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BITS Pilani
                            Pilani Campus




Lecture 12 – FIRST LAW ANALYSIS FOR
             FIRST-
A CONTROL VOLUME
Throttling valve

Throttling valves are any kind of flow-restricting devices
         g              y                        g
  that cause a significant pressure drop in the fluid.

The pressure drop in the f
                         fluid is often accompanied by a large
                                   f
  drop in temperature, and for that reason throttling devices
  are commonly used in refrigeration and air-conditioning
  applications.




                                                         BITS Pilani, Pilani Campus
Throttling valve




                   BITS Pilani, Pilani Campus
Throttling valve

Helium is adiabatically throttled from 1.2 MPa,
                      y
 20°C, to a pressure of 100 kPa. The diameter of
 the exit pipe is so much larger than the inlet pipe
 that the inlet
 th t th i l t and exit velocities are equal. Fi d
                   d it l iti                l Find
 the exit temperature of the helium and the ratio
 of the pipe diameters
             diameters.




                                             BITS Pilani, Pilani Campus
BITS Pilani, Pilani Campus
Helium is adiabatically throttled from 1.2 MPa, 20°C, to a pressure of 100
kPa. The diameter of the exit pipe is so much larger than the inlet pipe that
the inlet and exit velocities are equal. Find the exit temperature of the
helium and the ratio of the pipe diameters.

           1 2              1 2
   q + hi + Vi + gZi = he + Ve + gZe + w
           2                2
                  ⇒ hi = he
  Assuming for Helium as an ideal gas ⇒ Ti = Te = 20 C
                                                                                         o

  Also please note here that for Helium specific heat remains
    constant (Fig. 5.17)
                                  A iV i        A eV e
            o
           Now         mi =
                       &                 = m
                                           &e =
                                   vi            ve
            Ai   di
          ∴    =    =                   P e P i = 0 . 288683
            Ae   de

                                                                                BITS Pilani, Pilani Campus
Turbine
A rotary steady-state machine whose
   purpose is to produce shaft work ( power
   on rate basis) at the expense of energy of
   flowing fluid. Eg. Steam turbine, Gas
   turbine, Hydraulic turbine.
Normally turbine process is adiabatic.




                                                BITS Pilani, Pilani Campus
Turbine




          BITS Pilani, Pilani Campus
Turbine




          BITS Pilani, Pilani Campus
Turbine

A small adiabatic turbine, shown in Fig., is operated
  at part l d b th ttli a 0 25 k / steam supply at
   t    t load by throttling 0.25 kg/s t         l t
  1.4 MPa, 250°C down to 1.1 MPa before it enters
  the turbine and the exhaust is at 10 kPa If the
                                          kPa.
  turbine produces 110 kW, find the exhaust
  temperature (and quality if saturated).
      p         (    q      y          )




                                             BITS Pilani, Pilani Campus
A small adiabatic turbine, shown in Fig., is operated at part load by
throttling a 0.25 kg/s steam supply at 1.4 MPa, 250°C down to 1.1 MPa
before it enters the turbine and the exhaust is at 10 kPa. If the turbine
produces 110 kW fi d th exhaust t
    d           kW, find the h t temperature ( d quality if saturated).
                                             t (and          lit     t t d)


   Control volume: throttle valve
   Steady state process, q = 0 and w = 0.
   single stream entry and exit
   Assume no change in kinetic or p
                   g              potential energy.
                                                gy
   The energy equation then reduces to

             1 2             1 2
     q + hi + Vi + gZi = he + Ve + gZe + w
                    Z               Z
             2               2
                        h1 = h2 = 2927.22 kJ/kg




                                                                              BITS Pilani, Pilani Campus
A small adiabatic turbine, shown in Fig., is operated at part load by
throttling a 0.25 kg/s steam supply at 1.4 MPa, 250°C down to 1.1 MPa
before it enters the turbine and the exhaust is at 10 kPa. If the turbine
produces 110 kW fi d th exhaust t
    d           kW, find the h t temperature ( d quality if saturated).
                                             t (and          lit     t t d)


