Module for Grade 9 for Asynchronous/Distance learning
Solar System Geometry (Summarized Discussion - Part 3)
1. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Solar System Geometry (Summarized Discussion - Part 3)
Gerges Francis Twadrous
2nd
Course Student – Physics Department - Physics & Math Faculty –
Peoples' Friendship University – Moscow – Russia -2010-2013
TEL +201022532292 mrwaheid@gmail.com / georgytawdrous@yandex.ru
The Assumption Of S. Virgin Mary -Written in Cairo – Egypt – 4th
August 2019
Abstract
The Sun Creation process depends on
(1) Jupiter Energy
(2) Earth Motion
(3) Different Rate Of Time
(4) Earth Moon Orbit
(5) Mars Effect
Gerges Francis Tawdrous +201022532292
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
Linkedln https://eg.linkedin.com/in/gerges-francis-86a351a1
Twitter https://twitter.com/TawdrousF
Facebook https://www.facebook.com/gergis.tawadrous
Academia https://rudn.academia.edu/GergesTawadrous
All my papers http://vixra.org/author/gerges_francis_tawdrous
2. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
2
1- Introduction
We complete our discussion in the previous papers
Solar System Geometry (Summarized Discussion- part 2)
https://www.academia.edu/40001387/Solar_System_Geometry_Summarized_Discussion_-_Part_2_
Solar System Geometry (Summarized Discussion part 1)
http://vixra.org/abs/1908.0016
In this papers series we discuss a heavy claim – which is:
Sun Rays Are Produced By Planets Motions Energies Accumulation
And Not By Any Nuclear Interactions –i.e. –Planets Motions
Mechanical Waves Are Transformed Into Light Waves...
Because the claim is heavy we need hard discussion and huge analyzed data – that's
why the discussion needs many papers-
Our discussion depends on my solar group alternative description- which I provide
with Nasa Planetary fact sheet in following page to be our main references
In this paper – we need to answer many questions – before any progress we may
perform…. Let's write these questions in following:
Question No. 1
Does Neptune And Jupiter Relationship Control The Solar Group Data?
Question No. 2
If Jupiter Energy = 86400 mkm only how the value 90000 mkm is produced and why
this value 90000 mkm = C2
(which we know from the electrodynamics)
Question No. 3
How the sun rate of time can be different from Earth Rate of Time and why the moon
orbit effects on the sun rate of time?
Question No.4
How the sun diameter is created? (What's Mars Role in the sun creation process)
Question no. 1 (answer) in Point 2-1
Question no. 2 (answer) in Point 2-2
Question no. 3 (answer) in Point 2-3
Question no. 4 (answer) in Point 2-7
Research Methodology is discussed in this paper
Solar System Geometry (Summarized Discussion part 1)
http://vixra.org/abs/1908.0016
3. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
3
Planetary Fact Sheet - Metric
MERCURY VENUS EARTH MOON MARS JUPITER SATURN URANUS NEPTUNE PLUTO
Mass (1024
kg) 0.330 4.87 5.97 0.073 0.642 1898 568 86.8 102 0.0146
Diameter (km) 4879 12,104 12,756 3475 6792 142,984 120,536 51,118 49,528 2370
Density (kg/m3
) 5427 5243 5514 3340 3933 1326 687 1271 1638 2095
Gravity (m/s2
) 3.7 8.9 9.8 1.6 3.7 23.1 9.0 8.7 11.0 0.7
Escape
Velocity (km/s)
4.3 10.4 11.2 2.4 5.0 59.5 35.5 21.3 23.5 1.3
Rotation
Period (hours)
1407.6 -5832.5 23.9 655.7 24.6 9.9 10.7 -17.2 16.1 -153.3
Length of
Day (hours)
4222.6 2802.0 24.0 708.7 24.7 9.9 10.7 17.2 16.1 153.3
Distance from
Sun (106
km)
57.9 108.2 149.6 0.384* 227.9 778.6 1433.5 2872.5 4495.1 5906.4
Perihelion (106
km) 46.0 107.5 147.1 0.363* 206.6 740.5 1352.6 2741.3 4444.5 4436.8
Aphelion (106
km) 69.8 108.9 152.1 0.406* 249.2 816.6 1514.5 3003.6 4545.7 7375.9
