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Physics Helpline
L K Satapathy
Alternating Current Theory 4
LCR Series Circuit
L C R
E
Physics Helpline
L K Satapathy
Cells in Parallel
Alternating Current Theory 4
L C R
E
sin . . . (1)o
dI q
L RI E E t
dt C
    
sinoE E t
sin( )oI I t  
LCR Series Circuit
Applied voltage
Current
Phase difference =  & Current amplitude = Io
If dI/dt be the rate of change of current , then voltage across L
dI
L
dt

Voltage across the resistor = RI
If q be the charge on the capacitor , voltage across C
q
C

Inductive reactance LX L
Capacitive reactance 1CX C
Physics Helpline
L K Satapathy
Cells in Parallel
Alternating Current Theory 4
VC
Io
t
Capacitance
t
Inductance
VL
Io
t
Resistance
VRIo
R oV I R
L o L oV I X I L 
o
C o C
I
V I X
C
 
Phasor Method
Voltage across R is
Current is in phase with voltage
Voltage across L is
Current is (/2) behind voltage
Voltage across C is
Current is (/2) ahead of voltage
For single circuit elements (discussed in AC Theory 3) :
Physics Helpline
L K Satapathy
Cells in Parallel
Alternating Current Theory 4
VR
VL
VC
t+
Io
VL & VC are out of phase
The corresponding Phasors act along the same line
but in opposite directions
Eo
-VLVC
VR

t
Io
We assume that voltage across C > voltage across L
The Phasors of (VC – VL) & VR are shown in the figure
The resultant voltage = Eo
Current leads voltage by phase angle  (as shown)
For LCR series circuit :
Let the phase of current = (t + )
Physics Helpline
L K Satapathy
Cells in Parallel
Alternating Current Theory 4
2 2 2
( )o R C LE V V V   2 2 2
( )o o C o LI R I X I X  
2 2 2 2 2
[ ( ) ]o C L oI R X X I Z    2 2
( )C Lwhere Z R X X  
o
o o o
E
E I Z I
Z
   
1
tan tanC L C LX X X X
Also
R R
    
    
 
(i) XC  XL :  is +ve  current leads voltage (Capacitive behavior)
(ii) XC  XL :  is ve  current lags behind voltage (Inductive behavior )
Adding the voltages vectorially, we get
Physics Helpline
L K Satapathy
Cells in Parallel
Alternating Current Theory 4
Analytical Method :
(1) sino
dI q
L RI E t
dt C
   
2
2
sin . . . (2)o
d q dq q
L R E t
dt dt C
   
sin( )oq q t  
cos( ) . . . (3)o
dq
q t
dt
    
2
2
2
& sin( )o
d q
q t
dt
    
2
2
&
dq dI d q
I
dt dt dt
 
  
 
Let the solution be
 o oq I 
Physics Helpline
L K Satapathy
Cells in Parallel
Alternating Current Theory 4
2
(2) sin( ) cos( ) sin( ) sino
o o o
q
q L t q R t t E t
C
               
1
[ sin( ) cos( ) sin( )] sino oq L t R t t E t
C
        

       
[( )sin( ) cos( )] sino C L oq X X t R t E t          
cos( ) sin( ) sin . . . (4)C L
o o
X XR
q Z t t E t
Z Z
     
 
     
 
cos & sinC LX XR
Put
Z Z
 

 
tan C LX X
R


 
Physics Helpline
L K Satapathy
Cells in Parallel
Alternating Current Theory 4
(4) [cos( )cos sin( )sin ] sino oq Z t t E t           
[cos( )] sino oq Z t E t       
 o oI Z E
2 2
( )C LZ R X X   
22
2 2
2 2
( )
cos sin 1C LX XR
Also
Z Z
 

   
[cos( )] sino oI Z t E t        o oq I 
[cos( )] sino oE t E t      
cos( ) sint t      
sin( 2) sint t         sin cos
2

 
  
   
  
Physics Helpline
L K Satapathy
Cells in Parallel
Alternating Current Theory 4
2 2t t              
(3) cos( ) cos( )o o
dq
I q t I t
dt
         
cos( 2 )oI I t     
( ) sin( )oii I I t  
1
( ) tan C LX X
iii
R
   
  
 
