The Solar System Design Disproves Newton Theory (Revised No.2)

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
The Solar System Design Disproves Newton Theory (Revised No.2)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –28th
September 2021
Abstract
Paper hypothesis
The Solar Planets Revolutions Around The Sun Be Done In Equal Periods of Time
Paper hypothesis Explanation
(I)
- The Solar Planets move as gears in one machine- each planet motion depends on
the other planets motions.
- The solar planets motions be integrated with one another to create one unified
integrated motion.
- The unified integrated motion causes the planets revolutions around the sun to be
done in equal periods of time, to save the timing adjustments of the planets
motions to be integrated with one another.
- The equal periods causes the planets motions to use different rates of time to adjust
the planets orbital distances increasing and their velocities decreasing
- The equal periods of time and the using of the different rates of time causes the
solar system distances to be created in a network form
- The distances network means, the distances be created based on one geometrical
design and be distributed as a network.
- This vision attributes 3 new features to the solar planets motions which are:
- (1) The Planets Move An Integrated Unified Motion
- (2) The Planets Motions Use Different Rates Of Time

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- (3) The Solar System Distances Be Created In A Network Form
- By that, the solar group be similar to a great mechanical clock, each planet works
as a gear moves depending on the other planets motions and defines a part of the
solar system general rate of time (the general rate of time is the solar day 86400s)
(II)
- Mars was the next planet after Mercury with original orbital distance 84 mkm
- Pluto was the Mercury moon revolving around it
- The Earth Moon and Saturn weren't created in that time
- Also the sun wasn't created in that time. The Sun is the last created piece in the
solar system
- Then
- Mars And Pluto had migrated from their original orbital distances to their current
positions.
- The solar system distances network was effected greatly by the planets migration.
- The solar system network design tried to repair the negative effects of the planets
migration.
- As a result, the solar system network forced the outer and inner planets motions
periods of time to use Mars and Pluto rate of time as their basic rate.
- That put Mars and Pluto as 2 heads for the solar system motion.
(III)
- The Equal periods theory disproves Newton Theory Of The Sun Mass Gravity, for
many basic reasons (1st
The sun is the last created piece in the solar system) and
(2nd
the planets motions be integrated disproving planet motion independency
concept) and (3rd
the solar planets motion be transported or caused in a series from
one planet to another in sequence series but Newton vision told all planets connect
with the sun by the mass gravity)

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Paper Objectives
- (1st
Objective) The paper proves, The Solar Planets Revolve Around The Sun In
Equal Periods Of Time
- (2nd
Objective) The Paper Provides The Solar System Creation Theory.
Please scan the figure (ORCID)

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Paper Contents
Subject Page No.
1- Introduction 6
2- Methodology 10
Paper Part No. (I) The Equal Periods Proof 13
3- Can The Solar Planets Motions Use Different Rates Of Time? 14
3-1 Preface 15
3-2 The Rates Of Time Using Proof Idea 16
3-3 The Planets Rates of time Definition 22
4- The Solar Planets Rates Of Time Analysis 26
4-1 Preface 27
4-2 Venus Motion Rate of time 28
4-3 Earth Motion Rate of time 30
4-4 Mars Motion Rate of time 32
4-5 Jupiter Motion Rate of time 34
4-6 Saturn Motion Rate of time 36
4-7 Uranus Motion Rate of time 38
4-8 Neptune Motion Rate of time 40
4-9 Pluto Motion Rate of time 42
4-10 The General Discussion 44
5- The Planets Orbital Distances Depend On Their Rates Of Time 46
5-1 Preface 47
5-2 The Planets Orbital Distances Test 48
5-3 Mars, Jupiter and Saturn Motions Analysis 54
5-4 One Equation controls The planets orbital periods and distances 60
5-5 Why Saturn And The Moon Use Equal Rates Of Time? 72
5-6 Why Mercury Use A Double Of Its Orbital Distance? 78
5-7 Pluto And Saturn Motions Rate of Time 80
5-8 The Rate (4.61) be used between Pluto and the moon motion 86
5-9 The Moon Orbital Motion Equation 90
6- Mars Migration Theory 106
6-1 Mars Migration Theory 107
6-2 Pluto Migration Theory 110
6-3 Planets Migration Theories Proves 112
7- Planets Unified General Motion 115
7-1 The Planets Unified General Motion Description 116
7-2 The Solar Planets Motions Are Complementary One Another 118
7-3 The Solar Planets Move An Unified Motion (A Team Motion) 122
8- Mercury Motion Distance During Its Day Period 127
8-1 Preface 128
8-2 Why Mercury Jupiter Distance =720.7 mkm? 129

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8-3 Jupiter Motion In A Comparison With Light Motion 133
9- Jupiter orbital Circumference Analysis 138
9-1 Preface 139
9-2 Jupiter orbital Circumference Analysis 140
10- The Sun Age Description 154
10-1 The Sun Circles The Earth 155
10-2 The Rate (1.0725) 156
10-3 The Sun Diameter Analysis 160
10-4 The Sun Rays Analysis 163
Paper Part No. (II) The Solar System Creation Theory 168
11- The Solar System Creation Theory 169
11-1 Preface 170
11-2 The Solar System Creation Theory 172
11-3 The Inner Planets Motions Reason 177
11-4 Light Beam (1.16 mkm/sec) Proves Discussion 181
11-5 Saturn Motion More Analysis 218
11-6 Equal Distances Method 225
12-The Solar System Distances Be Created In A Network Form 231
12-1 Preface 232
12-2 The Continuum effect Through the Solar System Distances 234
12-3 The Solar System Distances Distribution 239
12-4 The Solar System Distances Dependency On One Another 243
Appendix No.1 The Solar System Equal Distances List 245
References and Biography 247

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1-Introdcution
- Many discovered new features be attributed to the planet motion…
- The question is, why all these features weren't discovered before? Because in fact,
the features give us a different vision completely from Newton Vision about the
solar system motion?
- The question is valid, it asks "Why We Are So Far From The Truth"?
(I)
- The solar system is designed by some accurate geometrical design, the secret of its
study is to use the planets motions data.
- If someone studied any ancient building will find this fact. the ancient building
geometrical design doesn't depend on its outer shape, to be as a pyramid or a cube.
But depends on its dimensions. For that reason when we just look at some ancient
building we learn nothing. The geometrical design be found in the dimensions.
- The basic mistake was the removing of the planets motions data from the theory
analysis and to accept the theories regardless the planets data.
- By that, while Newton gave us the gravitation equation, Jupiter be in order no. (5)
from the sun, when we asked why Jupiter isn't the most near planet to the sun
because of it's greatest mass, the answer be because of (the initial conditions!),
regardless the (initial conditions) claim be a fact or not. in all cases, the planets
order don't support Newton theory and his gravitation equation. By that the theory
be built without support from the planets motions data.
- Titus bode law is an example for this problem, the law be refused because it
couldn't predict Neptune orbital distance but it predicted all other planets. The
point is that, the people who refused the law didn't know why the law be used by 8
planets and why Neptune only didn’t follow it, they refused and removed the law
without understanding for its error. This example is useful because it shows the
unfairness of treatment with the planets motions data. no one search behind the
data to know how this data be created

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(II)
- The moon orbital motion can explain this idea as clear as possible, let's summarize
it in following
- The moon displacement per a solar = 88000 km
- The moon day period =29.53 solar day
- By that, the distances total which be passed by the moon in its day period should
be =(88000 km x 29.53 days = 2598640 km = 2π x 413600 km)
- Based on this data, The Moon Apogee Radius Should Be = 413600 km
- But it's not a fact
- The moon apogee radius = 406000 km
- Means,
- The moon can't be far from the Earth at a distance more than 406000 km, and the
moon never visit the point 413600 km
- This data shows clearly we can't understand the moon motion trajectory by the
observation only but we need to analyze the motion data to know what's going on.
- Again
- How the moon apogee radius be (406000 km)? it should be (413600 km?)
- Notice
- There's one more feature should be found as a result because the distance
(2598640 km) is so long the moon would have to revolve around Earth through its
(new) apogee orbit
- Shortly
- Based on this data, the moon would revolve around Earth along month through the
apogee orbit whose radius (r=413600 km) and would be prevented to revolve
around Earth through any near orbit!
- The Fact Is That,
- The moon creates an angle (θ) between the moon displacement direction and the
moon orbit horizontal level, by that, while the moon moves daily 88000 km but

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this distance doesn't be accounted for the moon orbit. The orbit considers another
displacement depend on the angle, let's call it (the real displacement L)
- (The Real Displacement) L = 88000 km cos (θ)
- As a result
- The real displacement be shorter than (88000 km) and the total displacements
during (29.53 days) be less than (2598640 km) and be (2550973 km) (-2%)
- By this intelligent technique, the genius moon can revolve around Earth through
more near orbit and avoid to visit the point 413600 km forever
(III)
- The moon orbital motion is a good example to explain the solar system motion,
because the observation doesn’t give all details, we need to analyze the data to
discover in more clear the planets motions …
- For example, One new feature tells, The Planets Move Their Revolutions
Around The Sun In Equal Periods!
- How can that be possible? If the planets orbital distances be greater and their
velocities be lower, how the periods be equal?
- The planets use different rates of time,
- By that, 1 hour of Mercury Motion = 24.6 hours of Jupiter motion. the different
rates of time compensates the 2 other features (increasing distances and decreasing
velocities)
- I want to say,
- We can't understand the solar system motion by the observation only, we need to
analyze the planets motions data to know how this data be created. this is the
method by which the solar system geometrical design can be discovered and by
that we can protect ourselves from the imaginary ideas- as Newton's!-
- The point is that, the sun is the last created piece in the solar system and all planets
were created and moving before the sun creation. Based on that, Newton theory of
the sun mass gravity is absolute imaginary one.

