The Solar System Motion Analysis (Revised And Modified).pdf

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
The Solar System Motion Analysis (Revised And Modified)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –19th
February 2022
Abstract
Paper hypothesis no. (1)
- The Solar System Be Created Based On One Geometrical Design
- The Solar Planets And Their Distances Be Created Out Of One Light Beam
- This Light Beam Travels With A Velocity 1.16 Million Km Per Second
Paper hypotheses Explanation
- Hypothesis no. (1)
- The hypothesis tells, the solar system be created based on one geometrical design,
means, the planets dimensions and data be defined by one equation and can be
concluded based on one another – this fact the paper proves clearly –
- The paper provides 4 equations which can be considered as a discovery, by them
we can conclude the planets fact sheet theoretically without observation, let's prove
that by introducing the first equation of them
- d2
= 4d0 (d- d0) where (d =planet orbital distance) and (d0 = previous planet orb. dis.)
- The equation tells, the distance from the sun to Pluto be distributed geometrically
in order regardless the planets data – neither their masses nor their diameters –
simply the distance be distributed geometrically regardless planets data –
- (The paper tests and proves the equation) - let's provide the 2nd
equation

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- (d1/d2) = (v2/v1)2
where (d = planet orbital distance) and (v= planet velocity),
- The equation doesn't use the planets order as the first one –
- The 4 equations tells one clear information which is
- If we know (Mercury orbital distance =57.9 mkm), By use these 4 equations,
we can conclude theoretically all planets orbital distances, periods, velocities,
their diameters, rotation periods, masses, orbital inclinations and axial tilts.
This data we conclude theoretically without observation by these 4 equations
- The next question should be Why? hypothesis no. (2) answers -Because,
- The Solar Planets And Their Distances Be Created Out Of One Light Beam.
- This is similar to Young Experiment (the double slits experiment), the sun rays
produces bright fringes and dark fringes (One Design) (If we accept that, we have
to suppose the bright fringes be seen by us as matters and the dark as space)
- The paper proves this fact also, by analysis of Lorentz length contraction effect
and tries to answer the question (Why does Particle length be contracted by its
high velocity motion?)
- But, the complexity isn't finished
- The light beam based on which the solar planets and their distances be created, this
light beam travels with a velocity 1.16 million km per second!!
- And how to prove this fact? and from where we know this number 1.16 mkm/s??
- From planets velocities where
- Mercury (47.4 km/s) moves during 6.8 hours a distance = 1.16 million km
- Uranus (6.8 km/s) moves during 47.4 hours a distance = 1.16 million km
- Earth (29.8 km/s) moves during 5.4 x 2 hours a distance = 1.16 million km
- Neptune (5.4 km/s) moves during 29.8 x 2 hours a distance = 1.16 million km
- Shortly
- The planets velocities be created complementary one another based on this
velocity 1.16 million km per second – because of that – I know this velocity

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- This is a strong reference (and can't be a proof) but it tells, the solar system design
takes into consideration the distance 1.16 million km.
Paper objective
- The paper tries to create a revolution in physics because it supposes the solar
system be created based on one design, and this design be found by light motion
effect on planet motion where matter and space together be created out of one light
beam, and also the paper argues about the light velocity 1.16 million km per
second as another real velocity of light.
- Based on what this revolution should depend? Based on the moon orbit
- Because
- The moon daily displacement be = 88000 km and during 29.53 days (the moon
day) the displacements total be = 2.5986 mkm, if this is the moon apogee
circumference – the apogee radius should be 413600 km – not only – but because
the moon daily displacement be 88000 km (so long) the moon would be prisoner in
the orbit with radius (413600 km) and can't revolve around the Earth through any
more near orbits
- The facts contradicts the data, because the moon apogee radius =406000 km and
the moon revolves around the Earth through more near orbits and can reach to the
perigee radius (363000 km) and how can we explain the data??
- I have discovered that, the intelligent moon creates an angle (θ) between its motion
and its orbit horizontal level – by that – the real displacement (L) through the orbit
be less than 88000 km because it be (L = 88000 cos (θ)) now the moon can change
the angle (θ) and decreases the real displacement (L) as required which enable the
moon to revolve around Earth through more near orbits
- The angle (θ) is an intelligent idea and based on it the moon motion equation be
formed and the paper tests it (Point No.5-10)

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- The next question should be (why the apogee radius be 406000 km specifically?) if
the intelligent moon has this technique to decrease its real displacement (L) why
not the apogee radius be shorter than (406000 km)? or why not the perigee radius
not be more near than (363000 km)?
- This question answer creates the paper objective, because the apogee radius be
only 406000 km by an effect of Uranus motion on the moon motion – the idea tells
Uranus motion effects on the moon motion and causes it to moves Metonic Cycle
(19 years), more questions be born in the way… why the moon moves Metonic
Cycle? If The Earth doesn't, that means, another planet must effect on the moon
motion and causes this Cycle (Metonic Cycle 19 years)….
- Uranus orbital distance = 19.2 Earth orbital distance, means, if the 2 planets
velocities be equal, while Uranus revolves around the sun one revolution the Earth
revolves 19 revolutions (19 years) and Metonic Cycle (19 years), Can this data be
a proof for the claim? Not but it creates a reference can help
- Now we have a great rock in the way, because, the gravitation equation prevents
us-
- We have searched deeply to know if really Uranus motion can effect on the moon
motion and how the moon apogee radius be decreased from 413600 km to 406000
km- but more searching creates more difficulties – because
- The planet which effect directly on the moon apogee radius 406000 km is Pluto
motion and not Uranus. And we have discovered that Uranus motion must effect
also on Pluto motion (that's why Pluto day is so long relative to the outer planets) -
but – Pluto has no hope to effect on the moon for mass and distance – although –
Pluto data be used in the process perfectly (as we will see)
- Before this dilemma, the only solution be that
- The Solar System be created based on one design and works as a machine of gears
each planet be a gear in it – means- the solar group is similar to one creature body
and the planets are members in it – by that – each planet role be defined based on

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its position in the general design and for that reason while the effect on the moon
orbit is Uranus motion effect but this effect be transported by Pluto motion
basically
- Then more searching be done to discover this One Design based on which the
solar system be created. and
- The searching process showed that the one design depends on One Light, and we
have to conclude that matter and space both are created out of the same one light
beam
- Followers for the data results, we have to examine the light beam nature based on
which the one design be created based on which the solar planets and their
distances be created – and the fact be discovered is that
- This light beam travels with velocity 1.16 million km per second – and this is the
original light beam based on which the solar planets and their distances be created.
- The light known velocity (300000 km/s) be created later, as we should discuss in
the paper, which proves that the sun be created after all planets creations and
motion. (In fact the sun be created depending on the planets motions) disproving
decisively Newton theory of the sun gravity as the planets motions reason
Paper point on discussion
- We discuss the moon orbit apogee radius decreasing process as a proof for the
claim (the solar system be created based on one geometrical design) and the paper
analyzes this design to prove it depends on one light and to prove this light beam
velocity must be 1.16 million km per second
Notice
- The Moon Orbit Apogee Radius Analysis Be Summarized In Point No. (5-2).
This summary needed a modification for the paper pages numbers.
(Please scan the figure (ORCID)

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Paper Contents
Subject Page No.
1- Introduction 9
2- Methodology 16
3- Planets Data Depends On One Equation 18
3-1 Preface 19
3-2 Planet Orbital Distance Equation (Test) 20
3-3 Planet Orbital Distance And Its Velocity Equation (Test) 23
3-4 Planet Velocity Equation (Test) 26
3-5 Planet Velocity And Its Diameter Equation (Test) 29
3-6 The Solar System Motion Depends On One Design. 35
3-7 Why Does The Solar System Motion Depend On One Design? 37
4- Can Light Motion Effect On Planet Motion? 38
4-1 Preface 39
4-2 The Main Data (Data No. 1) 41
4-3 Planet Velocity Proportionality (Data No. 2) 47
4-4 The Solar System One Design Description (Data No. 3) 50
4-5 The Solar System One Design Analysis (Data No. 4) (I) 52
4-6 Data No. (4) (Part II) 54
4-7 The Distances Be In Network Form (Data No. 5) (Part A) 60
4-8 Data No. (5) (Part B) 63
4-9 Planet Motion Data Depends On Light Motion (Data No. 6) 68
4-10 Planets Motions for 30 mkm (Data No. 7) 72
5- The Moon Apogee Radius Analysis 78
5-1 Preface 79
5-2 The Moon Orbit Apogee Radius Analysis 80
5-3 The Comparison between the Solar Day period and Mars rotation period 114
5-4 Jupiter Velocity More Analysis 115
5-5 Uranus Velocity Analysis 118
5-6 Can The Solar System Depend On One Geometrical Design? 124
5-7 The Moon Orbit Design Analysis
(Point No. i) (The Moon Apogee Radius)
(Point No. ii) (The Distance 742 mkm)
(Point No. iii) (The Distance 720.7 mkm)
(Point No. iv) (The Distances 742 mkm and 720.7 mkm)
(Point No. v) (The Rate 1.0725)
(Point No. vi) (Pluto Motion Analysis)
(Point No. vii) (Mercury Day Period)
(Point No. viii) (Earth Cycle Analysis)
(Point No. ix) (Planet Diameter Definition)
130
5-8 Uranus Effect On The Moon Motion 164
5-9 The Planets Unified General Motion 170
5-10 The Moon Orbital Motion Description 182

