OBJECTIVES
Draw the graphs of a quadratic function.
Determine and identify the domain, range,
intercepts, axis of symmetry, and the opening
of the parabola.
Show appreciation of the graph of quadratic
function through active participation in classroom
activities
Graphing
Quadratic
Functions
Quadratic Function
A quadratic function is a function that can
be written in the form
f(x) = ax2 + bx + c
For real numbers a, b, and c, with a ≠ 0.
The graph of every quadratic function is a parabola.
The vertex is the lowest point on a parabola that opens
upward or the highest point on a parabola that opens
downward.
A parabola can open upward or downward.
If the parabola opens upward, the lowest
point is called the vertex (minimum).
If the parabola opens downward, the
vertex is the highest point (maximum).
NOTE: if the parabola opens left or right it is not a function!
y
x
Vertex
Vertex
The parabola will open
downward when the value of 𝒂
is negative.
The parabola will open upward
when the value of 𝒂 is positive.
y
x
a > 0
a < 0
a ¹ 0
Graphs of quadratic equations have symmetry about a line
through the vertex. This line is called the axis of symmetry.
The sign of a, the numerical coefficient of the squared term,
determines whether the parabola will open upward or
downward.
Vertex of a Parabola
The parabola represented by the function f(x) = ax2 + bx + c will have
vertex
Since we often find the y-coordinate of the vertex by substituting the x-
coordinate of the vertex into f(x), the vertex may also be designated as





 

a
b
ac
a
b
4
4
,
2
2













a
b
f
a
b
2
,
2
Axis of Symmetry
For a quadratic function of the form f(x) = ax2 + bx +
c, the equation of the axis of symmetry of the
parabola is
a
b
x
2


x-Intercepts of a Parabola
To find the x-intercepts (if there are any) of a quadratic
function, solve the equation ax2 + bx + c = 0 for x.
This equation may be solved by factoring, by using the
quadratic formula, or by completing the square.
y
x
Y-intercept of a Quadratic Function
y = 2x2
- 4x -1 Y-axis
The y-intercept of a
Quadratic function can
Be found when x = 0.
y = 2x2
- 4x -1
= 2 0
( )2
- 4(0) -1
= 0 - 0 -1
= -1
The constant term is always the y-intercept.
STEP 1: Find the Axis of symmetry
( )
4
1
2 2 2
b
x
a
-
= = =
y
x
Graph : y = 2x2
- 4x -1
Graphing a Quadratic Function
STEP 2: Find the vertex
Substitute in x = 1 to find the y – y-
value of the vertex.
( ) ( )
2
2 1 4 1 1 3
y = - - = - Vertex : 1, - 3
( )
x =1
5
–1
( ) ( )
2
2 3 4 3 1 5
y = - - =
STEP 3: Find two other points and reflect
them across the Axis of symmetry. Then
connect the five points with a smooth
curve.
y
x
( ) ( )
2
2 2 4 2 1 1
y = - - = -
3
2
y
x
Example Consider the quadratic function
y = -x2 + 8x – 12.
a. Determine whether the parabola opens upward or downward.
b. Find the y-intercept.
c. Find the vertex.
d. Find the axis of symmetry.
e. Find the x-intercepts, if any.
f. Draw the graph.
a. Since a is -1, which is less than 0, the parabola opens downward.
b. To find the y-intercept, set x = 0 and solve for y.
12
12
)
0
(
8
)
0
( 2






y
The y-intercept is (0, 12)
Example Consider the quadratic function
y = -x2 + 8x – 12.
c. First, find the x-coordinate, then find the y-coordinate of the vertex. From the
function, a = -1, b = 8, and c = -12.
continued
4
)
1
(
2
8
2





a
b
x
Since the x-coordinate of the vertex is not a fraction, we will substitute x = 4 into the
original function to determine the y-coordinate of the vertex.
4
12
32
16
12
)
4
(
8
)
4
(
12
8
2
2













y
x
x
y
The vertex is (4, 4).
d. Since the axis of symmetry is a vertical line through
the vertex, the equation is found using the same formula
used to find the x-coordinate of the vertex. Thus, the
equation of the axis of symmetry is x = 4.
e. To find the x-intercepts, set y = 0.
2
x
6
0
2
or
0
6
0
)
2
)(
6
(
0
12
8
2












x
x
x
x
x
x
x
Thus, the x-intercepts are (2, 0) and (6, 0). These values could also be
found by the quadratic formula (or by completing the square).
f. Draw the graph.

