The Sun Is The Solar System Last Created Piece (Newton Was Wrong) (Revised)

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
The Sun Is The Solar System Last Created Piece (Newton Was Wrong) (Revised)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –9th
August 2021
Abstract
Paper hypothesis
- Newton Theory of The Sun Mass Gravity Be Refuted Decisively By 2 Facts
Which Are:
- (1st
Fact) The Sun Is Created After All Solar Planets Creation And Motion.
- (2nd
Fact) The Solar Planets Move A Type Of Motion Different Completely
From The Planet Motion Be Described By Newton Theory Of The Sun Mass
Gravity.
Paper Proves
- The (2nd
Fact) is proved by The Solar Planets Motions Analysis.
- While Newton had supposed that, Each planet moves independently from the other
planets. The fact is that, the planets motions be integrated into one unified general
motion. by that, The Planets Motions Be similar to The Train Carriages Motion.
or similar to A Machine Of Gears Motion.
- The Planets Motions Data Analysis disproves the Motion Independency Concept,
showing that, the planets motions be different completely from Newton Motion
Description.
- The (1st
Fact) which is (The Sun is Created after all Planets Creation and Motion).
This Fact disproves Newton Theory decisively. This fact proves are discussed in
this paper introduction.
Please scan the figure (ORCID)

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Paper Contents
Subject Page No.
1- Introduction 4
2- Methodology 8
3- The Sun Age Historical Proves 8
3-1 The Sun Circles The Earth 8
3-2 The Rate (1.0725) 9
3-3 The Sun Diameter Analysis 13
4- The Light Velocity 1.16 mkm/sec 16
4-1 Preface 16
4-2 Jupiter Motion Data proves the existence of the light velocity 1.16 mkm/sec 19
4-3 More Proves For The Light Velocity 1.16 mkm/sec 37
4-4 Jupiter Orbital Circumference Analysis 44
4-5 The Sun Rays Creation 60
5- The Solar Planets Move One Unified General Motion 65
5-1 The Planets Unified General Motion Description 65
5-2 The Solar Planets Motions Are Complementary One Another 66
5-3 The Solar Planets Move An Unified Motion (A Team Motion) 71
6- The Solar Planets Motions Depend On Different Rates of Time 76
6-1 Preface 76
6-2 Earth And Pluto Rate Of Time 77
6-3 Mercury Motion Rate Of Time 86
6-4 Saturn Motion Rate Of Time 89
6-5 Uranus And Jupiter Rate Of Time 92
7- The Solar Planets Motions Analysis 94
7-1 Preface 94
7- 2 The Equal Distances Method 95
7-3 The Inner And Outer Planets Motions Be Distinguished 101
8- The Moon Orbital Motion Description 109
8-1 Why Does The Moon Use Pythagorean Triangle In Its Motion? 110
8-2 How Does The Moon Use Pythagorean Triangle In Its Motion? 111
8-3 The Moon Orbital Motion Analysis 113
8-4 The Moon Orbital Motion Equation 116
Appendix No.1 The Solar System Equal Distances List 125
Appendix No.2 Planet Orbital Distance Equation 127
Appendix No.3 Planet Gravity Equation 130
References and Biography 131

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1-Introduction
- How to prove, The Sun Is Created After All Planets Creation And Motion?
- More easy question (How The Solar Group Be Created?)
- I have an answer for this question…
o The Matter Is Created Out Of Light
o Specifically
o The Solar Planets Matters And Their Distances Are Created from One Light
Beam
o And
o There's a light beam its velocity =1.16 million km per second.
o Means
o The Solar Planets Matters And Their Distances Are Created from One
Light Beam Its Velocity =1.16 million km Per Second.
- Let's remember the question
- How to prove, The Sun Is Created After All Planets Creation And Motion?
o Where
o The Sun Light Velocity =300000 km /sec.
o This Velocity Of Light Proves That The Sun Is Created After All
Planets Creation And Motions.
o Because
o The Planets Creation and Motion data shows their energy depend on light
beam its velocity =1.16 mkm/sec. that means, the light known velocity (0.3
mkm/sec) is created as a side product from the original one (1.16 mkm/sec)
o Shortly
o The Planets Creation and Motion data show their source of energy depend
on a light beam its velocity =1.16 mkm/sec

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o This velocity of light be registered in the solar planets creation and motion
data. because of that we analyze the planets data and prove that these planets
be created based on a light beam its velocity =1.16 mkm/sec
o And
o The sun light velocity is 0.3 mkm/sec. which proves that, this light beam is
created as a side product of the original one (1.16 mkm/sec) and that proves
decisively the claim (the sun is created after all planets creation and motion)
- Based on that
- The Refutation of Newton Theory of The Sun Mass Gravity depends on 2 basic
points.
- (1st
Point) to prove that, There's A Light Beam Its Velocity =1.16 mkm/sec In
The Solar System
- (2nd
Point) to prove that, The Solar Planets Move One Unified General Motion
- The paper provides also some historical proves to support its arguments.

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2-Methodology
(I)
- I use Planets Data Analysis to discover the solar planets creation and motion.
- This method put planets data in comparison with physics theory trying to know if
the theory is sufficient to explain the planets motions data.
- The method is useful because it creates questions and shows the consistency or
inconsistency between planets motions data and the theory
(II)
- This method also tries to discover how the planet get its data. So, questions (why
the moon diameter =3475 km?) be usual question. The method tries to know if the
planet data be created based on any geometrical reason or by an effect of other
planets or any other force.
- The vision tells, Planet moves depending on its data, by that, the research method
tries to discover the relationship between planet motion and its data, for example it
tries to answer the question (If a planet velocity changes what data will be changed
as a result?).
(III)
- The research method considers planet data be very useful source of knowledge for
planet motion explanation. Let's use one example to explain that
Example no. (1)
- The solar planets order contradicts the gravitation equation strongly, when we
asked why? the answer was because of (The Initial Conditions)!!
- Jupiter occupies the order no (5) in the solar system, and the 3 planets (Earth –
Venus – Mercury) shows that greater mass needs longer orbital distance and not
shorter. And even Uranus (less mass) be more near to the sun than Neptune
(greater) mass. these are clear contradictions with the gravitation equation. Why
the equation be acceptable spite?! Because of (The Initial Conditions)!!
- And what are (These Initial Conditions)?!

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- The planets positions be inherited through the history. These positions restricted
the planets and prevented them to correct their positions to follow the gravitation
equation. This answer simply disregards the planet motion, because it considers
the planet motion has no any effect on this planet data.
- I want to say, not only the answer is wrong. But the answer also shows that, no
attention is paid for the planet data as if the plant motion be done regardless any
planet data. and that's the wrong concept. Because the fact is that, planet does its
motion depending on its data. And based on that,
- Planet data be (modified) according to this planet motion (modification).
Example no. (2)
- The Diameter =12430 km
- There's no a planet in the solar group its diameter =12430 km, this number I have
invented it.
- The idea behind this diameter is, We try to know if Planets Data be created
independently from other planets data or dependent on each other.
o The (supposed) diameter 12430 km is the one middle rate between Venus
diameter (12104 km) and Earth diameter (12756 km).
o (Earth diameter / moon diameter) = (Jupiter diameter) / (12430 x π)
o Mars (24.1 km/s) moves during (12430 seconds) a distance = 300000 km =
light (0.3 mkm/s) motion distance for 1 second.
o Saturn (13.1 km/s) moves during (12430 seconds) a distance = 120536 km
= Saturn Diameter
- Planet diameter using as a period of time is a usual using in the solar planets
motion. by that, the value (12430 km or seconds) is similar to any other real planet
diameter… let's remember the following:
o Jupiter (13.1 km/s) moves during 10921 sec a distance = 142984 km (=
Jupiter diameter) where (10921 km = the Earth moon circumference)

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o Uranus (6.8 km/s) moves during 7510 sec a distance = 51118 km (=Uranus
diameter) where (7510 km = Pluto circumference)
o Pluto (4.7 km/s) moves during 10921 sec a distance = 51118 km (=Uranus
Diameter) where (10921 km = The Earth Moon Circumference)
o Pluto (4.7 km/s) moves during 51118 sec a distance = 2 x 120536 km
(=Saturn Diameter)
o Pluto (4.7 km/s) moves during 2 x 120536 sec a distance = 1.1318 mkm
(Jupiter Motion Distance During A Solar Day)
- We analyze the value (12430 km) to prove that, the solar planets creation data be
defined based on One Geometrical Design.
- That means, the planets data be controlled by one Equation only.
- The supposed diameter (12430 km) proves this idea. the data shows that, the value
(12430 km) is found geometrically in the solar system data but not created actually
- We should discuss in this paper the question (Why The Solar Planets Data Be
Created Based On One Geometrical Design?)

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3- The Sun Age Historical Proves
3-1 The Sun Circles The Earth
3-2 The Rate (1.0725)
3-3 The Sun Diameter Analysis
3-1 The Sun Circle The Earth
- The sun gives one face always to the Earth during the motion. although Earth
revolves around the sun a complete revolution, we always see the same face of the
sun, that tells the sun rotates with us giving The Earth The Same face always
- Can this motion refer to the Sun dependency on the period (365.25 days = Earth
orbital period)?
- Can that lead us to conclude, the sun be created after the Earth and because of that,
The Sun motion takes into consideration the period 365.25 days?
- Also
- The Sun Behavior is similar perfectly to the moon behavior, both give the same
face to the Earth during the motion.
- Why we accept that the moon be created after The Earth Creation but The Sun be
Created Before The Earth Creation? if the 2 behaviors are similar it may prove
both (the sun and the moon) be created after The Earth Creation.