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6- Jupiter Motion Effect On Earth And Venus Motions 198
6-1 Preface 199
6-2 Jupiter Motion Effect On Earth And Venus Motions 203
6-3 Jupiter Orbital Circumference Analysis 209
6-4 Saturn Velocity Analysis 213
6-5 The Solar System Creation and Motion Theory 234
6-6 Questions And Answers 232
7- The Solar Planets Motions Use Different Rates Of Time 241
7-1 Preface 242
7-2 The Planets Motions Rates Of Time 244
8- The Solar Planets Rates Of Time Analysis 248
8-1 Preface 249
8-2 Venus Motion Rate of time 250
8-3 Earth Motion Rate of time 252
8-4 Mars Motion Rate of time 254
8-5 Jupiter Motion Rate of time 256
8-6 Saturn Motion Rate of time 258
8-7 Uranus Motion Rate of time 260
8-8 Neptune Motion Rate of time 262
8-9 Pluto Motion Rate of time 264
8-10 The Planets Orbital Distances Test 266
8-11 One Law Controls The Planets Orbital Periods And Distances 271
8-12 The General Discussion 272
9- The Planets Motions Rates Of Time Effect Analysis 275
9-1 Preface 276
9-2 Planets Motions Rates Of Time And Distances Data 277
9-3 The Data Equal Distances 281
9-4 The Data and the planets velocities. 289
9-5 The Data Distances And Rates Of Time Interaction 293
9-6 The Data General Discussion 303
9-7 Mars, Jupiter and Saturn Motions Analysis 305
9-8 Why Saturn And The Moon Use Equal Rates Of Time? 310
9-9 Why Mercury Use A Double Of Its Orbital Distance? 315
9-10 The Rate (4.61) be used between Pluto and the moon motion 316
10- Mars Migration Theory 320
10-1 Mars Migration Theory 321
10-2 Pluto Migration Theory 324
10-3 Planets Migration Theories Proves 326
10-4 Is There An Absent Planet In The Solar Group? 329
11-The Solar System Distances Be Created In A Network Form 332
11-1 Preface 333
11-2 The Continuum effect Through the Solar System Distances 335
11-3 The Solar System Distances Distribution 340

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11-4 The Solar System Distances Dependency On One Another 344
12- The Continuum Effect Proof 346
12-1 The Continuum Effect Proof 347
12-2 Saturn Motion Analysis 353
12-3 Planet Diameter Analysis 379
12-4 Why do the planets revolve around the sun if there's no sun gravity? 381
13- Planet Mass Effect On its Motion 382
13-1 Preface 383
13-2 Planet Mass effect on its Motion 385
13-3 Saturn and Earth Motions Interaction 396
13-4 Planets Velocities Proportionality 405
14- Saturn Motion Analysis 413
14-1 Preface 414
14-2 Saturn Diameter Analysis 416
14-3 Neptune Circumference Analysis 426
14-4 Neptune Day Period Analysis 435
14-5 Mercury Motion effect on Jupiter and Neptune Motions 444
14-6 Earth Motion Distance Daily Analysis 451
14-7 Uranus Day Period Analysis 455
14-8 The Inner Planets Motions Analysis 461
15- The Sun Age Description 469
15-1 Preface 470
15-2 The Sun Circles The Earth 471
15-3The Rate (1.0725) 472
15-4 The Sun Diameter Analysis 475
15-5 The Sun And Earth Motions Rate Of Time (1 day =365.25 days) 478
15-6 The Sun Rays Creation 486
16- Mercury Jupiter Distance Analysis 492
16-1 Mercury Jupiter Distance Analysis (720.7 mkm) 493
16-2 (Jupiter And Mercury Motions Analysis) 506
16-3 Jupiter Distances Analysis 510
Appendix No.1 The Solar System Equal Distances List 511
Claims Be Sent Against The Decision Of Nobel Prize For Physics 2021 513
References and Biography 518

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1- Introduction
- We discuss here 2 questions which are:
- (1) Can The Solar System Be Created Based On One Geometrical Design?
- (2) Can Uranus Motion Effect On The Earth Moon Motion?
- (1st
Question)
- Can The Solar System Be Created Based On One Geometrical Design?
- The first equation tells
- d2
= 4d0 (d-d0)
- where
- (d= planet orbital distance) and (d0 = its previous neighbor orbital distance)
- Example,
- (108.2 mkm)2
= 4 (57.9 mkm) x (108.2 mkm – 57.9 mkm)
- 108.2 mkm = Venus orbital distance
- 57.9 mkm =Mercury orbital distance
- The equation works sufficiently for all solar planets with error less than 1% except
with Earth (error 2.8%) and Neptune (error 4%)
- The equation has 3 exceptions which are
- (Earth depends on Mercury not Venus – Mars on Venus – Pluto on Uranus)
- (The paper discussion explains the reason behind these exceptions)
- Also the equation considers the planet Ceres between Mars and Jupiter means
Ceres depends on Mars and Jupiter depends on Ceres
- The paper tests the equation for all planets orbital distances and proves its
credibility –
- The equation disproves the (initial conditions claim) which be the answer for the
question (why the planets order doesn't follow the gravitation equation?)
- What concept can we conclude from this equation? Newton Equation tells some
different meaning – Newton tells – the planet orbital distance should be defined
based on the sun mass in proportionality with this planet mass.

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- This isn't the fact where the planets orbital distances aren’t follow the gravitation
equation and the explanation for that should be (the initial conditions claim)…
- This is the story of the planets order from Newton Vision
- My equation tells some different meaning – it tells –
- The Distance Between The Sun And Pluto Be Distributed By One Design
Regardless Any Planet Data
- Simply we know Mercury orbital distance = 57.9 mkm and based on it we can
conclude theoretically all planets orbital distances regardless their data
- No mass here be used – the distances be distributed by some (unknown) Factor –
and without any relationship with any planet data!
- Notice
- Did Newton refuse the claim tells (Each planet can effect on another planet)?
Openly Newton didn't refuse this meaning, but, the effect at Newton be the mass
effect and the sun mass is so massive in comparison with the planet masses means
no effect of any planet can be comparable with the sun effect on planets motions,
but as my equation shows, we see planets data effect on thier neighbor but we don't
see any effect of the sun mass on planets motion data– Newton Idea Is Wrong
- My equation still tells some interesting meaning because each planet orbital
distance depends on its neighbor orbital distance but doesn't depend on its mass,
instead, it depends on its position, the equation tells (I don't see any planet of them
nor interest for their data– I see them as points on One Straight Line)
- The equation gives us a reason to review the solar system vision –
- Notice
- The rest 3 equations enable us to conclude all planets data, means, if we know
Mercury orbital distance =57.9 mkm we can conclude theoretically all planets
orbital distances, periods, velocities, diameters, rotation periods, masses, orbital
inclinations and axial tilts, this data can be concluded theoretically by the (4

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equations) we discuss and test them in the paper – the point is that – we have a
reason to consider the idea tells (One Geometrical Design Be Found Behind).
- The (4 equations) together creates a discovery by which we can conclude the
planets fact sheet by using one data only of it.
- This discovery can be found if one geometrical design be found behind the solar
system. because this design defines the planets data and creates them accordingly
- (2nd
Question)
- Can Uranus Motion Effect On The Earth Moon Motion?
- Metonic Cycle was the first observation for this idea, Uranus orbital distance =19.2
Earth orbital distance, and Metonic Cycle is (19 years) this data gives some feeling
that Uranus must be the reason behind, specially because Earth doesn't move this
cycle and the moon moves it under another planet motion effect – and Uranus is
the planet provides the number (19) – again we have to contradict the gravitation
equation – because Jupiter is greater in Mass and nearer in distance.
- Then we have searched after to know the truth and found the following data
- (a) Uranus axial tilt 97.8 deg = 19.2 x 5.1 deg (the moon orbital inclination)
- (b) 23.75deg x 0.8 deg = 19 deg (where 0.8 deg = Uranus orbital inclination) and
(23.4 deg = Earth axial tilt different from 23.7 deg with error 1.5%) where the
moon orbit regresses per year 19 degrees
- (c) (Uranus mass / Earth mass) =(Uranus diameter / the moon diameter) (error 1%)
- I try to provide the data which supports the claim – but whatsoever data I have
provided the only available explanation was (pure coincidence of numbers)!
- Means, no data gives proof for this claim –
- Then – the light motion effect on planet motion idea be suggested and then it
provides one more data can help even partially let's see it in following:
- (Notice/ The idea supposes a light beam its velocity 1.16 million km/s be found)

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- (1) Uranus Motion
- Light supposed velocity (1.16 mkm/s) needs 15559 s to pass 18048 mkm
- 18048 mkm = Uranus Orbital Circumference
- Light known velocity (0.3 mkm/s) passes during 15559 s a distance = 4668 mkm
- 4668 mkm = 2π x 742 mkm
- Uranus moves during the period 30589 hours a distance = 742 mkm (error 1%)
- 30589 solar days = Uranus orbital period
- By similar calculation all planets data can be used and all planets orbital
circumferences and periods be defined by a similar calculation -
- The point we need is the following
- (2) The Earth Moon Motion
- During 639s light supposed velocity (1.16 mkm/) travels 742 mkm
- During 639s light known velocity (0.3 mkm/) travels 191.6 = 2π x 30.5 mkm
- But
- 30.5 mkm = 88000 km x 346.6 days
- The moon displacements total during 346.6 days (solar days) = 30.5 mkm
- Where
- 346.6 solar days= The nodal year
- 88000 km = The moon displacement for a solar day
- We still need to explain the data, but the data proves directly the relationship
between Uranus and the moon – because of the distance (742 mkm)
- Let's review the question (Can Uranus cause the moon apogee radius decreasing?)
- Yes, How?
- (For Revision, the moon displacements total during 29.53 days = 88000 km x
29.53 = 2.5986 mkm = 2π x 413600 km)
- (i.e. The Moon Apogee Radius should be 413600 km) !!
- How the apogee radius (413600 km) be only (406000 km)?