Orbital Period (days) 88.0 224.7 365.2 27.3 687.0 4331 10,747 30,589 59,800 90,560
Orbital
Velocity (km/s)
47.4 35.0 29.8 1.0 24.1 13.1 9.7 6.8 5.4 4.7
Orbital
Inclination (degrees)
7.0 3.4 0.0 5.1 1.9 1.3 2.5 0.8 1.8 17.2
Orbital Eccentricity 0.205 0.007 0.017 0.055 0.094 0.049 0.057 0.046 0.011 0.244
Obliquity to
Orbit (degrees)
0.034 177.4 23.4 6.7 25.2 3.1 26.7 97.8 28.3 122.5
Mean
Temperature (C)
167 464 15 -20 -65 -110 -140 -195 -200 -225
Surface
Pressure (bars)
0 92 1 0 0.01 Unknown* Unknown* Unknown* Unknown* 0.00001
Number of Moons 0 0 1 0 2 79 62 27 14 5
Ring System? No No No No No Yes Yes Yes Yes No
Global Magnetic
Field?
Yes No Yes No No Yes Yes Yes Yes Unknown
MERCURY VENUS EARTH MOON MARS JUPITER SATURN URANUS NEPTUNE PLUTO
Note Please
- I Use this Data basically in all my papers you can find it on the following link
(https://nssdc.gsfc.nasa.gov/planetary/factsheet/)
- I analyze this data to conclude the geometrical rules behind it
- I analyze this Data based on the following hypothesis:
There's One Equation Controls All Previous Data. i.e. All Planets
Data Are Created Relative To Each Other And There's One
Equation Only Controls All This Table Data –
In following Page I provide my suggested description for the solar group which may
explain this hypothesis reasoning
4. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
4
Solar Group alternative Description (My Suggested Description)
1- The solar group is one trajectory of Energy and each planet is a point on this
same trajectory
i.e.
2- The Solar Group is One Building and each planet is a part of this same building-
3- Also The solar group is similar to a train and each planet is a carriage of it.
4- Also the solar group can be similar to one body, and each planet is a member in it
5- Also, The solar group can be similar to one machine and each planet is a gear in
this same machine…
That means
6- When a planet moves –it doesn't mean this planet moves individually and
independently from the other planets- NOT TRUE – The Planet moves with all
other planets together as a train moves with all carriages –
Description Basic Concept
Planets cooperation and integration is the reason of their existence and motions.
How to understand that?
WE know that the matter is created of Energy (E=mc2
) – but How The Space Is
Created? I suppose the Space is created of Energy also… (Space = Energy)
So the matter and space both are created from the same energy..
Can that be possible?
Energy has different forms (sun rays – nuclear interactions – oil- food ..etc)
Different forms for same content, i.e. it's possible to create matter & space of energy
Another Example
In double slit experiment (Young Experiment) – the light coherence produced bright
and dark fringes –regardless the experiment explanation – the experiment tells "when
one input is used (light)–outputs can be in 2 different forms (bright and dark fringes)"
The Solar Group Creation
I suppose the solar group is one energy creates the planet matter and orbital distance
– so this same energy passes through the whole group to create all solar planets and
their orbital distances from the same energy where this energy creates all planets data
complementary to each other because all of them are created from the same source.
Shortly
The solar group is one thread – as one necklace – all solar planets and their distances
are created from one energy to be complementary to each other- and that's why the
planets data analysis shows the solar planets dependency.
5. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
5
2-1 Does Neptune And Jupiter Relationship Control The Solar Group?