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3-2 The Rate 1.0725
I- Data
(A)
Why These Distances Are Equal?
(1)
Saturn Orbital Distance = Saturn Uranus Distance
= Mars Orbital Circumference
= Pluto Neptune Distance
= Pluto eccentricity Distance
= Neptune Orbital Distance/π
= Uranus Orbital Distance /2
= Mercury Jupiter Distance x 2
(2)
Mercury Neptune Distance = Saturn Pluto Distance
Jupiter Pluto Distance = Uranus Neptune Circumference
Earth Neptune Distance = Mercury Saturn Circumference (error 0.5%)
(3)
Jupiter Mercury Distance = 2 Mercury Orbital Circumference
Jupiter Venus Distance = Venus Orbital Circumference (error 1.5%)
Jupiter Earth Distance = Earth Orbital Circumference (error 1.2%)
(Earth and Jupiter at 2 different sides from the sun)
(4)
Jupiter Mercury Distance = Mars Orbital Distance x π (error 0.6%)
Jupiter Uranus Distance = Venus Jupiter Circumference (error 0.8%)
Pluto Orbital Distance = Earth Orbital Circumference x 2π

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(B)
More Data
Why These Distances Are NOT Equal?
1. 0725
.
1
mkm
2.41
nce
Circumfere
Orbital
Moon
mkm
2.58
Motion
Daily
Earth
=
2. 1.0725
km)
(378500
radius
Eclipse
Solar
Total
km)
(406000
radius
orbital
Apogee
=
3. 0725
.
1
distance
Mercury
Jupiter
mkm
720.3
Distance
Orbital
Juppiter
mkm
6
.
778
= (Error 0.7%)
4. 1.0725
Distance
Venus
Jupiter
mkm
670
distance
Mercury
Jupiter
mkm
720.3
=
5. 1.0725
Distance
Earth
Jupiter
mkm
629
Distance
Venus
Jupiter
mkm
670
= (Error 0.6%)
6. 1.0725
mkm)
(1325.3
Distance
Venus
Sarurn
mkm)
(1433.5
Distance
Orbital
Saturn
= (Error 0.8%)
7. 1.0725
mkm)
(1205.6
Distance
Mars
Sarurn
mkm)
(1284
Distance
Earth
Saturn
= (Error 0.7%)
8. 1.0725
mkm)
(2644
Distance
Mars
Uranus
mkm)
(2872.5
Distance
Orbital
Uranus
= (Error 0.7%)
9. 1.0725
mkm)
(4495.1
Distance
Orbital
Neptune
mkm)
(4894
nce
Circumfere
Orbital
Jupiter
= (Error 1.5 %)
(10)
0725
.
1
T.
Axail
Earth
23.4
T.
Axail
Mars
25.2
T.
Axail
Mars
25.2
T.
Axail
Satrun
26.7
Tilt
Axail
Satrun
26.7
Tilt
Axail
Neptune
28.3
=
=
=

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II – Discussion
- The previous data shows that
- 50% of all distances in the solar system be equal one another, and
- 40% of all distances in the solar system be rated one another with the same rate
(1.0725)
- Why?
- The solar system motion analysis lead us to the conclusion that, the machine works
by equal distances feature (let's remember it in following)
- An Example
- Earth moves during its day period (24 h) a distance = Pluto motion distance during
its day period (153.3 h) (error 1%).
- We have observed this equality of distances.
- The periods of time are defined because they are defined by planets motions.
means, these periods of time aren't common periods but defined periods,
depending on planets motions.
- Means, these 2 distances be equal by some mentioned process. Because they
depend on 2 defined periods of time (depend on 2 planets motions).
- And,
- We have discovered that, this method is used by all solar planets motions. That
means, The equal distances method is used (thousands of times) in the solar
system motion.
- Because of this heavy using (50%) of all distances in the solar system to be equal
one another.
- That explains the data group No. (A) and makes it understandable.
- Means,
- 50% of all distances in the solar system are equal because of the equal distance
method Using.
- (The Equal Distances Method is discussed in details in point no.7)

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- Now
- The point needs explanation is the data group no. (B) where the distances are NOT
equal But Rated with 1.0725 (Why?)
- Why 40% of distances are rated with the same rate (1.0725)?
- Let's consider this question in following:
o The usual case is the equal distances as the data in Point no. (A), That
means, these rated distances were equal distances one another before and all
of them be effected by the rate 1.0725,
o Means,
o We have some historical order here, which is
o The distances were equal, but
o Some change caused these equal distances to be rated with (1.0725)
o And, 1.0725 = (100/100) + (7.25/100)
o We can conclude that,
o The distances were equal till The Sun Creation, and after the sun creation,
the sun obliquity on ecliptic (7.25 deg) caused the equal distances to be
rated with one another by the same one rate (1.0725).
o Means, the rate 1.0725 proves that, The Sun Is Created After All Solar
Planets Creation.
o One more feature supports this powerful argument, that
o The same rate (1.0725) is used for different distances. Because the sun
effects on all solar planets. That shows the rate (1.0725) must be related to
the sun because it's the same one rate. If this rate be belonged to any planet,
it will not effect on different distances equally because the sun only effects
on the planets equally. That shows the rate 1.0725 is belonged to the sun effect.

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3-3 The Sun Diameter Analysis
I-Data
1- Diameters
- (6792 km Mars Diameter) / (4879 km Mercury Diameter) =1.392
- (4879 km Mercury Diameter) / (3475 km the moon Diameter) =1.392 (1%)
- (71492 km Jupiter Radius) / (51118 km Uranus Diameter) =1.392
2- Distances
- (57.9 mkm Mercury orbital distance) /(41.4 mkm Venus Earth distance)=1.392
- (108.2 mkm Venus orbital distance) /(78.3 mkm Earth Mars distance)=1.392
- (149.6 mkm Earth orbital distance) /(108.2 mkm Venus orbital distance)=1.392
- (4267 mkm Mars Neptune distance) /(3061 mkm Saturn Neptune distance)=1.392
- (778.6 mkm Jupiter orbital distance) /(550.7 mkm Mars Jupiter distance)=1.392
- (550.7 mkm Mars Jupiter distance x 2) /(778.6 mkm Jupiter orbital distance) =1.392
- (5127 mkm Pluto Jupiter distance) /(3716 mkm Jupiter Neptune distance) =1.392
(error 1%)
- (5906 mkm Pluto orbital distance) /(4267 mkm Mars Neptune distance) =1.392
- (2872.5 mkm Uranus orbital distance) /(2094 mkm Jupiter Uranus distance) =1.392
3- Periods
- (243 days Venus Rotation Period) /(175.94 days Mercury day period) =1.392
- 2.5 deg (Saturn orbital inclination) /1.8 deg (Neptune orbital inclination) =1.392
- 1.8 deg (Neptune orbital inclination) / 1.3 deg (Jupiter orbital inclination) =1.392
- 5.1 deg (The moon orbital inclination) / 3.66 =1.392
4- The Sun Diameter
- 1.392 mkm (The Sun Diameter) = Venus Diameter 12104 km x 115.2
- 1.392 mkm (The Sun Diameter) = Mars Diameter 6792 km x 205.2
- 1.392 mkm (The Sun Diameter) = Neptune Diameter 49528 km x 28.3

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II- Discussion
- The data groups no. (1,2 and 3) show that,
- The rate 1.392 is used frequently among planets different data.
- Why? because
- The solar system is similar to one machine of gears and each planet is one gear in
it. because the machine moves one unified motion, the gears data should be in
proportionality with one another.
- Similar to that, the planets creation and motion data be created in proportionality
with one another. we will prove that in details in thus paper discussion.
- Based on this vision the solar planets data be created depends on one geometrical
design.
- This idea we have discussed before in the paper methodology, where the
(supposed) diameter 12430 km be defined geometrically and not created actually
- The Sun Diameter Can Have A Similar Discussion.
- The Sun Diameter Be defined geometrically before the sun creation.
- Because
- The machine depends on one geometrical design and each part should be created
in harmony with this geometrical design otherwise the machine can't work.
- We should notice that, the rate 1.392 is defined with the solar system creation
geometrically, Before the sun creation and also before the planets migration.
- This definition is done geometrically, so, the value (1.392) in the data is very
ancient. But the sun diameter (1.392 mkm) be created later.
- Let's discuss the data no. (4)

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Group Data No. (4)
- The sun diameter 1.392 mkm = Venus diameter 12104 km x 115.2 = Mars
diameter 6792 km x 205.2
- But
- 25.2 + 90 = 115.2 and 115.2 +90 =205.2
- 25.2 degrees = Mars Axial Tilt
And
- The sun diameter 1.392 mkm = Neptune diameter 49528 km x 28.3
- And 28.3 degrees = Neptune Axial Tilt
Discussion
- The data shows that, Venus, Mars and Neptune diameters are rated with the sun
diameter based on Mars axial tilt and Neptune axial tilt
- Means,
- We have 3 planets diameters are rated with 2 planets axial tilts based on the sun
diameter.
- More logical that, the sun diameter is created after the 3 planets diameters,
depending on their values, causing planets axial tilts be created in proportionality.
- The other option to create the sun diameter at first and the 3 planets diameters later
which can be option also.
- Shortly
- The sun diameter analysis can't provide a decisive conclusion for the sun creation
after all planets creation. but it provides a clear argument that the sun diameter is
created as similar to any planet diameter in proportionality with the planets
motions data. which disproves Newton description about the sun and solar planets
creation.
Notice (1)
- In kepler third law in which (D3
= P2
x constant), the constant used for the solar
planets orbital distance and periods should be = 25

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4- The Light Velocity 1.16 mkm/sec
4-1 Preface
4-2 Jupiter Motion Data proves the existence of the light velocity 1.16 mkm/sec
4-3 More Proves For The Light Velocity 1.16 mkm/sec
4-4 Jupiter Orbital Circumference Analysis
4-5 The Sun Rays Creation
4-1 Preface
- Let's suppose that,
- (There's a light beam its velocity =1.16 mkm/sec in the solar system)
- How to discover this light beam? Or how to prove its existence?
- My proves method is a simple one, which is
- The planets creation and motion data shows that, there's a light beam its
velocity=1.16 mkm/sec. that means, this data can't be created if there's no light
beam its velocity = 1.16 mkm per second.
- For example
- The 9 Solar Planets Orbital Circumferences Total = 100723 mkm
- This distance (100723mkm) can be passed in a period= a solar day period =86400s
- If , Be Passed By A light beam its velocity =1.16 mkm per second.
- This data isn't created by any pure coincidence, on the contrary, the solar group is
created based on a light beam its velocity =1.16 mkm /sec.
- Because of that, the value (1.16 mkm/sec) be found in the solar planets creation
and motion data.
- To make our analysis and discussion more understandable, we have to suppose the
following hypotheses
- (1st
hypothesis) the matter is created out of light. Specifically, the solar planets are
created from one light beam, its velocity =1.16 mkm/sec
- (2nd
hypothesis) (Distance = Energy)

