Section	1.6
            Limits	involving	Infinity

                V63.0121.006/016, Calculus	I



                      February	3, 2010


Announcements
   Office	Hours: M,W 1:30–2:30, R 9–10	(CIWW 726)
   Written	Assignment	#2	due	today.
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   First	Quiz: Friday	February	12	in	recitation	(§§1.1–1.4)
                                           .    .   .    .    .   .
Recall	the	definition	of	limit



   Definition
   We	write
                                lim f(x) = L
                               x→a

   and	say

              “the	limit	of f(x), as x approaches a, equals L”

   if	we	can	make	the	values	of f(x) arbitrarily	close	to L (as	close	to
   L as	we	like)	by	taking x to	be	sufficiently	close	to a (on	either
   side	of a)	but	not	equal	to a.




                                                  .   .    .     .   .     .
Recall	the	unboundedness	problem
                      1
  Recall	why lim        doesn’t	exist.
             x →0 +   x

                          y
                          .




                        .? .
                        L



                           .                  x
                                              .

  No	matter	how	thin	we	draw	the	strip	to	the	right	of x = 0, we
  cannot	“capture”	the	graph	inside	the	box.

                                              .   .    .   .       .   .
Recall	the	unboundedness	problem
                      1
  Recall	why lim        doesn’t	exist.
             x →0 +   x

                          y
                          .




                        .? .
                        L



                           .                  x
                                              .

  No	matter	how	thin	we	draw	the	strip	to	the	right	of x = 0, we
  cannot	“capture”	the	graph	inside	the	box.

                                              .   .    .   .       .   .
Recall	the	unboundedness	problem
                      1
  Recall	why lim        doesn’t	exist.
             x →0 +   x

                          y
                          .




                        .? .
                        L



                           .                  x
                                              .

  No	matter	how	thin	we	draw	the	strip	to	the	right	of x = 0, we
  cannot	“capture”	the	graph	inside	the	box.

                                              .   .    .   .       .   .
Recall	the	unboundedness	problem
                      1
  Recall	why lim        doesn’t	exist.
             x →0 +   x

                          y
                          .




                        .? .
                        L



                           .                  x
                                              .

  No	matter	how	thin	we	draw	the	strip	to	the	right	of x = 0, we
  cannot	“capture”	the	graph	inside	the	box.

                                              .   .    .   .       .   .
Outline



  Infinite	Limits
     Vertical	Asymptotes
     Infinite	Limits	we	Know
     Limit	“Laws”	with	Infinite	Limits
     Indeterminate	Limit	forms


  Limits	at ∞
     Algebraic	rates	of	growth
     Rationalizing	to	get	a	limit




                                        .   .   .   .   .   .
Infinite	Limits


  Definition
  The	notation                    y
                                  .
          lim f(x) = ∞
          x →a

  means	that	values	of f(x) can
  be	made	arbitrarily large (as
  large as	we	please)	by	taking
  x sufficiently	close	to a but
  not	equal	to a.
                                  .                       x
                                                          .




                                      .   .   .   .   .       .
Infinite	Limits


  Definition
  The	notation                    y
                                  .
          lim f(x) = ∞
          x →a

  means	that	values	of f(x) can
  be	made	arbitrarily large (as
  large as	we	please)	by	taking
  x sufficiently	close	to a but
  not	equal	to a.

      “Large”	takes	the	place     .                       x
                                                          .
      of	“close	to L”.



                                      .   .   .   .   .       .
Infinite	Limits


  Definition
  The	notation                    y
                                  .
          lim f(x) = ∞
          x →a

  means	that	values	of f(x) can
  be	made	arbitrarily large (as
  large as	we	please)	by	taking
  x sufficiently	close	to a but
  not	equal	to a.

      “Large”	takes	the	place     .                       x
                                                          .
      of	“close	to L”.



                                      .   .   .   .   .       .
Infinite	Limits


  Definition
  The	notation                    y
                                  .
          lim f(x) = ∞
          x →a

  means	that	values	of f(x) can
  be	made	arbitrarily large (as
  large as	we	please)	by	taking
  x sufficiently	close	to a but
  not	equal	to a.

      “Large”	takes	the	place     .                       x
                                                          .
      of	“close	to L”.



                                      .   .   .   .   .       .
Infinite	Limits


  Definition
  The	notation                    y
                                  .
          lim f(x) = ∞
          x →a

  means	that	values	of f(x) can
  be	made	arbitrarily large (as
  large as	we	please)	by	taking
  x sufficiently	close	to a but
  not	equal	to a.

      “Large”	takes	the	place     .                       x
                                                          .
      of	“close	to L”.



                                      .   .   .   .   .       .
Infinite	Limits


  Definition
  The	notation                    y
                                  .
          lim f(x) = ∞
          x →a

  means	that	values	of f(x) can
  be	made	arbitrarily large (as
  large as	we	please)	by	taking
  x sufficiently	close	to a but
  not	equal	to a.

      “Large”	takes	the	place     .                       x
                                                          .
      of	“close	to L”.



                                      .   .   .   .   .       .
Infinite	Limits


  Definition
  The	notation                    y
                                  .
          lim f(x) = ∞
          x →a

  means	that	values	of f(x) can
  be	made	arbitrarily large (as
  large as	we	please)	by	taking
  x sufficiently	close	to a but
  not	equal	to a.

      “Large”	takes	the	place     .                       x
                                                          .
      of	“close	to L”.



                                      .   .   .   .   .       .
Infinite	Limits


  Definition
  The	notation                    y
                                  .
          lim f(x) = ∞
          x →a

  means	that	values	of f(x) can
  be	made	arbitrarily large (as
  large as	we	please)	by	taking
  x sufficiently	close	to a but
  not	equal	to a.

      “Large”	takes	the	place     .                       x
                                                          .
      of	“close	to L”.



                                      .   .   .   .   .       .
Negative	Infinity



   Definition
   The	notation
                             lim f(x) = −∞
                             x →a

   means	that	the	values	of f(x) can	be	made	arbitrarily	large
   negative (as	large	as	we	please)	by	taking x sufficiently	close	to a
   but	not	equal	to a.