   Control Volume: Turbine,
   Steady state process, adiabatic turbine q=0,
   Assume no change in kinetic or potential energy.
   The energy equation then reduces to
           gy q
            1 2             1 2
    q + hi + Vi + gZi = he + Ve + gZe + w
            2               2
   specific work: w = 110/0.25 = 440 kJ/kg
    h1 = h2 = h3 + w = 2927.2 kJ/kg
   h3 = 2927.22 - 440 = 2487.22 kJ/kg
   h < hg
   2487.22 = 191.81 + x3 × 2392.82
   x3 = 0.9593, T = 45.81°C
                                                                              BITS Pilani, Pilani Campus
Turbine
A steam turbine (adiabatic) receives water at 15 MPa, 600°C at
  a rate of 100 kg/s, shown in Fig In the middle section 20 kg/s
                kg/s           Fig.
  is withdrawn at 2 MPa, 350°C, and the rest exits the turbine
  at 75 kPa, and 95% quality. Assuming no heat transfer and
  no changes in kinetic energy, find the total turbine power
  output.




                                                      BITS Pilani, Pilani Campus
A steam turbine (adiabatic) receives water at 15 MPa, 600°C at a rate of 100
kg/s, shown in Fig. In the middle section 20 kg/s is withdrawn at 2 MPa,
350°C, and the rest exits the turbine at 75 kPa, and 95% quality. Assuming no
heat transfer and no changes in kinetic energy, find the total turbine power
                           g                  gy,                      p
output.

m1 = m2 + m3
&      &     &
 &       &
m1h1 = WT + m2 h2 + m3 h3
            &       &
 from t bl h1 = 3582 .3 kJ / kg , h 2 = 3136 .96 kJ / kg
 f    table
 h 3 = h f + x 3 h ffg = 384 . 36 + 0 . 95 × 2278 . 59
 = 2549 . 02 kJ / kg

    &
    WT = m 1 h1 − m 2 h 2 − m 3 h 3 = 91 ,569 .2 kW
         &        &         &

                                                                                BITS Pilani, Pilani Campus
Compressor

Compressors, as well as pumps are devices used to
   p       ,            p p
  increase the pressure of a fluid. Work is supplied to these
  devices from an external source through a rotating shaft
                                                     shaft.

A compressor is capable of compressing the gas to very
  high pressures.

Pumps work very much like compressors except that they
  handle liquids instead of gases.