I-Data
(1) Saturn Diameter – Jupiter Radius = Neptune Diameter x 0.99
(2) Jupiter diameters x 2 + Saturn diameter = solar planets diameters total
(3) Neptune Circumference x 2 = outer planets diameters total (except Neptune
diameter)
Note Please
a. Earth Circumference = Inner Planets Diameters Total
(4) Jupiter sends his energy for 2 days (as we have discussed in Part. 1)
(5) Mercury moves during 5040 seconds a distance = 2 Saturn Diameters
(6) (2.58 mkm moon orbital circumference at apogee - 2.41 mkm moon orbital
circumference at average point) = 2 x 88000 km (Moon daily displacement).
(7) Energy reflected from Neptune toward inner planets = 2 x 86400 km
(8) Jupiter Orbital Circumference =Mercury Orbital Circumference + Venus
Orbital Circumference + Earth Orbital Circumference + 2 Mars Orbital
Circumferences
(9) Mercury Orbital Circumference x 2 = Mercury Jupiter Distance
(i.e. mercury during his day period moves a distance = Mercury Jupiter Distance)
(10) Saturn Orbital Distance = Mercury Jupiter Distance x 2
(11) Uranus Orbital Distance = Saturn orbital Distance x 2
Let's remember also Jupiter & Saturn relationship equations in following:
(12)
(13)
2 Jupiter Circumferences - 2 Saturn Circumferences = 1 Jupiter Diameter (error 1.3%)
(14)
(Jupiter Diameter)2
+ (Saturn Diameter)2
= (0.5 Saturn Circumference)2
(1.2%)
(15)
2 Jupiter Diameters + 1 Saturn Diameter = Solar Planets Diameters Total (No Error)
i.e.
Jupiter Diameter = 8 Planets Diameters Total
(16)
Saturn Diameter – Jupiter Radius = Neptune Diameter x 0.99 (No Error)
12
2
km120536diameterSaturn
km142984diameterJupiter
−
=
π
π
6. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
6
I-Discussion
How to explain Jupiter Neptune Relationship?
Let's summarize the main points in following:
(1) Solar Group Main energy is sent basically from Jupiter Toward Pluto and
Reflected by Neptune – we have discussed that clearly in the previous paper
Solar System Geometry (Summarized Discussion part 1)
http://vixra.org/abs/1908.0016
(2) Equation No.(1) Saturn Diameter – Jupiter Radius = Neptune Diameter x 0.99
we have discussed this equation also frequently and we have discovered that
this equation tells that the relationship between Jupiter and Neptune causes
Saturn diameter creation – but the geometrical process of Saturn creation
required 2 diameters of Jupiter to produce 1 diameter of Saturn – as we have
seen – now I have concluded that the solar planets creation depend on Jupiter
because 1 Jupiter diameter = 8 planets diameters – based on that – the solar
planets diameters total = 2 Jupiter diameters + 1 Saturn diameter – this
equation is not found as a chosen design for the solar group but found as
geometrical necessity…! What does that mean? If 1 Saturn Diameter needs 2
Jupiter diameters to deal with –So the planets diameters total should equal
2 Jupiter diameters + 1 Saturn diameter – because the components geometrical
structure force the final system to be suitable for them –
i.e.
(3) Jupiter, Saturn and Neptune Creation define the general frame for the other
solar planets creation – clearly we see that there's no independency here – on
the contrary we see clearly the dependency- Simply – the solar planets data
depend on Jupiter, Saturn & Neptune Data…..
This is My Conclusion…. Can I prove it?
The planet data proves this idea clearly
(1st
Proof)
Many of Planets Data depend on the rate 2:1 …as we have seen in the previous data
(16 equations) - the double value (2) is used widely in the solar planets data… that
proves the claim that this rate is used based on a geometrical necessity…
Let's ask why this rate (2) is used frequently as such? Because Jupiter basic energy is
sent for a period 2 days and this feature is kept inside the moving energy from point
to another point which shows this feature according to the geometrical situation
(2nd
Proof)
Planet orbital Distance Equation
Planet orbital distance equation also depends on the rate 2: 1
d2
= 4do(d-do) i.e. d= 2 (do(d-do))1/2
the equation supports the data direction clearly – please review
Gerges Equations For Solar Group Geometry
http://vixra.org/abs/1906.0564
7. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
7
2-2 Additional Energy Origin Analysis
Let's remember the question….
