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• DABHI MAYUR 140210116007
• HADVANI YOGENDRA 140210116016
• KOYANI SAGAR 140210116029
• VARIYA ANKIT 140210116058
VECTOR SPACES AND SUBSPACES
© 2012 Pearson Education, Inc.
Vector Spaces
VECTOR SPACES AND SUBSPACES
• Definition: A vector space is a nonempty set V of
objects, called vectors, on which are defined two
operations, called addition and multiplication by
scalars (real numbers), subject to the ten axioms
(or rules) listed below. The axioms must hold for all
vectors u, v, and w in V and for all scalars c and d.
1. The sum of u and v, denoted by is in V.
2. .
3. .
4.
.
u v
u v v u  
(u v) w u (v w)    
u ( u) 0  
VECTOR SPACES AND SUBSPACES
© 2012 Pearson Education, Inc.
5. For each u in V, there is a vector in V such
that .
6. The scalar multiple of u by c, denoted by cu, is
in V.
7. .
8. .
9. .
10. .
• Using these axioms, we can show that the zero
vector in Axiom 4 is unique, and the vector ,
called the negative of u, in Axiom 5 is unique for
each u in V.
u
u ( u) 0  
(u v) u vc c c  
( )u u vc d c c  
( u) ( )uc d cd
1u u
u
VECTOR SPACES AND SUBSPACES
© 2012 Pearson Education, Inc. Slide 4.1- 6
• For each u in V and scalar c,
----(1)
----(2)
----(3)
• Example 1: Let V be the set of all arrows (directed
line segments) in three-dimensional space, with two
arrows regarded as equal if they have the same
length and point in the same direction. Define
addition by the parallelogram rule, and for each v in
V, define cv to be the arrow whose length is times
the length of v, pointing in the same direction as v if
and otherwise pointing in the opposite direction.
0u 0
0 0c 
u ( 1)u  
c
0c 
VECTOR SPACES AND SUBSPACES
© 2012 Pearson Education, Inc. Slide 4.1- 7
• See the following figure below. Show that V is a
vector space.
• Solution: The definition of V is geometric, using
concepts of length and direction.
• No xyz-coordinate system is involved.
• An arrow of zero length is a single point and
represents the zero vector.
• The negative of v is v.
• So Axioms 1, 4, 5, 6, and 10 are evident. See the
figures on the next slide.
( 1)
SUBSPACES
• Definition: A subspace of a vector space V is a
subset H of V that has three properties:
a. The zero vector of V is in H.
b. H is closed under vector addition. That is, for
each u and v in H, the sum is in H.
Slide 4.1- 8© 2012 Pearson Education, Inc.
u v
SUBSPACES
© 2012 Pearson Education, Inc. Slide 4.1- 9
c. H is closed under multiplication by scalars.
That is, for each u in H and each scalar c, the
vector cu is in H.
• Properties (a), (b), and (c) guarantee that a
subspace H of V is itself a vector space, under the
vector space operations already defined in V.
• Every subspace is a vector space.
• Conversely, every vector space is a subspace (of
itself and possibly of other larger spaces).
A SUBSPACE SPANNED BY A SET
© 2012 Pearson Education, Inc. Slide 4.1- 10
• The set consisting of only the zero vector in a vector
space V is a subspace of V, called the zero subspace
and written as {0}.
• As the term linear combination refers to any sum of
scalar multiples of vectors, and Span {v1,…,vp}
denotes the set of all vectors that can be written as
linear combinations of v1,…,vp.
A SUBSPACE SPANNED BY A SET
© 2012 Pearson Education, Inc. Slide 4.1- 11
• Example 2: Given v1 and v2 in a vector space V, let
. Show that H is a subspace of V.
• Solution: The zero vector is in H, since .
• To show that H is closed under vector addition, take
two arbitrary vectors in H, say,
and .
• By Axioms 2, 3, and 8 for the vector space V,
1 2
Span{v ,v }H 
1 2
0 0v 0v 
1 1 2 2
u v vs s  1 1 2 2
w v vt t 
1 1 2 2 1 1 2 2
1 1 1 2 2 2
u w ( v v ) ( v v )
( )v ( )v
s s t t
s t s t
    
   
A SUBSPACE SPANNED BY A SET
© 2012 Pearson Education, Inc. Slide 4.1- 12
• So is in H.
• Furthermore, if c is any scalar, then by Axioms 7 and 9,
which shows that cu is in H and H is closed under scalar
multiplication.
• Thus H is a subspace of V.
u w
1 1 2 2 1 1 2 2
u ( v v ) ( )v ( )vc c s s cs cs   
A SUBSPACE SPANNED BY A SET
© 2012 Pearson Education, Inc. Slide 4.1- 13
• Theorem 1: If v1,…,vp are in a vector space V, then
Span {v1,…,vp} is a subspace of V.
• We call Span {v1,…,vp} the subspace spanned (or
generated) by {v1,…,vp}.
• Give any subspace H of V, a spanning (or generating)
set for H is a set {v1,…,vp} in H such that
.
1
Span{v ,...v }p
H 
© 2012 Pearson Education, Inc. Slide 4.1- 14

