Planet Motion Reason (Revised) (no.2).pdf

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Planet Motion Reason (Revised) (No. 2)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –12th
December 2021
Abstract
Paper question
How Can Light Motion Effect On Planet Motion?
Paper Question Explanation
- There are 2 basic questions need to answer which are
- (1) Can light motion effect on Planet motion?
- (2) Is there a light beam its velocity = 1.16 mkm per second?
- The following data provide the sufficient answer for these 2 questions
- Let's see this data in following:
- (1) Mercury Motion
- During 4222.6s light supposed velocity (1.16 mkm/) travels 4900=2π x 778.6 mkm
- During 4222.6s light known velocity (0.3 mkm/) travels 1267 = 2π x 201.7 mkm
- Where
- 4900 mkm =Jupiter Orbital Circumference
- 778.6 mkm = Jupiter Orbital Distance
- 4222.6 h = Mercury Day Period
- Mercury moves during 4222.6 hours a distance = 720.7 mkm
- Jupiter moves during 4222.6 hours a distance = 201.7 mkm
- And 778.6 mkm =1.0725 x 720.7mkm

I do this research
2nd
2
- (2) Venus Motion
- During 586s light supposed velocity (1.16 mkm/) travels 680 = 2π x 108.2 mkm
- During 586s light known velocity (0.3 mkm/) travels 175.8 = 2π x 28 mkm
- Where
- 680 mkm = Venus Orbital Circumference
- 224.7 days = Venus Orbital Period
- Venus moves during 224.7 hours a distance =28.3 mkm (error1%)
- (3) Earth Motion
- During 810s light known velocity (0.3 mkm/) travels 243 = 2π x 38.7 mkm
- Where
- 940 mkm =Earth Orbital Circumference
- 149.6 mkm= Earth Orbital Distance
- 365.25 days = Earth Orbital Period
- Earth moves during 365.25 hours a distance = 38.7 mkm (error 1.2%)
- (4) Mars Motion
- During 1235s light known velocity (0.3 mkm/) travels 370.6 = 2π x 59 mkm
- Where
- 1433 mkm = Mars Orbital Circumference
- 227.9 mkm= Mars Orbital Distance
- 687 days = Mars Orbital Period
- Mars moves during 687 hours a distance = 59 mkm (error 1%)
- (5) Saturn Motion
- During 7765s light supposed velocity (1.16 mkm/) travels 9007 = 2π x 1433 mkm
- During 7765s light known velocity (0.3 mkm/) travels 2330 = 2π x 371 mkm
- Where
- 9007 mkm = Saturn Orbital Circumference

I do this research
2nd
3
- 1433 mkm = Saturn Orbital Distance
- Saturn moves during 10747 hours a distance = 371 mkm (error 1%)
- (6) Uranus Motion
- During 15559s light supposed velocity (1.16 mkm/) travels 18048=2π x 2872 mkm
- Where
- 18048 mkm = Uranus Orbital Circumference
- 2872 mkm = Uranus Orbital Distance
- Uranus moves during 30589 hours a distance = 742 mkm (error 1%)
- (7) Neptune Motion
- During 24348s light supposed velocity (1.16 mkm/) travels 28244 = 2π x 4495
mkm
- Where
- 28244 mkm = Neptune Orbital Circumference
- 4495.5 mkm = Neptune Orbital Distance
- 59800 days = Neptune Orbital Period
- Neptune moves during 59800 hours a distance = 1163 mkm
- (8) Pluto Motion
- During 31983s light supposed velocity (1.16 mkm/) travels 37100=2π x 5906 mkm
- Where
- 37100 mkm = Pluto Orbital Circumference
- 5906 mkm = Pluto Orbital Distance
- 90560 days = Pluto Orbital Period
- Pluto moves during 90560 hours a distance = 1527 mkm
(Please scan the figure (ORCID)

I do this research
2nd
4
Paper Contents
Subject Page No.
1-1- Introduction 6
1-2- Methodology 12
2- Planet Mass Effect On its Motion 14
2-1 Preface 15
2-2 Planet Mass effect on its Motion 17
2-3 Saturn and Earth Motions Interaction 28
2-4 Planets Velocities Proportionality 37
3- Saturn Motion Analysis 45
3-1 Preface 46
3-2 Saturn Diameter Analysis 48
3-3 Neptune Circumference Analysis 58
3-4 Neptune Day Period Analysis 67
3-5 Mercury Motion effect on Jupiter and Neptune Motions 76
3-6 Earth Motion Distance Daily Analysis 83
3-7 Uranus Day Period Analysis 87
3-8 The Inner Planets Motions Analysis 93
4- The Continuum Effect Proof 101
4-1 The Continuum Effect Proof 102
4-2 Saturn Motion Analysis 108
4-3 Planet Diameter Analysis 134
4-4 Why do the planets revolve around the sun if there's no sun gravity? 136
5- The Solar Planets Motions Use Different Rates Of Time 137
5-1 Preface 138
5-2 The Planets Motions Rates Of Time 140
6- The Solar Planets Rates Of Time Analysis 144
6-1 Preface 145
6-2 Venus Motion Rate of time 146
6-3 Earth Motion Rate of time 148
6-4 Mars Motion Rate of time 150
6-5 Jupiter Motion Rate of time 152
6-6 Saturn Motion Rate of time 154
6-7 Uranus Motion Rate of time 156
6-8 Neptune Motion Rate of time 158
6-9 Pluto Motion Rate of time 160
6-10 The Planets Orbital Distances Test 162
6-11 One Law Controls The Planets Orbital Periods And Distances 167
6-12 The General Discussion 168
7- The Planets Motions Rates Of Time Effect Analysis 171
7-1 Preface 172
7-2 Planets Motions Rates Of Time And Distances Data 173

I do this research
2nd
5
7-3 The Data Equal Distances 177
7-4 The Data and the planets velocities. 185
7-5 The Data Distances And Rates Of Time Interaction 189
7-6 The Data General Discussion 199
7-7 Mars, Jupiter and Saturn Motions Analysis 201
7-8 Why Saturn And The Moon Use Equal Rates Of Time? 206
7-9 Why Mercury Use A Double Of Its Orbital Distance? 211
7-10 The Rate (4.61) be used between Pluto and the moon motion 212
7-11 The Moon Orbital Motion Equation 216
8- Planets Unified General Motion 232
8-1 The Planets Unified General Motion Description 233
8-2 The Solar Planets Motions Are Complementary One Another 235
8-3 The Solar Planets Move An Unified Motion (A Team Motion) 239
9- Mars Migration Theory 244
9-1 Mars Migration Theory 245
9-2 Pluto Migration Theory 248
9-3 Planets Migration Theories Proves 250
9-4 Is There An Absent Planet In The Solar Group? 253
10- The Sun Age Description 256
10-1 Preface 257
10-2 The Sun Circles The Earth 258
10-3The Rate (1.0725) 259
10-4 The Sun Diameter Analysis 262
10.5 The Sun And Earth Motions Rate Of Time (1 day =365.25 days) 265
10-6 The Sun Rays Creation 273
11- Light Beam (1.16 mkm/sec) Proves 279
11-1 The solar system Creation Theory 280
11-2 Light Beam (1.16 mkm/sec) Proves Discussion 285
12-The Solar System Distances Be Created In A Network Form 322
12-1 Preface 323
12-2 The Continuum effect Through the Solar System Distances 325
12-3 The Solar System Distances Distribution 330
12-4 The Solar System Distances Dependency On One Another 334
Appendix No.1 The Solar System Equal Distances List 336
Claims Be Sent Against The Decision Of Nobel Prize For Physics 2021 338
References and Biography 343

I do this research
2nd
6
1-1 Introduction
- One more hypothesis tells (Planet Motion Creates Its Own Period Of Time)
- Let's explain one example in details to explain and prove this hypothesis
- Example No. (1)
- 31 hours of Mercury Motion = 224.7 days of Uranus motion
- 31 hours of Mercury Motion = 224.7 days x 2 of Neptune motion (error 1%)
- 224.7 days is Venus orbital period
- The data tells, Uranus and Neptune motion cause to create 224.7 days (Venus
orbital period) – the 2 planets cover the light beam which produced this period
224.7 days as a distance = 224.7 mkm by this light motion
- Now let's follow the detailed data to discover how this process is done:
- Equation no. (1)
- (708.7 h /17.2 h) = (655.7 h /16.1 h ) = 41.2 (error 1%)
- Where
- 708.7 hours = The Earth Moon Day Period
- 655.7 hours = The Earth Moon Rotation Period
- 17.2 hours = Uranus Day Period
- 16.1 hours = Neptune Day Period
- This equation tells that, some effect be found from Uranus and Neptune on the
moon day and rotation periods –
- Equation no. (2)
- (708.7 h /10.7 h) = (655.7 h /9.9 h ) = 66.2
- Where
- 708.7 hours = The Earth Moon Day Period
- 655.7 hours = The Earth Moon Rotation Period
- 10.7 hours = Saturn Day Period
- 9.9 hours = Jupiter Day Period

I do this research
2nd
7
- This equation tells Saturn and Jupiter effect on the moon day and rotation periods
that means,
- Uranus and Saturn effect on the moon day period and
- Neptune and Jupiter effect on the moon rotation period
- This effect aimed to create the rate 66.2
- Equation no. (3)
- (4.87 /0.073) = (224.7/3.4) = (243/3.67) = 66.1 (error 1%)
- Where
- 4.87 x 1024
kg = Venus Mass
- 0.073 x 1024
kg = The moon Mass
- 243 days = Venus Rotation Period
- 3.4 degrees = Venus Orbital Inclination
- 3.67 deg =7 deg (Mercury Orbital Inclination) – 3.4 deg (Venus Orbital Inclination)
- Equation no. (3) tells that the rate (66.1) which shows the effect of Neptune and
Uranus on one side and Jupiter and Saturn on the other side – this rate be used by
Venus and the moon data – where Venus and the moon masses create a strong base
for this rate –because – the planet motion depend on the masses rates.
- Shortly
- Venus 2 periods (224.7 days and 243 days) be create based on this rate by help
from Venus orbital inclination –
- The rate 66.1 be found by effect of the 4 planets – but from where Venus orbital
inclination (3.4 degrees) is created?
- Equation no. (5)
- 177.4 deg = 98.6 deg x 1.8 deg
- 180.8 deg = 177.4 deg +3.4 deg = 0.8 deg +180 deg
- 93.4 days = 116.75 days x 0.8
- 177.4 degrees = Venus Axial Tilt