If Jupiter sent Energy is 86400 mkm only how the value 90000 mkm is produced?
and why this value 90000 mkm = C2
(which we know from the electrodynamics)?
First
How this value 90000 mkm is produced?
86400 mkm +3600 mkm =90000 mkm
86400 mkm = Jupiter Sent Energy
3600 mkm = additional energy is produced based on the different rate of time
Is It True?
Let’s examine if the suggested rate of time can produce this energy!
I claimed that 1 day on the sun = 1 year on Earth
And we have asked
How the rate of time can be changed..? by relativistic effect
We have 3 rates of length contraction which are (7.1 – 1.0725 and 71)
71 is related to the sun data- as we will discuss later
So 71 mkm will be contracted to be 1 mkm
I claimed also that time and distance values are equivalent in higher velocities
So
71mkm can be easily 71 days and with contraction 71 days will be 1 day
This is not the required rate …We need
3635.25 days = 1 day
How ….because of the moon orbital inclination – as we have discussed before
71 days x 5.18 degrees = 365.25 days
Why The moon orbit effects on the sun rate of time? This is the next question
But here we need to be sure that –the change rate of time produced the required
energy ………….The rate of time is
365.25 days to 1 day
365.25 days x π2
= 3600 days
(The Sun Diameter = π2
x Jupiter diameter
also Saturn diameter= π2
x Venus diameter)
(The secret here is 1 second of light motion = 1 day of the planet motion)
For that reason – the value 3600 days will work as 3600 seconds
3600 seconds x 1.16 mkm/sec (supposed light velocity) =2088 mkm x 2
The additional energy is sent from Jupiter To Uranus through this distance (Jupiter
Uranus Distance)
(1 second of light motion = 1 day of the planet motion) we should discuss that later
But now let’s examine the moon orbit effect on the sun rate of time
8. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
8
2-3 The Moon orbit effect on the sun rate of time
Let's remember the question in following….
Why does the moon orbit effect on the sun rate of time? And How the sun rate of
time can be different from Earth Rate of Time?
I-Data
(A)
71 mkm = 2.58 mkm (Earth Motion Distance Daily) x 27.3 days (Earth moon orbital period)
(B)
71 mkm = 2.41 mkm (Motion orbital circumference at average radius) x 27.3 days
(Earth moon orbital period) ………………..Also
(C)
71 degrees = 63.7 degrees (Sun North Pole Declination) + 7.25 degrees he sun
Obliquity to ecliptic
We know that 71 is a rate of length contraction produced by velocity V2=0.9999C
Note Please
0.0001 C (Earth registered Velocity) +0.9999 C (supposed velocity) =c light velocity
II-Discussion
(1)
The first notice we can see in Earth and Moon motions are the incredible harmony
- Earth daily moves a distance =2.58 mkm = 0.985 degrees to complete 360
degrees in 365.25 days…
- i.e. Earth during 29.53 days move 29.2 degrees
but
- The moon moves daily 2.58 mkm but the moon during the day moves 13.18
degrees to perform 360 degrees during 27.3 days
Means
- The moon during 29.53 days move a distance = 389.2 degrees
- 389.2 degrees – 360 degrees = 29.2 degrees
Why these values are equal?