                                                    BITS Pilani, Pilani Campus
Compressor




             BITS Pilani, Pilani Campus
Compressor




             BITS Pilani, Pilani Campus
Compressor




             BITS Pilani, Pilani Campus

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Thermodynamics lecture 12

  • 1. BITS Pilani Pilani Campus Lecture 12 – FIRST LAW ANALYSIS FOR FIRST- A CONTROL VOLUME
  • 2. Throttling valve Throttling valves are any kind of flow-restricting devices g y g that cause a significant pressure drop in the fluid. The pressure drop in the f fluid is often accompanied by a large f drop in temperature, and for that reason throttling devices are commonly used in refrigeration and air-conditioning applications. BITS Pilani, Pilani Campus
  • 3. Throttling valve BITS Pilani, Pilani Campus
  • 4. Throttling valve Helium is adiabatically throttled from 1.2 MPa, y 20°C, to a pressure of 100 kPa. The diameter of the exit pipe is so much larger than the inlet pipe that the inlet th t th i l t and exit velocities are equal. Fi d d it l iti l Find the exit temperature of the helium and the ratio of the pipe diameters diameters. BITS Pilani, Pilani Campus
  • 6. Helium is adiabatically throttled from 1.2 MPa, 20°C, to a pressure of 100 kPa. The diameter of the exit pipe is so much larger than the inlet pipe that the inlet and exit velocities are equal. Find the exit temperature of the helium and the ratio of the pipe diameters. 1 2 1 2 q + hi + Vi + gZi = he + Ve + gZe + w 2 2 ⇒ hi = he Assuming for Helium as an ideal gas ⇒ Ti = Te = 20 C o Also please note here that for Helium specific heat remains constant (Fig. 5.17) A iV i A eV e o Now mi = & = m &e = vi ve Ai di ∴ = = P e P i = 0 . 288683 Ae de BITS Pilani, Pilani Campus
  • 7. Turbine A rotary steady-state machine whose purpose is to produce shaft work ( power on rate basis) at the expense of energy of flowing fluid. Eg. Steam turbine, Gas turbine, Hydraulic turbine. Normally turbine process is adiabatic. BITS Pilani, Pilani Campus
  • 8. Turbine BITS Pilani, Pilani Campus
  • 9. Turbine BITS Pilani, Pilani Campus
  • 10. Turbine A small adiabatic turbine, shown in Fig., is operated at part l d b th ttli a 0 25 k / steam supply at t t load by throttling 0.25 kg/s t l t 1.4 MPa, 250°C down to 1.1 MPa before it enters the turbine and the exhaust is at 10 kPa If the kPa. turbine produces 110 kW, find the exhaust temperature (and quality if saturated). p ( q y ) BITS Pilani, Pilani Campus
  • 11. A small adiabatic turbine, shown in Fig., is operated at part load by throttling a 0.25 kg/s steam supply at 1.4 MPa, 250°C down to 1.1 MPa before it enters the turbine and the exhaust is at 10 kPa. If the turbine produces 110 kW fi d th exhaust t d kW, find the h t temperature ( d quality if saturated). t (and lit t t d) Control volume: throttle valve Steady state process, q = 0 and w = 0. single stream entry and exit Assume no change in kinetic or p g potential energy. gy The energy equation then reduces to 1 2 1 2 q + hi + Vi + gZi = he + Ve + gZe + w Z Z 2 2 h1 = h2 = 2927.22 kJ/kg BITS Pilani, Pilani Campus
  • 12. A small adiabatic turbine, shown in Fig., is operated at part load by throttling a 0.25 kg/s steam supply at 1.4 MPa, 250°C down to 1.1 MPa before it enters the turbine and the exhaust is at 10 kPa. If the turbine produces 110 kW fi d th exhaust t d kW, find the h t temperature ( d quality if saturated). t (and lit t t d) Control Volume: Turbine, Steady state process, adiabatic turbine q=0, Assume no change in kinetic or potential energy. The energy equation then reduces to gy q 1 2 1 2 q + hi + Vi + gZi = he + Ve + gZe + w 2 2 specific work: w = 110/0.25 = 440 kJ/kg h1 = h2 = h3 + w = 2927.2 kJ/kg h3 = 2927.22 - 440 = 2487.22 kJ/kg h < hg 2487.22 = 191.81 + x3 × 2392.82 x3 = 0.9593, T = 45.81°C BITS Pilani, Pilani Campus
  • 13. Turbine A steam turbine (adiabatic) receives water at 15 MPa, 600°C at a rate of 100 kg/s, shown in Fig In the middle section 20 kg/s kg/s Fig. is withdrawn at 2 MPa, 350°C, and the rest exits the turbine at 75 kPa, and 95% quality. Assuming no heat transfer and no changes in kinetic energy, find the total turbine power output. BITS Pilani, Pilani Campus
  • 14. A steam turbine (adiabatic) receives water at 15 MPa, 600°C at a rate of 100 kg/s, shown in Fig. In the middle section 20 kg/s is withdrawn at 2 MPa, 350°C, and the rest exits the turbine at 75 kPa, and 95% quality. Assuming no heat transfer and no changes in kinetic energy, find the total turbine power g gy, p output. m1 = m2 + m3 & & & & & m1h1 = WT + m2 h2 + m3 h3 & & from t bl h1 = 3582 .3 kJ / kg , h 2 = 3136 .96 kJ / kg f table h 3 = h f + x 3 h ffg = 384 . 36 + 0 . 95 × 2278 . 59 = 2549 . 02 kJ / kg & WT = m 1 h1 − m 2 h 2 − m 3 h 3 = 91 ,569 .2 kW & & & BITS Pilani, Pilani Campus
  • 15. Compressor Compressors, as well as pumps are devices used to p , p p increase the pressure of a fluid. Work is supplied to these devices from an external source through a rotating shaft shaft. A compressor is capable of compressing the gas to very high pressures. Pumps work very much like compressors except that they handle liquids instead of gases. BITS Pilani, Pilani Campus
  • 16. Compressor BITS Pilani, Pilani Campus
  • 17. Compressor BITS Pilani, Pilani Campus
  • 18. Compressor BITS Pilani, Pilani Campus