     PY =
             K


For σ ave = σ Y

      PU = σ Y A

                 PU
       PY =
                 K
2.20 Residual Stresses


  After the applied load is removed, some
  stresses may still remain inside the material
          → Residual Stresses
44558176 chapter-2-stress-and-strain-axial-loading

44558176 chapter-2-stress-and-strain-axial-loading

  • 1.
    Chapter 2 Stress and Strain -- Axial Loading Statics – deals with undeformable bodies (Rigid bodies) Mechanics of Materials – deals with deformable bodies -- Need to know the deformation of a boy under various stress/strain state -- Allowing us to computer forces for statically indeterminate problems.
  • 2.
    The following subjectswill be discussed: • Stress-Strain Diagrams • Modulus of Elasticity • Brittle vs Ductile Fracture • Elastic vs Plastic Deformation • Bulk Modulus and Modulus of Rigidity • Isotropic vs Orthotropic Properties • Stress Concentrations • Residual Stresses
  • 3.
    2.2 Normal Strainunder Axial Loading δ ε = normal strain = L For variable cross-sectional area A, strain at Point Q is: ∆δ d δ ε = lim = ∆x → 0 ∆x dx The normal Strain is dimensionless.
  • 4.
  • 5.
    Ductile Fracture Brittle Fracture
  • 7.
    Some Important Conceptsand Terminology: 1. Elastic Modulus 2. Yield Strength – lower and upper Y.S. -- σ y 0.2% Yield Strength 3. Ultimate Strength, σ ut 4. Breaking Strength or Fracture Strength 5. Necking 6. Reduction in Area 7. Toughness – the area under the σ-ε curve 8. Percent Elongation 9. Proportional Limit
  • 8.
    2.3 Stress-Strain Diagram LB − Lo Percent elongation = 100% Lo A0 − AB Percent reduction in area = 100% Ao
  • 9.
    2.4 True Stressand True Strain Eng. Stress = P/Ao True Stress = P/A Ao = original area A = instantaneous area δ Eng. Strain = True Strain = ε t = Σ∆ε = Σ( ∆L / L) Lo Lo = original length L = instantaneous length dL L L εt = ∫ = ln (2.3) Lo L Lo
  • 10.
    2.5 Hooke's Law:Modulus of Elasticity σ = Eε (2.4) Where E = modulus of elasticity or Young’s modulus Isotropic = material properties do not vary with Anisotropic = material properties vary with direction or direction or orientation. E.g.: metals E.g.: wood, composites orientation.
  • 12.
    2.6 Elastic VersusPlastic Behavior of a Material 2
  • 13.
    Some Important Concepts: 1. Recoverable Strain 2. Permanent Strain – Plastic Strain 3. Creep 4. Bauschinger Effect: the early yielding behavior in the compressive loading
  • 14.
    2.7 Repeated Loadings:Fatigue Fatigue failure generally occurs at a stress level that is much lower than σ y The σ -N curve = stress vs life curve The Endurance Limit = the stress for which fatigue failure does not occur.
  • 16.
    2.8 Deformations ofMembers under Axial Loading σ = Eε (2.4) σ P ε = = (2.5) E AE δ = εL (2.6) PL δ = (For Homogeneous rods) AE Pi Li δ = ∑ i A Ei (For various-section rods) i Pdx d δ = ε dx = (For variable cross-section rods) AE P
  • 17.
    L Pdx ∫ (2.9) δ = o AE PL δ B/ A = δB − δA = (2.10) AE
  • 18.
    2.9 Statically IndeterminateProblems A. Statically Determinate Problems: -- Problems that can be solved by Statics, i.e. ΣF = 0 and ΣM = 0 & the FBD B. Statically Indeterminate Problems: -- Problems that cannot be solved by Statics -- The number of unknowns > the number of equations -- Must involve “deformation” Example 2.02:
  • 19.
    Example 2.02 δ1 = δ 2
  • 20.
    Superposition Method forStatically Indeterminate Problems 1. Designate one support as redundant support 2. Remove the support from the structure & treat it as an unknown load. 3. Superpose the displacement Example 2.04
  • 21.
  • 22.
    δ = δL+ δR = 0
  • 23.