We should examine the moon orbit motion deeply – to be sure – that – the moon and
Earth move together as 2 gears in the same machine – the ruler of degrees for both of
them are one – which creates their motions harmony and interactions…
(2)
Moon Circumference 10921 km x 86400 seconds = 940 mkm (Earth orbital
Circumference) – we know this equation – it tells that – if Earth revolves around the
sun one complete revolution in one day – the moon circumference will be = 1 second
of Earth Motion
Also- 10921 km (Moon Circumference) x 27.3 days = 300000 km
(27.3 days = moon orbital period) and (300000km = light motion for 1 second)
The moon orbit and moon body details tell us that the relationship between Earth and
Moon is so complex and need a deep analysis…
(the sun circles Earth during 365.25 days because of the complex relationship between
the sun, Earth and Moon motion) (and without the moon orbit the sun can't be created)
9. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
9
2-4 The Moon Orbit Regression
I-Data
(1)
6585.39 degrees2
= 232.7 degrees x 28.3 degrees = 278.4 degrees x 23.6 degrees
6585.39 degrees2
= 115 degrees x (180/π)
(2)
727 degrees = 23.45 degrees x π3
=232.7 degrees x π = 278.4 degrees x 2.6 degrees
Where
232.7 degrees = Inner Planets Axial Tilts Total
278.4 degrees = Outer Planets Axial Tilts Total
28.3 degrees = Neptune axial tilt
23.6 degrees = outer planets orbital inclinations total
115 degrees = the difference between Umbra shadow from cycle to another cycle
(during Saros Cycle)
2.6 degrees = 180 degrees - 177.4 degrees (Venus Axial Tilt)
6585.39 days = Saros Cycle Period
II-Discussion
Let's summarize the main idea in following:
Because the solar group is one trajectory of energy all planets data are related and
connected with each other strongly – as we see in the previous data…
Let's try to explain the previous equations
Equation No. 1
6585.39 degrees2
= 232.7 degrees x 28.3 degrees = 278.4 degrees x 23.6 degrees
6585.39 degrees2
= 115 degrees x (180/π)
6585.39 days = Saros Cycle Period
Where 1 degree = 1 day ? with the moon orbit regression because the moon regresses
yearly 19 degrees and that cause regression for the calendar for 19 days
i.e. 1 day =1 degrees – So Saros period 6585.39 days can be = 6585.39 degrees
Now
This value 6585.39 degrees can be found by many equations…
As we see – but – we know that Neptune axial tilt is the master value because
Neptune reflects the energy toward the inner planets – that means 28.3 degrees is the
master value here –……..Now
(1) Saros 6585.39 degrees is defined based on Neptune axial tilt 28.3 degrees and
inner planets axial tilts total ……Also
(2) Saros 6585.39 degrees is defined based on 23.6 degrees (outer planets orbital
inclinations total) and 278.4 degrees (outer planets axial tilt total)
I wish we see how the connection is clear and so strong – It's so hard to claim for any
pure coincidences here – we here deal with clear connections
The previous data proves 2 points clearly
10. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
10
(A) The solar group is one trajectory of Energy – each planet is a point on it
(B) Saros Cycle 6585.39 is a general Cycle in the solar group that's why the
main values are connected with it
The last point (B) is my objective here – Saros and Metonic Cycles are not cycles
related to the moon motion only – but related to the whole solar group
The previous data supports this claim clearly
Let's provide more data to support this same idea
Saros Cycle 6585.39 days = 29.53 days (lunar Synodic Month) x 223
= 19 x 346.6 days (nodal year)
=27.32 days (lunar sidereal Month) x 241
Metonic Cycle 6939.75 days = 29.53 days (lunar Synodic Month) x 235
= 20 x 346.6 days (nodal year)
= 19 x 365.25 (Earth Sidereal Year)
Comment
In Saros as in Metonic Cycles periods … we see the motions of Earth, Moon and
moon orbit are in harmony with each other greatly…!
Why these 3 motions are in harmony as such…?
Now we have
(1) Data Consistency for these Cycle periods
(2) Motions harmony between the planets
I see – as any one else- that's impossible to claim for any pure coincidences here-
simply it's not true….