                                                .    .    .   .    .     .
Negative	Infinity



   Definition
   The	notation
                             lim f(x) = −∞
                             x →a

   means	that	the	values	of f(x) can	be	made	arbitrarily	large
   negative (as	large	as	we	please)	by	taking x sufficiently	close	to a
   but	not	equal	to a.

       We	call	a	number large or small based	on	its	absolute	value.
       So −1, 000, 000 is	a	large	(negative)	number.




                                                .    .    .   .    .     .
Vertical	Asymptotes




   Definition
   The	line x = a is	called	a vertical	asymptote of	the	curve y = f(x)
   if	at	least	one	of	the	following	is	true:
          lim f(x) = ∞                       lim f(x) = −∞
       x →a                                 x →a
        lim f(x) = ∞                         lim f(x) = −∞
       x →a +                               x →a +
        lim f(x) = ∞                         lim f(x) = −∞
       x →a −                               x →a −




                                                   .   .   .   .   .     .
Infinite	Limits	we	Know

                                         y
                                         .
                                         .

                                         .
           1
     lim
         + x
             =∞
    x →0                                 .

                         .   .   .       .       .       .       .   x
                                                                     .

                                         .

                                         .

                                         .

                                     .       .       .       .       .   .
Infinite	Limits	we	Know

                                         y
                                         .
                                         .

                                         .
           1
     lim
         + x
             =∞
    x →0                                 .
           1
      lim    = −∞
    x →0 − x             .   .   .       .       .       .       .   x
                                                                     .

                                         .

                                         .

                                         .

                                     .       .       .       .       .   .
Infinite	Limits	we	Know

                                         y
                                         .
                                         .

                                         .
           1
     lim
         + x
             =∞
    x →0                                 .
           1
      lim    = −∞
    x →0 − x             .   .   .       .       .       .       .   x
                                                                     .
          1
    lim      =∞
    x →0 x 2                             .

                                         .

                                         .

                                     .       .       .       .       .   .
Finding	limits	at	trouble	spots



   Example
   Let
                                         x2 + 2
                            f(x ) =
                                      x2 − 3x + 2
   Find lim f(x) and lim f(x) for	each a at	which f is	not
         x →a −      x→a+
   continuous.




                                                    .   .   .   .   .   .
Finding	limits	at	trouble	spots



   Example
   Let
                                         x2 + 2
                            f(x ) =
                                      x2 − 3x + 2
   Find lim f(x) and lim f(x) for	each a at	which f is	not
         x →a −      x→a+
   continuous.

   Solution
   The	denominator	factors	as (x − 1)(x − 2). We	can	record	the
   signs	of	the	factors	on	the	number	line.




                                                    .   .   .   .   .   .
Use	the	number	line

       −
       ..        0
                 ..           .
                              +
                                . x − 1)
                                (
                 1
                 .




  So




                      .   .     .     .    .   .
Use	the	number	line

       −
       ..        0
                 ..                .
                                   +
                                     . x − 1)
                                     (
                 1
                 .
       −
       .              0
                      ..           .
                                   +
                                     . x − 2)
                                     (
                      2
                      .




  So




                           .   .     .     .    .   .
Use	the	number	line

       −
       ..        0
                 ..                    .
                                       +
                                         . x − 1)
                                         (
                 1
                 .
       −
       .                  0
                          ..           .
                                       +
                                         . x − 2)
                                         (
                          2
                          .
                      .
                      +
                                        . x2 + 2 )
                                        (




  So




                               .   .     .     .     .   .
Use	the	number	line

       −
       ..        0
                 ..                    .
                                       +
                                         . x − 1)
                                         (
                 1
                 .
       −
       .                  0
                          ..           .
                                       +
                                         . x − 2)
                                         (
                          2
                          .
                      .
                      +
                                        . x2 + 2 )
                                        (

                  .        .            f
                                        .(x)
                 1
                 .        2
                          .

  So




                               .   .     .     .     .   .
Use	the	number	line

       −
       ..        0
                 ..                    .
                                       +
                                         . x − 1)
                                         (
                 1
                 .
       −
       .                  0
                          ..           .
                                       +
                                         . x − 2)
                                         (
                          2
                          .
                      .
                      +
                                        . x2 + 2 )
                                        (
       .
       +          .        .            f
                                        .(x)
                 1
                 .        2
                          .

  So




                               .   .     .     .     .   .
Use	the	number	line

       −
       ..          0
                   ..                       .
                                            +
                                              . x − 1)
                                              (
                   1
                   .
       −
       .                       0
                               ..           .
                                            +
                                              . x − 2)
                                              (
                               2
                               .
                        .
                        +
                                             . x2 + 2 )
                                             (
       .
       +      . ∞.
              +                 .            f
                                             .(x)
                 1
                 .             2
                               .

  So
               lim f(x) = +∞
              x →1 −




                                    .   .     .     .     .   .
Use	the	number	line

       −
       ..          0
                   ..                       .
                                            +
                                              . x − 1)
                                              (
                   1
                   .
       −
       .                       0
                               ..           .
                                            +
                                              . x − 2)
                                              (
                               2
                               .
                         .
                         +
                                             . x2 + 2 )
                                             (
       .
       +      . ∞ .. ∞
              +    −            .            f
                                             .(x)
                 1
                 .             2
                               .

  So
               lim f(x) = +∞
              x →1 −
               lim f(x) = −∞
              x →1 +



                                    .   .     .     .     .   .
Use	the	number	line

       −
       ..          0
                   ..                       .
                                            +
                                              . x − 1)
                                              (
                   1
                   .
       −
       .                       0
                               ..           .
                                            +
                                              . x − 2)
                                              (
                               2
                               .
                        .
                        +
                                             . x2 + 2 )
                                             (
       .
       +      . ∞ .. ∞ .
              +    −   −        .            f
                                             .(x)
                 1
                 .             2
                               .

  So
               lim f(x) = +∞
              x →1 −
               lim f(x) = −∞
              x →1 +



                                    .   .     .     .     .   .
Use	the	number	line

       −
       ..          0
                   ..                           .
                                                +
                                                  . x − 1)
                                                  (
                   1
                   .
       −
       .                        0
                                ..              .
                                                +
                                                  . x − 2)
                                                  (
                                2
                                .
                        .
                        +
                                                 . x2 + 2 )
                                                 (
       .
       +      . ∞ .. ∞ . . ∞ .
              +    −   − −
                                                 f
                                                 .(x)
                 1
                 .          2
                            .

