The document introduces exponents and rules for exponents. It defines exponents as representing repeated multiplication, where AN means multiplying A by itself N times. It provides examples of evaluating exponents like 43. It then introduces rules for exponents, including the multiply-add rule where ANAK = AN+K, and the divide-subtract rule where AN/AK = AN-K. It also covers fractional exponents by defining the 0-power rule where A0 = 1 and the negative power rule where A-K = 1/AK.
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Synthetic Fiber Construction in lab .pptxPavel ( NSTU)
Synthetic fiber production is a fascinating and complex field that blends chemistry, engineering, and environmental science. By understanding these aspects, students can gain a comprehensive view of synthetic fiber production, its impact on society and the environment, and the potential for future innovations. Synthetic fibers play a crucial role in modern society, impacting various aspects of daily life, industry, and the environment. ynthetic fibers are integral to modern life, offering a range of benefits from cost-effectiveness and versatility to innovative applications and performance characteristics. While they pose environmental challenges, ongoing research and development aim to create more sustainable and eco-friendly alternatives. Understanding the importance of synthetic fibers helps in appreciating their role in the economy, industry, and daily life, while also emphasizing the need for sustainable practices and innovation.
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In this webinar you will learn how your organization can access TechSoup's wide variety of product discount and donation programs. From hardware to software, we'll give you a tour of the tools available to help your nonprofit with productivity, collaboration, financial management, donor tracking, security, and more.
The Roman Empire A Historical Colossus.pdfkaushalkr1407
The Roman Empire, a vast and enduring power, stands as one of history's most remarkable civilizations, leaving an indelible imprint on the world. It emerged from the Roman Republic, transitioning into an imperial powerhouse under the leadership of Augustus Caesar in 27 BCE. This transformation marked the beginning of an era defined by unprecedented territorial expansion, architectural marvels, and profound cultural influence.
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Under Augustus, the empire experienced the Pax Romana, a 200-year period of relative peace and stability. Augustus reformed the military, established efficient administrative systems, and initiated grand construction projects. The empire's borders expanded, encompassing territories from Britain to Egypt and from Spain to the Euphrates. Roman legions, renowned for their discipline and engineering prowess, secured and maintained these vast territories, building roads, fortifications, and cities that facilitated control and integration.
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Culturally, the Romans were eclectic, absorbing and adapting elements from the civilizations they encountered, particularly the Greeks. Roman art, literature, and philosophy reflected this synthesis, creating a rich cultural tapestry. Latin, the Roman language, became the lingua franca of the Western world, influencing numerous modern languages.
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It is possible to hide or invisible some fields in odoo. Commonly using “invisible” attribute in the field definition to invisible the fields. This slide will show how to make a field invisible in odoo 17.
The Indian economy is classified into different sectors to simplify the analysis and understanding of economic activities. For Class 10, it's essential to grasp the sectors of the Indian economy, understand their characteristics, and recognize their importance. This guide will provide detailed notes on the Sectors of the Indian Economy Class 10, using specific long-tail keywords to enhance comprehension.
For more information, visit-www.vavaclasses.com
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The people of Punjab felt alienated from main stream due to denial of their just demands during a long democratic struggle since independence. As it happen all over the word, it led to militant struggle with great loss of lives of military, police and civilian personnel. Killing of Indira Gandhi and massacre of innocent Sikhs in Delhi and other India cities was also associated with this movement.
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2024.06.01 Introducing a competency framework for languag learning materials ...Sandy Millin
http://sandymillin.wordpress.com/iateflwebinar2024
Published classroom materials form the basis of syllabuses, drive teacher professional development, and have a potentially huge influence on learners, teachers and education systems. All teachers also create their own materials, whether a few sentences on a blackboard, a highly-structured fully-realised online course, or anything in between. Despite this, the knowledge and skills needed to create effective language learning materials are rarely part of teacher training, and are mostly learnt by trial and error.
Knowledge and skills frameworks, generally called competency frameworks, for ELT teachers, trainers and managers have existed for a few years now. However, until I created one for my MA dissertation, there wasn’t one drawing together what we need to know and do to be able to effectively produce language learning materials.
This webinar will introduce you to my framework, highlighting the key competencies I identified from my research. It will also show how anybody involved in language teaching (any language, not just English!), teacher training, managing schools or developing language learning materials can benefit from using the framework.
5. Example A.
43 = (4)(4)(4) = 64
Exponents
base
exponent
We write “1” times the quantity “A” repeatedly N times as AN, i.e.
