The document discusses exponents and rules for exponents. It defines exponents as representing the quantity A multiplied by itself N times, written as AN. It then provides examples to illustrate the multiplication rule (ANAK = AN+K), division rule (AN/AK = AN-K), power rule ((AN)K = ANK), 0-power rule (A0 = 1), and negative power rule (A-K = 1/AK).
6. Example A.
43 = (4)(4)(4) = 64
base
exponent
Exponents
We write the quantity A multiplied to itself N times as AN, i.e.
A x A x A β¦.x A = AN
7. Example A.
43 = (4)(4)(4) = 64
(xy)2
base
exponent
Exponents
We write the quantity A multiplied to itself N times as AN, i.e.
A x A x A β¦.x A = AN
8. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy)
base
exponent
Exponents
We write the quantity A multiplied to itself N times as AN, i.e.
A x A x A β¦.x A = AN
9. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
base
exponent
Exponents
We write the quantity A multiplied to itself N times as AN, i.e.
A x A x A β¦.x A = AN
10. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2
base
exponent
Exponents
We write the quantity A multiplied to itself N times as AN, i.e.
A x A x A β¦.x A = AN
11. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2 = (x)(yy)
base
exponent
Exponents
We write the quantity A multiplied to itself N times as AN, i.e.
A x A x A β¦.x A = AN
12. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2 = (x)(yy)
βx2 = β(xx)
base
exponent
Exponents
We write the quantity A multiplied to itself N times as AN, i.e.
A x A x A β¦.x A = AN
13. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2 = (x)(yy)
βx2 = β(xx)
base
exponent
Exponents
We write the quantity A multiplied to itself N times as AN, i.e.
A x A x A β¦.x A = AN
14. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2 = (x)(yy)
βx2 = β(xx)
base
exponent
Exponents
Rules of Exponents
We write the quantity A multiplied to itself N times as AN, i.e.
A x A x A β¦.x A = AN
15. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2 = (x)(yy)
βx2 = β(xx)
base
exponent
Exponents
Multiplication Rule: ANAK =AN+K
Rules of Exponents
We write the quantity A multiplied to itself N times as AN, i.e.
A x A x A β¦.x A = AN
16. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2 = (x)(yy)
βx2 = β(xx)
base
exponent
Exponents
Multiplication Rule: ANAK =AN+K
Example B.
a. 5354
Rules of Exponents
We write the quantity A multiplied to itself N times as AN, i.e.
A x A x A β¦.x A = AN
17. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2 = (x)(yy)
βx2 = β(xx)
base
exponent
Exponents
Multiplication Rule: ANAK =AN+K
Example B.
a. 5354 = (5*5*5)(5*5*5*5)
Rules of Exponents
We write the quantity A multiplied to itself N times as AN, i.e.
A x A x A β¦.x A = AN
18. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2 = (x)(yy)
βx2 = β(xx)
base
exponent
Exponents
Multiplication Rule: ANAK =AN+K
Example B.
a. 5354 = (5*5*5)(5*5*5*5) = 53+4 = 57
b. x5y7x4y6
Rules of Exponents
We write the quantity A multiplied to itself N times as AN, i.e.
A x A x A β¦.x A = AN
19. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2 = (x)(yy)
βx2 = β(xx)
base
exponent
Exponents
Multiplication Rule: ANAK =AN+K
Example B.
a. 5354 = (5*5*5)(5*5*5*5) = 53+4 = 57
b. x5y7x4y6 = x5x4y7y6
Rules of Exponents
We write the quantity A multiplied to itself N times as AN, i.e.
A x A x A β¦.x A = AN
20. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2 = (x)(yy)
βx2 = β(xx)
base
exponent
Exponents
Multiplication Rule: ANAK =AN+K
Example B.
a. 5354 = (5*5*5)(5*5*5*5) = 53+4 = 57
b. x5y7x4y6 = x5x4y7y6 = x9y13
Rules of Exponents
We write the quantity A multiplied to itself N times as AN, i.e.
