This document contains several HSPICE examples demonstrating circuit analysis techniques, including: 1) Voltage divider, subcircuit, and calling subcircuit simulations; 2) Switching circuits using transmission line gates; 3) Pulse and triangle wave generator circuits; 4) Dependent source examples using VCCS and CCVS; 5) Ideal transformer and rectifier with filter simulations; 6) Mutual inductor, ideal op-amp, and identifying op-amp parameters; 7) Characteristic curve plotting for diode and maximum power transfer analysis.

1. HSPICE
Essential Examples
Dariush Naseh
Shahid Beheshti University of Tehran

2. Voltage Divider
** Voltage Divider **
R1 in out 1K
R2 out 0 1k
V1 in 0 DC 4V
.OP
.END
R1
1k
R2
1k
V1
4v
0
outin
Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

3. Subcircuit
** Subcircuit Voltage Divider**
.SUBCKT BLK1 input output
R1 input 1 1k
R2 1 output 1K
.ENDS
X1 in out BLK1
X2 out 0 BLK1
V1 in 0 DC 4v
.OP
.END
V1
4v
BLK1
input output
BLK1
inputoutput
0
Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

4. To Call a Subcircuit
** Call subcircuit **
.INCLUDE "z:Voltage Divider.sp"
X1 in out BLK
X2 out 0 BLK
VDC in 0 DC 4V
.OP
.END
Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

5. Switch tclose
** RC switch **
R1 2 3 1k
C1 3 0 1u IC=0
V1 1 0 DC 1v
G1 1 2 VCR PWL(1) 4 5 0 100MEG 1 0.1m
V2 4 5 PWL 0 0 4.9999m 0 5m 1
.TRAN 1n 10m 0.01m
.END
R1
1k
C1
1u
IC = 0
U1
TCLOSE = 5m
1 2
V1
1v
0
1 32
Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

6. Other SW tclose & Creating Step
Function
** RC Switch 1 **
I1 0 V1 PWL 0 0 0.0000001 1
C1 V1 0 1 IC=0
R1 V1 0 1
G1 V1 V2 VCR PWL(1) v4 0 0 100000meg 1 0.001m
R2 V2 0 1
G2 V2 v3 VCR PWL(1) v5 0 0 100000meg 1 0.001m
C2 V3 0 1 IC=0
V1 V4 0 PWL 0 0 10 0 10.000001 1
V2 V5 0 PWL 0 0 15 0 15.000001 1
.TRAN 10m 20
.END
I1
1A
C1
1
IC = 0
R1
1
U1
TCLOSE = 10s
1 2
R2
1
U2
TCLOSE = 15s
1 2
C2
1
IC = 0
0
V1 V2 V3
Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

7. Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

8. Pulse Generator
.TITLE pulse wave
Vin in 0 PULSE 1 -1 0 1n 1n 1m 2m
R1 in out 1k
C1 out 0 100n
.TRAN 10u 10m
.PROBE output=par('V(out)')
.PROBE input=par('V(in)')
.END
C2
100n
out
R2
1k
in
V3
TD = 0
TF = 1n
PW = 1m
PER = 2m
V1 = 1
TR = 1n
V2 = -1
0
Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

9. Triangle Pulse Generator
.TITLE triangle wave
V1 in 0 PWL 0ms 0 5ms 15v 15ms -15 20ms 0
R1 in out 1k
D1 A out d1n4734
D2 A 0 d1n4734
.MODEL d1N4734 D Is=1.085f Rs=.7945 N=1 Xti=3 Eg=1.11 Cjo=157p M=.2966
+ Vj=.75 Fc=.5 Bv=5.6 Ibv=.37157 Nbv=.64726
.TRAN 20us 20ms
.PROBE vin=par('v(in)')
.PROBE Vout=par('v(out)')
.END
V1
R1
1k
D1
D1N4734
D2
D1N4734
in
A
out
0
Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

10. Dependent Sources
** VCCS **
G1 0 1 VCCS 0 2 2
R1 1 2 1
I1 0 2 DC 1
R2 2 3 1
V1 3 0 DC 2
.OP
.END
V1
2v
R1
1
R2
1
+
-
G1
GAIN = 2
I1
1A
0
0
1 32
0
2
Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

