Jupiter and mercury motions analysis (revised) (2)

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Jupiter And Mercury Motions Analysis (Revised) (2)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –8th
September 2021
Abstract
Paper Argument
- Jupiter Motion analysis disproves Newton Theory of The Sun Mass Gravity and
Planet Motion Independency Concept.
- Because
- Jupiter Motion depends on Mercury and Mars Cycles Periods
- This dependency proves that,
- The solar planets motions be integrated into One Unified Motion
- Means,
- The solar planets be similar to gears move in one machine they do their motions in
comparison with each other, or
- The solar planets be similar to train carriages they move together One Unified
General Motion
- The solar system distances be similar to railways be built by energy and the planets
be similar to trains move on these railways
- Jupiter Motion analysis disproves Newton theory in 2 basic points which are
- (1) The Planet Motion Can't be Independent from the other planets motions
- (2) The Planet Motion Be done by the same force by which Planet Matter is
created, Because the motion features be effective in Planet Matter Dimensions.

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Paper Conclusion
- The Solar System Distances Be Created In A Network Form And Based On One
Geometrical Design.
- Means
- The distances be distributed based on geometrical design in comparison with other
distances and no a single distance be created independent from the other distances
Please scan the figure (ORCID)

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Paper Contents
Subject Page No.
1- Introduction 4
2- Methodology 7
3- Jupiter Motion Data Analysis 10
3-1 Preface 11
3-2 Mercury, Mars and Jupiter Motions Comparison 13
3-3 Mercury, Mars and Jupiter Motions Analysis 21
3-4 Earth and Pluto Motions Analysis 42
4-Mercury Motion Analysis 57
4-1 Preface 58
4-2 The Theory basic Ideas 59
4-3 Light Beam (1.16 mkm/s) Existence Proves Discussion 61
4-4 Jupiter Orbital Circumference Analysis 100
5-The Solar System Distances Be Created In A Network Form 118
5-1 Preface 119
5-2 The Continuum effect Through the Solar System Distances 121
5-3 The Solar System Distances Distribution 126
5-4 The Solar System Distances Dependency On One Another 133
6- The Solar Planets Motions Depend On Different Rates of Time 135
6-1 Preface 136
6-2 Earth And Pluto Rate Of Time 137
6-3 Mercury Motion Rate Of Time 146
6-4 Saturn Motion Rate Of Time 149
6-5 Uranus And Jupiter Rate Of Time 151
7- Planets Unified General Motion 152
7-1 The Planets Unified General Motion Description 153
7-2 The Solar Planets Motions Are Complementary One Another 154
7-3 The Solar Planets Move An Unified Motion (A Team Motion) 159
8- The Sun Age Historical Proves 164
8-1 The Sun Circles The Earth 165
8-2 The Rate (1.0725) 166
8-3 The Sun Diameter Analysis 170
8-4 The Sun Rays Analysis 173
9- Mercury Jupiter Distance Analysis 178
9-1 The Main Idea 179
9-2 Venus Jupiter Distance Analysis 184
9-3 Jupiter and Pluto Motions For The Distance 720.7 mkm 192
9-4 Planets Motions Rates of Time 195
9-5 Planets Motions Interaction 200
9-6 Mars Motion For The Distance 720.7 mkm 215
10- The Solar Planets Motions Analysis 227
10-1 Preface 228
10- 2 The Equal Distances Method 229
10-3 The Inner And Outer Planets Motions Be Distinguished 235
Appendix No.1 The Solar System Equal Distances List 244
References and Biography 246

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1-Introdcution
- Jupiter Orbital Period =4331 days = 2π x 687 days (Mars Orbital Period)
- This data is one noticeable data I have asked about it many times before, because
no clear answer for the question (Why?)
- What's the relationship between Jupiter motion and mars motion based on which
this relationship be produced…
- Why Jupiter Orbital Period = Mars Orbital Period x 2π?
- The answer usually be (Pure Coincidences of numbers)!
- But
- The Question Is So Deep Than The Superficial Answer.
- The question is produced based on a completely different vision of the solar
system motion contradicts and disproves Newton Vision inherited by his theory of
the sun mass gravity.
- The solar planets don't move by the sun mass gravity, the idea is an imaginary one
- The Solar Planet Motion can't be independent from other planets motions
- Simply
- The solar system motion facts contradict Newton Theory of The Sun mass gravity
and the planet motion independency Concept
- The ideas simply are mistaken
- The relationship between Jupiter orbital period and mars orbital period discovered
a deep interaction of the planets motions which create it
- What does this paper try to do?
- We analyze 3 planets motions which are (Mercury – Mars – Jupiter) to prove that
the 3 planets move relative to one another as gears in one machine. Their motions
be integrated together into one unified general motion disproves the planet motion
independency concept and Newton Theory of The sun mass gravity.
- Shortly
- The Nature Of Motion Is Different