More logical conclusions are:
(1) The Solar Group Is One Building And Each Planet Is A Part Of It
(Solar group is one Trajectory of Energy and each planet is a point on it)
(2) The moon orbit regression and data effect on many solar planets – which make
his effect as general effect in the solar group – such effect we have found
before in the rate 1.0725 and also with the percentage 99% - that tells us the
moon orbit is related to the sun – making the moon orbit geometrical structure
effective on all solar planets through the sun geometry…. That supports the
previous claim that "without the moon orbit the sun can't be crated!"
(3) The main point here is that- the moon orbit , moon and Earth motions (these 3
motions together) cause to delay the sun rate of time – which provides the
chance to concentrate the energy to complete the energy quantum c2
to enable
to produce the sun rays….
i.e.
Earth- Moon System Basic Job is to delay the sun rate of time – to
make 1 year on Earth = 1 day on the sun
This rate is produced by these 3 players motions together
(that makes the eclipse phenomena has a different vision)
11. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
11
Equation No. 2
727 degrees = 23.45 degrees x π3
=232.7 degrees x π = 278.4 degrees x 2.6 degrees
This equation tries to show that the distance 720.7 mkm or 727 mkm is a central
distance in the solar group…
We don't know the geometrical mechanism by which this distance is created (or any
other distance)
Just the used values tell us that- there's a complex geometrical mechanism behind it
This distance 727 mkm is related to our distance 627mkm how??
727 mkm x 99% = 720.7 mkm (Mercury Jupiter distance)
And
727 mkm = 1.16 mkm/sec x 627 seconds
Where
1.16 mkm/sec is a light beam found with Jupiter whose velocity= 1.16mkm/sec
i.e.
During 627 seconds the light beam (1.16mkm/sec) will pass 727 mkm
627 seconds became 627 mkm (Earth Jupiter distance) – how? Because in higher
velocity the time and distance values can be equivalent!
Also
2088 seconds x 0.3 mkm (light known velocity) = 627 mkm
(2088 mkm = Jupiter Uranus distance- whose the light 0.3mkm/sec is passed during
6939.75 seconds!)
The geometrical mechanism is hard to be seen clearly but the data is a strong train
gives no room for any doubt or refuse …
It's incredible to use a handful of data hundreds of times in different units and forms
and to accept all of them as separated value from each other …
This data is found based on Geometrical System and this system connects all of
them together and built by them the final planets motions…
12. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
12
2-5 The Sun Rays Creation
I-Data
Light beams Production (Sun Rays production) depends on the following Equation
2
4
4
1
CCC =×
(Gerges Equation For Sun Rays Production)
We have discussed this equation before – let's summarize it in following
1- (1/4 C) = planets velocities total relative to the sun
2- C2
The Sun Rays Energy Source
3- 4C = Jupiter energy
The question was …..
Jupiter energy = 1.16 mkm/sec So how does this become 1.2 mkm/sec = 4C??
Velocity 1.16 mkm/sec – means -1.16 mkm is passed each 1 second
0.04 mkm = Earth Circumference = a distance Earth moves daily because of here
rotation around axis…. means 0.04 mkm is passes each one day
So …. 1.16mkm +0.04 mkm = 1.2 mkm /sec = 4C
We have 2 questions here to answer
(1) The time is different 1 second with Jupiter and 1 day with Earth – to perform
this equation we need "1 second of Jupiter light beam = 1 day of Earth motion"
(2) How the distance is added … because Jupiter is far from Earth with 627 mkm?
627 mkm (Earth Jupiter Distance) is the distance in which the energy is concentrated
– as we have discussed in the previous paper - to produce the sun rays – that means –
if Jupiter light beam 1.16mkm/sec was at Jupiter and Earth motion was at Earth it's
not big problem –both motions will be added together? How? Because between both
there's a connector of energy and this connector will transport the energy from any
point to another without any difficulty
Let's discuss the main question
How 1 second of light motion can be 1 day of planet motion?
This is the main question in the solar group!
The solar group main job is to use energy of light motion for 1 second to produce
planet motion energy for 1 solar day….
