Another Force Effects On The Earth Moon Motion (III)

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Another Force Effects On The Earth Moon Motion (III)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo – Egypt – 2nd
November 2020
Abstract
Paper Question
- Can the moon orbit regress and the Earth still in its same point in the space If
the Earth moon distances after the regression still equal their values before
it?
- The paper question tells us that….
- The moon orbit regression is done because of the moon vertical motion and both
are done in consistency with a displacement done by Earth vertically for 1 km per
solar day…
- I claim that, there are 3 motions done, but only one motion is seen, we have to
conclude the 2 rest hidden motions….
o The seen motion is The Moon Orbit Regression
o The 1st
hidden motion is the moon vertical motion…that means, the moon
in its revolution around The Earth does a vertical motion, and this vertical
motion is the reason of the Metonic Cycle (19 sidereal years)
o The 2nd
hidden motion is the Earth motion, where the Earth moves daily a
vertical displacement = 1 km
- These 3 motions are done in consistency with each other, and depends on each
other (this dependency can be seen in a deep analysis for these 3 motions origin)
Paper Objective
- The paper tries to prove the moon vertical motion by using the moon motion data
analysis, after this proof , The paper discusses if a vertical displacement of Earth is
a necessary requirement for the moon orbit regression, which is done as a result of
the moon vertical motion.
Paper 2nd
Question
- Why it's necessary to know if the moon has a vertical motion?

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- (1st
) The moon motion has pauses can't be explained, as we have seen in our tests
for (Gerges Equation for the moon orbital motion)… where the moon moves on
a solar day a distance = 4000 km (in average) (for example from 384000 km to
388000 km) but we have found that, the moon in perigee & apogee top points stay
for many days without change its orbit (for example during 28th
, 29th
and 30th
January 2020, the moon stayed on (404425 km, 405333km, 405111 km)) – how to
explain that?
- The logical answer is that the moon uses its daily angle (0.9856262 degrees)
which causes its displacement daily through its orbit, in this vertical motion,
means… no horizontal displacement is found in these values (404425 km,
405333km, 405111 km) because the moon uses its motion angle to perform a
vertical motion, and this vertical motion consumed its daily displacement and
because of that the moon stayed long time in these top points…
- (2nd
) because the moon vertical motion in the solar system will change the whole
description. shortly, we will find some planets perpendicular on other planets orbit
Specifically because Uranus axial tilt (97.8 deg) is almost perpendicular on the
moon axial tilt (6.7 deg), the question is if Uranus itself is perpendicular on the
moon motion orbit.
References
The Moon Motion Basic Equation
https://www.academia.edu/s/46a3441e4a
or
https://www.academia.edu/44396469/The_Moon_Motion_Basic_Equation
or
https://www.slideshare.net/Gergesfrancis/the-moon-motion-basic-equation
The Moon Motion Basic Equation (III) (Test No.2)
https://www.academia.edu/44401947/The_Moon_Motion_Basic_Equation_III_Test_No_2_
or
https://www.slideshare.net/Gergesfrancis/the-moon-motion-basic-equation-iii-test-no2

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1- Does The Moon Move A Vertical Motion?
1-1 Preface
1-2- How to prove that the moon has a vertical motion?
1-3 The Moon Orbit Regression Analysis
1- 1 Preface
(1271 degrees), This value is our discussion point. Let's remember why
- The moon daily displacement = 88000 km.
Let's imagine
- The moon moves only a vertical motion from perigee to apogee and return back, as
the figure shows in 2 arrows (red and blue). The distance from perigee to apogee =
43000 km, so the travel once and return back costs 86000 km but the moon daily
displacement = 88000 km, which means, there's still only 2000 km of the moon
daily displacement….
- Let's imagine that
- The moon will use the rest (2000 km) in a horizontal displacement which is seen in
the green arrows…
- The moon orbital radius apogee (r= 0.406 mkm) and its circumference =2.58 mkm.
- If the moon moves daily 2000 km only in the horizontal displacement, so the moon
will need 1290 days to revolve its orbit at apogee.
- That means, the value 1290 days must be a cycle in the moon motion because by
this period the moon completes its apogee orbital circumference by this motion
which we describe here (if this motion is real)
But
- The moon moves daily by its angle (0.9856262 degrees) as we have discussed and
tested in (Gerges Equation for the moon orbital motion)….
i.e.
- If the moon moves in a vertical motion, so it uses this angle (0.9856262 degrees)
in this motion vertically in place of its using horizontally…. And the period 1290
days expresses the moon complete revolution around its orbital circumference at
apogee radius…. So
- 1290 days x 0.9856262 degrees = 1271.4 degrees
i.e.
- If the moon move a vertical motion, as this one which is described here, the value
1271.4 degrees must be used as one basic value among the moon data, because
this value is the proof of the moon vertical motion if it's real one.