11. Dependent sourse , another Ex.
(VCCS & CCVS)
** Other example in VCCS and CCCS **
I1 V1 V3 DC 1
R3 A V2 1
R1 V2 V3 1
R2 V3 0 1
R4 v1 V4 1
V1 V2 0 2
H1 V4 0 CCVS Vc 4
Vc V1 A DC 0
G1 V2 V4 VCCS V3 V2 2
.OP
.END
V1
2V
+
-
G1
GAIN = 2
R1
1
R2
1
V3
I1
1AR3
1
V2
R4
1
V4
H1
GAIN = 4 0
V1 A
V2
V3
Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

12. Ideal Transformer
** Rectifire with RC Filter **
E1 3 4 TRANSFORMER 1 2 10
Vin 1 2 SIN 0 318 50 0 0 0
D1 3 out d1n4007
D2 0 3 d1n4007
D3 4 out d1n4007
D4 0 4 d1n4007
.MODEL d1n4007 D IS=1.09774E-008 n=1.78309 Rs=0.0414388
+ Eg=1.11 Xti=3 Cjo=2.8173E-011 Vj=0.50772
+ m=0.318974 Fc=0.5 TT=9.85376E-006 Bv=1100 Ibv=0.1 Kf=0
R1 Out 0 1k
C1 out 0 220u
.TRAN 0.1m 1000m START=900m
.PROBE IDiode=par('I(D1)')
.PROBE Vtrans=par('V(3)-V(4)')
.END
V1
FREQ = 50Hz
VAMPL = 318v
TX1 D1
D1N4007
D2
D1N4007
D3
D1N4007
D4
D1N4007
R1
1k
C1
220uF
Out3
4
1
2
Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

13. Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

14. Linear mutual inductor
.Title Linear mutual inductor
R1 1 2 2
L1 2 0 8
L2 3 0 200
K1 L1 L2 1
R3 3 0 200
Vs 1 0 AC 50 0
.AC DEC 200 100 100k
.PROBE vtarget=par('V(2)')
.PROBE Phase=par('VP(2)')
.END
V1
50v
ACPHASE = 0
R1
2
L1
8
L2
200 R2
200
0
1 2 3
K
COUPLING=
K1
COUPLING = 1
Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

15. Ideal Op-Amp
.TITLE Ideal Op-Amp
.INCLUDE "Z:7805.sp"
Vi in 0 DC 15v
x1 in 2 out LM7805
R1 3 0 1k
R2 1 0 1k
R3 out 1 2k
E1 2 3 OPAMP 1 2
.TRAN 0.1m 10m
.END
V1
15v
U1
OPAMP
+
-
OUT
R1
1k
R2
1k
R3
2k
U2
LM7805C
IN
1
OUT
2
GND
3
0
in out
1
2
0
0
3
Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

16. Identifying Rin & Rout & Av in OPAMP
.TITLE op-amp
V1 2 0 DC 1
V2 1 0 DC 100m
R1 2 4 500
R2 1 3 5k
R3 3 0 10k
R4 4 3 100K **Rin=100k**
R5 4 6 1k
R6 5 6 1k ** Rout=1k**
R7 6 0 1k
E1 5 0 OPAMP 3 4 100K **Av=100K**
.DC V1 LIN 499 1m 500m
.PROBE Vout=par('v(6)')
.END
V1
1v
V2
100m
U1
OPAMP
+
-
OUT
0
0
R1
500
R2
5k
R3
10k
0
R5
1k
R7
1k
0
6
31
42
Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

17. Plotting characteristic curve of Doid
(source sweeping)
** characteristic curve of Diod **
R1 in out 1k
D1 out 0 d1n4148
V1 in 0 DC 1v
.MODEL d1n4148 D Is=2.682n N=1.836 Rs=.5664 Xti=3 Eg=1.11 Cjo=4p
+ M=.3333 Vj=.5 Fc=.5 Bv=100 Ibv=100u Tt=11.54n
.DC V1 LIN 300 0 30 SWEEP TEMP LIN 2 25 50
.PROBE IDiode=par('I(D1)')
.END
D1
D1N4148
V1
1v
R1
1k
0
outin
Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