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- Newton Was Mistaken
- How the motion be different from what Newton had described?
- Because
- The 3 planets depend on each other data in their motion. let's see examples in
following
- Example no. (1)
- Jupiter orbital period =4331 mkm. But Jupiter moves during (687 day = Mars
orbital period) a distance = 778.6 mkm = Jupiter orbital distance
- Example no. (2)
- Jupiter (13.1 km/s) moves during 24.6 hours (Mars rotation period) a distance =
1.16 mkm
- But
- 4900 mkm (Jupiter Orbital Circumference) = 1.16 mkm x 4224
- Where
- 4222.6 hours = Mercury Day Period (very near to 4224)
- If the data be produced by pure coincidences of numbers, we would to consider
tenths of data as pure coincidences results – no clear logic behind such thinking
- The straight logic tells that, the 3 planets motions have interaction with one
another and this interaction causes the planets motions data to be created taking
into consideration the other planets motions data and based on that no
independency of motion can be supposed…
- I try to show that, the 3 planets motions data analysis gives clearly another vision
for the solar system contradicting Newton Theory of the Sun mass gravity.
- The next question is
- Why and how these 3 planets motions be integrated in one unified motion or create
between one another motions interaction?

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- This question we should answer in this paper discussion
- Let's take a look on the paper contents
- Point no.(3) Jupiter Motions Data Analysis
- In this point we analyze Mercury, Mars And Jupiter Motions Data
- Point no.(4) The Solar System Distances Be Created In A Network Form
- In this point we try to prove that the distances be created in a network form
- Point no.(5) Mercury Motion Analysis
- Mercury Motion provides another reading for the planets motions data.
- Means
- The data which we have discussed in Jupiter Motion Data Analysis we will repeat
its discussion by using another reading…

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2-Methodology
- I use the planets data analysis to discover the planets motions laws
- This method provides good comparisons between The Solar Planets Motions Data
and the theories which try to explain These Planets Motions.
- The planets data analysis is so useful method because it protects greatly from the
imagination.
- By thinking approach we can find suitable tests for the solar system motion
theories, and based on that, let's test Newton Theory of the sun mass gravity.
- The sun mass gravity tells us that,
- The solar planet moves depending on the sun mass gravity independently from all
other planets motions. By that Each Planet Motion Data is almost created
independent from all other planets motions data. this idea we understood simply
from the planet motion independency concept.
- We don't need to discuss the independency concept here but we need to test if the
planets motions data supports it. Because if it doesn't that may refer to another
conclusion tells (Planet Motion Independency Concept Is An Imaginary Idea)
- Let's discuss an example in following:
Example No. (1)
(I)
- 778.6 mkm (Jupiter Orbital Distance) = 1.16 x 671 mkm (Jupiter Venus Distance)
- 720.7 mkm (Jupiter Mercury Distance) = 1.16 x 629 mkm (Jupiter Earth Distance)
- 550.7 mkm (Jupiter Mars Distance) =1.16 x π x149.6 mkm (Earth orbital distance)
- (Max error 1%)
- Shortly
- The Distances Between Jupiter On One Side And Mercury, Venus, Earth And
Mars On The Other Side, All These Distances Are Rated With The Rate (1.16)

