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IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Uranus Is Perpendicular On Earth Moon Orbit (IV)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt – 18th
November 2020
Abstract
Paper hypothesis
The moon motion has 2 orbit which are found in perpendicularity on one
another
Paper Idea
- As we have explained in the moon orbital triangle, Uranus axial tilt creates an
angle 90.6 degrees above the moon diameter (under the green rectangle)
- But, Uranus orbital inclination =0.8 degrees, so the vertical value of it will be =90
degrees +0.8 degrees = 90.8 degrees – this value is so near to the previous one
which is (90.6 degrees) and I try to discover if they can be the same value!
- We know that, the moon angular diameter consumes 0.5 degrees from the original
angle between Uranus axial tilt (97.8 degrees) and the moon axial tilt (6.7 degrees)
which =91.1 degrees and by consuming (0.5 degrees) the rest is (90.6 degrees) and
now we want to make this value = 90.8 degrees! How?
- The moon diameter (3475 km) consumes (0.5 degrees), so what smaller diameter
of the moon can consume only (0.2 degrees) to left the rest (90.8 degrees)?!
- (3475 km /5) x2 = 1390 km
- What have we done? W consider the moon as a ball of clay and we cut from
outside the extra diameter value and created one small moon its diameter=1390 km
and left the moon motion data without change (as hypothesis)… Why?
- Because we will test this value 1390 km and know if it's used as a basic value in
the moon motion – If so – that will tells us, Uranus axial tilt doesn't stop out of the
moon diameter but penetrates the moon diameter and stop before the core 1390 km
to create the angle 90.8 degrees by which Uranus orbital inclination will be created
in perpendicularity case
- so let's test this value 1390 km in following…
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
2
1- The Moon Orbital motion has 2 orbits
1-1 The Moon Orbital Triangle
Let's review The Earth Moon Orbital Triangle because we use it
Figure No. (1) (my figure)
Please Note
(1) SZ = 7665 km ZF = 2414 km
- CZS = 77.8 degrees CZF =102.195 degrees
(2) DY = 3475 km BCY = 28.39 degrees
(3) XB = 16203 km XCB = 10.67
- XCE = 66 degrees CX = 87513 km
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
3
Let's Review The Moon Orbital Triangle Data
(1st
Point)
- The figure I brought from internet to use in the Explanation -
- We have supposed that the inner circle is Perigee orbit and the
outer circle is apogee orbit – and we have calculated the tangent
AB = 181843 km
- AB = 363686 km (= perigee radius approximately)
- Perigee radius r =0.363 mkm Apogee radius r =0.406 mkm
- Based on that, the triangle (ODB) is a specific Pythagoras triangle (1, 2 and 51/2
)
- i.e. the triangle (ODB) angles are 26.564 degrees and 63.435 degrees
NOTE
- for these 2 angles (26.564 deg and 63.435 deg) we have searched, because these 2
angles will correct many data in the orbital triangle.
(2nd
Point) The Moon Orbital Triangle Data Correction
- EB = Perigee radius = 363000 km
- ED = Apogee radius = 406000 km
- EA= (Jupiter Circumference) =449197 km
- AC = (Saturn diameter) =121620 km (error 1%)
- ES = total solar eclipse radius = 373000 km (error 1%)
(EC = 373000 km = Earth moon distance at T. Solar eclipse, BUT point C is NOT
the moon position in T. solar eclipse, because the distance BC= 86000 km but the
distance between perigee point and total solar eclipse point = 11000 km)
- BS= (the moon Circumference) =10921 km
- BZ = 18586 km BF =21000 km
- BD = DA = 43000 km (BY =46475 km)
- BA = BC = 86000 km
- CS = = 86690 km
- CZ= (the moon daily displacement) =88000 km
- CF= 88526.8 km CD =96150.9 km
THE ANGLES
- The angle between the black and red lines (under E) = 1.1 degrees
- (E) = 13.33 degrees (C)= 121.67 degrees (A) = 45 degrees
- (ECB) = 76.67 degrees (BCA) = 45 degrees
- (BCS = 7.23 deg) (BCZ = 12.195 deg) (BCF = 13.72 deg) (BCD = 26.564 deg)
(ACD = 18.435 deg)
- (BSC = 82.7 deg) (BZC = 77.8 deg) (BFC = 76.82 deg) (BDC = 63.434 deg)
- (CSA =97.23 deg) (CZA =102.195 deg) (CFA= 103.7 deg) (CDA = 116.564 deg)
- (CYA = 118.92 deg) (
- (Uranus axial tilt = 97.8 degrees = FSC 0.6 degrees)
- Angle under (E) = 13.33 degrees 1.1 degrees = 14.43 degrees
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
4