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- By that we can conclude that, the light supposed velocity (1.16 mkm/sec) had
created the solar planets and their distances.
- Let's see as deep as possible the previous hypotheses…
- (1st
hypothesis) The Matter Is Created Out Of Light.
- The matter is born from a light beam. But the born matter isn't separated from its
parent, on the contrary, the light beam and the born matter both move together in
one unified motion. but they use Different Rates Of Time
- This hypothesis is very useful because, as we will see that, the planets motions use
different rates of time.
- Also many light motion features be discovered in Planets motions and we have no
explanation for them except through this hypothesis.
- The paper discussion will show that, this hypothesis can be concluded simply from
the planets creation and motion data.
- (2nd
hypothesis) (Distance = Energy)
- We have to accept this hypothesis. there are tenths of distances of the solar system
and even hundreds of the planets motions distances can be explained only if we
accept that (Distance =Energy). this hypothesis is a general rule be used by all
planets motions. Specially in Jupiter motion we will see that, the data depends on
this rule strongly.
- Jupiter orbital circumference is a piece of Gold Because it proves the existence of
the light supposed velocity (1.16 mkm/sec) by different ways.
- Now let's remember
- Why do we need to prove the existence of the light supposed velocity 1.16
mkm/sec?
- Because, while
- The sun rays velocity = 300000 km /sec
- But

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- The solar planets and their data be built of light beam its velocity 1.16 mkm/sec
- That proves The Sun Is Created After All Planets Creation And Motion.
- The idea became clear
- Shortly
- The light supposed velocity (1.16 mkm/sec) is registered in the solar planets
creation and motion data. because the planets matters and distances are created of
this light beam. By that, the planets data analysis will show this supposed velocity
(1.16 mkm/sec) simply and clearly because the planets data be built on it.
- On the other side, the sun rays velocity =0.3 mkm/sec
- That proves the sun is created after all planets creation and motion. Because the
light known velocity (0.3 mkm/sec) is a product from the light supposed velocity
1.16 mkm/sec.
- This method will provide a decisive proof for the claim that (The sun is created
after all solar planets creation) because the planets data (always) shows the
velocity 1.16 mkm/sec and the sun rays (always) be 300000 km/sec
- By that, we have a decisive proof for the claim (The Sun Is Created After All
Planets Creation And Motion)

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4-2 Jupiter Motion Data proves the existence of the light velocity 1.16 mkm/sc
I - Data
Group no. (I)
1.16 mkm per second x 500 seconds = 580 mkm
1.16 mkm per second x 671 seconds = 778.6 mkm
1.16 mkm per second x 629 seconds = 720.7 mkm (error 1%)
And
1.16 mkm per second x 5127 seconds = 5906 mkm (error 0.7%)
Group no. (II)
(1)
(2)
Group no. (III)
(3)
1.16 mkm per second x 2 x 86400 seconds =2 x 100733 mkm = (37100 mkm – 4900
mkm) x 2π = 28255 mkm + 2 x 86400 mkm
(4)
(28255 mkm – 680 mkm) x 2π = 2x 86400 mkm
But
2 x 100733 mkm = 28255 mkm + 2 x 86400 mkm

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II- Discussion
Data Group no. (I)
1.16 mkm per second x 671 seconds = 778.6 mkm
1.16 mkm per second x 629 seconds = 720.7 mkm (error 1%)
And
1.16 mkm per second x 5127 seconds = 5906 mkm (error 0.7%)
- Where
- 778.6 mkm = Jupiter Orbital Distance
- 671 mkm = Venus Jupiter Distance
- 629 mkm = Earth Jupiter Distance
- 720.7 mkm = Mercury Jupiter Distance
- 5127 mkm = Jupiter Pluto Distance
- 5906 mkm = Pluto Orbital Distance
- Data group no. (1) shows that, we deal with light motion, because the distances
values be used as a periods of time
- But
- It's a noticeable that, all distances between Jupiter and the inner planets be used as
periods of time. Also the distance between Jupiter and Pluto. later we will see that,
there's a geometrical reason behind this using and also Jupiter orbital
circumference will show many strange and surprised using of Data.
- Notice
- 500 seconds is required by the light known velocity (0.3 mkm/sec) to travel from
the sun to the Earth (149.6 mkm = Earth Orbital Distance)

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Data Group no. (II)
Equation no. (1)
(A)
- Equation no. (1) tells that, If there's a light beam its velocity =1.16 mkm/sec. this
light beam can pass a distance = 4900 mkm = Jupiter orbital circumference in a
period = 4224 seconds.
- We know that, Mercury Day Period =4222.6 hours.
- If 1 second of light motion be = 1 hour of Mercury Motion, this hypothesis will tell
us that, Mercury Day Period Is Defined By this motion of light supposed velocity
(1.16 mkm/sec).
- In more clear words
- The light supposed velocity (1.16 mkm/sec) travels a distance =4900 mkm and
through this motion it carried an energy to Mercury, and Mercury received this
energy and by that, this energy caused to create Mercury Day Period to be =
4222.6 hours.
- This is just an idea, let's try to know if it can be proved.
(B)
- The energy which is received by Mercury reach also to Venus and Earth, by that
we find the value (4224) effective on the 2 planets data, for example
- 4224 mkm = 2π x 671 mkm (Venus Jupiter Distance)
- And
- (5040 sec/4224 sec) = (928 mkm/778.6 mkm)
- Where
- 778.6 mkm = Jupiter orbital distance
- 928 mkm = Earth Jupiter distance (notice 928 mkm = 778.6 mkm +149.6 mkm)
- 5040 sec = Mercury Day Period be less 5040 seconds than 176 solar days

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- The data shows that, the value (4224 or 4222.6) is effective greatly in the three
planets motions data. and we will see more strange data concerning these 3 planets
motions as results for the light motion effect on them (as I claim).
Notice
- The light supposed velocity (1.16 mkm/sec) travels during 4224 s a distance =4900
mkm (Light Motion)
- But
- During Mercury Day Period (4222.6 h), Mercury moves a distance = 720.7 mkm
(Planet Motion).
- We suppose that 1 second of light motion = 1 hour of Mercury Motion
- So, we have 2 motions for comparison which are
- Light Motion (for the distance 4900 mkm)
- And
- Planet Motion (for the distance 720.7 mkm)
- Where
- 4900 mkm = 2π x 778.6 mkm (Jupiter orbital distance)
- And
- 778.6 mkm = 1.0725 x 720.7 mkm (Jupiter Mercury distance)
- We have studied the rate (1.0725) before,
- We should keep an eye on the rate (2π) in the next discussion. Because this rate
(2π) distinguish between light motion and planet motion.
- Let's summarize what we learnt till now…
- The light supposed velocity (1.16 mkm/sec) travels a distance = 4900 mkm =
Jupiter orbital circumference, and by this motion, the light provides energy for
Mercury by which Mercury Day Period (4222.6 h) is Created and the 2 planets
Venus and Earth motions be effected.
- This vision creates some relationship between Jupiter motion and Mercury day
period (Result no.1)

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Equation no. (2)
1.16 mkm / sec x 5040 seconds = 5848 mkm,
Where
- 5040 seconds = (Mercury Day Period needs 5040 s to be = 176 solar days)
- 5848 mkm = Mercury Pluto Distance
- Equation no. (2) tells that,
- If there's a light beam its velocity (1.16 mkm/sec), this light beam will travel
during 5040 seconds a distance = 5848 mkm = Mercury Pluto Distance
- I wish the argument is clear…
- We have to distinguish between the data (I supposed) and the real planets motions
data. because (I have supposed the light velocity 1.16 mkm/sec),
- But, Mercury Day period 4222.6 hours is a real data. and
- 5040 seconds is a real data
- And 5848 mkm is a real data.
- The hypothesis (There's a light beam its velocity =1.16 mkm/sec) gives the real
data new meanings and make them more effective in the planets motions
understanding.
- Let's look deeply in following:
- The light supposed velocity (1.16 mkm/sec) travels during (4224 sec) a distance
=4900 mkm = Jupiter orbital circumference, and by this motion the light provides
energy for Mercury by which Mercury Day Period is created.
- Means, Mercury day Period is Created By The Light Supposed Velocity Motion.
- Based on that,
- Light supposed velocity (1.16 mkm/sec) caused Mercury Day Period to be less
than 176 solar days with 5040 seconds.
- During this 5040 seconds, light supposed velocity (1.16 mkm/sec) travels a
distance =5848mkm= Mercury Pluto Distance

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- We deal here with some geometrical machine, the light supposed velocity (1.16
mkm/sec) created Some Method To Connect Mercury With Pluto!
- Let's try to support this meaning in following:
(Point No. 1)
o 5040 seconds =84 minutes
o Mercury moves during 84 solar days a distance = 346.6 mkm (error 0.8%)
o Mercury moves during 346.6 days a distance = 1419 mkm
o 346.6 days = The Nodal Year
o 1433.5 mkm = Saturn Orbital Distance (it's used as a period of time)
o 5848 mkm = Mercury Pluto Distance
o We suppose the using of different rates of time in planets motions (which
we should discuss later)
o This data tries to prove, some geometrical mechanism be found behind the
period 5040 seconds. We don't know that, because of 2 reasons (1st
, the
planets motions aren't independent from one another and by that they
exchange their periods of time in their motions) and (2nd
, the light motion be
accompanying with planet motion) that means, the solar planets motions is
consisted of a network of motions. and that shows the period 5040 seconds be
found based on geometrical interaction of motions between planets and light.
(Point No. 2)
o Mercury (47.4 km/sec) moves during (5040 seconds) a distance = 238896
km = 2x Saturn Diameter (error 1%)
(Point No. 3)
o Saturn (0.838 mkm/day) moves during (5848 days) a distance = 4900 mkm
o The distance (5848 mkm = Mercury Pluto distance) be used here as a period
of time (5848 solar days) by Saturn motion to pass a distance =4900 mkm =
Jupiter orbital circumference.