I do this research
2nd
8
- 98.6 degrees = 97.8 deg (Venus Axial Tilt) + 0.8 deg (Venus orbital inclination)
- 1.8 degrees = Neptune orbital inclination
- 0.8 degrees = Uranus orbital inclination
- 3.4 degrees = Venus orbital inclination
- 93.4 degrees = 90 degrees + 3.4 degrees (Venus orbital inclination)
- 116.75 days = Venus Day Period
- Equation (5) shows clearly that, Venus axial tilt and orbital inclination both be
created based on Uranus and Neptune data. that means, the 2 basic planets which
effect on the rate (66.1) both themselves cause to create Venus orbital inclination
and caused it to be (3.4 degrees)
- Notice
- Venus orbital inclination has 2 important effect
- (1st
) Planet orbital inclinations be used as rates between planets velocities and
cause the planets motions -
- (2nd
) Venus orbital inclination defines its diameter because 3.4 hours = 12104
seconds
- Equation no. (6)
- (35/6.8) = (61920/12104) = 5.1
- Where
- 35 km/s = Venus velocity
- 6.8 km/s = Uranus velocity
- 61920 s = Uranus day period (=17.2h)
- 12104 km = Venus diameter (be used here as a period of time)
- Notice
- (Venus velocity 35 / Uranus velocity 6.8) = 5.1
- (Mars velocity 24.1 / Pluto velocity 4.7) = 5.1
- (the moon velocity 27.78 / Neptune velocity 5.4) = 5.1
- The proportionality between Venus diameter and Uranus day period produces
different effects and shows interaction between the 2 planets motions

I do this research
2nd
9
- Equation no. (7)
- 35 x 12104 sec = 421056 (error 0.6%)
- 3.024 x 12104 days = 18048 mkm (1.4%
- Where
- 3.024 km/day = Venus velocity per a solar day
- 421056 km = Uranus motion distance during Uranus day period
- 18048 mkm = Uranus orbital circumference
- The equation tells that
- Venus moves during 12104 seconds a distance = Uranus motion distance during
Uranus day period
- And
- Venus moves during 12104 solar days a distance = Uranus orbital circumference
- It shows the period 224.7 days be defined by Uranus and be transported to Venus.
- But where is the light motion which creates the period 224.7 solar days?
- Equation no. (8)
- 224.7 mkm = 0.3 mkm/s x 749 seconds
- Where
- 224.7 days = Venus orbital period
- 0.3 mkm/s = light motion velocity
- 749 seconds= ??
- We discuss this period deeply let's summarize its discussion in following:
- Uranus Day Period = 17.2 hours = 61920 seconds
- Uranus Orbital Period = 30589 days
- If it be used by seconds units (30589 seconds) that will give interesting point of
discussion because
- Uranus Day Period (61920 seconds) = 2 x 30589 seconds + 742 second
- This is the period we search for because it different with 1% with (749s)

I do this research
2nd
10
- Also more interactions be related to this period we discuss it deeply in point no. (3-
7) (Uranus Day Period Analysis) - for example
- Uranus moves during 30589 hours a distance = 749 mkm if 1 mkm = 1 sec we will
get this same period 749 seconds.
- The point is that, Venus diameter be in full harmony with Uranus day period and
orbital period in addition to all motion data – that because –
- (1)
- (Venus velocity 35 /Uranus velocity 6.8) = (61920 s /12104s) as we have discussed
in Equation no. (6) and
- (2)
- 61920 s = 2 x 30589 s +742 s
- That can be created only based on deep interaction between the 2 planets
motions – the previous data and discussion proves the idea clearly
- Notice
- 1.44 = 1.8 x 0.8
- Where
- 1.44 deg = The moon orbit regression degrees monthly
- 1.8 deg = Neptune Orbital Inclination
- 0.8 deg = Uranus Orbital Inclination
- The data shows that, the 2 planets which effect on Venus motion data effect also
on the moon orbit regression – showing that the effect is real and supported.
- That causes (for example)
- 243/224.7 = 29.53/27.3
- Where
- 243 days = Venus Rotation Period
- 29.53 days = The Moon Day Period
- 27.3 days = The Moon Rotation Period

I do this research
2nd
11
- Let's take a look on the paper contents
- Planet Mass Effect On Its Motion
- The point explains how Planet moves where the sun gravity theory is mistaken
(Be discussed in point no. 2 of this paper)
- Saturn Motion Analysis
- Saturn motion be analyzed to prove that planets motions features are different from
Newton Theory of the sun gravity description (be discussed in point no. 3)
- A Continuum Effect be discovered In The Planets Motions Features
- The Solar Planets Motions Use Different Rates Of Time
(Be discussed in points no. 5-6-7 of this paper)
- The Planets Move One Unified Motion
- Mars Migration Theory And The Sun Creation
(Be discussed in points no. 9 and 10 of this paper respectively)
- A Light Beam Its Velocity 1.16 mkm/Sec Be Found And Effects On The Solar
System Motion.
- The Solar System Distances Be Created In A Network Form
- And The Solar System Creation Theory

I do this research
2nd
12
1-2 Methodology
- I use the planets motions data analysis in comparison with the theories which try to
explain the planets motions-
- Shortly
- I suppose the planet motion data be similar to a creature genes and by analysis of
this data we should discover this planet motion features.
- Let's use one example to explain how this method works?
- Example No. (2)
- Why does The Moon Apogee Radius = 406000 km?
- The moon daily displacement = 88000 km, and the displacements total during the
moon day period (29.53 solar days) be = 2598693 km
- If this distance be the moon orbital apogee circumference, the moon orbital apogee
radius should be = 413600 km –
- It's a valid question – how the apogee radius be = 406000 km?
- The moon creates an angle (θ) between its motion direction and its orbit horizontal
level by that the real displacement (L) will not be = 88000 km, instead it be =
88000 cos (θ), which be shorter than the displacement 88000 km
- By that the total displacements in 29.53 days be less than 2598693 km and the
apogee orbital radius be =406000 km and its circumference be = 2551444 km,
means the apogee orbital circumference be shorter by (2%)
- We should notice that, if the moon doesn't create the angle (θ) in its motion and
depend on the displacement 88000 km directly - not only the apogee orbital radius
will be 413600 km but also the moon will not be able to revolve around The Earth
through any more near orbit– instead –the moon would be prisoner in the apogee
orbit whose radius =413600 km and can't revolve around the Earth through any
more near orbit
- The moon using of the angle (θ) technique – or we call – Pythagorean triangle
technique provides the moon the ability to revolve through more near orbits.

I do this research
2nd
13
- But why the moon needs to move its daily displacement 88000 km? the moon has
to move equal distance to Earth motion distance daily (2.57 mkm). We conclude
that because they aren’t separated from one another in the motion. if the moon has
to move (2.57 mkm) daily why does it need a displacement (88000 km) daily?
This question be answered in point no. (7-11) (The Moon Orbital Motion
Equation) in which the moon motion features be discussed in details
- Without the data analysis it's hard to discover this moon motion technique
- The paper also examines the moon creation process – and based on the planets
motions data analysis it suggests that Mars itself did the collision with Earth by
which the moon be created. Because
- Mars was the second planet after Mercury with original orbital distance (84 mkm)
and Mars had migrated from its original position to its current one (227.9 mkm) in
its motion from (84 mkm) to (227.9 mkm) Mars had collided with Venus and then
with Earth and caused the moon creation –
- Mars migration theory answers many questions – such as – Why Venus has no
moon if it had suffered from a collision as Earth? Because Mars had moved from
the point (84 mkm) to (227.9 mkm) with force and by that Mars had pushed all
collisions debris to move in its motion direction, left Venus without debris around,
as a result, Venus could not create it own moon. this idea also explains the lunar
Magma Ocean (LMO) Origin. (it's Venus). Because the debris be pushed with
Mars in its motion direction and among this debris was the Lunar Magma Ocean–
Earth gravity is greater than Venus' and the debris lost some of their momentum
that gave Earth the chance to create its moon.
- Mars Migration Theory be discussed in point no. (9)
- Shortly
- The planets motions data analysis put the planets motions data in comparison with
the theories trying to explain how this data be created and to test the theory trying
to prove if it's sufficient and trustee.

I do this research
2nd
14
2- Planet Mass Effect On its Motion
2-1 Preface
2-2 Planet Mass effect on its Motion
2-3 Saturn and Earth Motions Interaction
2-4 Planets Velocities Proportionality

I do this research
2nd
15
2-1 Preface
- How Does Planet Mass Effect On Its Motion?
- I suggest the following rule
- (Planet Mass / Planet Mass) = Planet Orbital Inclination = (Planet Velocity /
Planet Velocity)
- The suggested rule tells that
- Planets masses rates define Planets orbital inclinations for their motions and based
on Planets orbital inclinations the planets velocities be defined in comparison one
another – this idea we can conclude from Saturn Motion Analysis because
- (Saturn velocity 9.7 km/s) / (Neptune velocity 5.4) = 1.8
- Neptune orbital inclination = 1.8 degrees
- Also
- (Mars velocity 24.1 km/s) /(Saturn velocity 9.7 km/s) = 2.5
- Saturn orbital inclination = 2.5 degrees
- That shows directed data and gives hope that the rule is a correct one – means- the
planets masses causes to create their orbital inclinations and the orbital inclinations
define each planet velocity in comparison with other planets
- Now we should ask
- The planets velocities be decreased from the sun to Pluto in order and that shows
the velocities must be created in one system – can we find one system expresses all
planets orbital inclinations? The following data may answer this question
- Notice
- The inner planets orbital inclinations total = 17.4 degrees
- Pluto orbital inclination = 17.2 degrees (error 1%)
- The outer planets orbital inclinations total = 23.6 degrees
- Earth axial tilt = 23.4 degrees (error 1%)

I do this research
2nd
16
- The data shows the planets orbital inclinations be created by one system which
support the velocities regular distribution
- But
- The planets motions create interactions among one another – for example
- 7 deg (Mercury orbital inclination) = 1.9 deg (Mars orbital inclination) + 5.1
deg (Mercury orbital inclination)
- This data tells the planets orbital inclinations can be suffered from interactions
which force the rule to be used through additional geometrical and mathematical
methods –
- The points no. (2-2) and (2-3) try to prove the suggested rule
- The point no. (2-4) analyze the planets velocities rates
- Let's discuss the planets data in following to test how to use the rule –