    2.10 Problems Involving Temperature Changes δ T = α ( ∆T ) L 2(.21) α = coefficient of thermal expansion δT + δP = 0 ε T = α∆T δ T = α ( ∆T ) L PL δP = AE PL δ = δ T + δ P = α ( ∆T ) L + =0 AE
  • 24.
    Therefore: P = − AEα ( ∆T ) P σ = = − Eα ( ∆T ) A
  • 25.
    2.11 Poisson 'sRatio εx =σx / E lateral strain υ = Poisson ' s Ratio = − axial strain εy εz υ= − = − εx εx σ υσ ε = X ε =ε = − X x E y z E
  • 26.
    2.12 Multiaxial Loading:Generalized Hooke's Law • Cubic → rectangular parallelepiped • Principle of Superposition: -- The combined effect = Σ (individual effect) Binding assumptions: 1. Each effect is linear 2. The deformation is small and does not change the overall condition of the body.
  • 27.
    2.12 Multiaxial Loading:Generalized Hooke's Law Generalized Hooke’s Law σ x υσ y υσ z εx = + − − E E E υσ x σ y υσ z εy = − + − (2.28) E E E υσ x υσ y σ z εz = − − + E E E Homogeneous Material -- has identical properties at all points. Isotropic Material -- material properties do not vary with direction or orientation.
  • 28.
    2.13 Dilation: BulkModulus Original volume = 1 x 1 x 1 = 1 Under the multiaxial stress: σ x, σ y, σ z The new volume = υ = (1 + ε x )(1 + ε y )(1 + ε z ) Neglecting the high order terms yields: υ =1+ εx + ε y + εz e = the hange of olume = υ − 1 = 1 + ε x + ε y + ε z − 1 ∴e = ε x + ε y + εz ( 2.30)
  • 29.
    e = dilation= volume strain = change in volume/unit volume Eq. (2.28) → Eq. (2-30) σ X + σy + σz 2υ (σ X + σ y + σ z ) e = − (2.31) E E 1 − 2υ e= (σ X + σ y + σ z ) E Special case: hydrostatic pressure -- σx, σy, σz = p 3(1 − 2υ ) E e= − p Define: κ = (2.33) E 3(1 − 2υ ) p e= − (2.33) κ κ = bulk modulus = modulus of compression +
  • 30.
    E Since κ =positive, κ= 3(1 − 2υ ) (1 - 2υ) > 0 1>2υ υ <½ Therefore, 0 < υ < ½ 3 E υ= 0 e= − E p κ= 3 3(1 − 2υ ) κ =∞ e=0 υ =½ e= − E p =0 -- Perfectly incompressible materials
  • 31.
    2.14 Shearing Strain If shear stresses are present Shear Strain = γ xy (In radians) τ xy = G γ xy (2.36) τ yz = G γ yz τ zx = G γ zx (2.37)
  • 32.
    The Generalized Hooke’sLaw: σ X υσ y υσ z εx = + − − E E E υσ X σ y υσ z εy = − + − E E E υσ X υσ y σ z εz = − − + E E E τ xy τ yz τ zx γ xy = γ yz = γ zx = G G G
  • 33.
    2.18 Further Discussionof Deformation under Axial Loading: Relation Among E, υ, and G E =1+υ 2G E G= 2(1 + υ )
  • 34.
    Saint-Venant’s Principle: -- the localized effects caused by any load acting on the body will dissipate or smooth out within region that are sufficiently removed form the location of he load.
  • 35.
    2.16 Stress-Strain Relationshipsfor Fiber-Reinforced Composite Materials -- orthotropic materials εy εz υ xy = − and υ xz = − εx εx σ X υ xyσ y υ zxσ z εx = + − − Ex Ey Ez υ xyσ X σ y υ zxσ z εy = − + − Ex Ey Ez υ xyσ X υ yzσ y σ z εz = − − + Ex Ey Ez
  • 36.
    υ xy υyx υ yz υ zy υ zx υ xz = = = E x E y E y Ez Ez E x τ xy τ yz τ zx γ xy = γ yz = γ zx = G G G
  • 37.
    2.17 Stress andStrain Distribution Under Axial Loading: Saint-Venant's Principle If the stress distribution is uniform: P σ y = (σ y )ave = A In reality:
  • 38.
    2.18 Stress Concentrations -- Stress raiser at locations where geometric discontinuity occurs σ max K= = Stress Concentration Factor σ ave
  • 40.
    2.19 Plastic Deformation Elastic Deformation → Plastic Deformation →Elastoplastic behavior σ σy Y C Rupture ε A D
  • 41.
    For σ max< σ Y σ max σ max K= σ ave = σ ave K σ max A P = σ ave A = K For σ max = σ Y σY A PY = K For σ ave = σ Y PU = σ Y A PU PY = K
  • 42.
    2.20 Residual Stresses After the applied load is removed, some stresses may still remain inside the material → Residual Stresses