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Example No. (1)
(II)
- 778.6 mkm (Jupiter Orbital Distance) =1.072 x 720.7mkm (Jupiter Mercury Distance)
- 720.7 mkm (Jupiter Mercury Distance) =1.072 x 671 mkm (Jupiter Venus Distance)
- 671 mkm (Jupiter Venus Distance) =1.072 x 629 mkm (Jupiter Earth Distance)
- 629 mkm (Jupiter Earth Distance) = (1.072)2
x 550.7 mkm (Jupiter Mars Distance)
- The previous data tries to explain one feature of Jupiter Motion.
- We deal with the same 5 distances which are
- Jupiter Orbital Distance = 778.6 mkm
- Jupiter Mercury Distance = 720.7 mkm
- Jupiter Venus Distance = 671 mkm
- Jupiter Earth Distance = 629 mkm
- Jupiter Mars Distance = 550.7 mkm
- These 5 distances are rated with each other based on the rates (1.16) and (1.0725)
- The question is why these 5 distances be rated with (1.0725) and (1.16)?!
- Because these distances are created based on one another by using one geometrical
design.
- (Imagine we a have a square, each dimension in this square be in proportionality
with this square data and by that all dimensions be rated with one another
geometrically)…
- The 5 distances be rated with one another because they are created as dimensions
in one geometrical design.
- I want to say these distances can't be independent distances from one another. they
are created by using one geometrical system…
- The direct conclusion tells that (Planet Motion Can't Be Independent)…
- I try to show that
- Newton Simple Idea is an imaginary one because

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- The solar system is so complex machine, and the simple vision without data
analysis gives us no facts. The solar system is a building of Gold made based on a
complex geometrical design.
- The provided data is an example for hundreds similar data. each part of the solar
system design refers to a complex machine.
- The direct question is (Why Jupiter distances are rated with one another by these 2
rates 1.0725 and 1.16)??
- The answer is not a simple one
- The rate 1.0725 controls 40% of all distances in the solar system (appendix no. 1
provides a list for these distances)
- Why this rate is used between 40% of all distances? This question still needs
answer but the using is a fact can't be disproved.
- Planets data analysis put planet motion data in comparison with the theory tri to
explain it, by that, we can understand much better both the planet motion data and
the theory which tries to explain it.

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3- Jupiter Motion Data Analysis
3-1 Preface
3-2 Mercury, Mars and Jupiter Motions Comparison
3-3 Mercury, Mars and Jupiter Motions Analysis
3-4 Earth and Pluto Motions Analysis

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3-1 Preface
- Jupiter Motion Data Analysis disproves Newton Theory of The Sun Mass Gravity..
- Because
- Jupiter Motion Data Analysis Proves The Solar Planets Motions Be Integrated Into
One Unified Motion.
- The unified motion can't be created of planets move by the sun mass gravity but be
created by planets move by one force uses them as players in comparisons with
one another.
- Means,
- The force which created the solar planets matters forces them to move as puppets
on a puppets theater relative to one another.
- Let's use one data as example to explain this meaning as clear as possible
Example no. (1)
4331 solar days = 24.6 hours x 175.94 = 687 solar days x 2π
- Where
- 4331 solar days = Jupiter Orbital Period
- 175.94 solar days = Mercury Day Period
- 687 solar days = Mars Orbital Period
- 24.6 hours = Mars Rotation Period
- This data is the main data in this point discussion.
- Let's ask why the 3 cycles periods of time be created in proportionality with one
another?
- We don't understand the clear meaning behind this data!
- Because, for example
- 175.94 solar days = Mercury Day Period, But what's the relationship with (24.6 h)
here? how to explain this equality between data and why they are found?
- Many other questions we need to answer in our try to explain this data,

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- But
- The usual answer be (Pure Coincidence Of Numbers)
- And
- We shouldn't occupy ourselves by fighting with the pure coincidence claim, on the
contrary, we should kill this claim at once by a direct shoot because it prevents us
from a very important understanding for the solar system motion.
- As a result, we ask the direct question
- Does this data depend on planets real motions or be created by pure
coincidence of numbers?
- The answer be in the next point directly, where we bring the 3 planets motions data
and create comparisons between them to prove that These 3 Planets Motions
Can't Be Done Independently From One Another.
- Based on that,
- We analyze the three planets motions in the next point aiming to prove that the 3
planets motions can't be independent from one another.

