ISHANT JAIN, MALHAR SHAH,MEET DOSHI
2 3 −5
1 2 4
6 5 0
MEANING: -
m x n real numbers arranged in m rows and n columns and enclosed by a pair of
brackets is called m x n matrix.
TYPES
OF
MATRIX
Row Matrix
Column Matrix
Null Matrix/ Zero Matrix
Square Matrix
Diagonal Matrix
Scalar Matrix
Identity Matrix or Unit Matrix
Equal Matrix
Negative Matrix
Upper Triangular Matrix
Lower Triangular Matrix
Symmetric Matrix
Skew Symmetric Matrix
Sr.
No.
Type of Matrix Meaning Example
1. Row Matrix  A matrix consisting of a single row.
 Also called as row vector.
1 2 3
2. Column Matrix  A matrix consisting of a single column.
 Also called as column vector.
1
2
3
3. Null Matrix  All the elements are zero.
 Also known as zero matrix.
 Denoted by “O”.
0 0
0 0
4. Square Matrix  Matrix having same number of rows and columns.
 It can also be written as An.
2 3
4 5
2 1 3
1 6 2
5 2 4
5. Diagonal Matrix  All elements are zero except main or principal diagonal. 2 0
0 5
3 0 0
0 4 0
0 0 1
6. Scalar Matrix  All the diagonal elements are same. 3 0
0 3
2 0 0
0 2 0
0 0 2
7. Unit Matrix  A scalar matrix in which each diagonal element is 1.
 Also called “Identity matrix”.
 Denoted by In.
 Every unit matrix is a diagonal matrix and also a scalar matrix.
1 0
0 1
1 0 0
0 1 0
0 0 1
Sr.
No.
Type of Matrix Meaning Example
8. Equal Matrix  Two matrices having the same order.
 Each element of A= Corresponding to the element of B
A=
2 3
1 0
B=
4
2 9
2 − 1 0
9. Negative Matrix  Replacing all the elements with its additive inverse.
A=
3 −1
−2 4
5 −3
B=
−3 1
2 −4
−5 3
10. Upper Triangular
Matrix
 A square matrix in which all elements below the principal
diagonal are zero.
1 3 7
0 2 8
0 0 7
11. Lower Triangular
Matrix
 A square matrix in which all elements above the principal
diagonal are zero.
1 0 0
3 6 0
2 5 7
12. Symmetric Matrix
 A square matrix having aij=aji
2 1 3
1 6 2
3 2 4
13. Skew Symmetric Matrix
 A square matrix having aij= -aji
2 1 3
−1 6 2
−3 −2 4
a12 =a21
a13 =a31
a23 =a32
a12 =-a21
a13 =-a31
a23 =-a32
1. Matrix Addition
2. Matrix Subtraction
3. Scalar Multiplication
4. Matrix Multiplication
4 6
0 2
3 2
8 5
7 8
8 7
9 7
5 8
5 3
0 2
4 4
5 6
4 3
6 9
12 09
18 27
2 5
7 1
7 5
-3 0
-1 10
46 35
 Determinant is a scalar value that is calculated from a matrix.
 It can only be calculated for a square matrix.
 It is denoted by ∆ (Delta).
 Calculation For 2X2 Matrix
1 3
5 6
(1 x 6) –
(3 x 5) - 9
03 05 02
04 00 01
−2 06 10
3{(0 X 10) – (1 X 6)} –
5{(4 X 10) – (-2 X 1)} +
2{(4 X 6) – (-2 X 0)}
- 180
MEANING: -
The minor of a element in a matrix is the determinant obtained by deleting the row
and the column in which that element appears.
 Minor of a particular element in a matrix
8 2 4
6 0 7
3 5 9
Step 1:-Ignore the row and column in which the
element a11 i.e. 8 is
Step 2: -Write the remaining elements in determinant
form
0 7
5 9
0 7
5 9
Minor of particular element is
(-35)
8 2 4
6 0 7
3 5 9
0 7
5 9
6 7
3 9
6 0
3 5
2 4
5 9
8 4
3 9
8 2
3 5
2 4
0 7
8 4
6 7
8 2
6 0
 Minor of a Matrix
−35 33 30
−2 60 34
14 32 −12
Minor
Matrix
In some cases, minor and
co-factor remains same but
it may be different or there
may be difference of minus.