  So
               lim f(x) = +∞    lim f(x) = −∞
              x →1 −           x →2 −
               lim f(x) = −∞
              x →1 +



                                        .   .     .     .     .   .
Use	the	number	line

       −
       ..          0
                   ..                           .
                                                +
                                                  . x − 1)
                                                  (
                   1
                   .
       −
       .                        0
                                ..              .
                                                +
                                                  . x − 2)
                                                  (
                                2
                                .
                        .
                        +
                                                 . x2 + 2 )
                                                 (
       .
       +      . ∞ .. ∞ . . ∞ .. ∞
              +    −   − −    +
                                                 f
                                                 .(x)
                 1
                 .          2
                            .

  So
               lim f(x) = +∞    lim f(x) = −∞
              x →1 −           x →2 −
               lim f(x) = −∞    lim f(x) = +∞
              x →1 +           x →2 +



                                        .   .     .     .     .   .
Use	the	number	line

       −
       ..          0
                   ..                           .
                                                +
                                                  . x − 1)
                                                  (
                   1
                   .
       −
       .                        0
                                ..              .
                                                +
                                                  . x − 2)
                                                  (
                                2
                                .
                        .
                        +
                                                 . x2 + 2 )
                                                 (
       .
       +      . ∞ .. ∞ . . ∞ .. ∞
              +    −   − −    +
                                                 f
                                                 .(x)
                 1
                 .          2
                            .

  So
               lim f(x) = +∞    lim f(x) = −∞
              x →1 −           x →2 −
               lim f(x) = −∞    lim f(x) = +∞
              x →1 +           x →2 +



                                        .   .     .     .     .   .
Use	the	number	line

       −
       ..          0
                   ..                           .
                                                +
                                                  . x − 1)
                                                  (
                   1
                   .
       −
       .                        0
                                ..              .
                                                +
                                                  . x − 2)
                                                  (
                                2
                                .
                        .
                        +
                                                 . x2 + 2 )
                                                 (
       .
       +      . ∞ .. ∞ . . ∞ .. ∞
              +    −   − −    +                 .
                                                +
                                                  f
                                                  .(x)
                 1
                 .          2
                            .

  So
               lim f(x) = +∞    lim f(x) = −∞
              x →1 −           x →2 −
               lim f(x) = −∞    lim f(x) = +∞
              x →1 +           x →2 +



                                        .   .     .      .    .   .
In	English, now




   To	explain	the	limit, you	can	say:
   “As x → 1− , the	numerator	approaches 3, and	the	denominator
   approaches 0 while	remaining	positive. So	the	limit	is +∞.”




                                            .    .   .   .   .    .
The	graph	so	far

                   y
                   .




          .        .     .     .             . .
                                               x
        −
        . 1            1
                       .     2
                             .             3
                                           .




                             .     .   .    .      .   .
The	graph	so	far

                   y
                   .




          .        .     .     .             . .
                                               x
        −
        . 1            1
                       .     2
                             .             3
                                           .




                             .     .   .    .      .   .
The	graph	so	far

                   y
                   .




          .        .     .     .             . .
                                               x
        −
        . 1            1
                       .     2
                             .             3
                                           .




                             .     .   .    .      .   .
The	graph	so	far

                   y
                   .




          .        .     .     .             . .
                                               x
        −
        . 1            1
                       .     2
                             .             3
                                           .




                             .     .   .    .      .   .
The	graph	so	far

                   y
                   .




          .        .     .     .             . .
                                               x
        −
        . 1            1
                       .     2
                             .             3
                                           .




                             .     .   .    .      .   .
Limit	Laws	(?) with	infinite	limits


       If lim f(x) = ∞ and lim g(x) = ∞, then lim (f(x) + g(x)) = ∞.
         x →a             x→a                 x →a
       That	is,

                                ∞  .
                                . +∞=∞


       If lim f(x) = −∞ and lim g(x) = −∞, then
         x →a               x →a
       lim (f(x) + g(x)) = −∞. That	is,
       x →a


                             −      .
                             . ∞ − ∞ = −∞




                                              .      .   .   .   .     .
Rules	of	Thumb with	infinite	limits


      If lim f(x) = ∞ and lim g(x) = ∞, then lim (f(x) + g(x)) = ∞.
        x →a             x→a                 x →a
      That	is,

                               ∞  .
                               . +∞=∞


      If lim f(x) = −∞ and lim g(x) = −∞, then
        x →a               x →a
      lim (f(x) + g(x)) = −∞. That	is,
      x →a


                            −      .
                            . ∞ − ∞ = −∞




                                             .      .   .   .   .     .
Rules	of	Thumb	with	infinite	limits



      If lim f(x) = L and lim g(x) = ±∞, then
        x →a            x →a
      lim (f(x) + g(x)) = ±∞. That	is,
      x →a



                                L+∞=∞
                               .     .
                                L − ∞ = −∞




                                                .   .   .   .   .   .
Rules	of	Thumb	with	infinite	limits
Kids, don’t	try	this	at	home!


           The	product	of	a	finite	limit	and	an	infinite	limit	is	infinite if
           the	finite	limit	is	not	0.

                                       {
                                        ∞.          if L > 0
                                 . ·∞=
                                 L
                                        −∞          if L < 0.



                                             {
                                                 −∞ if L > 0
                                                 .
                                . · (−∞) =
                                L
                                                 ∞  if L < 0.




                                                         .      .   .   .   .   .
Multiplying	infinite	limits
Kids, don’t	try	this	at	home!




           The	product	of	two	infinite	limits	is	infinite.


                                       ∞·∞=∞
                                .         .
                                    ∞ · (−∞) = −∞
                                (−∞) · (−∞) = ∞




                                                    .      .   .   .   .   .
Dividing	by	Infinity
Kids, don’t	try	this	at	home!




           The	quotient	of	a	finite	limit	by	an	infinite	limit	is	zero:

                                        L .
                                       . =0
                                       ∞




                                                    .    .    .    .    .   .
Dividing	by	zero	is	still	not	allowed




                           1 .
                           . =∞
                           0

   There	are	examples	of	such	limit	forms	where	the	limit	is ∞, −∞,
   undecided	between	the	two, or	truly	neither.




