Uranus is perpendicular on earth moon orbit (viii)

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Uranus Is Perpendicular On Earth Moon Orbit (VIII)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –20th
November 2020
Abstract
Paper hypothesis
The moon and Pluto motions are transported from one to another through the
solar planets motions.
Paper Investigation
- We analyze the moon orbital triangle to see this motion transportation
- Let's remember our basic argument:
- Uranus axial tilt (97.8 deg) creates an angle (91.1 deg) with the moon axial tilt (6.7
deg), but Uranus axial tilt is perpendicular on the moon orbit, because Uranus
creates a decline between the moon orbital triangle and the horizontal level =1.1
degrees, by that the angle became 90 degrees (perpendicularity)
- The angle 1.1 degrees Uranus created by stuffing consisted of 2 parts, the 1st
part is
Jupiter and Saturn interaction which created an angle =0.6 deg and seen in the
orbital triangle by the green rectangle under the triangle, the 2nd
part, An angle (0.5
degrees) is consumed by the moon diameter (3475 km) and means, Uranus axial
tilt angle above the moon surface should be = 90.6 deg
- Because Uranus orbital inclination =0.8 degrees and vertically =90.8 deg, so we
tried to make the angle (90.6 deg) = to (90.8 deg)! how?
- We cut inside the moon diameter because it consumes (0.5 deg) and reach to
smaller moon diameter (1390 km) which consumes only (0.2 deg) so the angle
above this smaller diameter surface is 90.9 deg.
- The rest diameter = 1042.5 km x 2, which we need to analyze deeply!
Paper conclusion
- Planet diameter is created based on this planet motion
- There's a transportation of motion between the Earth moon and Pluto.
- The planets do this motion transportation, that causes this motion features to be
seen on all planets motions
- The argument proves that, the planets can't be considered as separated masses
points, on the contrary they are knots in the same rope, where all solar planets are
created from the same one trajectory of energy and move by it.

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1- The Moon And Pluto Motions Transportations
1-1 The Moon diameter division
1-2 Planet diameter &velocity relationship analysis 1-3The period 1042.5 h analysis
1-1 The Moon diameter division
Figure No. (1)
(The moon orbital triangle is inserted in the paper end to be our discussion reference)
Let's summarize this figure idea
- (BTM) is Uranus axial tilt line (97.8 degrees), and (0.5 degrees) of it is consumed
for the moon diameter, so the angle on (T) = 90.6 degrees
- We cut into the moon diameter to above the small circle (smaller moon) its
diameter =1390 km (r= 695 km) – it consumes only (0.2 degrees), and the angle
above it = 90.9 degrees, from which 90 deg (perpendicularity), 0.8 deg (Uranus
orbital inclination) and 0.1 deg (the change in Mars orbital inclination form 1.8
deg to 1.9 deg)
- We study here the motion transportation between the moon and Pluto, and we need
from this figure is the value 1042.5 km, where the rest diameter = 2085 km and
its radius = 1042.5 km.
- Why this division for the moon diameter is correct? Because
o 38041 km (Venus circumference) = 27.3 x 1390 km (where 27.3 days is the
moon orbital period) that tells us this division is correct because the value
1390 km is used as any other registered data.
o 12014 km (Venus diameter) = 695 km (r) x 17.4 (where 17.4 deg = the
inner planets orbital inclinations total), the tested data is used as the
registered one and because of that we know that, this data is created really
by the geometrical structure, and not invented numbers.
o The value 1042.5 hours is used geometrically for different planets motions,
and the planets diameters and circumferences are used as periods of time
frequently in the solar system – so this value 1042.5 km- is a crucial proof
that the moon diameter division is a correct one – and this paper dedicated a
complete point of discussion to analyze this value 1042.5 km.