Graphing Quadratic Functions.pptx

  • 2.
    OBJECTIVES Draw the graphsof a quadratic function. Determine and identify the domain, range, intercepts, axis of symmetry, and the opening of the parabola. Show appreciation of the graph of quadratic function through active participation in classroom activities
  • 4.
  • 5.
    Quadratic Function A quadraticfunction is a function that can be written in the form f(x) = ax2 + bx + c For real numbers a, b, and c, with a ≠ 0.
  • 6.
    The graph ofevery quadratic function is a parabola. The vertex is the lowest point on a parabola that opens upward or the highest point on a parabola that opens downward.
  • 7.
    A parabola canopen upward or downward. If the parabola opens upward, the lowest point is called the vertex (minimum). If the parabola opens downward, the vertex is the highest point (maximum). NOTE: if the parabola opens left or right it is not a function! y x Vertex Vertex
  • 8.
    The parabola willopen downward when the value of 𝒂 is negative. The parabola will open upward when the value of 𝒂 is positive. y x a > 0 a < 0 a ¹ 0
  • 9.
    Graphs of quadraticequations have symmetry about a line through the vertex. This line is called the axis of symmetry. The sign of a, the numerical coefficient of the squared term, determines whether the parabola will open upward or downward.
  • 10.
    Vertex of aParabola The parabola represented by the function f(x) = ax2 + bx + c will have vertex Since we often find the y-coordinate of the vertex by substituting the x- coordinate of the vertex into f(x), the vertex may also be designated as         a b ac a b 4 4 , 2 2              a b f a b 2 , 2
  • 11.
    Axis of Symmetry Fora quadratic function of the form f(x) = ax2 + bx + c, the equation of the axis of symmetry of the parabola is a b x 2  
  • 12.
    x-Intercepts of aParabola To find the x-intercepts (if there are any) of a quadratic function, solve the equation ax2 + bx + c = 0 for x. This equation may be solved by factoring, by using the quadratic formula, or by completing the square.
  • 13.
    y x Y-intercept of aQuadratic Function y = 2x2 - 4x -1 Y-axis The y-intercept of a Quadratic function can Be found when x = 0. y = 2x2 - 4x -1 = 2 0 ( )2 - 4(0) -1 = 0 - 0 -1 = -1 The constant term is always the y-intercept.
  • 14.
    STEP 1: Findthe Axis of symmetry ( ) 4 1 2 2 2 b x a - = = = y x Graph : y = 2x2 - 4x -1 Graphing a Quadratic Function STEP 2: Find the vertex Substitute in x = 1 to find the y – y- value of the vertex. ( ) ( ) 2 2 1 4 1 1 3 y = - - = - Vertex : 1, - 3 ( ) x =1
  • 15.
    5 –1 ( ) () 2 2 3 4 3 1 5 y = - - = STEP 3: Find two other points and reflect them across the Axis of symmetry. Then connect the five points with a smooth curve. y x ( ) ( ) 2 2 2 4 2 1 1 y = - - = - 3 2 y x
  • 16.
    Example Consider thequadratic function y = -x2 + 8x – 12. a. Determine whether the parabola opens upward or downward. b. Find the y-intercept. c. Find the vertex. d. Find the axis of symmetry. e. Find the x-intercepts, if any. f. Draw the graph.
  • 17.
    a. Since ais -1, which is less than 0, the parabola opens downward. b. To find the y-intercept, set x = 0 and solve for y. 12 12 ) 0 ( 8 ) 0 ( 2       y The y-intercept is (0, 12) Example Consider the quadratic function y = -x2 + 8x – 12.
  • 18.
    c. First, findthe x-coordinate, then find the y-coordinate of the vertex. From the function, a = -1, b = 8, and c = -12. continued 4 ) 1 ( 2 8 2      a b x Since the x-coordinate of the vertex is not a fraction, we will substitute x = 4 into the original function to determine the y-coordinate of the vertex. 4 12 32 16 12 ) 4 ( 8 ) 4 ( 12 8 2 2              y x x y The vertex is (4, 4).
  • 19.
    d. Since theaxis of symmetry is a vertical line through the vertex, the equation is found using the same formula used to find the x-coordinate of the vertex. Thus, the equation of the axis of symmetry is x = 4.
  • 20.
    e. To findthe x-intercepts, set y = 0. 2 x 6 0 2 or 0 6 0 ) 2 )( 6 ( 0 12 8 2             x x x x x x x Thus, the x-intercepts are (2, 0) and (6, 0). These values could also be found by the quadratic formula (or by completing the square).
  • 21.