( ) sinoi E E t
cos( 2)oI I t     
sin( )oI I t   
 cos( ) cos  
Results obtained :
Physics Helpline
L K Satapathy
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Alternating Current Theory 4

  • 1. Physics Helpline L K Satapathy Alternating Current Theory 4 LCR Series Circuit L C R E
  • 2. Physics Helpline L K Satapathy Cells in Parallel Alternating Current Theory 4 L C R E sin . . . (1)o dI q L RI E E t dt C      sinoE E t sin( )oI I t   LCR Series Circuit Applied voltage Current Phase difference =  & Current amplitude = Io If dI/dt be the rate of change of current , then voltage across L dI L dt  Voltage across the resistor = RI If q be the charge on the capacitor , voltage across C q C  Inductive reactance LX L Capacitive reactance 1CX C
  • 3. Physics Helpline L K Satapathy Cells in Parallel Alternating Current Theory 4 VC Io t Capacitance t Inductance VL Io t Resistance VRIo R oV I R L o L oV I X I L  o C o C I V I X C   Phasor Method Voltage across R is Current is in phase with voltage Voltage across L is Current is (/2) behind voltage Voltage across C is Current is (/2) ahead of voltage For single circuit elements (discussed in AC Theory 3) :
  • 4. Physics Helpline L K Satapathy Cells in Parallel Alternating Current Theory 4 VR VL VC t+ Io VL & VC are out of phase The corresponding Phasors act along the same line but in opposite directions Eo -VLVC VR  t Io We assume that voltage across C > voltage across L The Phasors of (VC – VL) & VR are shown in the figure The resultant voltage = Eo Current leads voltage by phase angle  (as shown) For LCR series circuit : Let the phase of current = (t + )
  • 5. Physics Helpline L K Satapathy Cells in Parallel Alternating Current Theory 4 2 2 2 ( )o R C LE V V V   2 2 2 ( )o o C o LI R I X I X   2 2 2 2 2 [ ( ) ]o C L oI R X X I Z    2 2 ( )C Lwhere Z R X X   o o o o E E I Z I Z     1 tan tanC L C LX X X X Also R R             (i) XC  XL :  is +ve  current leads voltage (Capacitive behavior) (ii) XC  XL :  is ve  current lags behind voltage (Inductive behavior ) Adding the voltages vectorially, we get
  • 6. Physics Helpline L K Satapathy Cells in Parallel Alternating Current Theory 4 Analytical Method : (1) sino dI q L RI E t dt C     2 2 sin . . . (2)o d q dq q L R E t dt dt C     sin( )oq q t   cos( ) . . . (3)o dq q t dt      2 2 2 & sin( )o d q q t dt      2 2 & dq dI d q I dt dt dt        Let the solution be  o oq I 
  • 7. Physics Helpline L K Satapathy Cells in Parallel Alternating Current Theory 4 2 (2) sin( ) cos( ) sin( ) sino o o o q q L t q R t t E t C                 1 [ sin( ) cos( ) sin( )] sino oq L t R t t E t C                   [( )sin( ) cos( )] sino C L oq X X t R t E t           cos( ) sin( ) sin . . . (4)C L o o X XR q Z t t E t Z Z                 cos & sinC LX XR Put Z Z      tan C LX X R    
  • 8. Physics Helpline L K Satapathy Cells in Parallel Alternating Current Theory 4 (4) [cos( )cos sin( )sin ] sino oq Z t t E t            [cos( )] sino oq Z t E t         o oI Z E 2 2 ( )C LZ R X X    22 2 2 2 2 ( ) cos sin 1C LX XR Also Z Z        [cos( )] sino oI Z t E t        o oq I  [cos( )] sino oE t E t       cos( ) sint t       sin( 2) sint t         sin cos 2             
  • 9. Physics Helpline L K Satapathy Cells in Parallel Alternating Current Theory 4 2 2t t               (3) cos( ) cos( )o o dq I q t I t dt           cos( 2 )oI I t      ( ) sin( )oii I I t   1 ( ) tan C LX X iii R          ( ) sinoi E E t cos( 2)oI I t      sin( )oI I t     cos( ) cos   Results obtained :
  • 10. Physics Helpline L K Satapathy For More details: www.physics-helpline.com Subscribe our channel: youtube.com/physics-helpline Follow us on Facebook and Twitter: facebook.com/physics-helpline twitter.com/physics-helpline