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- Let's take a look on the paper contents
- Paper Part no. (I)
- The Planets Revolution Equal Periods be proved in 3 points (no.3, 4 and 5), in
these 3 points, we proves strongly that the solar planets use different rates of time
and these rates of time define their orbital periods and distances
- Mars Migration Theory be proved in point no. (6)
- The Planets Unified Motion be proved in point no. (7)
- Jupiter And Mercury Motions Be Analyzed in points no. (8 and 9) to be detailed
example of proof for the planets unified motion.
- The sun is created after all planets, this theory be proved in point (no.10)
- Paper Part no. (II)
- The solar system creation theory be proved in point (no.11)
- The solar system distances network theory be proved in point (no.12)

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2-Methodology
- I use the planets motions data analysis in comparison with the theories which try to
explain the planets motions- let's use one example to explain how this method
works?
- Example No. 1
- Newton told us– The planet motion be independent from all other planets motions
- This is the theory – let's see some planets motions data for a comparison
- Data
(1)
Saturn Orbital Distance = Saturn Uranus Distance
= Mars Orbital Circumference
= Pluto Neptune Distance (error 1.5%)
= Pluto eccentricity Distance (error 1.5%)
= Neptune Orbital Distance/π
= Uranus Orbital Distance /2
(2)
Mercury Neptune Distance = Saturn Pluto Distance
Jupiter Pluto Distance = Uranus Neptune Circumference
Earth Neptune Distance = Mercury Saturn Circumference (0.5%)
(3)
Jupiter Mercury Distance = 2 Mercury Orbital Circumference
Jupiter Venus Distance = Venus Orbital Circumference (1.5%)
Jupiter Earth Distance = Earth Orbital Circumference (1.2%)
(Earth and Jupiter at 2 different sides from the sun)
(4)
Jupiter Mercury Distance = Mars Orbital Distance x π (0.6%)
Jupiter Uranus Distance = Venus Jupiter Circumference (0.8%)
Pluto Orbital Distance = Earth Orbital Circumference x 2π
Why These Distances Are Equal?

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- The solar system has around (45 distances) and these distance are around (25
distances) why they are equal one another? Can Planets Independent Motions
Cause These Distances Equality?
- In some desert someone sees a mirage and thought it's a water! How can we prove
to him that this is a mirage and Not a water?
- Newton told that, Planets Motions be Independent From One Another, and as a
result - The solar system distances be created based on each other in a Network
form where more than 50% of all distances are equal one another!!
- I try to show that –Newton Theory mistake is some how clear.
- The planets creations and motions data should be similar to a creature genes which
can tell us how this planet be created and moving – so whatsoever the theory be
the planets motions data be more important than it – and by that – even if Newton
was correct, there's no reason to neglect the planets motions.
- Let's use one more example
- Example No. 2
- 778.6 mkm = 1.0725 x 720.7 mkm (Mercury Jupiter Distance)
- 720.7 mkm = 1.0725 x 671 mkm (Venus Jupiter Distance)
- 671 mkm = 1.0725 x 629 mkm (Earth Jupiter Distance)
- 629 mkm = (1.0725)2
x 550.7 mkm (Mars Jupiter Distance)
- 550.7 mkm = (1.0725) x 511 mkm
- 4900 mkm = (1.0725) x 4495.1 mkm (Neptune Orbital Distance) (1.6%)
- 1375 mkm = (1.0725) x 1284 mkm (Earth Saturn Distance)
- 4900 mkm = Jupiter orbital circumference
- 1375mkm = Mercury Saturn Circumference
- The previous distances are 13 distances (30%) of all distances- they are example of
many others- the question is why they are rated with the same one rate (1.0725)?

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- I try to show, some geometrical design effects through the planets motions data.
This effect is stronger than any planet motion and force all of them to use the same
one rate (1.0725)– No Independent Motion Be Found Here – the data simply
disproves Newton Theory Of The Sun Mass Gravity and Planet Independency
Motion.
- The previous data is example for wide range of data – I add some more of them
here to show the strong force range of using this rate (1.0725)
- (28.3 deg / 26.7 deg) =(26.7 deg /25.2 deg) = (25.2 deg /23.4 deg) = (122.5 /115.2)
= (1.0725)
- Where
- 28.3 degrees = Neptune Axial Tilt
- 26.7 degrees = Saturn Axial Tilt
- 25.2 degrees = Mars Axial Tilt
- 23.4 degrees = Earth Axial Tilt
- 115.2 degrees = 90 degrees + 25.2 degrees (Mars Axial Tilt)
- 122.5 degrees = Pluto Axial Tilt.
- Shortly
- The planets data analysis put the data in comparison with the theories to test the
theory sufficiency.

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Paper Part No. (I)
The Solar Planets Revolutions Around The Sun Be
Done In Equal Periods of Time

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3- Can The Solar Planets Motions Use Different Rates Of Time?
3-1 Preface
3-2 The Rates Of Time Using Proof Idea
3-3 The Planets Rates of time Definition

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3-1 Preface
- The paper supposes that, The Solar Planets Use Different Rates Of Time
- The Rates of time is a meaning we have learnt from special theory of relativity,
and it means, for example, (1 h of Mercury motion =24.6 h of Jupiter motion), that
means, (While the clock moves 1 hour in Mercury the other clock moves 24.6
hours in Jupiter).
- We accept this meaning, and based on it, the paper supposes, Planets Motions Use
Different Rates Of Time.
- Now
- Can That Be A Fact?
- I have a proof for this idea, and the proof is useful to improve our understanding
for the solar planets motions data and its meaning.
- But
- The proof can prove that, the solar planets motions use different rates of time, but
can't explain why or how to do that. that means, I have a proof for a discovery but
how to explain this discovery I can't answer. The proof which I have provides the
fact but no a theoretical explanation be provided neither geometrical mechanism to
explain how these rates of time be created.
- Let's write the proof idea in the next point as clear as possible before to discuss it.

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3-2 The Proof Of The Rates Of Time Using.
- Let's summarize the proof idea in following…
(I)
- The solar planets rates of time be defined for any planet based on the period this
planet needs to move a distance = this planet orbital distance.
- Let's provide these periods for better explanation:
- Mercury needs a period =14.13 solar days to move a distance =57.9 mkm =
Mercury Orbital Distance (So the required period is 14.13 Solar Days)
- Venus needs a period =35.8 solar days to move a distance =108.2 mkm = Venus
Orbital Distance (So the required period is 35.8 Solar Days)
- Earth needs a period =58.1 solar days to move a distance =149.6 mkm = Earth
- The Earth moon a period =1700 solar days to move a distance =149.6 mkm =
Earth Orbital Distance by using its daily displacement 88000 km (So the required
period is 1700 Solar Days)
- Mars needs a period =109.4 solar days to move a distance =227.9 mkm =Mars
- Jupiter needs a period =687 solar days to move a distance =778.6 mkm = Jupiter
Orbital Distance (So the required period is 687 Solar Days)
- Saturn needs a period =1710 solar days to move a distance =1433.5 mkm = Saturn
- Uranus needs a period =4890 solar days to move a distance =2872.5 mkm =
Uranus Orbital Distance (So the required period is 4890 Solar Days)
- Neptune needs a period =9635 solar days to move a distance =4495.1 mkm =
Neptune Orbital Distance (So the required period is 9635 Solar Days)
- Pluto needs a period =14547 solar days to move a distance =5906 mkm =Pluto

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(II)
- The Planet Motion Rate of Time be defined depends on these periods.
- For example
- 58.1 days (Earth period) = 1.622 x 35.8 days (Venus Period)
- Means
- 1 hour of Venus Motion = 1.622 hours of Earth Motion
- This is the rate of time we search for. And by this method we define it clearly.
- Then
- This rate of time does 2 basic Job which are
- (1st
Job)
- The rate of time defines the planets orbital periods, because of that
- 365.25 days (Earth Orbital Period) = 1.622 x 224.7 days (Venus Orbital Period)
- This rule is used for all planets orbital periods, as we will prove that later in our
discussion.
- (2nd
Job)
- The rate of time defines the planets orbital distances, let's do that in following…
- 1 day of Venus Motion = 1.622 days of Earth Motion (this is the rate of time)
- But
- Venus during one solar day moves a distance =3.024 mkm
- Earth during 1.622 solar days moves a distance =4.176 mkm
- And
- (4.176 mkm /3.024 mkm) = (940 mkm /680 mkm)
- Where
- 940 mkm = Earth Orbital Circumference
- 680 mkm = Venus Orbital Circumference
- As the data shows, the rate of time defines the planets orbital circumferences.

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(III)
- Now the idea be clear
- The periods of planets motions for their orbital distances define the rates of time be
used by these planets motions..
- And
- These rates of time define all planets orbital periods and distances
- This is a good understanding for the planets data
- But
- What do we need?
- We need to know if the planets motions required periods be defined independently
or dependently on one another…
- Now
- We have 2 different visions as result for these 2 options. Let's explain that in
following as clear as possible
- (1st
Option)
- If the planets required periods be defined independently for each planet, that
means, each planet motion can be independent from one another. because the
periods are independent periods from one another
- (2nd
Option)
- If the planets periods be defined dependently on one another, that will make the
solar group as one machine of gears.
- The solar planets in this case will be similar to carriages in one train which move
together one unified motion. or the planets be similar to gears in one machine of
gears. They move one unified motion.
- Or Better Example,
- the solar planets be similar to a mechanical clock, each planet is a gear in the
mechanical clock and causes to create a rate of time as a part of the machine
general rate of time.