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1-2 Planet Diameter And Velocity Relationship Analysis
- Let's discuss the following data:
- 142984 km = 13.1 km/sec (Jupiter velocity) x10921 seconds, this equation tells
that, Jupiter needs to move during 10921 seconds to pass a distance =142984 km
(= Jupiter diameter). But on the other side, the equation tells, the Earth moon needs
to rotate 13.1 times around its axis to pass by rotation a distance = 142984 km (the
Earth moon circumference 10921 km) (The moon needs 27.3 days to rotate around
its axis and by that the 13.1 rotations needs 13.1 x 27.3 = 358 days = 1 year)
- 51118 km = 6.8 km/sec (Uranus velocity)x 7511 seconds, this equation tells that,
Uranus needs to move during 7511 seconds to pass a distance =51118 km
(=Uranus diameter). But on the other side, the equation tells, Pluto needs to rotate
6.8 times around its axis to pass by rotation a distance = 51118 km (Pluto
circumference 7511 km) (Pluto 153.3 hours to rotate around its axis and by that the
6.8 rotations needs 6.8 x 153.3 = 1042.5 hours)
- 51118 km = 4.7 km/sec (Pluto velocity) x 10921 seconds, this equation tells that,
Pluto needs to move during 10921 seconds to pass a distance =51118 km
(=Uranus diameter). But on the other side, the equation tells, the Earth moon needs
to rotate 4.7 times around its axis to pass by rotation a distance = 51118 km (The
moon needs 27.3 days to rotate around its axis and by that the 4.7 rotations needs
4.7 x 27.3 = 128.3 days).
- 142984 km = 4.7 km/sec (Pluto velocity) x 30589 seconds, this equation tells
that, Pluto needs to move during 30589 seconds to pass a distance =142984 km
(=Jupiter diameter). But on the other side 30589 days = Uranus orbital period.
- 378674 km = 35 km/sec (Venus velocity) x 10921 seconds, this equation tells,
Venus needs to move during 10921 seconds to pass a distance =378674 km
(=Saturn Circumference). But on the other side, the equation tells, the Earth moon
needs to rotate 35 times around its axis to pass by rotation a distance = 378674 km
(the moon needs 27.3 day for each rotation, so for 35 it needs 35 x27.3 =955.5
days). (NOTE Please, Saturn diameter = Venus circumference x π, this
relationship will change our vision for the equation, because in this case Saturn
circumference can be considered as relating to Venus Circumference by the rate
(π2
) and that makes Venus is similar to the previous 2 planets, which use their
velocities to pass their own diameters or circumferences distances – but the close
relationship between Venus and Saturn causes the exchange of their data.
- 40080 km = 5.4 km/sec (Neptune velocity) x 7511 seconds (error 1%), this
equation tells that, Neptune needs to move during 7511 seconds to pass a distance
=40080 km (=Earth Circumference). But on the other side, the equation tells, Pluto
needs to rotate 5.4 times around its axis to pass by rotation a distance = 40080 km
(Pluto needs 153.3 hour for each rotation time, so for 5.4 it needs 5.4 x153.3
=827.8 hours =34.5 days).

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- 10921 km = 4.7 km/sec (Pluto velocity) x 2390 seconds (error 2.8%), this
equation tells, Pluto needs to move during 2390 seconds to pass a distance =10921
km (= the Moon Circumference). (where 2390 km = Pluto diameter).
- 2 x 160592 km = 29.8 km/sec (Earth velocity) x 10921 seconds (error 1.3%),
this equation tells, Earth needs to move during 10921 seconds to pass a distance =
2 x160592 km (2 Uranus Circumferences) (where10921 km= the moon Diameter).
on the other side, the moon needs to rotate around its axis 29.8 times to move a
distance = 2 Uranus Circumferences (where 29.8 times x 27.3 = 813.5 days)
- 2 x 38041 km = 6.8 km/sec (Uranus velocity) x 10921 seconds (error 2.4%), this
equation tells, Uranus needs to move during 10921 seconds to pass a distance = 2
x38041 km (2 Venus Circumferences) (where10921 km= the moon Diameter). on
the other side, the moon needs to rotate around its axis 6.8 times to move a
distance = 2 Venus Circumferences (where 6.8 times x 27.3 = 185.6 days)
- 2 x 120536 km = 4.7 km/sec (Pluto velocity) x 51118 seconds, this equation tells,
Pluto needs to move during 51118 seconds to pass a distance = 2 x 120536 km
(2 Saturn diameters) (where 51118 km = Uranus Diameter).
- (Please Note, Mercury day period needs 5040 seconds to be 176 solar day, but
(51118 seconds/5040 seconds) = (Mercury velocity / Pluto velocity). To add more
interesting information, Mercury moves during 5040 seconds a distance = 2 Saturn
diameters (error 1%). But Mars moves during (5040 seconds) a distance = Saturn
diameter!
- Also this equation can be seen as following
- 2 x 378674 km (Saturn circumference) = 4.7 km/s x 160592 seconds, (where
160592 km = Uranus circumference) – and the equation in this form is interesting
because Saturn circumference = earth moon distance at total solar eclipse radius,
and the 2 values of it means the orbital diameter.
- And Uranus diameter is defined by Perigee radius as we have discussed before
(2.58 mkm Earth motion distance per solar day = 7.1 x 0.363 km Perigee radius,
and 0.363 mkm = 51118 km Uranus diameter).