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o The geometrical mechanism based on which this data be created still need to
be discovered. But the data clearly shows, they are built on a geometrical
mechanism.
o Saturn be colored by blue to show that, the different motions aren't done in
random directions. On the contrary, we deal with directed motions. the
motions are connected with Saturn by different approaches. There are many
other data can support this meaning, for example …
o Pluto (4.7 km/sec) moves during (10921 sec) a distance =51118 km =
Uranus Diameter
o Pluto (4.7 km/sec) moves during (51118 sec) a distance = 2 x 120536 km =
Saturn Diameter
o Pluto (4.7 km/sec) moves during (2 x 120536 sec) a distance =1.1318 mkm=
Jupiter motion distance during a solar day
o Also
o ((2 x Saturn Diameter)/ (Pluto diameter)) = (5848 mkm/57.9 mkm) =101
o Where 5848 mkm is our distance
o 57.9 mkm = Mercury Orbital Distance
- What Conclusion Can We Reach By This Analysis?
- The light supposed velocity (1.16 mkm/sec) tried to connect Mercury and Pluto
motions. by doing that, the light has to depend on Saturn Motion. for that reason
Saturn is seen in different data in both sides (Mercury And Pluto)
- Please take care for planets real data. because my hypothesis is limited to one point
only tells that (there's a light beam its velocity =1.16 mkm/sec). I don't create any
other data. but
- the planets real data shows great harmony with my hypothesis. Where the velocity
(1.16 mkm/sec) can simply explain how the planets real data be created.

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Group no. (III)
Equation no. (3)
1.16 mkm per second x 2 x 86400 seconds =2 x 100733 mkm = (37100 mkm –
4900 mkm) x 2π = 28255 mkm + 2 x 86400 mkm
- Where
- 37100 mkm = Pluto Orbital Circumference
- 4900 mkm = Jupiter Orbital Circumference
- 100733 mkm = The 9 Solar Planets Orbital Circumferences Total
- 28255 mkm = Neptune orbital Circumference
- Equations no. (3) tells that,
- The different distance between Pluto orbital circumference (37100 mkm) and
Jupiter orbital circumference (4900 mkm) =32200 mkm
- If this distance be used as a radius of a circle, the circle circumference be =
distance can be passed by a light beam in a period = 2 solar days IF this light
beam velocity =1.16 mkm/sec.
- And
- This distance (32200 mkm x (2π)) = 2 x The Solar Planets Orbital Circumferences
Total.
- We have 2 interesting information here
- (1st
) Light motion be defined based on the solar day period
- (2nd
) The distance = 2 x The Solar Planets Orbital Circumferences Total.
- That tells there's a geometrical mechanism be found behind these distances
definition.
- Also simply we conclude that, light supposed velocity (1.16 mkm/sec) travels
during one solar day a distance = 100733 mkm = The 9 Solar Planets Orbital
Circumferences Total.
- But

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- The distance between Pluto and Jupiter can define double this value. That tells
these values be define geometrically. We here deal with some geometrical machine
- I wish the argument logic be clear
- I can't catch the geometrical mechanism based on which this data be created, but
the distances are divided and distributed based on geometrical mechanism, that
means the distances definition depends on A Geometrical Design.
Notice
- The solar day is an important period for the light motion, 2 Data prove that
(1st
Data)
- Light known velocity (0.3 mkm/sec) travels during a solar day (86400 sec) a
distance = 25920 mkm
- Because this is a light motion, we see this value as a period of time (25920 years=
The precession cycle)
- Also, the distance 25920 mkm still have effects on the solar planets motions. for
example, 25920 mkm = 17.75 mkm x 1461 days, where
- 17.75 mkm = The Solar Planets Daily Motions Distances Total (in addition to
the moon motion distance =2.57 mkm = Earth Motion Distance)
- means, the solar planets motions distances total during 1461 days be =25920 mkm.
- If 1461 days isn't a cycle, this data would be useless, but because it's Earth cycle
and defined by Earth motion (365 +365 +365+366) that shows the value 25920
mkm effects on the planets motions.
(2nd
Data)
- Light supposed velocity (1.16 mkm/sec) travels during a solar day (86400s) a
distance = 100733 mkm = The 9 Solar Planets Orbital Circumferences Total
- (9 planets =Mercury + Venus + Earth + Mars +Jupiter + Saturn + Uranus + Neptune + Pluto)
- The data tries to show that, the geometrical machine which uses light motion,
depends on the solar day as its period of time.

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Equation no. (3) (continued)
4900 mkm) x 2π = 28255 mkm + 2 x 86400 mkm
Where
- 28255 mkm = Neptune Orbital Circumference
- Equation no. (3) shows some very interesting data… let's analyze it in following:
- The different distance between Pluto orbital circumference (37100 mkm) and
Jupiter orbital circumference (4900 mkm) = 32200 mkm
- IF This distance be used as a radius of a circle, 32200 mkm x (2π) = 202000 mkm
- The value (202000 mkm) = 1.16 mkm/s x 2 x 86400 seconds
- And
- The value (202000 mkm) = 28255 mkm + 2 x 86400 mkm
- And we know
- The value (202000 mkm) = 32200 mkm x (2π)
- We have 3 distances defined based on this value (202000 mkm)
- How to understand that?
- We accept that (Distance = Energy)
- The energy is sent from Jupiter toward Pluto, the energy value was = (202000
mkm) (the energy may be sent in light beam form) but the planets motions shows
only (32200 mkm)
- The energy be reflected from Pluto to Neptune without change – this case is
similar almost to the light reflection – means Neptune received (202000 mkm)
- Neptune had consumed 14%of the energy to build its orbit but the rest energy
(86%) (= 2 x 86400 mkm) is sent from Neptune toward the inner planets.
- The energy is sent in 2 trajectories each has energy = (86400 mkm).
- The energy be = 2 x 86400 mkm and sent from Neptune to the inner planets
(specifically to Venus and Earth).
- Equation no. (4) gives more details

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Equation no. (4)
(28255 mkm – 680 mkm) x 2π = 2x 86400 mkm
- The energy is sent from Neptune toward Venus and Earth
- This equation uses Venus orbital circumference (680 mkm) for the (2 x 86400
mkm) that because the energy be sent in 2 trajectories each one has (86400 mkm),
one trajectory is sent to Venus (680 mkm) and the other is sent to Earth (940 mkm)
where the equations error can't be more than 1%.
- We should put equation no. (3) beside no. (4) to see as clear as possible, where the
planets distances are defined geometrically and distributed based on geometrical
design.
Equation no. (3) (continued)
4900 mkm) x 2π = 28255 mkm + 2 x 86400 mkm
- We have tried with this equation strongly, do we understand it?
- Many questions are still left behind, let's ask one of them in following:
- Why does the equation use the double Value?
- Let's remove the no. (2) from the equation what would happen?
1.16 mkm per second x 86400 seconds = 100733 mkm = (37100 mkm – 4900
mkm) x π = (28255 mkm)/2 + 86400 mkm
- That means,
- The equation uses the double value because of Neptune Orbital Circumference,
- Light supposed velocity (1.16 mkm/s) during one solar day (86400 s) travels a
distance = the 9 solar planets orbital circumferences total, and this energy can
provide one trajectory be sent to the inner planets carries (86400 mkm) but in this
case Neptune orbital circumference will not be created because the available
energy be enough for only (50%) of it.
- The light needed 2 solar days to provide enough energy to build Neptune orbital
circumference without change the other requirements.

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- Mars Migration Theory Tells that, Pluto was The Mercury Moon and had migrated
with Mars migration. This information answers why the light supposed velocity
tries to connect Mercury with Pluto, because almost they are created together.
- When Pluto had migrated, Neptune was occupied the orbital distance 5906 mkm.
But, Pluto had collided with Neptune and pushed it out its orbit. Forced Neptune to
be more near to the sun with orbital distance = 4495.1 mkm. And Pluto occupied
the orbital distance 5906 mkm. This fact is registered in Pluto data. where Pluto
eccentricity distance =1410 mkm= Pluto Neptune Distance.
- But, Neptune with its new orbital distance (4495.1 mkm) had no orbit.
- What does that mean?
- While Newton Theory tells us the planets motions are independent from one
another and be done depending on the sun mass gravity force. the fact is that, a
network of light motions be found under the planets motions. because the matter is
created out of light.
- The light motions network creates the planets matters and their motions distances.
In more clear words…..
- The light motions creates the map based on which the planets motions be done.
This map is drawn not by some ink but by the energy provided by the light motion
to be used by planet motion. that means, the light defined specifically tracks for
each planet motion.
- No planet moves neither independently nor without light motion accompanying
- That's similar to the railway
- The light motion creates the railways but the planets are the trains
- Neptune collision with Pluto put Neptune out of the railway, and the light has an
obligation to provide the required energy to build an orbit for Neptune motion.
- This analysis gives 2 proof for Pluto and Neptune collision, 1st
proof is the
distances equality, where Pluto and Neptune Distance = Pluto Eccentricity
distance.

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- And 2nd
proof is the energy consumed by Neptune (14%) to create Neptune Orbital
Circumference.
- That explains why Bode Law Couldn't predict Neptune orbital distance, because
it's created (additionally) on the original geometrical design to repair the planets
migration negative effects on the solar system motion. means, it's a distance not
designed geometrically with the original design. So the equations depend on the
original design couldn't see Neptune orbital distance.
- Please review Mars Migration Theory (See The References).
- Notice
- The planets motions analysis we discuss deeply in this paper to show that, the
planets real motions are different from Newton description about the planets
motions depends on The Sun Mass Gravity.
- Now, do we understand this hard equation no. (3), let's ask one more question!
- Why the double value = 2 x 100733 mkm (the 9 planets orbital circumferences
total)? why do we need the double value of the planets orbital circumferences?
- The data shows a historical order
- The planets orbital circumferences are created and completed before the machine
be ready to work
- The change in Neptune orbital circumference is found as an event occurred later.
It's a great change happened for the machine. And the designer had to find a
solution to repair the machine which is damaged seriously by the planets migration
so the repair process needed to use the double value to create a recovery for the
machine.
Notice
(202000 mkm)= (Jupiter Circumference 449791 km)2

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Notice
- 4495.1 mkm (Neptune orbital distance) = 78.3 mkm x 57.9 mkm
- = 108.2 mkm x 41.4 mkm
- = (149.6 mkm x 120 mkm)/4
- Where
- 57.9 mkm = Mercury Orbital Distance
- 108.2 mkm = Venus Orbital Distance
- 149.6 mkm = Earth Orbital Distance 41.4 mkm = Earth Venus Distance
- 78.3 mkm = Earth Mars Distance 120 mkm = Venus Mars Distance
-
- The data shows, the inner planets distances depend on (4495.1 mkm) because their
energies are sent from Neptune.
Comments
- Light motion is a continuum, that means, the previous data be connected with one
another. because of that the distance (202000 mkm) depends on Jupiter orbital
circumference (4900 mkm) which is our main player in the first 2 equations.
- The energy is not transported in pulses, but in continuum and in a light beam form,
by that, all equations and data be created depends on one another, that makes the
machine is so complex.
- One more difficulty is the light motion effects and features. Where the distances
can be used as periods of time and length contraction can be found frequently in
data. these features are discovered and proved hundreds of times but we can't catch
the velocity which creates these effects because no idea tell (Planet motion be
accompanying with light motion.)