1 x A x A x A ….x A = AN
repeated N times
6. Example A.
43 = (4)(4)(4) = 64
(xy)2
Exponents
base
exponent
We write “1” times the quantity “A” repeatedly N times as AN, i.e.
1 x A x A x A ….x A = AN
repeated N times
7. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy)
Exponents
base
exponent
We write “1” times the quantity “A” repeatedly N times as AN, i.e.
1 x A x A x A ….x A = AN
repeated N times
8. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
Exponents
base
exponent
We write “1” times the quantity “A” repeatedly N times as AN, i.e.
1 x A x A x A ….x A = AN
repeated N times
9. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2
Exponents
base
exponent
We write “1” times the quantity “A” repeatedly N times as AN, i.e.
1 x A x A x A ….x A = AN
repeated N times
10. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2 = (x)(yy)
Exponents
base
exponent
We write “1” times the quantity “A” repeatedly N times as AN, i.e.
1 x A x A x A ….x A = AN
repeated N times
11. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2 = (x)(yy)
–x2 = –(xx)
Exponents
base
exponent
We write “1” times the quantity “A” repeatedly N times as AN, i.e.
1 x A x A x A ….x A = AN
repeated N times
12. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2 = (x)(yy)
–x2 = –(xx)
Exponents
base
exponent
We write “1” times the quantity “A” repeatedly N times as AN, i.e.
1 x A x A x A ….x A = AN
repeated N times
13. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2 = (x)(yy)
–x2 = –(xx)
Exponents
Rules of Exponents
base
exponent
We write “1” times the quantity “A” repeatedly N times as AN, i.e.
1 x A x A x A ….x A = AN
repeated N times
14. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2 = (x)(yy)
–x2 = –(xx)
Exponents
Multiply-Add Rule: ANAK =AN+K
Rules of Exponents
base
exponent
We write “1” times the quantity “A” repeatedly N times as AN, i.e.
1 x A x A x A ….x A = AN
repeated N times
15. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2 = (x)(yy)
–x2 = –(xx)
Exponents
Multiply-Add Rule: ANAK =AN+K
Example B.
a. 5354
Rules of Exponents
base
exponent
We write “1” times the quantity “A” repeatedly N times as AN, i.e.
1 x A x A x A ….x A = AN
repeated N times
16. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2 = (x)(yy)
–x2 = –(xx)
Exponents
Multiply-Add Rule: ANAK =AN+K
Example B.
a. 5354 = (5*5*5)(5*5*5*5)
Rules of Exponents
base
exponent
We write “1” times the quantity “A” repeatedly N times as AN, i.e.
1 x A x A x A ….x A = AN
repeated N times
17. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2 = (x)(yy)
–x2 = –(xx)
Exponents
Multiply-Add Rule: ANAK =AN+K
Example B.
a. 5354 = (5*5*5)(5*5*5*5) = 53+4 = 57
b. x5y7x4y6
Rules of Exponents
base
exponent
We write “1” times the quantity “A” repeatedly N times as AN, i.e.
1 x A x A x A ….x A = AN
repeated N times
18. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2 = (x)(yy)
–x2 = –(xx)
Exponents
Multiply-Add Rule: ANAK =AN+K
Example B.
a. 5354 = (5*5*5)(5*5*5*5) = 53+4 = 57
b. x5y7x4y6 = x5x4y7y6
Rules of Exponents
base
exponent
We write “1” times the quantity “A” repeatedly N times as AN, i.e.
1 x A x A x A ….x A = AN
repeated N times
19. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2 = (x)(yy)
–x2 = –(xx)
Exponents
Multiply-Add Rule: ANAK =AN+K
Example B.
a. 5354 = (5*5*5)(5*5*5*5) = 53+4 = 57
b. x5y7x4y6 = x5x4y7y6 = x9y13
Rules of Exponents
base
exponent
We write “1” times the quantity “A” repeatedly N times as AN, i.e.
1 x A x A x A ….x A = AN
repeated N times
20. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2 = (x)(yy)
–x2 = –(xx)
base
exponent
Exponents
Multiply-Add Rule: ANAK =AN+K
Example B.
a. 5354 = (5*5*5)(5*5*5*5) = 53+4 = 57
b. x5y7x4y6 = x5x4y7y6 = x9y13
Rules of Exponents
Divide–Subtract Rule:
AN
AK = AN – K
We write “1” times the quantity “A” repeatedly N times as AN, i.e.