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- Uranus caused the moon orbit inclination to be 5.1 degrees and caused also the
moon orbit regression (1.44 degrees monthly or 19 degrees yearly) by these 2
factors Uranus forced the moon apogee radius to be decreased from 413600 km to
406000 km!
- Let's summarize this process step by step,
- The available distance = 2.598 mkm ( r= 413600 km) and the required distance is
2.55 mkm (r= 406000 km)
- 2.598 million km x (cos 10.96 degrees) = 2.55 million km
- So, the main process depends on the angle (10.96 deg)
- How this angle (10.96 degrees) be created? by the equation
- 137 degrees x 0.08 = 10.96 degrees
- What are these 2 values?
- (0.08) is a rate produced geometrically by the moon orbit, let's explain how
- The moon perigee radius =363000 km and the apogee radius =406000 km, let's use
the figure in explanation
- Let's suppose the inner circle is the perigee orbit and the outer
circle is the apogee orbit,
- by geometrical calculations the distance DB = 181843 km
- The perigee orbital circumference be = 363000 km x 2π = 2.28
mkm, And
- (181843 km)/2.28 million km = (0.08)
- Means the rate (0.08) be produced geometrically based on the moon orbital
geometrical design.
- And what's the angle (137 degrees)?!
- 137 degrees = 95.1 degrees x 1.44 degrees
- Where
- 1.44 degrees = the moon orbit regression angle per month
- 95.1 degrees = 90 degrees + 5.1 degrees (the moon orbital inclination)

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- Means,
- The angle (137 degrees) depends on 2 basic angles of the moon motion, but the
moon orbital inclination (5.1 deg) be used based on its vertical axis (95.1 deg)
- Why?
- 4900 mkm = 95.1 x 51.5 mkm
- Where
- 4900 mkm = Jupiter orbital circumference
- 51.5 mkm = Uranus motion distance in 88 solar days
- 88 days = Mercury Orbital Period
- This equation aims to prove that Uranus motion is the reason of the value 95.1 by
which the angle 137 degrees be created -
- (means, Uranus motion is the reason of the moon orbital inclination 5.1 deg)
- but
- The explanation can't be clear unless we analyze the distance 4900 mkm and we
can do that only in the paper discussion, because
- The value 4900 mkm be the cornerstone in the solar system geometrical design
we have to discuss the design before to analyze this distance 4900 mkm – so we
can complete the explanation in the paper discussion –
- Let's take a look on the paper contents:
- The Paper Discovery (4 equations) be discussed in point no. (3)
- The Paper Hypothesis Proves Data And Discussion Be Found In 3 Points
- (These Points Number Are No.4, No.5 and No.6)
- Point No. (4) Provides the Proves Data Only
- Points No. (4 and 5) Provide The Data Discussion And Analysis
- (In point No. 5 the moon orbital apogee radius be analyzed)
- (also in Point No. 5 The moon orbital motion description be discussed)

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- The Solar Planets Motions Use Different Rates Of Time
(Be discussed in points no. 7-8-9 of this paper) and
- Mars Migration Theory
(Be discussed in point no. 10 of this paper)
- The Solar System Distances Be Created In A Network Form
(Be discussed in point no. 11 and 12 of this paper)
- Planet Mass Effect On its Motion
- Saturn Motion Analysis
- The Sun Age Description
Notice
The Moon Orbit Apogee Radius Analysis Be Summarized In Point No. (5-2).
This summary needed a modification for the paper pages numbers.

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2- Methodology
- I use the planets data analysis to discover the solar system creation and motion
facts – The method is so useful.
- The method simply put the planets data in comparison with the theory and tries to
know if there's a consistency between both – let's use one example to explain how
this method works
- An Example (Mars Migration Theory)
- Giant-Impact hypothesis tells that, a planet in Mars Size had collided with the
Earth and caused the moon creation.
- Can Mars Itself do that? NO
- The theory tells no hope Mars itself did this collision – So what does the data tell?
- If the planets be found in order –Mars position should be after Mercury –because
the 4 planets (Mercury – Mars – Venus – Earth) be in order for their diameters,
masses and orbital distances –this data tells suggests that Mars position was the
second planet between Mercury and Venus and Mars may be migrant from its
original orbital distance!
- Let's move with this hypothesis for a while
- Suppose Mars was the second planet after Mercury and had migrated to its current
point (227.9 million km) what would happen? Mars had collided with Venus and
then with Earth –
- Giant-Impact hypothesis asks why Venus has no its own moon spite it had suffered
of a collision similar to the Earth? the answer is a simple one
- Imagine Mars was the second planet after Mercury (84 mkm) and had migrated to
its current position (227.9 mkm), in its displacement, Mars was pushed by force
and had collided with Venus and pushed all debris with it in its motion direction
- Venus found no debris around – for that Venus couldn't create its own moon-
- Another question asks about (the origin of the lunar magma ocean!) Venus, The
Lunar Magma Ocean is came from Venus, it's a part of Venus found by the

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collision between Mars and Venus but Mars had pushed all debris with it in its
motion direction and left Venus without debris
- Earth gravity is greater than Venus and the debris lost some of their momentum
and by that the Earth could create its own moon where the moon rocks are
consisted of Venus, Earth and Mars debris
- The fact Mars has 2 moons is one more proof for this idea, because Mars with
small mass could attract 2 moons and Venus couldn't.
- The rest debris be attracted by Jupiter and consisted the asteroid belt
- The planets data analysis put the facts beside one another and by that the vision be
more clear
- (Mars Migration Theory be discussed in Point no. 10 of this paper)

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3- Planets Data Depends On One Equation
3-1 Preface
3-2 Planet Orbital Distance Equation (Test)
3-3 Planet Orbital Distance And Its Velocity Equation (Test)
3-4 Planet Velocity Equation (Test)
3-5 Planet Velocity And Its Diameter Equation (Test)
3-6 The Solar System Motion Depends On One Design.
3-7 Why Does The Solar System Motion Depend On One Design?

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3-1 Preface
- What does mean (Planets Data Depend On One Equation)?
- That means,
- By my 4 equations (be tested and discussed here)
- If we know that (Mercury Orbital Distance = 57.9 million km), based on this one
data only and by using my 4 equations we can conclude (theoretically) all planets
orbital distances, periods, velocities, rotation periods, diameters, masses, orbital
inclinations and axial tilts
- Shortly
- The planets fact sheet (Data) completely can be concluded theoretically without
observation based on one data only (Mercury Orbital Distance = 57.9 million km)
by using my 4 equations.
- We do this task in this point
- And
- If we succeed in this task, that will be a proof for the claim (The Solar System Be
Created Based On One Geometrical Design) where this design will be discussed
in the next point No. (5).

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3-2 Planet Orbital Distance Equation (Test)
- d = A Planet Orbital Distance
- d0= Its Direct Previous Neighbor Planet Orbital Distance
(1) Venus Motion
- d = 108.2 mkm (Venus Orbital Distance)
- d0 = 57.9 mkm (Mercury Orbital Distance)
- (108.2)2
= 4 x 57.9 x (108.2-57.9)
- Venus depends on Mercury
(2) Earth Motion
- d = 149.6 mkm (Earth Orbital Distance)
- d0 = 57.9 mkm (Mercury Orbital Distance)
- (149.6)2
= 4 x 57.9 x (149.6-57.9) (error 2.8%)
- Earth depends on Mercury and doesn't on Venus
(3) Mars Motion
- d = 227.9 mkm (Mars Orbital Distance)
- d0 = 108.2 mkm (Venus Orbital Distance)
- (227.9)2
= 4 x 108.2 x (227.9-108.2)
- Mars depends on Venus and doesn't on Earth
(4) Ceres Motion
- d = 415 mkm (Ceres Orbital Distance)
- d0 = 227.9 mkm (Mars Orbital Distance)
- (415)2
= 4 x 227.9 x (415-227.9)
- Ceres depends on Mars
)
(
4 0
0
2
d
d
d
d −
=

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(5) Jupiter Motion
- d = 778.6 mkm (Jupiter Orbital Distance)
- d0= 415 mkm (Ceres Orbital Distance)
- (778.6)2
= 4 x 415 x (778.6- 415)
- Jupiter depends on Ceres
(6) Saturn Motion
- d = 1433.5 mkm (Saturn Orbital Distance)
- d0 = 778.6 mkm (Jupiter Orbital Distance)
- (1433.5)2 = 4 x 778.6 x (1433.5- 778.6)
- Saturn depends on Jupiter
(7) Uranus Motion
- d = 2872.5 mkm (Uranus Orbital Distance)
- d0 = 1433.5 mkm (Saturn Orbital Distance)
- (2872.5)2
= 4 x 1433.5 x (2872.5- 1433.5)
- Uranus depends on Saturn
(8) Neptune Motion (error 4%)
- d = 4495.1 mkm (Neptune Orbital Distance)
- d0 = 2872.5 mkm (Uranus Orbital Distance)
- (4495.1)2
= 4 x 2872.5 x (4495.1- 2872.5)
- Neptune depends on Uranus
(9) Pluto Motion
- d = 5906 mkm (Pluto Orbital Distance)
- 4495.1 mkm (Neptune Orbital Distance)
- (5906)2
= 4 x 2872.5 x (5906- 2872.5)
- Pluto depends on Uranus
- Notice the error is less 1% for all planets except (Earth 2.8%) and Neptune (4%)

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The Equation Discussion
(1)
- The Equation has 3 exceptions, (Earth depends on Mercury Not Venus, Mars
depends on Venus Not Earth and Pluto depends on Uranus Not Neptune)
- The light motion analysis behind these planets motions will explain why these
planets don't depend on their direct previous neighbor – we discuss that in Point
No. (6)
- The equation works sufficiently with all planets orbital distances with errors are
less than (1%) except with the Earth (error 2.8%) and Neptune (error 4%)
- The equation depends on the planets order (Each planet depends on its neighbor)
(2)
- The equation shows simply, we can conclude theoretically all planets orbital
distances by using the one data (Mercury Orbital Distance = 57.9 mkm)
- by that, we can define a basic part of the planets fact sheet by this equation
(3)
- The equation shows an interesting meaning because
- It tells, the distance from the sun to Pluto be distributed geometrically based on
(One Design). This Distribution doesn't depend on any planet data, the equation
simply defines points for the planets positions regardless these planets data- each
planet depends on its neighbor (position) and not (data).
- The equation gives a reason for the idea (the solar system depends on one design)
and gives one more reason to disprove the mass gravity concept as a reason for the
planets orbital distances definition. It provides a different vision greatly from
Newton theory of the sun gravity
(4)
- When we asked (why the planets order doesn't follow the gravitation equation)?
The answer was (because of The Initial Conditions). Where are these initial
conditions here – the equation defines simply the planets orbital distances and no
initial conditions be discovered – means- the initial conditions idea was wrong –