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Notice
The rate (2π) distinguish light motion from the planet motion, we have seen it 3 times,
let's remember them in following
(1)
1.16 mkm/sec x 4222.6 seconds = 4900 mkm (Light Motion)
And 4900 mkm =(2π) x 778.6 mkm (Jupiter Orbital Distance)
But
Mercury moves during its day (4222.6 h) =720.7 mkm = Mercury Jupiter distance
But (778.6 mkm =1.0725 x 720.7 mkm) (Planet Motion)
(2)
1.16 mkm per second x 2 x 86400 seconds = (37100 mkm – 4900 mkm) x 2π
1.16 mkm/sec x 2 x 86400 sec = 202000 mkm (Light Motion)
But (37100 mkm – 4900 mkm) =32200 mkm (Planet Motion)
(3)
- 2x 86400 mkm = (28255 mkm – 680 mkm) x 2π (Light Motion)
- (28255 mkm – 680 mkm) =27575 mkm (Planet Motion)
- The data shows that, the rate (2π) distinguish between light motion and planet
motion.
Notice
- 5040 minutes x 0.99 = 4989 minutes
- 4989 minutes x 60 =299375 seconds
- Pluto (4.7 km/s) moves during 299375 seconds a distance = 1407060 km
- But
- 142984 km (Jupiter diameter) x π2
= 1411196 km (error 0.3%)
- Where
- 1411196 km is different from the sun diameter 1392000 km with (1.38%)
- Now

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- The only real data is (5040 seconds needed for Mercury day to be 146 days) and
we use this period as 5040 minutes.
- I try to show that, the data is interacted by complex forms and in every point of
data.
- This part of data should be added to mercury group to shows more harmony for the
data.
- Notice
o 5040 seconds =84 minutes
o Mercury moves during 84 days a distance = 346.6 mkm (error 0.8%)
o Where
o 346.6 days = The Nodal Year
o 1433.5 mkm = Saturn Orbital Distance (it's used as a period of time)

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More Discussion
- Can the previous investigation prove that, A Light Motion Be Accompanying With
A Planet Motion?
- I have provided 4 equations with some other data, can this data do the job? Can
The physicist simply remove our data and claim that they are found by some (pure
coincidences of numbers!)
- Imagine some people build their houses on a sea beach. What features these houses
have? If a visitor examines the house but doesn't see the sea beach, can he discover
that the houses be built on a sea beach. Of course yes. The sea water is simply
under their feet.
- The light motion is not limited for the previous 4 equations, The light motion
effect is seen in any planet data and in any planet motion.
- Because of that, the light motion is a fixed accompanying found in all data and be
proved by any data… let's use example
- We know that, light supposed velocity (1.16 mkm/s) travels during (4224s) a
distance = 4900 mkm. And by this motion the light supposed velocity caused
Mercury day period to be = 4222.6 hours. Also we know that, light supposed
velocity caused Mercury day period to be less that 176 solar days with a period
=5040 seconds.
- The light supposed velocity (1.16 mkm/s) did that, because during 5040 seconds, it
travels a distance = 5848 mkm (Mercury Pluto Distance). By that light supposed
velocity (1.16 mkm/s) creates a connection between the distances 5848 mkm and
4900 mkm, where Saturn uses (5848 mkm) as a period (5848 days) to move a
distance = 4900 mkm. Where we know that Mercury uses Saturn orbital distance
1433.5 mkm as a period (1433.5 days) to pass a distance = 5848 mkm (Mercury
Pluto distance). And tried to explain that data, I have suggested that, the light
supposed velocity (1.16 mkm/s) tries to connect Mercury with Pluto and the light
uses Saturn for this task.

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- This explanation can't prevent the data to be more extensive! Because
- 5848 mkm = 1.392 mkm x 4222.6
- Where
- 1.392 mkm = The Sun diameter
- 4222.6 h = Mercury Day Period
- 5848 mkm = Pluto Mercury Distance
- How to understand this data?! the point is that, the light supposed velocity (1.16
mkm/s) uses Saturn velocity to create The Sun Diameter, where
- 1.16 mkm = 1.392 x 0.838 mkm
- Here the sun diameter 1.392 mkm be used as a period of time (1.392 days) where
Saturn during 1.392 days moves a distance =1.16 mkm.
- This data is complex because
- Jupiter during (24.6 hours = Mars rotation period) moves a distance =1.16 mkm
- Also
- Jupiter orbital circumference (4900 mkm) be designed based on the distance 1.16
mkm.
- In the next point we analyze Jupiter orbital circumference (4900 mkm) may we
can explain how this data be created
- But, I want to say
- The universe of matter is similar to ships found on a sea
- The light motion is a network of motions or a sea of motions.
- What we see is the small part of the huge machine. The data simply proves the fact
- That shows what role this paper does.
- The paper with effort just can disprove Newton Theory of The Sun Mass Gravity.
Proving that, Light motion is found accompanying with planet motion and provide
the required energy.
- The paper also proves the light supposed velocity (1.16 mkm/s) existence, and
- The paper proves The Solar Planets Unified General Motion

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4-3 More Proves For The Light Velocity 1.16 mkm/sc
I - Data
(5)
1.16 mkm/sec x 50 seconds =58 mkm (Mercury Orbital Distance)
(6)
1.16 mkm/sec x 542 seconds =629 mkm (Earth Jupiter Distance)
(7)
1.16 mkm/sec x 3600 seconds =2 x 2088 mkm (Jupiter Uranus Distance)
(8)
(1.16 mkm/sec)2
x 2x 243 seconds = 654.9 mkm (Jupiter Saturn Distance)

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II- Discussion
Equation no. (5)
1.16 mkm/sec x 50 seconds =58 mkm (Mercury Orbital Distance)
- Equation no. (5) tells, light supposed velocity (1.16 mkm/sec) travels a distance
=58 mkm in a period = 50 seconds…
- We should notice that, Mercury orbital distance =57.9 mkm accurately
- Why does equation no. (5) refer to a significant fact?
- Because
- 58.65 days = Mercury Rotation Period
- We used before frequently the rate 1 mkm= 1 solar day and that means, the value
58.65 days can be = 58.65 mkm and by that, the distances 58.65 mkm and 57.9
mkm be equal with an error (=1.3%)
- That tells, light supposed velocity (1.16 mkm/s) motion during 50 seconds effect
on Mercury motion in 2 different data which are (57.9 mkm and 58.65 days).
- I have nothing to do if the physicist refuses my analysis and claims that the data be
created by (pure coincidence of numbers)… that because
- The light motion creates unknown effects on the planets motions. we can't discover
the geometrical rules for these effects but the data shows strongly them. That
means, the light motion effects on planets motion by some new geometrical rules
which we don't know. The geometry book is found inside the light nature. By that
the rules be unknown for us. but the data forces us to accept these effects.
- Why we accept the error (1.3%), where it's a great error and can effect
negatively on the data analysis?
- Because,
o Saturn Day period needs 1.3%, let's remember why
o Saturn (9.7 km/s) moves during its day period (10.7 h) a distance = 373644
km, where this distance is shorter than Saturn Circumference 378675 km
with 1.3%. by that the 2 process can be connected with each other.

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o That means (58.65mkm / 57.9mkm) =(378675 km / 373644 km)
o
o Why Saturn specifically be mentioned for this rate (58.65/57.9)?!
o Because
o Mercury (47.4 km/s) move during 5040s a distance = 2 x Saturn diameters
(error 1%). The data tells that, Mercury motion refers to Saturn Data.
o Please remember Saturn specific role effect on the distance between
Mercury and Pluto (5848 mkm) which we have analyzed in the previous
point.
o That shows we deal with one geometrical machine
- Notice
- The distance between Mercury and Venus =50.3 mkm
- If 1 second = 1 mkm, that makes the distance 50.3 mkm be belonged to our data
analysis (50s light supposed velocity needs to pass Mercury orbital distance)
- Notice
- 57.9 mkm =Mercury Orbital Distance
- But
- During 57.9 seconds, the light known velocity (0.3 mkm/s) travels a distance =
17.37 mkm
- Why this distance is important? Because Mercury moves a distance =17.37 mkm
during a period =366565 seconds but the outer planets diameters total =366565
km.
- Also 366565 sec = (101.8 hours), but
- Mercury Pluto Distance 5848 mkm / Mercury orbital distance 57.9 mkm = 101
- I don't know how this data be created… but this data be created depends on one
another. there one geometrical design be found behind this data.

