Jupiter And Mercury Motions Analysis

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Jupiter And Mercury Motions Analysis
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –5th
September 2021
Abstract
Paper Arguments
- The paper provides 2 basic arguments
- (1st
Argument)
- The Paper disproves Newton Theory of The sun mass gravity and proves that the
solar planets motions can't be independent motions from one another but each
planet motion depends on other planets motions.
- This discussion concludes that, the solar system distances be created in a network
form, integrated together in one geometrical design.
- The argument conclusion is (The solar planet move one unified general motion)
- The 1st
Argument Depends On (Jupiter Motion Analysis)
- (2nd
Argument)
- The Paper claims that the solar planets motions be accompanying with a light
beam motion which provides the required energy for the planets and their distances
creation (because matter is created of energy and space is created of energy)
- The light motion accompanying with the solar planets motions cause the planets to
move one unified general motion.
- The 2nd
Argument Depends On (Mercury Motion Analysis)
Please scan the figure (ORCID)

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Paper Contents
Subject Page No.
1- Introduction 3
2- Methodology 6
3- Jupiter Motion Data Analysis 9
3-1 Preface 10
3-2 Jupiter Motion Data Analysis 11
3-3 The 3 Planets Motions Analysis 18
3-4 Mercury And Mars Cycles Analysis 23
3-5 Jupiter Motion Data Analysis (continued) 31
4-The Solar System Distances Be Created In A Network Form 38
4-1 Preface 39
4-2 The Continuum effect Through the Solar System Distances 41
4-3 The Solar System Distances Distribution 46
4-4 The Solar System Distances Dependency On One Another 53
5-Mercury Motion Analysis 55
5-1 Preface 56
5-2 The Theory basic Ideas 57
5-3 Light Beam (1.16 mkm/s) Existence Proves Discussion 59
5-4 Jupiter Orbital Circumference Analysis 95
6- The Solar Planets Motions Depend On Different Rates of Time 113
6-1 Preface 114
6-2 Earth And Pluto Rate Of Time 115
6-3 Mercury Motion Rate Of Time 124
6-4 Saturn Motion Rate Of Time 127
6-5 Uranus And Jupiter Rate Of Time 129
7- Planets Unified General Motion 130
7-1 The Planets Unified General Motion Description 131
7-2 The Solar Planets Motions Are Complementary One Another 132
7-3 The Solar Planets Move An Unified Motion (A Team Motion) 137
8- The Sun Age Historical Proves 142
8-1 The Sun Circles The Earth 143
8-2 The Rate (1.0725) 144
8-3 The Sun Diameter Analysis 148
8-4 The Sun Rays Analysis 151
9- Mercury Jupiter Distance Analysis 156
9-1 The Main Idea 157
9-2 Venus Jupiter Distance Analysis 162
9-3 Jupiter and Pluto Motions For The Distance 720.7 mkm 170
9-4 Planets Motions Rates of Time 173
9-5 Planets Motions Interaction 178
9-6 Mars Motion For The Distance 720.7 mkm 193
10- The Solar Planets Motions Analysis 205
10-1 Preface 206
10- 2 The Equal Distances Method 207
10-3 The Inner And Outer Planets Motions Be Distinguished 213
Appendix No.1 The Solar System Equal Distances List 222
References and Biography 224

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1-Introdcution
- Jupiter Orbital Period =4331 days = 2π x 687 days (Mars Orbital Period)
- This data is one noticeable data I have asked about it many times before, because
no clear answer for the question (Why?)
- What's the relationship between Jupiter motion and mars motion based on which
this relationship be produced…
- Why Jupiter Orbital Period = Mars Orbital Period x 2π?
- The answer usually be (Pure Coincidences of numbers)!
- But
- The Question Is So Deep Than The Superficial Answer.
- The question is produced based on a completely different vision of the solar
system motion contradicts and disproves Newton Vision inherited by his theory of
the sun mass gravity.
- The solar planets don't move by the sun mass gravity, the idea is an imaginary one
- The Solar Planet Motion can't be independent from other planets motions
- Simply
- The solar system motion facts contradict Newton Theory of The Sun mass gravity
and the planet motion independency Concept
- The ideas simply are mistaken
- The relationship between Jupiter orbital period and mars orbital period discovered
a deep interaction of the planets motions which create it
- What does this paper try to do?
- We analyze 3 planets motions which are (Mercury – Mars – Jupiter) to prove that
the 3 planets move relative to one another as gears in one machine. Their motions
be integrated together into one unified general motion disproves the planet motion
independency concept and Newton Theory of The sun mass gravity.
- Shortly
- The Nature Of Motion Is Different

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- Newton Was Mistaken
- How the motion be different from what Newton had described?
- Because
- The 3 planets depend on each other data in their motion. let's see examples in
following
- Example no. (1)
- Jupiter orbital period =4331 mkm. But Jupiter moves during (687 day = Mars
orbital period) a distance = 778.6 mkm = Jupiter orbital distance
- Example no. (2)
- Jupiter (13.1 km/s) moves during 24.6 hours (Mars rotation period) a distance =
1.16 mkm
- But
- 4900 mkm (Jupiter Orbital Circumference) = 1.16 mkm x 4224
- Where
- 4222.6 hours = Mercury Day Period (very near to 4224)
- If the data be produced by pure coincidences of numbers, we would to consider
tenths of data as pure coincidences results – no clear logic behind such thinking
- The straight logic tells that, the 3 planets motions have interaction with one
another and this interaction causes the planets motions data to be created taking
into consideration the other planets motions data and based on that no
independency of motion can be supposed…
- I try to show that, the 3 planets motions data analysis gives clearly another vision
for the solar system contradicting Newton Theory of the Sun mass gravity.
- The next question is
- Why and how these 3 planets motions be integrated in one unified motion or create
between one another motions interaction?

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- This question we should answer in this paper discussion
- Let's take a look on the paper contents
- Point no.(3) Jupiter Motions Data Analysis
- In this point we analyze Mercury, Mars And Jupiter Motions Data
- Point no.(4) The Solar System Distances Be Created In A Network Form
- In this point we try to prove that the distances be created in a network form
- Point no.(5) Mercury Motion Analysis
- In this point we provide one more reading for the planets motions data
- More interesting points are inserted in the paper contents

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2-Methodology
- I use the planets data analysis to discover the planets motions laws
- This method provides good comparisons between The Solar Planets Motions Data
and the theories which try to explain These Planets Motions.
- The planets data analysis is so useful method because it protects greatly from the
imagination.
- By thinking approach we can find suitable tests for the solar system motion
theories, and based on that, let's test Newton Theory of the sun mass gravity.
- The sun mass gravity tells us that,
- The solar planet moves depending on the sun mass gravity independently from all
other planets motions. By that Each Planet Motion Data is almost created
independent from all other planets motions data. this idea we understood simply
from the planet motion independency concept.
- We don't need to discuss the independency concept here but we need to test if the
planets motions data supports it. Because if it doesn't that may refer to another
conclusion tells (Planet Motion Independency Concept Is An Imaginary Idea)
- Let's discuss an example in following:
Example No. (1)
(I)
- 778.6 mkm (Jupiter Orbital Distance) = 1.16 x 671 mkm (Jupiter Venus Distance)
- 720.7 mkm (Jupiter Mercury Distance) = 1.16 x 629 mkm (Jupiter Earth Distance)
- 550.7 mkm (Jupiter Mars Distance) =1.16 x π x149.6 mkm (Earth orbital distance)
- (Max error 1%)
- Shortly
- The Distances Between Jupiter On One Side And Mercury, Venus, Earth And
Mars On The Other Side, All These Distances Are Rated With The Rate (1.16)

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Example No. (1)
(II)
- 778.6 mkm (Jupiter Orbital Distance) =1.072 x 720.7mkm (Jupiter Mercury Distance)
- 720.7 mkm (Jupiter Mercury Distance) =1.072 x 671 mkm (Jupiter Venus Distance)
- 671 mkm (Jupiter Venus Distance) =1.072 x 629 mkm (Jupiter Earth Distance)
- 629 mkm (Jupiter Earth Distance) = (1.072)2
x 550.7 mkm (Jupiter Mars Distance)
- The previous data tries to explain one feature of Jupiter Motion.
- We deal with the same 5 distances which are
- Jupiter Orbital Distance = 778.6 mkm
- Jupiter Mercury Distance = 720.7 mkm
- Jupiter Venus Distance = 671 mkm
- Jupiter Earth Distance = 629 mkm
- Jupiter Mars Distance = 550.7 mkm
- These 5 distances are rated with each other based on the rates (1.16) and (1.0725)
- The question is why these 5 distances be rated with (1.0725) and (1.16)?!
- Because these distances are created based on one another by using one geometrical
design.
- (Imagine we a have a square, each dimension in this square be in proportionality
with this square data and by that all dimensions be rated with one another
geometrically)…
- The 5 distances be rated with one another because they are created as dimensions
in one geometrical design.
- I want to say these distances can't be independent distances from one another. they
are created by using one geometrical system…
- The direct conclusion tells that (Planet Motion Can't Be Independent)…
- I try to show that
- Newton Simple Idea is an imaginary one because

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- The solar system is so complex machine, and the simple vision without data
analysis gives us no facts. The solar system is a building of Gold made based on a
complex geometrical design.
- The provided data is an example for hundreds similar data. each part of the solar
system design refers to a complex machine.
- The direct question is (Why Jupiter distances are rated with one another by these 2
rates 1.0725 and 1.16)??
- The answer is not a simple one
- The rate 1.0725 controls 40% of all distances in the solar system (appendix no. 1
provides a list for these distances)
- Why this rate is used between 40% of all distances? This question still needs
answer but the using is a fact can't be disproved.
- Planets data analysis put planet motion data in comparison with the theory tri to
explain it, by that, we can understand much better both the planet motion data and
the theory which tries to explain it.