                                              .   .   .    .   .      .
Indeterminate	Limit	forms

                      L
   Limits	of	the	form   are indeterminate. There	is	no	rule	for
                      0
   evaluating	such	a	form; the	limit	must	be	examined	more	closely.
   Consider	these:
                      1                         −1
                 lim     =∞                lim      = −∞
                x→0 x2                    x →0 x 2
                       1                          1
                 lim
                     + x
                         =∞                  lim    = −∞
                x →0                       x →0 − x




                    1                     L
   Worst, lim               is	of	the	form , but	the	limit	does	not
           x→0 x sin(1/x)                 0
   exist, even	in	the	left-	or	right-hand	sense. There	are	infinitely
   many	vertical	asymptotes	arbitrarily	close	to	0!


                                                 .    .    .   .       .   .
Indeterminate	Limit	forms

   Limits	of	the	form 0 · ∞ and ∞ − ∞ are	also	indeterminate.
   Example
                               1
       The	limit lim sin x ·     is	of	the	form 0 · ∞, but	the	answer	is
                 x →0 +        x
       1.
                                1
       The	limit lim sin2 x ·     is	of	the	form 0 · ∞, but	the	answer	is
                 x →0 +         x
       0.
                             1
       The	limit lim sin x · 2 is	of	the	form 0 · ∞, but	the	answer	is
                x →0 +      x
       ∞.

   Limits	of	indeterminate	forms	may	or	may	not	“exist.” It	will
   depend	on	the	context.


                                                  .    .    .   .    .      .
Indeterminate	forms	are	like	Tug	Of	War




   Which	side	wins	depends	on	which	side	is	stronger.

                                             .   .      .   .   .   .
Outline



  Infinite	Limits
     Vertical	Asymptotes
     Infinite	Limits	we	Know
     Limit	“Laws”	with	Infinite	Limits
     Indeterminate	Limit	forms


  Limits	at ∞
     Algebraic	rates	of	growth
     Rationalizing	to	get	a	limit




                                        .   .   .   .   .   .
Definition
Let f be	a	function	defined	on	some	interval (a, ∞). Then

                           lim f(x) = L
                          x→∞

means	that	the	values	of f(x) can	be	made	as	close	to L as	we
like, by	taking x sufficiently	large.




                                            .   .    .     .    .   .
Definition
Let f be	a	function	defined	on	some	interval (a, ∞). Then

                             lim f(x) = L
                             x→∞

means	that	the	values	of f(x) can	be	made	as	close	to L as	we
like, by	taking x sufficiently	large.

Definition
The	line y = L is	a	called	a horizontal	asymptote of	the	curve
y = f(x) if	either

              lim f(x) = L      or      lim f(x) = L.
             x→∞                       x→−∞




                                              .   .     .   .    .   .
Definition
Let f be	a	function	defined	on	some	interval (a, ∞). Then

                              lim f(x) = L
                              x→∞

means	that	the	values	of f(x) can	be	made	as	close	to L as	we
like, by	taking x sufficiently	large.

Definition
The	line y = L is	a	called	a horizontal	asymptote of	the	curve
y = f(x) if	either

              lim f(x) = L       or      lim f(x) = L.
              x→∞                       x→−∞


y = L is	a horizontal line!


                                               .   .     .   .   .   .
Basic	limits	at	infinity




   Theorem
   Let n be	a	positive	integer. Then
             1
         lim    =0
        x→∞ xn
               1
          lim n = 0
        x→−∞ x




                                       .   .   .   .   .   .
Using	the	limit	laws	to	compute	limits	at ∞



   Example
   Find
                          2x3 + 3x + 1
                      lim
                      x→∞ 4x3 + 5x2 + 7

   if	it	exists.
   A does	not	exist
   B 1/2
   C 0
   D ∞




                                          .   .   .   .   .   .
Using	the	limit	laws	to	compute	limits	at ∞



   Example
   Find
                          2x3 + 3x + 1
                      lim
                      x→∞ 4x3 + 5x2 + 7

   if	it	exists.
   A does	not	exist
   B 1/2
   C 0
   D ∞




                                          .   .   .   .   .   .
Solution
Factor	out	the	largest	power	of x from	the	numerator	and
denominator. We	have
                 2x3 + 3x + 1    x3 (2 + 3/x2 + 1/x3 )
                               = 3
                 4x3 + 5x2 + 7    x (4 + 5/x + 7/x3 )
                 2x3 + 3x + 1          2 + 3/x2 + 1/x3
             lim               = lim
            x→∞ 4x3 + 5x2 + 7    x→∞ 4 + 5/x + 7/x3
                                 2+0+0          1
                               =             =
                                 4+0+0          2




                                            .    .       .   .   .   .
Solution
Factor	out	the	largest	power	of x from	the	numerator	and
denominator. We	have
                 2x3 + 3x + 1    x3 (2 + 3/x2 + 1/x3 )
                               = 3
                 4x3 + 5x2 + 7    x (4 + 5/x + 7/x3 )
                 2x3 + 3x + 1          2 + 3/x2 + 1/x3
             lim               = lim
            x→∞ 4x3 + 5x2 + 7    x→∞ 4 + 5/x + 7/x3
                                 2+0+0          1
                               =             =
                                 4+0+0          2


Upshot
When	finding	limits	of	algebraic	expressions	at	infinity, look	at
the highest	degree	terms.


                                            .    .       .   .   .   .
Another	Example

  Example
               x
  Find lim
      x→∞ x2   +1




                    .   .   .   .   .   .
Another	Example

  Example
                x
  Find lim
       x→∞ x2   +1
  Answer
  The	limit	is 0.




                     .   .   .   .   .   .
Solution
Again, factor	out	the	largest	power	of x from	the	numerator	and
denominator. We	have
              x         x(1)       1    1
                  = 2             = ·
           x2 + 1   x (1 + 1/x2 )  x 1 + 1/x2
              x          1    1          1        1
       lim        = lim            = lim · lim
      x→∞ x2 + 1    x→∞ x 1 + 1/x2   x→∞ x x→∞ 1 + 1/x2
                         1
                  =0·         = 0.
                       1+0




                                           .    .   .    .   .    .
Another	Example

  Example
                x
  Find lim
       x→∞ x2   +1
  Answer
  The	limit	is 0.
                         y
                         .