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3-3 Planet Orbital Distance And Its Velocity Equation (Test)
d1= Planet Orbital Distance (its velocity v1)
d2= Another Planet Orbital Distance (Not Neighbor) (its velocity v2)
- The equation doesn't depend on the planets order, and by that the planets (1 and 2)
aren't neighbors – simply any 2 planets follow this equation
- This is important notice because its creates some freedom in the planets data which
we need to know how it be created, because the first equation depends on the
order, so how this equation found the freedom from the planets order?
Example No. (1)
- (149.6 mkm/57.9 mkm) = (47.4/29.8)2
(error 2%)
- Where
- 149.6 mkm = Earth Orbital Distance
- 57.9 mkm = Mercury Orbital Distance
- 47.4 km/s = Mercury Velocity
- 29.8 km/s = Earth Velocity
- The rule works sufficiently
Example No. (2)
- (2872.5 mkm/778.6 mkm) = (13.1/6.8)2
- Where
- 2872.5 mkm = Uranus Orbital Distance
- 778.6 mkm = Jupiter Orbital Distance
- 13.1 km/s = Jupiter Velocity
- 6.8 km/s = Uranus Velocity
2
1
2
2
1
)
(
v
v
d
d
=

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Example No. (3)
- (5906 mkm /108.2 mkm) = (35/4.7)2
(error 1.6%)
- Where
- 5906 mkm = Pluto Orbital Distance
- 108.2 mkm = Venus Orbital Distance
- 35 km/s = Venus Velocity
- 4.7 km/s = Pluto Velocity
Example No. (4)
- (4495.1 mkm /57.9 mkm) = (47.4/5.4)2
- Where
- 4495.1 mkm = Pluto Orbital Distance
- 680 mkm = Venus Orbital Distance
- 35 km/s = Venus Velocity
- Notice
- Errors less than (1%) aren't written

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[
(1)
- This equation creates extension for the data.. based on that
- If we know that (Mercury orbital distance = 57.9 million km) by these 2 equations
we can conclude (theoretically) all planets orbital distances and velocities which
can produce also all planets orbital periods
- By that,
- Based on one data, 3 columns of data can be concluded theoretically of the planets
fact sheet
- But
- Why Planet velocity be changed reversely with its orbital distance? Why planet
orbital distance increasing causes (or necessitates) its velocity to be decreased?
- Again, the equation shows no effect of Planets masses we deal here with velocities
and distances only!
(2)
- I try to show that, there are 2 points in these data analysis which:
- (1st
Point) The Data Be Created Based On One Geometrical Design and by that the
data be created depending on one another by using geometrical rules
- (2nd
Point) There's one more player causes to create this geometrical design
- Means, the geometrical design controls all planets data and causes all planets data
to be created based on one law or one system of data only – but this design itself
be created by one more player outer of the solar system – for that reason – the data
shows we move following some point – we move following this point with
knowledge that this point is outer of the solar system but we more following it
because it causes to create the solar system -

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3-4 Planet Velocity Equation (Test)
Where
v1 = Planet Velocity
v2 = Another Planet Velocity
322 h = 1160000 seconds
The equation tells the planets velocities be created complementary one another
Example no. (1)
322 = 47.4 x 6.8 – for that -
Mercury (47.4 km/s) moves during 6.8 hours a distance = 1.16 million km
And
Uranus (6.8 km/s) moves during 47.4 hours a distance = 1.16 million km
Example no. (2)
322 = 35 x 4.7 x 2 – for that -
Venus (35 km/s) moves during 2 x 4.7 hours a distance = 1.16 million km
And
Pluto (4.7 km/s) moves during 2 x 35 hours a distance = 1.16 million km
(error 2%)
Example no. (3)
322 = 29.8 x 5.4 x 2 – for that -
Earth (29.8 km/s) moves during 2 x 5.4 hours a distance = 1.16 million km
And
Neptune (5.4 km/s) moves during 2 x 29.8 hours a distance = 1.16 million km
322
2
1 =
v
v

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Example no. (4)
322 = 24.1 x 13.1 – for that -
Mars (24.1 km/s) moves during 13.1 hours a distance = 1.16 million km
And
Jupiter (13.1 km/s) moves during 24.1 hours a distance = 1.16 million km
(error 2%) (In fact Jupiter moves during 24.6 hours a distance 1.16 mkm)
Example no. (5)
322 = 35 x 9.7 – for that -
Venus (35 km/s) moves during 9.7 hours a distance = 1.16 million km
And
Saturn (9.7 km/s) moves during 35 hours a distance = 1.16 million km
(error 5%)
- Notice
- (24.6 h +24.6 h = 25.2 h +24.1 h)
- 24.6 hours = Mars Rotation Period
- 24.7 hours = Mars Day Period
- 25.2 degrees = Mars Axial Tilt (be used as a period of time also)
- 24.1 km/s = Mars velocity
- The accurate addition tells that these 4 values are used for one process.

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- Why planets velocities be rated with the value 322?
- Because 1160000 = 3600 x 322
- We should notice that, if light travels a distance 1160000 km it can be seen by us
as 1160000 seconds = 3600 x 322 hours
- (as example, light 300000 km/s travels during a solar day a distance 25920 mkm)
but we see it as (25920 years = The Precession Cycle)
- The planets velocities be the first observation for the distance 1160000 km and
refers to the velocity 1160000 km per second as a reference for them.
- Notice
- This equation will be discussed in more details later

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3-5 Planet Velocity And Its Diameter Equation (Test)
v1 = planet velocity in second
v2 = another planet velocity in second
r = Planet Diameter
s = The Planet Rotation Periods Number In Its Orbital Period
Notice /
The equation doesn't depend on the planets order
Example No. (1)
(89143 /49528) = (9.7 /5.4) =1.8
- Neptune Orbital Period (59800 days) has 89143 Neptune rotation periods (16.1 h)
- 49528 km = Neptune Diameter
- 9.7 km/s = Saturn Velocity
- 5.4 km/s = Neptune Velocity
- The data follows the rule perfectly – error less than 1%
- Also
- 9.7 /5.4 = 1.8 where 1.8 degrees = Neptune Orbital Inclination
Example No. (2)
(24106 x2 /120536) = (9.7 /24.1)
- Saturn Orbital Period (10747 solar days) has 24106 Saturn rotation periods (10.7h)
- 120536 km = Saturn Diameter
- 9.7 km/s = Saturn Velocity
- 24.1 km/s = Mars Velocity
- The equation uses the rate (2) for data configuration with more modification–
where this rate isn't used in the equation
- 24.1/9.7 = 2.5 where 2.5 degrees = Saturn Orbital Inclination
r
s
v
v
=
2
1

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Example No. (3)
(42683 /51118) = (5.4/6.8) (error 5%)
- Uranus Orbital Period (30589 days) has 42683 Uranus rotation periods (17.2h)
- 51118 km = Uranus Diameter
- 5.8 km/s = Neptune Velocity
- 6.8 km/s = Uranus Velocity
- The data follows the equation sufficiently but with a great error (5%)
- Also
- 5.4/6.8 = 0.8 where 0.8 degrees = Uranus Orbital Inclination
Example No. (4)
(14178 /2390) = (27.78/4.7)
- Pluto Orbital Period (90560 solar days) has 14178 Pluto rotation periods (153.3 h)
- 2390 km = Pluto Diameter
- 27.78 km/s = The moon Velocity
- The data follows the rule perfectly
- The moon orbital inclination (5.1 degrees) is defined as a rate between its velocity
and Neptune velocity (27.78/5.4) = 5.1 = (Mars velocity / Pluto velocity)
Example No. (5)
(10500 / 142984) = (13.1/29.8 x 6)
- Jupiter Orbital Period (4331 solar days) has 10500 Jupiter rotation periods (9.9 h)
- 142984 km = Jupiter Diameter
- 13.1 km/s = Jupiter Velocity
- 29.8 km/s = Earth Velocity
- The data uses the rate (6) which isn't found in the equation!
- We should discuss why the data doesn't follow strictly – in the comment -

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Example No. (6)
671/6792 = (4.7 /24.1 x2) (error 1.3%)
- Mars Orbital Period (687 solar days) has 671 Mars rotation periods (24.6 h)
- 6792 km = Mars Diameter
- Also
- Mars orbital inclination 1.9 deg be defined as a rate between Mercury and Mars
velocities

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(1)
- The equation works from Mars to Pluto almost because the moon orbital period =
the moon rotation period – and there are difficulties to us the rule with Mercury
and Venus because their rotation periods are so great in comparison with the
orbital periods
(2)
- We notice that, the equation needs modifications with many planets, and also there
are planets use the equation with great errors – how to explain that?-
- The point depends on the velocities rate – because- the planets velocities rates
aren't only = the rates between planets diameters and the planets rotation periods
numbers in their orbital periods – But the planets velocities rates be used also as
planets orbital inclinations as we have seen – the orbital inclinations are the basic
problem behind why?
- Because the orbital inclinations be effected by 3 basic players which are
- (1) The Planets Masses Rates
- (2) The Planets Velocities Rates
- (3) The Planets Orbital Inclinations Configuration
- The point no. (3) can be understood by analysis of Mercury orbital inclination
- Mercury orbital inclination = 7 degrees = 1.9 degrees +5.1 degrees
- 1.9 degrees =Mars orbital inclination
- 5.1 degrees = The moon orbital inclination
- That means, the moon orbital inclination (5.1 deg) be created by effect of Mercury
and mars orbital inclinations configuration – that explains the idea –
- While the planets orbital inclinations be defined by effect of the planets velocities
rates and masses rates – the orbital inclinations themselves still need to create
configuration between each other to create a general harmony for planets motions
that causes the data to use the equation in distorted forms

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- We discuss more details about the planets orbital inclinations and their masses
rates in point no. (13)
(3)
- Based on the previous 4 equations discussions What conclusion can we reach?
- Where we know that (Mercury Orbital Distance =57.9 million km), by using the
previous (4) equations we can conclude theoretically All Solar Planets Orbital
Distances, Periods, Velocities, Rotation Periods, Diameters And Orbital
Inclinations,
- This data we can conclude theoretically without observation based on the
previous (4) equations.
- By analysis the planets orbital inclinations and their masses rates we can conclude
also the planets masses in addition
- By that, the planets fact sheet can be concluded theoretically by using these 4
equations and the one data only (Mercury Orbital Distance =57.9 million km)
- This conclusion proves the hypothesis tells, The solar planets data be created
according to One Geometrical Design
- The point no. (5) discovers and proves This One Geometrical Design

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Notice (Additional Analysis For Planets Velocities)
(1)
(9.7 /5.4) = 4π / 7
(6.8 /5.4) = 4/ π (1%)
(9.7 /6.8) = π2
/ 7 (1%) And
(9.7/5.4) + (13.1/9.7) = π
(2)
(27.78 x π2
/ 47.4 x2) = 2.86 (error 1%)
(35 x2 /24.1) = 2.86 (error 1.5%)
(4 x29.8 / 13.1π) = 2.86 (error 1.3%)
(27.78 /9.7) = 2.86 (Zero error)
(24.1 x 2 / 5.4 π) = 2.86 (error less 1%)
(2π x 13.1)/(5.4)2
= 2.86 (error 1.3%)
(9.7 x 2/6.8) = 2.86 (error less 1%)
(6.8 x 2/ 4.7) = 2.86 (error 1%)
(1.16/0.406) = 2.86 (Zero error)
- 47.4 km/s = Mercury velocity 35 km/s = Venus velocity
- 29.8 km/s = Earth velocity 27.78 km/s = The Earth Moon velocity
- 24.1 km/s = Mars velocity 13.1 km/s = Jupiter velocity
- 9.7 km/s = Saturn velocity 6.8 km/s = Uranus velocity
- 5.4 km/s = Neptune velocity 4.7 km/s = Pluto velocity
- 1.16 mkm = Jupiter motion distance during mars rotation period
- 0.406 mkm = Pluto motion distance during a solar day
- This data shows great importance for Pluto velocity per a solar day (0.406 mkm)
because its rate with light velocity (1.16 mkm/s) be (2.86) which controls all
planets velocities rates.