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3- Jupiter Motion Data Analysis
3-1 Preface
3-2 Jupiter Motion Data Analysis
3-3 The 3 Planets Motions Analysis
3-4 Mercury And Mars Cycles Analysis
3-5 Jupiter Motion Data Analysis (continued)

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3-1 Preface
- Jupiter Motion Analysis aims to prove that,
- The solar planet motion can't be an independent motion but dependent on other
planets motions.
- Jupiter Motion analysis provides the basic argument which disproves Newton
Theory of The sun mass gravity and the planet motion independency concept

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3-2 Jupiter Motion Data Analysis
I- Data
(1)
4331 days (Jupiter orbital period) = 175.94 days (Mercury Day Period) x 24.6
(2)
4331 days (Jupiter orbital period) = 2π x 687 days (Mars orbital period)
(But 687 days x 24 h = 24.6 h (Mars rotation period) x 671)
(3)
1.16 mkm= 13.1 km/s (Jupiter Velocity) x 24.6 h x3600 s
(4)
4900 mkm (Jupiter Orbital Circumference ) = 1.13184 mkm x 4331 days
(1.1318 mkm/day Jupiter Velocity Per A Solar Day)
(5)
4900 mkm (Jupiter Orbital Circumference )= 1.16 mkm x 4224
(6)
4900 mkm = 2π x 778.6 mkm = 199.2 mkm x 24.6
(7)
2.082 mkm (Mars Motion Distance Per A Solar Day) = 1.16 mkm x 1.8

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II- Discussion
(1st
Point)
- The correct start point to understand the previous data is the equation no. (3)
- Let's start by it immediately
Equation no. (3)
- Equation no. (3) tells, Jupiter moves during (24.6 hours = Mars Rotation period) a
distance = 1.16 mkm
- This is the first important information, let's see also equation no. (5)
Equation no. (5)
- Where
- 4222.6 hours = Mercury Day Period
- The value (4224) is very near to (4222.6) and we will consider they are equal for
now and later we explain why this difference is found.
- Equation no.(5) tells, Jupiter orbital circumference is designed geometrically based
on the distance (1.16 mkm).
- That means,
- If 1 hour of Mercury Motion = 24.6 hours of Jupiter motion. Jupiter will move its
orbital circumference (4900 mkm) in a period = 4222.6 (= Mercury Day Period)
- Let's try to understand what does that mean?
- Jupiter motion by using the period (24.6 h) will pass its orbital circumference 4900
mkm in a period = 24.6 hours x 4224 (or 4222.6)
- Jupiter Motion based on this information creates a connection between Jupiter,
Mercury and Mars motions data.
- The point of discovery is that (1 hour Of Mercury Motion Be =24.6 hours Of
Jupiter Motion)

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- This discovery is just an idea we should test and prove later
- But
- We have a connection be found clearly between Jupiter, Mercury and Mars
motions data. we don't know why this connection is found.
- Let's see this connection clearly in following:
- 1.16 mkm = 13.1 km/s x 24.6 hours x 3600 sec (1)
- 4900 mkm = 1.16 mkm x 4224 (2)
- But the connection between the three planets is more deep than this explanation,
let's see the equation no. (2)
Equation no. (2)
Why (Jupiter Orbital Period) = 2π x (Mars orbital period)??
- This is another connection between Jupiter motion data and Mars motion data, and
this connection is different from the previous one!
- The data is more complex than we see now, let's see some of its depth
- 687 days (Mars Orbital Period) x 24 hours = 24.6 h (Mars rotation period) x 671
- But
- 4222.6 h (Mercury day period) = 2π x 671
- Can we understand how this data be created? there's no piece of logic to
consider this data be created independent from one another…
- But why this data be created in proportionality with one another?!

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(2nd
Point)
- Jupiter Motion Can Be Calculated Based On 2 Different Measurements
- During Earth day period (24 hours) Jupiter moves (1.13184 mkm)
- And
- During Mars rotation period (24.6 hours) Jupiter moves (1.16 mkm)
- But
- Jupiter orbital circumference (4900 mkm) is divided by (1.1318 mkm) for the
period (4331 solar days) (Jupiter orbital period) (=2π x 687 days MARS orbital
period)
- And
- Jupiter orbital circumference (4900 mkm) is divided by (1.16 mkm) for the period
(4224) (where 4222.6 h =Mercury Day Period) (And if 1hour of Mercury motion
=24.6 hour of Jupiter motion. the period will refer to MERCURY day period)
- The difference in Jupiter (2 motions) = 1.16 mkm- 1.13184 mkm=28160 km =
(2.48%)
- Notice
- Mars rotation period 24.6 h = Jupiter rotation period 9.9 h x 2.48
- Notice
- 1160000 km–466884km (Jupiter motion distance during its day period) =693116
km
- But
- (693116 km/28160 km) = 24.6

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Equation no. (2) (continued)
4900 mkm (Jupiter Orbital Circumference) = 1.16 mkm x 4224
- Mercury Day Period =4222.6 hours
- As we have discussed before
- If each one hour of Mercury Motion = 24.6 hours of Jupiter Motion, in this case
Jupiter will move its orbital circumference (4900 mkm) in a period =(4222.6
hours)
- We should notice that the value (4224) is different from Mercury Day period
(4222.6h) with (1.4 hours) – this data we should discuss later
- From Our Discussion There's One Information We Need To Insert As The Basic
On Behind.
- Let's write is as clear as possible in following…

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The Discussion Basic Information
-
- This data tells,
- Some interaction be found between Mercury, Mars and Jupiter Motions Data
- Many questions can be raised here
- But
- The main question should be the next one
- (Can These 3 Planets Motions Integrate Into One Unified Motion? Or These 3
Planets Motions Be Independent Motions From One Another?)
- The question isn't simple because
- It interests for the previous data and asks directly
- (Is The Data Created Based On The Planets Motions Or As Results For Pure
Coincidences Of Numbers?)
- Again the question isn't a simple one
- It asks directly if Newton Theory of The Sun Mass Gravity Is Mistaken
- Because
- Newton told us (Each Planet motion depends on the sun mass gravity for this
planet and by that each planet motion be independent from the other planets
motions and as a result no planet uses other planets motions data because each
planet is independent in its motion)
- The question asks why Jupiter motion uses Mars and Mercury Cycles Periods?
Does this using depend on the 3 planets motions (interaction) or the data be similar
by chance?
- Let's answer this question in the next point in which we analyze the 3 planets
motions.
687 days (Mars Orbital Period) x 2π = 4331 days (Jupiter Orbital Period) = 24.6
x 175.9 days (Mercury Day Period)
(24.6 hours = Mars Rotation Period)

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- Notice
- This discussion isn't finished…
- We have a main question around this discussion basic data… because Jupiter
motion depends on Mercury and Mars cycles periods and we don't understand any
reason for that,
- As a result we try to test the 3 planets motions data to know if Jupiter using of
Mercury and Mars Cycles Periods depend on the 3 planets motions (interaction) or
found by pure coincidences of numbers…
- When we prove that, this using is created based on motions interaction (or
geometrical mechanism of motion), we should return to this same discussion
because we should find the reason behind the 3 planets motions (interaction) if
found.
- (In addition to provide a definition for the expression "Motions Interaction")
- Because of that, the equation no. (6) is not discussed yet and also the discussed (5
equations) still need motion explanations and discussions.
- So, we keep in minds that, this discussion is not finished yet.
- But we have to test the 3 planets motions in the next point for better vision

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3-3 The 3 Planets Motions Analysis
I-Data
(The Interaction between Mercury, Mars and Jupiter)
(No. 1) (Mercury and Mars Motions)
- Mercury moves during its day period (4222.6 h.) a distance = 720.7 mkm
- Mars moves during (2802 hours) a distance = 243 mkm
- Mercury moves during (1407.6 hours) a distance = 243 mkm (error 1%)
- Mars moves during 346.6 d. a distance =720.7 mkm (Mercury Jupiter Dis.)
- Mercury moves during 346.6 d. a distance =1419 mkm (with 1433 error 1%)
- Mars moves during 687 d. a distance = 1433 mkm (Mars orbit. Circum)
- Mercury moves during 687 d. a distance =2815mkm (Mercury Uranus Dis.)
- Mars moves during 4331d. a distance = 9010mkm (Saturn orbit. Circum)
- Mercury moves during 4331d. a distance = 2815 mkm x 2π
- Mars moves during 224.7 d. a distance = π x 149.6 mkm (Earth orb. Dis)
- Mercury moves during 224.7 d. a distance = 920 mkm (with 929 error 1%)
- Mars moves during 365.25 d. a distance = π x 243 mkm (0.5%)
- Mercury moves during 365.25 d. a distance = 2 x 748 mkm
- Mars moves during 5040s. a distance= 121464 km= Saturn Diameter (+1%)
- Mercury moves during 5040s. a distance= 238896 km= 2 Saturn Diameters (-1%)
Where
1407.6 h = Mercury Rotation Period 2802 h = Venus Day Period
346.6 days = the nodal year 224.7 days = Venus orbital period
687 days = Mars Orbital Period
4331 days = Jupiter orbital period = 2π x 687 days

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(No. 2) (Mars And Jupiter Motions)
- Mars moves during 636.7 days a distance =1325 mkm= (Venus Saturn Dis.)
- Jupiter moves during 636.7 days a distance =720.7 mkm
- Mars moves during 687 d. a distance= 1433 mkm= Mars Orbital Circumference
- Jupiter moves during 687 d. a distance= 778.6 mkm= Jupiter Orbital Distance
- Mars moves during 4331d. a distance= 9010 mkm= Saturn orbital circumference
- Jupiter moves during 4331 d. a distance= 4900 mkm= Jupiter Orbital Circum.
- Mars moves during 778.6 d. a distance = 1622 mkm = Uranus Neptune Dis.
- Jupiter moves during 778.6 d a distance= 881 mkm =58 days x 15.19 mkm.
- ( 15.19 mkm = the 9 solar planets motions distances total per a solar day).
- Notice
- 2.082 mkm / day x 778.6 days = 1622 mkm = 1.1318 mkm /day x 1433 days
- Where
- 2.082 mkm /day = Mars Velocity Per A Solar Day
- 4.095 mkm /day = Mercury Velocity Per A Solar Day
- 1.13184 mkm /day = Jupiter Velocity Per A Solar Day