                     .                           x
                                                 .




                             .   .   .   .   .       .
Another	Example

  Example
                x
  Find lim
       x→∞ x2   +1
  Answer
  The	limit	is 0.
                                     y
                                     .

                                 .                                    x
                                                                      .



  Notice	that	the	graph	does	cross	the	asymptote, which
  contradicts	one	of	the	heuristic	definitions	of	asymptote.


                                              .    .   .      .   .       .
Solution
Again, factor	out	the	largest	power	of x from	the	numerator	and
denominator. We	have
              x         x(1)       1    1
                  = 2             = ·
           x2 + 1   x (1 + 1/x2 )  x 1 + 1/x2
              x          1    1          1        1
       lim        = lim            = lim · lim
      x→∞ x2 + 1    x→∞ x 1 + 1/x2   x→∞ x x→∞ 1 + 1/x2
                         1
                  =0·         = 0.
                       1+0


Remark
Had	the	higher	power	been	in	the	numerator, the	limit	would
have	been ∞.


                                           .    .   .    .    .   .
Another	Example


  Example
  Find



              √
               3x4 + 7
          lim
         x→∞ x2 + 3




                         .   .   .   .   .   .
Another	Example


  Example
  Find

                         √           √      √
                         . 3x4 + 7 ∼ . 3x4 = 3x2
              √
               3x4 + 7
          lim
         x→∞ x2 + 3




  Answer         √
  The	limit	is    3.



                                       .   .   .   .   .   .
Solution

                √              √
                 3x4 + 7         x4 (3 + 7/x4 )
            lim          = lim 2
           x→∞ x2 + 3      x→∞ x (1 + 3/x2 )
                                 √
                               x2 (3 + 7/x4 )
                         = lim 2
                           x→∞ x (1 + 3/x2 )
                               √
                                 (3 + 7/x4 )
                         = lim
                           x→∞   1 + 3/x2
                           √
                             3+0 √
                         =        = 3.
                            1+0




                                        .   .     .   .   .   .
Rationalizing	to	get	a	limit

   Example         (√             )
   Compute lim       4x2 + 17 − 2x .
             x→∞




                                       .   .   .   .   .   .
Rationalizing	to	get	a	limit

   Example          (√             )
   Compute lim        4x2 + 17 − 2x .
              x→∞

   Solution
   This	limit	is	of	the	form ∞ − ∞, which	we	cannot	use. So	we
   rationalize	the	numerator	(the	denominator	is 1)	to	get	an
   expression	that	we	can	use	the	limit	laws	on.
        (√                  )       (√                ) √4x2 + 17 + 2x
    lim     4x2 + 17 − 2x = lim         4x2 + 17 − 2x · √
   x→∞                          x→∞                       4x2 + 17 + 2x
                                    (4x 2 + 17) − 4x2
                              = lim √
                                x→∞   4x2 + 17 + 2x
                                           17
                              = lim √                 =0
                                x→∞   4x 2 + 17 + 2x



                                              .    .   .   .    .   .
Kick	it	up	a	notch

   Example         (√              )
   Compute lim       4x2 + 17x − 2x .
             x→∞




                                        .   .   .   .   .   .
Kick	it	up	a	notch

   Example          (√              )
   Compute lim        4x2 + 17x − 2x .
              x→∞

   Solution
   Same	trick, different	answer:
          (√                 )
      lim     4x2 + 17x − 2x
     x→∞
                    (√              )  √
                                        4x2 + 17 + 2x
           = lim         + 17x − 2x · √
                         4x2
             x→∞                        4x2 + 17x + 2x
                 (4x2 + 17x) − 4x2
           = lim √
             x→∞   4x2 + 17x + 2x
                        17x                     17         17
           = lim √                 = lim √               =
             x→∞   4x 2 + 17x + 2x   x→∞    4 + 17/x + 2   4


                                            .   .   .   .   .   .
Summary




     Infinity	is	a	more	complicated	concept	than	a	single	number.
     There	are	rules	of	thumb, but	there	are	also	exceptions.
     Take	a	two-pronged	approach	to	limits	involving	infinity:
          Look	at	the	expression	to	guess	the	limit.
          Use	limit	rules	and	algebra	to	verify	it.




                                                 .     .   .   .   .   .