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- I want to say that,
- The second option of the periods dependency on one another isn’t so simple option
but it's a very effective option and even its effect be understood by any student of
astrophysics, because
- The planets orbital periods and distances be defined based on the motions rates of
time which are defined based on these required periods the planets need to pass
their orbital distances- So If these periods be created based on one another – that
makes all planets orbital periods and distances be defined based on one another.
- Shortly, that means,
- We don't need to observe to know any planet orbital period or distance, if any data
of it be absent, we can simply conclude it by using the rates of time – the second
option simply changes the solar planets data into data be defined by one Equation
only and by that we can remove all planets data (periods and distances) and can
conclude them correctly by using the rates of time
- Shortly
- If the planets required periods be defined based on one law and not independently
from one another the whole vision of the solar system will be changed by a very
strong proof
- To make this discussion more interesting, I want to say that,
- There's one law controls all planets required periods of time to move their orbital
periods. And this one law disproves and refuted completely Newton Theory of the
sun mass gravity and Planet Motion Independency Concept which be inherited
form Newton theory.
- We simply have a chance to create a progress in the solar system motion
understanding.
- So, Let's Summarize Our Discussion Steps In Following

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(IV)
- We Should Follow The Following Steps In Our Discussion
- (1st
Step)
- The Planets Motions Rates Of Time Definition
- And
- The Planets Orbital Periods Definition Based On The Rates Of Time
- (2nd
Step)
- The Planets Orbital Distances Definition Based On The Rates Of Time
- (3rd
Step)
- We discuss one law controls the planets required periods for the solar planets
orbital distances motions.
(V)
- We should notice that
- The previous steps are steps for data providing, that means, these steps are
methods to arrange the data
- Because
- I prove that, the planets motions use different rates of time. In this proof discussion
I provide the data in some arrangement to show that this data be understandable
only based on the hypothesis of the planets motions different rates of time.
- By that, these steps are a method of Data arrangement.
- Means
- We don't discuss the question (how the planets motion use different rate of time?)
neither the question (why the planets motions use different rates of time?) because,
we try to prove the discovery which is (the planets motions use different rates of
time), and to prove that, I put the planets data in the best arrangement form by
using these 3 steps to show that, this data can't be understandable except by using
the hypothesis (the planets motions use different rates of time).
- So, our process aims basically to prove this fact

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- Then
- We should analyze the planets required periods for their orbital distances motions
to prove that one law controls all periods and by that we can change the solar
system current description. for that reason the periods should be analyzed in a
separated dedicated point.
- I want to say
- We have to provide the data which prove the hypothesis (the planets motions use
different rates of time)
- After the proof discussion be completed we have to start the solar system
description discussion because one great effect be done as a result for the
hypothesis proof and the one law proof.
- Let's explain how we arrange the planets data in following:
- In next point (3-3) we provide Mercury Rates of time as an example and use it to
define all planets orbital periods based on Mercury Day Period
- Mercury is an example, and we should do the same job with each planet, for that
we dedicate the next point (NO. 4) for all planets rates of time test. Based on that,
- Mercury is our example for test and
- All planets periods be tested as Mercury rate in (Point No. 4)
- Then
- In point no. (5) we prove that, all planets orbital distances be defined based on the
planets motions rates of time.
- And in this point we prove that one law controls all periods

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3-3 The Planets Rates Of Time Definition
(I)
The Required Periods For The Solar Planets Orbital Distances Motions Are
- Mercury needs 14.13 Solar Days (27.9 Solar Days)
- Venus needs 35.8 Solar Days
- Earth needs 58.1 Solar Days
- The moon needs 1700 Solar Days
- Mars needs 109.4 Solar Days
- Jupiter needs 687 Solar Days
- Saturn needs 1710 Solar Days
- Uranus needs 4890 Solar Days
- Neptune needs 9635 Solar Days
- Pluto needs 14547 Solar Days
- The rates between these period define the rates of time used by each planet in
comparison with other – as we will explain in following
- But
- For Mercury we use the period (27.9 solar days) = (2 x 14.13 days) (error 1%) ,
because Mercury uses its Day Period and not its orbital period and also uses the
distance 720.7 mkm and not Mercury orbital circumference 360 mkm. This Data
Mercury uses because of some geometrical necessity we should explain in a point
no (8-2) in which we analyze the period of time Mercury needs to pass a distance =
its orbital distance.
- For now we use for Mercury the period (27.9 Solar Days) and we explain the
reason in this point (8-2).

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(II)
- Mercury Motions Rates Of Time
- (35.8 /27.9) = 1.279, means
- 1 hour of Mercury Motion = 1.28 hours of Venus Motion
- (58.1 /27.9) = 2.078, means
- 1 hour of Mercury Motion = 2.078 hours of Earth Motion
- (1700 /27.9) = 60.8, means
- 1 hour of Mercury Motion = 60.8 hours of The Moon Motion
- (109.4 /27.9) = 3.91, means
- 1 hour of Mercury Motion = 3.91 hours of Mars Motion
- (687 /27.9) = 24.6, means
- 1 hour of Mercury Motion = 24.6 hours of Jupiter Motion
- (1710 /27.9) = 61.1, means
- 1 hour of Mercury Motion = 3.91 hours of Saturn Motion
- (4890 /27.9) = 174.8, means
- 1 hour of Mercury Motion = 174.8 hours of Uranus Motion
- (9635 /27.9) = 344.8, means
- 1 hour of Mercury Motion = 344.8 hours of Neptune Motion
- (14547 /27.9) = 520.2, means
- 1 hour of Mercury Motion = 520.2 hours of Pluto Motion

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MERCURY MOTION RATES OF TIME LIST
1 hour of Mercury motion = 1.279 h of Venus Motion
1 hour of Mercury motion = 2.078 h of Earth Motion
1 hour of Mercury motion = 3.91 h of Mars Motion
1 hour of Mercury motion = 24.6 h of Jupiter Motion
1 hour of Mercury motion = 61.1 h of Saturn Motion
1 hour of Mercury motion = 174.8 h of Uranus Motion
1 hour of Mercury motion = 344.6 h of Neptune Motion
1 hour of Mercury motion = 520.2 h of Pluto Motion
1 hour of Mercury motion = 60.8 h of The Earth Moon Motion
- Notice
- The list tells, Saturn and the Moon use equal rate of time!! Why? we should
answer that in point no. (5-5) of this paper
- Now
- Can these rates of time define the planets orbital periods? Let's do that in
following:

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Mercury Rates Of Time Test
224.7 days (Venus orbital period) = 1.279 x 175.94 days (Mercury Day Period)
365.25 days (Earth orbital period) = 2.078 x 175.94 days (Mercury Day Period)
687 days (Mars orbital period) = 3.91 x 175.94 days (Mercury Day Period)
4331 days (Jupiter orbital period) = 24.6 x 175.94 days (Mercury Day Period)
10747 days (Saturn orbital period) = 61.1 x 175.94 days (Mercury Day Period)
30589 days (Uranus orbital period) = 174.8 x 175.94 days (Mercury Day Period)
59800 days (Neptune orbital period) = 344.6 x 175.94 days (Mercury Day Period)
90560 days (Pluto orbital period) = 520.2 x 175.94 days (Mercury Day Period)
- The errors are 1.4% and 1% with Neptune and Pluto orbital periods respectively,
no other error more than 1%
- The data tells, Mercury rate of time defines all planets orbital periods based on
Mercury Day Period.
- The data tells that, the planets orbital period be created in proportionality with one
another.
- We have to test all planets rates of time as Mercury to know if all periods be
definition correctly similar to Mercury test. For that reason we will test all planets
periods of time in the next point (No.4)

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4- The Solar Planets Rates Of Time Analysis
4-1 Preface
4-2 Venus Motion Rate of time
4-3 Earth Motion Rate of time
4-4 Mars Motion Rate of time
4-5 Jupiter Motion Rate of time
4-6 Saturn Motion Rate of time
4-7 Uranus Motion Rate of time
4-8 Neptune Motion Rate of time
4-9 Pluto Motion Rate of time
4-10 The General Discussion

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4-1 Preface
- In this point we test the planets motions rates of time definition as we have done
with mercury in the previous point. We bring Mercury test here in this preface to
be a reference for the other planets test.
MERCURY LIST
224.7 days (Venus orbital period) = 1.279 x 175.94 days (Mercury Day Period)
365.25 days (Earth orbital period) = 2.078 x 175.94 days (Mercury Day Period)
687 days (Mars orbital period) = 3.91 x 175.94 days (Mercury Day Period)
4331 days (Jupiter orbital period) = 24.6 x 175.94 days (Mercury Day Period)
10747 days (Saturn orbital period) = 61.1 x 175.94 days (Mercury Day Period)
30589 days (Uranus orbital period) = 174.8 x 175.94 days (Mercury Day Period)
59800 days (Neptune orbital period) = 344.6 x 175.94 days (Mercury Day Period)
90560 days (Pluto orbital period) = 520.2 x 175.94 days (Mercury Day Period)
Errors are 1.4% 1% with Neptune and Pluto respectively
- Each point uses a similar test with a planet of the solar group in order
- In point no. (4-10) we provide the general discussion of all data.