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(No. 3) (Mercury And Jupiter Motions)
- Mercury moves during 687 d. a distance= 2815 mkm= Mercury Uranus Distance
- Mercury moves during 1433 d. a distance =5848 mkm= Mercury Pluto Dis.
- Jupiter moves during 1433 d a distance =1622 mkm=Uranus Neptune Dis.
- Mercury moves during 4331d. a distance= 2815 mkm x 2π
- Mercury moves during 4222.6 h a distance = 720.7 mkm
- Jupiter moves during 4222.6 h a distance = 200 mkm = 629 mkm/π
- Mercury moves during 550.7 d a distance = π x 720.7 mkm (0.4%)
- Jupiter moves during 550.7 d a distance = 629 mkm (error 1%)
Please Remember,
Data Group No. (1)
- Mars moves during 687 d. a distance= 1433 mkm= Mars Orbital Circumference
- Mars moves during 4331d. a distance= 9010 mkm= Saturn orbital circumference
- Mars moves during 4331 x π d a distance= 28255 mkm= Neptune orbital circumference
Data Group No. (2)
- Mercury moves during 687 d. a distance= 2815 mkm= Mercury Uranus Distance
- Mercury moves during 4331d. a distance= 2815 mkm x 2π
Data Group No. (3)

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II-Discussion
- The planets move defined distances in defined periods of time.
- The Defined Distance means a distance is known in the solar system, as to be any
planet orbital distance or a distance between any 2 planets.
- The Defined Period Of Time means a period of any planet cycle, as 365.25 days
(Earth orbital period) or any planet orbital period. Or any planet rotation period or
any planet day period. All these periods are defined periods of time
- The argument tells that
- If the solar planets move their motions independently from one another, based on
that, the planets motions during defined periods of time should pass (random)
distances. Because these Planets are independent in their motion from one
another. (For example) Mercury motion depends on its orbital period (88 days) and
doesn't interest neither for Mars orbital period (687 days) nor for Jupiter orbital
period (4331 days) and by that, Mercury during these periods (687 days and 4331
days) should move some random distances (not defined in the solar system
distances).
- The data disproves Planet Motion Independency Concept. because the (3)
planets move defined distances in defined periods of time. These planets motions
aren't independent from one another. These motions are done based on One
Geometrical Design. And these motions be similar to Chess Board Pieces
Motions. Each Motion is calculated geometrically and be obligatory and takes into
consideration the other planets motions and their effects.

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II-Discussion (Continued)
- What's the main result we have from this analysis and discussion?
- Let’s remember why we have analyzed the 3 planet motions….
- We did that because
- Jupiter motion depends on Mercury and Mars Cycles Periods, where this
conclusions depends on one basic information let's see it again here
The Basic Information
-
- As we see
- Jupiter orbital period (4331 days) depends on Mars orbital period (687 days) and
Mercury day period (175.94 days) by using (Mars rotation period 24.6 h)
- E have asked if this basic information be produced as a result for the 3planets
motions interaction or by some pure coincidences of numbers…
- So we analyzed the 3 planets motions by using the periods (175.94 days, 687 days,
4331 days) and found that the 3 planets move defined distances in defined periods
of time ….. which tells that, these 3 planets move as 3 gears in one machine, each
planet motion depends on the other planets motion and takes into consideration
them and their effect.
- The first clear conclusion is that (Planet Motion Can't Be Independent From
Other planets Motions) (Newton Is Mistaken)
- The next question is
- Why Jupiter depends on (Mercury and Mars Cycles Periods) Specifically, Is there
any interaction between Mars and Mercury Cycles Periods? Let's answer in the
next point discussion..

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3-4 Mercury And Mars Cycles Analysis
(Point No. I) (Mercury Mars Cycles Analysis)
I-Data
(a)
4222.6 h (Mercury day period) = 671 h x 2π
And
Mars orbital period 687 days x 24 h = 671 x 24.6 h
(b)
4222.6 h (Mercury day period) = 24.7 h (Mars Day Period) x 171
(c)
1407.6 h (Mercury rotation period) = 24.6 h (Mars Rotation Period) x 57.2
(d)
4.095 mkm = 2.1429 mkm x 1.9
(e)
7 degrees = 5.1 degrees + 1.9 degrees
II-Discussion
- In this point of discussion we try to answer why Jupiter motion depends on
Mercury and Mars Cycles periods specifically
- Means,
- We try to know if the 2 planets (Mercury and Mars) Cycles Periods are related to
one another or be created in proportionality with one another and because Jupiter
motion depends on Mercury cycle that caused to depend on Mars cycle also
automatically (or vice versa).
- Because of that we analyze Mercury and Mars Cycles Periods Of Time in this
point… let's start our analysis directly

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Equation no. (a)
4222.6 h (Mercury day period) = 671 h x 2π
And
Mars orbital period 687 days x 24 h = 671 x 24.6 h
- 671 mkm =Venus Jupiter Distance
- If
- 1 mkm = 1 solar day, so this number will be = 671 days
- The data shows that, 671 is a number be used by Mercury Day Period and Mars
Rotation Period which creates a basic connection between Both Cycles
- Notice
- The used of the number (671) in the previous 2 data is found by a geometrical rule
which I still don't know.. for that reason I can't explain how this value 671 be
found in the 2 information. The value (671) simply connects between the 2 cycles
(4222.6 hours and 687 days) but the using of the value (671) be by an unknown
geometrical rule and because of that we can't catch the method by which the 2
cycles be created depending on one another.
- As a result
- The 2 cycles be created based on one another and in proportionality for each other,
but we don't how or why
- And
- Because the 2 cycles depend on each other, and because Jupiter motion depend on
Mercury Cycle that forced Jupiter to depend also on Mars Cycle

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Equation no. (b)
4222.6 h (Mercury day period) = 24.7 h (Mars Day Period) x 171
Equation no. (c)
1407.6 h (Mercury rotation period) = 24.6 h (Mars Rotation Period) x 57.2
- Where
- 170 mkm = Mercury Mars Distance (Different from 171 with error 0.6%)
- 57.9 mkm = Mercury Orbital Distance (Different from 57.2 with error 1%)
- Equation no. (b and c) provides the rates (171 and 57.2) which are very near to the
distances (170 mkm and 57.9 mkm)
- We don't understand why these distances be used as rates in these 2 data if the data
refers really to these distances…
- I can say only that, The 2 distances are related to Mercury position. One Distance
from Mercury to the sun and the other distance from Mercury to Mars while the 2
data provides Mercury and Mars cycles periods only – because of that – there's
some support for conclusion these rates (171 and 57.2) refer to the distances (170
mkm and 57.9 mkm) and they may be created based on the geometrical rule by
which the 2 planets cycles periods be created in proportionality with one another.
Notice
- The data is interesting but the understanding depends on our knowledge range
- Because, let's suppose
- (1) one hour of Mercury motion = 24.6 hours of Jupiter motion.
- (2) the solar distances be distributed based on the planets motions rates of time
- Based on that
- 2815 mkm (Mercury Uranus Distance) = 24.6 x 2 x 57.9 mkm (Mercury orbital
distance) (error 1%)
- This idea we should discuss later in details but here I try to show that, the data be
so interesting but because the required knowledge is absent we remove the data
without understanding.

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Equation no. (d)
4.095 mkm = 2.1429 mkm x 1.9
- Where
- 4.095 mkm = Mercury Motion Distance Per A Solar Day
- 2.1429 mkm = Mars Motion Distance during Mars Day Period
- 1.9 degrees = Mars Orbital Inclination
Equation no. (e)
7 degrees = 5.1 degrees + 1.9 degrees
- Where
- 7 degrees = Mercury Orbital Inclination
- 1.9 degrees = Mars Orbital Inclination
- 5.1 degrees = The Moon Orbital Inclination
- The difficulty is repeated again here
- The data is Mercury and Mars data… but how this data be created? we can't
answer…
- Mars orbital inclination (1.9 deg) be created as a rate between Mercury and Mars
motions, that supports the previous discussion meaning but no clear geometrical
rules be discovered behind the data… shortly we don't know by what geometrical
rule the data be created based on one another.
- Notice
- The discussion vision may be more clear by analysis Venus Cycles from Mars
Cycles Point of View… that will help greatly the discussion of Mercury and Mars
Cycles Periods proportionality.