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1- 2 How to prove that the moon has a vertical motion?
I- Data
Group No. (I)
1- 6939.75 days = π3
x 224.7 days (Error 0.4%)
2- 6939.75 days = 118.3 x 58.66 days (Zero Error)
3- (116.7 days / 58.66 days) = (687 days/346.6 days) (Error 0.4%)
Group No. (II)
4- 1271.4 degrees = 41 degrees x π3
5- 1271.4 degrees = 97.8 degrees x 13
6- 346.6 degrees = 26.6 degrees x 13
7- 103 degrees = 13 degrees + 90 deg (17.4 deg – 4.37 deg = 13.03 deg)
8- 1271 days = 346.6 days x 3.66
9- 1271.4 days = 2 x 23.45 x 27.1
10- 1271.4 degrees = (25.2 degrees )2
x 2 = 113.45 x 2 x 5.1 = 2 x 23.8 x 26.7
11- 13 degrees2
= 2.6 degrees x 5
12- 1271.4 = 254 x 5
13-1271.4 degrees = 1.9 degrees x 669.15
14- 1271.4 mkm =88000km x14448 (but 6939.75 x2.082 mk= 14448 mkm)
Group No. (III)
15- 1124 degrees = 41 degrees x 27.41
16- 1124 degrees = 1140 days x 0.9856262 degrees
Note Please
- If the moon makes the displacement (2000 km) which is produced in the moon
vertical motion according to the previous description…. if this displacement is
done in perigee orbit (r= 0.363 mkm), so 2πx 0.363 = 2.28 mkm
- The moon passes the perigee orbital circumference (2.28 mkm) during a period
=1140 solar days
- So if the moon moves a vertical motion and uses its daily angle (0.985 deg) in this
motion so 1140 days x 0.9856262 degrees = 1124 degrees, based on that the
equation No. 14 (for perigee) is equivalent to Equation No. 4 (for apogee)
- Let's discuss these equations in following …

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II- Discussion
Group No. (I)
1- 6939.75 days = π3
x 224.7 days (Error 0.4%)
2- 6939.75 days = 118.3 x 58.66 days (Zero Error)
3- (116.7 days / 58.66 days) = (687 days/346.6 days) (Error 0.4%)
The Data group No. (I) tries to show that, Metonic Cycle is a cycle effects on all inner
planets, for example, Earth moves during Metonic Cycle Period (6939.75 days) a
distance = Uranus orbital circumference =18050 mkm. i.e. Metonic Cycle isn't a
cycle limited on the moon motion but is used by different planets motions.
Equation No. (1)
6939.75 days (Metonic Cycle period) = π3
x 224.7 days (Venus orbital period)
(Error 0.4%)
- Equation No. (1) tells that Venus orbital period is created as a function of Metonic
Cycle period with the rate π3
, why this rate (π3
)??
- (Uranus axial tilt 97.8 deg /Jupiter axial tilt 3.1 deg) = π3
- Why the equation uses the rate π3
??
- Please see Equation No. 4 for this question answer….
Equation No. (2)
6939.75days (Metonic Cycle period)=118.3x 58.66days (Mercury rotation period)
- 118.3 degrees = 90 degrees +28.3 degrees (Neptune Axial Tilt)
- Equation No. (2) tells that Mercury rotation period is created as a function of
Metonic Cycle period based on (118.3) (Neptune axial tilt VERTICALLY),
- Why Neptune?? Later we may answer …. But
- Why Vertically??
- Because Metonic Cycle is produced by A Vertical Motion
- It's a vertical motion, but only the moon has the chance to move it and because of
that we conclude it in the moon motion…. i.e. the other inner planets have the
same vertical effect and if they have the chance to move vertically they could
move Metonic Cycle motion, but no one has this option except the moon – so the
vertical motion effect is found on the other planets as a potential effect.
Please Note
- Neptune is an important player in Metonic Cycle… for example… the moon orbit
regression 19 degrees yearly and that causes to create Metonic Cycle… that means
the moon regresses per month 1.44 degrees (1.44 deg = 1.8 deg x 0.8 deg), and we
know that (1.8 degrees = Neptune orbital inclination) and (0.8 degrees = Uranus
Orbital Inclination) … BUT we know that Metonic Cycle is found by Uranus
effect basically… so the equation tells us that, Neptune effects on Metonic Cycle

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greatly by Not Understandable Effect – because Metonic Cycle is a motion done
by energy found by light motion for Jupiter to Uranus, Neptune here does some
parasitic inexplicable role – shortly – How Neptune reach to Metonic Cycle??
Equation No. (3)
(116.7 days / 58.66 days) = (687 days/346.6 days) (Error 0.4%)
- Venus Day Period = 116.7 Solar Days
- Mercury Rotation Period = 58.66 Solar Days
- Mars Orbital Period = 687 Solar Days
- The Nodal Year = 346.6 Solar Days
- Equation No. (3) tells, the Nodal year 346.6 days (which causes Metonic Cycle), is
created based on the other inner planets periods of time –
- i.e. the Nodal year is a period similar to any inner planet orbital period, which
shows that, Metonic Cycle effect on all inner planets…