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3-6 The Solar System Motion Depends On One Design.
- The previous data discussion tried to prove that the solar system be created based
on one design. As you draw a right-angled triangle, this triangle dimensions and
angles can be concluded by geometrical rules– No dimension be found by a
random action – the data be found by geometrical rules –
- Now, the old question (Why the moon diameter be 3475 km?) has a new answer,
because planet diameter is rated with its rotation period and the rate of both be
rated with planets velocities, here we have a machine of gears and each gear
motion depends on the others and by that no gear dimensions can be independent
from the others. It's A Different Vision For The Solar Group –where
- This vision tells
- The solar group be created based on One Design,
- The Solar Group is similar to one building and each planet is a part of this same
building, or
- The Solar Group is similar a canal water moves through the canal and causes the
rotation for 9 waterwheels. The Motion Direction of The waterwheels is different
from the water motion direction but no waterwheel can rotate without the water
motion, or
- The solar planets are similar to train carriages, they move together one unified
general motion, or
- The solar planets be similar to knots on one robe or similar to points on the same
one trajectory of energy –
- The solar planets motions be similar to chess board pieces motions, each motion
depend on the other planets motions and be done by geometrical calculations.
- The solar system distances be created in a network form and based on one
geometrical design as A Chess Board.

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- The solar system distances be created as One Group by One Geometrical Design
and No One distance be created as individual distance, which be proved clearly by
the first equation (d2
=4d0(d-d0))
- Notice (1)
- "The One Geometrical Design" doesn't mean only an outer geometrical design but
also means the planets data and their distances be created based on this one
geometrical design – and by this vision – There's One Law Controls All Planets
Creation And Motion Data
- Notice (2)
- We should see some features of this design, where the planets orbital distances be
defined by the equation no.(1) show the distances be distributed geometrically–
this distribution – as we have discussed- doesn't depend on any planet data
- The next player is the planet velocity which be defined based on the planet orbital
distance by the equation no. (2) and based on the planets velocities rate the other
data be created as we have seen in equation no. (4) that tells – the motor which
defines the planets data is the planet velocity –
- Notice (3)
- The rate 322 causes the great effect on the planets motions velocities and by
analysis of the planets velocities we have the first reference to the value 1160000
km which be supposed a new velocity of light (1.16 million km per second)

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3-7 Why Does The Solar System Motion Depend On One Design?
- Let's review the basic idea we have referred in the paper abstract
- We try to explain why the moon orbital apogee radius be decreased from 413600
km to 406000 km
- This process be done by an effect of One Geometrical Design which uses Uranus
and Pluto motions to do that
- By this process we have discovered that One Geometrical Design be found
behind the solar system creation and motion data.
- We have tried to analyze this one design to discover how this process be done and
by this analysis we have discovered that the solar system design depends on one
light beam – that because –
- The planets matters and their distances be created out of one light beam and
because of that the solar system creation and motion data be created based on one
geometrical design
- We have to examine this light beam nature from which the solar planets and their
distances be created – and
- By this light beam analysis we have discovered that this light beam travels with a
velocity 1.16 million km per second
- Now
- We have proved The One Design by the discussion of the (4) equations
- In the next points we discuss the apogee radius decreasing process

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4- Can Light Motion Effect On Planet Motion?
4-1 Preface
4-2 The Main Data (Data No. 1)
4-3 Planet Velocity Proportionality (Data No. 2)
4-4 The Solar System One Design Description (Data No. 3)
4-5 The Solar System One Design Analysis (Data No. 4) (I)
4-6 Data No. (4) (Part II)
4-7 The Distances Be In Network Form (Data No. 5) (Part A)
4-8 Data No. (5) (Part B)
4-9 Planet Motion Data Depends On Light Motion (Data No. 6)
4-10 Planets Motions for 30 mkm (Data No. 7)

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4-1 Preface
- This point provides 10 data which tries to prove that light motion be found behind
Planet Motion and causes to create the planet motion data
- The idea can be summarized in following:
- The light motion be found before planet, and the light motion energy creates the
motion trajectories and distances – by that – the light creates something similar to
the railways where the planets be similar to trains – that explains why the light
motion controls the planets motions data-
- I try to explain why planet motion data can be produced by light motion and
because of that, the planets motions data be in proportionality with light motion
velocities
- Notice
- We have to suppose the following hypotheses
- (1) The Solar Planets and Their distances be created Out of One Light beam where
this Light Beam travels with a velocity 1.16 million km per second.
- (2) One Second of Light Motion be = One Solar Day of Planet Motion
- These hypotheses will be proved later, but it's necessary to use them to discuss the
6 data be provided here,
- The hypotheses means the planets orbital periods can be used in seconds units
because while the planet moves during its orbital period ink days units the light
can use thi0s same period in seconds units
- Notice
- The solar system creation theory tells the planets matters and their distances be
created out of one light beam (travels with velocity 1.16 million km per second),
means, the matter and space are 2 forms be created by light motion effect – as in

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Young Experiment (the double slits experiment) the coherence of light produces
bright fringes and dark fringes and by that we get the knowledge that the dark
fringes can be produced by light coherence
- I want to say that, Matter and space be created out of light, but we can't consider
the matter motion be equivalent light motion because their motions have different
features – as in double production experiment – from Gamma ray one electron and
one position be created, but the electrons and positrons motions are different from
Gamma ray motion.
- The provided 6 points tries to discover The One Geometrical Design which be
found behind the planets creation and motion data.

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4-2 The Main Data (Data No. 1)
The following Data Proves,
Planet Motion Data Be Defined By Light Motion
- (A) Light supposed velocity (1.16 mkm/s) travels a distance = The Planet Orbital
Circumference in a period (T seconds)
- (B) Light known velocity (0.3 mkm/s) travels during this period (T) a distance = D
- (C) Planet moves a distance d in a period (=Ph) where D = 2π d
- And
- Ph = The Planet Orbital Period (in hours units and not solar days)
- Let's Test That In Following:
- (1) Mercury Motion
- During 310.4s light supposed velocity (1.16 mkm/) travels 360 = 2π x 57.9 mkm
- During 310.4 s light known velocity (0.3 mkm/) travels 93.1 = 2π x 14.8 mkm
- Where
- 360 mkm = Mercury Orbital Circumference
- 57.9 mkm = Mercury Orbital Distance
- 88 days = Mercury Orbital Period
- Mercury moves during 88 hours a distance = 14.8 mkm (error1.4 %)
- (2) Venus Motion
- During 586s light supposed velocity (1.16 mkm/) travels 680 = 2π x 108.2 mkm
- During 586s light known velocity (0.3 mkm/) travels 175.8 = 2π x 28 mkm
- Where
- 680 mkm = Venus Orbital Circumference
- 224.7 days = Venus Orbital Period
- Venus moves during 224.7 hours a distance =28 mkm (error1%)

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- (3) Earth Motion
- During 810s light known velocity (0.3 mkm/) travels 243 = 2π x 38.7 mkm
- Where
- 940 mkm =Earth Orbital Circumference
- 149.6 mkm= Earth Orbital Distance
- 365.25 days = Earth Orbital Period
- Earth moves during 365.25 hours a distance = 38.7 mkm (error 1.2%)
- (4) Mars Motion
- During 1235s light known velocity (0.3 mkm/) travels 370.6 = 2π x 59 mkm
- Where
- 1433 mkm = Mars Orbital Circumference
- 227.9 mkm= Mars Orbital Distance
- 687 days = Mars Orbital Period
- Mars moves during 687 hours a distance = 59 mkm (error 1%)
- (5) Jupiter Motion
- During 4222.6s light supposed velocity (1.16 mkm/) travels 4900=2π x 778.6 mkm
- During 4222.6s light known velocity (0.3 mkm/) travels 1267 = 2π x 201.7 mkm
- Where
- 4900 mkm =Jupiter Orbital Circumference
- 4331 days = Jupiter Orbital Period
- 4222.6 h = Mercury Day Period
- Jupiter moves during 4331 hours a distance = 201.7 mkm (error 1.3%)

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- (6) Saturn Motion
- During 7765s light supposed velocity (1.16 mkm/) travels 9007 = 2π x 1433 mkm
- During 7765s light known velocity (0.3 mkm/) travels 2330 = 2π x 371 mkm
- Where
- 9007 mkm = Saturn Orbital Circumference
- 1433 mkm = Saturn Orbital Distance
- 10747 days = Saturn Orbital Period
- Saturn moves during 10747 hours a distance = 371 mkm (error 1%)
- (7) Uranus Motion
- During 15559s light supposed velocity (1.16 mkm/) travels 18048=2π x 2872 mkm
- Where
- 2872 mkm = Uranus Orbital Distance
- 30589 days = Uranus Orbital Period
- Uranus moves during 30589 hours a distance = 742 mkm (error 1%)
- (8) Neptune Motion
- During 24348s light supposed velocity (1.16 mkm/) travels 28244 =2π x4495 mkm
- Where
- 28244 mkm = Neptune Orbital Circumference
- 4495.5 mkm = Neptune Orbital Distance
- 59800 days = Neptune Orbital Period
- Neptune moves during 59800 hours a distance = 1163 mkm
- (9) Pluto Motion
- During 31983s light supposed velocity (1.16 mkm/) travels 37100= 2π x 5906mkm