This is the main job for the solar group – I have discussed it deeply before and we
should summarize this idea in following point – but for full discussion please review
Solar Day Production http://vixra.org/abs/1812.0426
Earth Circumference http://vixra.org/abs/1812.0434
13. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
13
2-6 Solar Day Production
The Main idea
Planet moves with a light beam – light motion energy for 1 second will be planet
motion energy for 1 day….
Why?
(Because the light creates the motion and the planet follows the light motion to
receive his required energy to live…) – my answer…
I have 2 examples to support this idea …
(1) Metonic Energy
Light with known velocity 0.3mkm/sec travels from Jupiter to Uranus (2088 mkm)
during 6939.75 seconds
Earth Moon moves Metonic Cycle for a period 6939.75 days
I claimed that 6939.75 is the energy transported from Uranus to earth Moon but with
different rate of time
(2) Pluto Orbital Distance
5040 seconds x 1.16 mkm/sec = 5846.4 mkm (where 5870 mkm = Pluto Orbital
Distance- the difference =23.6 mkm I claim this difference is found for geometrical
necessity)
So- light with supposed velocity 1.16 mkm/sec travels during 5040 seconds a
distance = Pluto orbital distance approximately…
Mercury during the nodal year (346.6 days) moves a distance = 1433.5 mkm
1433.5 mkm = Saturn orbital distance
Also
Mercury during 1433.5 days moves a distance = 5870 mkm = Pluto orbital distance
Mercury follows the light motion
How to prove the previous claims??
I use the planets data…
- Mercury needs 5040 seconds to make his day period = 176 solar days – so the
number 5040 second is already found with Mercury and the light velocity
1.16mkm/sec is already supposed with Jupiter and we have discussed the close
relationship between Mercury and Jupiter
- Also the distance 2088 mkm (Jupiter Uranus Distance) passed by light with
known velocity (0.3 mkm/sec) in 6939.75 seconds and Metonic Cycle period
6939.75 days where we have discussed the close relationship between Uranus
and Earth Moon orbit…
At end I try to explain how the planets data is created – so it's what I have and I
accept any other explanation….
Any way there are many data in harmony with each other supporting the same data
direction…
14. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
14
2-7 How the sun diameter is created? (What's Mars Role in the sun creation process)
I-Data
627 mkm = 1.392 mkm (sun diameter) x 455.4 mkm (error 1%) (I)
627 mkm = 4.37 mkm (sun circumference ) x 144 mkm (II)
Where
627 mkm = Earth Jupiter Distance – we have discussed in the previous paper
1.392 mkm = The Sun Diameter
455.4 mkm = Mars Orbital Diameter
II- Discussion
627 mkm = 1.392 mkm (sun diameter) x 455.4 mkm (error 1%) (I)
Equation (I) tells us that the sun creation depends on Mars Data -specifically on Mars
orbital distance (or orbital diameter)…. Can we prove this fact? let's try
We know Jupiter energy was 86400 mkm and we needed 3600 mkm to complete the
required value 90000 mkm to produce the sun rays – so the sun different rate of time
produces the required value 3600 mkm
(90000 mkm /3600 mkm ) =25
And we know that Mars axial tilt =25.2 degrees – can both values be equal?