A x A x A β¦.x A = AN
21. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2 = (x)(yy)
βx2 = β(xx)
base
exponent
Exponents
Multiplication Rule: ANAK =AN+K
Example B.
a. 5354 = (5*5*5)(5*5*5*5) = 53+4 = 57
b. x5y7x4y6 = x5x4y7y6 = x9y13
Rules of Exponents
Division Rule:
AN
AK = AN β K
We write the quantity A multiplied to itself N times as AN, i.e.
A x A x A β¦.x A = AN
22. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2 = (x)(yy)
βx2 = β(xx)
base
exponent
Exponents
Multiplication Rule: ANAK =AN+K
Example B.
a. 5354 = (5*5*5)(5*5*5*5) = 53+4 = 57
b. x5y7x4y6 = x5x4y7y6 = x9y13
Rules of Exponents
Division Rule:
Example C.
AN
AK = AN β K
56
52
We write the quantity A multiplied to itself N times as AN, i.e.
A x A x A β¦.x A = AN
23. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2 = (x)(yy)
βx2 = β(xx)
base
exponent
Exponents
Multiplication Rule: ANAK =AN+K
Example B.
a. 5354 = (5*5*5)(5*5*5*5) = 53+4 = 57
b. x5y7x4y6 = x5x4y7y6 = x9y13
Rules of Exponents
Division Rule:
Example C.
AN
AK = AN β K
56
52 =
(5)(5)(5)(5)(5)(5)
(5)(5)
We write the quantity A multiplied to itself N times as AN, i.e.
A x A x A β¦.x A = AN
24. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2 = (x)(yy)
βx2 = β(xx)
base
exponent
Exponents
Multiplication Rule: ANAK =AN+K
Example B.
a. 5354 = (5*5*5)(5*5*5*5) = 53+4 = 57
b. x5y7x4y6 = x5x4y7y6 = x9y13
Rules of Exponents
Division Rule:
Example C.
AN
AK = AN β K
56
52 =
(5)(5)(5)(5)(5)(5)
(5)(5)
We write the quantity A multiplied to itself N times as AN, i.e.
A x A x A β¦.x A = AN
25. Example A.
43 = (4)(4)(4) = 64
(xy)2= (xy)(xy) = x2y2
xy2 = (x)(yy)
βx2 = β(xx)
base
exponent
Exponents
Multiplication Rule: ANAK =AN+K
Example B.
a. 5354 = (5*5*5)(5*5*5*5) = 53+4 = 57
b. x5y7x4y6 = x5x4y7y6 = x9y13
Rules of Exponents
Division Rule:
Example C.
AN
AK = AN β K
56
52 =
(5)(5)(5)(5)(5)(5)
(5)(5)
= 56 β 2 = 54
We write the quantity A multiplied to itself N times as AN, i.e.
A x A x A β¦.x A = AN
28. Power Rule: (AN)K = ANK
Example D. (34)5 = (34)(34)(34)(34)(34)
Exponents
29. Power Rule: (AN)K = ANK
Example D. (34)5 = (34)(34)(34)(34)(34) = 34+4+4+4+4
Exponents
30. Power Rule: (AN)K = ANK
Example D. (34)5 = (34)(34)(34)(34)(34) = 34+4+4+4+4 = 34*5 = 320
Exponents
31. Power Rule: (AN)K = ANK
Example D. (34)5 = (34)(34)(34)(34)(34) = 34+4+4+4+4 = 34*5 = 320
Exponents
Since = 1
A1
A1
32. Power Rule: (AN)K = ANK
Example D. (34)5 = (34)(34)(34)(34)(34) = 34+4+4+4+4 = 34*5 = 320
Exponents
Since = 1 = A1 β 1A1
A1
33. Power Rule: (AN)K = ANK
Example D. (34)5 = (34)(34)(34)(34)(34) = 34+4+4+4+4 = 34*5 = 320
Exponents
Since = 1 = A1 β 1 = A0A1
A1
34. Power Rule: (AN)K = ANK
Example D. (34)5 = (34)(34)(34)(34)(34) = 34+4+4+4+4 = 34*5 = 320
Exponents
Since = 1 = A1 β 1 = A0, we obtain the 0-power Rule.
