The Solar System Design Disproves Newton Theory

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
The Solar System Design Disproves Newton Theory
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –22nd
September 2021
Abstract
Paper hypothesis
- The Solar System Geometrical Design depends on Mars and Pluto Motions
Paper hypothesis Explanation
- The Solar Group is a machine of gears and each planet motion be used as a gear in
it, the planets motions be integrated one another and create one unified motion.
- This vision tells, the solar system distances must be created as a network designed
geometrically based on the planets positions and motions.
- The vision makes the solar group as a train and the planets as carriages in one train
- Accordingly, Planet motion can't be independent from the others'
- The dependency of motions among the planets depends on the planets motions
periods, because each planet creates its own rate of time to perform the integration
among the planets motions to create the planets unified general motion.
- Based on this vision, each planet position and motion data be defined in
comparison with the other planets positions and data. As a result, the planets
motions be similar to chess board pieces motions. each motion depends on the
others and be calculated geometrically
- The vision disproves The Sun Mass Gravity Of Newton, and also Planet Motion
Independency Concept which is inherited of Newton theory, because it tells the
solar system moves by one geometrical design creates the planets data and
motions.

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- And
- Mars was the second planet after Mercury, and Pluto was the Mercury Moon.
- Some great strike caused Mars and Pluto to migrate from their original orbital
distances to their current positions.
- By the planets migration, the solar system distances network be confused and
needed a repair and by that, the solar system design takes Mars and Pluto as the
basic 2 points to redesign the solar system distances Network
- The solar system design caused to create new 2 Planets (The moon and Saturn), to
support the solar system redesign process.
Paper Objective
- The paper explains the solar system design, proving that Newton Theory of the sun
mass gravity is mistaken (this discussion be the paper part No. (II) under the title
"The Solar System Creation Theory")
- The paper explains the changes be occurred by Mars and Pluto migration in the
solar system design, proving the planets migration event (Part no. (I) of this paper
under title (The Solar System Design Description)
Please scan the figure (ORCID)

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Paper Contents
Subject Page No.
1- Introduction 5
2- Methodology 8
Paper Part No. (II) The Solar System Design Description 10
3- Can The Solar Planets Motions Use Different Rates Of Time? 11
3-1 Preface 12
3-2 The Rates Of Time Using Proof Idea 13
3-3 The Planets Rates of time Definition 19
4- The Solar Planets Rates Of Time Analysis 23
4-1 Preface 24
4-2 Venus Motion Rate of time 25
4-3 Earth Motion Rate of time 27
4-4 Mars Motion Rate of time 29
4-5 Jupiter Motion Rate of time 31
4-6 Saturn Motion Rate of time 33
4-7 Uranus Motion Rate of time 35
4-8 Neptune Motion Rate of time 37
4-9 Pluto Motion Rate of time 39
4-10 The General Discussion 41
5- The Planets Orbital Distances Depend On Their Rates Of Time 43
5-1 Preface 44
5-2 The Planets Orbital Distances Test 45
5-3 Mars, Jupiter and Saturn Motions Analysis 50
5-4 The Required Periods Dependency (One Law Controls All Data) 55
5-5 Why Saturn And The Moon Use Equal Rates Of Time? 64
6- Mars Migration Theory 70
6-1 Mars Migration Theory 71
6-2 Pluto Migration Theory 74
6-3 Planets Migration Theories Proves 76
7- Planets Unified General Motion 79
7-1 The Planets Unified General Motion Description 80
7-2 The Solar Planets Motions Are Complementary One Another 82
7-3 The Solar Planets Move An Unified Motion (A Team Motion) 86
8- Mercury Motion Distance During Its Day Period 91
8-1 Preface 92
8-2 Why Mercury Jupiter Distance =720.7 mkm? 93
8-3 Pluto Motion For A Distance =720.7 mkm 97
8-4 Jupiter Motion In A Comparison With Light Motion 103
9- Jupiter orbital Circumference Analysis 108

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9-1 Preface 109
9-2 Jupiter orbital Circumference Analysis 110
10- Jupiter Motion Analysis 124
10-1 Preface 125
10-2 Jupiter Orbital Period Analysis 126
10-3 Jupiter Orbital Circumference More Discussion 134
10-4 Mars Rotation Period Analysis 138
Paper Part No. (II) The Solar System Creation Theory 149
11- The Solar System Creation Theory 150
11-1 Preface 151
11-2 The Solar System Creation Theory 152
11-3 The Inner Planets Motions Reason 158
11-4 Light Beam (1.16 mkm/sec) Proves Discussion 162
11-5 Saturn Motion More Analysis 200
11-6 Equal Distances Method 207
12-The Solar System Distances Be Created In A Network Form 213
12-1 Preface 214
12-2 The Continuum effect Through the Solar System Distances 216
12-3 The Solar System Distances Distribution 221
12-4 The Solar System Distances Dependency On One Another 225
13- The Planets Motions Rates Of Time (More Discussion) 227
13-1 Preface 228
13-2 Mercury Pluto Motions Rate of Time 229
13-3 Mercury Saturn Motions Rate of Time 233
13-4 Earth, its moon And Pluto Motions Rates Of Time 236
13-5 Earth And Saturn Motions Rates Of Time 245
14- The Sun Age Description 246
14-1 The Sun Circles The Earth 247
14-2 The Rate (1.0725) 248
14-3 The Sun Diameter Analysis 252
14-4 The Sun Rays Analysis 255
Appendix No. (1) The Moon Orbital Motion Equation 260
References and Biography 275

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1-Introdcution
- The solar system design is a meaning we need to define
- Because
- Newton theory of the sun mass gravity gives us this vision tells, the solar planet is
a rigid body separated from all other planets in its creation and motion data.
- The solar system design is a meaning tells that, The solar planets are created to be
integrated into one machine. There's a basic difference between the 2 meanings.
- Because
- Newton theory meaning tells that, the planets are created by some random process
and be moving by the sun mass gravity effect on them. That tells No Geometrical
Plan Or Design was found behind the solar planets creation.
- The solar system design vision tells, there's A Geometrical Design be found before
the solar planets creation.
- The visions are contradicting one another
- But
- The solar system design supposes many hypotheses or features of motions which
we don't attribute usually to the solar planets motions – for example –
- (1) The Unified General Motion be created by The Planets Motions Integration.
- (2) The Planets Motions Use Different Rates Of Time
- (3) The Solar System Distances Be Created In A Network Form
- These features no one attributes to any solar planet motion and need to be proved
before any real discussion about the planets motions.
- Because of that this paper be divided into 2 Parts, let's refer to them in following:
- Paper Part No. (I) (The Solar System Design Description)
- This part provides the proves for the features no (1) and (2), which are (the planets
unified motion and their using of different rates of time), in addition to the proves,
this paper part analyzes Jupiter motion data
- This part also proves Mars and Pluto Migration Event
- Paper Part No. (II) (The Solar System Creation Theory)

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- This part provides The solar system Creation Theory to explain the solar planets
motions features (in addition to, The 3 New Features Creation Reason)
- This part proves the feature no. (3) which is (The solar system distance be created
in a network form) and explain its reason.
Let's Refer In Details To The Paper Contents
Paper Part No. (I)
(A)
- The 2nd
feature (The Planets Motions Use Different Rates Of Time)
- This feature is proved in the points No. (3, 4 and 5) of this paper
(B)
- Mars and Pluto Migration Event, in addition to the moon and Saturn Creation
- These events are discussed and proved in Point No. (6)
(C)
- The 1st
feature (The Planets Motions Be integrated into one unified motion)
- This feature is proved in point No. (7)
(D)
- Jupiter Motion Analysis
- This subject is discussed proved in point No. (8 and 9)
- The sun creation event is discussed in point No. (10)
Paper Part No. (II)
- The Solar System Creation Theory is discussed in Point No.(11)
- The 3rd
feature (The solar system distances are created in a network form)
- This feature is proved in point No. (12)

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2-Methodology
- I use the planets motions data analysis in comparison with the theories which try to
explain the planets motions- let's use one example to explain how this method
works?
- Example No. 1
- Newton told us– The planet motion be independent from all other planets motions
- This is the theory – let's see some planets motions data for a comparison
- Data
(1)
Saturn Orbital Distance = Saturn Uranus Distance
= Mars Orbital Circumference
= Pluto Neptune Distance (error 1.5%)
= Pluto eccentricity Distance (error 1.5%)
= Neptune Orbital Distance/π
= Uranus Orbital Distance /2
(2)
Mercury Neptune Distance = Saturn Pluto Distance
Jupiter Pluto Distance = Uranus Neptune Circumference
Earth Neptune Distance = Mercury Saturn Circumference (0.5%)
(3)
Jupiter Mercury Distance = 2 Mercury Orbital Circumference
Jupiter Venus Distance = Venus Orbital Circumference (1.5%)
Jupiter Earth Distance = Earth Orbital Circumference (1.2%)
(Earth and Jupiter at 2 different sides from the sun)
(4)
Jupiter Mercury Distance = Mars Orbital Distance x π (0.6%)
Jupiter Uranus Distance = Venus Jupiter Circumference (0.8%)
Pluto Orbital Distance = Earth Orbital Circumference x 2π
Why These Distances Are Equal?