1 x A x A x A ….x A = AN
repeated N times
21. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2 = (x)(yy)
–x2 = –(xx)
base
exponent
Exponents
Multiply-Add Rule: ANAK =AN+K
Example B.
a. 5354 = (5*5*5)(5*5*5*5) = 53+4 = 57
b. x5y7x4y6 = x5x4y7y6 = x9y13
Rules of Exponents
Divide–Subtract Rule:
Example C.
AN
AK = AN – K
56
52
We write “1” times the quantity “A” repeatedly N times as AN, i.e.
1 x A x A x A ….x A = AN
repeated N times
22. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2 = (x)(yy)
–x2 = –(xx)
base
exponent
Exponents
Multiply-Add Rule: ANAK =AN+K
Example B.
a. 5354 = (5*5*5)(5*5*5*5) = 53+4 = 57
b. x5y7x4y6 = x5x4y7y6 = x9y13
Rules of Exponents
Divide–Subtract Rule:
Example C.
AN
AK = AN – K
56
52 =
(5)(5)(5)(5)(5)(5)
(5)(5)
We write “1” times the quantity “A” repeatedly N times as AN, i.e.
1 x A x A x A ….x A = AN
repeated N times
23. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2 = (x)(yy)
–x2 = –(xx)
base
exponent
Exponents
Multiply-Add Rule: ANAK =AN+K
Example B.
a. 5354 = (5*5*5)(5*5*5*5) = 53+4 = 57
b. x5y7x4y6 = x5x4y7y6 = x9y13
Rules of Exponents
Divide–Subtract Rule:
Example C.
AN
AK = AN – K
56
52 =
(5)(5)(5)(5)(5)(5)
(5)(5)
We write “1” times the quantity “A” repeatedly N times as AN, i.e.
1 x A x A x A ….x A = AN
repeated N times
24. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2 = (x)(yy)
–x2 = –(xx)
base
exponent
Exponents
Multiply-Add Rule: ANAK =AN+K
Example B.
a. 5354 = (5*5*5)(5*5*5*5) = 53+4 = 57
b. x5y7x4y6 = x5x4y7y6 = x9y13
Rules of Exponents
Divide–Subtract Rule:
Example C.
AN
AK = AN – K
56
52 =
(5)(5)(5)(5)(5)(5)
(5)(5)
= 56 – 2 = 54
We write “1” times the quantity “A” repeatedly N times as AN, i.e.
1 x A x A x A ….x A = AN
repeated N times
27. Since = 1 = A1 – 1 = A0, we obtain the 0-power Rule.
A1
A1
Fractional Exponents
28. Since = 1 = A1 – 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Fractional Exponents
29. Since = 1 = A1 – 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since =1
AK
A0
AK
Fractional Exponents
30. Since = 1 = A1 – 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since = = A0 – K = A–K1
AK
A0
AK
Fractional Exponents
31. Since = 1 = A1 – 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since = = A0 – K = A–K, we get the negative-power Rule.1
AK
A0
AK
Fractional Exponents
32. Since = 1 = A1 – 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since = = A0 – K = A–K, we get the negative-power Rule.1
AK
A0
AK
Negative-Power Rule: A–K =
1
AK
Fractional Exponents
33. Since = 1 = A1 – 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since = = A0 – K = A–K, we get the negative-power Rule.1
AK
A0
AK
Negative-Power Rule: A–K =
1
AK
Fractional Exponents
The reverse of multiplication is division,
so 1 x A x A x …. x A = AK
A
1 x1 x
A
1 x .. x
A
1 = A–K
repeated K times
34. Since = 1 = A1 – 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since = = A0 – K = A–K, we get the negative-power Rule.1
AK
A0
AK
Negative-Power Rule: A–K =
1
AK
Example D. Simplify.
a. 30 = 1
Fractional Exponents
The reverse of multiplication is division,
so 1 x A x A x …. x A = AK
A
1 x1 x
A
1 x .. x
A
1 = A–K
repeated K times
35. Since = 1 = A1 – 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since = = A0 – K = A–K, we get the negative-power Rule.1
AK
A0
AK
Negative-Power Rule: A–K =
1
AK
Example D. Simplify.
b. 3–2
a. 30 = 1
Fractional Exponents
The reverse of multiplication is division,
so 1 x A x A x …. x A = AK
A
1 x1 x
A
1 x .. x
A
1 = A–K
repeated K times
36. Since = 1 = A1 – 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since = = A0 – K = A–K, we get the negative-power Rule.1
AK
A0
AK
Negative-Power Rule: A–K =
1
AK
Example D. Simplify.