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1-3The Period 1042.5 h analysis
- The period 1042.5 hours is created by Pluto rotation to move a distance = Uranus
diameter = 51118 km, because (51118 km = 6.8 x 7511 km) so Pluto needs to
rotate around its axis 6.8 times to pass the distance 5118 km and each rotation of
Pluto needs 153.3 hours, so the 6.8 rotations needs 1042.5 hours.
- But what about the 1042.5 seconds?
- During 1042.5 seconds Mercury moves a distance =49528 km = Neptune Diameter
- During 1042.5 s Mars moves a distance =25123 km = Uranus Radius (1.7%)
- During 1042.5 s Pluto moves a distance =4879 km = Mercury Diameter
- During 1042.5 s Uranus moves a distance =7070km = ancient Mars Diameter
- I try to show that, the motion is transported from planet to another in different
motion data – the value 1042.5 seconds (or hours or even km) it's some clear value
used in the transportation process and because of that, we notice it easily., the
other data express the motion transportation with more hidden description and
because of that we consider this data is independent from each other – but it's not
true.
Notice no. (1)
- One of the basic difficulties in the motion transportation explanation is that, the
planet data uses light motion features, as we have seen frequently… the distance
values are used as periods of time which is a light motion feature and can't be
explained by any planet motion – also – the different rates of time – while we deal
with 1042.5 hours we found here also 1042.5 seconds are working – such changes
in the rates of time can be done only by high velocity motion (light motion) – but
the feature is seen in planet motion and not in light motion and that causes a basic
difficulty for explanation – no one can say Earth moves by light velocity (0.3
mkm/sec) but the relativistic effects are observed in each data around – Earth
velocity is 29.8 km/sec but the light motion feature is found clearly –
- The point is that, light motion is accompanying with planet motion, but hidden
behind it.
Notice no. (2)
- Let's discuss the value 1042.5 km which we have found in the moo diameter in
following…

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The value 1042.5 km
Figure No. (1) (revision)
Why the value 1042.5 km is specific in this figure?
Equation No. (a)
- The moon (rotation) to move (51118 km) needs 128.3 days BUT Pluto (rotation)
to move (51118 km) needs 1042.5 hours (=43.32 days) i.e. (128.3/43.3) = 3
Equation No. (b)
- 0.406 mkm (Pluto motion per solar day) /51118 km (Uranus diameter) = (346.6
days nodal year/ 43.32 days
- Equation No. (b) tells that, the nodal year is created by the effect of this value
(1042.5 hours) or it's produced by an effect of Uranus & Pluto motions interaction
on the moon orbit.
- That means, the moon orbit regression is created by Uranus & Pluto motions
interactions effect on the moon orbit…
- 97.8 degrees (Uranus axial tilt) = 5.1 degrees (the moon orbital inclination) x 19
- That means practically, Uranus effect creates the moon orbital inclination to be 5.1
degrees in comparison with 19 degrees (the moon orbit regresses yearly 19 deg)
- Also
- 17.4 degrees = 5.1 degrees x 3.4 degrees (Venus orbital inclination)
- But
- 17.2 degrees (Pluto orbital inclination) = 17.4 deg x 0.99
i.e.
- Uranus and Pluto motions interaction effect on the moon orbit created the moon
orbital inclination (5.1 degrees) and this effect is done through Venus contribution
with them (please remember 12104 km Venus diameter =17.4 x 695 km (r))

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- That again tells us, the moon orbital inclination is the most powerful data in the
moon motion
Equation No. (c)
- 1042.5 km = 5.1 x 205 km
- 205 km /sec = The Solar Planets Velocities Total
- The equation tells that, the value 1042.5 km transports the solar planets motions
energies total to the moon motion.
- That tells the moon motion expresses A Total Motion Of The Solar Planets

