A  hyperbola  is the collection of points in the plane the difference of whose distances from two fixed points, called the  foci , is a constant. HYPERBOLA
 
Theorem Equation of a Hyberbola; Center at  (0, 0);  Foci at  (  +   c , 0);  Vertices at  (  +   a , 0);  Transverse Axis along the  x -Axis An equation of the hyperbola with center at  (0, 0),  foci at  ( -  c , 0)  and  ( c , 0),  and vertices at  ( -  a , 0)  and  ( a,  0)  is The transverse axis is the  x -axis.
 
Theorem Equation of a Hyberbola; Center at  (0, 0); Foci at ( 0,  +   c ); Vertices at  (0,  +   a ); Transverse Axis along the  y -Axis An equation of the hyperbola with center at (0, 0), foci at (0, -  c ) and (0,  c ), and vertices at (0, -  a ) and (0,  a ) is The transverse axis is the  y -axis.
 
Theorem  Asymptotes of a Hyperbola The hyperbola has the two oblique asymptotes
 
Theorem  Asymptotes of a Hyperbola The hyperbola has the two oblique asymptotes
Find an equation of a hyperbola with center at the origin, one focus at  (0, 5)  and one vertex at  (0, -3).   Determine the oblique asymptotes.  Graph the equation by hand and using a graphing utility. Center: (0, 0) Focus:  (0, 5) = (0,  c ) Vertex:  (0, -3) = (0, - a ) Transverse axis is the  y -axis, thus equation is of the form
= 25 - 9 = 16 Asymptotes:
V  (0, 3) V  (0, -3) (4, 0) (-4, 0) F (0, 5) F (0, -5)
Hyperbola with Transverse Axis Parallel to the  x -Axis; Center at ( h ,  k )   where  b 2  =  c 2  -  a 2 .
 
Hyperbola with Transverse Axis Parallel to the  y -Axis; Center at ( h ,  k )   where  b 2  =  c 2  -  a 2 .
 
Find the center, transverse axis, vertices, foci, and asymptotes of
Center: ( h ,  k ) = (-2, 4) Transverse axis parallel to  x -axis. Vertices: ( h   +   a ,  k ) = (-2  +  2, 4) or  (-4, 4) and (0, 4)
Asymptotes:   ( h ,  k ) = (-2, 4)
C (-2,4) V  (-4, 4) V  (0, 4) F  (2.47, 4) F  (-6.47, 4) (-2, 8) (-2, 0) y  - 4 = -2( x  + 2) y  - 4 = 2( x  + 2)
Sketch the curve represented by the equation: Exercise :
Solution:
Note:- To understand what this curve might look like, we have to work towards a standard form.  This is best accomplished by completing the square in the x terms and in the  y  terms.   From this, we see that the curve is a hyperbola centered at (1, 4).  When  y  = 4  we have:
So, Thus,  or  Therefore, (3, 4) and   are both on the curve.  The asymptotes are the lines  and  and they pass through the centre (1, 4).

Math1.4

  • 1.
    A hyperbola is the collection of points in the plane the difference of whose distances from two fixed points, called the foci , is a constant. HYPERBOLA
  • 2.
  • 3.
    Theorem Equation ofa Hyberbola; Center at (0, 0); Foci at ( + c , 0); Vertices at ( + a , 0); Transverse Axis along the x -Axis An equation of the hyperbola with center at (0, 0), foci at ( - c , 0) and ( c , 0), and vertices at ( - a , 0) and ( a, 0) is The transverse axis is the x -axis.
  • 4.
  • 5.
    Theorem Equation ofa Hyberbola; Center at (0, 0); Foci at ( 0, + c ); Vertices at (0, + a ); Transverse Axis along the y -Axis An equation of the hyperbola with center at (0, 0), foci at (0, - c ) and (0, c ), and vertices at (0, - a ) and (0, a ) is The transverse axis is the y -axis.
  • 6.
  • 7.
    Theorem Asymptotesof a Hyperbola The hyperbola has the two oblique asymptotes
  • 8.
  • 9.
    Theorem Asymptotesof a Hyperbola The hyperbola has the two oblique asymptotes
  • 10.
    Find an equationof a hyperbola with center at the origin, one focus at (0, 5) and one vertex at (0, -3). Determine the oblique asymptotes. Graph the equation by hand and using a graphing utility. Center: (0, 0) Focus: (0, 5) = (0, c ) Vertex: (0, -3) = (0, - a ) Transverse axis is the y -axis, thus equation is of the form
  • 11.
    = 25 -9 = 16 Asymptotes:
  • 12.
    V (0,3) V (0, -3) (4, 0) (-4, 0) F (0, 5) F (0, -5)
  • 13.
    Hyperbola with TransverseAxis Parallel to the x -Axis; Center at ( h , k ) where b 2 = c 2 - a 2 .
  • 14.
  • 15.
    Hyperbola with TransverseAxis Parallel to the y -Axis; Center at ( h , k ) where b 2 = c 2 - a 2 .
  • 16.
  • 17.
    Find the center,transverse axis, vertices, foci, and asymptotes of
  • 18.
    Center: ( h, k ) = (-2, 4) Transverse axis parallel to x -axis. Vertices: ( h + a , k ) = (-2 + 2, 4) or (-4, 4) and (0, 4)
  • 19.
    Asymptotes: ( h , k ) = (-2, 4)
  • 20.
    C (-2,4) V (-4, 4) V (0, 4) F (2.47, 4) F (-6.47, 4) (-2, 8) (-2, 0) y - 4 = -2( x + 2) y - 4 = 2( x + 2)
  • 21.
    Sketch the curverepresented by the equation: Exercise :
  • 22.
  • 23.
    Note:- To understandwhat this curve might look like, we have to work towards a standard form. This is best accomplished by completing the square in the x terms and in the y terms. From this, we see that the curve is a hyperbola centered at (1, 4). When y = 4 we have:
  • 24.
    So, Thus, or Therefore, (3, 4) and are both on the curve. The asymptotes are the lines and and they pass through the centre (1, 4).