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(Point No. II) (Venus Mars Cycles Analysis)
I- More Data
(f)
680 mkm (Venus Orbital Circumference)= 360 mkm (Mercury Orbital Circumference) x 1.9
(g)
720.7 mkm = 2.1429 mkm x 336
And
5832.5 h (Venus rotation period) = 339 x 17.2 h (Uranus Day Period)
(h)
5832.5 h (Venus rotation period) = 237 x 24.6 h (Mars rotation period)
II- More Discussion
Equation no. (f)
680 mkm = 360 mkm x 1.9
- Where
- 680 mkm = Venus Orbital Circumference
- 360 mkm = Mercury Orbital Circumference
- 1.9 deg = Mars Orbital Inclination
- Equation no. (f) shows that, the rate 1.9 is used between Mercury and Venus
orbital circumference – why? where 1.9 degrees = Mars orbital inclination?
- Let's answer in following
- 687 days can be = 687 mkm if 1mkm =1 solar days
- Between 687 mkm and 680 mkm (Venus Orbital Circumference) (error 1%)
- That tells, some proportionality be found between 680 and 687
- And
- 4222.6 h (Mercury Day Period) =2π x 671 hours
- If 1 hour = 1 mkm this value will be 671 mkm
- 671 mkm = Venus Jupiter Distance

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- Shortly
- The data be created based on each other as we see clearly but
- No understanding is found to answer how this data be created based on each other
because the used Geometrical rules are still absent or unknown for us
- The rate (1 hour = 1 mkm) is very interesting for me because
- Mercury Uranus distance = 2815.2 mkm = 2 x 1407.6 mkm
- And if
- 1 mkm = 1 hour
- 1407.6 mkm will be = 1407.6 hours =Mercury Rotation Period
Equation no. (g)
720.7 mkm = 2.1429 mkm x 336
And
5832.5 h (Venus rotation period) = 339 x 17.2 h (Uranus Day Period)
- Where
- 720.7 mkm = Mercury Motion Distance During Mercury Day Period
- 2.1429 mkm = Mars Motion Distance During Mars Day Period
- The rate 336 is important because
- 339 = (Venus rotation period 5832.5 h)/ Uranus Day Period (17.2 h)
- The error between (339) and (336) is (1%)
- Notice
- 365.25 days = 1.077 x 339 days
Equation no. (h)
5832.5 h (Venus rotation period) = 237 x 24.6 h (Mars rotation period)
- The rate 237 is so important one in the solar system geometry because
- 86400 seconds = 365.25 seconds x 237
- That tells the rate 237 is related to 365.25 but the data needs more analysis to
understand what's going..

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Extensive Discussion
- This point of discussion aimed to discover if there's a proportionality between
Mercury and Mars Cycles Periods
- We needed this result because Jupiter motion depends on Mercury and Mars
Cycles periods in the same time, and we guess that Mercury and Mars Cycles
periods are created in proportionality to one another and Jupiter motion depends on
Mercury Cycle which forced Jupiter motion to depend on Mars Cycles periods
because of the 2 planets cycles periods proportionality.
- The data showed many times that Mercury and Mars Cycles Periods be created in
proportionality with one another but we couldn't catch the geometrical rules based
on which this proportionality be produced by that the data proved the idea but no
clear understanding how that's done…
- Why The Understating Is Difficult For Us?
- Because, The vision is different
- The solar system description inherited from Newton Theory of the sun mass
gravity supposed that
(1) The Solar Planets Motions Are Independent From One Another
(2) All Planets Motions Depend On The Same One Rate Of Time
(3) The Distances between the solar planets are created as independent
trajectories because each planet motion be independent from the other
planets motions.
This (3) point tells that, each planet distance should be independent from the
other planets distances – this imaginary idea contradicts the facts-because the
solar system distances be created in one Network
Means
The solar system distances be created based on one geometrical design. No one
distance is created independently from the others. on the contrary all of them be
created based on one geometrical design…

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- We have completely another vision about the solar system from what Newton
Theory told us… let's summarize some features of the planets motions facts in
following:
(A) The Solar System Distances Are Created In A Network Form Depending
On One Another.
(B) The Planets Motions Can't Be Independent from one another. Instead,
The planets Motions Be Integrated Into One Unified General Motion.
(C) The Solar Planets Motions Depend on Different Rates Of Time
- We have proved that (The Solar Planet Motion Can't be Independent from the
other Planets Motions). The Motions Data of Mercury, Mars and Jupiter proves
This Fact.
- So, We Have 2 More Points To Discuss
- But
- We need to complete Jupiter Motion data analysis before… because of that
- Point No. (4) discusses The Solar System Network Theory
- Point No. (5) discusses The Solar Planets Motions Using of Different Rates of time

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3-5 Jupiter Motion Data Analysis (continued)
I- Data (continued)
(1)
4331 days (Jupiter orbital period) = 175.94 days (Mercury Day Period) x 24.6
(2)
(But 687 days x 24 h = 24.6 h (Mars rotation period) x 671)
(3)
(4)
4900 mkm (Jupiter Orbital Circumference ) = 1.13184 mkm x 4331 days
(1.1318 mkm/day Jupiter Velocity Per A Solar Day)
(5)
(6)
4900 mkm = 2π x 778.6 mkm = 199.2 mkm x 24.6

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II- Discussion (Continued)
- We have tried to analyze the previous data
- For that reason, we have analyzed previous data in point no. (3-2) but we had no
chance to discuss the equation no. (6). Because of the information which tells
-
-
- At this information we have asked why Jupiter motion depends on Mercury and
Mars cycles periods. To find an answer we had to analyze the 3 planets motions
and discovered that these 3 planets motions can't be considered as independent
motions from one another but we should consider them as on unified motion or
motions done based on one another.
- Also we have to analyze Mercury and Mars Cycles Periods to know if they have
any connection between them and we have found references to this connection
- Before to discuss the equation no. (6) let's try to summarize the answer why we
analyze Jupiter Motion Data in following….
o Jupiter orbital period be in proportionality with Mercury Day period on one
side and with Mars orbital period on the other side
o The data proportionality raised a significant question because it disproves
(The Planet Motion Independency Concept) and also disproves (Newton
Theory Of The Sun Mass Gravity)
o By that, the data proportionality provides a vision contradicts with the solar
system vision inherited from Newton Theory. We had to find the fact if the
data proportionality be found based on the planets motions or by chance.
o We have analyzed the three planets motions data and found that the data
proportionality depends on the planets motions, and many other data be
created in proportionality supporting this same conclusion..

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o As a result the planet motion description be different from Newton Theory
Description. The next question should Why And How the solar planets
motions be integrated with one another, or created depending on each other.
because Newton Theory can be understandable by the sun mass gravity
effect on a planet motion, but how to understand the unified motion of 3
planets or more? Because a planet is not a gear and doesn't touch the other
planet. How any planet motion can effect on another planet motion and
causes their data to be exchangeable in both Planets motions?
o I try to show that, we have no basics for this different vision. We simply
don't understand how the motion at distance be occurred, and when Newton
told us about the sun mass gravity we have no explanation how this force
works and we have no geometrical mechanism to explain the gravity effect
o Here
o We should notice that
o I don't disprove The Mass Gravity Theory (NO)
o I try to disprove The Sun Mass Gravity Theory
o The fact is that, The Sun is created after all planets creation and motions
and because of that the planet motion doesn't depend on the sun mass
gravity.
o But,
o The mass gravity concept still works and I have nothing against it
o Spite of that,
o The 3 planets motions data analysis gives us a vision can't be understood by
our geometrical tools. Not only because we don't know how the motion at
distance be occurred but also (more important) because we don't know how
the matter is created…!
o As a result many new features should be inserted in planet motion. we have
referred to these new features before let's remember them her again

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(A) The Solar System Distances Are Created In A Network Form Depending
On One Another.
(B) The Planets Motions Can't Be Independent from one another. Instead,
The planets Motions Be Integrated Into One Unified General Motion.
(C) The Solar Planets Motions Depend on Different Rates Of Time
o These new features we should discuss and prove in the next points (please
review the contents), but
o We still need to find the theoretical basics behind the decryption and its
features…for example, suppose the planets motions exchange the data
among them, why this is done? What positive result for such exchange of
data?
- I want to say
- The motions data analysis of the 3 planets be an approach to the new vision about
the solar system motion. This data analysis tried to put the planets motions data in
comparison with Newton Theory of the sun mass gravity and the solar system
description inherited from it. The analysis gave us no explanation but gave us a
vision about how the data be used…
- We have to support this approach with more data in the same direction…
- Because of that,
- We discuss the solar system distances creation in details to prove that the distances
be created based on one geometrical design. We try to prove that there's one
geometrical design and one Network behind all distances in the solar system. this
proof also supports the same vision of planets motions dependency on one another
- So, The Distances Network Theory Be Discussed In The Next Point Directly
(Point no. 4 of this paper)
- After that we should prove the planets motions using of different rates of time. But
this point we have to discuss later because of one reason I will refer to it in this
point Preface (The planets using different rates of time be discussed in point no.6)

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- Now
- We need to answer the basic questions, why and how the planets motions depends
on one another
- And more important
- What's the solar system description which be used in place of Newton Theory?
- To answer these questions we have to analyze Mercury motion….
- The fact is that, Mercury Motion analysis gives us another explanations for all
planets motions data
- That means, another reading for all data be provided by Mercury Motion Analysis
- That because
- Mercury motion analysis tells us that, one light beam be accompanying the solar
system motion and effect on the planets motions. by that Mercury Motion analysis
provides the required answers for the basic questions which are
- (1) (How The Matter Is Created?)
- (2) (How The space Be Created?)
- (3) (How the solar planets Motions depend on one another? and why?)
- So, Let's arrange our ideas
- In this current point we discuss shortly the equation no. (6). The discussion be in
short form because this equation can be understandable only through Mercury
Motion Analysis Approach.
- Then in the next point we discuss the solar system distances Network Theory
(Point No.4)
- The next Point will be Mercury Motion Analysis approach (Point no.5)
- And then Mercury Jupiter Distance Analysis (Point no.9) (this point discusses our
equation no. 6 details)
- The planets motions using of different rates of time (point no. 6)
- Then we should prove that the sun is the last piece created in the solar system
(point no.8)