1
32b. 3–2 = =
a. 30 = 1
Fractional Exponents
The reverse of multiplication is division,
so 1 x A x A x …. x A = AK
A
1 x1 x
A
1 x .. x
A
1 = A–K
repeated K times
37. Since = 1 = A1 – 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since = = A0 – K = A–K, we get the negative-power Rule.1
AK
A0
AK
Negative-Power Rule: A–K =
1
AK
Example D. Simplify.
1
32
1
9b. 3–2 = =
a. 30 = 1
Fractional Exponents
The reverse of multiplication is division,
so 1 x A x A x …. x A = AK
A
1 x1 x
A
1 x .. x
A
1 = A–K
repeated K times
38. Since = 1 = A1 – 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since = = A0 – K = A–K, we get the negative-power Rule.1
AK
A0
AK
Negative-Power Rule: A–K =
1
AK
Example D. Simplify.
1
32
1
9
c. ( )–12
5
b. 3–2 = =
a. 30 = 1
Fractional Exponents
The reverse of multiplication is division,
so 1 x A x A x …. x A = AK
A
1 x1 x
A
1 x .. x
A
1 = A–K
repeated K times
39. Since = 1 = A1 – 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since = = A0 – K = A–K, we get the negative-power Rule.1
AK
A0
AK
Negative-Power Rule: A–K =
1
AK
Example D. Simplify.
1
32
1
9
c. ( )–12
5
=
1
2/5
b. 3–2 = =
a. 30 = 1
Fractional Exponents
The reverse of multiplication is division,
so 1 x A x A x …. x A = AK
A
1 x1 x
A
1 x .. x
A
1 = A–K
repeated K times
40. Since = 1 = A1 – 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since = = A0 – K = A–K, we get the negative-power Rule.1
AK
A0
AK
Negative-Power Rule: A–K =
1
AK
Example D. Simplify.
1
32
1
9
c. ( )–12
5
=
1
2/5
= 1*
5
2
=
5
2
b. 3–2 = =
a. 30 = 1
Fractional Exponents
The reverse of multiplication is division,
so 1 x A x A x …. x A = AK
A
1 x1 x
A
1 x .. x
A
1 = A–K
repeated K times
41. Since = 1 = A1 – 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since = = A0 – K = A–K, we get the negative-power Rule.1
AK
A0
AK
Negative-Power Rule: A–K =
1
AK
Example D. Simplify.
1
32
1
9
c. ( )–12
5
=
1
2/5
= 1*
5
2
=
5
2
b. 3–2 = =
a. 30 = 1
Fractional Powers
Fractional Exponents
The reverse of multiplication is division,
so 1 x A x A x …. x A = AK
A
1 x1 x
A
1 x .. x
A
1 = A–K
repeated K times
42. Since = 1 = A1 – 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since = = A0 – K = A–K, we get the negative-power Rule.1
AK
A0
AK
Negative-Power Rule: A–K =
1
AK
Example D. Simplify.
1
32
1
9
c. ( )–12
5
=
1
2/5
= 1*
5
2
=
5
2
b. 3–2 = =
a. 30 = 1
Fractional Powers
Fractional Exponents
The reverse of multiplication is division,
so 1 x A x A x …. x A = AK
A
1 x1 x
A
1 x .. x
A
1 = A–K
repeated K times
1/2-Power Rule: A½ = A.
43. Since = 1 = A1 – 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since = = A0 – K = A–K, we get the negative-power Rule.1
AK
A0
AK
Negative-Power Rule: A–K =
1
AK
Example D. Simplify.
1
32
1
9
c. ( )–12
5
=
1
2/5
= 1*
5
2
=
5
2
b. 3–2 = =
a. 30 = 1
Fractional Powers
Fractional Exponents
The reverse of multiplication is division,
so 1 x A x A x …. x A = AK
A
1 x1 x
A
1 x .. x
A
1 = A–K
repeated K times
By the power-multiply rule (A½ )2 = A1
1/2-Power Rule: A½ = A.
44. Since = 1 = A1 – 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since = = A0 – K = A–K, we get the negative-power Rule.1
AK
A0
AK
Negative-Power Rule: A–K =
1
AK
Example D. Simplify.