I do this research
2nd
17
2-2 Planet Mass Effect On Its Motion
I –Data
Equation no. (1)
(0.642/0.33) = 1.94 = (47.4 /24.1) (error 1%)
Equation no. (2)
(0.073 /0.0146) = 5.1 = (24.1/4.7) = (27.78/5.4)
Equation no. (3)
(4.87/5.97) = (23.4/29.2) = 0.81
Equation no. (4)
(4.87 /0.073) = 66.7 = (708.7 /10.7) = (655.7/9.9)
Equation no. (5)
(1898 / 568) = 3.34
Equation no. (6)
(568/4.87) = 116.6
Equation no. (7)
(0.33 /0.0131) = 49
Equation no. (8)
(568/102) = (0.073 /0.0131) = 5.56 = (29.8/5.4)
Equation no. (9)
(102 /5.97) = 17.1
Equation no. (10)
(1898 /102) = (5.97/0.33) = 18.6 (error 2.8%)
Equation no. (11)
(The Planets Masses Total 2666.7) / (Uranus mass 86.8) = 30.772
Equation no. (12)
(The inner planets masses total 11.8) /(Venus mass 4.87) = 2.44

I do this research
2nd
18
II –Discussion
Equation no. (1)
(0.642/0.33) = 1.94 = (47.4 /24.1) (error 1%)
- 0.33 x 1024
kg = Mercury Mass
- 0.642 x 1024
kg = Mars Mass
- 47.4 km/s = Mercury velocity
- 24.1 km/s = Mars velocity
- Now
- What's 1.94?
- Mars orbital inclination = 1.9 degrees and it different from 1.94 with error 2.4%
- We may accept that this value (1.94) refers to Mars orbital inclination (1.9 deg)
- We may explain the error existence in following –
- Where 7 degrees (Mercury orbital inclination) = 1.9 deg +5.1 deg (the moon
orbital inclination) – the data tells that the motions get configuration for data
among one another – and by that the error can be produced
- Mercury and Mars data gives a good example for the suggested rule – we still need
to examine the planets motions data – because
- Mars moves during one solar day a distance = 0.52 degrees = (1/1.9) that shows
the masses rate effect on the motion and causes the velocities rate.
Equation no. (2)
(0.073 /0.0146) = 5.1 = (24.1/4.7) = (27.78/5.4)
- 0.073 x 1024
kg = The Moon Mass
- 0.0146 x 1024
kg = Pluto Mass
- 0.0131 x 1024
kg = Pluto Mass (old registered value)
- 4.7 km/s = Pluto velocity
- 27.78 km/s = The moon velocity

I do this research
2nd
19
- 5.4 km/s = Neptune velocity
- Pluto mass was registered as 0.0131, and based on it the rate between the moon
and Pluto masses be = 5.6 but with the new registered Pluto mass the rate be 5.1
- We see the rate 5.1 isn't between the moon and Pluto velocities directly but it uses
2 more planets (Mars and Neptune velocities) – the explanation is that –because
the planets motions depend on one another that causes the 2 planets velocities be
use – Please remember
- (Venus velocity 35 / Uranus velocity 6.8) = 5.1
- (Mars velocity 24.1/ Pluto velocity 4.7) = 5.1
- (the moon velocity 27.78/ Neptune velocity 5.4) = 5.1
- That shows a continuous interaction among many planets to create the moon
orbital inclination 5.1 degrees
- Notice
- Pluto mass old registered value (0.0131) can be used in this equation also because
in this cases (the moon mass / Pluto mass) =5.6 and this rate can create the moon
orbital inclination 5.1 degrees because the moon diameter needs angle 0.5 degrees
and that means the moon orbital inclination be measured talking into consideration
the moon diameter.
- Notice
- (Mercury Mass 0.33 / Pluto Mass 0.0131) =25.2 = (5.02)2
- Mars Axial Tilt = 25.2 degrees
- The moon orbital inclination = 5.1 degrees (with 5.02 has an error 1.6%)
- And
- 7 degrees = 5.1 degrees + 1.9 degrees
- And
- 17.2 degrees = 5.1 degrees x 3.4 degrees (Venus orbital inclination)
- We have seen the proportionality of the 6 planets velocities for 5.1

I do this research
2nd
20
Equation no. (3)
(4.87/5.97) = (23.4/29.2) = 0.81
- 4.87 x 1024
kg = Venus Mass
- 5.97 x 1024
kg = Earth Mass
- 23.4 degrees = Earth Axial Tilt
- 29.2 degrees = Earth motion degrees during 29.53 solar days
- Earth has no orbital inclination – for that reason the data uses its axial tilt (23.4
deg)
- The equation doesn't use Earth velocity directly – that because Earth doesn't move
alone but with its moon and the moon motion be part of Earth motion and for that
its data be seen in Earth motion data
- We notice that the moon moves during 29.53 days 13.177 x 29.53 = 389.2 deg =
360 degrees + 29.2 degrees
- Notice
- 0.8 degrees = Uranus orbital inclination, and the equation may show Uranus
motion effect on Earth and Venus Motions. other data can supports this meaning –
for example
- 116.75 days (Venus day period) x 0.8 = 93.4 (Zero error)
- 93.4 degrees = 90 deg + 3.4 deg (Venus orbital inclination)
- Also
- 102 (Neptune Mass) x 0.8 = 81.6 = (Uranus mass 86.8 – Venus mass 4.87)
- The data refers to the same meaning but by using different geometrical and
mathematical forms –
- Also
- 2.551392 mkm (the moon orbital circumference) = 116750 km x 21.8
- (where 21.8 = Jupiter mass / Uranus mass) and
- 116.75 days (Venus day period) x 1000 km = 116750 km
- (if the rate 1 day = 1000 km be used)

I do this research
2nd
21
Equation no. (4)
(4.87 /0.073) = 66.7 = (708.7 /10.7) = (655.7/9.9)
- 4.87 x 1024
kg = Venus Mass
- 0.073 x 1024
kg = The moon Mass
- 708.7 hours = The moon day period
- 655.7 hours = The moon rotation period
- 10.7 hours = Saturn day period
- 9.9 hours = Jupiter day period
- 66.7 = π2
x 6.7 degrees (The Moon Axial Tilt)
- Notice
- (Uranus Mass 86.8) / (Venus Mass 4.87) = 17.8
- 17.8 =5.1 x 3.49 (3.4 degrees = Venus orbital inclination error 2.5%)
- That shows Venus orbital inclination and the moon orbital inclination be created in
comparison with one another –this fact is supported by different data let's refer to
then in following
- 17.2 degrees = Pluto orbital inclination
- 17.4 degrees = The inner planets orbital inclinations total
- 17.2 hours = Uranus Day Period
- The data be created similar to one another because of the wide interaction behind
the moon orbital inclination creation – as the planets velocities show
- For more explanation
- Jupiter orbital distance 778.6 mkm = Earth orbital distance 149.6 mkm x 5.2
- That shows the moon orbital inclination be created as 5.1 degrees for different
used data
- Notice
- (Neptune Mass 102) / (Earth Mass 5.97) = 17.1
- The rate 17.1 is more near to 17.2 deg (Pluto orbital inclination), we will discuss
later

I do this research
2nd
22
- Equation no. (4) shows that there's a strong connection behind this data – the 4
periods (708.7 h – 655.7 h – 10.7 h -9.9 h) are created based on one another by a
great accuracy and for that the rate between them has Zero error – here this
connection depends on a great part on Venus motion – where Venus motion data
shows a great effect from Uranus on Venus by different forms of data – this effect
makes Venus as a land of project – it works as a place of work and through Venus
Jupiter and Saturn motions effect on the moon cycles periods - Please remember
- (243 days /224.7 days) = (29.53 days /27.3 days)
- 243 days = Venus rotation period
- 224.7 days = Venus orbital period
- 29.5 days = The moon day period 27.3 days = The moon orbital period
Equation no. (5)
(1898 / 568) = 3.34
- 1898 x 1024
kg = Jupiter Mass 568 x 1024
kg = Saturn Mass
- 3.4 degrees = Venus orbital inclination (error 1.7% with 3.34)
- Equation no. (5) shows that Venus orbital inclination is created as a rate between
different data and that because of Venus position as a point of work for many
planets motions effect which effect on the moon motion –
- We see that Venus orbital inclination be created as a rate between 2 great masses
planets – that tells – the solar system be designed by one geometrical design and
the planets motions effect on one another through one general system – that
explains why the 2 great masses planets effect to create Venus orbital inclination
to be 3.4 degrees – the effect is done as a rate of masses but in a general deign for
the whole area as one playground – Jupiter and Saturn doesn't create the rate 3.4
for themselves – but because they are the 2 basic masses and columns in the solar
system they define the required data for the whole playground- for that reason –
the choose Venus orbital inclination to be 3.4 deg – noting that – the rate 3.4 still
can effect on the 2 great planets motions.

I do this research
2nd
23
Equation no. (6)
(568/4.87) = 116.6
- 4.87 x 1024
kg = Venus Mass
- 568 x 1024
kg = Saturn Mass
- 116.75 days = Venus day period
- The rate 116.6 between Saturn and Venus masses can cause Venus day period to
be 116.75 days – but also this same rate effects on Saturn motion data because
116.7 degrees = 90 degrees +26.7 degrees (Saturn Axial Tilt), the data forces us to
accept very specific relationship between Saturn and Venus –This relationship be
seen also in different data of Saturn and Venus motions – for example 1433.5 mkm
= Saturn orbital distance = (37862 km)2
where 38025 km = Venus Circumference
(error 0.4%) – Also – (12104 km Venus diameter)2
= 120536 km Saturn diameter
Equation no. (7)
(0.33 /0.0131) = 49 ( Mercury orbital inclination = 7 degrees)
- 0.33 x 1024
kg = Mercury Mass
- 0.0131 x 1024
kg = Pluto Mass (old value)
- The equation shows that Mercury orbital inclination 7 deg be created as a rate
between the masses of Mercury and Pluto – we realize clearly that – Pluto motion
data effect on Mercury motion data by many and different forms- and we conclude
clearly that Pluto effects on Mercury motion data more than any other planet in the
solar system – the fact is that – Pluto was the mercury moon before te planet
migration – Mars migration theory proves this fact – it's found in point no. (9) of
this current paper.
- Please remember