1-2 The Moon Orbital Motion has 2nd
Orbit
I- Data
Equation No. 1
38041 km (Venus Circumference) = 27.3 (the moon orbital period) x 1390 km
Equation No. 2
2 x 41.4 mkm (Venus Earth Distance) = 3.02 mkm (Venus velocity daily) x 27.3 days
Equation No. 1
- Venus Circumference = 27.3 times x 1390 km! what does that mean
o Equation no. (1) tells that, if the moon moves daily a distance =1390 km, it
will pass during its orbital period a distance = Venus Circumference
o We accept that the value 1390 km is the small moon diameter
o Equation no. 1 gives us one information only which is that, the moon orbital
period 27.3 days is related to Venus motion geometry
o It's true as Equation no. 2 tells
Equation No. 2
- 2 x 41.4 mkm (Venus Earth Distance) = 3.02 mkm (Venus velocity daily) x 27.3
o Equation no. (2) tells that
o Venus during a period 27.3 days (the moon orbital period) moves a distance
= 2 x Venus Earth Distance, i.e. the orbital diameter between Venus and
Earth
o The equation proves that, the period 27.3 days is used by Venus motion and
because of that we know the equation no. (1) was correct and the value 1390
km is a real value and be using in the moon motion
Why This Data Is Important?
- Based on this analysis, the angle 90.6 degrees (under the point B and above the
moon surface immediately) is somehow not the real angle
- The real angle is hidden inside the moon body
- Because
- Uranus axial tilt penetrates the moon body till reach to small ball around the moon
center its diameter =1390 km and at this point (inside the moon body) Uranus axial
tilt creates an angle 90.8 degrees which is =90 degrees +0.8 degrees, and because
Uranus orbital inclination =0.8 degrees, we discovered that, Uranus orbital
inclination is crated here inside the moon body
- Suppose it's correct, why this is important? Because
- Venus axial tilt 177.4 degrees +Venus orbital inclination 3.4 deg.= 180.8 deg
- This angle 180.8 deg = 0.8 degrees (Uranus orbital inclination) +90 +90
- i.e. Venus data is created based on this orbital inclination (0.8 degrees)
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
5
AGAIN Why This Data Is significant At Any Case?
- Because the moon (2nd
Orbit) is found perpendicular on the first orbit by this angle
(180.8 deg) according to the following description
The 2 Orbits Description
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
6
References
The Moon Motion Trajectory Analysis (II)
https://www.academia.edu/44368860/The_Moon_Motion_Trajectory_Analysis_II_
or
https://www.slideshare.net/Gergesfrancis/the-moon-motion-trajectory-analysis-ii
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
or
https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion
Can Different Rates Of Time Be Found In The Solar System Motion?(II)
https://www.academia.edu/44334645/Can_Different_Rates_Of_Time_Be_Found_In_The_Solar_System_Motion_II_
Does Particle Data Depend on Its Motion? (Lorentz Transformations Analysis)
https://vixra.org/abs/1912.0134
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944&p=15209
Mr.Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Gerges Francis Tawdrous +201022532292
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
Linkedln https://eg.linkedin.com/in/gerges-francis-86a351a1
Facebook https://www.facebook.com
Researcherid https://publons.com/researcher/3510834/gerges-tawadrous/
ORCID https://orcid.org/0000-0002-1041-7147
Quora https://www.quora.com/profile/Gerges-F-Tawdrous
Google https://scholar.google.com/citations?user=2Y4ZdTUAAAAJ&hl=en
Academia https://rudn.academia.edu/GergesTawadrous
List of publications http://vixra.org/author/gerges_francis_tawdrous

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Uranus Is Perpendicular On Earth Moon Orbit (IV)