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Group No. (II)
Equation No. (4)
1271.4 degrees = 41 degrees x π3
- 41 degrees = The Planets Orbital Inclinations Total
- π3
= Uranus Axial Tilt/ Jupiter Axial Tilt, why this rate is used here?!
- Equation No (4) tells that, the motion (1271.4 degrees, which causes by Metonic
Cycle) is a collective motion because it depends on (41 deg) all planets orbital
inclinations total
- But why the rate π3
??
- We have seen this same rate is used in Equation No. (1) with Venus orbital period,
- (Uranus axial tilt 97.8 deg /Jupiter axial tilt 3.1 deg) = π3
….. also
- 90000 million km / 2872.5 mkm (Uranus orbital distance) = π3
o Let's remember this equation in following….
o 90000 mkm = C2
for a period 1 second of time, but we know that C2
is the
sun rays source of energy…this energy we see as 90000 mkm but the light
sees it as its source of energy
o The previous equation tells that, Uranus orbital distance is the first distance
created with the sun rays creation……
o Uranus orbital distance is created from C2
based on Uranus and Jupiter
interaction (π3
), So this rate shows the interaction between Jupiter and
Uranus by which they both effect on the sun creation process
o Why this rate (π3
) is found with Venus orbital period in Equation No. 1
(6939.75 days = (π3
) x 224.7 days)??!
Or why?
o Venus axial tilt 177.4 deg + Venus orbital inclination 3.4 deg = 180.8 deg,
but 180.8 deg = 90 deg + 90 deg + 0.8 deg (Uranus orbital inclination), the
question should be as following…
o Are Venus and Uranus found on straight line (180 degrees)?! How that can
be possible and why?? then if Uranus effect on the sun creation process,
does that mean Venus also effect on the sun position in the sky …. Shortly
o Are The Sun, Uranus and Venus found on a straight line (180 degrees)?
This question we have to discuss later…

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Equation No. (5)
1271.4 degrees = 97.8 degrees x 13
- 97.8 degrees = Uranus Axial Tilt, but what's this 13??
- Equation no (5) tells, the value 1271.4 degrees is found based on 2 independents
values (97.8 degrees and 13)
i.e.
- these values aren't created based on each other, but independently from each other,
its some marriage between (97.8 deg. and 13 and the born child is 1271.4 deg)
- So the moon vertical motion (1271.4 degrees) is found based on 2 players, Uranus
is the first one and what's the other player (13)?!
Equation No. (11)
13 degrees2
= 2.6 degrees x 5
13 degrees, we asked about it in the previous equation directly ….
2.6 degrees = 180 degrees – 177.4 degrees (Venus Axial Tilt)
5 = 5 million km = (152.1 mkm – 147.1 mkm)
13 is a cooperation done between Earth and Venus,
- Earth and Venus on one side and Uranus on the other side to produce (1271.4
degrees) The Moon Vertical Motion …. How to understand that?
- To produce the vertical motion, there are 2 different jobs should be done by Earth,
but because the Earth is so busy in the first job, Venus is used to do the second one
So, obligatory, and because of the geometrical necessity, Venus and Earth do
together 2 complementary jobs for the moon motion where these 2 jobs are seen as
one job only because they are so complementary to each other strongly, means no
one job can be found without the other, but the geometrical necessity forced Earth
to do one job only and Venus to do the other…
- How to understand that??
- Earth is busy in creation of the rate of time (1 to 365.25) through the moon orbit
regression, this rate is the inevitable requirements to produce the sun rays
- Venus has to define the sun position in the sky, because Earth is so busy to do.
- 13 expresses the cooperation between Venus and Earth to do these 2 jobs.
- But how this 13 degrees became 13.18 degrees in the moon motion??
Additional Equation No. (I)
- 27.2 days /149.6 mkm = 0.18 days So (13+0.18= 13.18 degrees)
- 27.2 days = The Perigee Cycle Month, the moon needs 27.2 days to reach to
perigee point again
- 149.6 mkm = Earth orbital distance,

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- Because the moon orbit regresses 19 degrees per year and causes the eclipse
calendar to be changed for 19 days, that means, 1 degree =1 day for the moon orbit
because of that, the value 0.18 days can be easily 0.18 degrees and perform the
equation (13 degrees +0.18 degrees= 13.18 degrees)
- Please remember, in the effect on the moon motion, Venus and Earth are on one
side and Mars is on the other side… let's remember that in following
Old Equation No. (A)
- (1.6 degrees x 0.98562 degrees) / (0.526 degrees) =3.02 degrees
- 1.6 degrees = 360 degrees /224.7 days (Venus Orbital Period)
- 0.9856 deg = 360 degrees /365.25 days (Earth Orbital Period)
- 0.526 deg = 360 degrees /687 days (Mars Orbital Period)
- The value 3.02 degrees shows the 3 planets motions interaction effect on the moon
motion – as we have discussed in the previous paper…
- In the new equation, we see that Venus and Earth are cooperated on one side and
Uranus on the other side in Equation No. 5 (1271.4 degrees= 97.8 degrees x 13)
- That tells us, Venus and Earth cooperate with some deep relationship, which needs
more analysis – any way – Venus defines the sun position in the sky based Uranus
supervision while The Earth is busy to produce the sun rays …
- This complex discussion, we will neglect for now, and concentrate only on
Number (13) which is (Venus and Earth Cooperation) to produce (1271.4) which
is the moon vertical motion by a direct effect of 97.8 deg (Uranus Axial Tilt)
- Equation no. (5) tells that, 2 players work independently (97.8 degrees and 13) to
produce the moon vertical motion (1271.4 degrees)
- Note Please, Uranus Axial Tilt 97.8 degrees, is created by light motion, before
any matter creation, means, Uranus axial tilt is not created by any of these
equations, it's found before all …Because light with known velocity (0.3mkm/sec)
travels from Jupiter to Uranus (2088 mk) in 6939.75 seconds (By contraction
6939.75=71x 97.8) produced Uranus Axial Tilt before any matter creation
Equation No. (6)
346.6 days = The nodal year
26.7 degrees = Saturn Axial Tilt
13 = Venus and Earth Cooperation Number
- Note Please,
o 1 degree =1day of the moon regression, so 346.6 degrees = 346.6 days = the
nodal year.

