Uranus Is Perpendicular On Earth Moon Orbit (VI)

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Uranus Is Perpendicular On Earth Moon Orbit (VI)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –19th
November 2020
Abstract
Paper hypothesis
The Earth moon motion has 2 orbits
The hypothesis explanation
- The Earth moon is so specific planet in the solar system and so effective in its
general geometry
- Uranus and Neptune effect on the moon orbit creation and cause its regression by
19 degrees yearly
- Uranus and Neptune orbital inclinations are created by the effect on their
interactions in the moon orbit
- Mars orbital inclination is created based on the moon orbit interactions
- The moon orbital motion has 2 orbits both perpendicular on one another
- Venus axial tilt and orbital inclination are created as a result of Uranus
perpendicularity on the moon orbits.
Paper conclusion
- Many of Planets data can be created by their values only if there are 2 orbits for
the moon motion.

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1- The Moon 2 Orbits Proves Discussion
1-1 The Moon Diameter Analysis
Figure No. (1)
- This figure I have created as a part of the moon orbital triangle
- The figure provides a clear vision for what's happening inside the moon diameter
to create Uranus orbital inclination
- In this figure we use the moon orbital triangle data, where I have inserted this
triangle in the paper end to be our discussion reference –
Let's start our discussion
- We woks basically with the line (BTM L), it's Uranus axial tilt line (97.8 degrees),
- The line KL is the Earth Moon Axial Tilt (6.7 degrees)
- The angle KLM = 91.1 degrees which supposed to be equal the angle in (the moon
center IMT)
- The angle 1.1 degrees is consumed in the moon diameter (3475 km = 0.5 degrees)
and the green rectangle =0.6 degrees (created by Saturn and Jupiter interaction)
- The angle UTB = 90 degrees +0.6 degrees = 90.6 degrees
- We search for an angle =90.8 degrees (Uranus orbital inclination 0.8+90)
- The moon diameter consumes 0.5 degrees, so we will cut the moon great diameter
to a smaller one which consume only 0.2 degree, this small moon r = 695 km..
- So the small moon (its diameter = 695 km x 2= 1390 km) consumes 0.2 deg
- The (Uranus axial tilt line) angle on this small moon surface = 90.9 degrees
- This 90.9 degrees = 90.8 degrees + 0.1 degree
- Now let's try to see how this analysis will wok in following ….

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Equation No. 1
1.8 deg (Neptune orbital inclination) x 0.8 deg (Uranus orbital inclination) =1.44 deg2
- 1.44 degrees = the moon orbit regresses degrees monthly
- We have 0.8 degrees in the previous figure, but where's 1.8 degrees? How to find
Neptune orbital inclination in the previous figure,
- Because
- The red line (SB) declines on the horizontal level (KL = the moon axial tilt) with
only 1.1 degrees – so how to create 1.8 degrees in this figure
(Question No. 1)
Equation No. 2
The greater circle r = 1042.5 km (3475 km -1390 km = 2 x 1042.5 km)
Where
51118 km = 6.8 km/sec x 7511 seconds
- Let's remember this beautiful equation …
- Equation no. (2) tells that,
o Uranus needs to move 7511 seconds to pass a distance = its diameter
o Where 7511 km = Pluto circumference….
o On the other side
o Pluto has to rotate around its axis 6.8 times to move a distance = 51118 km=
Uranus diameter,
o but
o Pluto rotates around its axis each 153.3 hours, so 6.8 x 153.3 = 1042.5 h
- This interesting data will be more attractive when we remember Jupiter case
o 142984 km (Jupiter diameter) = 13.1 km/sec x 10921 km
o Jupiter needs to move 10921 seconds to pass a distance = its diameter
o Where 10921 km = The Earth moon circumference….
o On the other side
o The moon has to rotate around its axis 13.1 times to move a distance
=142984 km= Jupiter diameter,
o but
o the moon rotates around its axis each 27.3 days, so 13.1 x 27.3 = a year
- It's hard to consider both cases as pure coincidences….
- Any way we have found the number 1042.5 inside the moon diameter, and we as
we have seen in 2 examples, to use the distance value as a time period is usual
using in the plants data…!
- How to explain this data
(Question No. 2)

