This document provides biographical information about the statistician Ronald Fisher: - Fisher was born in 1890 in London, England and had a happy childhood until his father lost his business when Fisher was 14. - He made significant contributions to statistics and developed concepts like maximum likelihood estimation and the analysis of variance. - Fisher spent time in England and Australia in his career and made groundbreaking advances in the field of statistics.

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2. AKNOWLEDGEMENT
I Nikhil Gogate & my friend Navin Patle gratefully acknowledges
for making this PowerPoint presentation informative and attractive
Special thanks to MR. MAHESH GOUR
(MATHEMATICS TEACHER)
For his valuable guidance and his kind support
We also acknowledge to
MR.C.B.PATLE(PRINCIPAL OF GPS)
We would like to give special thanks to all mathematics teacher from
primary high school who guided us.

4. NAME RONALD FISHER
Born:17 February 1890
East Finchley, London, England
Died :29 July 1962 (aged 72)
Adelaide, Australia
Residence :England
Australia
Nationality :British
Fields :Statistics

5. Fisher was born in East Finchley in
London, England, to George and Katie
Fisher. His father was a successful fine
arts dealer. He had a happy childhood,
being doted on by three older sisters, an
older brother, and his mother, who died
when Fisher was 14. His father lost his
business in several ill-considered
transactions only 18 months later,
according to the biography by Fisher's
daughter, Joan. Joan Fisher's biography
is the main source of information on her
father's early life; it was published under
her married name and with the
statistical advice of her husband, George
E. P. Box.

6. Statistics is the study of the collection, organization, analysis, and
interpretation of data.It deals with all aspects of this, including the planning of
data collection in terms of the design of surveys and experiments.
DATA
PRIMARY DATA: The data collected by collector directly is called as
primary data
SECONDARY DATA: The data collected by some one and used by some
else is called as secondary data
CENTRAL TENDENCY:
1) MEAN
2) MEDIAN
3) MODE
In this class we will learn about mean only

7. In mathematics and statistics, the arithmetic mean, or simply the
mean or average when the context is clear, is the central tendency of
a collection of numbers taken as the sum of the numbers divided by
the size of the collection. The collection is often the sample space of an
experiment.
The term "arithmetic mean" is preferred in mathematics and
statistics because it helps distinguish it from other means such as
the geometric and harmonic mean.
USES
1.Mean is used measure GDP(gross domestic product)
2.In school to find average mark of student or percentage
3.In cricket also mean used evaluate average of batsman.

8. 1.ARTHMATIC MEAN
OF UNGROUPED DATA
a. When frequency is not given
Where:
=
n = no. of observation

9. 1.Neeta and her 4 friends secured 65, 78, 82,
94 and 71 marks in a test.
Find average of their marks
Sol:
Arithmetic mean =
= 65+78+82+94+71
5
Hence , average=78

10. b. When frequency given :

11. 1.CALCULATE THE MEAN
VARIABLE 5 6 7 8 9
FREQUENY 4 8 14 11 3
Sol: x f fx
5 4 20
6 8 48
7 14 98
8 11 88
9 3 27
total N=40 281

12. Mean = = 281
40
= 7.025

13. FINDING MEAN BY DIFERENT METHODS:
1.DIRECT METHOD
2.ASSUMED METHOD
3.STEP DEVIATION METHOD

14. FORMULAE :
MEAN =
=
1
N
WHERE,
N=f1+f2+f3+….+fn

15. EXAMPLE:
1. Mid-values of class interval are given with their
frequencies are given .find there mean by direct
method
Mid-values 2 3 4 5 6
frequencies 49 43 57 38 13
Sol :
Mid-Values frequency fixi
2 49 98
3 43 129
4 57 228
5 38 190
6 13 78
total N= =200 =723

16. By direct method
1
N
Mean =
= 723
200

17. Formulae=mean=a+
WHERE,
di= xi-a(deviation)
{DEVIATION: deviation is difference between mid-value or
class interval with mean or assumed mean }

18. CALCULATE THE MEAN OF FOLLOWING
CLASS
INTERVAL
50-60 60-70 70-80 80-90 90-100
FRQUENCY 8 6 12 11 13
Sol: let assumed mean be 75 as per data i.e .a=75
Class Frequency Mid
value
di=xi-75 Fidi
50-60 8 55 -20 -160
60-70 6 65 -10 -60
70-80 12 75 0 0
80-90 11 85 10 110
90-100 13 95 20 260
=50 =150

19. Mean = a + h
WHERE ,
ui= xi-a , i=1,2,3,4,………………,n
h

20. TO FIND CONCENTRATION SO2 IN THE AIR (IN PPM),THE COLLECTED FOR
THIRTY LOCALITIES IN A CERTAIN CITY AND IS PRESENTED BELOW :
CONCENTRATION OF SO2 FREQUENCY
0.00-0.04 4
0.04-0.08 9
0.08-0.12 9
0.12-0.16 2
0.16-0.20 4
0.20-0.24 2
FIND THE MEAN CONCENTRATION OF SO2 IN AIR :

21. Sol : let assumed mean be 0.10
a =0.10
Conc. of
SO2
frequency Mid
values
Ui=xi-0.10
0.04
fiui
0.00-0.04 4 0.02 -2 -8
0.04-0.08 9 0.06 -1 -9
0.08-0.12 9 0.10 0 0
0.12-0.16 2 0.14 1 2
0.16-0.20 4 0.18 2 8
0.20-0.24 2 0.22 3 6
=30 =-1
by deviation method
Mean = a + h

22. = 0.10 +(-1) 0.04
30
=0.10-0.0013
=0.0987
=0.099 ppm