SODIUM CORRECTION FORMULA
DR. RAVIKIRAN H M
HYPONATREMIA
STEPS:
1. Change in S. Na+
with 1lt infusate (Adrogus-Madias equation) in meq/lit
=
𝐼𝑛𝑓𝑢𝑠𝑎𝑡𝑒 𝑁𝑎 − 𝑆𝑒𝑟𝑢𝑚 𝑁𝑎
𝑇𝐵𝑊 + 1
2. Volume required in lit
=
𝐷𝑒𝑠𝑖𝑟𝑒𝑑 𝑆𝑒𝑟𝑢𝑚 𝑁𝑎 − 𝑠𝑒𝑟𝑢𝑚 𝑁𝑎
𝐶𝑕𝑎𝑛𝑔𝑒 𝑖𝑛 𝑠𝑒𝑟𝑢𝑚 𝑛𝑎 𝑤𝑖𝑡𝑕 1𝑙𝑖𝑡 𝑖𝑛𝑓𝑢𝑠𝑎𝑡𝑒
=
140 − 𝑠𝑒𝑟𝑢𝑚 𝑁𝑎
𝐶𝑕𝑎𝑛𝑔𝑒 𝑖𝑛 𝑠𝑒𝑟𝑢𝑚 𝑛𝑎 𝑤𝑖𝑡𝑕 1𝑙𝑖𝑡 𝑖𝑛𝑓𝑢𝑠𝑎𝑡𝑒
3. Time required in hrs
=
𝐷𝑒𝑠𝑖𝑟𝑒𝑑 𝑆𝑒𝑟𝑢𝑚 𝑁𝑎 − 𝑠𝑒𝑟𝑢𝑚 𝑁𝑎
𝑟𝑎𝑡𝑒 𝑜𝑓 𝑐𝑜𝑟𝑟𝑒𝑐𝑡𝑖𝑜𝑛
=
140 − 𝑠𝑒𝑟𝑢𝑚 𝑁𝑎
𝑟𝑎𝑡𝑒 𝑜𝑓 𝑐𝑜𝑟𝑟𝑒𝑐𝑡𝑖𝑜𝑛
4. Run rate in ml/hr
=
𝑣𝑜𝑙𝑢𝑚𝑒 𝑟𝑒𝑞𝑢𝑖𝑟𝑒𝑑
𝑡𝑖𝑚𝑒 𝑟𝑒𝑞𝑢𝑖𝑟𝑒𝑑
Note:
FLUID Na+
in meq/lit
3% NS 513
0.9% NS 154
RL 130
0.45% NS 77
5D 0
Total body water (TBW) =0.6xBW in men
=0.5xBW in women
Na+
deficit=0.6xBWx[140-Na+
]
H2O deficit=0.6xBWx[
𝑁𝑎−140
140
]
Example:
70kg Male, Serum Na+
110, rate of correction 1meq/hr, using 3% NS
1. Change in S Na
=
513 − 110
0.6𝑥70 + 1
=
403
43
= 9.37𝑚𝑒𝑞/𝑙𝑖𝑡
2. Volume
=
140 − 110
9.37
=
30
9.37
= 3.2𝑙𝑖𝑡
3. Time
=
140 − 110
1
= 30𝑕𝑟
4. Run rate
=
3200
30
= 106𝑚𝑙/𝑕𝑟
Thus correction is: 3%NS at 106ml/hr for 30hrs.
HYPERNATREMIA
Example:
70kg male, serum Na 160, rate of correction 0.5meq/hr, using 5D
First method:
Change in Serum Na
=
0 − 160
0.6𝑥70 + 1
=
−160
43
= −3.72𝑚𝑒𝑞/𝑙𝑖𝑡
Volume required
=
140 − 160
−3.72
=
−20
−3.72
= 5.37𝑙𝑖𝑡
Time required
=
140 − 160
0.5
=
20
0.5
= 40𝑕𝑟𝑠
Run rate
Two methods
same steps as hyponatremia H2O deficit formula
=
5370
40
= 134𝑚𝑙/𝑕𝑟
Thus rate of correction is 5D at 134ml/hr for 40hrs.
H2O deficit method
= 0.6 × 70(
160 − 140
140
) = 6𝑙𝑖𝑡
So 6lit over 48hrs
=
6000
48
= 125𝑚𝑙/𝑕𝑟

Sodium correction formula

  • 1.