18. Maximum Power Transfer
(elements sweeping)
** Maxium Power Transfer**
.PARAM r=1
R1 in out r
R2 out 0 10k
V1 in 0 DC 10v
.DC r LIN 400 8k 12k
.PLOT P(R1)
.END
V1
10v
R1
{r}
0
outin
PARAMETERS:
r = 1k
R2
10k
Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

19. Thevenin Equivqlent & IF-ELSE
Structure
.TITLE Thevenin equivqlent
R1 1 2 1
R2 2 3 1
R3 2 4 1
VSENSE 4 0 DC 0
H1 3 0 CCVS VSENSE 0.5
.PARAM k=0
.IF(K==1)
{
Vin 1 0 DC 1v
.TRAN 0.1m 10m
.PROBE Rin=par('-V(1)/I(Vin)')
}
.ELSEIF(K==0)
{
Vin 1 0 DC 0
.TRAN 0.1m 10m
.PROBE ISC=par('I(Vin)')
}
.ENDIF
.END
R1
1
R2
1
R3
1
H1
GAIN = 0.5
0
2 31
0
VSENSE
4
Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

20. .SENS Command
Sensitivity of element’s variation
.TITLE Self Bias Sensivity ro Vcc
VCC VCC 0 DC 15v
RB1 VCC B 3.9k
RB2 B 0 1.5k
RC VCC C 470
RE E 0 180
Q1 C B E BC107A
.MODEL BC107A NPN Is=7.049f Xti=3 Eg=1.11 Vaf=116.3 Bf=375.5 Ise=7.049f
+ Ne=1.281 Ikf=4.589 Nk=.5 Xtb=1.5 Br=2.611 Isc=121.7p Nc=1.865
+ Ikr=5.313 Rc=1.464 Cjc=5.38p Mjc=.329 Vjc=.6218 Fc=.5 Cje=11.5p
+ Mje=.2717 Vje=.5 Tr=10n Tf=451p Itf=6.194 Xtf=17.43 Vtf=10
.OP
.SENS IC(Q1)
.END
VCC
15v
Q1
BC107A
RC
470
RB1
3.9k
RE
180
RB2
1.5k
0
00
dc sensitivities of output ic(q1)
element element element normalized
name value sensitivity sensitivity
(amps/unit) (amps/percent)
0:rb1 3.9000k -4.1551u -162.0503u
0:rb2 1.5000k 10.4832u 157.2486u
0:rc 470.0000 -101.2284n -475.7735n
0:re 180.0000 -99.2755u -178.6959u
0:vcc 15.0000 1.4890m 223.3519u
Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

21. Sweeping the specifications of models
.TITLE DC sweep
.PARAM k=5.6
Vi in 0 1v
R1 in out 1k
D1 0 out d1n4734
.MODEL d1N4734 D Is=1.085f Rs=.7945 N=1 Xti=3 Eg=1.11 Cjo=157p
+ M=.2966 Vj=.75 Fc=.5 Bv=k Ibv=.37157 Nbv=.64726
.DC Vi LIN 300 -15 +15 SWEEP k LIN 6 1.6 6.6
.PROBE target=par('V(out)')
.END
D1
D1N4734
R1
1kV1
1v
0
outin
Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

22. Output characteristic curve of BJT
.TITLE Curve
IDC 0 B DC 1m
VDC C 0 DC 5V
V1 E 0 DC 0
Q1 C B E BC107A
.MODEL BC107A NPN Is=7.049f Xti=3 Eg=1.11 Vaf=116.3 Bf=375.5 Ise=7.049f
+ Ne=1.281 Ikf=4.589 Nk=.5 Xtb=1.5 Br=2.611 Isc=121.7p Nc=1.865
+ Ikr=5.313 Rc=1.464 Cjc=5.38p Mjc=.329 Vjc=.6218 Fc=.5 Cje=11.5p
+ Mje=.2717 Vje=.5 Tr=10n Tf=451p Itf=6.194 Xtf=17.43 Vtf=10
.DC VDC LIN 200 0 20 SWEEP IDC LIN 5 0 40u
.PROBE I=par('IC(Q1)')
.END
IDC
1m
Q1
BC107A VDC
5v
00 0
Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