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Equation no. (6)
4900 mkm = 199.2 mkm x 24.6
- Where
- 4900 mkm = Jupiter Orbital Circumference
- 199.2 mkm = The distance be passed by Jupiter during 4222.6 hours (Mercury
Day period)
- 24.6 hours = Mars Rotation Period
- Do we understand Equation no. (6)?
- We know that (4331 days = 175.94 x 24.6 hours) where (175.94 days = Mercury
day period)
- The rate 24.6 is known between Jupiter cycle (4331 days) and Mercury Cycle
(175.94 days) where (24.6 hours = Mars rotation period)
- Based on that the equation is produced (4900 mkm = 24.6 x 199.2 mkm)
- But how to understand this equation?
- The proportionality between the cycles we suppose it create different rates of time.
Based on that, 1 hour of Mercury motion be = 24.6 hours,
- This is a rate of time where (1 hour of Mercury Motion = 24.6 hours of Jupiter
motion)
- But
- The rate of time can't effect directly on the planets motions because the velocities
rate doesn't = the rate of time
- In more details
- Mercury Velocity 47.4 km/s = Jupiter velocity x 3.61
- By that, the planets motions distances be defined based on the rate (6.8) why?
- Because
- (24.6 /3.61) = 6.8
- Where
- 24.6 is the rate of time between the 2 planets (Mercury and Jupiter)

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- 3.61 is the rate of velocities between the 2 planets (Mercury and Jupiter)
- Based on that, the planets motions distances are rated with the rate (6.8)
- Let's see the using of the rate (6.8) in following:
- 3717 mkm (Jupiter Neptune Distance) = 6.8 x 550.7 mkm (Mars Jupiter Distance)
- 4267.2 mkm (Mars Neptune Distance) = 6.8 x 629 mkm (Earth Jupiter Distance)
- 2π x 720.7 mkm (Mercury Jupiter Distance) = 6.8 x 629 mkm (Venus Jupiter Distance)
- 4900 mkm (Jupiter Orbital Circumference) = 6.8 x 720.7 mkm (Mercury Jupiter
Distance)
- 37100 mkm (Pluto Orbital Circumference) = 6.8 x 550.7 mkm (Mars Jupiter
Distance) x π2
- The Rate (6.8) Using Explanation:
- We suppose that, 1 hour of Mercury Motion = 24.6 hours of Jupiter Motion. can
this rate of time be a real one? can the planets motions have different rates of time?
And why it should be?
- Planets motions using of different rates of time we should discuss in details in this
paper. But we have referred to this meaning in our try to define the expression
(motions interaction), where we have found that (1 hour of Earth motion =6.37
hours of Pluto motion) and many other data of both planets be in proportionality as
a result)
- The point is that, the planet motion rate of time is an important rate and be
effective in planets motions data creation
- Notice
- Equation no. (6) can be explained only with Mercury Jupiter distance discussion
(point no.9) of this paper.

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4-The Solar System Distances Be Created In A Network Form
4-1 Preface
4-2 The Continuum effect Through the Solar System Distances
4-3 The Solar System Distances Distribution
4-4 The Solar System Distances Dependency On One Another

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4-1 Preface
- The Solar Planets data analysis shows that, The Planets Distances Be Created In A
Network Form.
- Means,
- The solar system distances are considered as one geometrical design or one
geometrical system. There's no one distance defined as independent distance or
created out of this one geometrical design.
- Let's suppose, this geometrical design be a square. So all dimensions in this
square be defined geometrically based on this square angles and data. means no
one dimension can be created independently from this square data because all of
them are parts in the same one geometrical design.
- Suppose we have a triangle its 2 angles are (60 degrees and 80 degrees) what's the
third one? (40 degrees). Can this angle be any thing else than (40 degrees)? NO it's
obligatory value defined by the geometrical basic rules
- Similar to that,
- The Solar System Distances Be Created Based On One Geometrical Design.
- But
- By using this vision we will have surprises. Because this vision tells (for example)
Venus Jupiter Distance be= 671 mkm Because Earth Jupiter distance = 629 mkm
- That creates another vision
- While we consider Venus is a planet and Earth is another planet and they move
independently from one another. We are astonished now with this fact that, their
distances to Jupiter be defined based on one another! How? And Why?
- How (Because The Solar System Distances Be Created In A Network Form)
- Why (this answer will be discussed in Mercury Motion Analysis Point)
- The fact is proved strongly that
- The Solar System Distances Be Created in A Network

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- There Are Many Basic Proves For This Fact which are:
- (1) The Continuum effect Through the Solar System Distances
- (2) The Solar System Distances Distribution
- (3) The Solar System Distances Dependency On One Another
- Let's discuss these proves in their details in following
- Notice
- The idea tells that,
- By energy the distances be created in a network form
- That means
- The Distances Be Similar To The Railways And The Planets Be Similar To The
Trains Move On The Railways.
- The important point is that, the distance be created by energy and because of that
it's a defined trajectory of motion. that makes the planet moves in some obligatory
motion because the energy created the distances.
- Means,
- The distances aren’t common space but defined distances be built for specific
reason. Based on that (Distance = Energy)
- And
- The created distance defined a trajectory of motion
- As a result
- The solar system distances be as a map created by energy

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4-2 The Continuum effect Through the Solar System Distances
Point No. (I)
The Continuum Effect Description
I- Data
(1)
50% of all distances in the solar system be equal one another
(2)
40% of all distances in the solar system be rated one another
Let's provide this data in details in following:
Data Group No. (A)
Why These Distances Are Equal?
(1)
Saturn Orbital Distance = Saturn Uranus Distance
= Mars Orbital Circumference
= Pluto Neptune Distance (error 1.5%)
= Pluto eccentricity Distance (error 1.5%)
= Neptune Orbital Distance/π
= Uranus Orbital Distance /2
= Mercury Jupiter Distance x 2
(2)
Mercury Neptune Distance = Saturn Pluto Distance
Jupiter Pluto Distance = Uranus Neptune Circumference
Earth Neptune Distance = Mercury Saturn Circumference (0.5%)
(3)
Jupiter Mercury Distance = 2 Mercury Orbital Circumference
Jupiter Venus Distance = Venus Orbital Circumference (1.5%)
Jupiter Earth Distance = Earth Orbital Circumference (1.2%)
(Earth and Jupiter at 2 different sides from the sun)
(4)
Jupiter Mercury Distance = Mars Orbital Distance x π (0.6%)
Jupiter Uranus Distance = Venus Jupiter Circumference (0.8%)
Pluto Orbital Distance = Earth Orbital Circumference x 2π
(These Equal Distances Be Around 50% Of All Distances In The Solar System)

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Data Group No. (B)
Why These Distances Are NOT Equal?
1. 0725
.
1
mkm
2.41
nce
Circumfere
Orbital
Moon
mkm
2.58
Motion
Daily
Earth
=
2. 1.0725
km)
(378500
radius
Eclipse
Solar
Total
km)
(406000
radius
orbital
Apogee
=
3. 0725
.
1
distance
Mercury
Jupiter
mkm
720.3
Distance
Orbital
Juppiter
mkm
6
.
778
= (Error 0.7%)
4. 1.0725
Distance
Venus
Jupiter
mkm
670
distance
Mercury
Jupiter
mkm
720.3
=
5. 1.0725
Distance
Earth
Jupiter
mkm
629
Distance
Venus
Jupiter
mkm
670
= (0.6%)
6. 1.0725
mkm)
(1325.3
Distance
Venus
Sarurn
mkm)
(1433.5
Distance
Orbital
Saturn
= (0.8%)
7. 1.0725
mkm)
(1205.6
Distance
Mars
Sarurn
mkm)
(1284
Distance
Earth
Saturn
= (0.7%)
8. 1.0725
mkm)
(2644
Distance
Mars
Uranus
mkm)
(2872.5
Distance
Orbital
Uranus
= (0.7%)
9. 1.0725
mkm)
(4495.1
Distance
Orbital
Neptune
mkm)
(4864
= (0.5 %)
(These Rated Distances Be Around 40% Of All Distances In The Solar System)
Additional Data
(10)
0725
.
1
T.
Axail
Earth
23.4
T.
Axail
Mars
25.2
T.
Axail
Mars
25.2
T.
Axail
Satrun
26.7
Tilt
Axail
Satrun
26.7
Tilt
Axail
Neptune
28.3
=
=
=

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II- Discussion
- Let's suppose that,
- The solar planet moves interpedently from all other planets motions depending on
the sun mass gravity, in this case how these equal distances (50%) and the rated
distances (40%) be created?
- No logic can imagine a different reason for each 2 equal distances? We conclude
logically that (One Reason Caused These Distances To Be Equal)
- Based on that, we don't deal with independent distances instead we deal with one
machine be created by all distances integration. and As A Result, ONE REASON
effects on (the machine) caused (all distances to be effected by this one reason)
- I want to say,
- These 2 groups of data disproves The Planet Motion Independency Concept.
- There's no way to create the equal and rated distances in huge percentage if the
planets motions be independent from one another.
- But
- Why These Distances Are Equal?
- The answer is somehow complex and will be clear in the point no.(10) in which we
should discuss the equal distances method… but here let's provide a short answer
in following:
- The solar planets don't move by the sun mass gravity. But they move by equal
distances method (or at least the outer planets move by this method)
- The equal distances method is a method be used by many planets. Let's explain
how this method be used…. 2 Planets move equal distances in defined periods of
time (as example, Earth moves during its day period a distance =2.574mkm and
Pluto moves during its day period a distance = 2.598 mkm, these 2 distances are
different with 1% only and by that they can be considered equal distances. As a
result for these 2 motions equal distances Earth and Pluto motions data be in
proportionality with one another. this data we should discuss in point no.(6)

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- This feature be used hundreds of time by the solar planets, I guessed that, because
this method is used hundreds or even thousands of times in the solar system, this
method causes the planets motions (but I don't know how yet). The idea is that,
this method (the equal distances) works by a geometrical rule, as a waterwheel or a
lever, these methods work by geometrical rules. Similar to that the equal distances
method caused the planets motions
- As a result for using the equal distances method, 50% of all distances in the solar
system be created equal one another and also 40% of all distances be rated with
one another by the same one rate (1.0725)
- But
- Please note
- The equal distances be created because the solar system uses the equal distances
method as I have explained it before and as we will discuss and prove deeply in
point no. (10) of this paper.
- But
- Why Does The Rate (1.0725) effect On 40% Of All Distances?
- The rate (1.0725) effect on (40% distances) is a proof for a continuous effect
through the distances. There's Some Effect Like A Continuum effects on the
solar system distances!
- How that can be done if the planets move independently from one another? and
- If the distances be created independently from one another how one effect can be
continuous through (40%) of all distances?
- I try to prove, the distances are created in a network or by one geometrical design.
- means,
- the distances be created together in one geometrical system as one machine
because of that one effect can continue through (40%) of all distances
- the explanation of using this rate (1.0725) isn't our question…. Our basic notice is
that this effect has a continuous task through the solar system distances which can't

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be done except if these distances be created based on one geometrical system or in
one Network
- I wish the argument is powerful and proved strongly
- The data gives us a chance to show that, the planet motion can't be independent
from other planets motions. we here don't deal with independent data but with one
system of data.