  • 1. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 1 Uranus Is Perpendicular On Earth Moon Orbit (IV) The Author Authorized To Be Used By Mr. Gerges Francis Tawdrous A Student–Physics Department- Physics & Mathematics Faculty – Peoples' Friendship University of Russia (RUDN University) – Moscow – Russia Dr. Budochkina, Svetlana Aleksandrovna Associate Professor (Mathematical Analysis and Theory of Functions Department) Peoples' Friendship University of Russia (RUDN University) – Moscow – Russia Phone +201022532292 E-Mail: mrwaheid@gmail.com Curriculum Vitae http://vixra.org/abs/1902.0044 Phone +7 (495) 952-35-83 E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru Website http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024 The Assumption Of S. Virgin Mary -Written in Cairo –Egypt – 18th November 2020 Abstract Paper hypothesis The moon motion has 2 orbit which are found in perpendicularity on one another Paper Idea - As we have explained in the moon orbital triangle, Uranus axial tilt creates an angle 90.6 degrees above the moon diameter (under the green rectangle) - But, Uranus orbital inclination =0.8 degrees, so the vertical value of it will be =90 degrees +0.8 degrees = 90.8 degrees – this value is so near to the previous one which is (90.6 degrees) and I try to discover if they can be the same value! - We know that, the moon angular diameter consumes 0.5 degrees from the original angle between Uranus axial tilt (97.8 degrees) and the moon axial tilt (6.7 degrees) which =91.1 degrees and by consuming (0.5 degrees) the rest is (90.6 degrees) and now we want to make this value = 90.8 degrees! How? - The moon diameter (3475 km) consumes (0.5 degrees), so what smaller diameter of the moon can consume only (0.2 degrees) to left the rest (90.8 degrees)?! - (3475 km /5) x2 = 1390 km - What have we done? W consider the moon as a ball of clay and we cut from outside the extra diameter value and created one small moon its diameter=1390 km and left the moon motion data without change (as hypothesis)… Why? - Because we will test this value 1390 km and know if it's used as a basic value in the moon motion – If so – that will tells us, Uranus axial tilt doesn't stop out of the moon diameter but penetrates the moon diameter and stop before the core 1390 km to create the angle 90.8 degrees by which Uranus orbital inclination will be created in perpendicularity case - so let's test this value 1390 km in following…
  • 2. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 2 1- The Moon Orbital motion has 2 orbits 1-1 The Moon Orbital Triangle Let's review The Earth Moon Orbital Triangle because we use it Figure No. (1) (my figure) Please Note (1) SZ = 7665 km ZF = 2414 km - CZS = 77.8 degrees CZF =102.195 degrees (2) DY = 3475 km BCY = 28.39 degrees (3) XB = 16203 km XCB = 10.67 - XCE = 66 degrees CX = 87513 km
  • 3. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 3 Let's Review The Moon Orbital Triangle Data (1st Point) - The figure I brought from internet to use in the Explanation - - We have supposed that the inner circle is Perigee orbit and the outer circle is apogee orbit – and we have calculated the tangent AB = 181843 km - AB = 363686 km (= perigee radius approximately) - Perigee radius r =0.363 mkm Apogee radius r =0.406 mkm - Based on that, the triangle (ODB) is a specific Pythagoras triangle (1, 2 and 51/2 ) - i.e. the triangle (ODB) angles are 26.564 degrees and 63.435 degrees NOTE - for these 2 angles (26.564 deg and 63.435 deg) we have searched, because these 2 angles will correct many data in the orbital triangle. (2nd Point) The Moon Orbital Triangle Data Correction - EB = Perigee radius = 363000 km - ED = Apogee radius = 406000 km - EA= (Jupiter Circumference) =449197 km - AC = (Saturn diameter) =121620 km (error 1%) - ES = total solar eclipse radius = 373000 km (error 1%) (EC = 373000 km = Earth moon distance at T. Solar eclipse, BUT point C is NOT the moon position in T. solar eclipse, because the distance BC= 86000 km but the distance between perigee point and total solar eclipse point = 11000 km) - BS= (the moon Circumference) =10921 km - BZ = 18586 km BF =21000 km - BD = DA = 43000 km (BY =46475 km) - BA = BC = 86000 km - CS = = 86690 km - CZ= (the moon daily displacement) =88000 km - CF= 88526.8 km CD =96150.9 km THE ANGLES - The angle between the black and red lines (under E) = 1.1 degrees - (E) = 13.33 degrees (C)= 121.67 degrees (A) = 45 degrees - (ECB) = 76.67 degrees (BCA) = 45 degrees - (BCS = 7.23 deg) (BCZ = 12.195 deg) (BCF = 13.72 deg) (BCD = 26.564 deg) (ACD = 18.435 deg) - (BSC = 82.7 deg) (BZC = 77.8 deg) (BFC = 76.82 deg) (BDC = 63.434 deg) - (CSA =97.23 deg) (CZA =102.195 deg) (CFA= 103.7 deg) (CDA = 116.564 deg) - (CYA = 118.92 deg) ( - (Uranus axial tilt = 97.8 degrees = FSC 0.6 degrees) - Angle under (E) = 13.33 degrees 1.1 degrees = 14.43 degrees