I do this research
2nd
24
- Mercury effects on the inner planets orbital inclinations, this fact we conclude
from the calculation 7 deg = 5.1 deg +1.9 deg, by that the value 17.4 may be
created by Mercury motion effect on the inner planets by interaction with Pluto
motion.
Equation no. (8)
(568/102) = (0.073 /0.0131) = 5.56 = (29.8/5.4)
- 568 x 1024
kg = Saturn Mass
- 102 x 1024
kg = Neptune Mass
- 0.073 x 1024
kg = The Moon Mass
- 0.0131 x 1024
kg = Pluto Mass
- 29.8 km /sec = Earth velocity
- 5.4 km /sec = Neptune velocity
- (1)
- The Equation uses Pluto old registered mass which creates the rate 5.56 with the
moon mass – this same rate equal Neptune mass to Saturn mass – it's so interesting
equation because it tells the geometrical design of the solar system takes into
consideration all planets data and the rule or rate which is used for massive masses
planets be used again for the mall masses planets to create one design for the
whole system – the data provides very good vision about how the solar system be
created – the data shows clearly Newton theory of the sun mass gravity is mistaken
because no category be created based on planet mass value but the system uses
planets masses rates.
- (2)
- The Earth and Neptune velocities rate be created based on this data – we notice
that Earth mass is not a player in the equation – So how to explain the production
of the velocities rate? Any way the moon mass can refer to the motion and because
the Earth motion be connected with the moon motion that creates effect of this
equation data of Earth velocity – better answer we find in the next equation no. (9)

I do this research
2nd
25
Equation no. (9)
(102 /5.97) = 17.1
- 102 x 1024
kg = Neptune Mass
- 5.97 km /sec = Earth Mass
- 17.2 degrees = Pluto Orbital Inclination
- This equation gives better answer for the question of the previous one – the
interaction between Pluto and the moon motions be connected also with Earth
motion with equal connection – Pluto connects with Earth and its moon strongly –
and by this interaction of motions Pluto orbital inclination be created –
- This data should be discussed in more details in the next point no. (2-3) (Saturn
and Earth Motions interaction) because
- 10747 days (Saturn orbital period) = 17.1 x 629 days
- 629 mkm = Earth Jupiter distance be used as a period of time
- We should discuss this data in that point but I want to refer to one interesting fact
that the data ((102 /5.97) = 17.1 = (10747/629)) this data is so accurate – there
error is Zero between all these values which creates a real astonishment
Equation no. (10)
(1898 /102) = (5.97/0.33) = 18.6 (error 2.8%)
- 1898 x 1024
kg = Jupiter Mass
- 102 x 1024
kg = Neptune Mass
- 5.97 x 1024
kg = Earth Mass
- 0.33 x 1024
kg = Mercury Mass
- The idea we have concluded in the previous equation no. (8) be supported here
again by this equation – the rates be used by the massive masses planets be used
again by small masses planets to create one geometrical design for the system.
Equation no. (11)
(The Planets Masses Total 2666.7) / (Uranus mass 86.8) = 30.772

I do this research
2nd
26
- 2666.7 x 1024
kg = The solar Planets Masses Total
- 86.8 x 1024
kg = Uranus Mass
- Uranus Axial Tilt 97.8 deg = 31.13 deg x π
- The error between 30.722 and 31.13 = (1.3%)
- There's one more rate can be useful in our discussion
- (The Sun Mass / The Planets Masses Total 2666.7) = 749
- We remember that the number 749 is related to Uranus motion – we discuss it
deeply in Point no.(3-7) (Uranus Day Period Analysis) let's refer to it in brief
- Uranus day period = 17.2 h = 61920 seconds, and Uranus orbital period =30589
days, we need to us this period in seconds units to be 30589 seconds
- 61290 seconds = 2 x 30589 seconds + 742 seconds
- This is our number (742) and it different with (749) by an error 1%
- The equation tells an interesting meaning – for some reason Uranus occupied the
basic planet in the solar system and because of that the data uses the planets
masses total – I guess Uranus position is the reason – that Uranus position enables
it to control the other planet motions or by some effect Uranus can effect on them
– the point is that – the planets masses rates caused to create the planets orbital
inclinations – and the orbital inclinations cause to create the planets velocities rates
- This meaning tells that – the masses distribution is a basic player in the planets
motions – here is the basic point we search for – because the masses distribution
gives Uranus special position and enables it to practice a great effect on other
planets –
- I have discussed before an idea tells– Uranus motion effects on all planets Axial
Tilts to prevent the planets from the overturning motions around the sun.
- I want to say Uranus position has specific effect in the planets masses distribution.
- That explains the data – and also shows the importance of 742 seconds.

I do this research
2nd
27
Equation no. (12)
(The inner planets masses total 11.8) /(Venus mass 4.87) = 2.44
- 11.8 x 1024
kg = The Inner Planets Masses Total
- 4.87 x 1024
kg = Venus Mass
- 2.5 degrees = Saturn orbital inclination (error 2.5%)
- The rate (2.48) we have discussed in point no. (5,6 and 7) (The Solar Planets
Motions Use Different Rates Of Time) – this is the rate of time between Jupiter
and Saturn – and this rate be transported to Pluto by interaction with Jupiter
motion for that this rate be seen in Pluto motion data for example
- (90560 /37100) = 2.44 (error 2%)
- Where
- 90560 days = Pluto Orbital Period
- 37100 mkm = Pluto Orbital Circumference
- And because of the interaction between Earth and Pluto motions this rate be
transported to Earth motion data – for example
- 365.25 days = Earth Orbital Period
- 149.6 mkm = Earth Orbital Distance
- And in discussion there was a confusion because we don't discover how the rate
(2.48) be transported from Pluto to Earth -
- The Equation answers this question because it shows that the rate be transported
by help of the inner planets masses total
- That may explain the old data we have seen – let's remember it here

I do this research
2nd
28
2-3 Saturn and Earth Motions Interaction
- Can Saturn motion effect on Earth motion?
- Many basic data shows that Saturn motion effects on Earth and its moon motions
strongly. Let's summarize this data in following
- (1)
- Saturn orbital period =10747 days = 29.5 x 365.25 days (Earth orbital period),
- Saturn orbital period shows interesting effect because the Earth moon daily
displacement = 88000 km and Earth orbital circumference = 940 mkm by that the
moon needs 10747 days to pass 940 mkm by its daily displacement (error 0.6%).
This data means, the moon needs the period 10747 days regardless Saturn motion.
The question should be why Saturn orbital period be 10747 days? Can this period
of time proves an interaction of motions be found between Saturn and Earth?
- (2)
- The planets use different rates of time which we discuss in point no. (5,6 and7) of
this current paper. Saturn and The moon use equal rates of time for their motions –
by that 1 hour of Earth motion= 29.4 hours of Saturn motion= 29.4 hours of the
moon motion.
- (3)
- Earth (29.8 km/s) moves during 12104 seconds a distance = 360700 km = 3 Saturn
diameters (error 0.3%) where
- 12104 km = Venus diameter (be used as a period of time by a rate 1 km= 1sec)
- The moon orbital perigee radius = 363000 km (different with 360700km by 0.6%)
- (4)
- (28.3 deg /26.7 deg) = (26.7 deg/25.2 deg) =(25.2 deg/23.8 deg) =(122.5 deg/115.2
deg)
- 28.3 degrees = Neptune Axial Tilt
- 26.7 degrees = Saturn Axial Tilt
- 25.2 degrees = Mars Axial Tilt

I do this research
2nd
29
- 23.6 degrees = The outer planets orbital inclination total (different from 23.8
degrees with 0.7%)
- 122.5 degrees = Pluto Axial Tilt
- 115.2 degrees = 90 degrees +25.2 degrees (Mars Axial Tilt)
- (5)
- Light (0.3 mkm/sec) travels during 120536 seconds a distance = 36161 mkm
where 36161= 2π x 5757 mkm (= Earth Pluto Distance)
- And 120536 km = Saturn Diameter
- (6)
- The cycle 2737 which is repeated on 3/12/2012
- This cycle is repeated one time each 2737 years and in this cycle the 3 planets
Mercury, Venus and Saturn were perpendicular on the 3 heads of the great
pyramids in Egypt. Some records told the phenomenon be recorded by picture.
- The point is that, Saturn is one planet of the 3, and that shows the interaction
between Saturn and Earth motions because Venus motion can simply have an
interaction with Earth motion but Saturn is so far and by that the cycle adds one
more proof for the interaction of motions between Earth and Saturn and that may
explain the 2 planets motions data.
- Let's discuss the data to test if Saturn and Earth motions can have an interaction
- Notice
- The error of data be found for geometrical reasons – for example –the error 1% is
repeated frequently in data that because it's used for geometrical necessities – also
the rate (0.3%) this rate means (0.3% = 361/360) – and this rate be found as a
result for Metonic Cycle – because the moon orbit regresses 19 degrees per year
and during 19 years the total be 361 degrees which creates another scale (=361)
and not (360) by that the planets motions data make configuration with the new
scale– based on that – when the error 1% be decreased with 0.3% the rest be
=0.7% which is repeated error also

I do this research
2nd
30
I- Data
(1)
86400
E
J
T
2
2
=
e
v
v
x
S
(2)
1898 x 0.33 = 102 x 5.97 = 629 (error 2.8%)
(3)
6939.75 seconds x 0.3 mkm/s = 2094 mkm
2094 seconds x 0.3 mkm/s = 629 mkm
(4)
(568/1898) = 0.3

I do this research
2nd
31
II- Discussion
Equation no. (1)
86400
E
J
T
2
2
=
e
v
v
x
S
- Where
- 86400 seconds =The Solar Day
- S = The Sun Mass = 1988500 x 1024
kg
- T = Saturn Mass = 568 x 1024
kg
- J = Jupiter Mass = 1898 x 1024
kg
- E = Earth Mass = 5.97 x 1024
kg
- v = Light known velocity =300000 km/sec
- ve = Earth velocity
- Equation error = 0.7%
- The equation shows the effect of 4 players on Earth velocity creation – light
velocity be one player – that because the matter is created out of light – the 3
massive masses effect on Earth motion in comparison with Earth mass –
- That shows the masses gravity concept is a correct one – but not as Newton told.
- The equation aims to prove the a interaction or effect be found by Saturn on the
Earth motion which can explains the 2 planets motions data
- Please note that, the other planet in the equation is Jupiter and that tells Jupiter and
Saturn has equal effect on Earth motion – that explains many of the planets
motions data for example
- Please remember equation no. (4) of point (2-2)
- (4.87 /0.073) = 66.7 = (708.7 /10.7) = (655.7/9.9) – where
- 708.7 h = the moon day period 655.7 h = the moon rotation period
- 10.7 h = Saturn day period 9.9 h = Jupiter day period

I do this research
2nd
32
Equation no. (2)
1898 x 0.33 = 102 x 5.97 = 629 (error 2.8%)
- Where
- 0.33 x 1024
kg = Mercury Mass
- 1898 x 1024
kg = Jupiter Mass
- 102 x 1024
kg = Neptune Mass
- 5.97 x 1024
kg = Earth Mass
- 629 mkm = Earth Jupiter Distance
- The equation suggests very strange meaning – where the distance can be produced
by Masses multiplication – the explanation can be based on the energy because the
mass is made of energy and I suppose the space is made of energy – the equation
still complex in meaning – but its tells the 4 planets masses are rated and because
of that they can be written in another form (1898/102) = (5.97/0.33) = 18.6
- The error is still (2.8%)
- I can't explain how the masses can create the distance directly – but as we have
seen in the previous point of discussion – the masses rates creates the planets
orbital inclinations and that defines the planets velocities rates – that can enable
the masses rate to be transported to the distances rate by planets motions-
- The point of this equation is the distance 629 mkm =Earth Jupiter distance, we
have 2 questions related to this distance – the second question is in Equation no.(3)
so let's ask the other one here
- 227.9 mkm (Mars orbital distance) x 2 x 1.392 = 629 mkm (error 1%)
- The sun diameter = 1.392 mkm. Means the sun diameter be defined as a rate
between Mars orbital distance and Earth Jupiter distance – we remember that – the
lunar eclipse umbra length = 1.392 mkm = the sun diameter and this umbra be
created in the distance between Mars and Earth -
- Notice 224.7 days (Venus orbital period) can be used in place of 227.9 and the
error will be (0.5%) if the period 224.7 days can be used as a rate only.