    SODIUM CORRECTION FORMULA DR.RAVIKIRAN H M HYPONATREMIA STEPS: 1. Change in S. Na+ with 1lt infusate (Adrogus-Madias equation) in meq/lit = 𝐼𝑛𝑓𝑢𝑠𝑎𝑡𝑒 𝑁𝑎 − 𝑆𝑒𝑟𝑢𝑚 𝑁𝑎 𝑇𝐵𝑊 + 1 2. Volume required in lit = 𝐷𝑒𝑠𝑖𝑟𝑒𝑑 𝑆𝑒𝑟𝑢𝑚 𝑁𝑎 − 𝑠𝑒𝑟𝑢𝑚 𝑁𝑎 𝐶𝑕𝑎𝑛𝑔𝑒 𝑖𝑛 𝑠𝑒𝑟𝑢𝑚 𝑛𝑎 𝑤𝑖𝑡𝑕 1𝑙𝑖𝑡 𝑖𝑛𝑓𝑢𝑠𝑎𝑡𝑒 = 140 − 𝑠𝑒𝑟𝑢𝑚 𝑁𝑎 𝐶𝑕𝑎𝑛𝑔𝑒 𝑖𝑛 𝑠𝑒𝑟𝑢𝑚 𝑛𝑎 𝑤𝑖𝑡𝑕 1𝑙𝑖𝑡 𝑖𝑛𝑓𝑢𝑠𝑎𝑡𝑒 3. Time required in hrs = 𝐷𝑒𝑠𝑖𝑟𝑒𝑑 𝑆𝑒𝑟𝑢𝑚 𝑁𝑎 − 𝑠𝑒𝑟𝑢𝑚 𝑁𝑎 𝑟𝑎𝑡𝑒 𝑜𝑓 𝑐𝑜𝑟𝑟𝑒𝑐𝑡𝑖𝑜𝑛 = 140 − 𝑠𝑒𝑟𝑢𝑚 𝑁𝑎 𝑟𝑎𝑡𝑒 𝑜𝑓 𝑐𝑜𝑟𝑟𝑒𝑐𝑡𝑖𝑜𝑛 4. Run rate in ml/hr = 𝑣𝑜𝑙𝑢𝑚𝑒 𝑟𝑒𝑞𝑢𝑖𝑟𝑒𝑑 𝑡𝑖𝑚𝑒 𝑟𝑒𝑞𝑢𝑖𝑟𝑒𝑑 Note: FLUID Na+ in meq/lit 3% NS 513 0.9% NS 154 RL 130 0.45% NS 77 5D 0 Total body water (TBW) =0.6xBW in men
  • 2.
    =0.5xBW in women Na+ deficit=0.6xBWx[140-Na+ ] H2Odeficit=0.6xBWx[ 𝑁𝑎−140 140 ] Example: 70kg Male, Serum Na+ 110, rate of correction 1meq/hr, using 3% NS 1. Change in S Na = 513 − 110 0.6𝑥70 + 1 = 403 43 = 9.37𝑚𝑒𝑞/𝑙𝑖𝑡 2. Volume = 140 − 110 9.37 = 30 9.37 = 3.2𝑙𝑖𝑡 3. Time = 140 − 110 1 = 30𝑕𝑟 4. Run rate = 3200 30 = 106𝑚𝑙/𝑕𝑟 Thus correction is: 3%NS at 106ml/hr for 30hrs.
  • 3.
    HYPERNATREMIA Example: 70kg male, serumNa 160, rate of correction 0.5meq/hr, using 5D First method: Change in Serum Na = 0 − 160 0.6𝑥70 + 1 = −160 43 = −3.72𝑚𝑒𝑞/𝑙𝑖𝑡 Volume required = 140 − 160 −3.72 = −20 −3.72 = 5.37𝑙𝑖𝑡 Time required = 140 − 160 0.5 = 20 0.5 = 40𝑕𝑟𝑠 Run rate Two methods same steps as hyponatremia H2O deficit formula
  • 4.
    = 5370 40 = 134𝑚𝑙/𝑕𝑟 Thus rateof correction is 5D at 134ml/hr for 40hrs. H2O deficit method = 0.6 × 70( 160 − 140 140 ) = 6𝑙𝑖𝑡 So 6lit over 48hrs = 6000 48 = 125𝑚𝑙/𝑕𝑟