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- Where
- 37100 mkm = Pluto Orbital Circumference
- 5906 mkm = Pluto Orbital Distance
- 90560 days = Pluto Orbital Period
- Pluto moves during 90560 hours a distance = 1527 mkm
- (1527 = 2π x 243)
- (10) The Earth Moon Motion
- During 639s light supposed velocity (1.16 mkm/) travels 742 mkm
- During 639s light known velocity (0.3 mkm/) travels 191.6 = 2π x 30.5 mkm
- But
- 30.5 mkm = 88000 km x 346.6 days
- The moon displacements total during 346.6 (solar days) = 30.5 mkm
- Where
- 346.6 solar days= The nodal year
- 88000 km = The moon displacement for a solar day
- 742 mkm = The distance be passed by Uranus in 30589 hours (error 1%)
- This data tells, the moon orbit regression be done by effect of Uranus motion.
- Notice
- All defined periods (the red colored periods) are the planets orbital periods in
hours units. (Data Max Error is 1.4%)
- Notice
- The moon motion be done in a period 346.6 solar days and not 346.6 hours (that
creates a special case for the moon motion) – because we need to know why the
moon uses the period (346.6) in days units and not in hours as the others.
- The moon motion data depends on the distance (742 mkm) which be defined by
Uranus motion data
-

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- Notice
- The inner planets distances in blue color ( 93.1, 175.8, 243, 370.6) can be used as
cycles periods because
- 175.8 solar days =Mercury day period
- 243 solar days = Venus rotation period
- 370.6 solar days are near to 365.25 days (error 1.5%),
- (93.1 days x 2π= 584 days =the period of periodical meeting of Earth and Venus)
- This equality depends on the rate 1mkm = 1 day
- That tells each planet creates its previous neighbor cycle period
- And the outer planets distances in blue color (1267, 2330 , 4664, 7305, 9595)
- 2330 = 2 x 1165
- 4664 = 4 x 1165
- 7305 = 2π x 1165
- This data we need later for analysis -
- Please note/
- Neptune motion is the most accurate data because it has Zero Error!

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Comments On Data No. (1)
The data shows all planets use the same system sufficiently –
Planet T/ P The values rate
Mercury 88/310.4 = 0.283 28.3% (----)
Venus 224.7/ 586 = 0.383 38.3 % (---)
Earth 365.25 /810 = 0.45 45% (--)
Mars 687/1235 = 0.55 55.6% (-)
Jupiter 4331 /4222.6 = 0.97 97.5%
Saturn 10747/7765 =1.384 72.2% (+)
Uranus 30589/15559 = 1.966 50.8% (++)
Neptune 59800 /24348 = 2.456 40.7% (+++)
Pluto 90560/31983 =2.8315 35.3% (++++)
- T = The period of time be required by light motion
- P = Planet Orbital Period
- The values rate measures the rate between the 2 periods of time (T and P), and
because of that (for example), the period T = 15559 while and P (Uranus orbital
period) =30589, and for that the period 15559 be 50.8% of Uranus orbital period.
- The data shows Jupiter is the nearest point for the equality of the 2 periods (T and
P) (The difference is only 2.5% - because Jupiter velocity 1.1318 is less than light
supposed velocity 1.16 with 2.5%)
- The inner planets data shows the period (T) is less than planet orbital period (P)
- But
- This fact is reversed in the outer planets data where the planet orbital period (P) be
greater than the period (T). That shows Jupiter is the balancing point between all
planets data.

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4-3 Planet Velocity Proportionality (Data No. 2)
We have discussed this equation before
Where's this is the firs reference for the light supposed velocity 1.16 million km/s
1160000 seconds = 3600 seconds x 322 hours
Data
(a)
1160000 seconds = 3600 seconds x 322.2 hours
(b)
322.2 = 47.4 km/s (Mercury velocity) x 6.8 km/s (Mercury velocity)
322.2 = 35 km/s (Venus velocity) x 2 x 4.7 km/s (Pluto velocity) (error 2%)
322.2 = 29.8 km/s (Earth velocity) x 2 x 5.4 km/s (Neptune velocity)
322.2 = 24.1 km/s (Mars velocity) x 13.1 km/s (Jupiter velocity) (error 2%)
322.2 =35 km/s (Venus velocity) x 9.7 km/s (Pluto velocity) (error 5%)
322.2 =27.78 km/s (The moon velocity) x (24.1/2) (error 4%)
(c)
300000 seconds x 4 = 3600 seconds x 333.3
333.3 = 35 km/s (Venus velocity) x 9.7 km/s (Pluto velocity) (error 1.8%)
333.3 = 24.1 km/s (Mars velocity) x 2 x 6.8 km/s (Uranus velocity) (error 1.7%)
(d)
(1.16 /0.3) = (24.1/2π)
(e)
83.33 = 2π x 13.26
(f)
322.2 =24.6 x 13.1
322
2
1 =
v
v

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- Based n this data
- Mercury (47.4 km/s) moves during 6.8 hours a distance = 1.16 million km
- Uranus (6.8 km/s) moves during 47.4 hours a distance = 1.16 million km
- And
- Earth (29.8 km/s) moves during 5.4 x 2 hours a distance = 1.16 million km
- Neptune (5.4 km/s) moves during 29.8 x 2 hours a distance = 1.16 million km
- We have 2 conclusions based on the previous data which are
- (1) The planets velocities be created complementary one another
- (2) The planets velocities proportionality depends on the light supposed velocity
(1.16 million km/s).
- Also that creates a great importance for the period (T) during which the light
supposed velocity (1.16 mkm/s) passes a distance =planet orbital circumferences
- This feature which be found for all planets motions concerning light supposed
velocity (1.16 mkm/s), be used for 4 planets only (Venus, Saturn, Mars and
Uranus) concerning the light known velocity (300000 km/s), but the rate 83.3
(83.3 x 3600 = 300000) this rate isn't used instead we need the rate (333.3 = 83.3 x
4) that may refers to the reason behind Earth Cycle (365+365+365+366 =1461
days).
Equation no. (d)
(1.16 /0.3) = (24.1/2π)
- 1.16 mkm/s = Light Supposed Velocity
- 0.3 mkm/s = Light Known Velocity

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Equation no. (e)
83.33 = 2π x 13.26
- 83.33 = 300000 /3600s
- 13.1 km/s = Jupiter Velocity (error 1.2% with 13.26)
Equation no. (e)
322.2 =24.6 x 13.1
- 24.6 hours = Mars Rotation Period
- 13.1 km/s = Jupiter velocity
- These 3 equations shows that, Jupiter and Mars have specific velocities, we have
to explain that in more details in the data discussion.
- Shortly
- Jupiter moves during Mars rotation period (24.6h) a distance = 1.16 mkm where
Jupiter orbital circumference be designed based on the rate (1.16) and that makes
Mars rotation period (24.6 h) is so effective period of time on Jupiter motion data,
and on all other planets motions.
- We discuss Mars rotation period in point no.(5-2) of this paper.

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4-4 The Solar System One Design Description (Data No. 3)
- (Point No. I)
- 100733 mkm (= the solar planets orbital circumferences total) = 2π x 16030 mkm
- 2 x 197392 days (= the solar planets orbital Periods total) = 24.6 x 16030 mkm
- And
- Light supposed velocity (1.16mkm/s) travels during 2x 16030 s a distance =37100
mkm (= Pluto Orbital Circumference)
- Light known velocity (300000km/s) travels during 16030 s a distance =4810 mkm
(= Jupiter Orbital Circumference 4900 mkm error 2%)
- In this point I try to show that the solar system geometrical design depends on this
value (16030)
- The basic difficulty is that
- We have to neglect the used units with the value because we deal with light motion
and the distances can be used as periods of time because of that – and the result is
that – the units be used according to the mentioned using of number – that will be
more clear later
- (Point No. II)
- (a)
- Light known velocity (0.3 mkm/s) travels during 1200 s a distance =360 mkm =
Mercury Orbital Circumference
- Light known velocity (0.3 mkm/s) travels during 16330 s a distance =4900 mkm =
Jupiter Orbital Circumference
- But
- 2 x 16330 = 1200 x 27.2
- The moon velocity (27.78 km/s) different with (27.2) by error (2%)

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- (b)
- Light (0.3 mkm/s) travels during 16330 s a distance =4900 mkm
- And
- The moon (27.78 mkm/s) travels during 16330 s a distance =449197 km = Jupiter
Circumference
- (The moon velocity =27.78 km/s be proved in Point no. (5-10) of this paper)
- Notice
- 4900 mkm (Jupiter Orbital Circumference) = 449197 km x 10921 km
- And
- Jupiter (13.1 km/s) travels during 10921 sec a distance = 142984 km = Jupiter
diameter
- Where (10921 km = The Moon Circumference)
- By Data No (b) I try to show that the moon motion be a partner in the main
trajectory motion be defined by light motion – means, the moon is created later but
its motion be effective on the solar system basic trajectory defined by light motion
because of the number (16030) or (16330) (error 2%)
- The error (2%) doesn't create a problem for the discussion, on the contrary, the
error (2%) we do need because
- The moon orbital apogee radius be decreased from 413600 km to 406000 km
where the difference be around 2%) by that this error may covers the decreasing
reason.
- Notice
- The moon displacements total during (29.53 days) be (2.5986 mkm) w3hose radius
be (413600 km) and the apogee real radius be (406000 km) and its circumference
be (2.5509 mkm) the difference between (2.5986 mkm) and (2.5509 mkm) be =
47720 km this distance be = the distance Jupiter passes in one hour (error 1%)
Notice/ We should keep our eyes on the 2 numbers (16030 and 4900)