1
32
1
9
c. ( )–12
5
=
1
2/5
= 1*
5
2
=
5
2
b. 3–2 = =
a. 30 = 1
Fractional Powers
Fractional Exponents
The reverse of multiplication is division,
so 1 x A x A x …. x A = AK
A
1 x1 x
A
1 x .. x
A
1 = A–K
repeated K times
By the power-multiply rule (A½ )2 = A1 = (A)2,
1/2-Power Rule: A½ = A.
45. Since = 1 = A1 – 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since = = A0 – K = A–K, we get the negative-power Rule.1
AK
A0
AK
Negative-Power Rule: A–K =
1
AK
Example D. Simplify.
1
32
1
9
c. ( )–12
5
=
1
2/5
= 1*
5
2
=
5
2
b. 3–2 = =
a. 30 = 1
Fractional Powers
Fractional Exponents
The reverse of multiplication is division,
so 1 x A x A x …. x A = AK
A
1 x1 x
A
1 x .. x
A
1 = A–K
repeated K times
By the power-multiply rule (A½ )2 = A1 = (A)2,
therefore A½ = A.
1/2-Power Rule: A½ = A.
51. Example E.
a. 16½ = 16 = 4
b. 9½ 25½ =925 = 3*5 = 15
Fractional Exponents
52. Example E.
a. 16½ = 16 = 4
b. 9½ 25½ =925 = 3*5 = 15
c. 43/2
Fractional Exponents
53. Example E.
a. 16½ = 16 = 4
b. 9½ 25½ =925 = 3*5 = 15
c. 43/2 = (4½ * 3)
Fractional Exponents
54. Example E.
a. 16½ = 16 = 4
b. 9½ 25½ =925 = 3*5 = 15
c. 43/2 = (4½ * 3) = (4½)3
Fractional Exponents
55. Example E.
a. 16½ = 16 = 4
b. 9½ 25½ =925 = 3*5 = 15
c. 43/2 = (4½ * 3) = (4½)3 = (4)3
Fractional Exponents
56. Example E.
a. 16½ = 16 = 4
b. 9½ 25½ =925 = 3*5 = 15
c. 43/2 = (4½ * 3) = (4½)3 = (4)3 = 23 = 8
Fractional Exponents
57. Example E.
a. 16½ = 16 = 4
b. 9½ 25½ =925 = 3*5 = 15
c. 43/2 = (4½ * 3) = (4½)3 = (4)3 = 23 = 8
d. 16 – ½
Fractional Exponents
58. Example E.
a. 16½ = 16 = 4
b. 9½ 25½ =925 = 3*5 = 15
c. 43/2 = (4½ * 3) = (4½)3 = (4)3 = 23 = 8
d. 16 – ½ = (16½) –1
Fractional Exponents
59. Example E.
a. 16½ = 16 = 4
b. 9½ 25½ =925 = 3*5 = 15
c. 43/2 = (4½ * 3) = (4½)3 = (4)3 = 23 = 8
d. 16 – ½ = (16½) –1 = (16) –1
Fractional Exponents
60. Example E.
a. 16½ = 16 = 4
b. 9½ 25½ =925 = 3*5 = 15
c. 43/2 = (4½ * 3) = (4½)3 = (4)3 = 23 = 8
d. 16 – ½ = (16½) –1 = (16) –1 = 4 –1 = 1/4
Fractional Exponents
61. Example E.
a. 16½ = 16 = 4
b. 9½ 25½ =925 = 3*5 = 15
c. 43/2 = (4½ * 3) = (4½)3 = (4)3 = 23 = 8
d. 16 – ½ = (16½) –1 = (16) –1 = 4 –1 = 1/4
e. 9 –3/2
Fractional Exponents
62. Example E.
a. 16½ = 16 = 4
b. 9½ 25½ =925 = 3*5 = 15
c. 43/2 = (4½ * 3) = (4½)3 = (4)3 = 23 = 8
d. 16 – ½ = (16½) –1 = (16) –1 = 4 –1 = 1/4
e. 9 –3/2 = (9 –½ * 3)