Cij = (-1)i+j Mij
Cij = co-factor of aij
Mij = minor of aij
a11 a12 a13
b21 b22 b23
c31 c32 c33
C11= (-1)1+1 M11
C11 =(-1)2 M11
C11= M11
a11 a12 a13
b21 b22 b23
c31 c32 c33
C12= (-1)1+2M12
C12 =(-1)3 M12
C12= -M12
MEANING: -
The Adjoint of A is the transposed matrix of cofactors of A.
Adjoint of a Square Matrix of order 2 x 2
Step 1:- Change the position of principal element i.e.
2 & 3.
Step 2:- Change the sign of remaining two elements
i.e. -1 & -5.
2 5
1 3
3
2
3 −5
−1 2
 Adjoint of a Square Matrix of order
3 x 3
−1 2 4
1 0 2
3 1 −1
Step 1:- Find out the minor matrix of given
matrix. 0 2
1 −1
1 2
3 −1
1 0
3 1
2 4
1 −1
−1 4
3 −1
−1 2
3 1
2 4
0 2
−1 4
1 2
−1 2
1 0
Step 2:- Find out the Cofactor matrix of
Obtained matrix i.e.
+ − +
− + −
+ − +
−2 −7 1
−6 −11 −7
4 −6 −2
−2 7 1
6 −11 7
4 6 −2
Step 3:- Find out the Transpose of Obtained
matrix.
−𝟐 𝟔 𝟒
𝟕 −𝟏𝟏 𝟔
𝟏 𝟕 −𝟐








1
3
5
7
4
2
3
2 A
A
2x3












1
7
3
4
5
2
3
2
T
T
A
A
T
ji
ij a
a  For all i and j
Interchange rows and columns
Then transpose of A, denoted AT
.
The dimensions of AT are the reverse
of the dimensions of A
MEANING: -
Consider a scalar k. The inverse is the reciprocal or division of 1 by the scalar.
Example: k=7 the inverse of k or k-1 = 1/k = 1/7
A-1 =
𝐴𝑑𝑗 (𝐴)
𝐴
A =
3 1 2
2 −3 −1
1 2 1
= 8 ≠ 𝟎
𝐴 = 3 (-3 x 1 – 2 x -1)
1 (2 x 1 – 1 x -1)
2 (2 x2 – 1 x -3)
𝐴
−1 3 7
−3 1 5
5 −7 −11
MINOR
Adj (A)
−1 3 5
−3 1 7
7 −5 −11
COFACTOR & TRANSPOSE
A-1=
1
8
−1 3 5
−3 1 7
7 −5 −11
MEANING: -
It is Solution by the method of inversion of the coefficient matrix.
3x + y + 2z = 3
2x +3y – z = -3
x + 2y + z = 4
Step 1:- Let A = Coefficient Matrix. A =
3 1 2
2 −3 −1
1 2 1
Step 2:- Let X= Unknown Matrix. X =
𝑥
𝑦
𝑧
Step 3:- Let B= Constant Matrix. B =
3
−3
4
X = A-1B Required Solution
A-1 =
𝐴𝑑𝑗 (𝐴)
𝐴
−1 3 7
−3 1 5
5 −7 −11
MINOR
A =
3 1 2
2 −3 −1
1 2 1
= 8 ≠ 𝟎
Adj (A)
𝐴 = 3 (-3 x 1 – 2 x -1)
1 (2 x 1 – 1 x -1)
2 (2 x2 – 1 x -3)
𝐴
−1 3 5
−3 1 7
7 −5 −11
COFACTOR & TRANSPOSE
A =
3 1 2
2 −3 −1
1 2 1
A-1=
1
8
−1 3 5
−3 1 7
7 −5 −11
𝑥
𝑦
𝑧
=
1
8
−1 3 5
−3 1 7
7 −5 −11
X
3
−3
4
As, X = A-1B
𝑥
𝑦
𝑧
=
1
2
−1
X = 1
Y = 2 Ans.