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Equation no. (6)
1.16 mkm/sec x 542 seconds =629 mkm (Earth Jupiter Distance)
But
580 mkm = 1.0725 x 542 mkm
And
580 mkm = 1.16 mkm/sec x 500 sec.
- Let's move with this data step by step
o Light known velocity (0.3 mkm/s) needs 500 seconds to travel from the sun
to Earth (149.6 mkm)
o Light supposed velocity (1.16 mkm/sec) uses this same period 500 seconds,
and during this period passes a distance =580 mkm
o And
o 580 mkm = 1.0725 x 542 mkm
o Why the rate (1.0725) is used here? what is a geometrical effect of this rate
(1.0725) on planets motions? no available answer. Shortly 40% of all
distances in the solar system be rated one another with this rate (1.0725).
that tells, this rate using is a fact regardless any explanation.
o The distance 542 mkm be used as a period of time (542 s) (similar to all
distances between Jupiter and the inner planets in addition to Jupiter Pluto
distance)
o So
o 1.16 mkm/sec x 542 seconds =629 mkm (Earth Jupiter Distance)
o How can we understand this data?
o The period 500 s is used for light motion from the sun to Earth, this same
period (500 s) be used to define the distance between Earth and Jupiter (629
mkm).

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o That may explain why Earth orbital circumference 940 mkm = Earth Jupiter
distance 928 mkm (error 1.3 %)
o (notice 928 mkm =778.6 mkm +149.6 mkm, means, Earth and Jupiter
should be on 2 different sides from the sun to create the distance 928 mkm)
o This equality of distances is found because of using the same period of time
(500 s) in both directions (the sun and Jupiter)
Notice
o 928 mkm /542 mkm = 1.7
o The angle (1.7 deg) we have discussed in the moon orbital motion equation.
o This data shows that, there's a deep interaction behind this rate (928 mkm/
542 mkm). Because it effects on the earth moon orbital motion and causes
the moon to use the angle 1.7 deg in the equal (θ1 = θ0 +1.7 deg) (This
equation we discuss in The Moon Orbital Motion Description in point no.8
of this paper)

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Equation no. (7)
1.16 mkm/sec x 3600 seconds =2 x 2088 mkm (Jupiter Uranus Distance)
- Equation no. (7) tells that during 1 hour (3600 sec) light supposed velocity travels
a distance =2 x 2088 mkm
- Where
- 2094 mkm = Jupiter Uranus Distance (the difference with 2088 mkm is 0.3%)
- W notice clearly that, the light supposed velocity uses the distances between
Jupiter and the other planets which is a noticeable behavior, Why?
- But what's the value 3600 s (= 1 hour)? Why this value belongs to Jupiter motion?!
- Notice
- Light known velocity (0.3 mkm/s) travels during a period (2094 sec) a distance
=629 mkm (Earth Jupiter Distance).
- That means, the light known velocity (0.3 mkm/s) uses Jupiter Uranus Distance
(2094 mkm) as a period of time (2094 sec). And during this period the light travels
a distance = 629 mkm (Earth Jupiter Distance)
- The data shows that, Jupiter is found in light motion trajectory from Earth to
Uranus.
- That makes the 2 distances (Earth Jupiter distance and Jupiter Uranus distance)
consist together one trajectory of light motion. means geometrically they be found
together.
- Notice
- Light known velocity (0.3 mkm/s) travels during a period (720 sec) a distance
=216 mkm (Venus Orbital Diameter).
- Where 720.7 mkm= the distance from Mercury to Jupiter
- I don't know how this data be created. but I try to prove the theory of the railway.
The idea tells that, the light motions (by both velocities 0.3 mkm/s and 1.16
mkm/s) use the planets motions data in their creation of the motions network
which be found under the planets motion.

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Equation no. (8)
(1.16 mkm/sec)2
x 2x 243 seconds = 654.9 mkm (Jupiter Saturn Distance)
- Where
- 243 solar days =Venus rotation period.
- During (2 x 243 sec), the light supposed velocity (1.16 mkm /sec) travel a distance
= 563.8 mkm
- Again the distance 563.8 mkm be used as a period of time (563.8 sec),
- During (563.8 seconds) light supposed velocity (1.16 mkm/sec) travels a distance
=654.9 mkm = Jupiter Saturn Distance
- Notice
- During 654.9 seconds, light supposed velocity (1.16 mkm/s) travels a distance
=760 mkm
- But
- light known velocity (0.3 mkm/s). During 760 seconds travels a distance =227.9
mkm (= Mars orbital distance)
- I try to prove that, the planets motions depend on a network of light motions. by
that, the classical description of planet independent motion be refuted. Because
planet motion be found depends on light motions and accompanying with it.
- We note, the period (760 seconds) is used by light known velocity (0.3 mkm/s) to
define Mars New Orbital Distance (227.9 mkm) after its Migration.
- But
- We see clearly, the light supposed velocity (1.16 mkm/s) is the original light beam
by which all planets data be defined.
- The planets motion analysis will be discussed in this paper to prove that the planets
motions be integrated into One Unified General Motion, which disproves Planet
motion independence concept.

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4-4 Jupiter Orbital Circumference Analysis
I-Data
Group No. (1)
(A)
4900 mkm = 360 mkm +680 mkm +940 mkm +1433 mkm +1433 mkm
(B)
1.16 mkm/s x 4224 seconds = 4900 mkm
(C)
1.1318 mkm/s x 4222.6 days = 4780 mkm
(D)
4900 mkm = 449197 km x 10921 km
But
4846 mkm =1.392 mkm x 3475 km
(E)
9.7 km/s x 142984 seconds = 1386945 km (notice 1.392 mkm = the sun diameter)
(F)
4900 mkm = 0.384 mkm x 12756 km =0.406 mkm x 12104 km
(G) (please remember)
(37100 mkm – 4900 mkm) x 2π =28255mkm + 2 x 86400 mkm =2 x 1.16 mkm/s x 86400 s
Group No. (2)
(H)
(2 x The Sun Mass) = Jupiter Mass x 2094

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II-Discussion
- Jupiter orbital circumference is a very rich distance for discussion and analysis,
also it provides surprised using of data.
- There are 3 basic features of this distance makes it very specific distance, let's refer
to them in following:
- (1) The Distance 4900 mkm Is Defined By Many Planets Motions
- (2) The Distance 4900 mkm be in proportionality with The Sun Diameter.
- (3) The Distance 4900 Is Defined also by Light Motion Also.
- Let's analyze the distance 4900 mkm in following…
Equation No. (A)
4900 mkm = 360 mkm +680 mkm +940 mkm +1433 mkm +1433 mkm
(Error 1%)
- Where
- 360 mkm = Mercury Orbital Circumference
- 680 mkm = Venus Orbital Circumference
- 940 mkm = Earth Orbital Circumference
- 1433 mkm = Mars Orbital Circumference
- The data considers that, the Earth Moon Orbital Circumference around the sun
=1433 mkm = Mars Orbital Circumference.
- If we accept this idea, the data will give a clear meaning. Which tells that (Jupiter
orbital circumference = the inner planets orbital circumferences total)
- Then we have to ask.
Why does Jupiter Orbital Circumference=
= The Inner Planets Orbital Circumferences Total?
- More data can help our analysis,

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(I)
- We accept that, Jupiter orbital circumference 4900 mkm be passed by a light
supposed velocity (1.16 mkm/s) in a period = 4224 seconds. And by this motion
the light caused to create Mercury day period (4222.6 h) where we accept that 1
second of light motion be = 1 hour of Mercury motion.
- Venus and Earth Data also be effected by (4224), Let's remember their data
o 4224 mkm = 2π x 671 mkm (Venus Jupiter Distance)
o And
o (5040 sec/4224 sec) = (928 mkm/778.6 mkm)
o Where
o 778.6 mkm = Jupiter orbital distance
o 928 mkm = Earth Jupiter distance (notice 928 mkm= 778.6 mkm +149.6 mkm)
o 5040 sec = Mercury Day Period be less by 5040 seconds than 176 solar days
(II)
o 778.6 mkm = 1.0725 x 720.7 mkm (Mercury Jupiter Distance)
o 720.7 mkm = 1.0725 x 671 mkm (Venus Jupiter Distance)
o 671 mkm = 1.0725 x 629 mkm (Earth Jupiter Distance)
o 778.6 mkm = Jupiter Orbital Distance
(III)
o 1.16 mkm /sec x 500 sec = 580 mkm
o 1.16 mkm /sec x 580 sec = 671 mkm (Venus Jupiter Distance)
o 1.16 mkm /sec x 671 sec = 778.6 mkm (Jupiter Orbital Distance)
o 1.16 mkm /sec x 629 sec = 720.7 mkm (Mercury Jupiter Distance) (1%)
- The data shows, the distances between Jupiter and the inner planets are defined
based on Geometrical Calculations, because of that all distances are rated with
(1.0725) and (1.16).
- Means, these planets motions are not independent motions, on the contrary they
are (complementary motions) and be created based on One Geometrical Design.

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- The previous data shows a complex geometrical machine behind. More analysis
provides even more complex interactions for example
- (778.6 mkm/ 629 mkm) = (720.7 mkm/580 mkm)
- These distances also we have used in the previous data. that means, the distances
between Jupiter and the inner planets be created by some geometrical system
makes these distances be in proportionality to one another mutually.
- Means,
- Not just, Jupiter orbital circumference be = the inner planets orbital circumferences
total, but also all used distances be created in proportionality with one another.

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Equation No. (B)
1.16 mkm/s x 4224 seconds = 4900 mkm
- This equation we know perfectly
- Light supposed velocity (1.16 mkm/s) travels during 4224 seconds a distance =
4900 mkm = Jupiter Orbital Circumference
- But
- This equation has another reading, let's try with it in following
(1)
o Jupiter (13.1 km/s) moves during 24.6 h a distance = 1.16 mkm.
o Where (24.6 hours = Mars rotation period)
(2)
o Jupiter orbital circumference (4900 mkm) be divided on the distance 1.16
mkm and the rate 4224 (or 4222.6).
o Means, if each 1 hour of Mercury Day period be = 24.6 hours, based on that,
Jupiter during the period (4222.6) x (24.6 h) moves a distance =4900 mkm =
Jupiter orbital circumference.
o Can that refer to some interaction of motions among the 3 planets (Mercury,
Mars and Jupiter)? Of course yes, this fact is proved in the planets unified
motion discussion in this paper (point no.5 of this paper) where huge
number of data shows clearly the motions interactions among the 3 planets.
(3)
o Why Jupiter moves 1.16 mkm in a period 24.6 hours? The planets machine
is so complex. We understand that, light supposed velocity (1.16 mkm/s)
motion caused the motions interactions among the 3 planets by its energy.
because the planets are created and moving by this energy.
o But geometrically the distance 4900 mkm depend on (1.16 mkm and 4224)
where the distance 1.16 mkm depends on (24.6 hours). That causes the
interactions between the 3 planets motions.