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4-3 The Solar System Distances Distribution
(1st
Point) The Idea Explanation
- There are 2 basic features we should discuss about the solar planet motion, thee 2
features are:
- (1) The Planets Motions Use Different Rates Of Time
- (2) The Planets Motions Use The Distances As Periods Of Time
- These 2 features we should discuss and prove in this paper discussion
- I need here jut to explain how these features be used to test their effects on the
distances distribution
- There are different rates of time be used by the solar planets, for example:
- 1 hour of Mercury motion = 9.18 hours of Pluto Motion
- And
- 1 hour of Earth motion = 6.37 hours of Pluto Motion
- And also
- 1 hour of Pluto motion = 4.61 hours of The Moon Motion
- We will prove this data in the paper next discussion, but let's take a look on the
second feature in following… (for example)
- Mercury moves during its rotation period a distance = 243 mkm (error 1%)
- Venus moves during 365.25 days a distance =1106 mkm
- If 1mkm= 1 solar day
- 243 mkm will be = 243 solar days (Venus Rotation Period), and
- 1106 mkm will be = 1106 days =2π x 175.94 days (Mercury Day Period)
- These are just examples for hundreds of data be used similar to this way
- I want to say that, the planets motions use the distances values as periods of time
- But
- The first feature tells, different rates of time be used by the planets motions

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- As we have seen (1hour of Mercury motion = 9.18 h of Pluto motion),
- If different rates of time be used how the distances values be used as periods of
time?
- Means,
- 1 mkm be =1 solar day, or equal 9.18 solar days, or equal 6.37 solar days ……etc?
- How to use this feature (the using of distances values as periods of time)??
- Let's use the rate between Pluto motion and the Earth moon motion as example for
our discussion
- Notice
- 1 Hour Of Pluto Motion = 4.61 Hours Of The Moon Motion
- How do I know this rate?
- By their motions distances
- Pluto move during a solar day 406000 km
- and
- the Earth moon displacement per a solar day =88000 km
- (406000 km) = 4.61 x (88000 km)
- As A Result
- 708.7 hours (The Moon Day Period) = 4.61 x 153.3 hours (Pluto Day Period)
- And the rate (4.61) effects on many other data between Pluto and the moon
motions. this data we should discuss deeply in point no. (6) of this paper
- Now
- If the 2 features be used really by the planets motions. the rate (4.61) should be
found in the solar system distances distribution… because the distances be used as
periods of time and (1 hour of Pluto motion = 4.61 hours of the moon motion) and
that necessitates to create some distances based on this rate…
- Let's see the data in following

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(2nd
Point) The Rate (4.61) Effect On The Distances Distribution
I- Data
778.6 mkm (Jupiter Orbital Distance) = 4.61 x 170 mkm
550.7mkm (Jupiter Mars Distance) = 4.61 x 119.7 mkm
2094 mkm (Jupiter Uranus Distance) = 4.61 x 2 x 227.9 mkm
2872.5 mkm (Uranus Orbital Distance) = 4.61 x 629 mkm
3033.5 mkm (Uranus Pluto Distance) =4.61 x 654.9 mkm
5127 mkm (Jupiter Pluto Distance) = 4.61 x 2 x 550.7 mkm
5906 mkm (Pluto Orbital Distance) =4.61 x 1284 mkm
1375.6 mkm (Mercury Saturn Distance) =4.61 x 2 x 149.6 mkm
3062 mkm (Saturn Neptune Distance) =4.61 x 671 mkm
4345.5 mkm (Earth Neptune Distance) =4.61 x 940 mkm
4267.2 mkm (Mars Neptune Distance) =4.61 x 929 mkm
Where
170 mkm = Mercury Mars Distance
119.7 mkm = Venus Mars Distance
227.9 mkm = Mars Orbital Distance
629 mkm = Jupiter Earth Distance
654.9 mkm = Jupiter Saturn Distance
550.7 mkm = Jupiter Mars Distance
1284 mkm = Earth Saturn Distance
149.6 mkm = Earth Orbital Distance
671 mkm = Jupiter Venus Distance
940 mkm = Earth Orbital Circumference
929 mkm = Earth Jupiter Distance when the 2 planets be on the sun 2 sides
(Max error 1%)

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II- Discussion
- The solar system orbital and internal distances total be (45 distances)
- The previous data shows that (22 distances) are rated with the rate (4.61)
- Means
- 50% of all distances in the solar system be rated with one another based on this
same rate (4.61).
- The data proves the distances distribution depends on the planets motions rates
time.
- The data proves, The Solar System Distances Be Created As A Network.

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(3rd
Point) The Distances Distribution Proof.
I - Data
Equation no. (A)
1.16 mkm per second x (2) x 86400 seconds =(2) x 100733 mkm = (37100 mkm –
4900 mkm) x 2π = 28255 mkm + (2) x 86400 mkm
- Where
- 100733 mkm = The 9 Planets Orbital Circumferences Total
- 37100 mkm = Pluto Orbital Circumference
-
- This equation is the paper main equation and the solar system main equation and
the most important one generally
- This discussion we discuss deeply with Mercury Motion analysis because of the
light supposed velocity (1.16 mkm/sec) motion which is found in Part one of the
II- Discussion
- This equation is the paper main equation and the solar system main equation and
the most important one generally
- This discussion we discuss deeply with Mercury Motion analysis because of the
light supposed velocity (1.16 mkm/sec) motion which is found in Part one of the
equation.
- We discuss here only Part (3) and part (4)

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- (Part no. 3)
- (37100 mkm – 4900 mkm) x 2π
- 37100 mkm = Pluto Orbital Circumference
- Part no. (3) shows why the equation be a real one and not imaginary equation.
Because the difference in distance between Pluto orbital circumference (37100
mkm) and Jupiter orbital circumference (4900 mkm) creates this equation.
- The equation tells that
- The difference in distances between Pluto orbital circumference (37100 mkm) and
Jupiter orbital circumference (4900 mkm) be used as a radius in a circle and in this
case this circle circumference will be = 2 x 100733 mkm
- Where
- 100733 mkm= The 9 Planets Orbital Circumferences Total
- That shows there are 2 equal distances which are the difference between Pluto and
Jupiter orbital circumferences and the planets orbital circumferences total
- These are 2 equal distances in this equation
- But
- Let's see the part no. (4) of it in following
- (Part no. 4)
- 28255 mkm + 2 x 86400 mkm
- Where
- 28255 mkm =Neptune Orbital Circumference
- 86400 mkm=??
- Let's See The Next Equation
- 2 x 86400 mkm = (28255 mkm – 680 mkm) x 2π (Venus Equation)
- Where
- 680 mkm = Venus orbital circumference
- If we use Earth orbital circumference in place of Venus the error be (1%)

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- How to understand the part no. (4)
- (Part no. 4) (continued)
- 28255 mkm + 2 x 86400 mkm
- We had 2 equal distances which are the (32200 mkm x2π) and (2 x 100733 mkm)
- And now we have a third distance equal them which is
- (28255 mkm+ 2 x 86400 mkm)
- This equation part tells that distances between Neptune and Venus (1st
Trajectory)
and between Neptune and Earth (2nd
Trajectory), these distances + Neptune orbital
circumference be the third distance and = (2 x 100733 mkm)
- I try to show, these distances are distributed in proportionality with one another
- That proves the solar system distances be created in a network form and
distributed geometrically
- This equation will be discussed again wit Mercury Motion analysis. In this
discussion we should see more clear that these distances are distributed based on
geometrical rules.