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4-2 Venus Motion Rate Of Time
I – Data
VENUS MOTION LIST
1 hour of Venus motion = (0.78) h of Mercury Motion
1 hour of Venus motion = 1.62 h of Earth Motion
1 hour of Venus motion = 3.057 h of Mars Motion
1 hour of Venus motion = 19.233 h of Jupiter Motion
1 hour of Venus motion = 47.8 h of Saturn Motion
1 hour of Venus motion = 136.7 h of Uranus Motion
1 hour of Venus motion = 269.4 h of Neptune Motion
1 hour of Venus motion = 406.7 h of Pluto Motion
1 hour of Venus motion = 47.54 h of The Moon Motion
- In Following We Provide The Data Analysis

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II–Data Analysis
175.94 days (Mercury day period) = 0.78 x 224.7 days (Venus orbital period)
365.25 days (Earth orbital period) = 1.62 x 224.7 days (Venus orbital period)
687 days (Mars orbital period) = 3.057 x 224.7 days (Venus orbital period)
4331 days (Jupiter orbital period) = 19.2 x 224.7 days (Venus orbital period)
10747 days (Saturn orbital period) = 47.8 x 224.7 days (Venus orbital period)
30589 days (Uranus orbital period) = 136.7 x 224.7 days (Venus orbital period)
59800 days (Neptune orbital period) = 266.2 x 224.7 days (Venus orbital period)
90560 days (Pluto orbital period) = 403 x 224.7 days (Venus orbital period)
- There Are Errors (1%) Only With Neptune And Pluto Orbital Periods
- Shortly
- All planets orbital periods be created based on Venus orbital period (224.7 days)
by using the rates of time between Venus and these planets –
- No error in all data more than 1% -
- The Data Proves That – The Rate of Time Controls The Solar System motion

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4-3 Earth Motion Rate Of Time
I – Data
EARTH MOTION LIST
1 hour of Earth motion = (0.48) h of Mercury Motion
1 hour of Earth motion = (0.617) h of Venus Motion
1 hour of Earth motion = 1.88 h of Mars Motion
1 hour of Earth motion = 11.8 h of Jupiter Motion
1 hour of Earth motion = 29.4 h of Saturn Motion
1 hour of Earth motion = 84.1 h of Uranus Motion
1 hour of Earth motion = 165.8 h of Neptune Motion
1 hour of Earth motion = 250.4 h of Pluto Motion
1 hour of Earth motion = 29.3 h of The Moon Motion

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II–Data Analysis
175.94 days (Mercury day period) = 0.48 x 365.25 days (Earth orbital period)
224.7 days (Venus orbital period) = 0.617 x 365.25 days (Earth orbital period)
687 days (Mars orbital period ) = 1.88 x 365.25 days (Earth orbital period)
4331 days (Jupiter orbital period) = 11.8 x 365.25 days (Earth orbital period)
10747 days (Saturn orbital period) = 29.4 x 365.25 days (Earth orbital period)
30589 days (Uranus orbital period) = 84.1 x 365.25 days (Earth orbital period)
59800 days (Neptune orbital period) = 163.8 x 365.25 days (Earth orbital period)
90560 days (Pluto orbital period) = 248 x 365.25 days (Earth orbital period)
- Errors (1.2% and 1%) With Neptune And Pluto Orbital Periods Respectively
- Shortly
- All planets orbital periods be created based on Earth orbital period (365.25 days)
by using the rates of time between Earth and these planets –
- No other error in all data more than 1% -

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4-4 Mars Motion Rate Of Time
I – Data
MARS MOTION LIST
1 hour of Mars motion = (0.255) h of Mercury Motion
1 hour of Mars motion = (0.327) h of Venus Motion
1 hour of Mars motion = (0.531) h of Earth Motion
1 hour of Mars motion = 6.3 h of Jupiter Motion
1 hour of Mars motion = 15.6 h of Saturn Motion
1 hour of Mars motion = 44.71 h of Uranus Motion
1 hour of Mars motion = 88.1 h of Neptune Motion
1 hour of Mars motion = 133 h of Pluto Motion
1 hour of Mars motion = 15.55 h of The Moon Motion

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II–Data Analysis
175.94 days (Mercury day period) = 0.255 x 687 days (Mars Orbital Period)
224.7 days (Venus orbital period) = 0.327 x 687 days (Mars Orbital Period)
365.25 days (Earth orbital period = 0.531 x 687 days (Mars Orbital Period)
4331 days (Jupiter orbital period) = 6.3 x 687 days (Mars Orbital Period)
10747 days (Saturn orbital period) = 15.6 x 687 days (Mars Orbital Period)
30589 days (Uranus orbital period) = 44.7 x 687 days (Mars Orbital Period)
59800 days (Neptune orbital period) = 88.1 x 687 days (Mars Orbital Period)
90560 days (Pluto orbital period) = 133 x 687 days (Mars Orbital Period)
- Errors (1.2% and 1%) With Neptune And Pluto Orbital Periods Respectively
- Shortly
- All planets orbital periods be created based on Mars orbital period (687 days) by
using the rates of time between Mars and these planets

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4-5 Jupiter Motion Rate Of Time
I – Data
JUPITER MOTION LIST
1 hour of Jupiter motion = (0.040) h of Mercury Motion
1 hour of Jupiter motion = (0.0419) h of Venus Motion
1 hour of Jupiter motion = (0.084) h of Earth Motion
1 hour of Jupiter motion = (0.1589) h of Mars Motion
1 hour of Jupiter motion = 2.48 h of Saturn Motion
1 hour of Jupiter motion = 7.1 h of Uranus Motion
1 hour of Jupiter motion = 14 h of Neptune Motion
1 hour of Jupiter motion = 21.1 h of Pluto Motion
1 hour of Jupiter motion = 2.47 h of The Moon Motion

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II–Data Analysis
175.94 days (Mercury day period) = 0.040 x 4331 days (Jupiter Orbital Period)
224.7 days (Venus orbital period) = 0.0419 x 4331 days (Jupiter Orbital Period)
365.25 days (Earth orbital period = 0.084 x 4331 days (Jupiter Orbital Period)
687 days (Mars orbital period) = 0.1589 x 4331 days (Jupiter Orbital Period)
10747 days (Saturn orbital period) = 2.48 x 4331 days (Jupiter Orbital Period)
30589 days (Uranus orbital period) = 7.1 x 4331 days (Jupiter Orbital Period)
59800 days (Neptune orbital period) = 14 x 4331 days (Jupiter Orbital Period)
90560 days (Pluto orbital period) = 21.1 x 4331 days (Jupiter Orbital Period)
- Errors (1.4% and 1%) With Neptune And Pluto Periods respectively
- All planets orbital periods be created based on Jupiter orbital period (4331days)
by using the rates of time between Jupiter and these planets

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4-6 Saturn Motion Rate Of Time
I – Data
SATURN MOTION LIST
1 hour of Saturn motion = (0.016) h of Mercury Motion
1 hour of Saturn motion = (0.0209) h of Venus Motion
1 hour of Saturn motion = (0.0339) h of Earth Motion
1 hour of Saturn motion = (0.0639) h of Mars Motion
1 hour of Saturn motion = (0.403) h of Jupiter Motion
1 hour of Saturn motion = 2.857 h of Uranus Motion
1 hour of Saturn motion = 5.63 h of Neptune Motion
1 hour of Saturn motion = 8.5 h of Pluto Motion
1 hour of Saturn motion = 1 h of The Moon Motion

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II–Data Analysis
175.94 days (Mercury day period) = 0.040 x 10747 days (Saturn Orbital Period)
224.7 days (Venus orbital period) = 0.0209 x 10747 days (Saturn Orbital Period)
365.25 days (Earth orbital period = 0.0339 x 10747 days (Saturn Orbital Period)
687 days (Mars orbital period) = 0.0639 x 10747 days (Saturn Orbital Period)
4331 days (Jupiter orbital period) = 0.403 x 10747 days (Saturn Orbital Period)
30589 days (Uranus orbital period) = 2.857 x 10747 days (Saturn Orbital Period)
59800 days (Neptune orbital period) = 5.63 x 10747 days (Saturn Orbital Period)
90560 days (Pluto orbital period) = 8.5 x 10747 days (Saturn Orbital Period)
- Errors (1%) Only With Neptune And Pluto Orbital Periods
- Shortly
- All planets orbital periods be created based on Saturn orbital period (10747 days)
by using the rates of time between Saturn and these planets

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4-7 Uranus Motion Rate Of Time
I – Data
URANUS MOTION LIST
1 hour of Uranus motion = (0.0057) h of Mercury Motion
1 hour of Uranus motion = (0.0073) h of Venus Motion
1 hour of Uranus motion = (0.011) h of Earth Motion
1 hour of Uranus motion = (0.022) h of Mars Motion
1 hour of Uranus motion = (0.14) h of Jupiter Motion
1 hour of Uranus motion = (0.3499) h of Saturn Motion
1 hour of Uranus motion = 1.97 h of Neptune Motion
1 hour of Uranus motion = 2.97 h of Pluto Motion
1 hour of Uranus motion = (0.349) h of The Moon Motion

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II–Data Analysis
175.94 days (Mercury day period) = 0.0057 x 30589 days ( Uranus Orbital Period)
224.7 days (Venus orbital period) = 0.0073 x 30589 days ( Uranus Orbital Period)
365.25 days (Earth orbital period = 0.011 x 30589 days ( Uranus Orbital Period)
687 days (Mars orbital period) = 0.022 x 30589 days ( Uranus Orbital Period)
4331 days (Jupiter orbital period) = 0.14 x 30589 days ( Uranus Orbital Period)
10747 days (Saturn orbital period) = 0.3499 x 30589 days (Uranus Orbital Period)
59800 days (Neptune orbital period) = 1.97 x 30589 days ( Uranus Orbital Period)
90560 days (Pluto orbital period) = 2.97 x 30589 days ( Uranus Orbital Period)
- No Error In All Data More Than 1% -
- All planets orbital periods be created based on Uranus orbital period (30589 days)
by using the rates of time between Uranus and these planets