23. ICQ-B Curve in BJT
.TITLE Beta
IDC 0 B DC 1m
VDC C 0 DC 5v
V1 E 0 DC 0
Q1 C B E BC107A
.MODEL BC107A NPN Is=7.049f Xti=3 Eg=1.11 Vaf=116.3 Bf=375.5 Ise=7.049f
+ Ne=1.281 Ikf=4.589 Nk=.5 Xtb=1.5 Br=2.611 Isc=121.7p Nc=1.865
+ Ikr=5.313 Rc=1.464 Cjc=5.38p Mjc=.329 Vjc=.6218 Fc=.5 Cje=11.5p
+ Mje=.2717 Vje=.5 Tr=10n Tf=451p Itf=6.194 Xtf=17.43 Vtf=10
.DC IDC LIN 10000 1u 10m SWEEP VDC LIN 3 5 15
.PROBE Beta=par('IC(Q1)/IB(Q1)')
.PROBE ICollector=par('(IC(Q1))')
.END
IDC
1m
Q1
BC107A VDC
5v
00 0
Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

24. HFE & Transition Frequency of BJT
** HFE and transition frequency **
.PARAM k=1u
VDC C 0 DC 5v
IDC 0 B DC k AC 1 0
V1 E 0 DC 0
Q1 C B E BC107A
.MODEL BC107A NPN Is=7.049f Xti=3 Eg=1.11 Vaf=116.3 Bf=375.5 Ise=7.049f
+ Ne=1.281 Ikf=4.589 Nk=.5 Xtb=1.5 Br=2.611 Isc=121.7p Nc=1.865
+ Ikr=5.313 Rc=1.464 Cjc=5.38p Mjc=.329 Vjc=.6218 Fc=.5 Cje=11.5p
+ Mje=.2717 Vje=.5 Tr=10n Tf=451p Itf=6.194 Xtf=17.43 Vtf=10
.AC DEC 200 1 1G SWEEP K LIN 3 5u 15u
.probe beta=par('IC(Q1)/IB(Q1)')
.end
IDC
1u
Q1
BC107A VDC
5v
00 0
Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

25. Wien Bridge Oscillator
.TITLE wien brigde oscillator
.INCLUDE "Z:LM741.sp"
Vcc Vcc 0 DC 12v
Vee 0 Vee DC 12v
X1 3 2 Vcc Vee 1 LM741
R1 5 2 18k
R2 2 0 10k
R3 3 4 1.6k
R4 3 0 1.6k
R5 1 5 4.7k
C1 4 1 10n
C2 3 0 10n
D1 5 1 d1n4148
D2 1 5 d1n4148
I1 0 3 PWL 0 0 1us 1mA 4us 1mA 4.0001us 0
.MODEL d1n4148 D Is=2.682n N=1.836 Rs=.5664 Ikf=44.17m Xti=3 Eg=1.11 Cjo=4p
+ M=.3333 Vj=.5 Fc=.5 Isr=1.565n Nr=2 Bv=100 Ibv=100u Tt=11.54n
.TRAN 1n 2m
.PROBE vout=par('V(1)')
.END
U2
LM741/NS
+
3
-
2
V+
7
V-
4
OUT
6
OS2
5
OS1
1
R1
18k
R2
10k
R3
1.6k
R4
1.6k
C1
10n
C2
10n
0
00
2
3
4
1
V1
12v
V2
12v
0
Vcc
Vee
Vee
Vcc
R5
4.7k
D1
D1N4148
D2
D1N4148
5
I1
0
Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