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Equation No. 3
91.7 degrees = 63.7 degrees x 1.44 degrees
- 63.7 degrees is the sun declination
- 1.44 degrees = the moon orbit regression monthly
- But
- What's this value 91.7 degrees??
-
- In the previous figure, the total decline angle between the moon triangle base (the
red line BS) on the horizontal level (the moon axial tilt) only 1.1 degrees and the
total angle between Uranus axial tilt and the moon axial tilt =97.8- 6.7 =91.1 deg.!
- So
- How to create this number 91.7 degrees? We need 91.1 deg +0.6 deg
- How to create this strange value (97.1 =91.1 deg +0.6 deg)??
(Question No. 3)
Equation No. 4
1.9 degrees = 1.1 degrees + 0.8 degree
- 1.9 degrees = Mars orbital incaution
- 0.8 degree = Uranus orbital incaution
- 1.1 degrees = (91.1 degrees -90 degrees) (i.e. the total decline angle)
i.e.
- If we consume 0.8 degrees from the total decline angle (1.1 degrees) how to add
the same angle (1.1) again to this total?
Also
- In Neptune orbital inclination 1.8 degrees
- We need
- 0.1 degrees works negatively against (1.9 degrees) (on the opposite direction!) so
(1.9 degrees – 0.1 degree = 1.8 degrees)
- That tells w have 2 value of the same total angle (1.1 degrees), and they may be in
opposite to each other!
Equation No. 5
1.44 degrees = 1.9 degrees x 0.378 degree x 2
- 1.44 degrees = the moon orbit regression per month
- 1.9 degrees = Mars orbital inclination
- 0.378 mkm = The Earth Moon Distance at total solar eclipse radius
- Equation No. (5) tells us, there's some reason to create an interaction between the
moon orbit regression and Mars motion! can really such interaction be created?
(Question No. 4)

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Equation No. 6
5.6 degrees = 1.1 degrees x 5.1 degree
- The value 1.1 degrees is the decline angle total
- 5.1 degrees = the moon orbital inclination
- 5.6 degrees = the moon orbital inclination + the moon diameter angle (5.1+0.5)
i.e. the moon orbital inclination is measure above the moon diameter
- Equation No. (6) tells that, the moon orbital inclination (5.1 deg) is produced as a
result of Uranus perpendicularly on the moon orbit and specifically as a result of
the decline total angle (1.1 degrees) in the moon orbital triangle
How to solve the
previous
questions?
A CONCLUSION
THERE'S ONE MORE ORBIT IS FOUND UNDER THE HORIZONTAL
LEVEL (AS SHOWS IN THE FIGURE)
This conclusion can solve the questions
- The value 1.9 degrees can be produced So 1.1 degrees (1st
orbit) +0.8 deg ( 2nd
orbit)
- Also (1.9 deg – 0.1 deg) = 1.8 deg where the value (0.1 deg) effects in opposite
direction to the first one (1.9 deg)
- Also
- The value 91.7 degrees = 63.7 x 1.44 degrees can be easily produced, because the
value 91.1 degrees (1st
orbit) +0.6 degrees (2nd
orbit)

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1-2 Pluto Effect On The Moon Orbital Triangle
We discuss here the interesting equation No.2
Equation No. 2 (Revision)
The greater circle r = 1042.5 km (3475 km -1390 km = 2 x 1042.5 km)
Let's add more data to extend our discussion
Equation No. 7
(a) 1042.5 km x 2 = 6.01 x 346.6
(b) 8 degrees = 1.9 degrees + 6.1 degrees
(c) 346.6 days (the nodal year) = 8 x 43.3 days but (1042.5 hours = 43.3 days)
How to understand this equation, let's move step by step:
- 1042.5 km = the greater circle radius (R = 1042.5 km) in our figure No. 1
- So the diameter = 1042.5 km x 2 =2085 km
- We remember the story concerning the equation no. (2), that Pluto needs to move
during 1042.5 hours to rotate around its axis 6.8 times…. But (1042.5 h =43.3 day)
- The hours (1042.5) causes to create the days (346.6 days) based on the rate 8
- 8 = 1.9 deg (Mars orbital inclination) + 6.1 degrees
- But we have only 6.01 and how to create 6.1? (6.01 /0.1) =6.1 degrees
- Equation no. (b) tells that, the value (0.1 degree) is owned by Mars and it uses
freely as here, proving that (1.9 deg= 0.1 deg +1.8 deg Neptune orbital inclination)
- What conclusions here?
- Mars and Pluto are 2 players in the nodal year creation (346.6 days)
- Because of that
o (687 days mars orbital inclination + 2 x 3.1) = 2 x 346.6 days
(3.1 degrees = Jupiter Axial Tilt which is used here in days unit)
o 90560 days (Pluto Orbital Period) = 346.6 days x 261.3
o 261.3 x 0.1 = 26.13 = (5.1)2
(5.1 degrees = The moon orbital inclination)

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Equation No. 8
180.8 degrees = 179.9 degrees +0.9 degrees
- 180.8 degrees = 177.4 deg (Venus axial tilt) +3.4 deg (Venus orbital inclination)
- But
- 179.9 degrees = 177.4 deg (Venus axial tilt) +2.5 deg (Saturn orbital inclination)
- 0.9 degrees is the total decline angle above the moon small diameter (r=695 km)
And
- We know that the green triangle in the figure (mo.1) is created to consume 0.6 by
interaction between Jupiter and Saturn (that proved by the equations 2.5 deg = 0.6
deg +1.9 deg and 1.9 deg = 0.6 deg +1.3 deg)
- So the interaction is done inside the moon body –
- Simply above a radius =695 km, the interaction is done between Venus axial tilt
(177.4 deg) and Saturn orbital incaution (2.5 degrees) =179.9 deg, then add to that
the value 0.9 degrees which is the total decline angle above the small moon
diameter (695 km) – to create the total 180.8 degrees based on which Venus orbital
inclination is created.
- To prove this story… is there any relationship between 695 km and Venus?
Equation No. 9
12104 km (Venus diameter) = 695 km x 17.4
- 17.4 degrees = the inner planets orbital inclination total
(But 17.2 deg Pluto orbital inclination = 17.4 x 0.99)
- 23.6 degrees = the outer planets orbital inclination total
(But 23.4 deg Earth axial tilt = 23.6 x 0.99)
- Equation no. ( 9) tells that there's a strong relationship between Venus diameter
and the small moon radius (695 km)
- But we know that
o Venus circumference x π = Saturn diameter
o (Venus circumference)2
= Saturn orbital distance (1%)
i.e.
- Based on the radius 695 km both planets are interacted and created their data to be
in consistency with this dame distance