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- The solar system has around (45 distances) and these distance are around (25
distances) why they are equal one another? Can Planets Independent Motions
Cause These Distances Equality?
- In some desert someone sees a mirage and thought it's a water! How can we prove
to him that this is a mirage and Not a water?
- Newton told that, Planets Motions be Independent From One Another, and as a
result - The solar system distances be created based on each other in a Network
form where more than 50% of all distances are equal one another!!
- I try to show that –Newton Theory mistake is some how clear.
- The planets creations and motions data should be similar to a creature genes which
can tell us how this planet be created and moving – so whatsoever the theory be
the planets motions data be more important than it – and by that – even if Newton
was correct, there's no reason to neglect the planets motions.
- Let's use one more example
- Example No. 2
- 778.6 mkm = 1.0725 x 720.7 mkm (Mercury Jupiter Distance)
- 720.7 mkm = 1.0725 x 671 mkm (Venus Jupiter Distance)
- 671 mkm = 1.0725 x 629 mkm (Earth Jupiter Distance)
- 629 mkm = (1.0725)2
x 550.7 mkm (Mars Jupiter Distance)
- 550.7 mkm = (1.0725) x 511 mkm
- 4900 mkm = (1.0725) x 4495.1 mkm (Neptune Orbital Distance) (1.6%)
- 1375 mkm = (1.0725) x 1284 mkm (Earth Saturn Distance)
- 4900 mkm = Jupiter orbital circumference
- 1375mkm = Mercury Saturn Circumference
- The previous distances are 13 distances (30%) of all distances- they are example of
many others- the question is why they are rated with the same one rate (1.0725)?

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- I try to show, some geometrical design effects through the planets motions data.
This effect is stronger than any planet motion and force all of them to use the same
one rate (1.0725)– No Independent Motion Be Found Here – the data simply
disproves Newton Theory Of The Sun Mass Gravity and Planet Independency
Motion.
- The previous data is example for wide range of data – I add some more of them
here to show the strong force range of using this rate (1.0725)
- (28.3 deg / 26.7 deg) =(26.7 deg /25.2 deg) = (25.2 deg /23.4 deg) = (122.5 /115.2)
= (1.0725)
- Where
- 28.3 degrees = Neptune Axial Tilt
- 26.7 degrees = Saturn Axial Tilt
- 25.2 degrees = Mars Axial Tilt
- 23.4 degrees = Earth Axial Tilt
- 115.2 degrees = 90 degrees + 25.2 degrees (Mars Axial Tilt)
- 122.5 degrees = Pluto Axial Tilt.
- Shortly
- The planets data analysis put the data in comparison with the theories to test the
theory sufficiency.

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Paper Part No. (I)
The Solar System Design Description

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3- Can The Solar Planets Motions Use Different Rates Of Time?
3-1 Preface
3-2 The Rates Of Time Using Proof Idea
3-3 The Planets Rates of time Definition

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3-1 Preface
- The paper supposes that, The Solar Planets Use Different Rates Of Time
- The Rates of time is a meaning we have learnt from special theory of relativity,
and it means, for example, (1 h of Mercury motion =24.6 h of Jupiter motion), that
means, (While the clock moves 1 hour in Mercury the other clock moves 24.6
hours in Jupiter).
- We accept this meaning, and based on it, the paper supposes, Planets Motions Use
Different Rates Of Time.
- Now
- Can That Be A Fact?
- I have a proof for this idea, and the proof is useful to improve our understanding
for the solar planets motions data and its meaning.
- But
- The proof can prove that, the solar planets motions use different rates of time, but
can't explain why or how to do that. that means, I have a proof for a discovery but
how to explain this discovery I can't answer. The proof which I have provides the
fact but no a theoretical explanation be provided neither geometrical mechanism to
explain how these rates of time be created.
- Let's write the proof idea in the next point as clear as possible before to discuss it.

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3-2 The Proof Of The Rates Of Time Using.
- Let's summarize the proof idea in following…
(I)
- The solar planets rates of time be defined for any planet based on the period this
planet needs to move a distance = this planet orbital distance.
- Let's provide these periods for better explanation:
- Mercury needs a period =14.13 solar days to move a distance =57.9 mkm =
Mercury Orbital Distance (So the required period is 14.13 Solar Days)
- Venus needs a period =35.8 solar days to move a distance =108.2 mkm = Venus
Orbital Distance (So the required period is 35.8 Solar Days)
- Earth needs a period =58.1 solar days to move a distance =149.6 mkm = Earth
- The Earth moon a period =1700 solar days to move a distance =149.6 mkm =
Earth Orbital Distance by using its daily displacement 88000 km (So the required
period is 1700 Solar Days)
- Mars needs a period =109.4 solar days to move a distance =227.9 mkm =Mars
- Jupiter needs a period =687 solar days to move a distance =778.6 mkm = Jupiter
Orbital Distance (So the required period is 687 Solar Days)
- Saturn needs a period =1710 solar days to move a distance =1433.5 mkm = Saturn
- Uranus needs a period =4890 solar days to move a distance =2872.5 mkm =
Uranus Orbital Distance (So the required period is 4890 Solar Days)
- Neptune needs a period =9635 solar days to move a distance =4495.1 mkm =
Neptune Orbital Distance (So the required period is 9635 Solar Days)
- Pluto needs a period =14547 solar days to move a distance =5906 mkm =Pluto

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(II)
- The Planet Motion Rate of Time be defined depends on these periods.
- For example
- 58.1 days (Earth period) = 1.622 x 35.8 days (Venus Period)
- Means
- 1 hour of Venus Motion = 1.622 hours of Earth Motion
- This is the rate of time we search for. And by this method we define it clearly.
- Then
- This rate of time does 2 basic Job which are
- (1st
Job)
- The rate of time defines the planets orbital periods, because of that
- 365.25 days (Earth Orbital Period) = 1.622 x 224.7 days (Venus Orbital Period)
- This rule is used for all planets orbital periods, as we will prove that later in our
discussion.
- (2nd
Job)
- The rate of time defines the planets orbital distances, let's do that in following…
- 1 day of Venus Motion = 1.622 days of Earth Motion (this is the rate of time)
- But
- Venus during one solar day moves a distance =3.024 mkm
- Earth during 1.622 solar days moves a distance =4.176 mkm
- And
- (4.176 mkm /3.024 mkm) = (940 mkm /680 mkm)
- Where
- 940 mkm = Earth Orbital Circumference
- 680 mkm = Venus Orbital Circumference
- As the data shows, the rate of time defines the planets orbital circumferences.

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(III)
- Now the idea be clear
- The periods of planets motions for their orbital distances define the rates of time be
used by these planets motions..
- And
- These rates of time define all planets orbital periods and distances
- This is a good understanding for the planets data
- But
- What do we need?
- We need to know if the planets motions required periods be defined independently
or dependently on one another…
- Now
- We have 2 different visions as result for these 2 options. Let's explain that in
following as clear as possible
- (1st
Option)
- If the planets required periods be defined independently for each planet, that
means, each planet motion can be independent from one another. because the
periods are independent periods from one another
- (2nd
Option)
- If the planets periods be defined dependently on one another, that will make the
solar group as one machine of gears.
- The solar planets in this case will be similar to carriages in one train which move
together one unified motion. or the planets be similar to gears in one machine of
gears. They move one unified motion.
- Or Better Example,
- the solar planets be similar to a mechanical clock, each planet is a gear in the
mechanical clock and causes to create a rate of time as a part of the machine
general rate of time.

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- I want to say that,
- The second option of the periods dependency on one another isn’t so simple option
but it's a very effective option and even its effect be understood by any student of
astrophysics, because
- The planets orbital periods and distances be defined based on the motions rates of
time which are defined based on these required periods the planets need to pass
their orbital distances- So If these periods be created based on one another – that
makes all planets orbital periods and distances be defined based on one another.
- Shortly, that means,
- We don't need to observe to know any planet orbital period or distance, if any data
of it be absent, we can simply conclude it by using the rates of time – the second
option simply changes the solar planets data into data be defined by one Equation
only and by that we can remove all planets data (periods and distances) and can
conclude them correctly by using the rates of time
- Shortly
- If the planets required periods be defined based on one law and not independently
from one another the whole vision of the solar system will be changed by a very
strong proof
- To make this discussion more interesting, I want to say that,
- There's one law controls all planets required periods of time to move their orbital
periods. And this one law disproves and refuted completely Newton Theory of the
sun mass gravity and Planet Motion Independency Concept which be inherited
form Newton theory.
- We simply have a chance to create a progress in the solar system motion
understanding.
- So, Let's Summarize Our Discussion Steps In Following

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(IV)
- We Should Follow The Following Steps In Our Discussion
- (1st
Step)
- The Planets Motions Rates Of Time Definition
- And
- The Planets Orbital Periods Definition Based On The Rates Of Time
- (2nd
Step)
- The Planets Orbital Distances Definition Based On The Rates Of Time
- (3rd
Step)
- We discuss one law controls the planets required periods for the solar planets
orbital distances motions.
(V)
- We should notice that
- The previous steps are steps for data providing, that means, these steps are
methods to arrange the data
- Because
- I prove that, the planets motions use different rates of time. In this proof discussion
I provide the data in some arrangement to show that this data be understandable
only based on the hypothesis of the planets motions different rates of time.
- By that, these steps are a method of Data arrangement.
- Means
- We don't discuss the question (how the planets motion use different rate of time?)
neither the question (why the planets motions use different rates of time?) because,
we try to prove the discovery which is (the planets motions use different rates of
time), and to prove that, I put the planets data in the best arrangement form by
using these 3 steps to show that, this data can't be understandable except by using
the hypothesis (the planets motions use different rates of time).
- So, our process aims basically to prove this fact