Fractional Exponents
63. Example E.
a. 16½ = 16 = 4
b. 9½ 25½ =925 = 3*5 = 15
c. 43/2 = (4½ * 3) = (4½)3 = (4)3 = 23 = 8
d. 16 – ½ = (16½) –1 = (16) –1 = 4 –1 = 1/4
e. 9 –3/2 = (9 –½ * 3) = (9 ½) –3
Fractional Exponents
64. Example E.
a. 16½ = 16 = 4
b. 9½ 25½ =925 = 3*5 = 15
c. 43/2 = (4½ * 3) = (4½)3 = (4)3 = 23 = 8
d. 16 – ½ = (16½) –1 = (16) –1 = 4 –1 = 1/4
e. 9 –3/2 = (9 –½ * 3) = (9 ½) –3 = (9)–3
Fractional Exponents
65. Example E.
a. 16½ = 16 = 4
b. 9½ 25½ =925 = 3*5 = 15
c. 43/2 = (4½ * 3) = (4½)3 = (4)3 = 23 = 8
d. 16 – ½ = (16½) –1 = (16) –1 = 4 –1 = 1/4
e. 9 –3/2 = (9 –½ * 3) = (9 ½) –3 = (9)–3 = 3–3 = 1/27
Fractional Exponents
66. Example E.
a. 16½ = 16 = 4
b. 9½ 25½ =925 = 3*5 = 15
c. 43/2 = (4½ * 3) = (4½)3 = (4)3 = 23 = 8
d. 16 – ½ = (16½) –1 = (16) –1 = 4 –1 = 1/4
e. 9 –3/2 = (9 –½ * 3) = (9 ½) –3 = (9)–3 = 3–3 = 1/27
A–1/2 =
A
1In general,
Fractional Exponents
67. Example E.
a. 16½ = 16 = 4
b. 9½ 25½ =925 = 3*5 = 15
c. 43/2 = (4½ * 3) = (4½)3 = (4)3 = 23 = 8
d. 16 – ½ = (16½) –1 = (16) –1 = 4 –1 = 1/4
e. 9 –3/2 = (9 –½ * 3) = (9 ½) –3 = (9)–3 = 3–3 = 1/27
A–1/2 = and
A
1 A –k/2 = ( )k
A
1In general,
Fractional Exponents
68. Example E.
a. 16½ = 16 = 4
b. 9½ 25½ =925 = 3*5 = 15
c. 43/2 = (4½ * 3) = (4½)3 = (4)3 = 23 = 8
d. 16 – ½ = (16½) –1 = (16) –1 = 4 –1 = 1/4
e. 9 –3/2 = (9 –½ * 3) = (9 ½) –3 = (9)–3 = 3–3 = 1/27
A–1/2 = and
A
1 A –k/2 = ( )k
A
1
Using an argument similar to the argument for ½-power rule,
we have the following rule for 1/k power.
In general,
Fractional Exponents
69. Example E.
a. 16½ = 16 = 4
b. 9½ 25½ =925 = 3*5 = 15
c. 43/2 = (4½ * 3) = (4½)3 = (4)3 = 23 = 8
d. 16 – ½ = (16½) –1 = (16) –1 = 4 –1 = 1/4
e. 9 –3/2 = (9 –½ * 3) = (9 ½) –3 = (9)–3 = 3–3 = 1/27
A–1/2 = and
A
1
1/k-Power Rule A1/k = A
k
A –k/2 = ( )k
A
1
Using an argument similar to the argument for ½-power rule,
we have the following rule for 1/k power.
In general,
Fractional Exponents
70. Example E.
a. 16½ = 16 = 4
b. 9½ 25½ =925 = 3*5 = 15
c. 43/2 = (4½ * 3) = (4½)3 = (4)3 = 23 = 8
d. 16 – ½ = (16½) –1 = (16) –1 = 4 –1 = 1/4
e. 9 –3/2 = (9 –½ * 3) = (9 ½) –3 = (9)–3 = 3–3 = 1/27
A–1/2 = and
A
1
1/k-Power Rule A1/k = A
k
A –k/2 = ( )k
A
1
Using an argument similar to the argument for ½-power rule,
we have the following rule for 1/k power.
In general,
Example F. Simplify.
a. 81/3
Fractional Exponents
71. Example E.
a. 16½ = 16 = 4
b. 9½ 25½ =925 = 3*5 = 15
c. 43/2 = (4½ * 3) = (4½)3 = (4)3 = 23 = 8
d. 16 – ½ = (16½) –1 = (16) –1 = 4 –1 = 1/4
e. 9 –3/2 = (9 –½ * 3) = (9 ½) –3 = (9)–3 = 3–3 = 1/27
A–1/2 = and
A
1
1/k-Power Rule A1/k = A
k
A –k/2 = ( )k
A
1
Using an argument similar to the argument for ½-power rule,
we have the following rule for 1/k power.