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Let's review The Earth Moon Orbital Triangle because we use it
Figure No. (1) (my figure)
Please Note
(1) SZ = 7665 km ZF = 2414 km
- CZS = 77.8 degrees CZF =102.195 degrees
(2) DY = 3475 km BCY = 28.39 degrees
(3) XB = 16203 km XCB = 10.67
- XCE = 66 degrees CX = 87513 km

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Let's Review The Moon Orbital Triangle Data
(1st
Point)
- The figure I brought from internet to use in the Explanation -
- We have supposed that the inner circle is Perigee orbit and the
outer circle is apogee orbit – and we have calculated the tangent
AB = 181843 km
- AB = 363686 km (= perigee radius approximately)
- Perigee radius r =0.363 mkm Apogee radius r =0.406 mkm
- Based on that, the triangle (ODB) is a specific Pythagoras triangle (1, 2 and 51/2
)
- i.e. the triangle (ODB) angles are 26.564 degrees and 63.435 degrees
NOTE
- for these 2 angles (26.564 deg and 63.435 deg) we have searched, because these 2
angles will correct many data in the orbital triangle.
(2nd
Point) The Moon Orbital Triangle Data Correction
- EB = Perigee radius = 363000 km
- ED = Apogee radius = 406000 km
- EA= (Jupiter Circumference) =449197 km
- AC = (Saturn diameter) =121620 km (error 1%)
- ES = total solar eclipse radius = 373000 km (error 1%)
(EC = 373000 km = Earth moon distance at T. Solar eclipse, BUT point C is NOT
the moon position in T. solar eclipse, because the distance BC= 86000 km but the
distance between perigee point and total solar eclipse point = 11000 km)
- BS= (the moon Circumference) =10921 km
- BZ = 18586 km BF =21000 km
- BD = DA = 43000 km (BY =46475 km)
- BA = BC = 86000 km
- CS = = 86690 km
- CZ= (the moon daily displacement) =88000 km
- CF= 88526.8 km CD =96150.9 km
THE ANGLES
- The angle between the black and red lines (under E) = 1.1 degrees
- (E) = 13.33 degrees (C)= 121.67 degrees (A) = 45 degrees
- (ECB) = 76.67 degrees (BCA) = 45 degrees
- (BCS = 7.23 deg) (BCZ = 12.195 deg) (BCF = 13.72 deg) (BCD = 26.564 deg)
(ACD = 18.435 deg)
- (BSC = 82.7 deg) (BZC = 77.8 deg) (BFC = 76.82 deg) (BDC = 63.434 deg)
- (CSA =97.23 deg) (CZA =102.195 deg) (CFA= 103.7 deg) (CDA = 116.564 deg)
- (CYA = 118.92 deg) (
- (Uranus axial tilt = 97.8 degrees = FSC 0.6 degrees)
- Angle under (E) = 13.33 degrees 1.1 degrees = 14.43 degrees

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A Model For The Moon Motion 2 Orbits

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References
The Moon Motion Trajectory Analysis (II)
https://www.academia.edu/44368860/The_Moon_Motion_Trajectory_Analysis_II_
or
https://www.slideshare.net/Gergesfrancis/the-moon-motion-trajectory-analysis-ii
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
or
https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion
Can Different Rates Of Time Be Found In The Solar System Motion?(II)
https://www.academia.edu/44334645/Can_Different_Rates_Of_Time_Be_Found_In_The_Solar_System_Motion_II_
Does Particle Data Depend on Its Motion? (Lorentz Transformations Analysis)
https://vixra.org/abs/1912.0134
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944&p=15209
Mr.Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Gerges Francis Tawdrous +201022532292
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
Linkedln https://eg.linkedin.com/in/gerges-francis-86a351a1
Facebook https://www.facebook.com
Researcherid https://publons.com/researcher/3510834/gerges-tawadrous/
ORCID https://orcid.org/0000-0002-1041-7147
Quora https://www.quora.com/profile/Gerges-F-Tawdrous
Google https://scholar.google.com/citations?user=2Y4ZdTUAAAAJ&hl=en
Academia https://rudn.academia.edu/GergesTawadrous
List of publications http://vixra.org/author/gerges_francis_tawdrous

Uranus Is Perpendicular On Earth Moon Orbit (VI)

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