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o 26.7 deg +90 deg =116.7 deg, where Venus day period =116.7 solar days,
also (Saturn Mass /Venus Mass) = 116.7,
o That tells the value 116.7 or 26.7 is a common value between Venus and
Saturn, i.e. this value 26.7 deg shows also Venus effect on the moon motion
data but through Saturn.
- Equation No. (6) tells that, the nodal year is created based on Venus and Earth
Cooperation with some help from Saturn…
Remember Please
Equation No. (8)
1271 days = 346.6 days x 3.66
3.66 = (Earth diameter / the moon diameter) …. Also
(3.66)2
= (365.25 days Earth orbital period / 27.3 days the moon orbital period)
- Equation No. (8) tells that, the nodal year (346.6 days) is produced from 1271.4
days (proving that, the moon orbit regression is produced by the moon vertical
motion), but these 2 values are rated to each other by the diameters rate, i.e., this
relationship is fixed one because the diameters are fixed – i.e. – The moon vertical
motion which causes the moon orbit regression is A Permanent Motion!
Equation No. (7)
103 degrees = 13 degrees + 90 deg
- Pluto orbital distance =5906 mkm = 102 x 57.9 mkm (Mercury orbital distance)
- 103 = 102 (5906 mkm) + 1 (57.9 mkm)
- i.e.
- 103 is a relationship between Pluto and Mercury But 103 deg = 13 deg +90 deg
- How to understand that??
- Pluto was The Mercury moon before Mars Migration
- Equation No. (7) tells that, The Earth moon will be built based on the same rules
by which Mercury had controlled its moon (Pluto), so the rules are doubled in the
solar system – because Pluto still save its motion rules and the Earth moon is
produced based on these same rules, may that explain why Pluto velocity daily =1/
the Earth moon velocity daily)
Note Please
17.4 deg – 4.37 deg = 13 deg
- 13 degrees = 17.4 degrees (the inner planets orbital inclinations total) – 4.37 deg
(Where 4.37 deg=4.37 mkm = the sun circumference)
- This equation tells that, the sun circumference is created as a function of the inner
planets orbital inclinations total in one side and Venus Earth Cooperation (13)
on the other side…..

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- Please remember, the sun circumference =361 Venus diameter, but the light
needs 361 seconds to reach Venus from the sun,
- But the sun diameter /Venus diameter =115 this rate is so important one in the
solar system because Mars axial tilt =25.2 degrees but 115.2 = 25.2 +90
- Also Saros shift angle =115 degrees but 6585.3 days (Saros) = 115 x (180/π)
Equation No. (9)
1271.4 days = 2 x 23.45 x 27.1
- 27.1 = 27.3 days x 0.99
- Equation No. (9) tells that, the value 1271.4 days is created based on Earth axial
tilt 23.45 degrees and the moon orbital period (27.3)
- But why uses 2 values of Earth axial tilt? It's used in many different equations let's
see that in following….
Equation No. (10)
1271 = 113.45 x 2 x 5.1
- 113.45 deg = 90 deg +23.45 degrees (Earth Axial Tilt)
- 5.1 degrees = The moon orbital inclination
- Again uses the axial tilt (2 times)! Why? this feature is found frequently in the
equations as we see,
- Here also
- 1271.4 degrees = (25.2 degrees )2
x 2, uses a double value of (25.2)
- Equation No. (10) tells that, Metonic Cycle depends on (double values) of the
Earth Axial Tilt! Why??
o (23.45 degrees)2
= 1.52 x 361 degrees
o Metonic Cycle = 19 degrees x 19 years = 361 degrees
o 5.1 deg (the moon orbital inclination) = 3.4 deg (Venus orbital inclination) x
1.52
o The moon vertical motion is done by a cooperation between the Earth and
Venus – why this information is useful??
o Because … we know that, Venus is higher than the moon and Earth is lower
than the moon and that means, the planets are found on stairs (steps)
different horizontally from each other…
o Not please, the moon moves above and under the Earth….