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- Then
- We should analyze the planets required periods for their orbital distances motions
to prove that one law controls all periods and by that we can change the solar
system current description. for that reason the periods should be analyzed in a
separated dedicated point.
- I want to say
- We have to provide the data which prove the hypothesis (the planets motions use
different rates of time)
- After the proof discussion be completed we have to start the solar system
description discussion because one great effect be done as a result for the
hypothesis proof and the one law proof.
- Let's explain how we arrange the planets data in following:
- In next point (3-3) we provide Mercury Rates of time as an example and use it to
define all planets orbital periods based on Mercury Day Period
- Mercury is an example, and we should do the same job with each planet, for that
we dedicate the next point (NO. 4) for all planets rates of time test. Based on that,
- Mercury is our example for test and
- All planets periods be tested as Mercury rate in (Point No. 4)
- Then
- In point no. (5) we prove that, all planets orbital distances be defined based on the
planets motions rates of time.
- And in this point we prove that one law controls all periods

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3-3 The Planets Rates Of Time Definition
(I)
The Required Periods For The Solar Planets Orbital Distances Motions Are
- Mercury needs 14.13 Solar Days (27.9 Solar Days)
- Venus needs 35.8 Solar Days
- Earth needs 58.1 Solar Days
- The moon needs 1700 Solar Days
- Mars needs 109.4 Solar Days
- Jupiter needs 687 Solar Days
- Saturn needs 1710 Solar Days
- Uranus needs 4890 Solar Days
- Neptune needs 9635 Solar Days
- Pluto needs 14547 Solar Days
- The rates between these period define the rates of time used by each planet in
comparison with other – as we will explain in following
- But
- For Mercury we use the period (27.9 solar days) = (2 x 14.13 days) (error 1%) ,
because Mercury uses its Day Period and not its orbital period and also uses the
distance 720.7 mkm and not Mercury orbital circumference 360 mkm. This Data
Mercury uses because of some geometrical necessity we should explain in a point
no (8-2) in which we analyze the period of time Mercury needs to pass a distance =
its orbital distance.
- For now we use for Mercury the period (27.9 Solar Days) and we explain the
reason in this point (8-2).

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(II)
- Mercury Motions Rates Of Time
- (35.8 /27.9) = 1.279, means
- 1 hour of Mercury Motion = 1.28 hours of Venus Motion
- (58.1 /27.9) = 2.078, means
- 1 hour of Mercury Motion = 2.078 hours of Earth Motion
- (1700 /27.9) = 60.8, means
- 1 hour of Mercury Motion = 60.8 hours of The Moon Motion
- (109.4 /27.9) = 3.91, means
- 1 hour of Mercury Motion = 3.91 hours of Mars Motion
- (687 /27.9) = 24.6, means
- 1 hour of Mercury Motion = 24.6 hours of Jupiter Motion
- (1710 /27.9) = 61.1, means
- 1 hour of Mercury Motion = 3.91 hours of Saturn Motion
- (4890 /27.9) = 174.8, means
- 1 hour of Mercury Motion = 174.8 hours of Uranus Motion
- (9635 /27.9) = 344.8, means
- 1 hour of Mercury Motion = 344.8 hours of Neptune Motion
- (14547 /27.9) = 520.2, means
- 1 hour of Mercury Motion = 520.2 hours of Pluto Motion

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MERCURY MOTION RATES OF TIME LIST
1 hour of Mercury motion = 1.279 h of Venus Motion
1 hour of Mercury motion = 2.078 h of Earth Motion
1 hour of Mercury motion = 3.91 h of Mars Motion
1 hour of Mercury motion = 24.6 h of Jupiter Motion
1 hour of Mercury motion = 61.1 h of Saturn Motion
1 hour of Mercury motion = 174.8 h of Uranus Motion
1 hour of Mercury motion = 344.6 h of Neptune Motion
1 hour of Mercury motion = 520.2 h of Pluto Motion
1 hour of Mercury motion = 60.8 h of The Earth Moon Motion
- Notice
- The list tells, Saturn and the Moon use equal rate of time!! Why? we should
answer that in point no. (5-5) of this paper
- Now
- Can these rates of time define the planets orbital periods? Let's do that in
following:

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Mercury Rates Of Time Test
224.7 days (Venus orbital period) = 1.279 x 175.94 days (Mercury Day Period)
365.25 days (Earth orbital period) = 2.078 x 175.94 days (Mercury Day Period)
687 days (Mars orbital period) = 3.91 x 175.94 days (Mercury Day Period)
4331 days (Jupiter orbital period) = 24.6 x 175.94 days (Mercury Day Period)
10747 days (Saturn orbital period) = 61.1 x 175.94 days (Mercury Day Period)
30589 days (Uranus orbital period) = 174.8 x 175.94 days (Mercury Day Period)
59800 days (Neptune orbital period) = 344.6 x 175.94 days (Mercury Day Period)
90560 days (Pluto orbital period) = 520.2 x 175.94 days (Mercury Day Period)
- The errors are 1.4% and 1% with Neptune and Pluto orbital periods respectively,
no other error more than 1%
- The data tells, Mercury rate of time defines all planets orbital periods based on
Mercury Day Period.
- The data tells that, the planets orbital period be created in proportionality with one
another.
- We have to test all planets rates of time as Mercury to know if all periods be
definition correctly similar to Mercury test. For that reason we will test all planets
periods of time in the next point (No.4)

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4- The Solar Planets Rates Of Time Analysis
4-1 Preface
4-2 Venus Motion Rate of time
4-3 Earth Motion Rate of time
4-4 Mars Motion Rate of time
4-5 Jupiter Motion Rate of time
4-6 Saturn Motion Rate of time
4-7 Uranus Motion Rate of time
4-8 Neptune Motion Rate of time
4-9 Pluto Motion Rate of time
4-10 The General Discussion

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4-1 Preface
- In this point we test the planets motions rates of time definition as we have done
with mercury in the previous point. We bring Mercury test here in this preface to
be a reference for the other planets test.
MERCURY LIST
224.7 days (Venus orbital period) = 1.279 x 175.94 days (Mercury Day Period)
365.25 days (Earth orbital period) = 2.078 x 175.94 days (Mercury Day Period)
687 days (Mars orbital period) = 3.91 x 175.94 days (Mercury Day Period)
4331 days (Jupiter orbital period) = 24.6 x 175.94 days (Mercury Day Period)
10747 days (Saturn orbital period) = 61.1 x 175.94 days (Mercury Day Period)
30589 days (Uranus orbital period) = 174.8 x 175.94 days (Mercury Day Period)
59800 days (Neptune orbital period) = 344.6 x 175.94 days (Mercury Day Period)
90560 days (Pluto orbital period) = 520.2 x 175.94 days (Mercury Day Period)
Errors are 1.4% 1% with Neptune and Pluto respectively
- Each point uses a similar test with a planet of the solar group in order
- In point no. (4-10) we provide the general discussion of all data.

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4-2 Venus Motion Rate Of Time
I – Data
VENUS MOTION LIST
1 hour of Venus motion = (0.78) h of Mercury Motion
1 hour of Venus motion = 1.62 h of Earth Motion
1 hour of Venus motion = 3.057 h of Mars Motion
1 hour of Venus motion = 19.233 h of Jupiter Motion
1 hour of Venus motion = 47.8 h of Saturn Motion
1 hour of Venus motion = 136.7 h of Uranus Motion
1 hour of Venus motion = 269.4 h of Neptune Motion
1 hour of Venus motion = 406.7 h of Pluto Motion
1 hour of Venus motion = 47.54 h of The Moon Motion
- In Following We Provide The Data Analysis

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II–Data Analysis
175.94 days (Mercury day period) = 0.78 x 224.7 days (Venus orbital period)
365.25 days (Earth orbital period) = 1.62 x 224.7 days (Venus orbital period)
687 days (Mars orbital period) = 3.057 x 224.7 days (Venus orbital period)
4331 days (Jupiter orbital period) = 19.2 x 224.7 days (Venus orbital period)
10747 days (Saturn orbital period) = 47.8 x 224.7 days (Venus orbital period)
30589 days (Uranus orbital period) = 136.7 x 224.7 days (Venus orbital period)
59800 days (Neptune orbital period) = 266.2 x 224.7 days (Venus orbital period)
90560 days (Pluto orbital period) = 403 x 224.7 days (Venus orbital period)
- There Are Errors (1%) Only With Neptune And Pluto Orbital Periods
- Shortly
- All planets orbital periods be created based on Venus orbital period (224.7 days)
by using the rates of time between Venus and these planets –
- No error in all data more than 1% -
- The Data Proves That – The Rate of Time Controls The Solar System motion

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4-3 Earth Motion Rate Of Time
I – Data
EARTH MOTION LIST
1 hour of Earth motion = (0.48) h of Mercury Motion
1 hour of Earth motion = (0.617) h of Venus Motion
1 hour of Earth motion = 1.88 h of Mars Motion
1 hour of Earth motion = 11.8 h of Jupiter Motion
1 hour of Earth motion = 29.4 h of Saturn Motion
1 hour of Earth motion = 84.1 h of Uranus Motion
1 hour of Earth motion = 165.8 h of Neptune Motion
1 hour of Earth motion = 250.4 h of Pluto Motion
1 hour of Earth motion = 29.3 h of The Moon Motion

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II–Data Analysis
175.94 days (Mercury day period) = 0.48 x 365.25 days (Earth orbital period)
224.7 days (Venus orbital period) = 0.617 x 365.25 days (Earth orbital period)
687 days (Mars orbital period ) = 1.88 x 365.25 days (Earth orbital period)
4331 days (Jupiter orbital period) = 11.8 x 365.25 days (Earth orbital period)
10747 days (Saturn orbital period) = 29.4 x 365.25 days (Earth orbital period)
30589 days (Uranus orbital period) = 84.1 x 365.25 days (Earth orbital period)
59800 days (Neptune orbital period) = 163.8 x 365.25 days (Earth orbital period)
90560 days (Pluto orbital period) = 248 x 365.25 days (Earth orbital period)
- Errors (1.2% and 1%) With Neptune And Pluto Orbital Periods Respectively
- Shortly
- All planets orbital periods be created based on Earth orbital period (365.25 days)
by using the rates of time between Earth and these planets –
- No other error in all data more than 1% -