I do this research
2nd
33
Equation no. (3)
6939.75 seconds x 0.3 mkm/s = 2094 mkm (error 0.6%)
Where
6939.75 days = Metonic Cycle Period
2094 mkm = Jupiter Uranus Distance
629 mkm = Jupiter Earth Distance
- Light (0.3 mkm/s) uses the period 6939.75 days as 6939.75 seconds, and during it
the light passes a distance = 2094 mkm = Jupiter Uranus Distance,
- The light (0.3 mkm/s) uses the passed distance as a period of time based on the
rate 1 mkm = 1 second, and during 2094 seconds the light passes a distance = 629
mkm = Earth Jupiter Distance
- By that Jupiter be as a point on a trajectory of light motion extends from Earth to
Uranus and vice versa – and this motion of light causes to create both distances
from Earth to Jupiter and from Jupiter to Uranus by one motion of light
- That supposes a massive effect of Metonic Cycle motion – and while we see the
Earth moon moves Metonic Cycle the moon refers by its motion to a great motion
be done by the light behind.
- The distance 629 mkm is our point of discussion – If we suppose the period 224.7
days be used to define the sun diameter by the data (629 mkm = 2 x 224.7 x 1.392
mkm), if we accept this data, that may explain important other data – because
- The sun diameter 1.392 mkm = Venus diameter 12104 km x 115.2
- Where 25.2 degrees = Mars Axial Tilt and 115.2 deg = 25.2 deg + 90 deg
- That tells the values (227.9 and 224.7) are crated depending on one another and
both be used for the sun diameter definition.

I do this research
2nd
34
- Notice
- 10747 days (Saturn orbital period) = 17.1 x 629 days
- 629 mkm = Earth Jupiter distance be used as a period of time
- Please remember equation no. (9) in point no (2-2)
(102 /5.97) = 17.1
- Where
- 102 x 1024
kg = Neptune Mass
- 5.97 km /sec = Earth Mass
- 17.2 degrees = Pluto Orbital Inclination
- The astonishment be found in the data accuracy where
- (102/5.97) = 17.08 = (10747/629)
- These 5 data are created together where the error generally is (Zero)
- That tells clearly, the period 10747 must be created for the moon motion and an
interaction must be found between Saturn and the moon motion and by this
interaction the period 10747 days be used as (Saturn orbital period)
- That means the data gives one more proof for an interaction must be found
between Earth and Saturn motions.

I do this research
2nd
35
Equation no. (4)
(568/1898) = 0.3
- Where
- 568 x 1024
kg = Saturn Mass
- 1898 km /sec = Jupiter Mass
- 0.3 = ??
- We know that (1898/568) = 3.34, which causes Venus orbital inclination to be
created as (3.4 degrees) (error 1.7%)
- We accept also that 1 degree can be = 1 mkm
- Can this value (0.3) be = 0.3 mkm
- I want to say that,
- This value is 0.3 mkm/sec and it's the light velocity – or in more clear words – it's
the creation of light with velocity = 0.3 mkm/s
- The idea is that, the mass distribution and proportionality creates the planets
orbital inclinations and the orbital inclinations cause the velocities to be created in
proportionality and comparison -
- By this machine – a motion velocity be equal 0.3mkm/s and by this velocity the
light be produced – this velocity be seen as a rate between Saturn and Jupiter
masses as seen in the equation –
- Based on this conclusion
- The sun rays creation be done by using Saturn and Jupiter motions data, that
explains why Saturn motion distances be related frequently with motions distance
of light (0.3 mkm/s).
- The point is that, Venus orbital inclination (3.4 deg) be created also by this process
that means, Venus is a basic player in the sun rays creation – that explains why the
sun diameter 1.392 mkm = 115.2 Venus diameter 12104 km

I do this research
2nd
36
- Notice
- The sun diameter 1.392 mkm= 115.2 x Venus diameter = 28.3 x Neptune diameter
= 205 x Mars diameter 6792 km
- where
- 28.3 degrees = Neptune Axial Tilt
- 25.2 degrees = Mars Axial Tilt
- 115.2 degrees = 90 degrees + 25.2 degrees
- 205 degrees = 180 degrees + 25 degrees
- That tells the sun diameter be created based on these 3 planets data – we should
discuss that in the sun creation point no. (10)
- Notice
- The solar system be created of one light beam its supposed 1.16 mkm/s and the
light known velocity (0.3 mkm/s) be created later with the sun creation – the light
supposed velocity existence proves be discussed in point no. (11)
- I want to say
- Newton is mistaken because the sun is created after all planets creation and motion
The light beam (0.3 mkm/s) proves that the planets be created before the sun
because the light supposed velocity (1.16 mkm/) was found before this light (0.3
mkm/s) creation.

I do this research
2nd
37
2-4 Planets Velocities Proportionality
I- Data
Data Part No. (1)
The Following Rule Controls Planet Motion Data
(r/R) (v1/ v2)
Where
- r = The Planet Rotation Periods Number In Its Orbital Period
- R = The Planet Diameter
- V1 = The Planet Velocity
- V2 = Another Planet Velocity
- Also
- The rate (v1/ v2) defines the planet orbital inclination –
- Let's test this rule for the solar planets data in following
(a)
(89143 /49528) = (9.7 /5.4)
(b)
(24106 x2 /120536) = (9.7 /24.1)
(c)
(42683 /51118) = (5.4/6.8) (error 5%)
(d)
(14178 /2390) = (27.78/4.7)
(e)
(10500 / 142984) = (13.1/29.8 x8)
(f)
671/6792 = (4.7 /24.1 x2) (error 1.3%)

I do this research
2nd
38
Data Part No. (2)
(1)
- (9.7 /5.4) = 4π / 7
- (6.8 /5.4) = 4/ π (1%)
- (9.7 /6.8) = π2
/ 7 (1%)
- And
- (9.7/5.4) + (13.1/9.7) = π
- Where
- 5.4 km/s = Neptune Velocity
- 6.8 km/s = Uranus Velocity
- 9.7 km/s = Saturn Velocity
- 13.1 km/s = Jupiter Velocity
(2)
(35/24.1) = π2
/ 6.8
(9.7 /6.8) = (35/24.1) (1.8%)
(35/ π2
) = 47.4/13.37 = 24.1 /6.8 = (2 x 9.7) /5.4 (1.3%)
(3)
(27.78 x π2
/ 47.4 x2) = 2.86 (error 1%)
(35 x2 /24.1) = 2.86 (error 1.5%)
(4 x29.8 / 13.1π) = 2.86 (error 1.3%)
(27.78 /9.7) = 2.86 (Zero error)
(24.1 x 2 / 5.4 π) = 2.86 (error less 1%)
(2π x 13.1)/(5.4)2
= 2.86 (error 1.3%)
(9.7 x 2/6.8) = 2.86 (error less 1%)
(6.8 x 2/ 4.7) = 2.86 (error 1%)
(1.16/0.406) = 2.86 (Zero error)

I do this research
2nd
39
Where
- 29.8 km/s = Earth velocity
- 27.78 km/s = The Earth Moon velocity
- 13.1 km/s = Jupiter velocity
- 9.7 km/s = Saturn velocity
- 4.7 km/s = Pluto velocity
- 1.16 mkm = Jupiter motion distance during mars rotation period
- 0.406 mkm = Pluto motion distance during a solar day

I do this research
2nd
40
II- Discussion
- We analyze the planets velocities proportionality as an independent subject before
our main discussion - because I try to show the transportation of motion is a
meaning has roots in the planets motions – We can't explain how the planets
velocities be defined in such proportionality unless a transportation of motion must
be found among the solar planets – simply no planet can move independently from
the others and their velocities be rated in such proportionality - I try to prove that
we don't deal with separated rigid bodies move independently from one another –
one the contrary we deal with one machine or one creature where the planets
motions show this creature members motions – because of that – the motions and
velocities be rated with one another – the data discussion will prove this meaning
clearly – let's start with Data Part No. (1) - Let's remember the rule -
(r/R) (v1/ v2)
Where
- r = The Planet Rotation Periods Number In Its Orbital Period
- R = The Planet Diameter
- V1 = The Planet Velocity
- V2 = Another Planet Velocity
Equation no. (a)
(89143 /49528) = (9.7 /5.4)
- Neptune Orbital Period (59800 solar days) has 89143 Neptune rotation periods
(16.1 h)
- 49528 km = Neptune Diameter
- The data follows the rule perfectly – error less than 1%
- Also
- 9.7 /5.4 = 1.8 where 1.8 degrees = Neptune Orbital Inclination