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4-8 Neptune Motion Rate Of Time
I – Data
NEPTUNE MOTION LIST
1 hour of Neptune motion = (0.0029) h of Mercury Motion
1 hour of Neptune motion = (0.0037) h of Venus Motion
1 hour of Neptune motion = (0.006) h of Earth Motion
1 hour of Neptune motion = (0.011) h of Mars Motion
1 hour of Neptune motion = (0.0713) h of Jupiter Motion
1 hour of Neptune motion = (0.177) h of Saturn Motion
1 hour of Neptune motion = (0.507) h of Uranus Motion
1 hour of Neptune motion = 1.509 h of Pluto Motion
1 hour of Neptune motion = (0.1773) h of The Moon Motion

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II–Data Analysis
175.94 days (Mercury day period) = 0.0029 x 59800 days (Neptune Orbital Period)
224.7 days (Venus orbital period) = 0.0037 x 59800 days (Neptune Orbital Period)
365.25 days (Earth orbital period = 0.006 x 59800 days (Neptune Orbital Period)
687 days (Mars orbital period) = 0.011 x 59800 days (Neptune Orbital Period)
4331 days (Jupiter orbital period) = 0.0713 x 59800 days (Neptune Orbital Period)
10747 days (Saturn orbital period) = 0.177 x 59800 days (Neptune Orbital Period)
30589 days (Uranus orbital period) = 0.507 x 59800 days (Neptune Orbital Period)
90560 days (Pluto orbital period) = 1.509 x 59800 days (Neptune Orbital Period)
- Neptune orbital period creates an error 1.3% with all data except Pluto and
Uranus
- All planets orbital periods be created based on Neptune orbital period (59800 days)
by using the rates of time between Neptune and these planets

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4-9 Pluto Motion Rate of time
I – Data
PLUTO MOTION LIST
1 hour of Pluto motion = (0.00192) h of Mercury Motion
1 hour of Pluto motion = (0.00245) h of Venus Motion
1 hour of Pluto motion = (0.00399) h of Earth Motion
1 hour of Pluto motion = (0.0075) h of Mars Motion
1 hour of Pluto motion = (0.0472) h of Jupiter Motion
1 hour of Pluto motion = (0.1174) h of Saturn Motion
1 hour of Pluto motion = (0.336) h of Uranus Motion
1 hour of Pluto motion = (0.662) h of Neptune Motion
1 hour of Pluto motion = (0.11743) h of The Moon Motion

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II–Data Analysis
175.94 days (Mercury day period) = 0.00192 x 90560 days (Pluto Orbital Period)
224.7 days (Venus orbital period) = 0.00245 x 90560 days (Pluto Orbital Period)
365.25 days (Earth orbital period = 0.00399 x 90560 days (Pluto Orbital Period)
687 days (Mars orbital period) = 0.0075 x 90560 days (Pluto Orbital Period)
4331 days (Jupiter orbital period) = 0.0472 x 90560 days (Pluto Orbital Period)
10747 days (Saturn orbital period) = 0.1174 x 90560 days (Pluto Orbital Period)
30589 days (Uranus orbital period) = 0.336 x 90560 days (Pluto Orbital Period)
59800 days (Neptune orbital period) = 0.662 x 90560 days (Pluto Orbital Period)
- Pluto orbital period creates error 1% with all data.
- No error In All Data More Than 1% -
- All planets orbital periods be created based on Pluto orbital period (90560 days)
by using the rates of time between Pluto and these planets –
The Data Proves That – The Rate of Time Controls The Solar System motion

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4-10 The General Discussion
- Shortly
- The data shows that
- All Planets Orbital Periods are rated with one another by the rates of time we
have calculated based the required periods for the solar planets orbital distances
motions.
- Why?
- If the solar planets motions are independent from one another, how all planets
orbital periods be defined based on these rates?
- In the next point (No.5) we prove that, the solar planets orbital distances be created
depending on these rates of time also. How that can be possible?
- Why all planets orbital periods and distances be defined based on these rates of
time?
- BUT
- We should keep an eye on the required periods because they are the source based
on which the rates of time be created.
- And
- The question should be,
- Are these required periods be defined independently from one another? or all these
periods be defined based on one another by using one law only?
- I want to say,
- We have to know perfectly the answer of this question, because if there's one law
or one Equation by which the planets required periods can be defined that
summarizes all data of the solar planets orbital periods and distances into one
Equation only
- In this case we can use the one equation in place of all planets orbital periods and
distances, and as a result no need for any observation for this data because we can
conclude them theoretically

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- That's why we need to move step by step in our discussion, and proves each step
strongly because it will result one equation is place of ten planets orbital periods
and distances.
- After we do that, we have to discuss the reason behind.
- Now let's move to the next point to prove,
- The Planets Orbital Distances Be Defined Based On These Rates Of Time.
- NOTICE
- If we prove that, the solar planets distances be based on these rates of time, the
solar group description should be changed into the following one…
- (Solar Group Is)
- The Solar Group is similar to a machine of gears each planet is a gear in it, or
- The Solar Group is similar to one building and each planet is a part of this same
building, or
- The Solar Group is similar to one body and each planet is a member of it, or
- The Solar Group is similar to puppets theater, all puppets are connected together
by one force and causes their motions, or
- The Solar Group is similar a canal, the water moves through it and causes the
rotation of 9 waterwheels. The Motion Direction of The waterwheels is different
from the water motion direction but no waterwheel can rotate without the water
motion, or
- The solar planets are similar to train carriages, they move together one unified
general motion, or
- The solar planets be similar to knots on one robe or similar to points on the same
one trajectory of energy –
- The solar planets motions be similar to chess board pieces motions, each motion
depend on the other planets motions and be done by geometrical calculations.
- Clearly
- The Planets Move One Unified Motion Be Done In Equal Periods Of Time

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5- The Planets Orbital Distances Depend On Their Rates Of Time
5-1 Preface
5-2 The Planets Orbital Distances Test
5-3 Mars, Jupiter and Saturn Motions Analysis
5-4 One Equation controls The planets orbital periods and distances
5-5 Why Saturn And The Moon Use Equal Rates Of Time?
5-6 Why Mercury Use A Double Of Its Orbital Distance?
5-7 Pluto And Saturn Motions Rate of Time
5-8 The Rate (4.61) be used between Pluto and the moon motion
5-9 The Moon Orbital Motion Equation

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5-1 Preface
- In This Point We Have Defined Tasks Are:
- We prove, the solar planets distances be created based on their rates of time (Point
No. 5-2)
- We analyze Mars, Jupiter and Mercury Motions to explain how their motions data
be created (for example we answer, Why Saturn Orbital Distance = 2π x Mars
Orbital Distance) (Point No. 5-3)
- We prove, There's One Equation controls all planets orbital periods and distances
(Point No. 5-4)
- Then,
- We try to answer why Saturn rate of time equal the Earth moon rate of time and
what effect of this equality on both planets motions (Point No. 5-5).
- And
- We ask why Mercury use double values (Point No.5-6)
- Then
- We analyze Saturn and Pluto Motions Rate Of Time in (Point No.5-7)
- Then
- We analyze The basic rate between Pluto and the moon motion data (4.61), this
analysis is done (Point No. 5-8)
- The moon orbital motion equation we discuss (Point No. 5-9)

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5-2 The Planets Orbital Distances Test
- Let's refer to what we will do here
- We remember here Mercury rates of time with the other planets
- Then
- We suppose that, Mercury moves during one solar day
- And
- We will find the other planets periods of time in comparison with this 1 solar day
of Mercury motion based on these planets rates of time with Mercury
- Then
- We will discover the distances the planets pass during these periods
- Then
- We will compare these distances with Mercury motion distance for 1 solar day
=4.095 mkm
- Based on this comparison, we should test if the planets orbital distances be defined
based on these planets rates of time,
- Let's Do That In Following…

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I- Data
Mercury Rates Of Time
The Motions Distances Based On Mercury Rates Of Time
(1)
Mercury (4.095 mkm / solar day) moves during 1 day a distance =4.095 mkm
(2)
Venus (3.024 mkm / solar day) moves during 1.279 days a distance =3.867 mkm
(3)
Earth (2.574 mkm / solar day) moves during 2.078 days a distance = 5.35 mkm
(4)
Mars (2.082 mkm / solar day) moves during 3.91 days a distance = 8.14 mkm
(5)
Jupiter (1.13184 mkm / solar day) moves during 24.6 days a distance = 27.8 mkm
(6)
Saturn (0.838 mkm / solar day) moves during 61.1 days a distance = 51.2 mkm
(7)
Uranus (0.5875 mkm / solar day) moves during 174.8 days a distance = 102.7 mkm
(8)
Neptune (0.4665 mkm / solar day) moves during 344.8 days a distance = 160.8 mkm
(9)
Pluto (0.406 mkm / solar day) moves during 520.2 days a distance = 211.2 mkm

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II- Data Analysis
No. (2)
(Venus motion distance=3.867 mkm) /(Mercury Motion Distance 4.095 mkm) =0.944
Where
(Venus orbital circumference =680 mkm) /(Mercury Distance 720.7 mkm) =0.944
No. (3)
(Earth motion distance=5.35 mkm) /(Mercury Motion Distance 4.095 mkm) =1.3
Where
(Earth orbital circumference =940 mkm) /(Mercury Distance 720.7 mkm) = 1.3
No. (4)
(Mars motion distance=8.14 mkm) /(Mercury Motion Distance 4.095 mkm) = 1.98
Where
(Mars orbital circumference =1433 mkm) /(Mercury Distance 720.7 mkm) = 1.98
No. (5)
(Jupiter motion distance=27.8 mkm) /(Mercury Motion Distance 4.095 mkm) = 6.8
Where
(Jupiter orbital circumference =4900 mkm) /(Mercury Distance 720.7 mkm) = 6.8
No. (6)
(Saturn motion distance=51.2 mkm) /(Mercury Motion Distance 4.095 mkm) = 12.5
Where
(Saturn orbital circumference =9010 mkm) /(Mercury Distance 720.7 mkm) = 12.5
No. (7)
(Uranus motion distance =102.7 mkm) /(Mercury Motion Distance 4.095 mkm) =25.1
Where
(Uranus orbital circumference =18048 mkm) /(Mercury Distance 720.7 mkm) = 25.1