In general,
Example F. Simplify.
a. 81/3 = 8
3
Fractional Exponents
72. Example E.
a. 16½ = 16 = 4
b. 9½ 25½ =925 = 3*5 = 15
c. 43/2 = (4½ * 3) = (4½)3 = (4)3 = 23 = 8
d. 16 – ½ = (16½) –1 = (16) –1 = 4 –1 = 1/4
e. 9 –3/2 = (9 –½ * 3) = (9 ½) –3 = (9)–3 = 3–3 = 1/27
A–1/2 = and
A
1
1/k-Power Rule A1/k = A
k
A –k/2 = ( )k
A
1
Using an argument similar to the argument for ½-power rule,
we have the following rule for 1/k power.
In general,
Example F. Simplify.
a. 81/3 = 8 = 2
3
Fractional Exponents
73. Example E.
a. 16½ = 16 = 4
b. 9½ 25½ =925 = 3*5 = 15
c. 43/2 = (4½ * 3) = (4½)3 = (4)3 = 23 = 8
d. 16 – ½ = (16½) –1 = (16) –1 = 4 –1 = 1/4
e. 9 –3/2 = (9 –½ * 3) = (9 ½) –3 = (9)–3 = 3–3 = 1/27
A–1/2 = and
A
1
1/k-Power Rule A1/k = A
k
A –k/2 = ( )k
A
1
Using an argument similar to the argument for ½-power rule,
we have the following rule for 1/k power.
In general,
Example F. Simplify.
a. 81/3 = 8 = 2
b. 27 –2/3
3
Fractional Exponents
74. Example E.
a. 16½ = 16 = 4
b. 9½ 25½ =925 = 3*5 = 15
c. 43/2 = (4½ * 3) = (4½)3 = (4)3 = 23 = 8
d. 16 – ½ = (16½) –1 = (16) –1 = 4 –1 = 1/4
e. 9 –3/2 = (9 –½ * 3) = (9 ½) –3 = (9)–3 = 3–3 = 1/27
A–1/2 = and
A
1
1/k-Power Rule A1/k = A
k
A –k/2 = ( )k
A
1
Using an argument similar to the argument for ½-power rule,
we have the following rule for 1/k power.
In general,
Example F. Simplify.
a. 81/3 = 8 = 2
b. 27 –2/3 = (271/3)–2
3
Fractional Exponents
75. Example E.
a. 16½ = 16 = 4
b. 9½ 25½ =925 = 3*5 = 15
c. 43/2 = (4½ * 3) = (4½)3 = (4)3 = 23 = 8
d. 16 – ½ = (16½) –1 = (16) –1 = 4 –1 = 1/4
e. 9 –3/2 = (9 –½ * 3) = (9 ½) –3 = (9)–3 = 3–3 = 1/27
A–1/2 = and
A
1
1/k-Power Rule A1/k = A
k
A –k/2 = ( )k
A
1
Using an argument similar to the argument for ½-power rule,
we have the following rule for 1/k power.
In general,
Example F. Simplify.
a. 81/3 = 8 = 2
b. 27 –2/3 = (271/3)–2 = (27)–2
3
3
Fractional Exponents
76. Example E.
a. 16½ = 16 = 4
b. 9½ 25½ =925 = 3*5 = 15
c. 43/2 = (4½ * 3) = (4½)3 = (4)3 = 23 = 8
d. 16 – ½ = (16½) –1 = (16) –1 = 4 –1 = 1/4
e. 9 –3/2 = (9 –½ * 3) = (9 ½) –3 = (9)–3 = 3–3 = 1/27
A–1/2 = and
A
1
1/k-Power Rule A1/k = A
k
A –k/2 = ( )k
A
1
Using an argument similar to the argument for ½-power rule,
we have the following rule for 1/k power.
In general,
Example F. Simplify.
a. 81/3 = 8 = 2
b. 27 –2/3 = (271/3)–2 = (27)–2
3
3
Fractional Exponents
77. Example E.
a. 16½ = 16 = 4
b. 9½ 25½ =925 = 3*5 = 15
c. 43/2 = (4½ * 3) = (4½)3 = (4)3 = 23 = 8
d. 16 – ½ = (16½) –1 = (16) –1 = 4 –1 = 1/4
e. 9 –3/2 = (9 –½ * 3) = (9 ½) –3 = (9)–3 = 3–3 = 1/27
A–1/2 = and
A
1
1/k-Power Rule A1/k = A
k
A –k/2 = ( )k
A
1
Using an argument similar to the argument for ½-power rule,
we have the following rule for 1/k power.