I do this research
2nd
41
Equation no. (b)
(24106 x2 /120536) = (9.7 /24.1)
- Saturn Orbital Period (10747 solar days) has 24106 Saturn rotation periods (10.7h)
- 120536 km = Saturn Diameter
- 24.1 km/s = Mars Velocity
- Also
- 24.1/9.7 = 2.5 where 2.5 degrees = Saturn Orbital Inclination
Equation no. (c)
(42683 /51118) = (5.4/6.8) (error 5%)
- Uranus Orbital Period (30589 solar days) has 42683 Uranus rotation periods
(17.2h)
- 51118 km = Uranus Diameter
- The data has an error 5%
- Also
- 5.4/6.8 = 0.8 where 0.8 degrees = Uranus Orbital Inclination
Equation no. (d)
(14178 /2390) = (27.78/4.7)
- Pluto Orbital Period (90560 solar days) has 14178 Pluto rotation periods (153.3 h)
- 2390 km = Pluto Diameter
- 4.7 km/s = Pluto Velocity
- 27.78 km/s = The moon Velocity
- The moon orbital inclination (5.1 degrees) is defined as a rate between its velocity
and Neptune velocity (27.78/5.4) = 5.1

I do this research
2nd
42
Equation no. (e)
(10500 / 142984) = (13.1/29.8 x 6)
- Jupiter Orbital Period (4331 solar days) has 10500 Jupiter rotation periods (9.9 h)
- 142984 km = Jupiter Diameter
- 29.8 km/s = Earth Velocity
- Also
- (29.8/13.1) x 2 = 4.5 where (Jupiter orbital inclination 1.3 deg + Jupiter axial tilt
3.1 deg) = 4.4 deg
Equation no. (f)
671/6792 = (4.7 /24.1 x2)
- Mars Orbital Period (687 solar days) has 671 Mars rotation periods (24.6 h)
- 6792 km = Mars Diameter
- The data has error 1.3%
- Also
- Mars orbital inclination 1.9 deg be defined as a rate between Mercury and Mars
velocities
- The rule doesn't work with the Earth almost because the moon orbital period = the
moon rotation period – and there are difficulties to us the rule with Mercury and
Venus because the rotation period is so great in comparison with the orbital period

I do this research
2nd
43
Data Part No. (2)
Equation no. (1)
- (9.7 /5.4) = 4π / 7
- (6.8 /5.4) = 4/ π (1%)
- (9.7 /6.8) = π2
/ 7 (1%)
- And
- (9.7/5.4) + (13.1/9.7) = π
- Where
- I use these 4 planets velocities as example for analysis – the rates shows clearly
that – there are found based on a geometrical mechanism and rules – we don't deal
with separated motions be done independently from one another but we deal with
some machine – imagine we analyze a car motion – the four wheels move relative
to one another – the motions be in comparison to one another – by that – I try to
show the planets motions can't be independent which supports the claim of the
transportation of motions among the solar planets.

I do this research
2nd
44
Equation no. (2)
(35/24.1) = π2
/ 6.8
(9.7 /6.8) = (35/24.1) (1.8%)
(35/ π2
) = 47.4/13.37 = 24.1 /6.8 = (2 x 9.7) /5.4 (1.3%)
Where
- 13.1 km/s = Jupiter velocity (error 2% with 13.37)
- Equation no.(2) supports the same discussion meaning and proves it
- Notice
- Equation no.(3) shows one equation controls all planets velocities – that creates
one connection for all planets motions which disprove the planet independent
motion concept.

I do this research
2nd
45
3- Saturn Motion Analysis
3-1 Preface
3-2 Saturn Diameter Analysis
3-3 Neptune Circumference Analysis
3-4 Neptune Day Period Analysis
3-5 Mercury Motion effect on Jupiter and Neptune Motions
3-6 Earth Motion Distance Daily Analysis
3-7 Uranus Day Period Analysis
3-8 The Inner Planets Motions Analysis

I do this research
2nd
46
3-1 Preface
- Can The Motion Be Transported Among The Solar Planets?
- The motion data be transported among the planets, how can motions data be
transported if the motions aren't? Can the data transportation among the planets be
considered as a proof for the motion transportation?
- I use Saturn motion data as example to prove that the data be transported among
the planets motions – let's make this point more clear by using an example for
explanation
- Example No. (1)
- 10 x 10747 days x 24 hours = 10.7 hours x 2 x 120536
- Where
- 10747 days = Saturn Orbital Period
- Later we may explain how the data use Saturn diameter as a rate in it
- The point which I try to explain is that –
- The 3 values (10747 days, 10.7 hours and 120536 km) are Saturn Data and without
the number (10) the values can't be created as seen in this equation –
- I want to say
- This number (10) is transported from a planet to another – and this number is
necessary for Saturn motion data as the previous equation shows –In the discussion
Point (No. 3) we will follow the number (10) from a planet to another proving that
all planets motions data aimed to transport this number (10) to Saturn motion data
–
- Shortly- I try to prove that the data be transported from a planet to another and I
use this number (10) as one example – during the discussion we will see tenths of
data be transported from a planet to another but we keep our eyes on this number

I do this research
2nd
47
(10) specifically to prove that it's (really) transported among the planets motions
data.
- This task of the discussion point is a promised task and important one – basically
because it proves there's a transportation of data (or of motions) among the planets
be performed –
- The Idea Summary
- The discussion tries to prove a transportation of motion be found in the solar
system among the planets– we use Saturn data and especially the number (10) as
our guide through the planets motions to discover if the motions or the motions
data really be transported.

I do this research
2nd
48
3-2 Saturn Diameter Analysis
I- Data
(1)
2 x 16.1 h x 3600s x 13.1 = 1518552 km = 4 x 379638 km =9.7 x 156552
(5.4 x 155597 = 7 x 120536 = 840224 km)
(2)
13.1 x 49528 = 648817 =5.4 x 120151 = 4 x 162204 (error 1%)
(3)
(378675 /13.1) =(155597/5.4) =28800 = 8 x 3600
(4)
13.1 x 51118 = 5.4 x 2 x 17.2 h x 3600 s
(5)
0.6 hour = 2160 s where 13.1 x 2160 = 28296 km
(6)
49528 x 1.13184 mkm = 2 x 28029 mkm
28244 days x 1.13184 mkm = 32200 mkm (0.7%)
(7)
9.7 x 2 x 16.1 h x 3600 = 13.1 x 85834 (error 0.6%)
(8)
13.1 x 120536=1579029 =47.4 x 33313=35x 45115 = 29.8 x 53000 = 27.78 x 56840=
24.1 x 65519 =9.7 x 162785 = 6.8 x 232210 =5.4 x 292411=4.7 x 335962

I do this research
2nd
49
II- Discussion
Equation no (1)
2 x 16.1 h x 3600s x 13.1 = 1518552 km = 4 x 379638 km =9.7 x 156552
And
Equation no (7)
9.7 x 2 x 16.1 h x 3600 = 13.1 x 86400 (error 0.6%)
- Equation no. (1) tells that
- Jupiter (13.1 km/s) moves during 2 Neptune days periods (2x16.1 h =2x 57960s) a
distance = 1518552 km = 4 Saturn Circumferences = Saturn motion distance
during 155597 seconds (where 155597 km =Neptune Circumference)
- And
- Equation no. (7) tells that
- Saturn (9.7 km/s) moves during Neptune day period (2 x 16.1 h =2 x 57960s)
a distance = 1124424 km = Jupiter motion distance during a solar day
- The main player in these motions is Neptune day period – Jupiter moves a distance
related to Saturn motion and Saturn moves a distance related to Jupiter motion
Why??
- The fact is that
- (13.1)2
/(4 x 9.7) = 4.4 = (378675/86400)
- Where
- 13.1 km /sec = Jupiter velocity
- 9.7 km /sec = Saturn velocity
- 378675 km = Saturn Circumference
- 86400 sec = The Solar Day
- We generally accept the supposed rate (1 km = 1 second)
- Based on the previous equation, Jupiter and Saturn both move during 2 Neptune
Days periods distances are rated to Saturn Circumferences and Jupiter motion
during the solar day period – the point is that –Saturn moves during its day period

I do this research
2nd
50
a distance = Saturn circumference (error 1.3%), that makes Saturn motion
distances rated to Saturn Circumferences
- This simple explanation left many questions behind – for example – can any planet
motion distances be rated with its circumference?– Saturn moves during its day
period a distance = Saturn Circumference (error 1.3%), Jupiter does the same but
the error is greater (4%) Uranus moves a distance = 2.6 its Circumference and
Neptune moves 2 Circumferences in its day period –the rule isn't clear yet –
- But
- The question was, Why both planets move distances related to each other during
Neptune day period?
- The part one is answered because of ((13.1)2
/(4 x 9.7) = 4.4 = (378675/86400) )
this part provides the answer but – part 2 isn't answered yet-Why during Neptune
day period specially? Let's answer that with Neptune Day period analysis point no.
(3-4)
- Here let's try to see why Jupiter and Saturn velocities be rated by this rule in
following (additional rule for Planets Velocities Analysis)
- A Rule For Planet Velocity Definition
- 4 x 5.4 (Neptune velocity) = (4.7)2
(error 2%)
- 4 x 6.8 (Uranus velocity) = ((5.4)2
) / 1.0725
- 4 x 9.7 (Saturn velocity) = 6.8 x 5.4 (error 5%)
- 4 x 13.1 (Jupiter velocity) = 9.7 x 5.4
- 8 x 24.1 (Mars velocity) = 6.8 x 27.78 (error 1.8%)
- 4 x 27.78 (the moon velocity) = 24.1 x 4.7 (error 1.8 %)
- 8 x 29.8 (Earth velocity) = 6.8 x 35
- 4 x 35 (Venus velocity) = 29.8 x 4.7
- 4 x 47.4 (Mercury velocity) = 27.78 x 6.8
- (4.7 km/s = Pluto velocity)

I do this research
2nd
51
- The previous rule shows that the form of (4 v1 = v2 x v3) or (4 v1 = v2
) is a usual
form of using and by that the rule we have found which is
- (13.1)2
/(4 x 9.7) = 4.4 = (378675/86400)
- This rule is found based on the same rule we have explained – and by that we
discover one more rule be found behind the planets velocities definition –
- Let's complete our data discussion
Equation no (2)
13.1 x 49528 = 648817 =5.4 x 120536 = 4 x 160592 (error 1%)
- Where
- 13.1 km /s = Jupiter velocity
- 5.4 km /s =Neptune velocity
- 160592 km = Uranus Circumference
- The data shows interesting feature – because –
- Each time Neptune diameter be used as a period of time for (any) planet motion,
the passed distance be related to Saturn Diameter –let's prove that in following
(1)
- Jupiter (13.1km/s) moves during 49528 sec a distance = 648817 km = the distance
be passed by Neptune in a period 120536 sec (where 120536 km =Saturn diameter
and 49528 km = Neptune diameter)
(2)
- Saturn (9.7 km/s) moves during 155597 sec a distance = 1509291 km = 4 x
378675 km (Saturn Circumference) (Where 155597 km =Neptune Circumference)
(3)
- Neptune (5.4 km/s) moves during 155597 sec a distance = 840224 km = 7 x
120536 km (Saturn Diameter) = Saturn motion distance during a solar day