Lesson 6: Limits Involving Infinity

  • 1.
    Section 1.6 Limits involving Infinity V63.0121.006/016, Calculus I February 3, 2010 Announcements Office Hours: M,W 1:30–2:30, R 9–10 (CIWW 726) Written Assignment #2 due today. WebAssignments due Tuesday. First Quiz: Friday February 12 in recitation (§§1.1–1.4) . . . . . .
  • 2.
    Recall the definition of limit Definition We write lim f(x) = L x→a and say “the limit of f(x), as x approaches a, equals L” if we can make the values of f(x) arbitrarily close to L (as close to L as we like) by taking x to be sufficiently close to a (on either side of a) but not equal to a. . . . . . .
  • 3.
    Recall the unboundedness problem 1 Recall why lim doesn’t exist. x →0 + x y . .? . L . x . No matter how thin we draw the strip to the right of x = 0, we cannot “capture” the graph inside the box. . . . . . .
  • 4.
    Recall the unboundedness problem 1 Recall why lim doesn’t exist. x →0 + x y . .? . L . x . No matter how thin we draw the strip to the right of x = 0, we cannot “capture” the graph inside the box. . . . . . .
  • 5.
    Recall the unboundedness problem 1 Recall why lim doesn’t exist. x →0 + x y . .? . L . x . No matter how thin we draw the strip to the right of x = 0, we cannot “capture” the graph inside the box. . . . . . .
  • 6.
    Recall the unboundedness problem 1 Recall why lim doesn’t exist. x →0 + x y . .? . L . x . No matter how thin we draw the strip to the right of x = 0, we cannot “capture” the graph inside the box. . . . . . .
  • 7.
    Outline Infinite Limits Vertical Asymptotes Infinite Limits we Know Limit “Laws” with Infinite Limits Indeterminate Limit forms Limits at ∞ Algebraic rates of growth Rationalizing to get a limit . . . . . .
  • 8.
    Infinite Limits Definition The notation y . lim f(x) = ∞ x →a means that values of f(x) can be made arbitrarily large (as large as we please) by taking x sufficiently close to a but not equal to a. . x . . . . . . .
  • 9.
    Infinite Limits Definition The notation y . lim f(x) = ∞ x →a means that values of f(x) can be made arbitrarily large (as large as we please) by taking x sufficiently close to a but not equal to a. “Large” takes the place . x . of “close to L”. . . . . . .
  • 10.
    Infinite Limits Definition The notation y . lim f(x) = ∞ x →a means that values of f(x) can be made arbitrarily large (as large as we please) by taking x sufficiently close to a but not equal to a. “Large” takes the place . x . of “close to L”. . . . . . .
  • 11.
    Infinite Limits Definition The notation y . lim f(x) = ∞ x →a means that values of f(x) can be made arbitrarily large (as large as we please) by taking x sufficiently close to a but not equal to a. “Large” takes the place . x . of “close to L”. . . . . . .
  • 12.
    Infinite Limits Definition The notation y . lim f(x) = ∞ x →a means that values of f(x) can be made arbitrarily large (as large as we please) by taking x sufficiently close to a but not equal to a. “Large” takes the place . x . of “close to L”. . . . . . .
  • 13.
    Infinite Limits Definition The notation y . lim f(x) = ∞ x →a means that values of f(x) can be made arbitrarily large (as large as we please) by taking x sufficiently close to a but not equal to a. “Large” takes the place . x . of “close to L”. . . . . . .
  • 14.
    Infinite Limits Definition The notation y . lim f(x) = ∞ x →a means that values of f(x) can be made arbitrarily large (as large as we please) by taking x sufficiently close to a but not equal to a. “Large” takes the place . x . of “close to L”. . . . . . .
  • 15.
    Infinite Limits Definition The notation y . lim f(x) = ∞ x →a means that values of f(x) can be made arbitrarily large (as large as we please) by taking x sufficiently close to a but not equal to a. “Large” takes the place . x . of “close to L”. . . . . . .
  • 16.
    Negative Infinity Definition The notation lim f(x) = −∞ x →a means that the values of f(x) can be made arbitrarily large negative (as large as we please) by taking x sufficiently close to a but not equal to a. . . . . . .
  • 17.
    Negative Infinity Definition The notation lim f(x) = −∞ x →a means that the values of f(x) can be made arbitrarily large negative (as large as we please) by taking x sufficiently close to a but not equal to a. We call a number large or small based on its absolute value. So −1, 000, 000 is a large (negative) number. . . . . . .
  • 18.
    Vertical Asymptotes Definition The line x = a is called a vertical asymptote of the curve y = f(x) if at least one of the following is true: lim f(x) = ∞ lim f(x) = −∞ x →a x →a lim f(x) = ∞ lim f(x) = −∞ x →a + x →a + lim f(x) = ∞ lim f(x) = −∞ x →a − x →a − . . . . . .
  • 19.
    Infinite Limits we Know y . . . 1 lim + x =∞ x →0 . . . . . . . . x . . . . . . . . . .
  • 20.
    Infinite Limits we Know y . . . 1 lim + x =∞ x →0 . 1 lim = −∞ x →0 − x . . . . . . . x . . . . . . . . . .
  • 21.
    Infinite Limits we Know y . . . 1 lim + x =∞ x →0 . 1 lim = −∞ x →0 − x . . . . . . . x . 1 lim =∞ x →0 x 2 . . . . . . . . .
  • 22.
    Finding limits at trouble spots Example Let x2 + 2 f(x ) = x2 − 3x + 2 Find lim f(x) and lim f(x) for each a at which f is not x →a − x→a+ continuous. . . . . . .