Z = -1
x - 3y = 5
2x + y = 4
=
∆
∆
x
1
=
∆
∆
y
2
SOLUTIONS ARE: -
∆ =
01 −3
02 01
= 7
∆1 =
05 −3
04 01
= 17
∆2 =
01 05
02 04
= -6
x=
17
7
y=
−6
7
x+2y+3z =1
x+3y+5z =2
2x+5y+9z =3
Step 1:- Let A = Coefficient Matrix. A =
1 2 3
1 3 5
2 5 9
Step 2:- Let X= Unknown Matrix. X =
𝑥
𝑦
𝑧
Step 3:- Let B= Constant Matrix. B =
1
2
3
Step 4:- Convert coefficient matrix into upper triangular matrix.
A =
1 2 3
1 3 5
2 5 9
𝑥
𝑦
𝑧
=
1
2
3
~
1 2 3
0 1 2
0 1 3
X=
1
1
1
R2 – R1
R3 - 2R1
R3 – R2 ~
1 2 3
0 1 2
0 0 1
X =
1
1
0
Step 5:- Convert matrix form into equation again.
1x+2y+3z=1 …….(1)
0x+1y+2z=1 …….(2)
0x+0y+1z=0 …….(3)
From 3rd Eqn
From 2nd Eqn
y+2z=1
y=1
z=0
x+2y+3z=1
x+2+0=1
x= -1
From 1st Eqn
X = -1
Y = 1 Ans.
Z = 0
1.
• If |A|≠ 0 𝑛𝑜𝑛 − 𝑠𝑖𝑛𝑔𝑢𝑙𝑎𝑟 𝑚𝑎𝑡𝑟𝑖𝑥 𝑡ℎ𝑒𝑛 𝐴−1
𝑒𝑥𝑖𝑠𝑡𝑠
2.
• Let A = In∙ 𝐴 ; 𝑤ℎ𝑒𝑟𝑒 In= 𝑖𝑑𝑒𝑛𝑡𝑖𝑡𝑦 𝑚𝑎𝑡𝑟𝑖𝑥 𝑜𝑓 𝑜𝑟𝑑𝑒𝑟 ′𝑛′
3.
• Convert A=In∙A into In=BA
4.
• Convert B=𝐴−1
A =
1 0 −1
2 −1 3
1 −1 0
|A|=1
−1 3
−1 0
-0
2 3
1 0
+(-1)
2 −1
1 −1
= 1(3)-0(3)+(-1)(-1)
 |A| = 4 ≠ 0
𝐴
1 0 −1
2 −1 3
1 −1 0
=
1 0 0
0 1 0
0 0 1
A
A=In∙A
~
1 0 −1
0 −1 5
0 −1 1
=
1 0 0
−2 1 0
−1 0 1
A
𝑅2 − 2𝑅1
𝑅3 − 𝑅1
~
1 0 −1
0 −1 5
0 0 −4
=
1 0 0
−2 1 0
1 −1 1
A 𝑅3 − 𝑅2
1 0 −1
0 −1 5
0 0 1
=
1 0 0
−2 1 0
−1
4
1
4
−1
4
A −𝑅3
4
1 0 −1
0 1 −5
0 0 1
=
1 0 0
2 −1 0
−1
4
1
4
−1
4
A −R2
𝐴−1 =
3
4
1
4
−1
4
3
4
1
4
−5
4
−1
4
1
4
−1
4
1 0 0
0 1 0
0 0 1
=
3
4
1
4
−1
4
3
4
1
4
−5
4
−1
4
1
4
−1
4
A
R1 + R3
R2 + 5R3 In=BA
B=𝐴−1
Matrices & Determinants

Matrices & Determinants

  • 1.