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3-2 Mercury, Mars and Jupiter Motions Comparison
I-Data
(No. 1) (Mercury and Mars Motions)
- Mercury moves during its day period (4222.6 h.) a distance = 720.7 mkm
- Mars moves during (2802 hours) a distance = 243 mkm
- Mercury moves during (1407.6 hours) a distance = 243 mkm (error 1%)
- Mars moves during 346.6 d. a distance =720.7 mkm (Mercury Jupiter Dis.)
- Mercury moves during 346.6 d. a distance =1419 mkm (with 1433 error 1%)
- Mars moves during 687 d. a distance = 1433 mkm (Mars orbit. Circum)
- Mercury moves during 687 d. a distance =2815mkm (Mercury Uranus Dis.)
- Mars moves during 4331d. a distance = 9010mkm (Saturn orbit. Circum)
- Mercury moves during 4331d. a distance = 2815 mkm x 2π
- Mars moves during 224.7 d. a distance = π x 149.6 mkm (Earth orb. Dis)
- Mercury moves during 224.7 d. a distance = 920 mkm (with 929 error 1%)
- Mars moves during 365.25 d. a distance = π x 243 mkm (0.5%)
- Mercury moves during 365.25 d. a distance = 2 x 748 mkm
- Mars moves during 5040s. a distance= 121464 km= Saturn Diameter (+1%)
- Mercury moves during 5040s. a distance= 238896 km= 2 Saturn Diameters (-1%)
Where
1407.6 h = Mercury Rotation Period 2802 h = Venus Day Period
346.6 days = the nodal year 224.7 days = Venus orbital period
687 days = Mars Orbital Period
4331 days = Jupiter orbital period = 2π x 687 days

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(No. 2) (Mars And Jupiter Motions)
- Mars moves during 636.7 days a distance =1325 mkm= (Venus Saturn Dis.)
- Jupiter moves during 636.7 days a distance =720.7 mkm
- Mars moves during 687 d. a distance= 1433 mkm= Mars Orbital Circumference
- Jupiter moves during 687 d. a distance= 778.6 mkm= Jupiter Orbital Distance
- Mars moves during 4331d. a distance= 9010 mkm= Saturn orbital circumference
- Jupiter moves during 4331 d. a distance= 4900 mkm= Jupiter Orbital Circum.
- Mars moves during 778.6 d. a distance = 1622 mkm = Uranus Neptune Dis.
- Jupiter moves during 778.6 d a distance= 881 mkm =58 days x 15.19 mkm.
- ( 15.19 mkm = the 9 solar planets motions distances total per a solar day).
- Notice
- 2.082 mkm / day x 778.6 days = 1622 mkm = 1.1318 mkm /day x 1433 days
- Where
- 2.082 mkm /day = Mars Velocity Per A Solar Day
- 4.095 mkm /day = Mercury Velocity Per A Solar Day
- 1.13184 mkm /day = Jupiter Velocity Per A Solar Day

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(No. 3) (Mercury And Jupiter Motions)
- Mercury moves during 687 d. a distance= 2815 mkm= Mercury Uranus Distance
- Mercury moves during 1433 d. a distance =5848 mkm= Mercury Pluto Dis.
- Jupiter moves during 1433 d a distance =1622 mkm=Uranus Neptune Dis.
- Mercury moves during 4331d. a distance= 2815 mkm x 2π
- Mercury moves during 4222.6 h a distance = 720.7 mkm
- Jupiter moves during 4222.6 h a distance = 200 mkm = 629 mkm/π
- Mercury moves during 550.7 d a distance = π x 720.7 mkm (0.4%)
- Jupiter moves during 550.7 d a distance = 629 mkm (error 1%)
Please Remember,
Data Group No. (1)
- Mars moves during 687 d. a distance= 1433 mkm= Mars Orbital Circumference
- Mars moves during 4331d. a distance= 9010 mkm= Saturn orbital circumference
- Mars moves during 4331 x π d a distance= 28255 mkm= Neptune orbital circumference
Data Group No. (2)
- Mercury moves during 687 d. a distance= 2815 mkm= Mercury Uranus Distance
- Mercury moves during 4331d. a distance= 2815 mkm x 2π
Data Group No. (3)