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(4)
o I want to say that,
o We have 2 pictures for the same scene. As if we use 2 covers for the same
place. One cover is put on another. the 2 covers are equal in length. But they
are different in natures. Similar to that, we have equal distances (4900 mkm)
be passed by (light motion) and by (planet motion). the motions create
interactions in data. while we don't see the light motion but we see only the
planet motion. but we discover the interactions which are done as a result
for light motion effect on planet motion.
(5)
o The real data causes even more confusion, because light moves 1.16 mkm in
one second. but Jupiter moves 1.16 mkm in 24.6 hours, by that the simple
interactions which depend on (1 second) should be explained in some
complex form based on the period (24.6 h) and then we have to ask (why
Jupiter uses Mars rotation period 24.6 h?). Because we know that some
relationship is found between Mercury Day Period and Jupiter orbital
circumference. And now we have a relationship between Jupiter orbital
circumference (4900 mkm) and Mars rotation period (24.6 h) through the
distance 1.16 mkm. That simply creates a relationship (or a proportionality)
between Mercury day period and Mars rotation period! (why?)
o Notice/
o (Mercury Day period 4222.6h) / (Mars rotation period 24.6 h) =170 (error 1%)
o Mercury Mars Distance = 170 mkm
o But
o (1407.6 h/ 24.6 h) = 2 x ( (4900 mkm) /(170 mkm)), where
o 1407.6 h = Mercury Rotation Period
o 24.6 h = Mars Rotation Period
o 4900 mkm = Jupiter Orbital Circumference

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o I wish the argument logic is clear.
o Jupiter moves a distance 1.16 mkm during a period (24.6 h =Mars Rotation
Period) because (1st
, Jupiter motion and Jupiter orbital circumference 4900
mkm have a relationship with Mercury Day Period). And (2nd
, Mercury
motion has a relationship with Mars Motion as the previous data refers).
o We deal with a machine of gears, the main motor is the light motion and the
planets are gears, because of that, their data be in proportionality with one
another according to the motions interactions.

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Equation No. (C)
1.1318 mkm/s x 4222.6 days = 4780 mkm
- Where
- 1.1318 mkm /day = Jupiter motion distance during a solar day
- 4222.6 hours = Mercury Day Period
- Equation (C) supposes that 1 hour of Mercury Motion = 1 day of Jupiter motion.
by that, Jupiter uses Mercury Day Period as 4222.6 Solar Days
- During 4222.6 days Jupiter moves 4780 mkm. But during 4331 days Jupiter moves
4900 mkm.
- That means, the period 4222.6 days is incorrect period, because if we want to
measure the distance 4900 mkm we should use the period 4331 days
- But
- (4222.6 days /4331 days) = (654.9 mkm/ 671 mkm)
- Where
- 654.9 mkm = Jupiter Saturn Distance
- 671 mkm = Jupiter Venus Distance
- That tells the rate (4222.6 /4331) is defined geometrically and by that, the distance
4780 mkm which is less than 4900 mkm by 2.5% may refer to the distance 4846
mkm (with error 1.3%)
- Based on that
- Equation no. (C) tells, Jupiter moves during 4222.6 days a distance = (4780 mkm)
= 4846 mkm (the inner planets orbital circumferences total) (error 1.38%)
- Equation no. (C) can refer to that, 1 hour of Mercury Motion be = 24 hours of
Jupiter motion.
- This is the same rate of Uranus where 1 hour of Mercury Motion be =24 hours
of Uranus motion.
- Be we know that, 1 h of Mercury motion = 9.18 h of Pluto motion

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- Based on that
- 1 h of Pluto motion = 2.62 h of Uranus Motion = 2.62 h of Jupiter Motion
- We should discuss that in details in the planets unified motion discussion, we need
this data here because
- The rate 2.62 is so specific for both planets
- Uranus Circumference x 2.62 = Uranus motion distance during its day period
- And
- Jupiter Circumference x 2.62 = 1.16 mkm (error 1.4%)
- I try to show that, the distance (1.16 mkm) is found again under some new data. it's
not some random number found by chance in Jupiter data. it's a basic distance
based on which Jupiter motion and orbital circumference be designed, because of
that we face this distance (1.16 mkm) in any place we move.
- The negative point is that, we can't discover the geometrical design based on which
this distance 1.16 mkm be defined. For that reason, we meet this distance (1.16
mkm) frequently but couldn't catch the machine which produces it.

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Equation No. (D)
4900 mkm = 449197 km x 10921 km
But
4846 mkm =1.392 mkm x 3475 km
- Where
- 449197 km =Jupiter Circumference
- 10921 km = The Moon Circumference
- And
- 1.392 mkm = The Sun Diameter
- 3475 km = The Moon Diameter
- 4846 mkm = The Inner Planets Orbital Circumferences Total
(4846 mkm = 360+680+940+1433+1433)
- Equation (D) tells, the multiplication of the sun diameter and the moon diameter =
accurately the value (4846 mkm)
- But
- The multiplication of the Jupiter Circumference and the moon Circumference =
accurately the value (4900 mkm)
- Can that refer to some relationship between the distance 4900 mkm and the sun
creation?
- Let's move step by step in following:
o Jupiter diameter x π2
= 1411196 km which is different from the sun diameter
1392000 km with the rate (1.38%)
o But
o Saturn (9.7 km/s) moves during 142984 seconds a distance = 1386945 km
(notice 1.392 mkm = the sun diameter and the difference 0.4%)
o Can this data tell (the sun is created in proportionality with Jupiter diameter)

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o We have 2 reasons for this conclusion. Because (1st
) the data refers to a
proportionality between the sun and Jupiter diameter and (2nd
) the data
refers to proportionality between the sun and Jupiter orbital circumference.
That shows 2 basic data be in proportionality with the sun diameter.
o The second player is the Earth moon
o The moon circumference (10921 km) be in proportionality with Jupiter
orbital circumference 4900 mkm based on Jupiter circumference (449197
km).
o And
o Jupiter (13.1 km/s) moves during 10921 sec a distance = 142984 km =
Jupiter diameter.
o I don't need to prove that, this data be created based on geometrical system.
Because the data proves that strongly and clearly. I need to discover this
geometrical system based on which this data be created.
o Shortly
o Jupiter is the basic player found on other side and effects on the sun creation
process. Where this event is happening, Jupiter adopted the Earth moon as
its own son and uses its data as part of Jupiter own data. as a result the earth
moon (small planet) has some chance to effect on the sun creation data!
o Again
o Why We See The Sun Disc =The Moon Disc? Because
o (The sun diameter / the moon diameter) = (Earth orbital distance/ Earth
moon Distance)
o Why The Diameters Rate = The Distances Rate?
o Because all players are created in proportionality with 4900 mkm (Jupiter
orbital circumference).
o The data can't be created by any pure coincidence. The fact can be seen if
we try to answer the question (how the matter is created?)

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Equation No. (E)
4900 mkm = 0.384 mkm x 12756 km =0.406 mkm x 12104 km
- Where
- 0.384 mkm = the moon orbital distance
- 0.406 mkm = the moon orbital Radius At Apogee
- 12756 km = Earth Diameter
- 12104 km = Venus Diameter
- Equation no. (E) shows, the distance 4900 mkm controls the data around the moon
motion.
- Earth and Venus Diameters must be ancient and aren't changed. That tells the
value (4900 mkm) use the 2 planets diameters as references to define the moon
motion range. By that the moon orbital distance be =0.384 mkm depends on Earth
diameter and the moon apogee radius be 406000 km depends on Venus diameter.
- The data shows these meaning but no geometrical mechanism be discovered to
answer how this data be created in proportionality with one another.
- More data can support the same meaning for example
- This data tells that (the apogee orbital radius 406000 km be defined by Venus),
more data supports this same meaning beefcake (406000 km = 3475 km x 116.75),
where 3475 km = The Moon Diameter and 116.75 days = Venus Day Period.
- The data gives the meaning but no geometrical mechanism be discovered.
- Shortly
- The distance 4900 mkm controls the sun creation process and the moon
orbital motion definition.
- The distance 4900 mkm uses Earth and Venus diameters as references to
define the moon orbital distance and its apogee radius.

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- Notice
- 1433 mkm =550.7 x 2.5986 mkm
- 2.598 mkm (the moon displacements total during 259.53 days),
- 550.7 mkm= Mars Jupiter Distance,
- 1433 mkm = Saturn Orbital Distance
- This data tells why the data considers the moon orbital circumference round the
sun be = 1433 mkm = Mars orbital circumference and Not be =940 mkm = Earth
orbital circumference.
- The data shows that, the Earth moon is the son of the inner planets. The moon isn't
belonged to the Earth alone where Venus effects greatly on the moon apogee
radius definition on one side where Mars still effect on the moon motion and
causes its orbital circumference around the sun be considered =1433 mkm = Mars
orbital circumference.
- The geometrical machine based on which this data be created has answers for the
question how this data be created.
Comments
- The distance 4900 mkm defines the moon diameter and its orbital motion range
- And
- The distance 4900 mkm controls the sun creation process and defines the sun
diameter.
- Because of that, the sun and moon data be created in proportionality as we have
discussed before.
- But
- Is the aforementioned data sufficient for this conclusion? Suppose (4900 mkm =
the sun diameter 1.392 mkm x 3475 km the moon diameter) can this data be a
sufficient for this heavy conclusion? Let's discuss the next data to answer this
question.