    ISHANT JAIN, MALHARSHAH,MEET DOSHI
  • 2.
    2 3 −5 12 4 6 5 0 MEANING: - m x n real numbers arranged in m rows and n columns and enclosed by a pair of brackets is called m x n matrix.
  • 3.
    TYPES OF MATRIX Row Matrix Column Matrix NullMatrix/ Zero Matrix Square Matrix Diagonal Matrix Scalar Matrix Identity Matrix or Unit Matrix Equal Matrix Negative Matrix Upper Triangular Matrix Lower Triangular Matrix Symmetric Matrix Skew Symmetric Matrix
  • 4.
    Sr. No. Type of MatrixMeaning Example 1. Row Matrix  A matrix consisting of a single row.  Also called as row vector. 1 2 3 2. Column Matrix  A matrix consisting of a single column.  Also called as column vector. 1 2 3 3. Null Matrix  All the elements are zero.  Also known as zero matrix.  Denoted by “O”. 0 0 0 0 4. Square Matrix  Matrix having same number of rows and columns.  It can also be written as An. 2 3 4 5 2 1 3 1 6 2 5 2 4 5. Diagonal Matrix  All elements are zero except main or principal diagonal. 2 0 0 5 3 0 0 0 4 0 0 0 1 6. Scalar Matrix  All the diagonal elements are same. 3 0 0 3 2 0 0 0 2 0 0 0 2 7. Unit Matrix  A scalar matrix in which each diagonal element is 1.  Also called “Identity matrix”.  Denoted by In.  Every unit matrix is a diagonal matrix and also a scalar matrix. 1 0 0 1 1 0 0 0 1 0 0 0 1
  • 5.
    Sr. No. Type of MatrixMeaning Example 8. Equal Matrix  Two matrices having the same order.  Each element of A= Corresponding to the element of B A= 2 3 1 0 B= 4 2 9 2 − 1 0 9. Negative Matrix  Replacing all the elements with its additive inverse. A= 3 −1 −2 4 5 −3 B= −3 1 2 −4 −5 3 10. Upper Triangular Matrix  A square matrix in which all elements below the principal diagonal are zero. 1 3 7 0 2 8 0 0 7 11. Lower Triangular Matrix  A square matrix in which all elements above the principal diagonal are zero. 1 0 0 3 6 0 2 5 7 12. Symmetric Matrix  A square matrix having aij=aji 2 1 3 1 6 2 3 2 4 13. Skew Symmetric Matrix  A square matrix having aij= -aji 2 1 3 −1 6 2 −3 −2 4 a12 =a21 a13 =a31 a23 =a32 a12 =-a21 a13 =-a31 a23 =-a32
  • 6.
    1. Matrix Addition 2.Matrix Subtraction 3. Scalar Multiplication 4. Matrix Multiplication
  • 7.
    4 6 0 2 32 8 5 7 8 8 7
  • 8.
    9 7 5 8 53 0 2 4 4 5 6
  • 9.
    4 3 6 9 1209 18 27
  • 10.
    2 5 7 1 75 -3 0 -1 10 46 35
  • 12.
     Determinant isa scalar value that is calculated from a matrix.  It can only be calculated for a square matrix.  It is denoted by ∆ (Delta).  Calculation For 2X2 Matrix 1 3 5 6 (1 x 6) – (3 x 5) - 9
  • 13.
    03 05 02 0400 01 −2 06 10 3{(0 X 10) – (1 X 6)} – 5{(4 X 10) – (-2 X 1)} + 2{(4 X 6) – (-2 X 0)} - 180
  • 14.
    MEANING: - The minorof a element in a matrix is the determinant obtained by deleting the row and the column in which that element appears.  Minor of a particular element in a matrix 8 2 4 6 0 7 3 5 9 Step 1:-Ignore the row and column in which the element a11 i.e. 8 is Step 2: -Write the remaining elements in determinant form 0 7 5 9 0 7 5 9 Minor of particular element is (-35)
  • 15.