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II-Discussion
- The planets move defined distances in defined periods of time.
- The Defined Distance means a distance is known in the solar system, as to be any
planet orbital distance or a distance between any 2 planets.
- The Defined Period Of Time means a period of any planet cycle, as 365.25 days
(Earth orbital period) or any planet orbital period. Or any planet rotation period or
any planet day period. All these periods are defined periods of time
- The argument tells that
- If the solar planets move their motions independently from one another, based on
that, the planets motions during defined periods of time should pass (random)
distances. Because these Planets are independent in their motion from one
another. (For example) Mercury motion depends on its orbital period (88 days) and
doesn't interest neither for Mars orbital period (687 days) nor for Jupiter orbital
period (4331 days) and by that, Mercury during these periods (687 days and 4331
days) should move Random distances (not be one of the solar system distances).
- The data disproves Planet Motion Independency Concept. because the (3)
planets move defined distances in defined periods of time. These planets motions
aren't independent from one another. These motions are done based on One
Geometrical Design. And these motions be similar to Chess Board Pieces
Motions. Each Motion is calculated geometrically and be obligatory and takes into
consideration the other planets motions and their effects.

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- Why Did We Create The Comparisons Between The 3 Planets Motions?
- We have found an interesting relationship between the 3 planets cycles periods,
let's remember this relationship in following…
- Where
- We have referred to this data in the point preface, Then we have asked why the 3
planets cycles periods be in proportionality with one another? Is there a real reason
behind or it's found by pure coincidence of number? And to find a definitive
answer for the "Pure Coincidences" claim, we have compared between the 3
planets motions to prove that these planets motions can't be independent from one
another.
- And
- The previous planets motions comparisons prove that their motions can't be
created independently from one another.
- So,
- The simple puzzle of the cycles periods be supported now by huge number of the 3
planets motions data which shows that some great force be behind the 3 planets
and forces them to move (in proportionality) with one another, and forces each
planet motion to take into consideration the other planets motions data!
- The question is
- Why Each Planet Motions Data Be In Proportionality With The Other
Planets Motions Data?

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- In the next point (3-3) we analyze the 3 planets motions data in details…
- But
- There are 2 features of motion we have to refer to them because we should use in
our discussion, these 2 features are
- (1st
Feature)
- Each planet motion uses a different rate of time from the other planets motions
rates of time… that means, the planets motions don't use one rate of time but
different rates of time which is an important feature of the solar planets motions.
- (2nd
Feature)
- The solar system distances values be used as periods of time by the solar planets
motions depending on their motions rates of time.
- For example
- 1 hour of Pluto motion =4.61 hours of the Earth moon motion
- This is the rate of time between Pluto and The Moon Motions.
- But 50% of all distances in the solar system be rated based on the rate (4.61)
- That's happened because these distances be used as periods of time
- For example
- Mercury moves during its rotation period (1407.6 h) a distance = 243 mkm (1%)
- Venus moves during its day period (2802 h) x 2 a distance = 706 mkm
- Where
- 243 days = Venus Rotation Period
- 706 days = π x 224.7 days (= Venus Orbital Period)
- These 2 data is an example of similar hundreds, where usually the distances be
used as periods of time by the planets motions.

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Discussion
- The previous 2 features are basic features used in the solar planets motions
- Many explanations can be provided to answer why or how these 2 features be used
by the planets motions.
- But
- We will analyze (The 3 planets Motions Data),
- That means, we follow the data and don't try to explain it till we have a complete
vision about it… means, we don't create our own ideas to explain how the data
works because the data is a treasure we shouldn't destroy it by our ideas, we should
analyze the data as deep as possible and there in the depth we can see the basic
understanding behind it.
- I want to say,
- These features of motions are working features because of that they be explained
through hundreds of data as a result for their using frequently. Now the reason
behind these features using is one more question we don't deal here because we try
to know if really these features be used by the planets motions data or not …
- I mean,
- We should move step by step, Because
- Newton told us that, The Solar Planet moves by The Sun Mass Gravity Force
independently in its motion from all other solar planets motions. this is the basic
theory based on which the solar planets motions be described and understood
- And, Here
- We create comparisons between the 3 planets motions data and analyze them.
- By this analysis and comparisons we should prove or disprove Newton Theory.
And If we disprove Newton theory we have to provide an alternative description
for the solar planets motions
- Because of that,

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- I have provided the 2 new features because we use them in the planets motions
comparisons and analysis. And by the analysis we should prove these 2 features
are used really in the planets motions and based on that we provide a new vision
for the solar planets motions.
- Why this vision be proved?
- Because it depends on the 3 planets motions data
- Shortly
- We provide a description for the planets motions under the analysis form, where
this description be created based on the planets motions real data and disproves
Newton Theory and its description.
- Because of that, the question (why these features be used?) will be discussed later
in this paper but not in our analysis and comparisons discussion.
- Notice
- Because the solar system distances be used as periods of time and the planets use
different rates of time among themselves. As a result for this fact, the solar system
distances be created in a network form which should be discussed and proved in
(Point no.5)