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Let's review The Earth Moon Orbital Triangle because we use it
Figure No. (1) (my figure)
Please Note
(1) SZ = 7665 km ZF = 2414 km
- CZS = 77.8 degrees CZF =102.195 degrees
(2) DY = 3475 km BCY = 28.39 degrees
(3) XB = 16203 km XCB = 10.67
- XCE = 66 degrees CX = 87513 km

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Let's Review The Moon Orbital Triangle Data
(1st
Point)
- The figure I brought from internet to use in the Explanation -
- We have supposed that the inner circle is Perigee orbit and the
outer circle is apogee orbit – and we have calculated the tangent
AB = 181843 km
- AB = 363686 km (= perigee radius approximately)
- Perigee radius r =0.363 mkm Apogee radius r =0.406 mkm
- Based on that, the triangle (ODB) is a specific Pythagoras triangle (1, 2 and 51/2
)
- i.e. the triangle (ODB) angles are 26.564 degrees and 63.435 degrees
NOTE
- for these 2 angles (26.564 deg and 63.435 deg) we have searched, because these 2
angles will correct many data in the orbital triangle.
(2nd
Point) The Moon Orbital Triangle Data Correction
- EB = Perigee radius = 363000 km
- ED = Apogee radius = 406000 km
- EA= (Jupiter Circumference) =449197 km
- AC = (Saturn diameter) =121620 km (error 1%)
- ES = total solar eclipse radius = 373000 km (error 1%)
(EC = 373000 km = Earth moon distance at T. Solar eclipse, BUT point C is NOT
the moon position in T. solar eclipse, because the distance BC= 86000 km but the
distance between perigee point and total solar eclipse point = 11000 km)
- BS= (the moon Circumference) =10921 km
- BZ = 18586 km BF =21000 km
- BD = DA = 43000 km (BY =46475 km)
- BA = BC = 86000 km
- CS = = 86690 km
- CZ= (the moon daily displacement) =88000 km
- CF= 88526.8 km CD =96150.9 km
THE ANGLES
- The angle between the black and red lines (under E) = 1.1 degrees
- (E) = 13.33 degrees (C)= 121.67 degrees (A) = 45 degrees
- (ECB) = 76.67 degrees (BCA) = 45 degrees
- (BCS = 7.23 deg) (BCZ = 12.195 deg) (BCF = 13.72 deg) (BCD = 26.564 deg)
(ACD = 18.435 deg)
- (BSC = 82.7 deg) (BZC = 77.8 deg) (BFC = 76.82 deg) (BDC = 63.434 deg)
- (CSA =97.23 deg) (CZA =102.195 deg) (CFA= 103.7 deg) (CDA = 116.564 deg)
- (CYA = 118.92 deg) (
- (Uranus axial tilt = 97.8 degrees = FSC 0.6 degrees)
- Angle under (E) = 13.33 degrees 1.1 degrees = 14.43 degrees

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A Model For The Moon Motion 2 Orbits

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References
The Moon Motion Trajectory Analysis (II)
https://www.academia.edu/44368860/The_Moon_Motion_Trajectory_Analysis_II_
or
https://www.slideshare.net/Gergesfrancis/the-moon-motion-trajectory-analysis-ii
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
or
https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion
Can Different Rates Of Time Be Found In The Solar System Motion?(II)
https://www.academia.edu/44334645/Can_Different_Rates_Of_Time_Be_Found_In_The_Solar_System_Motion_II_
Does Particle Data Depend on Its Motion? (Lorentz Transformations Analysis)
https://vixra.org/abs/1912.0134
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944&p=15209
Mr.Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Gerges Francis Tawdrous +201022532292
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
Linkedln https://eg.linkedin.com/in/gerges-francis-86a351a1
Facebook https://www.facebook.com
Researcherid https://publons.com/researcher/3510834/gerges-tawadrous/
ORCID https://orcid.org/0000-0002-1041-7147
Quora https://www.quora.com/profile/Gerges-F-Tawdrous
Google https://scholar.google.com/citations?user=2Y4ZdTUAAAAJ&hl=en
Academia https://rudn.academia.edu/GergesTawadrous
List of publications http://vixra.org/author/gerges_francis_tawdrous

Uranus is perpendicular on earth moon orbit (viii)

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