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4-4 Mars Motion Rate Of Time
I – Data
MARS MOTION LIST
1 hour of Mars motion = (0.255) h of Mercury Motion
1 hour of Mars motion = (0.327) h of Venus Motion
1 hour of Mars motion = (0.531) h of Earth Motion
1 hour of Mars motion = 6.3 h of Jupiter Motion
1 hour of Mars motion = 15.6 h of Saturn Motion
1 hour of Mars motion = 44.71 h of Uranus Motion
1 hour of Mars motion = 88.1 h of Neptune Motion
1 hour of Mars motion = 133 h of Pluto Motion
1 hour of Mars motion = 15.55 h of The Moon Motion

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II–Data Analysis
175.94 days (Mercury day period) = 0.255 x 687 days (Mars Orbital Period)
224.7 days (Venus orbital period) = 0.327 x 687 days (Mars Orbital Period)
365.25 days (Earth orbital period = 0.531 x 687 days (Mars Orbital Period)
4331 days (Jupiter orbital period) = 6.3 x 687 days (Mars Orbital Period)
10747 days (Saturn orbital period) = 15.6 x 687 days (Mars Orbital Period)
30589 days (Uranus orbital period) = 44.7 x 687 days (Mars Orbital Period)
59800 days (Neptune orbital period) = 88.1 x 687 days (Mars Orbital Period)
90560 days (Pluto orbital period) = 133 x 687 days (Mars Orbital Period)
- Errors (1.2% and 1%) With Neptune And Pluto Orbital Periods Respectively
- Shortly
- All planets orbital periods be created based on Mars orbital period (687 days) by
using the rates of time between Mars and these planets

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4-5 Jupiter Motion Rate Of Time
I – Data
JUPITER MOTION LIST
1 hour of Jupiter motion = (0.040) h of Mercury Motion
1 hour of Jupiter motion = (0.0419) h of Venus Motion
1 hour of Jupiter motion = (0.084) h of Earth Motion
1 hour of Jupiter motion = (0.1589) h of Mars Motion
1 hour of Jupiter motion = 2.48 h of Saturn Motion
1 hour of Jupiter motion = 7.1 h of Uranus Motion
1 hour of Jupiter motion = 14 h of Neptune Motion
1 hour of Jupiter motion = 21.1 h of Pluto Motion
1 hour of Jupiter motion = 2.47 h of The Moon Motion

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II–Data Analysis
175.94 days (Mercury day period) = 0.040 x 4331 days (Jupiter Orbital Period)
224.7 days (Venus orbital period) = 0.0419 x 4331 days (Jupiter Orbital Period)
365.25 days (Earth orbital period = 0.084 x 4331 days (Jupiter Orbital Period)
687 days (Mars orbital period) = 0.1589 x 4331 days (Jupiter Orbital Period)
10747 days (Saturn orbital period) = 2.48 x 4331 days (Jupiter Orbital Period)
30589 days (Uranus orbital period) = 7.1 x 4331 days (Jupiter Orbital Period)
59800 days (Neptune orbital period) = 14 x 4331 days (Jupiter Orbital Period)
90560 days (Pluto orbital period) = 21.1 x 4331 days (Jupiter Orbital Period)
- Errors (1.4% and 1%) With Neptune And Pluto Periods respectively
- All planets orbital periods be created based on Jupiter orbital period (4331days)
by using the rates of time between Jupiter and these planets

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4-6 Saturn Motion Rate Of Time
I – Data
SATURN MOTION LIST
1 hour of Saturn motion = (0.016) h of Mercury Motion
1 hour of Saturn motion = (0.0209) h of Venus Motion
1 hour of Saturn motion = (0.0339) h of Earth Motion
1 hour of Saturn motion = (0.0639) h of Mars Motion
1 hour of Saturn motion = (0.403) h of Jupiter Motion
1 hour of Saturn motion = 2.857 h of Uranus Motion
1 hour of Saturn motion = 5.63 h of Neptune Motion
1 hour of Saturn motion = 8.5 h of Pluto Motion
1 hour of Saturn motion = 1 h of The Moon Motion

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II–Data Analysis
175.94 days (Mercury day period) = 0.040 x 10747 days (Saturn Orbital Period)
224.7 days (Venus orbital period) = 0.0209 x 10747 days (Saturn Orbital Period)
365.25 days (Earth orbital period = 0.0339 x 10747 days (Saturn Orbital Period)
687 days (Mars orbital period) = 0.0639 x 10747 days (Saturn Orbital Period)
4331 days (Jupiter orbital period) = 0.403 x 10747 days (Saturn Orbital Period)
30589 days (Uranus orbital period) = 2.857 x 10747 days (Saturn Orbital Period)
59800 days (Neptune orbital period) = 5.63 x 10747 days (Saturn Orbital Period)
90560 days (Pluto orbital period) = 8.5 x 10747 days (Saturn Orbital Period)
- Errors (1%) Only With Neptune And Pluto Orbital Periods
- Shortly
- All planets orbital periods be created based on Saturn orbital period (10747 days)
by using the rates of time between Saturn and these planets

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4-7 Uranus Motion Rate Of Time
I – Data
URANUS MOTION LIST
1 hour of Uranus motion = (0.0057) h of Mercury Motion
1 hour of Uranus motion = (0.0073) h of Venus Motion
1 hour of Uranus motion = (0.011) h of Earth Motion
1 hour of Uranus motion = (0.022) h of Mars Motion
1 hour of Uranus motion = (0.14) h of Jupiter Motion
1 hour of Uranus motion = (0.3499) h of Saturn Motion
1 hour of Uranus motion = 1.97 h of Neptune Motion
1 hour of Uranus motion = 2.97 h of Pluto Motion
1 hour of Uranus motion = (0.349) h of The Moon Motion

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II–Data Analysis
175.94 days (Mercury day period) = 0.0057 x 30589 days ( Uranus Orbital Period)
224.7 days (Venus orbital period) = 0.0073 x 30589 days ( Uranus Orbital Period)
365.25 days (Earth orbital period = 0.011 x 30589 days ( Uranus Orbital Period)
687 days (Mars orbital period) = 0.022 x 30589 days ( Uranus Orbital Period)
4331 days (Jupiter orbital period) = 0.14 x 30589 days ( Uranus Orbital Period)
10747 days (Saturn orbital period) = 0.3499 x 30589 days (Uranus Orbital Period)
59800 days (Neptune orbital period) = 1.97 x 30589 days ( Uranus Orbital Period)
90560 days (Pluto orbital period) = 2.97 x 30589 days ( Uranus Orbital Period)
- No Error In All Data More Than 1% -
- All planets orbital periods be created based on Uranus orbital period (30589 days)
by using the rates of time between Uranus and these planets

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4-8 Neptune Motion Rate Of Time
I – Data
NEPTUNE MOTION LIST
1 hour of Neptune motion = (0.0029) h of Mercury Motion
1 hour of Neptune motion = (0.0037) h of Venus Motion
1 hour of Neptune motion = (0.006) h of Earth Motion
1 hour of Neptune motion = (0.011) h of Mars Motion
1 hour of Neptune motion = (0.0713) h of Jupiter Motion
1 hour of Neptune motion = (0.177) h of Saturn Motion
1 hour of Neptune motion = (0.507) h of Uranus Motion
1 hour of Neptune motion = 1.509 h of Pluto Motion
1 hour of Neptune motion = (0.1773) h of The Moon Motion

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II–Data Analysis
175.94 days (Mercury day period) = 0.0029 x 59800 days (Neptune Orbital Period)
224.7 days (Venus orbital period) = 0.0037 x 59800 days (Neptune Orbital Period)
365.25 days (Earth orbital period = 0.006 x 59800 days (Neptune Orbital Period)
687 days (Mars orbital period) = 0.011 x 59800 days (Neptune Orbital Period)
4331 days (Jupiter orbital period) = 0.0713 x 59800 days (Neptune Orbital Period)
10747 days (Saturn orbital period) = 0.177 x 59800 days (Neptune Orbital Period)
30589 days (Uranus orbital period) = 0.507 x 59800 days (Neptune Orbital Period)
90560 days (Pluto orbital period) = 1.509 x 59800 days (Neptune Orbital Period)
- Neptune orbital period creates an error 1.3% with all data except Pluto and
Uranus
- All planets orbital periods be created based on Neptune orbital period (59800 days)
by using the rates of time between Neptune and these planets

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4-9 Pluto Motion Rate of time
I – Data
PLUTO MOTION LIST
1 hour of Pluto motion = (0.00192) h of Mercury Motion
1 hour of Pluto motion = (0.00245) h of Venus Motion
1 hour of Pluto motion = (0.00399) h of Earth Motion
1 hour of Pluto motion = (0.0075) h of Mars Motion
1 hour of Pluto motion = (0.0472) h of Jupiter Motion
1 hour of Pluto motion = (0.1174) h of Saturn Motion
1 hour of Pluto motion = (0.336) h of Uranus Motion
1 hour of Pluto motion = (0.662) h of Neptune Motion
1 hour of Pluto motion = (0.11743) h of The Moon Motion