I do this research
2nd
52
(4)
- 8 Neptune days periods = 466884 seconds (error 0.7%) where
- 466884 km = Neptune motion distance during a solar day = 3 x 155597 km
(Neptune Circumferences)
Equation no (3)
(378675 /13.1) =(155597/5.4) =28800 = 8 x 3600
- Where
- 155597 km = Neptune Circumference
- 378675 km = Saturn Circumference
- Equation no. (3) tells that,
- Jupiter (13.1 km/s) moves during (8 hours) a distance = 378675 km = Saturn
Circumference
- And
- Neptune (5.4 km/s) moves during (8 hours) a distance = 155597 km = Neptune
Circumference
- The secret is that 8 hours is around (50%) of Neptune day period (16.1 h)
- Means
- During 2 Neptune days periods
o Jupiter moves a distance = 4 Saturn Circumferences
o Neptune moves a distance = 4 Neptune Circumferences
o Saturn moves a distance = Jupiter motion distance during a solar day
- Why?
- What's the big secret in Neptune day period? It = 67% of a solar day!
- That's all why it's very specific period of time?!
- We should discuss that in point no. (3-4)

I do this research
2nd
53
Equation no (4)
13.1 x 51118 = 5.4 x 2 x 17.2 h x 3600 s
- Where
- 51118 km = Uranus diameter
- 17.2 hours = Uranus diameter
- Equation no. (4) shows that,
- Uranus data be used also in this same network –
- We clearly have some network between Jupiter, Saturn and Neptune, in this
network the 3 planets diameters, days periods and velocities are rated to perform
specific motions which be seen in the passed distances proportionality
- Equation no.(4) and Equation no. (2) tell that Uranus data be used also in this same
network – by that –
- Jupiter (13.1 km/s) moves during (51118 seconds) a distance = 669646 km = the
distance be passed by Neptune during 2 Uranus days periods – The proportionality
of data be seen clearly..
- To make this discussion more understandable let's see the 4 planets velocities
proportionality again in following
- The 4 Planets Velocities
- (9.7 /5.4) = 4π / 7
- (6.8 /5.4) = 4/ π (1%)
- (9.7 /6.8) = π2
/ 7 (1%)
- And
- (9.7/5.4) + (13.1/9.7) = π
- Where

I do this research
2nd
54
- The point is that these velocities be created based on one another by specific
geometrical rule – the motions distances are mentioned and defined clearly for
geometrical necessities –
- We clearly deal with one machine and these 5 planets are players in one team
move defined distances for specific geometrical reasons
- Notice
- Pluto is the fifth player where
- Pluto (4.7 km/s) moves during 51118 seconds a distance = 2 x 120536 km (Saturn
diameter) (where 51118km= Uranus diameter)
- And
- Pluto (4.7 km/s) moves during 2 x 120536 seconds a distance = 1.13184 mkm
(=Jupiter motion distance during a solar day)
- Pluto talk a similar language to the 4 other planets – it moves distances equal
Saturn diameters or circumferences and when this distance be used as a period of
time Pluto moves during it a distance = Jupiter motion distance during a solar day
– Why? What's the geometrical mechanism which causes this network of planets to
move as pieces of chess each piece moves a distance be calculated and defined in
comparison and proportionality with the other distances?
- I wish the data shows and proves that we are very far from the point on which
Newton theory of the sun gravity stand – where we discuss and analyze different
motions features completely from his description of the planets motions

I do this research
2nd
55
Equation no (5)
0.6 hour = 2160 s where 13.1 x 2160 = 28296 km
- Where
- 0.6 hours = 24.6 h (Mars rotation period) – 24h (the solar day)
- The Equation tells that
- Jupiter moves during (0.6 hours) distance = 28296 km
Equation no (6)
49528 x 1.13184 mkm = 2 x 28029 mkm
28244 days x 1.13184 mkm = 32200 mkm (0.7%)
- Where
- 1.13184 mkm = Jupiter Motion Distance During a solar day
- 28244 mkm = Neptune Orbital Circumference (be used as a period of time)
- 32200 mkm = The different distance between Pluto orbital circumference
(37100mkm) and Jupiter orbital Circumference (4900 mkm)
- The Equation tells Jupiter moves during (28244 days) a distance = 32200 mkm

I do this research
2nd
56
Equation no (8)
13.1 x2x 120536=2 x 1579029 =47.4 x 66626=35x 90560 = 29.8 x 106000 = 27.78 x
113680= 24.1 x 131038 =9.7 x 2x 162785 = 6.8 x 2x 232210 =5.4 x2x 292411=4.7 x
2x 335962
- Where
- 13.1 km/s = Jupiter velocity
- 29.8 km/s = Earth velocity
- 27.78 km/s = The moon velocity
- 4.7 km/s =Pluto velocity
-
- Equation no. (8) tells that,
- Jupiter (13.1 km/s) moves during ( 2 x 120536 seconds) a distance = 2 x 1579029
km – this distance be passed by the other planets in different periods of time – the
point is that – Each planet uses a very specific period of time – let's refer to Venus
Motion in following
- Venus Motion
- Venus (35km/s) moves during 90560 seconds the distance = 2 x 1579029km
- Where
- 90560 solar days = Pluto Orbital Period
- Venus uses 90560 seconds
- The data is a complex one because –

I do this research
2nd
57
- Pluto (4.7 km /s) moves during 90560 seconds a distance = 425632 km = Venus
motion distance during 12104 seconds (where 12104 km = Venus diameter)
- But
- The distance 425632 km = Uranus motion distance during its day period 421056
km (error 1%)
- Means
- Venus moves the distance 2 x 1579029km in 90560 seconds because there's
another connection between Venus and Pluto related to Uranus motion distance
during its day period – but still we need to discover the geometrical mechanism
based on which these motions be done
- We deal with a network or a board of chess – each piece moves in comparison
with the other pieces based on geometrical calculations.
- Let's look at Saturn motion
- Saturn Motion
- Saturn (9.7 km/s) moves during (2 x 162785 seconds = 160592 error 1%) where
(160592 km = Uranus diameter) the distance 2 x 1579029
- Saturn using of Uranus diameter as a period of time be created based on the
network of the 5 planets we have discussed before
- The other planets data be interesting and we will use them in different points of
discussion – but there's a difficulty to explain them in details here because it needs
extending discussion – the next points of discussion will make them more clear

I do this research
2nd
58
3-3 Neptune Circumference Analysis
Group no. (I)
(1)
155597 sec = 4 x 10.7 hours x 3600 s (error 1%)
(2)
120536 sec = π x 10.7 hours x 3600 s (error 0.4 %)
(3)
(9.7 / 5.4) = 4π/7
(4)
155597 sec x 5.4 km/s = 840224 km = 2 x 420112 km = 7 x 120536 km = 373644 km
+ 466884 km
(5)
2 x 155597 sec x 9.7 km/s = 8 x 378675 km = 3.024 mkm =
(6)
49528 km = 9.7 x 5106 sec
Group no. (II)
(7)
142984 sec = 4 x 9.9 hours x 3600 s (error 361/360)
(8)
2x 160592 sec = 9 x 9.9 hours x 3600 s (error 361/360)
(9)
(120536 km /5.4 km) = (25920 mkm /1.16 mkm)
Notice
In Neptune Circumference analysis there are many data be used from Saturn diameter
analysis but we need to extend the discussion for better vision – for that we have to
repeat the data using.

I do this research
2nd
59
II-Discussion
Equation no. (1)
155597 sec = 4 x 10.7 hours x 3600 s (error 1%)
Equation no. (2)
120536 sec = π x 10.7 hours x 3600 s (error 0.4 %)
Equation no. (3)
(9.7 / 5.4) = 4π/7
- Where
- The previous data shows that
- Neptune Circumference and Saturn diameter both can be considered as functions
in Saturn day period if 1 km be = 1 second - the data has error (1%) and (0.4%),
the functions depend on (4) for Neptune and (π) for Saturn and by that the rate
between both = (4/π)
- The 2 planets velocities rate be (4π/7), we see that the 2 rates are near
- We should ask why the 2 rates are near?
- The point I need to discuss now immediately is the result of this proportionality,
because it has a massive effect on both planets motions –
- Let's see the next equations

I do this research
2nd
60
Equation no. (4)
+466884 km
Equation no. (5)
2 x 155597 sec x 9.7 km/s = 8 x 378675 km = 3.024 mkm
Equation no. (6)
49528 km = 9.7 x 5106 sec
- Shortly
- Neptune motion during (155597 s) passes a distance = 7 Saturn diameters
- Saturn motion during (155597 s) passes a distance = 4 Saturn Circumferences
- We notice that
- Neptune Circumference =4 Saturn days periods if 1 km = 1sec and
- Saturn Diameter =π x Saturn day period if 1 km = 1sec and
- I try to prove that a geometrical rule must be found behind this proportionality of
data, before any progress in the discussion we need to know why Saturn velocity
=9.7 km/s and Neptune velocity =5.4 km/s – because the rate between the 2
velocities is very near to the rate between Neptune circumference and Saturn
diameter – No hope to use (the pure coincidence of numbers) as a method of
Escape – because we have many different data be created depends on one another.
- Let's see equation no. (4) in following

I do this research
2nd
61
Equation no. (4)
+466884 km
- Where
- 838000 km = Saturn motion distance during a solar day
- 421056 km = Uranus motion distance during Uranus day period
- 120536 km= Saturn diameter
- 373644 km = Saturn motion distance during Saturn day period
- 466884 km = Neptune motion distance during a solar day
- 155597 km= Neptune Circumference
- Neptune (5.4 km/s) moves during 155597 sec a distance = 840224 km
- But, the distance 840224 km is so interesting one because
- (1)
- 840224 km = it equals Saturn motion distance during a solar day (838000 km)
- (840224 /838000) =(361/360)
- (2)
- 840224 km = 2 x Uranus motion distance during Uranus day period (17.2 h)
- 840224 km = 2 x 420112 km (Uranus motion distance =421056 km)
- (3)
- 840224 km =373644 km + 466884 km
- So
- Neptune motion during (155597 sec) moves distance = 7 Saturn diameters =
Saturn motion distance during a solar day = 2 Uranus motion distance during its
day period = the total of Neptune motion distance during a solar day plus Saturn
motion distance during Saturn day period
- It must be the greatest happy chance in the universe which produces so many
(correct) distances by one motion!