A1
A1
35. Power Rule: (AN)K = ANK
Example D. (34)5 = (34)(34)(34)(34)(34) = 34+4+4+4+4 = 34*5 = 320
Exponents
Since = 1 = A1 β 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
36. Power Rule: (AN)K = ANK
Example D. (34)5 = (34)(34)(34)(34)(34) = 34+4+4+4+4 = 34*5 = 320
Exponents
Since = 1 = A1 β 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since =
1
AK
A0
AK
37. Power Rule: (AN)K = ANK
Example D. (34)5 = (34)(34)(34)(34)(34) = 34+4+4+4+4 = 34*5 = 320
Exponents
Since = 1 = A1 β 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since = = A0 β K1
AK
A0
AK
38. Power Rule: (AN)K = ANK
Example D. (34)5 = (34)(34)(34)(34)(34) = 34+4+4+4+4 = 34*5 = 320
Exponents
Since = 1 = A1 β 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since = = A0 β K = AβK, we get the negative-power Rule.
1
AK
A0
AK
39. Power Rule: (AN)K = ANK
Example D. (34)5 = (34)(34)(34)(34)(34) = 34+4+4+4+4 = 34*5 = 320
Exponents
Since = 1 = A1 β 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since = = A0 β K = AβK, we get the negative-power Rule.
1
AK
A0
AK
Negative-Power Rule: AβK =
1
AK
40. Power Rule: (AN)K = ANK
Example D. (34)5 = (34)(34)(34)(34)(34) = 34+4+4+4+4 = 34*5 = 320
Exponents
Since = 1 = A1 β 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since = = A0 β K = AβK, we get the negative-power Rule.
1
AK
A0
AK
Negative-Power Rule: AβK =
1
AK
Example E. Simplify
a. 30
41. Power Rule: (AN)K = ANK
Example D. (34)5 = (34)(34)(34)(34)(34) = 34+4+4+4+4 = 34*5 = 320
Exponents
Since = 1 = A1 β 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since = = A0 β K = AβK, we get the negative-power Rule.
1
AK
A0
AK
Negative-Power Rule: AβK =
1
AK
Example E. Simplify
a. 30 = 1
42. Power Rule: (AN)K = ANK
Example D. (34)5 = (34)(34)(34)(34)(34) = 34+4+4+4+4 = 34*5 = 320
Exponents
Since = 1 = A1 β 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since = = A0 β K = AβK, we get the negative-power Rule.
1
AK
A0
AK
Negative-Power Rule: AβK =
1
AK
Example E. Simplify
b. 3β2
a. 30 = 1
43. Power Rule: (AN)K = ANK
Example D. (34)5 = (34)(34)(34)(34)(34) = 34+4+4+4+4 = 34*5 = 320
Exponents
Since = 1 = A1 β 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since = = A0 β K = AβK, we get the negative-power Rule.
1
AK
A0
AK
Negative-Power Rule: AβK =
1
AK
Example E. Simplify
1
32b. 3β2 =
a. 30 = 1
44. Power Rule: (AN)K = ANK
Example D. (34)5 = (34)(34)(34)(34)(34) = 34+4+4+4+4 = 34*5 = 320
Exponents
Since = 1 = A1 β 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since = = A0 β K = AβK, we get the negative-power Rule.
1
AK
A0
AK
Negative-Power Rule: AβK =
1
AK
Example E. Simplify
1
32
1
9b. 3β2 = =
a. 30 = 1
45. Power Rule: (AN)K = ANK
Example D. (34)5 = (34)(34)(34)(34)(34) = 34+4+4+4+4 = 34*5 = 320
Exponents
Since = 1 = A1 β 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since = = A0 β K = AβK, we get the negative-power Rule.
