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Circuits and Ohm’s Law Physics 102:   Lecture 05
Summary of Last Time ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],Summary of Today
Electric   Terminology ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Physical Resistor ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],A L
Preflight 5.1 ,[object Object],[object Object],[object Object],[object Object],2 1
Comparison: Capacitors  vs.  Resistors ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
[object Object],[object Object],[object Object],[object Object],Simple Circuit R  I I Example I = V/R = 3 Amps
Resistors in Series ,[object Object],[object Object],[object Object],[object Object],R eq  = R 1  + R 2 R R = 2R
Resistors in Series: “Proof” that R eq =R 1 +R 2 ,[object Object],[object Object],[object Object],[object Object],[object Object],R 1 R 2 R eq R eq  =  V eq   =  V 1  + V 2   = R 1  + R 2   I eq   I eq
Preflight 5.3 ,[object Object],[object Object],[object Object],[object Object],R 1 =1   0 R 10 =10 
Compare V 1  the voltage across R 1 , with V 10  the voltage across R 10 . 1. V 1 >V 10 2. V 1 =V 10 3.   V 1 <V 10 ACT: Series Circuit R 1 =1   0 R 10 =10 
Practice: Resistors in Series ,[object Object],[object Object],[object Object],[object Object],= 11   =  ε 0  = 22 Volts  = V 12 /R 12  = 2 Amps ,[object Object],[object Object],[object Object],= 2 x 1 = 2 Volts  = 2 x 10 = 20 Volts  Check: V 1  + V 2  = V 12  ? Simplify (R 1  and R 2  in series): Example R 12  0 R 1 =1   0 R 2 =10  R 1 =1   0 R 2 =10 
Resistors in Parallel ,[object Object],[object Object],[object Object],R R = R/2 1/R eq  = 1/R 1  + 1/R 2
Resistors in Parallel ,[object Object],[object Object],[object Object],[object Object],[object Object],R eq R 2 R 1
Preflight 5.5 ,[object Object],[object Object],[object Object],[object Object],What happens to the current through the battery? (1) Increases (2) Remains Same (3) Decreases ACT: Parallel Circuit
Practice:  Resistors in Parallel ,[object Object],[object Object],[object Object],[object Object],[object Object],R 23  = 12   = 60 Volts = V 23  /R 23  = 5 Amps Simplify: R 2  and R 3  are in parallel Example R 2 R 3  R 23 
Johnny “Danger” Powells uses one power strip to plug in his microwave, coffee pot, space heater, toaster, and guitar amplifier all into one outlet. Toaster This is dangerous because… (By the way, power strips are wired in parallel.) ACT: Your Kitchen 1.  The resistance of the kitchen circuit is too high.   2.  The voltage across the kitchen circuit is too high.   3.  The current in the kitchen circuit is too high.   Coffee Pot Microwave 10 A 5 A 10 A 25 A
ACT/Preflight 5.6, 5.7 ,[object Object],[object Object],[object Object],[object Object],1 2 3 Which configuration has the  largest  resistance?
Try it! R 1 R 2 R 3 Calculate current through each resistor. R 1  = 10   , R 2  = 20   R 3  = 30     V ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],: R 23  = 12   : R 123  = 22   R 1  : I 123  = 44 V/22   A Power delivered by battery? P=IV = 2  44 = 88W Example R 123  R 23 
Try it! (cont.) Calculate current through each resistor. R 1  = 10   , R 2  = 20   R 3  = 30     V ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object], : I 23  = 2 A : V 23  = I 23  R 23  = 24 V I 2  = V 2 /R 2  =24/20=1.2A I 3  = V 3 /R 3  =24/30=0.8A Example R 1 R 2 R 3 R 123  R 1 R 23 
Voltage Current Resistance Series Parallel Summary Different  for each resistor. V total  = V 1  + V 2   Increases R eq  = R 1  + R 2   Same  for each resistor I total  = I 1  = I 2   Same  for each resistor. V total  = V 1  = V 2   Decreases 1/R eq  = 1/R 1  + 1/R 2   Wiring Each resistor on the  same   wire. Each resistor on a  different   wire. Different  for each resistor I total  = I 1  + I 2   R 1 R 2 R 1 R 2

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Lect05 handout

  • 1. Circuits and Ohm’s Law Physics 102: Lecture 05
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  • 11. Compare V 1 the voltage across R 1 , with V 10 the voltage across R 10 . 1. V 1 >V 10 2. V 1 =V 10 3. V 1 <V 10 ACT: Series Circuit R 1 =1   0 R 10 =10 
  • 12.
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  • 17. Johnny “Danger” Powells uses one power strip to plug in his microwave, coffee pot, space heater, toaster, and guitar amplifier all into one outlet. Toaster This is dangerous because… (By the way, power strips are wired in parallel.) ACT: Your Kitchen 1. The resistance of the kitchen circuit is too high. 2. The voltage across the kitchen circuit is too high. 3. The current in the kitchen circuit is too high. Coffee Pot Microwave 10 A 5 A 10 A 25 A
  • 18.
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  • 21. Voltage Current Resistance Series Parallel Summary Different for each resistor. V total = V 1 + V 2 Increases R eq = R 1 + R 2 Same for each resistor I total = I 1 = I 2 Same for each resistor. V total = V 1 = V 2 Decreases 1/R eq = 1/R 1 + 1/R 2 Wiring Each resistor on the same wire. Each resistor on a different wire. Different for each resistor I total = I 1 + I 2 R 1 R 2 R 1 R 2

Editor's Notes

  1. 1
  2. Resistance Demo 1055 Ramp with balls as resistor (Ohm’s Law)—change height Ohm’s Law Demo 1228 Water resistance, effect of A, L on flow
  3. Demo 1091: lots of appliances to blow fuse—do this while ACT is going on