26. Power Amplifiers in B-Class and
Fourier Analysis
.TITLE Power amplifire in B-Class
VCC VCC 0 12v
Vee 0 Vee 12v
Q1 Vcc B out BD135
Q2 Vee B out BD136
RL out 0 100
R1 in B 50
Vin in 0 Sin 0 8V 10KHz 0 0 0
.MODEL BD135 NPN IS = 4.815E-14 NF = 0.9897 ISE = 1.389E-14 NE = 1.6 BF = 124.2
+ IKF = 1.6 VAF = 222 NR = 0.9895 ISC = 1.295E-13 NC = 1.183
+ BR = 13.26 IKR = 0.29 VAR = 81.4 RB = 0.5 IRB = 1E-06 RBM = 0.5
+ RE = 0.165 RC = 0.096 XTB = 0 EG = 1.11 XTI = 3 CJE = 1.243E-10
+ VJE = 0.7313 MJE = 0.3476 TF = 6.478E-10 XTF = 29 VTF = 2.648
+ ITF = 3.35 PTF = 0 CJC = 3.04E-11 VJC = 0.5642 MJC = 0.4371
+ XCJC = 0.15 TR = 1E-32 CJS = 0 VJS = 0.75 MJS = 0.333 FC = 0.9359
.MODEL BD136 PNP IS = 7.401E-14 NF = 0.9938 ISE = 4.104E-16 NE = 1.054 BF = 336.5
+ IKF = 0.1689 VAF = 22.47 NR = 0.9913 ISC = 1.290E-14 NC = 1.100
+ BR = 13.91 IKR = 9.888E-2 VAR = 30.00 RB = 0.500 IRB = 1E-06
+ RBM = 0.500 RE = 0.208 RC = 5.526E-02 XTB = 0 EG = 1.11 XTI = 3
+ CJE = 1.066E-10 VJE = 0.6900 MJE = 0.3676 TF = 2.578E-10 XTF = 13.56
+ VTF = 2.366 ITF = 1.3040 PTF = 0 CJC = 5.234E-11 VJC = 0.6431
+ MJC = 0.4436 XCJC = 0.440 TR = 1E-25 CJS = 0 VJS = 0.75 MJS = 0.333
+ FC = 0.990
.TRAN 0.1u 1m START=0.8m
.PROBE output=par('v(out)')
.FOUR 10k v(out)
.END
Q1
BD135
Q2
BD136
Vcc
12
Vee
12RL
100
R1
50
B
Vcc
Vee 0
out
Vee
Vcc
0
V3
FREQ = 10k
VAMPL = 8v
VOFF = 0
0
in
Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

27. Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

28. .MEASURE Command
(Calculation of output DC Level)
.TLTEL CE
VCC VCC 0 DC 12v
RB1 VCC B 100K
RB2 B 0 27k
RC VCC C 4.7k
RE1 E 1 47
RE2 1 0 3.9k
RS in 2 50
CB 1 0 470u
CC 2 B 10u
Q1 C B E BC107A
.MODEL BC107A NPN Is=7.049f Xti=3 Eg=1.11 Vaf=116.3 Bf=375.5 Ise=7.049f
+ Ne=1.281 Ikf=4.589 Nk=.5 Xtb=1.5 Br=2.611 Isc=121.7p Nc=1.865
+ Ikr=5.313 Rc=1.464 Cjc=5.38p Mjc=.329 Vjc=.6218 Fc=.5 Cje=11.5p
+ Mje=.2717 Vje=.5 Tr=10n Tf=451p Itf=6.194 Xtf=17.43 Vtf=10
Vin in 0 0 AC 1 Sin 0 5mV 10kHz
.op
.AC DEC 200 1 100MEG
.TRAN 0.1us 1ms
.PROBE AC Gain=par('VDB(c)')
.PROBE AC Phase=par('-ABS(VP(c))')
.MEASURE TRAN val avg v(c) from=0 to=0.1ms
.PROBE TRAN output=par('V(c)-val')
.PROBE AC Rin=par('V(in)/I(Rs)')
.END
VCC
12vRC
4.7k
RB1
4.7k
RB2
27k
RE1
47
Q1
BC107A
RE2
3.9k
RS
50
C1
10u
V2
FREQ = 10k
VAMPL = 5m
VOFF = 0
AC = 1
00
B
C2
470u
0
1
0in 2
Vcc
0
Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

29. Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

30. Example of .MEASURE Command
WHEN-FIND
TITLE measure
Vin in 0 PWL 0 0 1ns 1v 10ms 1 10.0000001m 0
R1 in out 1k
C1 out 0 1u
.TRAN 20u 20ms
.MEASURE TRAN val1 FIND I(R1) AT=1m
.MEASURE TRAN Val2 WHEN V(out)='0.5' CROSS=2
.PROBE input=par('V(in)')
.PROBE output=par('V(out)')
.END
R1
1k
C1
1u
0
V1
outin
Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