1
AK
A0
AK
Negative-Power Rule: AβK =
1
AK
Example E. Simplify
1
32
1
9
c. ( )β12
5
b. 3β2 = =
a. 30 = 1
46. Power Rule: (AN)K = ANK
Example D. (34)5 = (34)(34)(34)(34)(34) = 34+4+4+4+4 = 34*5 = 320
Exponents
Since = 1 = A1 β 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since = = A0 β K = AβK, we get the negative-power Rule.
1
AK
A0
AK
Negative-Power Rule: AβK =
1
AK
Example E. Simplify
1
32
1
9
c. ( )β12
5
=
1
2/5
=
b. 3β2 = =
a. 30 = 1
47. Power Rule: (AN)K = ANK
Example D. (34)5 = (34)(34)(34)(34)(34) = 34+4+4+4+4 = 34*5 = 320
Exponents
Since = 1 = A1 β 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since = = A0 β K = AβK, we get the negative-power Rule.
1
AK
A0
AK
Negative-Power Rule: AβK =
1
AK
Example E. Simplify
1
32
1
9
c. ( )β12
5
=
1
2/5
= 1*
5
2
=
5
2
b. 3β2 = =
a. 30 = 1
48. Power Rule: (AN)K = ANK
Example D. (34)5 = (34)(34)(34)(34)(34) = 34+4+4+4+4 = 34*5 = 320
Exponents
Since = 1 = A1 β 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since = = A0 β K = AβK, we get the negative-power Rule.
1
AK
A0
AK
Negative-Power Rule: AβK =
1
AK
Example E. Simplify
1
32
1
9
c. ( )β12
5
=
1
2/5
= 1*
5
2
=
5
2
b. 3β2 = =
a. 30 = 1
In general ( )βKa
b = ( )K
b
a
49. Power Rule: (AN)K = ANK
Example D. (34)5 = (34)(34)(34)(34)(34) = 34+4+4+4+4 = 34*5 = 320
Exponents
Since = 1 = A1 β 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since = = A0 β K = AβK, we get the negative-power Rule.
1
AK
A0
AK
Negative-Power Rule: AβK =
1
AK
Example E. Simplify
1
32
1
9
c. ( )β12
5
=
1
2/5
= 1*
5
2
=
5
2
b. 3β2 = =
a. 30 = 1
In general ( )βKa
b = ( )K
b
a
d. ( )β22
5
50. Power Rule: (AN)K = ANK
Example D. (34)5 = (34)(34)(34)(34)(34) = 34+4+4+4+4 = 34*5 = 320
Exponents
Since = 1 = A1 β 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since = = A0 β K = AβK, we get the negative-power Rule.
1
AK
A0
AK
Negative-Power Rule: AβK =
1
AK
Example E. Simplify
1
32
1
9
c. ( )β12
5
=
1
2/5
= 1*
5
2
=
5
2
b. 3β2 = =
a. 30 = 1
In general ( )βKa
b = ( )K
b
a
d. ( )β22
5
= ( )25
2
51. Power Rule: (AN)K = ANK
Example D. (34)5 = (34)(34)(34)(34)(34) = 34+4+4+4+4 = 34*5 = 320
Exponents
Since = 1 = A1 β 1 = A0, we obtain the 0-power Rule.
A1
A1
0-Power Rule: A0 = 1
Since = = A0 β K = AβK, we get the negative-power Rule.
1
AK
A0
AK
Negative-Power Rule: AβK =
1
AK
Example E. Simplify
1
32
1
9
c. ( )β12
5
=
1
2/5
= 1*
5
2
=
5
2
b. 3β2 = =
a. 30 = 1
In general ( )βKa
b = ( )K
b
a
d. ( )β22
5
= ( )2 =
25
4
5
2
57. e. 3β1 β 40 * 2β2 =
1
3
β 1*
1
22 = 1
3
β 1
4
= 1
12
Exponents
Although the negative power means to reciprocate,
for problems of collecting exponents, we do not reciprocate
the negative exponents.