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No. (8)
(Neptune motion distance =161 mkm) /(Mercury Motion Distance 4.095 mkm) =39.3
Where
(Neptune orbital circumference =28255 mkm) /(Mercury Distance 720.7 mkm) = 39.3
No. (9)
(Pluto motion distance =211.2 mkm) /(Mercury Motion Distance 4.095 mkm) =51.6
Where
(Pluto orbital circumference =37100 mkm) /(Mercury Distance 720.7 mkm) = 51.6
- Let's discuss the previous data in following:

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III- Discussion
(A)
- The data proves that
- The solar planets orbital circumferences are defined depending on these planets
motions rates of time.
- Based on that,
- THE PLANETS MOTIONS RATES OF TIME DEFINE THESE PLANETS
ORBITAL PERIODS AND DISTANCES.
- i.e.
- A huge number of data be controlled by a small group of data.
- Means,
- The solar planets periods and distances are defined as functions in the planets
motions rates of time.
- But
- The planets motions rates of time be defined based on The Required Periods For
The Planets Orbital Distances Motions.
- Shortly
- It tells, if we know the required periods we can calculate all solar planets orbital
distances and periods.
- Now, the question is,
- Are these required periods be defined based on one another or independently from
one another?
- The question = All Planets Orbital Distances And Periods
- Because
- If the required periods be defined based on one another and we can use One
Equation to calculate these required periods – that will summarize all solar planets
periods and distances into One Equation.
- That shows the importance behind this discussion.

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- Because
- One Equation controls all planets orbital periods and distances
(B)
- Usually The Planets Motions Data shows different puzzles,
- Let's remember some of them, (Saturn Orbital Distance = 2π x Mars Orbital
Distance),and (Uranus Orbital Distance = 2 Saturn Orbital Distance) Also
(Neptune Orbital Distance = π x Saturn Orbital Distance).
- All these rates can be concluded from the previous distances, shows that, these
rates be results of the planets motions rates of time.
- I want to say, many planets motions data can be understood and explained by this
analysis of the passed distances.
- The planets motions rates of time give us a chance for better understanding for
how the planets motions data be created.
- By that we will have more clear vision about the planets creation process.
- In next point (5-3) we analyze mars, Jupiter and Saturn Motions data to explain
how their data be created by effect of their motions rates of time and by that, we
understand how these planets motions data be created, which solves many old
unanswered questions.
- Notice
- Mercury uses the distance 720.7 mkm in place of its orbital circumference 360
mkm, and uses its day period 175.95 solar days in place of its orbital period (88
days) and uses the required period 671 hours to move a distance = 2 x 57.2 mkm
(Mercury orbital distance) (error 1%)
- Shortly Mercury uses a double value of its data in comparison with the other
planets. Although if Mercury use the ordinary data as other planets it works by
Mercury uses double value because of a basic geometrical reason we should
discuss in point no. (5-6).

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5-3 Mars, Jupiter And Saturn Motions Analysis
- In this point we use the planets motions rates of time to explain the puzzled data of
Mars, Jupiter and Saturn Motions
- Let's take a look on this puzzled data in following:
- 4331 days (Jupiter Orbital Period) =2π x 687 days (Mars Orbital Period)
- 1433 mkm (Saturn Orbital Distance) =2π x227.9 mkm (Mars Orbital Distance)
- 10747 days (Jupiter Orbital Period) =2.5 x 4331 mkm (Jupiter Orbital Period)
- 24.1 km/s (Mars Velocity) =2.5 x 9.7 km/s (Saturn Velocity)
- 24.6 h (Mars rotation period) =2.5 x 9.9 h (Jupiter Day Period)
- ((10747 days x 24 h) /24.6 h) = ((4331 days x 24 h) /9.9h) = 10485
- 3.1 deg (Jupiter Axial Tilt) x 2 = (2.5 deg = Saturn orbital inclination)2
- Let's use the planets motions rates of time to help us to answer how the data be
created…

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I - Data
(5-3-a)
- 1 hour of Mars Motion = 6.3 hours of Jupiter Motion = 15.56 hours of Saturn
Motion = 44.6 hours of Uranus Motion = 88 hours of Neptune motion = 132.7
hours of Pluto motion
(5-3-b)
- 4331 days (Jupiter Orbital Period) =2π x 687 days (Mars Orbital Period)
- 1433 mkm (Saturn Orbital Distance) =2π x227.9 mkm (Mars Orbital Distance)
- 10747 days (Jupiter Orbital Period) =2.5 x 4331 mkm (Jupiter Orbital Period)
- 24.1 km/s (Mars Velocity) =2.5 x 9.7 km/s (Saturn Velocity)
- 24.6 h (Mars rotation period) =2.5 x 9.9 h (Jupiter Day Period)
- ((10747 days x 24 h) /24.6 h) = ((4331 days x 24 h) /9.9h) = 10485

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II –Discussion
Equation no. (5-3-a)
- 1 hour of Mars Motion = 6.3 hours of Jupiter Motion = 15.56 hours of Saturn
Motion = 44.6 hours of Uranus Motion = 88 hours of Neptune motion = 132.7
hours of Pluto motion
- These rates of time we have concluded in point no. (4) of this paper.
- i.e.
- 1 Solar Day of Mars Motion = 6.3 Solar Days of Jupiter Motion = 15.56 Solar
Days of Saturn Motion = 44.6 Solar Days of Uranus Motion = 88 Solar Days
of Neptune motion = 132.7 Solar Days of Pluto motion.
- Let's define the distances which these planets pass during these periods of time
- Mars (2.08 mkm per solar day) moves during 1 solar day a distance = 2.082 mkm
- Jupiter (1.1318 mkm per day) moves during 6.3 solar days a distance = 7.13 mkm
- Saturn (0.838 mkm per day) moves during 15.56 solar days a distance =13.1 mkm
- Uranus (0.5875 mkm per day) moves during 44.6 days a distance=26.22 mkm
- Neptune (0.466560 mkm per day) moves during 88 days a distance = 41.05 mkm
- Pluto (0.406 mkm per day) moves during 132.7 solar days a distance =53.88 mkm
- Based on that
- Mars during (1 solar day) moves 2.082 mkm
- Jupiter during (6.3 solar day) moves 7.13 mkm
- Saturn during (15.5 solar day) moves 13.1 mkm
- Uranus during (44.6 solar day) moves 26.22 mkm
- Neptune during (88 solar day) moves 41.05 mkm
- Pluto during (132.7 solar day) moves 53.88 mkm

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Data Analysis
(1)
- Saturn motion distance = 13.1 mkm = Mars Motion Distance 2.08 mkm x 2π
- This data explains why
- Saturn orbital circumference 9007 mkm = Mars orbital circumference 1433
mkm x 2π
(2)
- Uranus motion distance = 26.22 mkm = Saturn Motion Distance 13.1 mkm x 2
- Uranus orbital circumference 18048 mkm = Saturn orbital circumference
9007 mkm x 2
(3)
- Neptune motion distance =41.05 mkm =Saturn Motion Distance 13.1 mkm x π
- Neptune orbital circumference 28255 mkm = Saturn orbital circumference
9007 mkm x π
(4)
- Pluto motion distance =53.9 mkm =Saturn Motion Distance 13.1 mkm x 4.11
- Pluto orbital circumference 37100 mkm = Saturn orbital circumference 9007
mkm x 4.11
(5)
- Pluto motion distance =53.9 mkm =Uranus Motion Distance 26.22 mkm x 2.06
- Pluto orbital circumference 37100 mkm= Uranus orbital circumference 18048
mkm x 2.06

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Discussion (Continued)
- Now we know that,
- Saturn moves a distance =13.1 mkm = 2π x Mars Distance 2.082 mkm
- Simply that rate (2π) is created here because of the motions rates of time among
the planets.
- We have explained one data
- Based on that, the rate (2π) isn't be created by any pure coincidence of numbers
but because,
- 1 day of Mars motion = 6.3 days of Jupiter motion = 15.56 days of Saturn motion
- These rates of time effect on the planets motions distances
- The period 15.56 days enables Saturn to move 13.1 mkm = (2π) x Mars Motion
Distance per a solar day (2.082 mkm).
- By that we explain clearly how these planets data be created.
- The result is important because, it tells we can explain all planets motions data
origin.
- Now
- We explained why Saturn orbital distance = (2π) Mars orbital distance
- Let’s try with another data
- Why Mars Velocity =(2.5) Saturn Velocity?
- Let's analyze the data no (4 and 5) to explain this one
(5)
- Pluto orbital circumference 37100 mkm= Uranus orbital circumference 18048
mkm x 2.06 = Saturn orbital circumference 9007 mkm x 4.1
- Pluto is a common point between the 2 planets (Saturn and Uranus), and the rates
are (4.1 and 2.06), but we know that, Mercury motion distance per a solar day
=4.095 mkm and Mars motion distance per a solar day =2.08 mkm (error 1%)
- The rates can be used as these planets velocities…