  • 4. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 4 1-2 The Moon Orbital Motion has 2nd Orbit I- Data Equation No. 1 38041 km (Venus Circumference) = 27.3 (the moon orbital period) x 1390 km Equation No. 2 2 x 41.4 mkm (Venus Earth Distance) = 3.02 mkm (Venus velocity daily) x 27.3 days Equation No. 1 - Venus Circumference = 27.3 times x 1390 km! what does that mean o Equation no. (1) tells that, if the moon moves daily a distance =1390 km, it will pass during its orbital period a distance = Venus Circumference o We accept that the value 1390 km is the small moon diameter o Equation no. 1 gives us one information only which is that, the moon orbital period 27.3 days is related to Venus motion geometry o It's true as Equation no. 2 tells Equation No. 2 - 2 x 41.4 mkm (Venus Earth Distance) = 3.02 mkm (Venus velocity daily) x 27.3 o Equation no. (2) tells that o Venus during a period 27.3 days (the moon orbital period) moves a distance = 2 x Venus Earth Distance, i.e. the orbital diameter between Venus and Earth o The equation proves that, the period 27.3 days is used by Venus motion and because of that we know the equation no. (1) was correct and the value 1390 km is a real value and be using in the moon motion Why This Data Is Important? - Based on this analysis, the angle 90.6 degrees (under the point B and above the moon surface immediately) is somehow not the real angle - The real angle is hidden inside the moon body - Because - Uranus axial tilt penetrates the moon body till reach to small ball around the moon center its diameter =1390 km and at this point (inside the moon body) Uranus axial tilt creates an angle 90.8 degrees which is =90 degrees +0.8 degrees, and because Uranus orbital inclination =0.8 degrees, we discovered that, Uranus orbital inclination is crated here inside the moon body - Suppose it's correct, why this is important? Because - Venus axial tilt 177.4 degrees +Venus orbital inclination 3.4 deg.= 180.8 deg - This angle 180.8 deg = 0.8 degrees (Uranus orbital inclination) +90 +90 - i.e. Venus data is created based on this orbital inclination (0.8 degrees)
  • 5. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 5 AGAIN Why This Data Is significant At Any Case? - Because the moon (2nd Orbit) is found perpendicular on the first orbit by this angle (180.8 deg) according to the following description The 2 Orbits Description
  • 6. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 6 References The Moon Motion Trajectory Analysis (II) https://www.academia.edu/44368860/The_Moon_Motion_Trajectory_Analysis_II_ or https://www.slideshare.net/Gergesfrancis/the-moon-motion-trajectory-analysis-ii Light Motion Features Are Discovered in Planet Motion https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion or https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion Can Different Rates Of Time Be Found In The Solar System Motion?(II) https://www.academia.edu/44334645/Can_Different_Rates_Of_Time_Be_Found_In_The_Solar_System_Motion_II_ Does Particle Data Depend on Its Motion? (Lorentz Transformations Analysis) https://vixra.org/abs/1912.0134 Dr. Budochkina, Svetlana Aleksandrovna Associate professor - Candidate of physico-mathematical sciences (2005) http://www.mathnet.ru/eng/person22119 List of publications on Google Scholar List of publications on ZentralBlatt https://mathscinet.ams.org/mathscinet/MRAuthorID/757317 http://elibrary.ru/author_items.asp?spin=6087-3245 http://orcid.org/0000-0003-3447-0425 http://www.researcherid.com/rid/G-7453-2014 http://www.scopus.com/authid/detail.url?authorId=6507007003 https://www.researchgate.net/profile/Svetlana_Budochkina Full list of publications: http://web-local.rudn.ru/web- local/prep/rj/index.php?id=2944&p=15209 Mr.Gerges Francis Tawdrous +201022532292 Physics Department- Physics & Mathematics Faculty Gerges Francis Tawdrous +201022532292 Curriculum Vitae http://vixra.org/abs/1902.0044 E-mail mrwaheid@gmail.com Linkedln https://eg.linkedin.com/in/gerges-francis-86a351a1 Facebook https://www.facebook.com Researcherid https://publons.com/researcher/3510834/gerges-tawadrous/ ORCID https://orcid.org/0000-0002-1041-7147 Quora https://www.quora.com/profile/Gerges-F-Tawdrous Google https://scholar.google.com/citations?user=2Y4ZdTUAAAAJ&hl=en Academia https://rudn.academia.edu/GergesTawadrous List of publications http://vixra.org/author/gerges_francis_tawdrous