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4-5 The Solar System One Design Analysis (Data No. 4) (I)
Can The Solar Planets Motions Depend On One Geometrical Design?
(A)
- Light known velocity (0.3 mkm/s) needs 1200 seconds to pass a distance = 360
mkm = Mercury Orbital Circumference – But
- Mercury (4.095 mkm /day) moves during 1200 solar day a distance = 4914 mkm
(where 4900 mkm = Jupiter Orbital Circumference)
(B)
- Light known velocity (0.3 mkm/s) needs 16333 s to pass a distance = 4900 mkm =
Jupiter Orbital Circumference – But
- Jupiter (1.1318 mkm /day) moves during 16333 solar days a distance = 18486.4
mkm (where 18048 mkm = Uranus Orbital Circumference – error 2.4%)
(C)
- Light known velocity (0.3 mkm/s) needs 60161 s to pass a distance = 18048 mkm
= Uranus Orbital Circumference – But
- Uranus (0.5875 mkm /day) moves during 60161 solar days a distance = 35346
mkm (where 37100 mkm = Pluto Orbital Circumference – error 4.8%)
(D)
- Light known velocity (0.3 mkm/s) needs 123667 s to pass a distance = 37100 mkm
= Pluto Orbital Circumference –
- Notice
- Light known velocity (0.3 mkm/s) needs 3134 s to pass a distance = 940 mkm =
Earth Orbital Circumference – But
- During 2 x 3134 solar days, the moon displacements total = 550.7mkm =Mars
Jupiter Distance.
- Notice
- The planets orbital circumferences total till Uranus (including Uranus orbital
circumference) be 35346 mkm

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Comments On Data No. (4) (Part I)
- This data idea tells that, there's one thread connects Mercury, Jupiter, Uranus and
Pluto together. That can be noticed because the 4 planets motions depends on the
value (4900).
- Jupiter Orbital Circumference = 4900 mkm
- Uranus needs 4900 solar days to move a distance = 2872.5 mkm (Uranus Orbital
Distance)
- Pluto needs 3 x 4900 solar days to move a distance = 5906 mkm (Pluto Orbital
Distance) (error 1%)
- Notice
- Neptune needs 2 x 4900 solar days to move a distance = 4495.1 mkm (Neptune
Orbital Distance) (error 1.7%)
- The data tells some geometrical design must be found behind which we need to
discover
- For that reason we examine all planets motions to discover the effect of this value
(4900) on them
- Notice
- The value 4900 mkm plays (again) the central role in the solar planets motions
data, this notice is important because, Jupiter velocity per a solar day (1.131 mkm)
be the most near to light supposed velocity (1.16 mkm/s) the error (2.5%) that
makes Jupiter the central planet in the solar system motion – and here we catch
that the distance 4900 mkm plays one more central role in the general design. We
have a reason to suppose that Jupiter is a central motor of the solar system. under
this idea we can see the moon motion effect because of the deep interaction of
motion between Jupiter and the moon as we have discussed before

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4-6 Data No. (4) (Part II)
(A)
mkm = Mercury Orbital Circumference – But
- Mercury (4.095 mkm /day) moves during 1200 solar day a distance = 4914 mkm
(Where 4900 mkm = Jupiter Orbital Circumference)
- Notice
- Mercury orbital distance 57.9 mkm and Mercury needs 14.14 days (=340 h) to
pass this distance (but light known velocity (0.3mkm/s) moves in (340s) a distance
102 mkm). (Note Please, 4914 mkm =102 mkm x 48.2)
(B)
- Light known velocity (0.3 mkm/s) needs 2266.7 seconds to pass a distance = 680
mkm = Venus Orbital Circumference – But
- Venus (3.024 mkm /day) moves during 2266.7 solar day a distance = 6855 mkm
- Notice
- Venus orbital distance 108.2 mkm and Venus needs 35.8 days (=859.2 h) to pass
this distance (but light known velocity (0.3mkm/s) moves in (859.2s) a distance
257.8 mkm). (Note Please, 6855 mkm =257.8 mkm x 26.6)
(C)
mkm = Earth Orbital Circumference – But
- Earth (2.574 mkm /day) moves during 3134 solar day a distance = 8067.5 mkm
- Notice
- Earth orbital distance 149.6 mkm and Earth needs 58.1 days (=1394.5 h) to pass
418.35 mkm). (Note Please, 8067.5 mkm =418.35 mkm x 19.28)

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(D)
mkm = Mars Orbital Circumference – But
- Mars (2.082 mkm /day) moves during 4776 solar day a distance = 9946.2 mkm =
2 x 4973 mkm
- Notice
- Mars orbital distance 227.9 mkm and Mars needs 109.5 days (=2626.8 h) to pass
788 mkm). (Note Please, 9946.2 mkm =788 mkm x 12.62)
- Also
- (Mars Axial Tilt =25.2 deg = 2 x 12.6) and (778.6 mkm=Jupiter orbital distance
and with 788 mkm the error 1.2%) and (9946.2 mkm = 2 x 4973 mkm where 4900
mkm is Jupiter Orbital Circumference with 4973 mkm be 1.5%)
(E)
mkm = Jupiter Orbital Circumference – But
- Jupiter (1.1318 mkm /day) moves during 16333 solar day a distance = 18487 mkm
(18048 mkm = Uranus Orbital Circumference) (error 2.4%)
- Notice
- Jupiter orbital distance 778.6 mkm and Jupiter needs 688 days (=16510 h) to pass
this distance (but light known velocity (0.3mkm/s) moves in (16510 s) a distance
4952 mkm). (Note Please, 18487 mkm =4952 mkm x 3.73)
(4900 =Jupiter Orbital Circumference with (4952) the error 1%)
(F)
mkm = Saturn Orbital Circumference – But
- Saturn (0.838 mkm /day) moves during 30023 solar day a distance = 25162 mkm

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- Notice
- Saturn orbital distance 1433.5 mkm and Saturn needs 1710 days (=41037 h) to
pass this distance (but light known velocity (0.3mkm/s) moves in (41037 s) a
distance 12311 mkm(Note Please, 25162 mkm =12311 mkm x 2.04)
(G)
- Light known velocity (0.3 mkm/s) needs 60160 seconds to pass a distance =18048
mkm = Uranus Orbital Circumference – But
- Uranus (0.5875 mkm /day) moves during 60160 solar day a distance = 35345
mkm
- Notice
- Uranus orbital distance 2872.5 mkm and Uranus needs 4889 days (=117341 h) to
pass this distance (but light known velocity (0.3mkm/s) moves in (117341 s) a
distance 35202 mkm (Note Please, 35345 mkm =35202 mkm, error 0.4%)
(H)
mkm = Neptune Orbital Circumference – But
- Neptune (0.4668 mkm /day) moves during 94147 solar day a distance = 43925 mkm
- Notice
- Neptune orbital distance 4495.1 mkm and Neptune needs 9635 days (=231229 h)
to pass this distance (but light known velocity (0.3mkm/s) moves in (231229 s) a
distance 69369 mkm (Note Please, 43925 mkm = 69369 mkm x 0.6333)
(I)
- Light known velocity (0.3 mkm/s) needs 123667 seconds to pass a distance =
37100 mkm = Pluto Orbital Circumference – But
- Pluto (0.406 mkm /day) moves during 123667 solar day a distance = 50219 mkm

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- Notice
- Pluto orbital distance 5906 mkm and Pluto needs 14544 days (=349054 h) to pass
this distance (but light known velocity (0.3mkm/s) moves in (349054 s) a distance
104716 mkm (Note Please, 50219 mkm = 104716 mkm x 0.47957)
- Notice
- Jupiter moves during (24.6 h =Mars Rotation Period) a distance =1.16 mkm (light
supposed velocity passes in 1 second a distance = 1.16 mkm) - And
- Uranus moves during (24.6 h =Mars Rotation Period) a distance =0.6 mkm
- (light known velocity passes in 2 seconds a distance = 0.6 mkm)
- Also
- Uranus moves in 2 solar days a distance =1.16 mkm (error 1.3%)
- Let's see the following Data
- That shows One Geometrical Design be found for the solar system motion

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- Because the 2 distances are equal in Uranus Data (35345 mkm =35202 mkm,
error 0.4%), We conclude that a geometrical design be found behind the planets
velocities distribution.
- Before Uranus, Planet motion distance be greater than light motion distance in all
planets but the difference be decreasing gradually.
- After Uranus, Planet motion distance be shorter than light motion distance in
(Neptune and Pluto) where the difference be increasing gradually.
- For the 3 planets (Uranus, Saturn and Neptune) the rates be function in their orbital
distance – (if Uranus be 1), So Saturn be (1/2) and Neptune be (π/2) because
Uranus orbital distance 2872.5 mkm = 2 Saturn orbital distance 1433 mkm =2/ π
Neptune orbital distance 4495.1 mkm.
- For another group of 3 planets (Jupiter, Saturn and Uranus), their velocities per a
solar day almost be in order (2, 3, and 4), where Uranus moves in a solar day
0.5875 mkm (Light 0.3mkm/s moves during 2 sec a distance 0.6 mkm error 2%)
and Saturn moves 0.838 mkm (light 0.3 mkm/s in 3 sec 0.9 mkm error 7.25%) and
Jupiter moves 1.1318 mkm (light 0.3 mkm/s in 4 sec 1.2 mkm error 6%)
- We should discuss these great errors later, because the error (7.25%) depends on
the rate (1.0725) which be used as a rate between 40% of all distances in the solar
system –for that reason –the error explanation needs more area for extending
discussion.