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Equation No. (12)
1271.4 = 254.2 x 5
- 254.2 lunar sidereal months (27.3 days) in Metonic Cycle
- We know that 1271.4 degrees is Metonic Cycle degrees value
i.e.
- Equation No. (12) has 2 values express Metonic Cycle (1271.4 & 254.2)
- So what's this 5 which is found between both?? We know that 5 mkm is the Earth
free motion (from 152.1 mkm -147.2 mkm =5 mkm)…but let's see one more old
equation…
Old Equation No. (B)
3475 km (the moon diameter) x 43000 km (Perigee apogee distance) = 149.6 mkm
- This is a very strange equation! Because the moon motion free space (the distance
between perigee and apogee =43000 km) is proportional with Earth orbital
distance 149.6 mkm and not Earth free space (5 million km)! how to explain that??
- 43000 km (the moon free space) tells us that, the moon can move from perigee to
apogee ….
But
- 149.6 mkm tells us nothing, because the Earth can't move to the sun point, the
Earth orbital distance change is from 152.1 mkm to 147.1 mkm = 5mkm that
means this equation gives us no meaning because both motions aren't equivalent to
each other …
- Otherwise the Earth can move to reach to the sun point!! So the distance 149.6
mkm (totally) will be considered as the Earth free motion space!!
- But
- 5000000 km = 3475 km (the moon diameter) x 1440
- 43000 km = 1440 seconds x 29.8 km/sec (Earth velocity per second)
- During 1440 seconds, Earth moves a distance = 43000 km (perigee apogee
distance). But this 1440 seconds is defined as a rate between Earth free space (5
mkm) and the moon diameter (3475 km)
- How to understand this language?? It's the solar system language… we have to
understand as clear as possible… this language by which Mercury orbital period
88 days is seen in the moon data as 88000 km, these 2 values are one value, and
the 2 planets are 2 balanced points of one light beam which transports the energy
from on planet (point) to another, and this energy is transported by its value but

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seen by 2 different forms…. this language is not strange for us… we have seen it
frequently.. while Mercury moves during its rotation period (58.66 days) a distance
as 243 mkm, but Venus sees this 243 mkm as 243 days (where Venus rotation
period =243 days)… also Venus moves during (365.25 days) a distance = 2π x
175.94 mkm, But Mercury day period =175.94 days ….. it's a language used
frequently….
- Its point is clear, that the unit is relative, what's defined as time can be seen as
distance (as in light motion, where x =ct, when c=1 So x =t ) .. this feature is found
in the planet motion because (Light Motion Features Are Discovered In Planet
Motion) please review my paper in this subject …..
- Also, 1 million km = 1 degree, that because Mercury orbital circumference = 360
mkm = 360 degrees… that makes the unit is relative for example when we see that
(28.3 degree/26.7 deg) = (26.7 degrees/ 25.2 deg) = (25.2 degrees /23.4 deg) – in
such equation we can replace the distance (1mkm in place of 1 degree) and
explain the equation based on that….
But
- How to explain this equation
- 5000000 km = 3475 km (the moon diameter) x 1440
- This equation tells, Earth motion free space (5 mkm) is created in proportionality
to the moon motion free space (43000 km) based the moon diameter ….. it's
perfectly as the (B) equation it's the same meaning….
- But
- This equation tells about Earth motion from 152.1 mom to 147.1 mkm (5 mkm) in
proportionality with the moon motion free space (43000km) which is the distance
from (perigee 0.363 mkm) to apogee (0.406 mkm)…
And what about the previous one
Old Equation No. (B)
3475 km (the moon diameter) x 43000 km (Perigee apogee distance) = 149.6 mkm
- Who can reach to the sun according to this equation?!
- The moon motion between perigee and apogee is created in proportionality with
someone moves from Earth point to the sun point at distance (149.6mkm)! and
what's this someone who can travel to the sun?!!
- It's the light beam
- Or the energy from which the light beam is created
- This equation tells us that, the sun rays are created by an effect done by The Earth
& moon motions interaction ….
- The distance 149.6 mkm is correctly used because it expresses the sun rays
production process…