31. Square wave, MEASURMET of RISE TIME
(MIN,MAX,PP &TRIG… TARG… )
.TITLE Rise Time
Vi in 0 PULSE 1 -1 0 1p 1p 1m 2m
R1 in out 1k
C1 out 0 100n
.TRAN 0.1u 10m
.MEASURE MAX MAX V(out) FROM=6.1m TO=8m
.MEASURE MIN MIN V(out) FROM=6.1m To=8m
.MEASURE PP PP V(out) FROM=6.1m TO=8m
.MEASURE TRAN T1 TRIG V(in) val=1 TD=6.1ms RISE=1 TARG V(out) val=0.1*PP+MIN TD=6.1ms RISE=1
.MEASURE TRAN T2 TRIG V(in) val=1 TD=6.1ms RISE=1 TARG V(out) val=0.9*PP+MIN TD=6.1ms RISE=1
.MEASURE TRAN Tr=param'T2-T1'
.PROBE in=par('v(in)')
.PROBE OUT=par('V(out)')
.END
Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

32. .PZ Command
Pole & Zero
.TITLE Pole and zero
V1 in 0 DC 0 AC 1
R1 in out 1k
C1 out 0 100n
.AC DEC 200 1 100k
.PROBE gain=par('VDB(out)')
.PROBE pahse=par('VP(out)')
.PZ v(out) v1
.END
V2
1Vac
0Vdc
out
0
R1
1k
C1
100n
in
Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

33. .TF Command
(Transfer Function)
.TITLE Diffrentional Amplifire
VCC VCC 0 12v
VEE 0 VEE 12v
V1 in 0 DC 0
Q1 1 1 VCC BC177
Q2 2 1 VCC BC177
Q3 1 in 3 BC107A
Q4 2 0 3 BC107A
Q5 3 4 6 BC107A
R1 4 VEE 1.8k
R2 4 0 22k
R3 6 VEE 100
.MODEL BC107A NPN Is=7.049f Xti=3 Eg=1.11 Vaf=116.3 Bf=375.5 Ise=7.049f
+ Ne=1.281 Ikf=4.589 Nk=.5 Xtb=1.5 Br=2.611 Isc=121.7p Nc=1.865
+ Ikr=5.313 Rc=1.464 Cjc=5.38p Mjc=.329 Vjc=.6218 Fc=.5 Cje=11.5p
+ Mje=.2717 Vje=.5 Tr=10n Tf=451p Itf=6.194 Xtf=17.43 Vtf=10
.MODEL BC177 PNP Is=336.7f Xti=3 Eg=1.11 Vaf=55.46 Bf=154.4 Ise=412.1f
+ Ne=1.429 Ikf=.2994 Nk=.7028 Xtb=1.5 Br=3.99 Isc=1.03n Nc=1.958
+ Ikr=9.726 Rc=1.833 Cjc=11p Mjc=.2223 Vjc=.5 Fc=.5 Cje=33p
+ Mje=.3333 Vje=.5 Tr=10n Tf=847.7p Itf=2.198 Xtf=23.26 Vtf=10
.OP
.TF v(2) v1
.END
Q1
BC177
Q2
BC177
Q3
BC107A
Q4
BC107A
Q5
BC107A
V1
12
V2
12
VEE
VCC
R1
100
R2
1.8k
R3
22k
VEE
0
VCC
0
V3VAC=1
VDC=0
0
Vin
Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016

34. LAPLACE Transform Simulation
TITLE LAPLACE
ERC 2 0 LAPLACE 1 0 1/1,1E-3
Vin 1 0 DC 0 AC 1 sin 0 1 159
.AC DEC 200 0.1 100MEG
.TRAN 0.6u 60m
.PROBE TRAN out=par('V(2)')
.PROBE AC ampel=par('VDB(2)')
.PROBE AC phase=par('VP(2)')
.MEASURE AC MAX FIND VDB(2) AT=1
.MEASURE AC cutoff WHEN vDB(2)='MAX-3'
.END
V2
R1
1k
0
C1
1u
Dariush Naseh - Shahid Beheshti University
of Tehran
10/2/2016