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II–Data Analysis
175.94 days (Mercury day period) = 0.00192 x 90560 days (Pluto Orbital Period)
224.7 days (Venus orbital period) = 0.00245 x 90560 days (Pluto Orbital Period)
365.25 days (Earth orbital period = 0.00399 x 90560 days (Pluto Orbital Period)
687 days (Mars orbital period) = 0.0075 x 90560 days (Pluto Orbital Period)
4331 days (Jupiter orbital period) = 0.0472 x 90560 days (Pluto Orbital Period)
10747 days (Saturn orbital period) = 0.1174 x 90560 days (Pluto Orbital Period)
30589 days (Uranus orbital period) = 0.336 x 90560 days (Pluto Orbital Period)
59800 days (Neptune orbital period) = 0.662 x 90560 days (Pluto Orbital Period)
- Pluto orbital period creates error 1% with all data.
- No error In All Data More Than 1% -
- All planets orbital periods be created based on Pluto orbital period (90560 days)
by using the rates of time between Pluto and these planets –
The Data Proves That – The Rate of Time Controls The Solar System motion

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4-10 The General Discussion
- Shortly
- The data shows that
- All Planets Orbital Periods are rated with one another by the rates of time we
have calculated based the required periods for the solar planets orbital distances
motions.
- Why?
- If the solar planets motions are independent from one another, how all planets
orbital periods be defined based on these rates?
- In the next point (No.5) we prove that, the solar planets orbital distances be created
depending on these rates of time also. How that can be possible?
- Why all planets orbital periods and distances be defined based on these rates of
time?
- BUT
- We should keep an eye on the required periods because they are the source based
on which the rates of time be created.
- And
- The question should be,
- Are these required periods be defined independently from one another? or all these
periods be defined based on one another by using one law only?
- I want to say,
- We have to know perfectly the answer of this question, because if there's one law
or one Equation by which the planets required periods can be defined that
summarizes all data of the solar planets orbital periods and distances into one
Equation only
- In this case we can use the one equation in place of all planets orbital periods and
distances, and as a result no need for any observation for this data because we can
conclude them theoretically

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- That's why we need to move step by step in our discussion, and proves each step
strongly because it will result one equation is place of ten planets orbital periods
and distances.
- After we do that, we have to discuss the reason behind.
- Now let's move to the next point to prove,
- The Planets Orbital Distances Be Defined Based On These Rates Of Time.
- NOTICE
- If we prove that, the solar planets distances be based on these rates of time, the
solar group description should be changed into the following one…
- (Solar Group Is)
- The Solar Group is similar to a machine of gears each planet is a gear in it, or
- The Solar Group is similar to one building and each planet is a part of this same
building, or
- The Solar Group is similar to one body and each planet is a member of it, or
- The Solar Group is similar to puppets theater, all puppets are connected together
by one force and causes their motions, or
- The Solar Group is similar a canal, the water moves through it and causes the
rotation of 9 waterwheels. The Motion Direction of The waterwheels is different
from the water motion direction but no waterwheel can rotate without the water
motion, or
- The solar planets are similar to train carriages, they move together one unified
general motion, or
- The solar planets be similar to knots on one robe or similar to points on the same
one trajectory of energy –
- The solar planets motions be similar to chess board pieces motions, each motion
depend on the other planets motions and be done by geometrical calculations.
- Clearly
- The Planets Move One Unified Motion Be Done In Equal Periods Of Time

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5- The Planets Orbital Distances Depend On Their Rates Of Time
5-1 Preface
5-2 The Planets Orbital Distances Test
5-3 Mars, Jupiter and Saturn Motions Analysis
5-4 The Required Periods Dependency (One Law Controls All Data)
5-5 Why Saturn And The Moon Use Equal Rates Of Time?

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5-1 Preface
- In this point we prove that,
- The Planets Rates Of Time Define The Planets Orbital Distances.
- This discussion is seen so simple one but it presents a heavy claim.
- Because
- The planets rates of time provides the chance to discover how the planets motions
data be created. for example, Saturn orbital Distance = 2π x Mars Orbital Distance,
frequently we have asked Why? but no answer be available – and then
- The planets rates of time gives us the chance to answer this question, and not only
this question, but also many interesting data be found among Mars, Jupiter and
Saturn which was always puzzled data, be understandable now and can be
explained.
- We should discuss this data and explain how they are created in point no. (5-3),
- Let's in the direct next point prove that the solar planets orbital distances be
defined depending on the planets motions rates of time.

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5-2 The Planets Orbital Distances Test
I- Data
Mercury Rates Of Time
The Motions Distances Based On Mercury Rates Of Time
(1)
Mercury (4.095 mkm / solar day) moves during 1 day a distance =4.095 mkm
(2)
Venus (3.024 mkm / solar day) moves during 1.279 days a distance =3.867 mkm
(3)
Earth (2.574 mkm / solar day) moves during 2.078 days a distance = 5.35 mkm
(4)
Mars (2.082 mkm / solar day) moves during 3.91 days a distance = 8.14 mkm
(5)
Jupiter (1.13184 mkm / solar day) moves during 24.6 days a distance = 27.8 mkm
(6)
Saturn (0.838 mkm / solar day) moves during 61.1 days a distance = 51.2 mkm
(7)
Uranus (0.5875 mkm / solar day) moves during 174.8 days a distance = 102.7 mkm
(8)
Neptune (0.4665 mkm / solar day) moves during 344.8 days a distance = 160.8 mkm
(9)
Pluto (0.406 mkm / solar day) moves during 520.2 days a distance = 211.2 mkm

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II- Data Analysis
No. (2)
(Venus motion distance=3.867 mkm) /(Mercury Motion Distance 4.095 mkm) =0.944
Where
(Venus orbital circumference =680 mkm) /(Mercury Distance 720.7 mkm) =0.944
No. (3)
(Earth motion distance=5.35 mkm) /(Mercury Motion Distance 4.095 mkm) =1.3
Where
(Earth orbital circumference =940 mkm) /(Mercury Distance 720.7 mkm) = 1.3
No. (4)
(Mars motion distance=8.14 mkm) /(Mercury Motion Distance 4.095 mkm) = 1.98
Where
(Mars orbital circumference =1433 mkm) /(Mercury Distance 720.7 mkm) = 1.98
No. (5)
(Jupiter motion distance=27.8 mkm) /(Mercury Motion Distance 4.095 mkm) = 6.8
Where
(Jupiter orbital circumference =4900 mkm) /(Mercury Distance 720.7 mkm) = 6.8
No. (6)
(Saturn motion distance=51.2 mkm) /(Mercury Motion Distance 4.095 mkm) = 12.5
Where
(Saturn orbital circumference =9010 mkm) /(Mercury Distance 720.7 mkm) = 12.5
No. (7)
(Uranus motion distance =102.7 mkm) /(Mercury Motion Distance 4.095 mkm) =25.1
Where
(Uranus orbital circumference =18048 mkm) /(Mercury Distance 720.7 mkm) = 25.1

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No. (8)
(Neptune motion distance =161 mkm) /(Mercury Motion Distance 4.095 mkm) =39.3
Where
(Neptune orbital circumference =28255 mkm) /(Mercury Distance 720.7 mkm) = 39.3
No. (9)
(Pluto motion distance =211.2 mkm) /(Mercury Motion Distance 4.095 mkm) =51.6
Where
(Pluto orbital circumference =37100 mkm) /(Mercury Distance 720.7 mkm) = 51.6
- Let's discuss the previous data in following:

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III- Discussion
- The data proves that
- The solar planets orbital circumferences are defined depending on these planets
motions rates of time.
- Based on that,
- The planets motions rates of time define the solar planets orbital periods and
distances. By that we have a huge number of data depend on a small group of data.
- Means,
- The solar planets periods and distances are defined as function in the planets
motions rates of time. And these rates of time be defined based on the required
periods for the planets orbital distances motions.
- Shortly
- It tells, if we have the required periods we can calculate all solar planets orbital
distances and periods.
- Now, the question is,
- Are these required periods be defined based on one another or independently from
one another?
- The question = All Distances And Periods In The Solar System
- Because
- If the required periods be defined based on one another and we can use One
Equation to calculate all these required periods – that will summarize all solar
planets periods and distances into One Equation.
- That shows the importance behind this discussion.
- After we find the (one equation) which controls all required periods of the solar
planets, we will not need to observe the planets orbital distances or periods…!
- Because, we can calculate them theoretically by using One Equation
- Now
- Let's use the rates of time to explain the puzzled data of Mars, Jupiter And Saturn

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- Notice
- Mercury uses the distance 720.7 mkm in place of its orbital circumference 360
mkm, and use its day period 175.95 solar days in place of its orbital period and use
the period 671 hours to move a distance = 2 x 57.2 mkm (Mercury orbital distance)
(error 1%)
- We should discus why Mercury uses its (double) values (the only and unique
planet does that)
- We note that, If we use Mercury values as other planets (360 mkm, 88 days and
57.9 mkm) in this case the rates with the planets will not change and works
normally, but Mercury uses its double values for one important geometrical
necessity which we should discuss in a separated point No. (8)

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5-3 Mars, Jupiter And Saturn Motions Analysis
- In this point we use the planets motions rates of time to explain the puzzled data
we have referred to it frequently before
- Let's take a look on this puzzled data in following:
- 4331 days (Jupiter Orbital Period) =2π x 687 days (Mars Orbital Period)
- 1433 mkm (Saturn Orbital Distance) =2π x227.9 mkm (Mars Orbital Distance)
- 10747 days (Jupiter Orbital Period) = 2.5 x1433 mkm (Saturn Orbital Distance)
- 24.1 km/s (Mars Velocity) =2.5 x 9.7 km/s (Saturn Velocity)
- 24.6 h (Mars rotation period) =2.5 x 9.9 h (Jupiter Day Period)
- Saturn Orbital Inclination = 2.5 degrees
- Let's use the planets motions rates of time to help us to answer how the data be
created…