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Equation No. (13)
670 mkm = Venus Jupiter Distance
1.9 deg = Mars orbital inclination
- 1.9 is a rate used by all inner planets distances… so we may conclude that, this 1.9
is a common used value by the inner planets
- (for example, 78.3 mkm x 1.9 =149.6 mkm, and 119.7 mkm x 1.9 = 227.9 mkm,
also 78.3 mkm = 41.4 mkm x 1.9 and 108.2 mkm = 1.9 x 57.9 (error 1.7%))
- 670 mkm = Venus Jupiter Distance
- We accept that, the three inner planets (Mercury, Venus and Mars) unify their
energies to effect on the moon motion to perform the other distance 88000 km
- The energy is ready, but Jupiter is the inner planets parent, so the three planets
will send this energy to Jupiter and Jupiter will use it for the Earth moon sake,
- If Jupiter is the inner planets source of energy, why Jupiter doesn't send its own
energy in place of the 3 inner planets? Because Jupiter has sent already its energy,
and now Jupiter is spent of energy, means, Jupiter has nothing left after he sent its
energy to the inner planets and to Pluto also…
- So, Jupiter will use the (inner planets energies total) to effect on the Earth moon,
can Jupiter do this job? NO why Not
- Because Jupiter effects on the horizontal level, and Earth gravity controls the
moon on the horizontal level.
- So, how to use this energy to effect on the moon motion? Jupiter will send this
energy to Uranus and Uranus will effect on the moon motion Vertically
- So what does this equation No. (13) tell us?
- It shows the energy sent from the 3 inner planets to Jupiter through Venus, why
Venus? Because it has a direct connection with Jupiter… please remember
o Mercury moves during its Day period a distance = Mercury Jupiter distance
o Venus moves during its orbital period a distance = Venus Jupiter distance
o Earth moves during its orbital period a distance = Earth Jupiter distance
(but Earth and Jupiter should be at 2 different sides from the sun)
- i.e.
- Venus is the only planet has a direct connection with Jupiter between the 3 inner
planets ….
- Please note, Mars Migration caused Mars to lose its connection point with Jupiter
and has to depend on Saturn (where Mars moves during its orbital period a
distance = Saturn orbital distance)

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Equation No. (14)
1271.4 mkm =88000km x14448 days (but 6939.75 x2.082 mk= 14448 mkm)
- 14448 mkm is the distance passed by Mars during Metonic Cycle,
- If this distance is used as time period (14448 days), so the moon during this period
will pass a total displacement =1271.4 mkm which = 1271.4 degrees
- Equation No. (14) tells that, Mars is a partner in Metonic Cycle, means Mars does
Metonic Cycle but not by Vertical motion, but does it on the horizontal level.
- That means, Mars motion for Metonic Cycle is a geometrical necessity for this
cycle to be performed
Equation No. (16)
1124 degrees = 1140 days x 0.9856262 degrees
Let's remember this idea
- The moon daily displacement = 88000 km, let's imagine the following….
- The moon moves only a vertical motion from perigee to apogee and return back, as
the figure shows in 2 arrows (red and blue). The distance from perigee to apogee =
43000 km, so the travel once and return back costs 86000 km but the moon daily
displacement = 88000 km, which means, there's still only 2000 km of the moon
daily displacement, and the moon will use it in a horizontal displacement
o At apogee orbital circumference 2.58 mkm this 2000 km needs 1290 days
o At perigee orbital circumference 2.28 mkm this 2000 km needs 1140 days
- Equation no (16) tells that, this 1140 days will be = 1124 degrees
Equation No. (15)
1124 degrees = 41 degrees x 27.41 …. Please remember Equation No. (4)
Equation No. (4)
1271.4 degrees = 41 degrees x π3
- 41 degrees = The Planets Orbital Inclinations Total
- Equation No (4) tells that, the motion (1271.4 degrees, which causes by Metonic
Cycle) is a collective motion because it depends on (41 deg) all planets orbital
inclinations total
- Equation No. (15) tells this same meaning that, the motion (1124 degrees) is a
collective motion because it depends on (41 deg).

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1-3 The Moon Orbit Regression Analysis
In this point we try as possible to explain what causes the moon orbit regression
(1st
Point The Regression Discussion)
What does mean that, the moon orbit regresses 19 degrees yearly??
Let's try to draw that in following
- In the figures, I try to explain how the moon orbit regresses 19 degrees per year.
- The left figure shows that, the angle is Zero degrees on the horizontal line…. But
- The right figure shows an angle =19 degrees on the horizontal line, now we need
to ask…. If the Earth moon distances are fixed how that can be occurred?
i.e.
- How the apogee radius still =406000 km If the moon orbit regresses yearly with 19
degrees -
- I want to say, if the moon regresses yearly 19 degrees and the Earth moon
distances still without changes… that means … Earth itself change its position in
the space (the moon orbit) according to this regression
i.e.
- The moon orbit regression is a proof that, Earth changes its position in the space
according to the moon orbit regression….
- The Earth revolves around the sun and that changes its position in the space but I
don't mention this change, I mean, the moon orbit regression is a proof that the
Earth changes its position in the space ACCORDING TO the moon orbit
regression…
- So, if the moon orbit regression is done because of the moon vertical motion, that
means Earth must have a vertical displacement and this vertical displacement
causes the moon orbit regression.
E
E

