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PREPARED BY:
Asst. Prof. GAURANG PRAJAPATI
CIVIL DEPARTMENT
TEE BEAM
Mahatma Gandhi Institute Of
Technical Education
& Research Centre, Navsari (396450)
ELEMENTARY STRUCTURAL DESIGN
6TH SEMESTER
CIVIL ENGINEERING
INTRODUCTION
 T-beam:
 If the flange projections are on either side of the rectangular web or rib ,the
resulting cross section resembles the T-shape and hence is called T-beam.
 L-beam:
 If the flange projections is on one side ,the resulting cross section resembles an
inverted ‘L’ and is termed as L-beam.
ESD
2160607
2
TEE BEAM
CONCEPT OF T-BEAM
ESD
2160607
3
TEE BEAM
Tee beam = Singly Reinforced Rectangular beam + Slab portion
= (bw × D) + (bf- bw) × df
STRESS STRAIN DIAGRAM FOR TEE BEAM
ESD
2160607
4
TEE BEAM
STRESS STRAIN DIAGRAM FOR TEE BEAM
 Notation of diagram:
ESD
2160607
5
TEE BEAM
bf = Width of flange C1 = Force of Compression (in Concrete)
= 0.36 fck bw xu
Df = Depth of flange C2 = Force of Compression (in slab)
= 0.446 fck (bf – bw) Df
bw = Width of web T = Force of Tension (in Steel) = 0.87 fy Ast
d = Eff. Depth of beam Z1 = Lever Arm = d – 0.42 xu
D = overall depth of beam Z2 = d -
𝐷
2
Ast = Area of Steel fck = Compressive Strength of Conc.
xu = Depth of Neutral Axis (N.A.) fy = Yield Strength of Steel
NEUTRAL AXIS:
ESD
2160607
6
TEE BEAM
 Position of Neutral Axis (N.A):
Fc = Force of Total Compression
= 0.36 fck bf Df
Ft = Force of total Tension
= 0.87 fy Ast
 Conditions:
 If Fc > Ft N.A lies in the flange (xu < Df)
 If Fc < Ft N.A lies in the flange (xu > Df)
 If Fc = Ft N.A lies in the flange (xu = Df)
NEUTRAL AXIS:
ESD
2160607
7
TEE BEAM
 Depth of N.A (xu)
o If Fc > Ft N.A lies in the flange (xu < Df)
C1 + C2 = T
0.36 fck bw xu + 0.446 fck (bf – bw) Df = 0.87 fy Ast …..(A)
xu = ____mm
o If Fc < Ft, N.A lies in the web (xu > Df)
but if xu = _____mm ≯ Df,
put Df = yf in equation (A)
where yf = 0.15 xu + 0.65 Df
Now, find new xu = ____mm
FLANGE WIDTH:
ESD
2160607
8
TEE BEAM
bf =
𝒍 𝟎
𝟔
+ bw + 6 Df
IS 456
Clause No.: 23.1.2
Page No.: 36, 37
 Flange width (bf )of the T beams
 Flange width (bf )of the L beams
bf =
𝒍 𝟎
𝟏𝟐
+ bw + 3 Df
IS 456
Clause No.: 23.1.2
Page No.: 36, 37
Where
𝑙0 = distance between points of zero moments in the beam (eff. Span)
Df = depth of flange
Bw = width of web
CONCEPTS OF T BEAM ANALYSIS
ESD
2160607
9
TEE BEAM
CONCEPTS OF T BEAM ANALYSIS
ESD
2160607
10
TEE BEAM
Tee beam

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Tee beam

  • 1. PREPARED BY: Asst. Prof. GAURANG PRAJAPATI CIVIL DEPARTMENT TEE BEAM Mahatma Gandhi Institute Of Technical Education & Research Centre, Navsari (396450) ELEMENTARY STRUCTURAL DESIGN 6TH SEMESTER CIVIL ENGINEERING
  • 2. INTRODUCTION  T-beam:  If the flange projections are on either side of the rectangular web or rib ,the resulting cross section resembles the T-shape and hence is called T-beam.  L-beam:  If the flange projections is on one side ,the resulting cross section resembles an inverted ‘L’ and is termed as L-beam. ESD 2160607 2 TEE BEAM
  • 3. CONCEPT OF T-BEAM ESD 2160607 3 TEE BEAM Tee beam = Singly Reinforced Rectangular beam + Slab portion = (bw × D) + (bf- bw) × df
  • 4. STRESS STRAIN DIAGRAM FOR TEE BEAM ESD 2160607 4 TEE BEAM
  • 5. STRESS STRAIN DIAGRAM FOR TEE BEAM  Notation of diagram: ESD 2160607 5 TEE BEAM bf = Width of flange C1 = Force of Compression (in Concrete) = 0.36 fck bw xu Df = Depth of flange C2 = Force of Compression (in slab) = 0.446 fck (bf – bw) Df bw = Width of web T = Force of Tension (in Steel) = 0.87 fy Ast d = Eff. Depth of beam Z1 = Lever Arm = d – 0.42 xu D = overall depth of beam Z2 = d - 𝐷 2 Ast = Area of Steel fck = Compressive Strength of Conc. xu = Depth of Neutral Axis (N.A.) fy = Yield Strength of Steel
  • 6. NEUTRAL AXIS: ESD 2160607 6 TEE BEAM  Position of Neutral Axis (N.A): Fc = Force of Total Compression = 0.36 fck bf Df Ft = Force of total Tension = 0.87 fy Ast  Conditions:  If Fc > Ft N.A lies in the flange (xu < Df)  If Fc < Ft N.A lies in the flange (xu > Df)  If Fc = Ft N.A lies in the flange (xu = Df)
  • 7. NEUTRAL AXIS: ESD 2160607 7 TEE BEAM  Depth of N.A (xu) o If Fc > Ft N.A lies in the flange (xu < Df) C1 + C2 = T 0.36 fck bw xu + 0.446 fck (bf – bw) Df = 0.87 fy Ast …..(A) xu = ____mm o If Fc < Ft, N.A lies in the web (xu > Df) but if xu = _____mm ≯ Df, put Df = yf in equation (A) where yf = 0.15 xu + 0.65 Df Now, find new xu = ____mm
  • 8. FLANGE WIDTH: ESD 2160607 8 TEE BEAM bf = 𝒍 𝟎 𝟔 + bw + 6 Df IS 456 Clause No.: 23.1.2 Page No.: 36, 37  Flange width (bf )of the T beams  Flange width (bf )of the L beams bf = 𝒍 𝟎 𝟏𝟐 + bw + 3 Df IS 456 Clause No.: 23.1.2 Page No.: 36, 37 Where 𝑙0 = distance between points of zero moments in the beam (eff. Span) Df = depth of flange Bw = width of web
  • 9. CONCEPTS OF T BEAM ANALYSIS ESD 2160607 9 TEE BEAM
  • 10. CONCEPTS OF T BEAM ANALYSIS ESD 2160607 10 TEE BEAM