58. e. 3β1 β 40 * 2β2 =
1
3
β 1*
1
22 = 1
3
β 1
4
= 1
12
Exponents
Although the negative power means to reciprocate,
for problems of collecting exponents, we do not reciprocate
the negative exponents. Instead we add or subtract them
using the multiplication and division rules first.
59. e. 3β1 β 40 * 2β2 =
Exponents
Although the negative power means to reciprocate,
for problems of collecting exponents, we do not reciprocate
the negative exponents. Instead we add or subtract them
using the multiplication and division rules first.
Example F. Simplify 3β2 x4 yβ6 xβ8 y 23
1
3
β 1*
1
22 = 1
3
β 1
4
= 1
12
60. e. 3β1 β 40 * 2β2 =
Exponents
Although the negative power means to reciprocate,
for problems of collecting exponents, we do not reciprocate
the negative exponents. Instead we add or subtract them
using the multiplication and division rules first.
Example F. Simplify 3β2 x4 yβ6 xβ8 y 23
3β2 x4 yβ6 xβ8 y23
1
3
β 1*
1
22 = 1
3
β 1
4
= 1
12
61. e. 3β1 β 40 * 2β2 =
Exponents
Although the negative power means to reciprocate,
for problems of collecting exponents, we do not reciprocate
the negative exponents. Instead we add or subtract them
using the multiplication and division rules first.
Example F. Simplify 3β2 x4 yβ6 xβ8 y 23
3β2 x4 yβ6 xβ8 y23
= 3β2 x4 xβ8 yβ6 y23
1
3
β 1*
1
22 = 1
3
β 1
4
= 1
12
62. e. 3β1 β 40 * 2β2 =
Exponents
Although the negative power means to reciprocate,
for problems of collecting exponents, we do not reciprocate
the negative exponents. Instead we add or subtract them
using the multiplication and division rules first.
= x4 β 8 yβ6+23
Example F. Simplify 3β2 x4 yβ6 xβ8 y 23
3β2 x4 yβ6 xβ8 y23
= 3β2 x4 xβ8 yβ6 y23
1
9
1
3
β 1*
1
22 = 1
3
β 1
4
= 1
12
63. e. 3β1 β 40 * 2β2 =
Exponents
Although the negative power means to reciprocate,
for problems of collecting exponents, we do not reciprocate
the negative exponents. Instead we add or subtract them
using the multiplication and division rules first.
= x4 β 8 yβ6+23
= xβ4 y17
Example F. Simplify 3β2 x4 yβ6 xβ8 y 23
3β2 x4 yβ6 xβ8 y23
= 3β2 x4 xβ8 yβ6 y23
1
9
1
9
1
3
β 1*
1
22 = 1
3
β 1
4
= 1
12
64. e. 3β1 β 40 * 2β2 =
Exponents
Although the negative power means to reciprocate,
for problems of collecting exponents, we do not reciprocate
the negative exponents. Instead we add or subtract them
using the multiplication and division rules first.
= x4 β 8 yβ6+23
= xβ4 y17
= y17
Example F. Simplify 3β2 x4 yβ6 xβ8 y 23
3β2 x4 yβ6 xβ8 y23
= 3β2 x4 xβ8 yβ6 y23
1
9
1
9
1
9x4
1
3
β 1*
1
22 = 1
3
β 1
4
= 1
12
65. e. 3β1 β 40 * 2β2 =
Exponents
Although the negative power means to reciprocate,
for problems of collecting exponents, we do not reciprocate
the negative exponents. Instead we add or subtract them
using the multiplication and division rules first.
= x4 β 8 yβ6+23
= xβ4 y17
= y17
=
Example F. Simplify 3β2 x4 yβ6 xβ8 y 23
3β2 x4 yβ6 xβ8 y23
= 3β2 x4 xβ8 yβ6 y23
1
9
1
9
1
9x4
y17
9x4
1
3
β 1*
1
22 = 1
3
β 1
4
= 1
12
66. Exponents
Example G. Simplify using the rules for exponents.