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- The available data is that, Earth moves vertically 1 kilometer per solar day, this
motion is a vertical displacement done by Earth perpendicular on its position.
- I want to say, we have 3 motions are done but 1 motion only is seen and we have
to conclude the 2 hidden motions…. These three motions are
o The Moon Orbit Regression
o Earth moves vertically 1 km per solar day
o The moon moves vertically 2000 km per solar day
- These 3 motions are done depending on each other – and we have to conclude the
2 hidden motions by analysis the moon orbit regression
- The previous analysis tells us that, Earth must change its position in the space
according to the moon regression yearly (19 degrees) to save the distances between
Earth and the moon as them without changes
- Before to start the next point discussion, I need to explain how I know that the
Earth moves vertically 1 km per solar day, let's try to explain that in following:
o The Earth original orbital distance almost was 153 million km
o The Earth has seen 3 cycles of the phenomenon 2737 years, which we have
discussed before …
o The period 2737 years = around 1 million days
o 3 Periods of this cycle (2737 years), means around 3 million days
o Earth current orbital distance =149.6, means Earth orbital distance is
decreased around 3 million km in 3 million days, means 1 km per day
o This conclusion is NOT A Proof, it's a reason for a hypothesis, where I
suppose that (Earth moves vertically per a solar day 1 km) this is just a
hypothesis and we have to find proves for it in The Earth and Moon motions
data…
- The next question how the Earth vertical displacement (1 km) depends on the
moon orbit regression…

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18
(2nd
Point The Earth & Moon Motions Reason)
Let's return to the double production experiment…
- From Gamma rays (1.2 Mev), an electron and a positron are produced…. If we left
them in free space, they would attract each other and create again Gamma ray…
- But, let's imagine
- We will push the electron into some pipe, and the positron into another one, these
pipes are connected to each other but not with a direct connection instead we will
allow only the indirect passages to prevent their direct attraction, but use their
charges attraction to cause their motion to each other…. The idea is a simple one
- Into the maze which we have created for the electron and positron, they move to
reach each other but couldn't do that because the maze doesn't provide the chance
but always uses their charges attraction in their motions… we simply have a
continuous motor of a continuous motion…
Now Let's remember our old model…….
- Because Earth mass = the 4 inner planets masses total, I suppose that, one great
Gamma Ray (or any suitable electromagnetic wave) is used in a great double
production process, from this process Earth is created as (the great electron) and
the 4 inner planets are created as (the great positron)
- (The Great Electron) means, Earth atom has a positive nucleus and a negative
charge (electrons) moves around
- (The Great Positron) means, The 4 inner planets atoms have a negative nucleus
and positives charges (positrons) move around
- The attraction between these 5 planets are found based on their charges attraction
One more suggestion I need to inset here
- We should accept that, the moon behaves in place of all 4 planets, that means, the
moon motion is a representative of the 4 planets motions, and that makes the
picture between the Earth and its Moon as a similar to a picture between an
electron and an positron….. still we need one more suggestion
- We have to suggest that, the planets charges attraction or repulsion is so weak and
be equal to the gravity force effect, and that means, the moon is attracted into its
orbit around Earth by the charges attraction but the Earth can't attract the moon
strongly to it because of the Earth Centrifugation, so we have 2 equal forces, one
force is produced by electric charges and the second is produced by the gravity
Centrifugation, and the moon motion is stable because these 2 forces are equal
- But, the stability doesn't produce a static case, but a dynamic motion based on
which the moon does its vertical motion and the Earth does its daily displacement
1 km vertically…

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19
(3rd
Point "The moon behaves in place of the 4 inner planets " The Proves )
I-Data
(a)
2000 km = 19 x 105
(b)
((4.095 mkm + 3.02 mkm +2.082 mkm) /88000 km)) = 105
(c)
105 = 1.16 mkm/10921 km
(d)
(2000/7) = (the sun diameter/ Mercury diameter)
Equation (a)
2000 km = 19 x 105
2000 km is the moon daily displacement if the moon moves its vertical motion…
let's remember….
- The moon daily displacement =88000 km
- Suppose, the moon moves only in vertical motion, from perigee to apogee
(distance 43000km) and return back (43000km), so the moon consumes in this
motion (86000km) of its daily displacement 88000 km, so the rest is 2000 km
which the moon will use in a horizontal displacement….
- 19 degrees = the moon orbit regression per year
- Equation No (a) shows 2 basic motions of our 3 motions, (1st
motion) is the moon
vertical motion and (2nd
motion) is the moon orbit regression,
- Equation No (a) tells that, the moon orbit regression is done depends on the moon
vertical motion because of the rate 105
And
- What's this 105??
Equation (b)
((4.095 mkm + 3.02 mkm +2.082 mkm) /88000 km)) = 105
4.095 mkm = Mercury velocity per solar day
3.02 mkm = Venus velocity per solar day
2.58 mkm = Earth velocity per solar day
88000 km = the moon daily displacement
- Equation No (b) shows that, the moon daily displacement is a representative of
the 3 inner planets motions,
- This is the equation we need, Because it tells that, the value 88000 km is
produced by a total effect from (Mercury + Venus + Mars) motions daily…
- The equation shortly proves that, the moon behaves as (the great positron) relative
to Earth, Because Of the 3 inner planets effect on it to move this value 88000km