  • 23.
    Finding limits at trouble spots Example Let x2 + 2 f(x ) = x2 − 3x + 2 Find lim f(x) and lim f(x) for each a at which f is not x →a − x→a+ continuous. Solution The denominator factors as (x − 1)(x − 2). We can record the signs of the factors on the number line. . . . . . .
  • 24.
    Use the number line − .. 0 .. . + . x − 1) ( 1 . So . . . . . .
  • 25.
    Use the number line − .. 0 .. . + . x − 1) ( 1 . − . 0 .. . + . x − 2) ( 2 . So . . . . . .
  • 26.
    Use the number line − .. 0 .. . + . x − 1) ( 1 . − . 0 .. . + . x − 2) ( 2 . . + . x2 + 2 ) ( So . . . . . .
  • 27.
    Use the number line − .. 0 .. . + . x − 1) ( 1 . − . 0 .. . + . x − 2) ( 2 . . + . x2 + 2 ) ( . . f .(x) 1 . 2 . So . . . . . .
  • 28.
    Use the number line − .. 0 .. . + . x − 1) ( 1 . − . 0 .. . + . x − 2) ( 2 . . + . x2 + 2 ) ( . + . . f .(x) 1 . 2 . So . . . . . .
  • 29.
    Use the number line − .. 0 .. . + . x − 1) ( 1 . − . 0 .. . + . x − 2) ( 2 . . + . x2 + 2 ) ( . + . ∞. + . f .(x) 1 . 2 . So lim f(x) = +∞ x →1 − . . . . . .
  • 30.
    Use the number line − .. 0 .. . + . x − 1) ( 1 . − . 0 .. . + . x − 2) ( 2 . . + . x2 + 2 ) ( . + . ∞ .. ∞ + − . f .(x) 1 . 2 . So lim f(x) = +∞ x →1 − lim f(x) = −∞ x →1 + . . . . . .
  • 31.
    Use the number line − .. 0 .. . + . x − 1) ( 1 . − . 0 .. . + . x − 2) ( 2 . . + . x2 + 2 ) ( . + . ∞ .. ∞ . + − − . f .(x) 1 . 2 . So lim f(x) = +∞ x →1 − lim f(x) = −∞ x →1 + . . . . . .
  • 32.
    Use the number line − .. 0 .. . + . x − 1) ( 1 . − . 0 .. . + . x − 2) ( 2 . . + . x2 + 2 ) ( . + . ∞ .. ∞ . . ∞ . + − − − f .(x) 1 . 2 . So lim f(x) = +∞ lim f(x) = −∞ x →1 − x →2 − lim f(x) = −∞ x →1 + . . . . . .
  • 33.
    Use the number line − .. 0 .. . + . x − 1) ( 1 . − . 0 .. . + . x − 2) ( 2 . . + . x2 + 2 ) ( . + . ∞ .. ∞ . . ∞ .. ∞ + − − − + f .(x) 1 . 2 . So lim f(x) = +∞ lim f(x) = −∞ x →1 − x →2 − lim f(x) = −∞ lim f(x) = +∞ x →1 + x →2 + . . . . . .
  • 34.
    Use the number line − .. 0 .. . + . x − 1) ( 1 . − . 0 .. . + . x − 2) ( 2 . . + . x2 + 2 ) ( . + . ∞ .. ∞ . . ∞ .. ∞ + − − − + f .(x) 1 . 2 . So lim f(x) = +∞ lim f(x) = −∞ x →1 − x →2 − lim f(x) = −∞ lim f(x) = +∞ x →1 + x →2 + . . . . . .
  • 35.
    Use the number line − .. 0 .. . + . x − 1) ( 1 . − . 0 .. . + . x − 2) ( 2 . . + . x2 + 2 ) ( . + . ∞ .. ∞ . . ∞ .. ∞ + − − − + . + f .(x) 1 . 2 . So lim f(x) = +∞ lim f(x) = −∞ x →1 − x →2 − lim f(x) = −∞ lim f(x) = +∞ x →1 + x →2 + . . . . . .
  • 36.
    In English, now To explain the limit, you can say: “As x → 1− , the numerator approaches 3, and the denominator approaches 0 while remaining positive. So the limit is +∞.” . . . . . .
  • 37.
    The graph so far y . . . . . . . x − . 1 1 . 2 . 3 . . . . . . .
  • 38.
    The graph so far y . . . . . . . x − . 1 1 . 2 . 3 . . . . . . .
  • 39.
    The graph so far y . . . . . . . x − . 1 1 . 2 . 3 . . . . . . .
  • 40.
    The graph so far y . . . . . . . x − . 1 1 . 2 . 3 . . . . . . .
  • 41.
    The graph so far y . . . . . . . x − . 1 1 . 2 . 3 . . . . . . .
  • 42.
    Limit Laws (?) with infinite limits If lim f(x) = ∞ and lim g(x) = ∞, then lim (f(x) + g(x)) = ∞. x →a x→a x →a That is, ∞ . . +∞=∞ If lim f(x) = −∞ and lim g(x) = −∞, then x →a x →a lim (f(x) + g(x)) = −∞. That is, x →a − . . ∞ − ∞ = −∞ . . . . . .
  • 43.
    Rules of Thumb with infinite limits If lim f(x) = ∞ and lim g(x) = ∞, then lim (f(x) + g(x)) = ∞. x →a x→a x →a That is, ∞ . . +∞=∞ If lim f(x) = −∞ and lim g(x) = −∞, then x →a x →a lim (f(x) + g(x)) = −∞. That is, x →a − . . ∞ − ∞ = −∞ . . . . . .
  • 44.
    Rules of Thumb with infinite limits If lim f(x) = L and lim g(x) = ±∞, then x →a x →a lim (f(x) + g(x)) = ±∞. That is, x →a L+∞=∞ . . L − ∞ = −∞ . . . . . .
  • 45.
    Rules of Thumb with infinite limits Kids, don’t try this at home! The product of a finite limit and an infinite limit is infinite if the finite limit is not 0. { ∞. if L > 0 . ·∞= L −∞ if L < 0. { −∞ if L > 0 . . · (−∞) = L ∞ if L < 0. . . . . . .
  • 46.
    Multiplying infinite limits Kids, don’t try this at home! The product of two infinite limits is infinite. ∞·∞=∞ . . ∞ · (−∞) = −∞ (−∞) · (−∞) = ∞ . . . . . .
  • 47.
    Dividing by Infinity Kids, don’t try this at home! The quotient of a finite limit by an infinite limit is zero: L . . =0 ∞ . . . . . .
  • 48.
    Dividing by zero is still not allowed 1 . . =∞ 0 There are examples of such limit forms where the limit is ∞, −∞, undecided between the two, or truly neither. . . . . . .
  • 49.
    Indeterminate Limit forms L Limits of the form are indeterminate. There is no rule for 0 evaluating such a form; the limit must be examined more closely. Consider these: 1 −1 lim =∞ lim = −∞ x→0 x2 x →0 x 2 1 1 lim + x =∞ lim = −∞ x →0 x →0 − x 1 L Worst, lim is of the form , but the limit does not x→0 x sin(1/x) 0 exist, even in the left- or right-hand sense. There are infinitely many vertical asymptotes arbitrarily close to 0! . . . . . .
  • 50.
    Indeterminate Limit forms Limits of the form 0 · ∞ and ∞ − ∞ are also indeterminate. Example 1 The limit lim sin x · is of the form 0 · ∞, but the answer is x →0 + x 1. 1 The limit lim sin2 x · is of the form 0 · ∞, but the answer is x →0 + x 0. 1 The limit lim sin x · 2 is of the form 0 · ∞, but the answer is x →0 + x ∞. Limits of indeterminate forms may or may not “exist.” It will depend on the context. . . . . . .