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- That tells Mercury Velocity = 2 x Mars velocity (approximately), because Uranus
orbital distance = 2 x Saturn orbital distance – that connects the solar system and
makes it as one machine.
- But
- Even if we accept that, the velocities are Mars and Mercury, where we search for
Mars and Saturn velocities rate,
- BUT
- Mercury velocity 47.4 km/s x 2 = (Saturn velocity 9.7 km/s)2
- That makes Saturn velocity as a function in Mercury velocity, the point is we have
seen this type of equation before let's remember it
- I want to say,
- It's a geometrical method used by Saturn with Jupiter and with Mercury
- Please Notice
- By discovery of the planets motions rates of time we enable to explain the rate
(2π) between Saturn and Mars orbital distances. And now we have a trustee
method to explain this rate (2π).
- But, there are many other geometrical methods needed to be discovered to explain
the other data because of that the form (Data)2
is a form we need to discover its
geometrical mechanism. But the data isn't created by pure coincidence of numbers
on the contrary base on a geometrical mechanism need to be discovered.
- Notice
- The planet motion has its own effect on its data for example (26.7 =2.5 x10.7)
(where 10.7 h = Saturn day period, 2.5 deg = Saturn orbital inclination, 26.7 deg =
Saturn Axial Tilt) There's a geometrical machine behind this data but we still need
to analyze Saturn motion data in more deep analysis.
- Also 687 days (Mars Orbital Period) + 2 x 3.1 = 2 x 346.6 days (the nodal year)
(where 3.1 deg = Jupiter Axial Tilt)

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5-4 One Equation controls The planets orbital periods and distances
- Let's summarize how this one equation can be created in following:
(Point No. I)
- The Solar Planets move their orbital circumferences in equal periods (The Paper
hypothesis)
- As a result, the solar planets motions use different rates of time, as we proved in
the previous points discussions
- The geometrical result for the planets motion rates of time is the solar system
distances creation and distribution in A Network Form.
- Means, the solar system distances be in one piece or one geometrical design as one
network, they are created and distributed based on one geometrical design. The
solar system distances Network Theory be explained and proved in point no. (12)
of this paper.
- We need here just to know that, the distances are distributed relative to one another
based on a network form and by one geometrical design.
- This fact is our basic point on which we conclude the one equation which controls
the planets orbital periods and distances
(Point No. II)
- Mars was the next planet after Mercury with original orbital distance =84 mkm
and Pluto was the Mercury moon revolves around it
- Mars and Pluto had migrated from their original orbital distances to their current
positions.
- Now
- The solar system distances are created in a network form, and
- The planets migration caused changes in the whole network, effected negatively on
the solar system general design and put it in risk
- The solar system geometrical design had tried to repair the negative results which
be produced by the planets migration

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- To do this job,
- The solar system geometrical design wanted to reform the network based on Mars
and Pluto new positions…
- This Task necessitated the solar system geometrical design to depend on Mars and
Pluto motions rate of time in the one equation creation.
- Means
- The one equation which controls all planets orbital distances and periods be
defined as a function in Mars and Pluto motions rate of time (133)
- The solar system geometrical design had to do that to save the planets motions
general harmony and to repair the negative effects of the planets migration on the
whole solar system motion and design.
(Point No. III)
- Why the solar system geometrical design needs to depend on Mars and Pluto
motions rate of time? Let's try to answer in following
- The planets orbital distances and periods are defined based on these distances
motions rates of time, and
- The planets motions rates of time be defined based these planets required periods
to move their orbital distances.
- The required periods we have calculated clearly and used them to define the
planets motions rates of time, let's remember them in following
- The Required Periods List
- For Mercury (27.9 Solar Days) – for Venus ( 35.8 Solar Days) – for Earth (58.1
Solar Days) – for the moon (1700 Solar Days) – for Mars ( 109.4 Solar Days) for
Jupiter (687 Solar Days )- for Saturn (1710 Solar Days) - for Uranus (4890 Solar
Days) - for Neptune (9635 Solar Days) – for Pluto (14547 Solar Days)
- Now
- Based on these required periods the planets motions rates of time be created and
based on the rates of time the planets orbital periods and distances be created….

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- Means,
- If we have one equation expresses these periods based on one another, by that
these periods will be summarized into one equation and as a result we can define
all planets orbital periods and distances based on this one equation.
- Now this equation depend on Mars and Pluto Rate Of Time (133) and we have no
explanation why except the planets migration reason.
- The point is that,
- The outer planets periods total = the inner planets periods total x 133
- And by that the rate (133) be found in the basic definition of the planets required
periods to pass their orbital distances.
- The data analysis discussion can make this discussion more clear,
- Let's analyze the data in following directly
- Notice
- (Mars Migration Theory be discussed in the next Point no.6 of this paper)

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(Point No. IV) One Equation Controls The Data
- Let's Summarize The One Law Idea In Following:
o The Solar Planets Required Periods Total Be = 31705 Solar Days
o The Inner Planets Required Periods Total Be = 235.8 Solar Days
o The Outer Planets Required Periods Total Be = 31469 Solar Days
o Notice
o The moon used required period is 4.61 days and not 1700 days because we
account the moon orbital distance to earth and not to the sun
(A)
o 31469 days (the outer planets) = 235.8 days (the inner planets) x 133
o Where 1 Mars Solar Day = 133 Pluto Solar day
o And
(B)
o 31705 solar day = 109.4 solar days x 133 x 2.18
o Where
o 31705 days = All Planets Total
o 109.4 solar days = Mars required period to move a distance = Mars orbital
period.
o 133 is used for second time
o 2.18 mkm = Mars Motion for a period 25.1 hours
o The using of the rate (133) two times shows that, the rate using is mentioned
(C)
o Let's summarize the idea in following
o The planets required periods are controlled by the planets unified motion,
that means, the periods total (31705 solar days) controls all data
o The periods total (31705 solar days) be divided into 2 parts (the inner) and
(the outer) these 2 parts be defined based on the rate of time between Mars
and Pluto.

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o These 2 planets are the 2 basic points to which the (total periods) be divided.
o The total period division means it creates one Equation, because the periods
total be divided into (2 parts) and each planet transports its period to its
group planets. Means Mars transports the periods to the inner planets and
Pluto transports to the outer planets.
o Based on that, all periods be defined based on one another and creates one
equation.
(D)
o Mars transports the period of time to the Earth and earth transported to
Venus and Venus to Mercury. The inner planets transport the periods of
time from one another by using the planets orbital inclination (And Earth
uses its axial tilt)
o Pluto transports the period of time to the (4) outer planets, by Pluto effect on
these 4 planets days periods total (53.9 hours).
o Let's analyze the data in following for better understanding.
o NOTICE
o The Motion Be Transported Among The Solar Planets By Time Periods
Transportation.
o This meaning is clear concluded from the data, but no geometrical machine
is clear yet. The basic question is that, why the planets motions rates of time
effect on the planets motions features. This fact which we have seen in all
planets orbital periods and distances – the rates of time cause to control this
data – but by what force the rate of time does this effect? Here also we have
a similar point. The motion transportation be done by transportation of a
period of time, how a period of time can be transported from a planet to
another? the data can help this question answer.

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(Point No. V) (The Data Discussion)
I- Data
Group No. (A)
(A-I)
31469 days (the outer planets) = 235.8 days (the inner planets) x 133
(A-II)
31705 solar day = 109.4 solar days x 133 x 2.18
Group No. (B)
(5-4-a)
109.4 solar days =1.88 x 58.1 solar days
(5-4-b)
23.6 x 1.622 = 35.7 solar days x 1.0725
(5-4-c)
27.9 solar days = 7π x 1.279
(5-4-d)
133 solar days x 0.406 mkm =53.9 mkm

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II- Discussion
Group No. (A)
Equation no. (A- I)
31469 days (the outer planets) = 235.8 days (the inner planets) x 133
- This equation we know, it tells
- A rate 133 be found between the inner planets required periods total the outer
periods total – why? because 133 is the rate between Mars and Pluto motions, by
that the periods total be divided into the inner and the outer based on (133), that
means, all other planets will define their required periods based on Mars and Pluto
required periods.
- Shortly
- The periods total = (T) for example, this (T) is divided between Mars and Pluto at
first and the 2 planets transported the rest period to their groups planets!
Equation no. (A-II)
31705 solar day = 109.4 solar days x 133 x 2.18
o Where
o 31705 days = All Planets Total
o 109.4 solar days = Mars required period to move a distance = Mars orbital
period.
o 133 is used for second time
o 2.18 mkm = Mars Motion for a period 25.1 hours
- Let's try to understand this equation
- Mars needs a period 109.4 solar day to pass its orbital distance (227.9 mkm) (Mars
moves a distance 2.082 mkm per a solar day 24 hours)
- 109.4 days of Mars be equal 109.4 days x 133 at Pluto
- Means,

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- If the equation be
- 109.4 days x 2.082 mkm/s x 133, this equation will be understood, it tells
- The distance mars moves during 109.4 solar days be (109.4 x 2.082 =227.9 mkm
= Mars orbital distance), this distance be seen by Pluto as a period of time (1 mkm
= 1days) mans it equals (227.9 solar days) but (1soalr day of Mars Motion =133
days of Pluto motion) as a result the period will be (30589 days = Uranus orbital
period error 1%)
- This manning we can't use now
- Because the velocity isn't 2.082 mkm but 2.18 mkm and Mars moves 2.18 mkm in
25.1 hours
- The difference be = 4.5% this is very interesting difference because
- 90560 seconds /86400 seconds = 1.045
- Means
- 90560 is greater with 4.5% than the solar day 86400 seconds , But
- 90560 days = Pluto orbital period
- For a geometrical reason Mars uses 25.1 hours in place of 24 hours!
- This subject we should discuss with the next point (5-5) which answers why
Saturn motion rate of time = the moon motion rate of time.
- There we should discuss why Mars uses 25.1 hours in place of 24 hours in this
equation
- Notice
- 366565 km (the outer planets diameters total) = 2390 km (Pluto diameter) x 153.3
- 153.3 h = Pluto day period

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Group No. (B)
Equation no. (5-4-a)
109.4 solar days =1.88 x 58.1 solar days
- Where
- 109.4 days = the period Mars needs to pass a distance 227.9 mkm = Mars orbital
distance, by using a velocity =2.082 mkm pr solar day
- 1 hour of Earth motion =1.88 hours of Mars Motion
- But
- 1.88 degrees = Mars orbital inclination (error 1%)
- I claim that, Mars transports the period (109.4 days) to Earth and be (58.1 days) by
using Mars orbital inclination – that may explain why Mars orbital inclination =
1.9 degrees.
- Shortly, Mars transports the period to Earth by using Mars orbital inclination.
- Please note
- The system controls all data by using the planets required periods, that means, the
control method is a period of time. That's what I need to explain clearly. The solar
group is a machine works as a great mechanical clock, the main force in this
machine is the period of time, it's the method of control for the machine work, So,
while Mars transports to Earth a period of time, means, Mars gives Earth a
treasure.