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I - Data
(5-3-a)
- 1 hour of Mars Motion = 6.3 hours of Jupiter Motion = 15.56 hours of Saturn
Motion = 44.6 hours of Uranus Motion = 88 hours of Neptune motion = 132.7
hours of Pluto motion
(5-3-b)
- 4331 days (Jupiter Orbital Period) =2π x 687 days (Mars Orbital Period)
- 1433 mkm (Saturn Orbital Distance) =2π x227.9 mkm (Mars Orbital Distance)
- 10747 days (Jupiter Orbital Period) = 2.5 x1433 mkm (Saturn Orbital Distance)
- 24.1 km/s (Mars Velocity) =2.5 x 9.7 km/s (Saturn Velocity)
- 24.6 h (Mars rotation period) =2.5 x 9.9 h (Jupiter Day Period)
- Saturn Orbital Inclination = 2.5 degrees

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II –Discussion
Equation no. (5-3-a)
- 1 hour of Mars Motion = 6.3 hours of Jupiter Motion = 15.56 hours of Saturn
Motion = 44.6 hours of Uranus Motion = 88 hours of Neptune motion = 132.7
hours of Pluto motion
- These rates of time we have concluded in point no. (4) of this paper.
- Based on the equation no. (5-3-a) we conclude the following
- 1 Solar Day of Mars Motion = 6.3 Solar Days of Jupiter Motion = 15.56 Solar
Days of Saturn Motion = 44.6 Solar Days of Uranus Motion = 88 Solar Days
of Neptune motion = 132.7 Solar Days of Pluto motion.
- Let's define the distances which these planets pass during these periods of time
- Mars (2.08 mkm per solar day) moves during 1 solar day a distance = 2.082 mkm
- Jupiter (1.1318 mkm per day) moves during 6.3 solar days a distance = 7.13 mkm
- Saturn (0.838 mkm per day) moves during 15.56 solar days a distance =13.1 mkm
- Uranus (0.5875 mkm per day) moves during 44.6 days a distance=26.22 mkm
- Neptune (0.466560 mkm per day) moves during 88 days a distance = 41.05 mkm
- Pluto (0.406 mkm per day) moves during 132.7 solar days a distance =53.88 mkm
- Based on that
- Mars during (1 solar day) moves 2.082 mkm
- Jupiter during (6.3 solar day) moves 7.13 mkm
- Saturn during (15.5 solar day) moves 13.1 mkm
- Uranus during (44.6 solar day) moves 26.22 mkm
- Neptune during (88 solar day) moves 41.05 mkm
- Pluto during (132.7 solar day) moves 53.88 mkm

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Data Analysis
(1)
- Saturn motion distance = 13.1 mkm = Mars Motion Distance 2.08 mkm x 2π
- This data explains why
- Saturn orbital circumference 9007 mkm = Mars orbital circumference 1433
mkm x 2π
(2)
- Uranus motion distance = 26.22 mkm = Saturn Motion Distance 13.1 mkm x 2
- Uranus orbital circumference 18048 mkm = Saturn orbital circumference
9007 mkm x 2
(3)
- Neptune motion distance =41.05 mkm =Saturn Motion Distance 13.1 mkm x π
- Neptune orbital circumference 28255 mkm = Saturn orbital circumference
9007 mkm x π
(4)
- Pluto motion distance =53.9 mkm =Saturn Motion Distance 13.1 mkm x 4.11
- Pluto orbital circumference 37100 mkm = Saturn orbital circumference 9007
mkm x 4.11

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Discussion (Continued)
- Now we know that,
- Saturn moves a distance =13.1 mkm = 2π x Mars Distance 2.082 mkm
- Simply that rate (2π) is created here because of the motions rates of time among
the planets.
- We have explained one data
- Based on that, the rate (2π) isn't be created by any pure coincidence of numbers
but because,
- 1 day of Mars motion = 6.3 days of Jupiter motion = 15.56 days of Saturn motion
- These rates of time effect on the planets motions distances
- The period 15.56 days enables Saturn to move 13.1 mkm = (2π) x Mars Motion
Distance per a solar day (2.082 mkm).
- In more details
- How to define the solar day for each planet? For example
- Mars Orbital Period =687 solar days
- We here depend on Earth day period and not Mars, Mars orbital period has 667.5
Mars Days, but we don't use this number, we use 687 solar day because we look
from The Earth Eyes.
- For us, Mars orbital distance =1433 mkm and Mars orbital period =687 solar days
and by that mars motion distance per a solar day = 2.082 mkm
- We don't follow the sun here, we follow the distance, when Mars moves (2.082
mkm) it consumes one day
- Let's summarize what we have done….?
- We have explained how the rate (2π) be found between Saturn orbital distance and
Mars orbital distance (where 1433.5 mkm = (2π) x 227.9 mkm)
- But there's still more puzzled data for example
- Why Mars Velocity 2.41 km/sec = 2.5 x Saturn Velocity 9.7 km/sec ? Why? we
should return to answer this question…

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5-4 The Required Periods Dependency (One Law Controls all Data)
(Point No. I)
- Now, Let's summarize the paper objective of this discussion:
- The required period is the period required by a planet to move a distance = its
orbital distance.
- The required periods are used to define each planet rate of time with the other
planets. By that we have discovered the planets motions rates of time
- And
- We have found, The Planets Orbital Periods depend on the planets motions rates
of time.
- And also
- We have found, The Planets Orbital Distances depend on the planets motions
rates of time.
- Means, the solar planets orbital periods and distances be created as function in the
planets required periods.
- Let's remember the required period for each planet before to ask our next question
- The Required Periods List
- For Mercury (27.9 Solar Days) – for Venus ( 35.8 Solar Days) – for Earth (58.1
Solar Days) – for the moon (1700 Solar Days) – for Mars ( 109.4 Solar Days) for
Jupiter (687 Solar Days )- for Saturn (1710 Solar Days) - for Uranus (4890 Solar
Days) - for Neptune (9635 Solar Days) – for Pluto (14547 Solar Days)
- Now, let's ask
- What's the next step? What we need here?
- One Law Controls All Data
- We have very good chance to find better understanding for the solar planets
motions and data. because we have a huge number of data be crated based on small
group of data.

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- Means,
- The solar planets orbital periods and distances be created as functions in the
planets rates of time or in the planets required periods to move their orbital
distances. Based on that we can find some method to control a huge number of
data by small group of data.
- Imagine we know only Earth orbital period (365.25 days) but we don't know any
other planet orbital period or distance. By using the planets rates of time we can
conclude all planets orbital periods and distances.
- So, we have some treasure.
- We need to find the (One Law Controls All Data)
- How to find it?
- If the planets required periods be defined based on one another. means, if there's
a method to conclude each planet required period to pass this planet orbital
distance from other required periods and by that, the planets required periods be
defined based on one law or one equation, This law or equation will control all
planets orbital periods and distances
- I want to say,
- We need to find a method causes to define the required periods based on one
another. this method will create a control for all planets orbital periods and
distances.

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(Point No. II) On Law Controls all Data
- Let's Summarize The One Law Idea In Following:
o The Solar Planets Required Periods Total Be = 31705 Solar Days
o The Inner Planets Required Periods Total Be = 235.8 Solar Days
o The Outer Planets Required Periods Total Be = 31469 Solar Days
o (the moon used required period is 4.61 days, the period for its orbital
distance to Earth and not to the sun)
(A)
o 31469 days (the outer planets) = 235.8 days (the inner planets) x 133
o Where 1 Mars Solar Day = 133 Pluto Solar day
o And
(B)
o 31705 solar day = 109.4 solar days x 133 x 2.18
o Where
o 31705 days = All Planets Total
o 109.4 solar days = Mars required period to move a distance = Mars orbital
period.
o 133 is used for second time
o 2.18 mkm = Mars Motion for a period 25.1 hours
(C)
o Let's summarize the idea and discuss the data later
o The planets required periods are controlled by the planets unified motion,
that means, the periods total (31705 solar days) controls all data
o The periods total (31705 solar days) be divided into 2 parts (the inner) and
(the outer) these 2 parts be defined based on the rate of time between Mars
and Pluto (Because of Their Migration, be discussed in Point No.6)
o These 2 planets are the 2 basic points to which the (total periods) be divided.

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(D)
o Each Planet transports its period of time to its planets group, by that Mars
transports the period of time to Earth and Earth transports to Venus and
Venus transports to Mercury. The inner planets transport the periods of time
from one another by using the planets orbital inclination (and Earth uses its
axial tilt)
o Pluto transports the period of time to the (4) outer planets, by Pluto effect on
these 4 planets days periods total (53.9 hours)
o By that the machine has 2 heads, Mars and Pluto, and these 2 planets control
the periods of time of all other planets motions and by that all planets orbital
periods and distances be defined.
o This description shows that, the planets required periods aren't independent
but they be created based on one another.
o The data discussion makes the vision more clear and understandable
o Notice
o The solar system design uses Mars and Pluto for this task, because, Mars
and Pluto had migrated from their original orbital distances and that effect
negatively on the solar system geometrical design by that the solar system
modify the periods according to the migrants planets positions to repair the
solar system geometrical design. The details of this theory be discussed and
proved Point No. (6) (Mars Migration Theory).

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(Point No. III) On Law Controls all Data (The Data Discussion)
I- Data
(5-4-a)
109.4 solar days =1.88 x 58.1 solar days
(5-4-b)
23.6 x 1.622 = 35.7 solar days x 1.0725
(5-4-c)
27.9 solar days = 7π x 1.279
(5-4-d)
133 solar days x 0.406 mkm =53.9 mkm
(5-4-e)
31705 solar days = 109.4 solar days x 133 x 2.18

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II- Discussion
Equation no. (5-4-a)
109.4 solar days =1.88 x 58.1 solar days
- Where
- 109.4 days = the period Mars needs to pass a distance 227.9 mkm = Mars orbital
distance, by using a velocity =2.082 mkm pr solar day
- 1 hour of Earth motion =1.88 hours of Mars Motion
- But
- 1.88 degrees = Mars orbital inclination (error 1%)
- I claim that, Mars transports the period (109.4 days) to Earth and be (58.1 days) by
using Mars orbital inclination – that may explain why Mars orbital inclination =
1.9 degrees.
- Shortly, Mars transports the period to Earth by using Mars orbital inclination.
- Please note
- The system controls all data by using the planets required periods, that means, the
control method is a period of time. That's what I need to explain clearly. The solar
group is a machine works as a great mechanical clock, the main force in this
machine is the period of time, it's the method of control for the machine work, So,
while Mars transports to Earth a period of time, means, Mars gives Earth a
treasure.