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Group No. (2)
Equation No. (H)
(2 x The Sun Mass) = Jupiter Mass x 2094
Where
2094 mkm = Jupiter Uranus Distance
- How to make the rate 2094 be = the distance 2094 mkm?
- Geometrically, this process depends on Jupiter motion. because Jupiter diameter
142984 km = (1 million km/7) where Mercury orbital inclination = 7 degrees
- That means, the interaction of motions between Jupiter and Mercury can produce
the distance 1 mkm based on geometrical methods.
- By that, the rate 2094 x 1 mkm = 2094 mkm (Jupiter Uranus Distance)
- Why do we need this data?
- I try to prove that, the sun is created by an effect of Jupiter motion. We have seen a
proportionality of data between the sun diameter and the distance 4900 mkm
(Jupiter orbital circumference) and also between the sun diameter and Jupiter
diameter. and this data shows a new proportionality between the sun mass and
Jupiter mass.
- Equation no. (I) shows that, Jupiter Uranus Distance has some role in the sun
creation (or perhaps Jupiter Uranus Motions Interaction does this role)
- Why does The Equation Use 2 Values Of The Sun Mass?
- We remember, Jupiter energy which is sent to Pluto used (2 solar days) where,
light supposed velocity (1.16 mkm/s) travels during one solar day a distance = the
solar planets orbital circumferences total, but Jupiter energy uses 2 solar days
which provides energy = 2 x the solar planets orbital circumferences total
- This is happened because of Neptune orbital circumference as we have discussed
before. So if the used energy be double value, and the matter is created of energy,
that caused the sun mass be used in double value.

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- Based on different data, Jupiter motion shows its role in the sun creation.
- Jupiter Uranus Distance shows specific role in this process.
- The difficulty is that, We can't discover the geometrical mechanism by which this
process is done or this data be created. the data tells what's happened but doesn't
tell how that's happened. By that the argument provides clear meanings but not
clear mechanism of motions.
- One more important we need to remember is the following
- 90000 mkm = 2872.5 mkm (Uranus orbital distance) x (97/3.1)
- Where
- C2
= 90000 mkm (if the period of time be = 1 second)
- 97 deg = 97.8 deg (Uranus Axial Tilt) – 0.8 deg (Uranus orbital inclination)
- 3.1 deg = Jupiter Axial Tilt
- We need this data because the sun rays be created from the value (C2
)
- The data shows that, the interaction between Uranus and Jupiter effects on the sun
creation process.
- This data supports the meaning we get from the analysis of the distance 2094 mkm
(Jupiter Uranus Distance)
- Notice
- The machine depends on layers, So, the rate (97/3.1) uses the value 97
- But, other rates can use different data for example
- (97.8 deg /3.1 deg) x 2872.5 mkm = 90560 mkm
- (where 90560 days = Pluto Orbital Period)
- Also
- (98.6 deg /3.1 deg) x 778.6 mkm x 2 = 49528 mkm
- Where
- 98.6 deg =97.8 deg (Uranus axial tilt) + 0.8 deg (Uranus orbital inclination)
- 778.6 mkm = Jupiter orbital distance and 49528 km = Neptune diameter.

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The Conclusions
- Jupiter orbital circumference 4900 mkm effects greatly on the machine motion
- The distance 4900 mkm defines the moon diameter and its motion range and by
that Jupiter motion effect on the moon motion be defined clearly
- Also
- The distance 4900 mkm defines the sun diameter 1.392 mkm, and that be done
through interaction with Jupiter diameter.
- These effects are found by the energy provided for the sun rays creation process
- This energy is seen through the interaction between Jupiter and Uranus motions.

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4-5 The Sun Rays Creation
- Let's Summarize The Sun Rays Creation Idea In Following:
(Point No. A)
o The Solar Planets Move One Unified General Motion. This Idea we discuss
and prove clearly in this paper.
o The planets unified general motion causes to unify the planets velocities in
one unifies velocity = the planets velocities total.
o The 9 planets velocities total =176 km/sec,
o But
o The Earth moon is a player and its velocity should be added, where the
moon velocity be considered = Earth velocity because they aren't separated
from one another through their motions.
o The 10 planets velocities total be 176 +29.8 =205.8 km/s
o Based on this velocity (205.8 km/s) the sun rays be created
(Point No. B)
o 10921 km (The Moon Circumference) x 86400 Seconds = 940 mkm
o This Equation tells. If Earth revolves around the sun a complete revolution
(=940 mkm = Earth Orbital Circumference) in one solar day only (86400
sec), in this case, the moon circumference (10921 km) will be equal the
Earth motion distance during 1 second.
o But, because
o Earth revolves around the sun in one year (=365.25 days), so this equation
may refer to a rate of time is used by The Sun herself.
o Let's use this idea as a hypothesis. where
o 1 Day Of The Sun Motion = 365.25 Days Of Earth Motion
o We suppose that's The Sun Rate Of Time

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(Point No. C)
o The velocity (205.8 km/s) passes during a solar day (86400 s) a distance
=17.75 mkm
o 1 day of Earth motion = 237 seconds of the sun motion.
(This value depends on our hypothesis)
o Now
o The distance =17.75 mkm and the time =237 seconds what's the velocity?
o 75000 km/s = (a quarter Light Velocity) = 0.25 C
o But
o Earth has a cycle of 4 years (1461 days = 365 +365 +365 +366)
o Based on one year, the velocity be (0.25 C)
o And
o Based on the cycle (4 years), the velocity (0.25C) became (C light velocity)
o Based on this explanation the sun rays be created.
(Point No. D)
o There's one more method to create the sun rays
o 0.25 C x 4 C = C2
o Where
o The velocity 0.25 C is produced already in the previous discussion
o We need only the value (4C) to perform this equation
o Jupiter motion enjoys by light motion supposed velocity (1.16 mkm/s) this
value is very near to our required value (4C)
o Light supposed velocity travels for 1 second and passed 1.16 mkm
o And
o Earth rotates around its axis one per solar day and move a distance = its
circumference =40080 km in a solar day
o If 1 solar day of Earth motion be = 1 second of light supposed velocity
motion.

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o Based on that, the distances can be added
o 1.16 mkm + 40080 km = 1.2 million km = 4C
o By that the equation works
o 0.25 C x 4 C = C2
o That explains why, Jupiter and The Moon data are the 2 basic players in the
sun data definition. Because the sun creation depends on Earth and Jupiter
motion. in addition to Uranus motion which is seen in the Earth moon
motion.
o The data explains how the sun rays be created
(Point No. E)
o The rate of time (1 solar day of planet motion = 1 second of light motion) is
the original rate of time in the solar system. We should refer to that in the
planets unified general motion discussion.
o The idea is that, the light motion for 1 second provides the required energy
for a planet to move one solar day, because the light motion depends on the
solar day as we have discussed. By that the planets divides this great rate of
time (1 sec = 86400 sec) on their motions to work as a great clock and
produce this rate by their Unified General Motion.
o The basic part (1 sec =365.25 sec) be between the Earth and the Sun motion.

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Extensive Discussion
- Why Does The Previous Investigation Prove The Claim?
- The claim tells that,
- The Sun Is The Solar System Last Created Piece. And that means, the sun is
created after All Planets Creation And Motion.
- If this fact can be proved, it will disprove Newton Theory of The Sun Mass
Gravity decisively.
- How to prove that the sun is created after all planets creation and motion?
- In addition to the historical proves there's one basic proof which is
- The sun rays velocity be = 300000 km
- While
- The solar planets matters and distances be created out of light beam its velocity
=1.16 mkm/sec.
- As a result, I have analyzed the planets data to prove that, this data be created
based on a light beam its velocity =1.16 mkm/sec
- After this analysis, we have to describe how the sun rays be created and the
previous data provides this description.
- Now
- Why Does This Analysis Provide A Sufficient Proof?
- The proof sufficiency depends on the arguments and discussions logic
- The discussions used hundreds of the planets data and put them in some form to
prove some idea. I can create the idea but can't create the data. that means if the
data be in harmony with the idea that supports the proof sufficiency.
- We have used hundreds of data in different discussion, if the discussion logic be
straight and the data be in harmony with it that proves the claim clearly
- The point is that, we searched for the rules based on which this data be created. so
as much as the used data be in harmony with these rules that prove these rules
sufficiency.

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- For example
- I claim (1 day of the sun motion = 1 year of Earth motion). this idea we have
accepted as a hypothesis and used it based on that
- But
- This idea is created because of the moon circumference equation (10921 km x
86400 seconds =940 mkm). Means, we have some data refer to this hypothesis.
- So we have used this idea as a hypothesis.
- We have found that, the data be in harmony and produce a velocity = (0.25 C)
- This velocity be created as a result for the hypothesis we suggested because of the
moon circumference
- But
- Earth Cycle (4 years) can change this velocity (0.25C) into ( 300000 km/s)
- I try to show that, w don't create the data
- We Rearrange The Data In New Positions Relative To One Another
- This is the basic method of the proof.
- Then we find that
- Jupiter (again) provides us a chance to create the value (C2
) (which can be a
source of the sun rays energy)
- So we used the velocity 1.16 mkm/s which we have learnt from Jupiter motion
data and added it to earth circumference to produce the required value (4C)
Notice
- The planets unified general motion supports the proof with powerful arguments
which makes the proof more understandable and trustee.

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5- The Solar Planets Move One Unified General Motion
5-1 The Planets Unified General Motion Description
5-2 The Solar Planets Motions Are Complementary One Another
5-3 The Solar Planets Move An Unified Motion (A Team Motion)
5-1 The Planets Unified General Motion Description
- I suppose that (The Planets Motions Create One Unified General Motion)
- This hypothesis tells the planets motions be similar to Train Carriages Motion
- Also It tells the planets motions be similar to Chess Pieces Motions
- The hypothesis discovers One Law controls the solar system motion and data.
- The planets unified general motion forces each planet motion to be complementary
with other planets motions to perform The Unified General Motion. as a result,
The Planet motion be An Obligatory Motion.
- The Solar Planet creates its data to be in consistency with its motion.
- The planet can't change its motion, but can change its data to be in consistency
with its motion. And the planet data be created in consistency with its motion.
- Because the planet motion be complementary with other planets motions.
- The planet data be created complementary with other planets data
- Based On This Vision
- The solar planets data be created complementary to other planets data and based
on that the planets data be created depends on One Geometrical Design.
- And
- The Planets Creation And Motions Data Be Controlled By One Equation Only
- The hypothesis gives a different vision from the planets classical description.
because its tells, (The Solar Planet Data Be Created Based On Geometrical
Calculations And Rules). The classical description tells planets data be created by
random process and without geometrical reasons behind.

The Sun Is The Solar System Last Created Piece (Newton Was Wrong) (Revised)

The Sun Is The Solar System Last Created Piece (Newton Was Wrong) (Revised)

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