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Equation no. (5-4-b)
23.6 solar days x 1.622 = 38.27 days = 35.7 days x 1.0725, Where
- 1 hour of Venus = 1.622 hours of Earth
- 35.7 solar days = Venus Required Period To Pass Its Orbital Distance
- 23.6 days of Earth be = 38.27 days of Venus
- But Venus required period is 35.7 days = 38.27 days/ 1.0725
- Means, Venus required period be defined based on the rate 1.0725
- We know this rate controls 40% of all solar planets distances and by that its effect
is a fact we don't know why it effects on data, but it's a fact we have no option to
escape.
- Just,
- We know that Venus data uses this rate 1.0725 for example
- 243 days (Venus rotation period) = 224.7 days (Venus orbital period) x 1.0725
- This behavior is perfectly similar to the moon behavior where
- 29.53 days (The moon day period) = 27.3 days (the moon rotation period) x 1.0725
- And
- 2.4 mkm (the moon daily distance) =2.574 mkm (Earth daily distance) x1.0725
- So, if Venus use the transported period from Earth by effect of the rate (1.0725),
that can be considered as a usual using.
- Now
- What's 23.6 days? Because earth axial tilt =23.4 degrees and even if we consider
each 1 degree = 1 solar day, the number is 23.4 and not 23.6?!
- 17.4 degrees = the inner planets orbital inclination
- 17.2 degrees = Pluto orbital inclination (error 1%)
- 23.6 degrees = the outer planets orbital inclination
- 23.4 degrees = Earth Axial Tilt (error 1%)
- But
- 40.8 degrees = 23.6 degrees +17.2 degrees = 23.4 degrees +17.4 degrees

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Equation no. (5-4-c)
27.9 solar days = 7π x 1.279 (error 1%)
- Where
- 27.9 solar days = Mercury required periods to pass it’s a distance = 2 x 57.2 mkm
(Mercury orbital distance error 1%)
- 1 h of Mercury motion =1.279 h of Venus Motion
- 7 degrees = Mercury orbital inclination and 7π =22
- Venus transported the period through Mercury orbital inclination.
- We understand that, the periods transportation is done by using the planets orbital
inclination but, Earth uses its Axial Tilt.
Equation no. (5-4-d)
133 solar days x 0.406 mkm =53.9 mkm
- Where
- 1 solar day of Mars = 133 solar days of Pluto
- 0.406 mkm = Pluto motion distance per a solar day
- Equation no. (5-4-d) tells, Pluto moves 53.9 mkm during the period 133 solar days.
- We see that, this period (133) is the cornerstone of our discussion and the
cornerstone of the planets required periods total. we deal with this number along
the data discussion.
- I want to say, the distance (53.9 mkm) is mentioned distance because the period
133 solar days is mentioned period, as we have discussed clearly
- The 4 planets days periods total (Jupiter 9.9 +Saturn 10.7 + Uranus 17.2 + Neptune
16.1) = 53.9 hours
- We need to find the geometrical machine by which 1 mkm be used as 1 hour,
based on this machine, Pluto motion distance will cause the period 53.9 h to be
created. by that Pluto transports the period to them.

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- Notice
- 2815 mkm = Mercury Uranus distance, if 1 mkm = 1 hour this value 2815 mkm =
2815 h = 2 x 1407.6 hours (Mercury rotation period)
- Notice
- (153.3 h /53.9 h) = 1.16 mkm/0.406 mkm= 4890 days /1700 days= (30589 days
/10747 days)
- This equation creates an importation meaning we should discuss later
- Notice
- We should remember the error (4.5%),
- This error is found between (2.082 mkm = Mars velocity per a solar day) and the
value 2.18 mkm (Mars motion distance in 25.1 hours we have found in equation
no. (II))
- This error is very important error because it controls basic data
- For example
- The moon required period to pass 149.6 mkm (Earth orbital distance) by its daily
displacement 88000 km be (1700 solar days)
- Pluto moves during (1775 solar days ) a distance =720.7 mkm (Mercury Jupiter
Distance)
- These 2 values difference = (4.5%),
- Where (5906 mkm/149.6 mkm) = 39.23 = 4.61 x 8.51
- We should discus that in point no. (5-8) which discuss the rate (4.61) between
Pluto and the moon motions.
- I wanted to explain that, this rate (4.5%) be defined by a geometrical necessity.
NOTICE
Venus (3.024 mkm per solar day) moves during 10485 days a distance =31705 mkm

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5-5 Why Saturn And The Moon Use Equal Rates Of Time?
I-Data
(5-5-a)
- The moon needs accurately 1700 solar days to pass a distance = 149.6 mkm =
(Earth orbital distance) by using its daily displacement 88000 km
And
- Saturn needs accurately 1710.457 solar days to pass a distance = 1433.5 mkm =
Saturn orbital distance
- The difference between the 2 periods (1700 days and 171.457 days = 251 hours)
(5-5-b)
90560 seconds = 25.1 hours
(5-5-c)
4.095 mkm (Mercury velocity per solar day) x 1433.5 days = 5848 mkm
0.838 mkm (Saturn velocity per solar day) x 6939.75 days = 5848 mkm
1.16 mkm/sec x 5040 seconds = 5848 mkm (Mercury Pluto Distance)
(5-5-d)
(4900 days /1710 days) = (153.3 hours / 53.9 hours) = (1.16 mkm /0.406 mkm)
(5-5-e)
317050 days = 37100 days x 8.5
But
(for revision) (A- II)
31705 solar days = 109.4 solar days x 133 x 2.18

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II-Discussion
Equation No. (5-5-a)
- The moon needs accurately 1700 solar days to pass a distance = 149.6 mkm =
Earth orbital distance
And
- Saturn needs accurately 1710.457 solar days to pass a distance = 1433.5 mkm =
Saturn orbital distance
- The difference between the 2 periods (1700 days and 171.457 days = 251 hours)
- The planets rates of time depends on the required periods to move their orbital
distances, and Saturn required period is 1710.457 solar days but the moon required
period is 1700 solar days – That causes their rates of time to be almost equal, for
example 1 hour of Earth motion be = 29.4 hours of the moon motion = 29.3 hours
of Saturn motion. almost they are equal
- We have to ask why?
- Let's summarize the idea in following:
(I)
- Uranus Orbital Distance =19.2 Earth Orbital Distance,
- This data means, if Uranus and Earth velocities are equal, During Uranus revolves
around the sun one revolution, Earth revolves around the sun 19 revolutions (19
years)
- And
- The Earth moon moves a cycle called Metonic Cycle continues for 19 years. we
know that Earth Cycle is 4 years (365 +365 +365 +366 days =1461 days) for that
we have asked frequently, why the moon moves Metonic Cycle?
- A suggested answer tell
- The Moon Moves Metonic Cycle By An Effect Of Uranus Motion
- And

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- We know that the moon and Saturn be created after Mars and Pluto migration,
(II)
- The idea is that, Uranus Motion effects on Saturn and the moon and by this effect,
Uranus caused the 2 planets periods to be (1700 days and 1710.5 days) (the
difference between them be 251 hours).
- Why? because
- Mars moves during 25.1 hours a desistance = 2.18 mkm
- This we have seen in the equation
- (for revision) (II-A) (point 5-4)
- 31705 solar days = 109.4 solar days x 133 x 2.18
- This equation needs the distance 2.18 mkm to define the periods 31705 days which
is the total required periods of the solar planets. Mars moves 2.18 mkm in a period
25.1 hours and the difference between the 2 planets (251 hours) be found to
support Mars motion.
- The number 251 hours is so effective because
- (1)
- If 1 hour = 1 month based on that 251 hours will be =251 months but Metonic
Cycle is (254 months) (error 1%)
- (2)
- 25.1 hours = 90560 seconds where Pluto orbital period =90560 days
- (3)
- 251 hours = 25.1 hours x 10 but
- 10747 days (Saturn Orbital Period) x 24 h x 10 = 10.7 h x 2 x 120536
- (where 10.7 h = Saturn day period and 120536 km = Saturn diameter)
- I try to show that, the data is integrated in harmony with one another, we don't
know the geometrical mechanism but the data shows interesting integration ability
- Shortly

The Solar System Design Disproves Newton Theory (Revised No.2)

The Solar System Design Disproves Newton Theory (Revised No.2)

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