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Equation no. (5-4-b)
23.6 solar days x 1.622 = 38.27 solar days = 35.7 solar days x 1.0725
- Where
- 1 hour of Venus = 1.622 hours of Earth
- 35.7 solar days = Venus Required Period To Pass Its Orbital Distance
- 23.6 days of Earth be = 38.27 days of Venus
- But Venus required period is 35.7 days = 38.27 days/ 1.0725
- Means, Venus required period be defined based on the rate 1.0725
- We know this rate controls 40% of all solar planets distances and by that its effect
is a fact we don't know why it effects on data, but it's a fact we have no option to
escape.
- Just,
- We know that Venus data uses this rate 1.0725 for example
- 243 days (Venus rotation period) = 224.7 days (Venus orbital period) x 1.0725
- This behavior is perfectly similar to the moon behavior where
- 29.53 days (The moon day period) = 27.3 days (the moon rotation period) x 1.0725
- So, if Venus use the transported period from Earth by effect of the rate (1.0725),
that can be considered as a usual using.
- Now
- What's 23.6 days? Because earth axial tilt =23.4 degrees and even if we consider
each 1 degree = 1 solar day, the number is 23.4 and not 23.6?!
- 17.4 degrees = the inner planets orbital inclination
- 17.2 degrees = Pluto orbital inclination (error 1%)
- 23.6 degrees = the outer planets orbital inclination
- 23.4 degrees = Earth Axial Tilt (error 1%)
- But
- 40.8 degrees = 23.6 degrees +17.2 degrees = 23.4 degrees +17.4 degrees
- The data be integrated by unknown geometrical mechanism!

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Equation no. (5-4-c)
27.9 solar days = 7π x 1.279 (error 1%)
- Where
- 27.9 solar days = Mercury required periods to pass it’s a distance = 2 x 57.2 mkm
(Mercury orbital distance error 1%)
- 1 h of Mercury motion =1.279 h of Venus Motion
- 7 degrees = Mercury orbital inclination and 7π =22
- Venus transported the period through Mercury orbital inclination.
- We understand that, the period transports is done by using the planets orbital
inclination but, Earth uses its Axial Tilt.
Equation no. (5-4-d)
133 solar days x 0.406 mkm =53.9 mkm
- Where
- 1 solar day of Mars = 133 solar days of Pluto
- 0.406 mkm = Pluto motion distance per a solar day
- Equation no. (5-4-4) tells, Pluto moves 53.9 mkm during the period 133 solar days.
- We see that, this period (133) is the cornerstone of our discussion and the
cornerstone of the planets required periods total. we deal with this number along
the data discussion.
- I want to say, the distance (53.9 mkm) is mentioned distance because the period
133 solar days is mentioned period, as we have discussed clearly
- The 4 planets days periods total (Jupiter 9.9 +Saturn 10.7 + Uranus 17.2 + Neptune
16.1) = 53.9 hours
- We need to find the geometrical machine by which 1 mkm be used as 1 hour,
based on this machine, Pluto motion distance will cause the period 53.9 h to be
created. by that Pluto transports the period to them.
- Notice 2815 mkm = Mercury Uranus distance, if 1 mkm = 1 hour this value 2815
mkm = 2815 h = 2 x 1407.6 hours (Mercury rotation period)

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Equation no. (5-4-e)
- Where
- 31705 solar days = The planets required periods total
- 109.4 solar days = The required period for mars to pass its orbital distance
- 133 = the rate between Mars and Pluto
- 2.18 mkm = Mars motion distance during 25.1 hours
- There's a basic difficulty in this equation, which is
- The period 109.4 solar days, Mars uses by its velocity for a solar day to pass a
distance = its orbital distance.
- Means, Mars motion distance for a period 24 hours and NOT 25.1 hours!!
- The difference between 25.1 hours and 24 hours is 4.5%
- The error is so great and can effect negatively on the discussion, we should search
behind it to know the fact.
- We have to do that through the moon and Saturn rates of time analysis because the
moon need 1700 solar days and Saturn needs 1710.5 solar days, that makes the 2
rates of time are almost equal and we don't know why Saturn rate of time = the
moon rate of time, because of that we have to solve our question through this point
of discussion.
- Notice
- (153.3 h /53.9 h) = 1.16 mkm/0.406 mkm
- This equation is the reason by which Pluto causes to create the period (53.9h) but
we should discuss in point no. (11) of this paper.

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5-5 Why Saturn And The Moon Use Equal Rates Of Time?
I-Data
(5-5-a)
- The moon needs accurately 1700 solar days to pass a distance = 149.6 mkm =
Earth orbital distance
And
- Saturn needs accurately 1710.457 solar days to pass a distance = 1433.5 mkm =
Saturn orbital distance
- The difference between the 2 periods (1700 days and 171.457 days = 251 hours)
(5-5-b)
90560 seconds = 25.1 hours
(5-5-c)
4.095 mkm (Mercury velocity per solar day) x 1433.5 days = 5848 mkm
0.838 mkm (Saturn velocity per solar day) x 6939.75 days = 5848 mkm
1.16 mkm/sec x 5040 seconds = 5848 mkm (Mercury Pluto Distance)
(5-5-d)
(4900 days /1710 days) = (153.3 hours / 53.9 hours) = (1.16 mkm /0.406 mkm)
(5-5-e)
317050 days = 37100 days x 8.5
But
(for revision) (5-4-e)

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II-Discussion
Equation No. (5-5-a)
- The moon needs accurately 1700 solar days to pass a distance = 149.6 mkm =
Earth orbital distance
And
- Saturn needs accurately 1710.457 solar days to pass a distance = 1433.5 mkm =
Saturn orbital distance
- The difference between the 2 periods (1700 days and 171.457 days = 251 hours)
- The planets rates of time depends on the required periods to move their orbital
distances, and Saturn required period is 1710.457 solar days but the moon required
period is 1700 solar days – That causes their rates of time to be almost equal, for
example 1 hour of Earth motion be = 29.4 hours of the moon motion = 29.3 hours
of Saturn motion. almost they are equal
- We have to ask why?
- Let's summarize the idea in following:
(I)
- Uranus Orbital Distance =19.2 Earth Orbital Distance,
- This data means, if Uranus and Earth velocities are equal, During Uranus revolves
around the sun one revolution, Earth revolves around the sun 19 revolutions (19
years)
- And
- The Earth moon moves a cycle called Metonic Cycle continues for 19 years. we
know that Earth Cycle is 4 years (365 +365 +365 +366 days =1461 days) for that
we have asked frequently, why the moon moves Metonic Cycle?
- The suggested answer is (By An Effect Of Uranus Motion)
- And
- We know that the moon and Saturn be created after Mars and Pluto migration,

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(II)
- The idea is that, Uranus Motion effects on Saturn and the moon and by this effect,
Uranus caused the 2 planets periods to be (1700 days and 1710.5 days) (the
difference between them be 251 hours).
- Why? because
- Mars moves during 25.1 hours a desistance = 2.18 mkm
- And
- (for revision) (5-4-e)
- 31705 solar days = 109.4 solar days x 133 x 2.18
- This equation needs the distance 2.18 mkm to define the periods 31705 days which
is the total required periods of the solar planets.
-
- The number 251 hours is so effective because
- (1)
- If 1 hour = 1 month based on that 251 hours will be =251 months but Metonic
Cycle is (254 months) (error 1%)
- (2)
- 25.1 hours = 90560 seconds where Pluto orbital period =90560 days
- (3)
- 251 hours = 25.1 hours x 10 but
- 10747 days (Saturn Orbital Period) x 24 h x 10 = 10.7 h x 2 x 120536
- (where 10.7 h = Saturn day period and 120536 km = Saturn diameter)
- I try to show that, the data is integrated in harmony with one another, w don't
know the geometrical mechanism but the data shows interesting integration ability
- Shortly
- Uranus caused the 2 planets periods to be rated with the difference 251 hours
(error 0.5%) and by that Uranus effect on the planets motions caused their required
periods to be equal approximately

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Equation No. (5-5-c)
4.095 mkm (Mercury velocity per solar day) x 1433.5 days = 5848 mkm
0.838 mkm (Saturn velocity per solar day) x 6939.75 days = 5848 mkm
1.16 mkm/sec x 5040 seconds = 5848 mkm (Mercury Pluto Distance)
- The idea tells us that, Uranus effect on the 2 planets be done through Metonic
Cycle, Equation no. (5-5-c) gives one proof for this claim, because
- Saturn (0.838 mkm per a solar day) moves a distance =5848 mkm during (6939.75
solar days = Metonic Cycle)
- The distance 5848 mkm = (Mercury Pluto Distance) is the basic Distance in the
solar system design and based on it many important data be created.
- We will explain the importance of this distance (5848 mkm) in Part (II) of this
paper, in which we discuss important data of Mercury motion, let's refer to this
data here and discuss them there
- Mercury moves during 84 days a distance =346.6 mkm (error 0.5%)
- Mercury moves during 346.6 days a distance =1433 mkm = Saturn orbital distance
- Mercury moves during 1433 days a distance =5848 mkm
- We should discuss this data in Part (II) of this paper.
- The point is that, Saturn motion is related to this basic distance through Metonic
Cycle.
- Notice (The velocity 1.16 mkm passes 5848 mkm in a period 5040 while Mercury
day period needs 5040 seconds to be 176 solar days) this data also be discussed in
part (II) of this paper.

