This will really help students in knowing Concentration of Solution. It has examples, explanations, exercises and activities.

1. 11/27/2020
1
SCIENCE 7Concentration of Solutions

2. MELC : Expresses concentrations of solutions quantitatively by
preparing different concentrations of mixtures
according to uses and availability of materials.
Quarter : 1
Week : 6
Objectives:
A. Defines concentration of a solution;
B. Distinguishes concentrated solution from diluted solution; and
C. Shows willingness to answer a given problem using the correct
formula in finding the percentage concentration of a solution.

3. Let’s have a recap…
 What is a solution?
A homogenous mixture of two or more substances.
A mixture of solvent & solute.
 How are you going to define a solute and a solvent?
A solvent is a substance that dissolves the solute.
A solute is a substance dissolved in a solvent.
What is the solute in the given solution?
• Orange Powder
How about the solvent?
• Water
A mixture of orange powder (solute ) and water
(solvent ) forms an orange juice (solution).

4. A B C
Which of the picture shows a saturated
solution and unsaturated solution?
Saturated – B
Unsaturated – A
How about supersaturated solution?
Picture C
How are you going to describe a solution that is unsaturated?
It contains less than the maximum amount of solute.
What is a saturated solution?
It contains the maximum amount of solute dissolved by a given amount of
solvent.
When can a solution become supersaturated?
It holds more solute than it normally could in its saturated form. It
involves heating.
Let’s have a recap…

5. Let’s start!
QUESTIONS:
1. How will you describe the pictures above?
2. Which of the following solution is concentrated?
3. How are you going to describe the concentration of a solution?
4. Is there a way to express the concentration of a solution?

6. Diluted
Solution
 contains small amount of solute.
Percent by
Mass
 is a ratio of a measured amount of solute to a
measured amount of solution.
Terms to remember…
Percent by
Volume
 is a ratio of the volume of solute to the total
amount of volume the solution.
Concentration  is a ratio comparing the amount of solute to the
amount of solution.
Concentrated
Solution
 contains large amount of solute.

7. Concentrations of Solutions
measures of how much solute is dissolved in a specific amount of
solvent
We describe a solution as concentrated and diluted.
Concentrated Solution
 contains large amount of solute
Diluted Solution
 contains small amount of solute

8. CONCENTRATED DILUTED

9. Ways of expressing concentration:
%
%
 Volume of solution is
in mL
 Mass of solute is in g
 Mass of Solution = Mass of Solute + Mass of
Solvent Volume of Solution= Volume of Solute + Volume of
Solvent

10. Sample Problem:
1. What is the percent by mass of NaHCO3 in a solution containing 20g NaHCO3
dissolved in 600 g of water?
Given:
mass of solute = 20 g of NaHCO3
mass of solvent = 600 g of water
Required: Percent by mass= ?
Formula:
Percent by
mass =
Mass of
solute
Mass of
solution
X 100 %
Percent by
mass = 600 g + 20
g
X 100 %
20 g________________
= 3.23 %
620 g
X 100 %________________
20
g
=

11. Sample Problem:
2.What is the percent by volume of ethanol in a solution that
contains 45 mL of ethanol dissolved in 125 mL of water ?
Given:
volume of solute = 45 mL of ethanol
volume of solvent =125 mL of water
Required: Percent by volume= ?
Formula:
Percent by Volume=Volume of
solute
Volume of
solution
X 100 %
Percent by
Volume=
125 mL+ 45
mL
X 100 %
45
mL
= 26.47
%
__________________
170 mL X 100 %____________45
mL
=

12. 1. Calculate the percent by mass of 4.35 g of NaCl dissolved in 105 g of water.
Percent by
mass=
Mass of
solute
Mass of
solution
X 100 %
Percent by
mass=
105 g + 4.35
g
X 100 %
4.35
g
________________
= 3.98 %
109.35 g
X 100 %4.35
g
________________
=
Given:
mass of solute = 4.35 g of NaCl
mass of solvent = 105 g of water
Required: Percent by mass =?
Formula:
Let’s wrap it up…

13. 2. What is the percent by volume of isopropyl alcohol in a solution that
contains 50 mL of isopropyl alcohol in 2.2 mL of water?
Percent by volume= Volume of solute
Volume of solution
X 100 %
Percent by volume=
50 mL + 2.2
mL
X 100 %
50 mL________________
= 95.79 %
52.2 mL
X 100 %
50 mL
= ________________
Given:
volume of solute = 50 mL of isopropyl alcohol
volume of solvent = 2.2 mL of water
Required: Percent by volume =?
Formula:
Let’s wrap it up…

14. I. Solve the following problems below. Show your solutions for 10 points each.
Let’s solve this…
For online, submit your answer on Friday, October 16, 2020 @ 02:00
PM to Google Classroom.
For modular, write your answer on a short bondpaper and submit your
answer on Tuesday, October 20, 2020 @ 08:00 – 04:00 PM here in school.
1. What is the percent by volume of hydrochloric acid in a solution that
contains 75 mL of hydrochloric solution in 4.2 mL of water?
2. Calculate the percent by mass of 7.05 g of calcium fluoride (CaF) dissolved
in 90 g of water.
3. What is the percent by volume of ethanol in a solution that contains 50 mL
of ethanol dissolved in 100 mL of water ?

15. ONLINE
For online, submit your answer on Friday, October 16, 2020 @ 02:00
PM to Google Classroom.
Attached the recorded video of the performed activity.
Let’s deepen more…
For modular, write your illustration and observation on a short
bondpaper and submit your answer on Tuesday, October 20, 2020 @ 08:00 –
04:00 PM here in school.
ACTIVITY # 4: LET’S MIX IT UP…
TASK: In a 2-minute video, perform an experiment showing the difference
between concentrated solution from diluted solution. Specify its importance.
ACTIVITY #4: LET’S MIX IT UP…
TASK: In a Home Task Activity, perform an experiment showing the difference
between concentrated solution from diluted solution. Illustrate each sample
and indicate each solution. Specify its importance.
MODULAR:

16. October 12, 2020
LET’S STUDY IN ADVANCE…
Let’s bring it home…
For online, please be ready for our Oral Examination next meeting
via Google Meet with your respective meeting code.
Sir Christian A. Ursabia
ONLINE/MODULAR:
For blended and modular, please be ready for our Oral Examination
on October 15, 2020 (02:30 – 04:00 PM) via Phone Call or Messenger if
available for blended.