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3-3 Mercury, Mars and Jupiter Motions Analysis
I –Data
(1)
- Where

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Discussion
Equation no.(1)
- 4331 days = Jupiter Orbital Period, and 175.94 days = Mercury Day Period, and
- 687 days = Mars Orbital Period , and 24.6 hours = Mars Rotation Period
- This is the data which we try to understand in this discussion point. Our analysis
started in the point preface (3-1) and then we compared the 3 planets motions data
in point (3-2) to prove that the 3 planets motions can't be independent from one
another,
- Now , Let's try to understand this data as possible in following:
- The data tells that
- This conclusion is a try to understand the equation no. (1).
- Based on this conclusion we have 3 rates which are (24.6, 3.9 and 2π) should be
found between these 3 planets motions data
- Because
- The idea tells, the planets motions be interacted with one another based on these 3
rates of time.
- We still don't understand how planets motions rates of time (if found) effect on
these planets motions. but we have 3 rates should be effective on the 3 planets
motions data and because of that we should test each rate individually
- Let's do that in following:
1 hour of Mercury Motion = 24.6 hours of Jupiter Motion
And
1 hour of Mercury Motion = 3.9 hours of Mars Motion
And
1 hour of Mars Motion = 2π hours of Jupiter Motion

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3-3-1 The Motions Rates Of Time
- The idea tells us
- 1 hour of Mercury motion = 24.6 hours of Jupiter motion
- Let's test this rule in following
(Test No.1) (Part no.1)
- 671 h (of Mercury Motion) = 16506.6 h =687.8 solar days of Jupiter motion
- Let's analyze this data in following:
- 687 days x 24 h =24.6 h (Mars rotation period) x 671
- And
(I)
- Mercury moves during (671 hours) a distance = 2 x 57.24 mkm (1)
- (Mercury orbital distance 57.9 mkm has error 1% with 57.24 mkm)
But
- Mercury rotation period (1407.6 h) = Mars rotation period (24.6 h) x 57.2 (2)
(II)
- Jupiter moves during (687 days) a distance = 778.6 mkm
- (Jupiter orbital distance =778.6 mkm)

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- 671 h (of Mercury Motion) = 2616.9 h = 109 solar days of Mars motion
- We analyze this data also in following:
(I)
- Mercury moves during (671 hours) a distance = 2 x 57.24 mkm (1)
- (Mercury orbital distance 57.9 mkm has error 1% with 57.24 mkm)
But
- Mercury rotation period (1407.6 h) = Mars rotation period (24.6 h) x 57.2 (2)
(II)
- Mars moves during (109 days) a distance = 227.9 mkm
- (Mars orbital distance =227.9 mkm)

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Discussion
- Shortly
- 671 hours of Mercury Motion = 687 days of Jupiter motion = 109 days of
Mars motion
- But
- During 671 hours Mercury moves a distance 57.2 mkm= 2 x Mercury Orbital
Distance (error 1%)
- And
- During 687 days Jupiter moves a distance 778.6 mkm = Jupiter Orbital
Distance
- And
- During 109 days Mars moves a distance 227.9 mkm = Mars Orbital Distance
- How to understand this data?
- Can we answer Why? the data is incredible rich and priceless
- Why these motions be done based on this data?!
- For more complex discussion
(1)
- Mercury rotation period = Mars rotation period x 57.2
- But
- Mercury moves during 671 hours a distance = 2 x 57.2 mkm
(2)
- Mercury day period 4222.6 hours = Mars day period 24.7 hours x 171.7
- But
- Mercury Mars Distance = 170 mkm (error 1% with 171.7)
- It's incredible puzzled data
- How to explain it?!!