Leave the answer in positive exponents only.
23xβ8
26 xβ3
67. Exponents
Example G. Simplify using the rules for exponents.
Leave the answer in positive exponents only.
23xβ8
26 xβ3
23xβ8
26xβ3
68. Exponents
Example G. Simplify using the rules for exponents.
Leave the answer in positive exponents only.
23xβ8
26 xβ3
23xβ8
26xβ3
= 23 β 6 xβ8 β (β3 )
69. Exponents
Example G. Simplify using the rules for exponents.
Leave the answer in positive exponents only.
23xβ8
26 xβ3
23xβ8
26xβ3
= 23 β 6 xβ8 β (β3 )
= 2β3 xβ5
70. Exponents
Example G. Simplify using the rules for exponents.
Leave the answer in positive exponents only.
23xβ8
26 xβ3
23xβ8
26xβ3
= 23 β 6 xβ8 β (β3 )
= 2β3 xβ5
=
23
1
x5
1
* = 8x5
1
71. Exponents
Example G. Simplify using the rules for exponents.
Leave the answer in positive exponents only.
23xβ8
26 xβ3
23xβ8
26xβ3
= 23 β 6 xβ8 β (β3 )
= 2β3 xβ5
=
23
1
x5
1
* = 8x5
1
Example H. Simplify
(3xβ2y3)β2 x2
3β5xβ3(yβ1x2)3
72. Exponents
Example G. Simplify using the rules for exponents.
Leave the answer in positive exponents only.
23xβ8
26 xβ3
23xβ8
26xβ3
= 23 β 6 xβ8 β (β3 )
= 2β3 xβ5
=
23
1
x5
1
* = 8x5
1
Example H. Simplify
(3xβ2y3)β2 x2
3β5xβ3(yβ1x2)3
(3xβ2y3)β2 x2
3β5xβ3(yβ1x2)3
73. Exponents
Example G. Simplify using the rules for exponents.
Leave the answer in positive exponents only.
23xβ8
26 xβ3
23xβ8
26xβ3
= 23 β 6 xβ8 β (β3 )
= 2β3 xβ5
=
23
1
x5
1
* = 8x5
1
Example H. Simplify
(3xβ2y3)β2 x2
3β5xβ3(yβ1x2)3
=
3β2x4yβ6x2
3β5xβ3yβ3 x6
(3xβ2y3)β2 x2
3β5xβ3(yβ1x2)3
74. Exponents
Example G. Simplify using the rules for exponents.
Leave the answer in positive exponents only.
23xβ8
26 xβ3
23xβ8
26xβ3
= 23 β 6 xβ8 β (β3 )
= 2β3 xβ5
=
23
1
x5
1
* = 8x5
1
Example H. Simplify
(3xβ2y3)β2 x2
3β5xβ3(yβ1x2)3
=
3β2x4yβ6x2
3β5xβ3yβ3 x6 =
(3xβ2y3)β2 x2
3β5xβ3(yβ1x2)3 3β5xβ3x6yβ3
3β2x4x2yβ6
75. Exponents
Example G. Simplify using the rules for exponents.
Leave the answer in positive exponents only.
23xβ8
26 xβ3
23xβ8
26xβ3
= 23 β 6 xβ8 β (β3 )
= 2β3 xβ5
=
23
1
x5
1
* = 8x5
1
Example H. Simplify
(3xβ2y3)β2 x2
3β5xβ3(yβ1x2)3
=
3β2x4yβ6x2
3β5xβ3yβ3 x6 =
=
(3xβ2y3)β2 x2
3β5xβ3(yβ1x2)3 3β5xβ3x6yβ3
3β2x4x2yβ6
3β2x6yβ6
3β5x3yβ3
76. Exponents
Example G. Simplify using the rules for exponents.
Leave the answer in positive exponents only.