    8 2 4 60 7 3 5 9 0 7 5 9 6 7 3 9 6 0 3 5 2 4 5 9 8 4 3 9 8 2 3 5 2 4 0 7 8 4 6 7 8 2 6 0  Minor of a Matrix −35 33 30 −2 60 34 14 32 −12 Minor Matrix
  • 16.
    In some cases,minor and co-factor remains same but it may be different or there may be difference of minus. Cij = (-1)i+j Mij Cij = co-factor of aij Mij = minor of aij a11 a12 a13 b21 b22 b23 c31 c32 c33 C11= (-1)1+1 M11 C11 =(-1)2 M11 C11= M11 a11 a12 a13 b21 b22 b23 c31 c32 c33 C12= (-1)1+2M12 C12 =(-1)3 M12 C12= -M12
  • 17.
    MEANING: - The Adjointof A is the transposed matrix of cofactors of A. Adjoint of a Square Matrix of order 2 x 2 Step 1:- Change the position of principal element i.e. 2 & 3. Step 2:- Change the sign of remaining two elements i.e. -1 & -5. 2 5 1 3 3 2 3 −5 −1 2
  • 18.
     Adjoint ofa Square Matrix of order 3 x 3 −1 2 4 1 0 2 3 1 −1 Step 1:- Find out the minor matrix of given matrix. 0 2 1 −1 1 2 3 −1 1 0 3 1 2 4 1 −1 −1 4 3 −1 −1 2 3 1 2 4 0 2 −1 4 1 2 −1 2 1 0 Step 2:- Find out the Cofactor matrix of Obtained matrix i.e. + − + − + − + − + −2 −7 1 −6 −11 −7 4 −6 −2 −2 7 1 6 −11 7 4 6 −2 Step 3:- Find out the Transpose of Obtained matrix. −𝟐 𝟔 𝟒 𝟕 −𝟏𝟏 𝟔 𝟏 𝟕 −𝟐
  • 19.
            1 3 5 7 4 2 3 2 A A 2x3             1 7 3 4 5 2 3 2 T T A A T ji ij a a For all i and j Interchange rows and columns Then transpose of A, denoted AT . The dimensions of AT are the reverse of the dimensions of A
  • 20.
    MEANING: - Consider ascalar k. The inverse is the reciprocal or division of 1 by the scalar. Example: k=7 the inverse of k or k-1 = 1/k = 1/7
  • 21.
    A-1 = 𝐴𝑑𝑗 (𝐴) 𝐴 A= 3 1 2 2 −3 −1 1 2 1 = 8 ≠ 𝟎 𝐴 = 3 (-3 x 1 – 2 x -1) 1 (2 x 1 – 1 x -1) 2 (2 x2 – 1 x -3) 𝐴 −1 3 7 −3 1 5 5 −7 −11 MINOR Adj (A) −1 3 5 −3 1 7 7 −5 −11 COFACTOR & TRANSPOSE A-1= 1 8 −1 3 5 −3 1 7 7 −5 −11
  • 23.
    MEANING: - It isSolution by the method of inversion of the coefficient matrix. 3x + y + 2z = 3 2x +3y – z = -3 x + 2y + z = 4 Step 1:- Let A = Coefficient Matrix. A = 3 1 2 2 −3 −1 1 2 1 Step 2:- Let X= Unknown Matrix. X = 𝑥 𝑦 𝑧 Step 3:- Let B= Constant Matrix. B = 3 −3 4 X = A-1B Required Solution
  • 24.