In general,
Example F. Simplify.
a. 81/3 = 8 = 2
b. 27 –2/3 = (271/3)–2 = (27)–2 = (3)–2
3
3
Fractional Exponents
78. Example E.
a. 16½ = 16 = 4
b. 9½ 25½ =925 = 3*5 = 15
c. 43/2 = (4½ * 3) = (4½)3 = (4)3 = 23 = 8
d. 16 – ½ = (16½) –1 = (16) –1 = 4 –1 = 1/4
e. 9 –3/2 = (9 –½ * 3) = (9 ½) –3 = (9)–3 = 3–3 = 1/27
A–1/2 = and
A
1
1/k-Power Rule A1/k = A
k
A –k/2 = ( )k
A
1
Using an argument similar to the argument for ½-power rule,
we have the following rule for 1/k power.
In general,
Example F. Simplify.
a. 81/3 = 8 = 2
b. 27 –2/3 = (271/3)–2 = (27)–2 = (3)–2 = 1/32 = 1/9
3
3
Fractional Exponents
79. All the following rules for operations of exponents hold for
fractional exponents N and K.
Fractional Exponents
80. All the following rules for operations of exponents hold for
fractional exponents N and K.
Multiplication Rule ANAK = AN + K
Fractional Exponents
81. Division Rule = AN – K
Power Rule (AN)K = ANK
All the following rules for operations of exponents hold for
fractional exponents N and K.
AN
AK
Multiplication Rule ANAK = AN + K
Fractional Exponents
82. Division Rule = AN – K
Power Rule (AN)K = ANK
All the following rules for operations of exponents hold for
fractional exponents N and K.
x(x1/3y3/2)2
x–1/2y2/3
AN
AK
Example G. Simplify the exponents.
Multiplication Rule ANAK = AN + K
Fractional Exponents
83. Division Rule = AN – K
Power Rule (AN)K = ANK
All the following rules for operations of exponents hold for
fractional exponents N and K.
x(x1/3y3/2)2
=
x*x2/3y3
x–1/2y2/3
2*1/3 2*3/2
AN
AK
Example G. Simplify the exponents.
x–1/2y2/3
Multiplication Rule ANAK = AN + K
Fractional Exponents
84. Division Rule = AN – K
Power Rule (AN)K = ANK
All the following rules for operations of exponents hold for
fractional exponents N and K.
x(x1/3y3/2)2
=
x*x2/3y3
x–1/2y2/3
=
2*1/3 2*3/2
x5/3y3
1+2/3
AN
AK
Example G. Simplify the exponents.
x–1/2y2/3 x–1/2y2/3
Multiplication Rule ANAK = AN + K
Fractional Exponents
85. Division Rule = AN – K
Power Rule (AN)K = ANK
All the following rules for operations of exponents hold for
fractional exponents N and K.
x(x1/3y3/2)2
=
x*x2/3y3
x–1/2y2/3
=
2*1/3 2*3/2
=
x5/3y3
1+2/3
x5/3 – (–1/2) y3 – 2/3
AN
AK
Example G. Simplify the exponents.
x–1/2y2/3 x–1/2y2/3
Multiplication Rule ANAK = AN + K
Fractional Exponents
86. Division Rule = AN – K
Power Rule (AN)K = ANK
All the following rules for operations of exponents hold for
fractional exponents N and K.
x(x1/3y3/2)2
=
x*x2/3y3
x–1/2y2/3
=
2*1/3 2*3/2
=
x5/3y3
1+2/3
x5/3 – (–1/2) y3 – 2/3
AN
AK
Example G. Simplify the exponents.
x–1/2y2/3 x–1/2y2/3
= x5/3 +1/2 y7/3
Multiplication Rule ANAK = AN + K
Fractional Exponents
87. Division Rule = AN – K
Power Rule (AN)K = ANK
All the following rules for operations of exponents hold for
fractional exponents N and K.
x(x1/3y3/2)2
=
x*x2/3y3
x–1/2y2/3
=
2*1/3 2*3/2
=
x5/3y3
1+2/3
x5/3 – (–1/2) y3 – 2/3
= x13/6 y7/3
AN
AK
Example G. Simplify the exponents.
x–1/2y2/3 x–1/2y2/3
= x5/3 +1/2 y7/3
Multiplication Rule ANAK = AN + K
Fractional Exponents