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Calculus it

  • 1.
  • 2. CREATER: NAME ENROLLMENT NO • DABHI MAYUR 140210116007 • HADVANI YOGENDRA 140210116016 • KOYANI SAGAR 140210116029 • VARIYA ANKIT 140210116058
  • 3. VECTOR SPACES AND SUBSPACES © 2012 Pearson Education, Inc. Vector Spaces
  • 4. VECTOR SPACES AND SUBSPACES • Definition: A vector space is a nonempty set V of objects, called vectors, on which are defined two operations, called addition and multiplication by scalars (real numbers), subject to the ten axioms (or rules) listed below. The axioms must hold for all vectors u, v, and w in V and for all scalars c and d. 1. The sum of u and v, denoted by is in V. 2. . 3. . 4. . u v u v v u   (u v) w u (v w)     u ( u) 0  
  • 5. VECTOR SPACES AND SUBSPACES © 2012 Pearson Education, Inc. 5. For each u in V, there is a vector in V such that . 6. The scalar multiple of u by c, denoted by cu, is in V. 7. . 8. . 9. . 10. . • Using these axioms, we can show that the zero vector in Axiom 4 is unique, and the vector , called the negative of u, in Axiom 5 is unique for each u in V. u u ( u) 0   (u v) u vc c c   ( )u u vc d c c   ( u) ( )uc d cd 1u u u
  • 6. VECTOR SPACES AND SUBSPACES © 2012 Pearson Education, Inc. Slide 4.1- 6 • For each u in V and scalar c, ----(1) ----(2) ----(3) • Example 1: Let V be the set of all arrows (directed line segments) in three-dimensional space, with two arrows regarded as equal if they have the same length and point in the same direction. Define addition by the parallelogram rule, and for each v in V, define cv to be the arrow whose length is times the length of v, pointing in the same direction as v if and otherwise pointing in the opposite direction. 0u 0 0 0c  u ( 1)u   c 0c 
  • 7. VECTOR SPACES AND SUBSPACES © 2012 Pearson Education, Inc. Slide 4.1- 7 • See the following figure below. Show that V is a vector space. • Solution: The definition of V is geometric, using concepts of length and direction. • No xyz-coordinate system is involved. • An arrow of zero length is a single point and represents the zero vector. • The negative of v is v. • So Axioms 1, 4, 5, 6, and 10 are evident. See the figures on the next slide. ( 1)
  • 8. SUBSPACES • Definition: A subspace of a vector space V is a subset H of V that has three properties: a. The zero vector of V is in H. b. H is closed under vector addition. That is, for each u and v in H, the sum is in H. Slide 4.1- 8© 2012 Pearson Education, Inc. u v
  • 9. SUBSPACES © 2012 Pearson Education, Inc. Slide 4.1- 9 c. H is closed under multiplication by scalars. That is, for each u in H and each scalar c, the vector cu is in H. • Properties (a), (b), and (c) guarantee that a subspace H of V is itself a vector space, under the vector space operations already defined in V. • Every subspace is a vector space. • Conversely, every vector space is a subspace (of itself and possibly of other larger spaces).
  • 10. A SUBSPACE SPANNED BY A SET © 2012 Pearson Education, Inc. Slide 4.1- 10 • The set consisting of only the zero vector in a vector space V is a subspace of V, called the zero subspace and written as {0}. • As the term linear combination refers to any sum of scalar multiples of vectors, and Span {v1,…,vp} denotes the set of all vectors that can be written as linear combinations of v1,…,vp.
  • 11. A SUBSPACE SPANNED BY A SET © 2012 Pearson Education, Inc. Slide 4.1- 11 • Example 2: Given v1 and v2 in a vector space V, let . Show that H is a subspace of V. • Solution: The zero vector is in H, since . • To show that H is closed under vector addition, take two arbitrary vectors in H, say, and . • By Axioms 2, 3, and 8 for the vector space V, 1 2 Span{v ,v }H  1 2 0 0v 0v  1 1 2 2 u v vs s  1 1 2 2 w v vt t  1 1 2 2 1 1 2 2 1 1 1 2 2 2 u w ( v v ) ( v v ) ( )v ( )v s s t t s t s t         
  • 12. A SUBSPACE SPANNED BY A SET © 2012 Pearson Education, Inc. Slide 4.1- 12 • So is in H. • Furthermore, if c is any scalar, then by Axioms 7 and 9, which shows that cu is in H and H is closed under scalar multiplication. • Thus H is a subspace of V. u w 1 1 2 2 1 1 2 2 u ( v v ) ( )v ( )vc c s s cs cs   
  • 13. A SUBSPACE SPANNED BY A SET © 2012 Pearson Education, Inc. Slide 4.1- 13 • Theorem 1: If v1,…,vp are in a vector space V, then Span {v1,…,vp} is a subspace of V. • We call Span {v1,…,vp} the subspace spanned (or generated) by {v1,…,vp}. • Give any subspace H of V, a spanning (or generating) set for H is a set {v1,…,vp} in H such that . 1 Span{v ,...v }p H 
  • 14. © 2012 Pearson Education, Inc. Slide 4.1- 14