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- Notice
- (0.9 mkm- 0.838 mkm = 61920 km where accurately 61920 s=17.2 h = Uranus
Day Period
- That tells, Uranus Day Period (17.2h) be created by Saturn motion effect, that
explains why Saturn moves in (17.2 h) a distance= 600000 km
- Many questions still be left behind - one basic question is that – How to explain
the using of the distance 4900 mkm? in different data we have seen this distance
and also Uranus needs around 4900 days to pass its orbital distance –How to
explain that

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4-7 The Distances Be In Network Form (Data No. 5) (Part A)
The Solar System Distances Creation In A Network Form
- The solar system distances be created in a network form. The following data can
prove this fact clearly…
(A)
- 0.3 mkm /s (light known velocity) passes in 2094 seconds a distance =629 mkm
- 629 mkm = Earth Jupiter Distance
- 2094 mkm= Jupiter Uranus Distance
- The data shows that, a light beam started from the Earth to Jupiter and passed from
Jupiter to Uranus
- The data shows that the 2 distances (629 mkm and 2094mkm) are created together
based on a geometrical mechanism
(B)
- 0.3 mkm /s (light known velocity) passes in 2 x 2723 sec a distance = 1634 mkm
- 2723 mkm = Earth Uranus Distance
- 1622.7 mkm = Uranus Neptune Distance (with 1634 mkm error0.7%)
- The data shows that, a light beam started from the Earth to Uranus and passed
from Uranus to Neptune -
- The data uses the rate (2) because the distance 2723 mkm x 2 = Earth Uranus
Orbital Diameter through the revolution around the sun – the data shows (two)
distances be used in equivalence to (one) distance- which is a known feature of the
solar system motion- as –Uranus orbital distance = 2 Saturn orbital distances
- The data shows that the 2 distances (2723 mkm and 1622.7 mkm) are created
together in a network form

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(C)
- The distance 1622.7 mkm be used as a period of time =1622.7 seconds and
- 1622.7 seconds = 2 x 810 seconds
- Where the period 810 seconds is very famous in the solar system motion –because
light supposed velocity (1.16 mkm/sec) passes in 810 sec a distance 940 mkm –
and light known velocity (0.3 mkm/s) passes in 810 seconds a distance= 243 mkm-
- That shows the distances be distributed based on one geometrical design
(D)
- 0.3 mkm /s (light known velocity) passes in 18048 sec a distance = 5415 mkm =2
x 2707 mkm (Earth Uranus Distance 2723 mkm error 0.5%)
- The data shows that, the distances 18048 mkm and 2723 mkm be distributed based
on one geometrical design.
(E)
- 0.3 mkm /s (light known velocity) passes in 4345.5 sec a distance = 1303 mkm
- 1411 mkm =1.0725 x 1303 mkm (error 1%)
- Where
- 4345.5 mkm = Earth Neptune Distance
- 1411 mkm = Neptune Pluto Distance
- Notice (1)
- The rate (1.0725) is used with around 40% of all distances in the solar system –
- This rate (1.0725) be discussed in point no. (5-7) on this current paper
(F)
- 0.3 mkm /s (light known velocity) passes in 5756.4 sec a distance = 1727 mkm
- Where
- 5756.4 mkm = Earth Pluto Distance
- 1727 mkm = π x 550.7 mkm Mars Jupiter Distance

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- Notice (2)
- The data deals with Earth distances to the outer planets in order and it shows all
distances must be distributed based on one geometrical design –which proves
clearly that the solar system distances be created in a network form based on one
geometrical design –and Earth distances shows one feature of this design features
- Notice (3)
- 37100 x (0.3)3
=1000 mkm
- 1000 x (1.16)3
= 2 x 780 mkm
- 1000 x 0.3 =300 mkm
- Where
- 37100 mkm = Pluto Orbital Circumference
- 300 mkm = Earth orbital diameter (=149.6 mkm x 2 = 299.2 mkm)
- Notice (2)
- 100733 x (0.3)2
= 9066 mkm
- Where
- 100733 mkm = The solar planets orbital circumferences total
- 9007 mkm = Saturn Orbital Circumference (with 9066 error 0.6%)
- This data may refer to specific importance of Saturn motion in the solar system
motion.

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4-8 Data No. (5) (Part B)
I- Data
(1)
310.3 =(360 mkm/1.16) = (351.3 /1.13184)
- 360 mkm = Mercury Orbital Circumference
- 1.1318 mkm = Jupiter Velocity Per A Solar Day
- 1.16 mkm = light supposed velocity
- 351.3 = ??
(2)
586.6 = (680 mkm/ 1.16) = (663.5 mkm/ 1.1318)
- 940 mkm = Venus Orbital Circumference
- 680 mkm = Earth Orbital Circumference
- 663.5 mkm = 670.4 mkm (Venus Jupiter Distance error 1%)
- (light supposed velocity 1.16mkm/s moves 680 mkm in 586.6 seconds)
(3)
810.4 = (940 mkm /1.16) = (917.2 /1.1318)
- 940 mkm = Earth Orbital Circumference
- 917.2 = 929 mkm (Earth Jupiter Distance error 1.3%)
- (929 mkm be produced when Earth and Jupiter be on 2 different sides from the sun)

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(4)
2 x 243 = (654.9 mkm /1.162
) = (550.7/1.1318)
- 654.9 mkm = Jupiter Saturn Distance
- 550.7 mkm = Mars Jupiter Distance
(5)
1850 = (2146 mkm/1.16) = (2094/1.1318)
- 2146 mkm = (4292 mkm/2) (where 4267 mkm Mars Neptune Distance)
- 2094 mkm = Jupiter Uranus Distance
(6)
4530 = (5259 mkm /1.16) = (5127.4/1.1318)
- 5259 mkm = (2630 mkm x 2) (Where 2644 mkm Mars Uranus Distance)
- 5127.4 mkm = Jupiter Pluto Distance
(7)
550.7 = (644.6 mkm/1.16) = (629/1.1318)
- 644.6 mkm = ???
- 629 mkm = Jupiter Earth Distance

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(8)
578.6 = (670.4 mkm /1.16) = ( 654.9 /1.1318)
- 670.4 mkm = Jupiter Venus Distance
- 654.9 mkm = Jupiter Saturn Distance
(9)
3283.6 =(3809 mkm/1.16) = (3717 mkm /1.1318)
- 3809 mkm = (3809 mkm = π x 1205 mkm Mars Saturn Distance)
- 3717 mkm = Jupiter Saturn Distance
II- More Data
1.16 mkm/s x 500 s = 580 mkm
1.16 mkm/s x 580 s = 671 mkm (Venus Jupiter Distance)
1.16 mkm/s x 671 s = 778.6 mkm (Jupiter Orbital Distance)
1.16 mkm/s x 629 s = 720.7 mkm (error 1%) (Mercury Jupiter Distance)
1.16 mkm/s x 5127 s = 5906 mkm (error 0.7%) (Pluto Orbital Distance)
This data shows that, there are more distances of Jupiter be distributed based on the
rate (1.16) or by using light supposed velocity (1.16mkm/s) which proves that the
solar planets distances be distributed based on one geometrical design and the
distances be created in a network form

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- Let's summarize the data idea in following:
- The data compares between light supposed velocity (1.16 mkm/s) and Jupiter
motion distance during a solar day (1.13184 mkm/day)
- The data uses 2 columns, one of them depends on light supposed velocity (1.16
mkm/s) and the other depends on Jupiter velocity per a solar day 1.1318 mkm
- The column of light motion uses the distances between Jupiter and the other
planets –
- The column of Jupiter motion produces 3 types of motions (first type 4 distances
between Jupiter and other planets, and 3 distances between Mars and other
planets and 2 values which are 351.3 and 644.6 which be related to the distance
720.7 mkm = Mercury Jupiter Distance)
- The Argument tells the following:
- I can provide a hypothesis tells that (A light beam its velocity be 1.16 mkm/s be
found and effective on the solar system motion), it's my hypothesis, and
- Because Jupiter velocity be 1.13184 mkm per a solar day, the 2 velocities 1.16
mkm and 1.1318 mkm be so near and that may effect on the planets motions data–
I also can conclude this idea
- But
- I can't define the planets positions based on my hypothesis unless the hypothesis
be a fact. If there's no light velocity = 1.16 mkm that should cause a chaos for the
distribution of data – but wee see a consistency of data – because
- 4 results are Jupiter distances to other planets and 3 results be Mars distances to
other planets. That tells 7 results are related to Jupiter motion – that because
Jupiter moves depending on Mars Period of time – that means- there's a deep
interaction between Mars and Jupiter Motions cause the 2 motions be considered
as one motion – by that Jupiter motion depends on Mars period of time – for

I do this research
2nd
67
example Jupiter motion a distance = 778.6 mkm = Jupiter orbital distance in a
period = 687 days = Mars orbital period
- The basic point here is that, Jupiter moves during (Mars rotation period 24.6 h) a
distance =1.16 mkm where Jupiter orbital circumference be designed based on the
distance 1.16 mkm –that creates the deep interaction between Jupiter and Mars
motions –
- The point is that, because the data defines clearly the planets positions based on
the 2 velocities 1.16 mkm/s and 1.13184 mkm /day that proves the hypothesis is a
fact otherwise why the planets positions be defined based on these velocities?
- We have only the rest 2 distances (351.3 mkm and 644.6 mkm)
- 351.3 mkm = 2 x 175.95 mkm ( Mercury Day Period = 175.95 days)
- 644.6 mkm = (during a period 636.3 days Jupiter motion 720.7 mkm)
- Mercury moves 720.7 mkm in its day period (175.95 solar days)
- This data shows a connection with the distance 720.7 mkm.
A Conclusion
- All used and produced distances are defined distances which means we deal with
One Geometrical Design And A Network Form. There's no random process can
be found here we deal completely with a geometrical system which proves the
light supposed velocity (1.16 mkm/sec) is a real one and a fact.

I do this research
2nd
68
4-9 Planet Motion Data Depends On Light Motion (Data No. 6)
I – Data
- 4.095 mkm (Mercury velocity per a solar day) x 360 days =4224 s x 0.3 x 1.16
- 3.024 mkm (Venus velocity per a solar day) x 680 days = 5906 s x 0.3 x 1.16
- 2.4 mkm (The Moon velocity per a solar day) x 940 days = 6483 s x 0.3 x 1.16
- 2.574 mkm (Earth velocity per a solar day) x 940 days = 6939.75 s x0.3 x1.16
- 2.082 mkm (Mars velocity per a solar day) x 1433 days = 8573 s x 0.3 x 1.16
- 1.1318 mkm (Jupiter velocity per a solar day) x 4900 days =15937 s x 0.3 x 1.16
- 0.838 mkm (Saturn velocity per a solar day) x 9007 days = 2x 10844 s x0.3 x 1.16
- 0.5875 mkm (Uranus velocity per a solar day) x 18048 days =30589 s x 0.3 x 1.16
- 0.4668 mkm (Neptune velocity per a solar day) x 28244 days =37893s x 0.3 x 1.16
- 0.406 mkm (Pluto velocity per a solar day) x 37100 days =43283 s x 0.3 x 1.16

The Solar System Motion Analysis (Revised And Modified).pdf

The Solar System Motion Analysis (Revised And Modified).pdf

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The Solar System Motion Analysis (Revised And Modified).pdf