    A-1 = 𝐴𝑑𝑗 (𝐴) 𝐴 −13 7 −3 1 5 5 −7 −11 MINOR A = 3 1 2 2 −3 −1 1 2 1 = 8 ≠ 𝟎 Adj (A) 𝐴 = 3 (-3 x 1 – 2 x -1) 1 (2 x 1 – 1 x -1) 2 (2 x2 – 1 x -3) 𝐴 −1 3 5 −3 1 7 7 −5 −11 COFACTOR & TRANSPOSE A = 3 1 2 2 −3 −1 1 2 1 A-1= 1 8 −1 3 5 −3 1 7 7 −5 −11 𝑥 𝑦 𝑧 = 1 8 −1 3 5 −3 1 7 7 −5 −11 X 3 −3 4 As, X = A-1B 𝑥 𝑦 𝑧 = 1 2 −1 X = 1 Y = 2 Ans. Z = -1
  • 25.
    x - 3y= 5 2x + y = 4 = ∆ ∆ x 1 = ∆ ∆ y 2 SOLUTIONS ARE: - ∆ = 01 −3 02 01 = 7 ∆1 = 05 −3 04 01 = 17 ∆2 = 01 05 02 04 = -6 x= 17 7 y= −6 7
  • 26.
    x+2y+3z =1 x+3y+5z =2 2x+5y+9z=3 Step 1:- Let A = Coefficient Matrix. A = 1 2 3 1 3 5 2 5 9 Step 2:- Let X= Unknown Matrix. X = 𝑥 𝑦 𝑧 Step 3:- Let B= Constant Matrix. B = 1 2 3 Step 4:- Convert coefficient matrix into upper triangular matrix.
  • 27.
    A = 1 23 1 3 5 2 5 9 𝑥 𝑦 𝑧 = 1 2 3 ~ 1 2 3 0 1 2 0 1 3 X= 1 1 1 R2 – R1 R3 - 2R1 R3 – R2 ~ 1 2 3 0 1 2 0 0 1 X = 1 1 0 Step 5:- Convert matrix form into equation again. 1x+2y+3z=1 …….(1) 0x+1y+2z=1 …….(2) 0x+0y+1z=0 …….(3) From 3rd Eqn From 2nd Eqn y+2z=1 y=1 z=0 x+2y+3z=1 x+2+0=1 x= -1 From 1st Eqn X = -1 Y = 1 Ans. Z = 0
  • 28.
    1. • If |A|≠0 𝑛𝑜𝑛 − 𝑠𝑖𝑛𝑔𝑢𝑙𝑎𝑟 𝑚𝑎𝑡𝑟𝑖𝑥 𝑡ℎ𝑒𝑛 𝐴−1 𝑒𝑥𝑖𝑠𝑡𝑠 2. • Let A = In∙ 𝐴 ; 𝑤ℎ𝑒𝑟𝑒 In= 𝑖𝑑𝑒𝑛𝑡𝑖𝑡𝑦 𝑚𝑎𝑡𝑟𝑖𝑥 𝑜𝑓 𝑜𝑟𝑑𝑒𝑟 ′𝑛′ 3. • Convert A=In∙A into In=BA 4. • Convert B=𝐴−1
  • 29.
    A = 1 0−1 2 −1 3 1 −1 0 |A|=1 −1 3 −1 0 -0 2 3 1 0 +(-1) 2 −1 1 −1 = 1(3)-0(3)+(-1)(-1)  |A| = 4 ≠ 0 𝐴 1 0 −1 2 −1 3 1 −1 0 = 1 0 0 0 1 0 0 0 1 A A=In∙A ~ 1 0 −1 0 −1 5 0 −1 1 = 1 0 0 −2 1 0 −1 0 1 A 𝑅2 − 2𝑅1 𝑅3 − 𝑅1 ~ 1 0 −1 0 −1 5 0 0 −4 = 1 0 0 −2 1 0 1 −1 1 A 𝑅3 − 𝑅2
  • 30.
    1 0 −1 0−1 5 0 0 1 = 1 0 0 −2 1 0 −1 4 1 4 −1 4 A −𝑅3 4 1 0 −1 0 1 −5 0 0 1 = 1 0 0 2 −1 0 −1 4 1 4 −1 4 A −R2 𝐴−1 = 3 4 1 4 −1 4 3 4 1 4 −5 4 −1 4 1 4 −1 4 1 0 0 0 1 0 0 0 1 = 3 4 1 4 −1 4 3 4 1 4 −5 4 −1 4 1 4 −1 4 A R1 + R3 R2 + 5R3 In=BA B=𝐴−1