Let's try to know …to do that we need Kepler 3rd
law table in following:
P2
* 25 = d3
(Kepler 3rd
Law)
- P : The Planet orbital period
- d : The Planet orbital distance
- 25.2 degrees : Mars Axial Tilt
The results are shown in the following table
Table No.1
Planet P2
* 25 = d3
Error
Mercury (88)2
*25 (57.9)3
0.2%
Venus (224.7)2
*25 (108.2)3
0.3%
Earth (366)2
*25 (149.6)3
0
Mars (687)2
*25 (227.9)3
0.3%
Jupiter (4331)2
*25 (778.6)3
1.4%
Saturn (10474)2
*25 (1433.5)3
1%
Uranus (30589)2
*25 (2872.5)3
1.3%
Neptune (59800)2
*25 (4495.1)3
1.5%
Pluto (90588)2
*25 (5870)3
1.4%
Comment
In kepler table – the constant =25 also as in our last equation (90000/3600)=25
I try to support the claim that "Mars is an effective player in the sun creation process"
Please Note
(1) Mars axial tilt is the constant in kepler law table shows a general effect which can be
done only by the sun herself – as we have discussed before –
(2) the constant has no unit but Mars axial tilt =25.2 degrees – but we know that the unit is
relative – for that reason the constant 25 = Mars axial tilt
The Unit Definition Is Relative http://vixra.org/abs/1906.0379
15. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
15
Equation (II)
627 mkm = 4.37 mkm (The Sun Circumference ) x 144 mkm
What's 144 mkm?
I claim that Mars original orbital distance was = 84 mkm and Mars orbital distance is
changed through the time to be 227.9 mkm through the history
Now the difference 227.9 mkm - 84 mkm = 144 mkm
That explains why Mars both values (227.9 x 2 =455 mkm and 144 mkm) are seen in
the equations
Because Mars effects on the sun creation process
Please review
Mars Orbital Distance Is Changed Through History
http://vixra.org/abs/1905.0510
Pluto was "The Mercury Moon"
http://vixra.org/abs/1807.0331
2-8 90000 mkm = C2
0.3 mkm /sec = light known velocity
(0.3mkm/sec)2
= 0.09 mkm2
/sec2
If time = 1 second
So
C2
will be = 90000 mkm which we have discussed in this series of papers…
(Please Note ….If 1 second of light motion = 1 day of planet motion – that means
one solar day of Earth motion = 1 second of light motion
Also because – the solar group geometrical structure depends on One Solar Day to
build its geometrical structure – that make the value 1 second is the geometrical base
on which the solar group is created – which causes the value 90000 mkm to be equal
C2
permanently..
Comment
86400 mkm = 5040 x 17.2 mkm = (71)2
x 17.2
71 is length contraction effected by velocity =0.9999 C
The previous equation tells us that the original energy is contracted to be 17.2 mkm
which = 17.2 degrees (Pluto orbital inclination)
Please Note
The contraction is happened with Mercury because the energy is sent from Neptune
without contraction- means – the contraction is done with Mercury and he sends the
energy to Pluto…
16. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
16
2-9 Solar Group Building Unit
We need to see this idea as a clear as possible
I claim that
1 Second Of Light Motion = 1 Day Of Planet Motion
i.e.
The Planet Follows The Light Motion But With A Different Rate Of Time
But
The solar group geometrical building depends on …what? One Solar Day
i.e.
The planets data (Planet Diameter- Orbital Distance- Mass- Orbital Inclination…etc)
All this data is produced with supposition that
The geometry used unit is 1 solar day
Let's explain that
- Earth Moon orbital circumference at apogee radius (the most far point from the
sun to which the moon can reach) = 2.58 mkm
- Earth Moves daily a distance = 2.58 mkm
- The moon has to move daily =2.58mkm (otherwise Earth and Moon will be
separated from each other)
i.e.
- The moon orbit geometrical structure depends on the solar day as his basic unit
The previous claim is the secret how the solar group is
created – the geometrical structure depends on a time
unit – the unit here is the solar day (for Planet motion)
which equal one second (of light motion)
That can explain easily the moon different equations…
Moon circumference 10921 km x 27.3 days (moon orbital period) = 300000km
If the moon rotates around his axis once daily – so the moon will move during his
orbital period a distance = light motion for 1 second…
(1 second here may support the idea) ………also
10921 km x 86400 seconds = 940 mkm (Earth Orbital Circumference)
This equation tells us …if Earth revolves the sun a complete revolution in 1 day only
– the moon circumference will = a distance of her motion for 1 second only
The data supports strongly the idea – spite the geometrical mechanism behind still
needs more discussion…