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4-4 The Solar System Distances Dependency On One Another
I-Data
(1)
1.16 x 580 mkm = 671 mkm (Venus Jupiter Distance)
1.16 x 671 mkm = 778.6 mkm (Jupiter Orbital Distance)
1.16 x 629 mkm = 720.7 mkm (error 1%) (Mercury Jupiter Distance)
1.16 x 542 mkm = 629 mkm (Earth Jupiter Distance)
1.16 x 5127 mkm = 5906 mkm (error 0.7%) (Pluto Orbital Distance)
(2)
1.16 x 778.6 mkm x 2 = 1806 mkm
1.16 x 1806 mkm = 2094 mkm (Jupiter Uranus Distance)
1.16 x 2094 mkm = 2 x 1205 mkm (error 0.8%) (Mars Saturn Distance)
(3)
(1.16)2
x 170 mkm = 227.9 mkm (error 0.4%) (Mars Orbital Distance)
Where 170 mkm = Mercury mars Distance
(5)
1.16 x 1980 mkm = 2296.8 mkm
1.16 x 2296.8 mkm = 2644.6 mkm (error 0.7%) (Mars Uranus Distance)
1.16 x 2644.5 mkm = 3033.5 mkm (error 1%) (Uranus Pluto Distance)

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II-Discussion
- The previous distances are example for similar huge number of distances which
depend on the rate (1.16)
- We should analyze this rate (1.16) later
- But
- We need here to see how the distances be distributed base don this rate (1.16)
- The next data can help our analysis greatly
More Data
- 778.6 mkm (Jupiter Orbital Distance) = 1.0725 x 720.7 mkm (error 1%)
- 720.7 mkm (Jupiter Mercury Distance) = 1.0725 x 671 mkm
- 671 mkm (Jupiter Venus Distance) = 1.0725 x 629 mkm
- 629 mkm (Jupiter Earth Distance) = 1.0725 x 580 mkm (error 1%)
- This data also proves, these distances be created based on a geometrical design.
Because the same distances be rated on (1.0725 and 1.16).
- Please remember 1.16 =(1.077)2
- The analysis shows that the solar system distances can't be created interpedently
from one another but created in a network form. And because of that the distances
be distributed based on a geometrical design and as a result the distances be rated
with the rates (1.16) and (1.0725)

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5-Mercury Motion Analysis
5-1 Preface
5-2 The Theory basic Ideas
5-3 The Light Beam (1.16 mkm/s) Proves Discussion
5-4 Jupiter Orbital Circumference Analysis

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5-1 Preface
- Mercury Motion Analysis provides Another Reading For The Data We Have
Discussed In Jupiter Motion Analysis.
- That means
- We discuss here the same data one more time based on Mercury Motion analysis
- Mercury Motion Analysis Depends On A Basic Hypothesis Which Is
- (A light beam its velocity 1.16 mkm/s be accompanying with Mercury Motion)
- Or
- (Mercury Motion Depends On A Light Beam Its Velocity =1.16 mkm/s)
- This hypothesis is complex because we need to prove at first that (There's a light
beam its velocity =1.16 mkm/sec)
- And We Hope To Do That Through The Planets Motions Data Analysis
- The next question should be
- Why Does A Light Beam Accompany Mercury Motion?
- The answer of this question be found in Matter Creation Theory, let's summarize
this theory in the next point.

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5-2 The Theory Basic Ideas
(I)
- The theory tells
- The matter is created out of light. And the born matter isn't separated from its
parent light beam but move together in one unified motion.
- Light and matter motions use different rates of time
- For The Solar System,
- The solar system is created of one light beam its velocity (1.16 mkm/s).
- The light energy creates the planets matters and their distances (because matter is
created of energy and space is created of energy)
- The solar planets be born from the light beam with supposed velocity (1.16
mkm/s) move with this light beam in One Unified General Motion.
- That's why one light beam its velocity (1.16 mkm/s) be accompanying with the
solar planets motions.
- Light and planets motions use different rate of time
- The basic rate of time is the following one
- 1 Second Of Light Motion = 1 Solar Day Of Planet Motion
(Or one second of light motion energy causes planet to move for one solar day)
- But
- This rate is the general rate between planets and light motions. and the solar
planets motions divide this rate into small rates for the planets among each other.
- The planets small rates of time be integrated into the general rate of time
- Examples of the planets rates of time are
- (1 hour of Mercury motion = 1 second of light motion)
- and
- (1 hour of Mercury motion = 9.18 hours of Pluto motion).
- The planets motions rates of time be integrated together till perform the general
one (1second of light motion = 1 solar day of planet motion).

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(II)
- We compare planets motions with light supposed velocity (1.16 mkm/s) motion.
- The light supposed velocity (1.16 mkm/s) starts its motion from Mercury point
and travels immediately to Jupiter. And from Jupiter the energy be sent directly to
Pluto and no clear trajectory of light motion be found in comparison with Mars
Motion.
- We should follow the trajectory in close because we depend on planets motions
data only and no outer data be used…. Based on that,
- Mercury data shows the light supposed velocity (1.16 mkm/s) started from
Mercury moving to Jupiter directly
- The second motion be from Jupiter to Pluto directly
- No light motion be available with Mars
- We should discuss these motions trajectories in details to prove the accompanying
of light motion with the solar planets motions.
- In the next point (4-3) we discuss deeply these motions trajectories.

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4-3 The Light Beam (1.16 mkm/s) Proves Discussion
I - Data
(1)
1.16 mkm/s x 86400 s = 100733 mkm
And
0.3 mkm/s x 86400 s = 25920 mkm
(2)
1.16 mkm/s x 500 s = 580 mkm
1.16 mkm/s x 580 s = 671 mkm (Venus Jupiter Distance)
1.16 mkm/s x 671 s = 778.6 mkm (Jupiter Orbital Distance)
1.16 mkm/s x 629 s = 720.7 mkm (error 1%) (Mercury Jupiter Distance)
1.16 mkm/s x 5127 s = 5906 mkm (error 0.7%) (Pluto Orbital Distance)
(3)
1.16 mkm/s x 4224 seconds = 4900 mkm
(4)
1.16 mkm per second x 2 x 86400 seconds =2 x 100733 mkm = (37100 mkm – 4900
mkm) x 2π = 28255 mkm + 2 x 86400 mkm
(5)
1.16 mkm/s x 5040 seconds = 5848 mkm (Mercury Pluto Distance)
And
5848 mkm (Mercury Pluto Distance) – 4900 mkm = 948 mkm
(6)
1.16 mkm/s x 4900 seconds = 5678.1 mkm (Mars Pluto Distance)
And
1.16 mkm/s x 5687.1 seconds = 6585.4 mkm
(7)
193 seconds x 0.3mkm/sec = 57.9 mkm (Mercury Orbital Distance)
196.5 seconds x 1.16 mkm/sec = 227.9 mkm (Mars Orbital Distance)

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II- Discussion
Equation no. (1)
1.16 mkm/s x 86400 s = 100733 mkm
And
0.3 mkm/s x 86400 s = 25920 mkm
- Light known velocity (0.3 mkm/s) travels during a solar day (86400 s) a distance =
25920 mkm.
- Because it's a light motion we see this value (25920 mkm) as a period of time
(25920 years = the Precession Cycle)
- Also
- The distance 25920 mkm be = The Planets Motions Distances Total During A
Period =1461 days (where 1461 days =365 +365 +365 +366)
- Because the period 1461 days is (Earth Cycle) we consider that the distance 25920
mkm be mentioned by planets motions total
- Notice, the distances total added the Earth moon motion distance to the 9 planets
motions distance to create the total per a solar day (17.75 mkm) where the moon
motion daily distance be considered = Earth motion daily distance because they
aren't separated from one another through their motions.
- The light supposed velocity (1.16 mkm/s) travels during a solar day (86400 s) a
distance = 100733 mkm = The 9 Planets Orbital Circumferences Total
- Equation no. (1) tries to prove that, Light Motion Uses The Solar Day Period As
Its Basic Period Of Motion.
- Light known velocity and light supposed velocity both use the solar day as the
basic period of time. Because of that, both light beams passes essential distances in
the solar system geometry.
- The next discussions will prove that these distances (25920 mkm and 100733
mkm) are essential distances in the solar system geometry.

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- Notice
- The rule tells
- (Light Motion For 1 Second = Planet Motion For 1 Solar Day)
- This rule which is a supposed one and we should prove it through the paper
discussions…
- This rule tells that,
- The light motion depends on the solar day as a period of time as similar to its
dependency on the second as a period of time.
- That means,
- These 2 periods of time (the second and the solar day) are the 2 basic columns for
light and planet motions accompaniment.
- And by that, light motion doesn't use the solar day as similar to any other planet
day period. On the contrary, the solar day is the basic period of time for light
motion (For both velocities, the known and supposed).

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Equation no. (2)
1.16 mkm/s x 500 s = 580 mkm
1.16 mkm/s x 580 s = 671 mkm (Venus Jupiter Distance)
1.16 mkm/s x 671 s = 778.6 mkm (Jupiter Orbital Distance)
1.16 mkm/s x 629 s = 720.7 mkm (error 1%) (Mercury Jupiter Distance)
1.16 mkm/s x 5127 s = 5906 mkm (error 0.7%) (Pluto Orbital Distance)
- The data show specific features of motions which are:
- The light supposed velocity (1.16 mkm/s) uses the distances values as a periods of
time by the rate (1 mkm = 1 second).
- Based on that, the distances be created depends on one another and no distance be
created independent from the other distances. That means, the distances be created
in a network form of distances and not as independent distances from one another.
- The data shows how the solar system distances be created in a network form
- In details
- Light supposed velocity (1.16 mkm/s) uses the period (500 sec) to pass a distance
580 mkm, and
- Light supposed velocity (1.16 mkm/s) uses the distance (580 mkm) as a period of
time (580 sec) to pass a distance 671 mkm (= Venus Jupiter Distance), and
time (671 sec) to pass a distance 778.6 mkm (=Jupiter Orbital Distance), and
time (629 sec) to pass a distance 720.7 mkm (=Jupiter Mercury Distance), …etc
- We have discussed this data before but now we have another reading for this same
data

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The Motion 1st
Trajectory
- The Trajectory Summary
- Light supposed velocity (1.16 mkm/s) travels starting from Mercury to Jupiter,
creating Jupiter orbital circumference
- And, then
- Light supposed velocity (1.16 mkm/s) travels from Jupiter to Pluto (Directly) and
doesn't touch any other planet in the way.
- The motion trajectory is built on 2 basic equations and many other additional data.
because
- Mercury Motion uses light supposed velocity (1.16 mkm/s) because of that,
different data of Mercury motion be created based on this light supposed velocity
(1.16 mkm/s) energy
- Shortly
- The motion 1st
trajectory is defined based on Equation no. (3) and (4) as basic
equations. And through discussion many other data be added
- Notice
Equation no. (4) is the solar system geometry main equation and it's the paper main
one we discuss it along the paper,

