This document discusses how to find the surface areas and volumes of various solid figures. It explains how to calculate the surface area of a cuboid by finding the areas of the six rectangles that make up its surfaces, which equals 2(lb+bh+hl). It also describes how to calculate the curved surface area of a cone by dividing a paper model into small triangles and summing their areas, which equals 1/2*πrL. Finally, it lists the formulas for finding the surface areas and volumes of common 3D shapes like cubes, cylinders, cones, spheres, and hemispheres.
this is about surface area and volume to help the students to do there projects or ppts and insure that u can also see this and make another like this so all the best of this ppt for who al cannot do on there own so enjoy this thing here .... and thanks for watching :) ..
this is about surface area and volume to help the students to do there projects or ppts and insure that u can also see this and make another like this so all the best of this ppt for who al cannot do on there own so enjoy this thing here .... and thanks for watching :) ..
cube cuboid and cylinder is found .here you can learn surface area and volume of these 3 dimensional figures.it also includes basic information on the basic properties of these figures
about daliy life using math in this ppt you will learn about volume and suraface area etc.3d shapes and many more new thing you can learn from this ppt
Areas related to Circles - class 10 maths Amit Choube
This a ppt which is based on chapter circles of class 10 maths it is a very good ppt which will definitely enhance your knowledge . it will also clear all concepts and doubts about this chapter and its topics
Surface area of a cuboid and a cube,cylinder,cone,sphere,volume of cuboid,cyl...kamal brar
surface area of a cuboid and a cube,surface area of a right circular cylinder,surface area of right circular cone,surface area of a sphere,volume of cuboid,volume of cylinder,volume of right circular cone and volume of sphere.powerpoint presentation
cube cuboid and cylinder is found .here you can learn surface area and volume of these 3 dimensional figures.it also includes basic information on the basic properties of these figures
about daliy life using math in this ppt you will learn about volume and suraface area etc.3d shapes and many more new thing you can learn from this ppt
Areas related to Circles - class 10 maths Amit Choube
This a ppt which is based on chapter circles of class 10 maths it is a very good ppt which will definitely enhance your knowledge . it will also clear all concepts and doubts about this chapter and its topics
Surface area of a cuboid and a cube,cylinder,cone,sphere,volume of cuboid,cyl...kamal brar
surface area of a cuboid and a cube,surface area of a right circular cylinder,surface area of right circular cone,surface area of a sphere,volume of cuboid,volume of cylinder,volume of right circular cone and volume of sphere.powerpoint presentation
Maths project surface area and volume by chirag jain class ix a roll no. 17Chirag Jain
This is a presentation of the chapter Surface Area and Volume made by me. It includes the derivation of almost all formulas which are explained in NCERT of class IX
Principles of measurement including accuracy, precision and significant figures.
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Surface area is the sum of total exposed area of a three dimensional solid object. Its unit can be in the form cm2, m2 etc.
Volume is the amount of space occupied by an object. Its unit can be cm3, m3, etc.
topics -
1. Cube, Cuboid and Cylinder
Cuboid: A cuboid is the solid shape which has six rectangle faces at right angles to each other.
Cube: A cube is a special form of cuboid which is bounded by six equal square faces.
Right Circular Cylinder: A solid obtained by revolving a rectangular lamina about one of its sides, is called as Right Circular Cylinder.
2. Cone and Frustum
Cone: A cone is a three-dimensional geometric shape that tapers smoothly from a flat circular base to a point called vertex.
We can also define it as, “A solid obtained by revolving a right angled triangular lamina about
any side (except hypotenuse) is a right circular cone.”
Frustum: If the cone is cut off by a plane parallel to the base not passing through vertex then we get the lower base portion as a frustum of cone.
3. Sphere and Hemisphere
Hemisphere: A plane passing through the center of a sphere divides sphere into two equal parts. Each part is called a hemisphere.
4. Combination of solids
In real life we come across different objects which are a combination of many shapes like cube cuboid, cylinder, sphere, cone etc. In our previous topics we have seen how to find the areas and volumes of simple objects. Now we will look at a few examples on how to find the areas and volumes of combination of solids.
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2. Wherever we look, usually we see solids. So far
, in all our study, we have been dealing with figures that can be easily drawn on our notebooks
Or blackboards . These are called plane figures.
We have understood what rectangles, squares,
Cylinders and circles are. What we mean by their
Perimeters, and areas and how we can find them
We have learnt these in earlier classes it would be I
Intresting to see what happens if we cut out many
Of these plane figure of the same shape and size
From cardboard sheet and stack them up in a
Vertical file. By this process , we shall obtain some
3. Solid figures such as a cuboid a cylinder a cube
e.t.c. u have shall now learn
To find the surface area and volume of
cuboiods and cylinders in detail and
Extend these studies to some other solids such
as cones and spheres.
4.
5. As we know that if we have to make a
cuboid we
Want a bottom, four walls and a
top, therefore
Six rectangular pieces to cover the
complete outer
Surface of cuboid.
If we take the length of cuboid as ‘l’
breadth as ‘b’
And height as ‘h’, then the figure with these
Dimensions would be like as the shape.
So the sum of the area of six rectangles is:
6. Area of rectangle 1= (lxh)
+
Area of rectangle 2= (lxb)
+
Area of rectangle 3= (lxh)
+
Area of rectangle 4= (lxb)
+
Area of rectangle 5= (bxh)
+
Area of rectangle 6= (bxh)
= 2(lxb)+2(bxh)+2(lxh)
= 2(lxb)+(bxh)+(hxl)
= 2(lb+bh+hl)
This give us:
surface area of cuboid = 2(lb+bh+hl)
7. Cut out a neatly paper cone that does not have any overlapped paper.
Straight along its side and opening its out, to see the shape of the
paper
That forms a surface of cone. The line along with you cut the cone is the
Slant height of the cone which is represented by the ‘l’. It look like a
part of
A round cake.
If you now bring the side marked ‘a’ and ‘b; at the tip together, you can
see
That the curved portion will form the circular base of the cone.
If the paper line 1 is now cut into hundred of little pieces along the line
Drawn from point ‘o’, each cut portion is almost a small triangle, whose
Height is the slant height ‘l’ of the cone.
8. Now the area of each triangle
= 1/2xbase of each triangle
So, the area of the entire piece of paper= sum of all the area
= 1/2b1l+1/2b2l+1/2b3l+……
= 1/2xlxlenghth of entire curved boundary
(as b1+b2 +b3 +…. Makes up the curved portion)
But the curved portion of the figure make up the perimeter of the base of the
Cone and the circumference of the base of the cone = 2x22/7xR
So the curved surface area of the cone
= 1/2xlx2x22/7xR
9. •Surface area of the cuboid= 2(lb+bh+hl)
•Surface area of the cube = 6a2
•Curved surface area of the cylinder= 2x22/7xRH
•Total surface area of the cylinder= 2x22/7xR(h+r)
•Curved surface area of the cone= 22/7xRL
•Volume of the cuboid= LxBxH
•Volume of the cube= a3
•Volume of cylinder= 22/7xR2H
10. •Volume of the cone= 1/3x22/7xR2H
•Volume of the sphere= 4/3x22/7xR3
•Volume of the hemisphere= 2/3x22/7xR3
•Curved surface area of the cuboid= 2(l+b)h
•Curved surface area of the cube= 4a2