I do this research
2nd
62
Equation no. (5)
155597 sec x 9.7 km/s = 4 x 378675 km
- Saturn moves during 155597 sec a distance = 4 Saturn Circumferences
- Here
- Neptune motion and Saturn motion (during the same period of time 155597 sec)
pass distances = Saturn diameters and circumferences respectively! Why?
- But
- 2 values of 155597 sec makes a difference because
2x 155597 sec x 9.7 km/s = 8 x 378675 km = 3.024 mkm
- Saturn moves during (2 x 155597 sec) a distance = 8 Saturn circumferences
- And
- For one more happy chance the 8 Saturn circumferences total be = 3.024 mkm =
Venus motion distance during a solar day
- Why?
- By the way
- 35 km/sec (Venus velocity) = 2x (9.7)2
x 5.4
- Means, Venus velocity is produced as a function in Saturn velocity (9.7 km/s) and
Neptune velocity (5.4 km/s)
- And
- (35/6.8) = (24.1 /4.7) = (27.78 /5.4)
- Where
- 35 km/s = Venus Velocity
- 27.78 km/s = The Moon Velocity

I do this research
2nd
63
- That makes Uranus velocity be rated with Venus velocity through this interesting
machine of velocities
- Notice
- Neptune moves during its day period a distance = 2 Neptune Circumferences = 2 x
155597 km
- This information is an important one because Neptune motion uses (usually) the
value (2 x 155597 km) as we have seen.
- Also
- 2 x 155597= 311194 km =Jupiter diameter +Saturn diameter + Uranus diameter (1%)
- This data shows again Neptune motion uses the value (2 x 155597 km) better than
(155597 km) and that means the geometrical design uses this distance of motion be
passed by Neptune during its day period and not uses Neptune circumference.

I do this research
2nd
64
Equation no. (6)
49528 km = 9.7 x 5106 sec
- The Equation tells that, Saturn (9.7 km/s) moves during 5106 seconds a distance =
49528 km (Neptune diameter) –
- but we know that –
- Mercury day period needs 5040 seconds to be 4224 hours
- 5106 seconds is different from 5040 seconds with (1.3%) - Means
- Saturn moves during (5040 seconds) a distance = Neptune diameter (error 1.3%)
- Mercury moves during (5040 seconds) a distance = 2 Saturn diameters (error -1%)
- Mars moves during (5040 seconds) a distance = Saturn diameter (error +1%)
Equation no. (7)
142984 sec = 4 x 9.9 hours x 3600 s (error 361/360)
- Where
- 142984 km =Jupiter diameter
- 9.9 hours = Jupiter day period
- Equation no.(7) tells simply that, Jupiter diameter can be equal 4 days of Jupiter
days if 1km= 1 second
- 4 Jupiter days = 142560 seconds
- And
- (142984 /142560) = (361/360)
- Now
- Jupiter is the 3rd
planet whose diameter can be used as a period of time because it
equals 4 Jupiter days periods (the 2 planets are Saturn and Neptune)
- Again
- We have to ask (Can Planet diameter depend on it day? Or on any period of time?)
Why the planet diameter be used as a period of time?!

I do this research
2nd
65
Equation no. (8)
2x 160592 sec = 9 x 9.9 hours x 3600 s (error 361/360)
- Where
- 160592 = Uranus Circumference
- 9.9 hours = Jupiter Day Period
- Equation no.(8) tells 2 Uranus circumferences can be = 9 Jupiter days if
- 1 km =1 second
- Shortly
- Saturn and Neptune diameters depend on Saturn Day Period
- And
- Jupiter And Uranus Diameters Depends One Jupiter Day Period
- We remember that
- 2 Jupiter circumferences – 2 Saturn circumferences = 1 Jupiter diameter (1.3%)
- This data tells that
- Saturn diameter be created as a function in Jupiter diameter and that connects the 4
planets data together
- Can Saturn day period (10.7 h) depend on Jupiter day period (9.9 h)?
- Notice
- Neptune Circumference depends on 4 Saturn days periods
- Jupiter diameter depends on 4 Jupiter days periods
- Earth cycle is 4 years (365 +365 +365 +366 =1461 days)
- Can this (4 Periods) Cycle be a general cycle in the solar system?

I do this research
2nd
66
- The Discussion Summary
- Let's summarize the discussion idea in following:
- There are 2 reasons of proportionality between Saturn and Neptune motions data –
- (First) (Saturn velocity /Neptune velocity) = (4π /7)
- (second ) (Saturn diameter be produced by a motion during 155597 seconds
whether . .this motion be done by Saturn or by Neptune
- Here we have 2 reasons of proportionality, and no logic to suppose both of them
be created by chance -
- If the 2 planets diameters be created as function in Saturn day period (although we
don't know how that can be possible) – the question is still on table asks that why
the velocities are rated? It's incredible the 2 planets diameters are rated and also
their velocities – that makes the 2 planets motions data some how identical – for
example –
- Neptune orbital distance 4495.1 mkm = Saturn orbital distance 1433 mkm x π
- And
- Neptune orbital period 59800 d = Saturn orbital period 10747 d x (π)3/2
- The 2 planets motions data be some how identical because of this proportionality

I do this research
2nd
67
3-4 Neptune Day Period Analysis
I-Data
(1)
8 x 16.1h x 3600s =3 x 155597s =466884 s
(2)
8 x 466884 km = 31 x 120536 km
(3)
16.1 -10.7 = 5.4 but 5.4 x 2 = 10.8 hours
(10.8 + 10.7 x 2 = 2 x 16.1)
(4)
24.1 x 5.4h x 3600 = 466884 km
13.1 x 5.4h x 3600 = (51118 km x5)
9.7 x 5.4h x 3600 = (378675 km /2)
6.8 x 5.4h x 3600 = (21346.6 km x 2π) (error 1.5%)
5.4 x 5.4 h x 3600 = 9.7 x 10747 (error +0.7%)
4.7 x 5.4 h x 3600 = 90560 (error 1%)
(5)
16.1 -9.9 = 6.2 hours x 3600 = 22320 seconds
(6)
(17.2 h -16.1h) = 1.1h = 3960 seconds
(7)
(24/16.1)= (16.1/10.7) (error -1%)
Where
24 h = The Solar Day
16.1 h = Neptune Day Period
10.7 h = Saturn Day Period
Notice
Saturn day period should be 10.8 hours to remove the equation error

I do this research
2nd
68
(8)
(24.1/4.7) x 7510 = 3600 x 10.7
Where
24.1 km/s = Mars Velocity
4.7 km/s = Pluto Velocity
10.7 h = Saturn Day Period
7510 km = Neptune Circumference

I do this research
2nd
69
II – Discussion
Equation no. (1)
8 x 16.1h x 3600s = 3 x 155597s = 466884 s
- Where
- 466884 km = Neptune Motion Distance During a solar day = Jupiter motion
distance during Jupiter day period
- Equation no. (1) explains how Neptune circumference be created depending on
Neptune day period – this creation depends on the rate (8/3) (= 2.6666)
- The fact is that
- 4 Saturn days periods total = 10.7 h x 4 = 154080 sec (=155597 km error 1%)
- And
- 8 Neptune days periods total = 466884 sec= 3 x 155597 sec
- That because
- 12 Saturn days periods total = 128.4 hours
- 8 Neptune days periods total = 128.8 hours
- The difference 0.4 hour = 1440 seconds
- That explain the connection between the 2 periods –
- But
- Why Neptune moves during its day period a distance = 466884 km = 3 Neptune
Circumferences = and can be = 8 Neptune days periods total if 1 km = 1 sec?
- Where
- Jupiter motion distance during Jupiter day period be = 466884 km
- How to understand this data??

I do this research
2nd
70
Equation no. (2)
8 x 466884 km = 31 x 120536 km
- Where
- 466884 km = Neptune motion distance during a solar day
- 120536 km = Saturn diameter
- We notice that,
- (1)
- Neptune moves during 22320 seconds a distance = 120536 km
- The period 22320 seconds = 6.2 hours = the difference between Neptune day
period 16.1 hours and Saturn day period 10.7 hours
- (2)
- Neptune moves during 10800 seconds a distance = 58320 km =3600 x 16.2
- (3)
- (466884 sec /86400 sec) = 5.4 (error 0.6%)
- Also
- We need to ask (How Planet Velocity Be Defined?)
- Let's try to answer this question with the next equation
Equation no. (3)
16.1 -10.7 = 5.4 but 5.4 x 2 = 10.8 hours
(10.8 + 10.7 x 2 = 2 x 16.1)
- Where
- Equation no.(3) is important for many reasons – let's refer to them in following:

I do this research
2nd
71
- (1st
Reason)
- Saturn (9.7 km/s) moves during its day period (10.7 hours) a distance= 373644 km
= Saturn circumference (378675 km) (error 1.3%). Accurately 378675 km is
different from 373644 km by a distance 5031 km
- Saturn needs its day period to be 10.84 hours to move a distance = 378675 km, by
that the difference 5.4 hours x 2 = 10.8 hours can be used as a period of time for
Saturn to move a distance = its circumference, more better than Saturn day 10.7
hours –that makes equation no. (3) important equation – but why Saturn day period
isn't equal = 10.84 hours and enable Saturn to move in its day period a distance =
its Circumference?
- We should discuss this question deeply – but for a short notice – that be a result of
Neptune motion effect on Saturn- let's add one more data in following
- Additional data no. (a)
- Neptune (5.4 km/s) moves during Saturn day period (10.7 h) a distance =208008
km and
- Uranus (6.8 km/s) moves during (30589 seconds) a distance =208008 km
- The point is that,
- Uranus orbital period = 30589 days and Uranus uses in its motion (30589 sec),
where this period of time be very accurate value has (Zero error), That shows the
period of Neptune motion was accurate also and that shows the period (10.7 h) is
almost created as a result of interaction between the 2 planets motions – and that
tells Saturn day period be defined based on this balancing of the 2 planets motions
periods.
- (2nd
Reason)
- We have 2 data pushed us to ask the question how the planet velocity be created?
which are:
- (466884 sec /86400 sec) = 5.4 (error 0.6%)
- And

Planet Motion Reason (Revised) (no.2).pdf

Planet Motion Reason (Revised) (no.2).pdf

Recommended

Recommended

More Related Content

Similar to Planet Motion Reason (Revised) (no.2).pdf

Similar to Planet Motion Reason (Revised) (no.2).pdf (20)

More from Gerges francis

More from Gerges francis (20)

Recently uploaded

Recently uploaded (20)

Planet Motion Reason (Revised) (no.2).pdf