  • 51.
    Indeterminate forms are like Tug Of War Which side wins depends on which side is stronger. . . . . . .
  • 52.
    Outline Infinite Limits Vertical Asymptotes Infinite Limits we Know Limit “Laws” with Infinite Limits Indeterminate Limit forms Limits at ∞ Algebraic rates of growth Rationalizing to get a limit . . . . . .
  • 53.
    Definition Let f be a function defined on some interval(a, ∞). Then lim f(x) = L x→∞ means that the values of f(x) can be made as close to L as we like, by taking x sufficiently large. . . . . . .
  • 54.
    Definition Let f be a function defined on some interval(a, ∞). Then lim f(x) = L x→∞ means that the values of f(x) can be made as close to L as we like, by taking x sufficiently large. Definition The line y = L is a called a horizontal asymptote of the curve y = f(x) if either lim f(x) = L or lim f(x) = L. x→∞ x→−∞ . . . . . .
  • 55.
    Definition Let f be a function defined on some interval(a, ∞). Then lim f(x) = L x→∞ means that the values of f(x) can be made as close to L as we like, by taking x sufficiently large. Definition The line y = L is a called a horizontal asymptote of the curve y = f(x) if either lim f(x) = L or lim f(x) = L. x→∞ x→−∞ y = L is a horizontal line! . . . . . .
  • 56.
    Basic limits at infinity Theorem Let n be a positive integer. Then 1 lim =0 x→∞ xn 1 lim n = 0 x→−∞ x . . . . . .
  • 57.
    Using the limit laws to compute limits at ∞ Example Find 2x3 + 3x + 1 lim x→∞ 4x3 + 5x2 + 7 if it exists. A does not exist B 1/2 C 0 D ∞ . . . . . .
  • 58.
    Using the limit laws to compute limits at ∞ Example Find 2x3 + 3x + 1 lim x→∞ 4x3 + 5x2 + 7 if it exists. A does not exist B 1/2 C 0 D ∞ . . . . . .
  • 59.
    Solution Factor out the largest power of x from the numerator and denominator.We have 2x3 + 3x + 1 x3 (2 + 3/x2 + 1/x3 ) = 3 4x3 + 5x2 + 7 x (4 + 5/x + 7/x3 ) 2x3 + 3x + 1 2 + 3/x2 + 1/x3 lim = lim x→∞ 4x3 + 5x2 + 7 x→∞ 4 + 5/x + 7/x3 2+0+0 1 = = 4+0+0 2 . . . . . .
  • 60.
    Solution Factor out the largest power of x from the numerator and denominator.We have 2x3 + 3x + 1 x3 (2 + 3/x2 + 1/x3 ) = 3 4x3 + 5x2 + 7 x (4 + 5/x + 7/x3 ) 2x3 + 3x + 1 2 + 3/x2 + 1/x3 lim = lim x→∞ 4x3 + 5x2 + 7 x→∞ 4 + 5/x + 7/x3 2+0+0 1 = = 4+0+0 2 Upshot When finding limits of algebraic expressions at infinity, look at the highest degree terms. . . . . . .
  • 61.
    Another Example Example x Find lim x→∞ x2 +1 . . . . . .
  • 62.
    Another Example Example x Find lim x→∞ x2 +1 Answer The limit is 0. . . . . . .
  • 63.
    Solution Again, factor out the largest power of xfrom the numerator and denominator. We have x x(1) 1 1 = 2 = · x2 + 1 x (1 + 1/x2 ) x 1 + 1/x2 x 1 1 1 1 lim = lim = lim · lim x→∞ x2 + 1 x→∞ x 1 + 1/x2 x→∞ x x→∞ 1 + 1/x2 1 =0· = 0. 1+0 . . . . . .
  • 64.
    Another Example Example x Find lim x→∞ x2 +1 Answer The limit is 0. y . . x . . . . . . .
  • 65.
    Another Example Example x Find lim x→∞ x2 +1 Answer The limit is 0. y . . x . Notice that the graph does cross the asymptote, which contradicts one of the heuristic definitions of asymptote. . . . . . .
  • 66.
    Solution Again, factor out the largest power of xfrom the numerator and denominator. We have x x(1) 1 1 = 2 = · x2 + 1 x (1 + 1/x2 ) x 1 + 1/x2 x 1 1 1 1 lim = lim = lim · lim x→∞ x2 + 1 x→∞ x 1 + 1/x2 x→∞ x x→∞ 1 + 1/x2 1 =0· = 0. 1+0 Remark Had the higher power been in the numerator, the limit would have been ∞. . . . . . .
  • 67.
    Another Example Example Find √ 3x4 + 7 lim x→∞ x2 + 3 . . . . . .
  • 68.
    Another Example Example Find √ √ √ . 3x4 + 7 ∼ . 3x4 = 3x2 √ 3x4 + 7 lim x→∞ x2 + 3 Answer √ The limit is 3. . . . . . .
  • 69.
    Solution √ √ 3x4 + 7 x4 (3 + 7/x4 ) lim = lim 2 x→∞ x2 + 3 x→∞ x (1 + 3/x2 ) √ x2 (3 + 7/x4 ) = lim 2 x→∞ x (1 + 3/x2 ) √ (3 + 7/x4 ) = lim x→∞ 1 + 3/x2 √ 3+0 √ = = 3. 1+0 . . . . . .
  • 70.
    Rationalizing to get a limit Example (√ ) Compute lim 4x2 + 17 − 2x . x→∞ . . . . . .
  • 71.
    Rationalizing to get a limit Example (√ ) Compute lim 4x2 + 17 − 2x . x→∞ Solution This limit is of the form ∞ − ∞, which we cannot use. So we rationalize the numerator (the denominator is 1) to get an expression that we can use the limit laws on. (√ ) (√ ) √4x2 + 17 + 2x lim 4x2 + 17 − 2x = lim 4x2 + 17 − 2x · √ x→∞ x→∞ 4x2 + 17 + 2x (4x 2 + 17) − 4x2 = lim √ x→∞ 4x2 + 17 + 2x 17 = lim √ =0 x→∞ 4x 2 + 17 + 2x . . . . . .
  • 72.
    Kick it up a notch Example (√ ) Compute lim 4x2 + 17x − 2x . x→∞ . . . . . .
  • 73.
    Kick it up a notch Example (√ ) Compute lim 4x2 + 17x − 2x . x→∞ Solution Same trick, different answer: (√ ) lim 4x2 + 17x − 2x x→∞ (√ ) √ 4x2 + 17 + 2x = lim + 17x − 2x · √ 4x2 x→∞ 4x2 + 17x + 2x (4x2 + 17x) − 4x2 = lim √ x→∞ 4x2 + 17x + 2x 17x 17 17 = lim √ = lim √ = x→∞ 4x 2 + 17x + 2x x→∞ 4 + 17/x + 2 4 . . . . . .
  • 74.
    Summary Infinity is a more complicated concept than a single number. There are rules of thumb, but there are also exceptions. Take a two-pronged approach to limits involving infinity: Look at the expression to guess the limit. Use limit rules and algebra to verify it. . . . . . .