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Equation No. (5-5-e)
317050 days = 37100 days x 8.5 (where 3710 mkm =Pluto orbital circumference)
But
(for revision) (5-4-e)
- The total periods are 31705 days based on the period 25.1 hours but we use a
period = 251 hours, as a result the period will be 317050 days
- Pluto orbital circumference (37100 mkm) be used as a period of time (37100 days)
- 1 hour of Saturn motion = 8.5 hours of Pluto motion.
- The data tells
- Equation no. (5-5-e) proves the period (317050 days) is mentioned and designed.
- That means, our conclusion is a correct one and the difference between Saturn and
the moon periods (251 hours) be created by Uranus to support mars motion
through the equation
- (for revision) (5-4-e)
- 31705 solar days = 109.4 solar days x 133 x 2.18
- Means, Uranus wanted to support Mars Motion (through this equation) and for
that, Uranus helped to create the moon and Saturn to do this task.
- The geometrical mechanism is so hard to be caught clearly but the data shows that
they occupy their right positions,

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Equation No. (5-5-d)
(4900 days /1710 days) = (153.3 hours / 53.9 hours) = (1.16 mkm /0.406 mkm)
- Where
- 4900 Days Uranus Needs To Move Its Orbital Distance
- 1710.5 Days Saturn Needs To Move Its Orbital Distance
- 153.3 hours = Pluto Day Period
- 53.9 hours = the outer planets days periods total
- 1.16 mkm = Jupiter motion distance during mars rotation period
- 0.406 mkm = Pluto velocity Per A Solar Day.
- This equation also can be clear just after studying the paper part (II), many data
can be explained only after Part (II) discussion, because
- The matter is created out of light and moves with its parent light beam by using
different rates of time, by that, light motion be an effective continuous player in
matter motion and planets motions. For that, whatsoever I do to avoid light motion
effect on planets motions it can't do the job perfectly, light motion be discovered
through any planet motion data because it’s the planet motion reason and source of
energy
- At least we can prove that, Mars ad Pluto were migrated from their original orbital
distances to the current and this even is done before the moon and Saturn creation.
- Let's prove that in the next point (Point No. 6)
- Notice
- The sun is the last created piece in the solar system and is created after all planets
creations and motions we should prove this claim also. In point no. (14)

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6- Mars Migration Theory
6-1 Mars Migration Theory
6-2 Pluto Migration Theory
6-3 Planets Migration Theories Proves

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6-1 Mars Migration Theory
- Mars was the next planet after Mercury with original orbital distance =84 mkm
and Mars had migrated into Mars current orbital distance (227.9 mkm)
- Through Mars Displacement from (84 mkm) to (227.9 mkm), Mars had collided
with Venus (at first) and then with Earth (at second) and then reach to its current
orbital distance point (227.9 mkm).
- Mars had moved from (84 mkm) to (227.9 mkm) in a direct displacement – and
had pushed with it all collisions debris in its direction
- From these collisions debris the Earth could create its own moon and also Mars
moons are created from them and the rest debris be attracted by Jupiter Gravity
and Created The Asteroid Belt.
- Means,
- Mars Migration Theory is in full harmony with (Giant- Impact Hypothesis), but
- Mars itself had collided with Earth and caused the moon creation and not the
ancient planet (theia) as supposed by the Giant-impact hypothesis.
- The point is that, the planets order (Mercury – Venus –Earth) shows that Mars was
the second planet after Mercury – and Mars had migrated from (84 mkm) to (227.9
mkm) –through this displacement – Mars has collided with Venus and Earth–
- Mars collisions with Earth and Venus left many proves behind which prove that
Mars did these collisions and not the planet (theia).
- Mars Migration theory answers many of the Giant-impact hypothesis questions.
- Let's do that in following
(1st
Question)
- Why has Venus no a moon? spite it suffered from a similar collision as Earth?
- Mars had moved its displacement from (84 mkm) to (227.9 mkm), and through
this displacement Mars pushed all debris with it in its motion direction and
because of that, Venus had found no debris around, And couldn't create its own
moon because of that.

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- But the debris lost some of their motion momentum at Earth position and Earth
gravity is more strong than Venus, by that Earth could attract some debris by
which Earth created its moon.
(2nd
Question)
- What's The Lunar Magma Ocean (LMO) Origin?– It's Venus
- Because
- The Earth moon rocks are created from the 3 planets debris (Mars- Venus – Earth)
and for that the moon has a Magma Ocean (LMO).
(3rd
Question)
- Why The Iron Oxide (Feo) of the Moon= (13%)?
- Because The rate (13%) is a middle rate between Mars rate (18%) and the
terrestrial mantle (8%).
Notice no.(1)
- Mars Moons Creation is a good proof for Mars Migration Theory.
- The collisions debris lost the great part of their momentum when reach to Mars
orbital distance point (227.9 mkm), because of that, Mars with its small mass could
attracted 2 moons, because the debris is too much around it and can attract them
easily.
- But Venus great gravity couldn't create even one moon because no debris be found
around it
Notice no.(2)
- The asteroid belt is one more proof for Mars Migration
- The collisions debris which were pushed with Mars motion to its current orbital
distance point (227.9 mkm) couldn't all be attracted by Mars gravity because of its
small mass, Mars had attracted only its 2 small moons
- But
- Jupiter great gravity attracted the rest debris and they created the asteroid belt.
- The whole trajectory is filled with references of the event and shows that it's a fact.

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Notice no.(3)
- Mars diameter before Migration was 7070 km and be 6792 mkm after migration as
a result for the collisions Venus and Earth
- We know that because
- The equation (7070 km x 1092
= 84 mkm), where 84 mkm=Mars original orbital
distance.
- The equation (d = r x 1092
) is the equation controls planet orbital distance based on
its diameter. The equation be used by Mercury, Earth and Saturn but the planets
migration effects negatively on the other planets using of it.
- From this analysis we conclude, Mars Diameter be decreased with 4.1%
- Additional Data
- Mercury Orbital Distance 57.9 mkm = Mercury Diameter 4879 km x 1092
- Earth orbital distance 149.6 mkm = Earth diameter 12756 km x 1092
- Saturn orbital distance 1433.5 mkm =Saturn diameter 120536 km x 1092
Notice no.(4)
- If Mars Mass be decreased as a result for the collisions with 8%, in this case
- Mercury mass (0.33) and its orbital distance (57.9 mkm) be in proportionality with
Mars mass (0.688) and Mars original orbital distance (84 mkm) based on Newton
gravitation Equation – this same proportionality be working also with the current
data of Jupiter and Saturn.

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6-2 Pluto Migration Theory
- Pluto Was The Mercury Moon
- One great force stroke Mercury, Pluto and Mars, with order
- Means,
- Mercury had received the most strong stroke directly, Mercury couldn't escape
from its fate. But Mercury axial tilt was (One Degree) and after the stroke be (0.01
Degree or even Zero)!
- The third stroke be received by Mars by which Mars had Migrated
- The second stroke be received by Pluto, which caused Pluto to be flying along the
solar system and reach to the end point of the solar system.
- The solar system end point with distance (5906 mkm) is a defined geometrically.
- Before Pluto migration –
- Neptune orbital distance was 5906 mkm
- Means,
- Neptune was in the position in which Pluto now be found. The distance 5906 mkm
was Neptune original orbital distance
- Pluto had flying along the solar system distance and reach to Neptune position, and
had collided with Neptune, pushed it out of its orbit and then put it out of (Pluto
Influence area) – That's why Pluto Neptune Distance = Pluto eccentricity Distance
Result No. 1
Mercury Pluto Distance = 5848 mkm = 101 x Mercury orbital distance 57.9 mkm
- This data is so important because the solar system distances be designed in
proportionality with it. based on that the rate (101) is one geometrical pillar in the
solar system design.
Result No. 2
Neptune Be Out Of The Network
- We will study that, the solar system distances be created in a network form in point
no. (12), with many proves we discuss this point…
- But

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- How the distances be created in a network form? We should answer this question
in details in that point no.(12) – but let's summarize the idea in following:
- Matter is created out of light and the planets be created of one light beam- light
motion creates the distances through which the planets move – by that –
- The Solar System Distances Be Similar To Railways
- And, the planets be similar to trains
- That shows why the planets motions be obligatory motions that because light
provides the required energy for distances creation and forces the planets to move
through these distances by this energy.
- Now, we have very (unclear) event – because –
- Pluto had pushed Neptune and put it Out Of The Railways
- That means, Neptune has no orbit and no definition of motion – and because of
that Neptune needed energy to build its orbit!
- Frankly
- I don't understand correctly the meaning of the network or how Neptune be out of
the network- because no space (I know) out of the network and I can't define any
point out of the network
- But
- This idea I have built on 2 data which are
- (1) Neptune Pluto Distance = Pluto Eccentricity Distance =1411 mkm
- (2) Neptune has seized 14% of Jupiter energy to create its orbital circumference
28255 mkm and this lost energy is registered clearly in the solar planets distances
as we will discuss in Part no.(II) of this paper.
- These 2 data pushed me to conclude that, Neptune had no orbit and had to create
one for which Neptune seized the energy, Now this result must be done by the
collision between Neptune and Pluto.
Result No. 3
- Pluto and Neptune collisions caused to create Pluto moons and the Kuiper belt.

The Solar System Design Disproves Newton Theory

The Solar System Design Disproves Newton Theory

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