23xβ8
26 xβ3
23xβ8
26xβ3
= 23 β 6 xβ8 β (β3 )
= 2β3 xβ5
=
23
1
x5
1
* = 8x5
1
Example H. Simplify
(3xβ2y3)β2 x2
3β5xβ3(yβ1x2)3
=
3β2x4yβ6x2
3β5xβ3yβ3 x6 =
= = 3β2 β (β5) x6 β 3 yβ6 β (β3)
(3xβ2y3)β2 x2
3β5xβ3(yβ1x2)3 3β5xβ3x6yβ3
3β2x4x2yβ6
3β2x6yβ6
3β5x3yβ3
77. Exponents
Example G. Simplify using the rules for exponents.
Leave the answer in positive exponents only.
23xβ8
26 xβ3
23xβ8
26xβ3
= 23 β 6 xβ8 β (β3 )
= 2β3 xβ5
=
23
1
x5
1
* = 8x5
1
Example H. Simplify
(3xβ2y3)β2 x2
3β5xβ3(yβ1x2)3
=
3β2x4yβ6x2
3β5xβ3yβ3 x6 =
= = 3β2 β (β5) x6 β 3 yβ6 β (β3)
= 33 x3 yβ3=
(3xβ2y3)β2 x2
3β5xβ3(yβ1x2)3 3β5xβ3x6yβ3
3β2x4x2yβ6
3β2x6yβ6
3β5x3yβ3
78. Exponents
Example G. Simplify using the rules for exponents.
Leave the answer in positive exponents only.
23xβ8
26 xβ3
23xβ8
26xβ3
= 23 β 6 xβ8 β (β3 )
= 2β3 xβ5
=
23
1
x5
1
* = 8x5
1
Example H. Simplify
(3xβ2y3)β2 x2
3β5xβ3(yβ1x2)3
=
3β2x4yβ6x2
3β5xβ3yβ3 x6 =
= = 3β2 β (β5) x6 β 3 yβ6 β (β3)
= 33 x3 yβ3=
27 x3
(3xβ2y3)β2 x2
3β5xβ3(yβ1x2)3 3β5xβ3x6yβ3
3β2x4x2yβ6
3β2x6yβ6
3β5x3yβ3
y3
79. Ex. A. Write the numbers without the negative exponents and
compute the answers.
1. 2β1 2. β2β2 3. 2β3 4. (β3)β2 5. 3β3
6. 5β2 7. 4β3 8. 1
2
( )
β3
9. 2
3
( )
β1
10. 3
2
( )
β2
11. 2β1* 3β2 12. 2β2+ 3β1 13. 2* 4β1β 50 * 3β1
14. 32 * 6β1β 6 * 2β3 15. 2β2* 3β1 + 80 * 2β1
Ex. B. Combine the exponents. Leave the answers in positive
exponentsβbut do not reciprocate the negative exponents until
the final step.
16. x3x5 17. xβ3x5 18. x3xβ5 19. xβ3xβ5
20. x4y2x3yβ4 21. yβ3xβ2 yβ4x4 22. 22xβ3xy2x32β5
23. 32yβ152β2x5y2xβ9 24. 42x252β3yβ34 xβ41yβ11
25. x2(x3)5 26. (xβ3)β5x β6 27. x4(x3yβ5) β3yβ8
Exponents
80. xβ8
xβ3
B. Combine the exponents. Leave the answers in positive
exponentsβbut do not reciprocate the negative exponents until
the final step.
28. x8
xβ329.
xβ8
x330. y6xβ8
xβ2y331.
x6xβ2yβ8
yβ3xβ5y232.
2β3x6yβ8
2β5yβ5x233.
3β2y2x4
2β3x3yβ234.
4β1(x3yβ2)β2
2β3(yβ5x2)β135.
6β2 y2(x4yβ3)β1
9β1(x3yβ2)β4y236.
C. Combine the exponents as much as possible.
38. 232x 39. 3x+23x 40. axβ3ax+5
41. (b2)x+1bβx+3 42. e3e2x+1eβx
43. e3e2x+1eβx
44. How would you make sense of 23 ?
2