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20
Equation (c)
105 = 1.16 mkm/10921 km
- Light supposed velocity 1.16 mkm /sec travels a distance =1.16 mkm per a second
- The moon rotates around its axis (10921 km) one per 27.3 days,
- We know that,
- 29.53 days (or 27.3 days) is equivalent to = 1 solar day of Earth motion, and we
know that 1 solar day of Earth motion is equivalent to 1 second of light motion that
because (light motion for 1 second causes planet motion for 1 solar day)
- The equation tells that, the rate 105 which equal (the three planets velocities total /
the moon daily displacement), and which shows that, the moon daily displacement
is produced by the three planets effect (Mercury + Venus + Mars) …. This same
rate is found between Light motion and the moon motion
- Equation No. (c) tells that, the energy is transported from the light motion to the
moon motion, but this transportation is done through the 3 planets motions… so
the moon motion energy is provided by light motion but transported by the three
planets motions – and that means- these 3 planets motions are done by light motion
but they use nothing of this energy for themselves, instead, all energy they send to
the moon
Equation (d)
(2000/7) = (the sun diameter/ Mercury diameter)
7 degrees = Mercury orbital inclination
2000 km = the moon displacement in its vertical motion
- 1degree = 1 mkm , so if we us (2000) here, it must be (2000 mkm), but the moon
displacement =2000 mkm only!!
- That means…… this 2000 km is multiplied with 1 mkm, where the moon orbital
diameter = 1 mkm …
- Equation No (d) tells that, the sun diameter creation is effected by the moon
vertical motion…how that can be possible??
Because
- The moon vertical motion causes the moon orbit regression, and the moon orbit
regression is the basic player in the creation of the rate of time (1 to 365) and the
sun rays is created based on this rate of time

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21
The Equations Discussion
- The previous equations shows that, the moon behaves in place of the 4 inner
planets, simply, the 3 inner planets provided the moon their motions energies and
by that the moon moves by force = the 4 inner planets masses total = Earth mass
=Earth gravity.
Shortly
- If there's A Great Electron, so it's The Earth, and if there's A Great Positron, so
it's the moon,
- Based on that, the Earth and Moon motion is a motion between electron and
positron.
But
- The charges attraction is so weak and because of that, the Earth and moon charges
attraction force is equal Earth gravity force and because of that the attraction
between the Earth and its moon = The Earth Centrifugation. That saves the moon
in its orbit around The Earth…

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22
(4th
Point " The Earth displacement is proved by Eclipse phenomenon"
- I claim that, "Earth does a vertical displacement per solar day = 1 km, and this
displacement is in consistency with the moon orbit regression" how to prove that??
o Saros Cycle proves that, let's analyze it as possible
o Saros Cycle on Earth is a cycle of the total solar eclipse umbra which wipes
the Earth surface, and this process creates a cycle to wipe the whole Earth
surface where the shift angle is 115 degrees
o How this cycle is created? we here have 2 machines
o (1st
machine) which creates the total solar eclipse umbra, and this machine
works by the Sun and Moon motions, because Earth here is a bearer and it
will receive any shadow sent …. means…. Any diameter of Earth should
not have any effect on the shadow sending process
o (2nd
machine) is the Earth surface in its motion…. this surface will receive
the shadow sent from the total solar eclipse phenomenon,
o The 1st
machine has a cycle (Metonic Cycle), means, the moon moves a
long way to specific point and return again
o The2nd
machine has no cycle, because it’s a surface will receive any shadow.
o If the situation is that, Saros Cycle can't be created, because while the moon
does Metonic it moves along its road and the Earth receives the shadow
whatsoever, but when Metonic Cycle (road) is longer than the Earth
diameter (capacity) to receive the shadow, the rest shadow will be thrown
into the space,
o That will show the shadows on the Earth surface in some pulses and no
cycle can be created
o Otherwise the Earth moves by this same Cycle (Metonic) which the moon
moves, in this case the Earth will provided (always) the available surface to
receive the total eclipse umbra shadow, and by that Saros Cycle can be
created
o I want to say that, if Metonic Cycle is created by the moon orbit regression,
so Earth also must does some motion (as a partner) with the moon in its
orbit regression…. Means the moon orbit regression proves the Earth
vertical displacement…

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References
The Moon Motion Trajectory Analysis (II)
https://www.academia.edu/44368860/The_Moon_Motion_Trajectory_Analysis_II_
or
https://www.slideshare.net/Gergesfrancis/the-moon-motion-trajectory-analysis-ii
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
or
https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion
Can Different Rates Of Time Be Found In The Solar System Motion?(II)
https://www.academia.edu/44334645/Can_Different_Rates_Of_Time_Be_Found_In_The_Solar_System_Motion_II_
Does Particle Data Depend on Its Motion? (Lorentz Transformations Analysis)
https://vixra.org/abs/1912.0134
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944&p=15209
Mr.Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Gerges Francis Tawdrous +201022532292
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
Linkedln https://eg.linkedin.com/in/gerges-francis-86a351a1
Facebook https://www.facebook.com
Researcherid https://publons.com/researcher/3510834/gerges-tawadrous/
ORCID https://orcid.org/0000-0002-1041-7147
Quora https://www.quora.com/profile/Gerges-F-Tawdrous
Google https://scholar.google.com/citations?user=2Y4ZdTUAAAAJ&hl=en
Academia https://rudn.academia.edu/GergesTawadrous
List of publications http://vixra.org/author/gerges_francis_tawdrous

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