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Equation no. (3)
1.16 mkm/s x 4224 seconds = 4900 mkm
- Where
- Equation no. (3) tells, the light supposed velocity (1.16 mkm/s) travels during
4224 seconds a distance = 4900 mkm = Jupiter Orbital Circumference.
- Now, let's suppose 1 second of light motion = 1 hour of Mercury Motion
- based on that, 4224 seconds be equivalent to 4224 hours (but 4222.6 hours =
Mercury Day Period).
- Equation no. (3) provides 3 braches of data! let's summarize them in following:
- (1st
Branch) Light supposed velocity (1.16 mkm/s) moves in (4224 s) a distance
=4900 mkm but Mercury moves during (4222.6 h) a distance = 720.7 mkm
(=Mercury Jupiter Distance) and we suppose that 1 second of light motion = 1
hour of Mercury Motion. Because of that we need to find some connection
between 4900 mkm and 720.7 mkm to create a comparison between light motion
and planet motion.
- The comparison is complex because, I suppose the rate (2π) distinguish between
light and planet motions. By that, if light moves 4900 mkm, a planet motion
should be 778.6 mkm but Mercury motion distance only be 720.7 mkm, where,
- 778.6 mkm (Jupiter orbital distance) =1.0725 x 720.7 mkm (Mercury Jupiter
Distance)
- The rate (1.0725) creates a negative effect on the rule of the value (2π). although
the rate (1.0725) be used between 40% of all distances in the solar system. But
because it be found here creates more complexity for the discussion and causes
some negative effect for the comparison between light and planet motions. because
always in other data we have found that the value (2π) distinguish clearly between

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light and planet motions but in our equation the rate (1.0725) causes some
difficulty for this comparison vision.
- Notice
- The distance 720.7 mkm (Mercury Jupiter Distance) be discussed in point no. (9)
of this paper.
- (2nd
Branch) Mercury Day Period Creation.
- We have supposed that, 1 second of light motion be equivalent to 1 hour of
Mercury Motion. that means the period (4224 s ) be equivalent to (4224 h) and
Mercury Day Period = (4222.6 hours).
- This supposition suggests that, Light supposed velocity (1.16 mkm/) motion causes
to create Mercury Day Period be (= 4222.6 hours).
- The data is accurate and clear
- NOW
- The data tells that…
- Mercury is the source of the light supposed velocity (1.16 mkm/s)
- The light supposed velocity (1.16 mkm/s) started from Mercury and sent to Jupiter,
creating the distance (4900 mkm = Jupiter Orbital Circumference).
- This motion depends on Mercury Day Period.
- As a result, Mercury Day Period be defined by light supposed velocity (1.16
mkm/s) motion effect on Mercury Motion.
- i.e.
- Mercury Day Period = 4222.6 hours
- And
- 4900 mkm= 1.16 mkm/s x 4224 seconds
- We suppose that, 1 hour of Mercury Motion = 1 second of light motion… means
- The difference (4224 -4222.6 = 1.4) is created by the light supposed velocity (1.16
mkm/s) motion effect. that means,

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- The light motion effected on Mercury Motion and caused Mercury day period to
be 4222.6 hours and less than 4224 hours with 1.4 hour = 5040 seconds
- Why? Because
- Light supposed velocity (1.16 mkm/s) travels during (5040 s) a distance =5848
mkm = Mercury Pluto Distance
- The light supposed velocity (1.16 mkm/s) created a connection between Mercury
and Pluto motions by creating the period 5040 seconds as a difference between
Mercury Day period (4222.6 h) and 176 solar days (=4224 hours).
- We can't discover the geometrical machine behind this data. But the data clearly
shows that, the light supposed velocity (1.16 mkm/s) travels during 5040 seconds a
distance = 5848 mkm.
- We have 3 information we got based on this analysis which are:
- (1st
) Mercury Is The Origin Point Of The Light Supposed Velocity (1.16 mkm/s)
- (2nd
) light supposed velocity (1.16 mkm/s) motion created Jupiter orbital
circumference 4900 mkm.
- (3rd
) Mercury Day Period be (4222.6 h) and less than (4224 h) with (5040 s)
because of light supposed velocity (1.16 mkm/s) effect on Mercury motion, to
create a connection between Mercury and Pluto motions.
- Notice
- The accompaniment of The Light supposed velocity and Mercury Motions caused
Mercury day Period to be (4222.6 hours) to create a connection between Mercury
and Pluto based on the distance (5848 mkm = Mercury Pluto Distance)
- Is There any Proof for this conclusion?
- Yes, There's a proof in Mercury Motion data,
- Let's analyze Mercury Motion Data in following:

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Mercury Motion Data
- 5040 seconds = 84 minutes
- Mercury (4.095 mkm/ daily) moves during 84 solar days a distance = 344 mkm
- And
- Mercury (4.095 mkm/ daily) moves during 346.6 solar days a distance = 1419.5 mkm
- And
- Mercury (4.095 mkm/ daily) moves during 1419.5 solar days a distance = 5813 mkm
- But
- Mercury (4.095 mkm/ daily) moves during 1433.5 solar days a distance = 5870 mkm
Pluto Orbital Distance
- NASA Planetary Fact sheet had defined Pluto orbital distance as 5870 mkm
- And
- From 5 years NASA had modified this distance to be 5906 mkm
- In the theoretical calculations both distances are required!
- Let's explain that in following
o 5906 mkm – 57.9 mkm (Mercury orbital distance) = 5848 mkm
o This distance 5848 mkm accurately = 1.16 mkm/s x 5040 seconds
But
o Mercury motion during 1419.5 days passes a distance =5813 mkm = 5870
mkm – 57.9 mkm - And
o Mercury motion during 1433.5 days passes a distance =5870 mkm (Pluto
orbital distance)
Shortly
o Light motion depends on the distance (5906 mkm as Pluto orbital distance)
but Mercury motion depends on the distance (5870 mkm as Pluto orbital
distance).
o That tells both distances are found geometrically but also tells some
difference be found between light and planet motions.

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Mercury Motion Data Analysis
- The previous data shows that,
- Mercury uses light motion strategy. By that, Mercury moves a distance and then
uses this distance as a period of time to move another distance. By that the
distances be created in a network form.
- We don't know how a planet moves with low velocity can use distances values as
periods of time. The data needs more analysis to discover the rule on which this
using is done.
- Mercury motion aims to pass a distance = 5848 mkm= Mercury Pluto Distance,
this distance is the distinguish one in the 1st
trajectory of motion and also the 2nd
trajectory of motion. Many data be created in proportionality with this distance
which proves some geometrical machine be found behind these motions.
- Mercury moves the distance (5848 mkm) following light motion
- Mercury uses the rate (1 mkm= 1 solar day)
- Notice
- Jupiter Orbital Circumference (4900 mkm) is a very rich distance of discussions
and arguments. Because of that,
- Jupiter orbital circumference analysis be discussed in a separated point no. (5-4) .
- The idea is that, the light supposed velocity (1.16 mkm/s) creates a connection
between Mercury and Pluto by using Jupiter orbital circumference (4900). That
means, Jupiter orbital circumference be used as a central point in the light
trajectory of motion from Mercury to Pluto, because of that, the light supposed
velocity (1.16 mkm/s) created Jupiter orbital circumference (4900 mkm) by
different geometrical features which be required for this task. As a result we find
Jupiter orbital circumference is so complex distance and filled of questions.

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The Conclusions
- The data tells,
- Mercury is the origin point of the light supposed velocity (1.16 mkm/s) motion.
that means, the light starts its motion from Mercury point. (A Conclusion No. 1)
- The light supposed velocity (1.16 mkm/s) passes the distance (4900 mkm = Jupiter
orbital circumference) in a period (4224 seconds). By that the light connects
between Mercury motion and Jupiter motion. (A Conclusion No. 2)
- Mercury Day Period be less than (4224 hours) by 5040 seconds because light
supposed velocity (1.16 mkm/s) travels during 5040s a distance = (5848 mkm) =
(Mercury Pluto Distance)
- Light supposed velocity (1.16 mkm/s) uses (5040s) to pass the distance (5848
mkm) and create a connection between Mercury motion and Pluto motion. (A
Conclusion No. 3)
- Notice
- 5848 mkm (Mercury Pluto Distance) –4900 mkm (Jupiter orbital circumference) =
946.5 mkm
- Where
- 940 mkm = Earth Orbital Circumference (error 0.7%)
- The value (946.5 mkm) is very important we will discuss in 2nd
Trajectory of
motion because it's related to Saturn motion data.

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Mercury Motion Data Analysis (Continued)
- The previous data analysis concluded that, Mercury is the source of light supposed
velocity (1.16 mkm/s).
- So, let's ask,
- Is Mercury Motion data in harmony with light supposed velocity (1.16 mkm/s)?
(I)
- Light suppose velocity (1.16 mkm/s) needs only 50 seconds to pass Mercury
orbital distance (57.9 mkm).
- Can this (50 s) be a data belong to Mercury Motion?
- Mercury (47.4 km/s) moves during 50.3 s a distance = 2390 km (Pluto diameter)
- Mercury (47.4 km/s) moves during 50.3 m x 60 s a distance = 142984 km (Jupiter
diameter)
- Mercury Venus Distance = 50.3 mkm ( 1mkm = 1 second)
- Mercury Neptune Distance (4437 mkm) = 50.3 mkm x 88
- (Mercury Orbital Period =88 days)
- Mercury Pluto Distance (5848 mkm) = 50.3 mkm x 116.2
- (57.9 mkm Mercury orbital distance x2 = 115.8 mkm)
- The data shows that, the period 50.3 seconds is a value be used frequently by
Mercury motion data. and mercury moves during (50.3 s) a distance = Pluto
diameter and moves during (50.3 m) a distance = Jupiter diameter, showing that
the 2 planets are the same planets mentioned by the 1st
trajectory motion.
- The basic difficulty is that, the light motion creates geometrical effects which we
can't discover because we don’t know neither their rule nor their effects. We have
only some data be transported from a point to another and that creates difficulties
for the analysis process.

Jupiter And Mercury Motions Analysis

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