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- But
- We should see this data as clear as possible
- The 3 planets create 3 different rates of time for their motions and these rates are
- 1 h Mercury Motion = 24.6 h Jupiter Motion = 3.9 h Mars Motion
- As a result
- 671 h Mercury Motion = 687 day Jupiter Motion = 109 days Mars Motion
- But
- During 671 hours Mercury moves a distance = its orbital distance x 2 (error 1%)
- During 687 days Jupiter moves a distance = its orbital distance
- During 109 days Mars moves a distance = its orbital distance
- Why?
- 1 h of Mercury Motion = 24.6 h of Jupiter Motion
- But
- 24.6 hours = Mars Rotation Period (be used by Jupiter not by Mars!)
- Also
- 687 days = Mars orbital period (be used by Jupiter not by Mars)
- Why?
- Let's provide more data for better vision
- (17.4 deg /7 deg) = (10747 days /4331 days) = (24.1/9.7) =(24.6/9.9) =2.48
- 7 degrees = Mercury Orbital Inclination
- 17.4 degrees = The inner planets orbital inclinations total
- 10747 days = Saturn Orbital Period
- 4331 days = Jupiter Orbital Period
- 24.1 km/s = Mars Velocity
- 9.7 km/s = Saturn Velocity
- 9.9 hours = Jupiter Rotation Period
- 2.5 d degrees = Saturn Orbital Inclination

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Discussion (Continued)
- We have one period of time seen in 3 different forms, which is
- 671 hours for Mercury Motion
- 687 days for Jupiter Motion
- 109 days for Mars Motion
- These 3 periods of time are equal
- Jupiter moves during its period a distance = Its Orbital Distance
- Mars moves during its period a distance = Its Orbital Distance
- But
- Mercury moves during its period a distance = 2 x Its Orbital Distance (error 1%)
- Why Mercury passes (double) of its orbital distance?
- We even don't know why each planet moves a distance = its orbital distance during
this period of time?
- And the second question is (Why Mercury pass a double value of its orbital
distance?)
- Let's analyze more data for some better understanding
- More Data Analysis
- Mercury Day Period =4222.6 hours which is less than (176 solar days) with a
value (1.4 h =5040 seconds)
- During 5040 seconds Mercury (47.4 km/s) moves a distance = 2 x 119448 km =
Saturn diameter (= 120536 km) (error -1%)
- But
- During 5040 seconds Mars (24.1 km/s) moves a distance =121464 km = Saturn
diameter (= 120536 km) (error +1%)
- Again the data tells when Mars moves (one value) during the same period of time
Mercury moves (double value)!
- During 5040 seconds Jupiter (13.1 km/s) moves a distance =66024 km !!

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- Let's now see Jupiter motion distance
- During 5040 seconds Jupiter (13.1 km/s) moves a distance =66024 km !!
- 120536 km (Saturn diameter) = 66024 km x 1.8 (error 1.4%)
- And
- What's the rate (1.8)??
- 2.082 mkm =1.16 mkm x 1.8
- Where
- 2.082 mkm = Mars Motion Distance During A Solar Day
- 1.16 mkm = Jupiter Motion Distance During Mars Rotation period (24.6h)
- The rate (1.8) be used between Saturn diameter (1205.6km) and Jupiter motion
distance 66024 km because both Mercury and Mars motion distances be relate to
Saturn diameter and I thought that may be this distance (120536 km) is the target
of their motions.
- Notice
- 5040 seconds = 88 seconds x 57.2
- (where 57.2 = Mercury Rotation Period / Mars Rotation Period)
- We know, Mercury day period = 4222.6 hours =175.94 solar days
- but
- Mercury Orbital Period = 88 days
- We have asked before,
- Why Mercury day period= 2 x Mercury Orbital Period?
- Means,
- Our 3 planets motions data discussion can answer the old question why mercury
day period = 2 x Mercury orbital period
- Because
- Mercury moves during the period (double it orbital distance) but Jupiter and Mars
move distances equal (their orbital distances)

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- The double value is the reason behind
- But we have to analyze it as deep as possible
- Our key is the equation (5040 seconds = 88 seconds x 57.2)
- But
- This equation we can't discuss here, because the period 88 seconds is seen by us as
88 days and this rate of time (1 second = 1 day) is the rate of time between light
and planet motions
- The fact is that, the planet motion depends on a light beam motion that because the
matter is created out of light and moves with its parent light by using different rate
of time. This story we should discuss through Mercury Motion Data Analysis
where Mercury Data provides another and different reading for the planets motions
data
- Means,
- The data which we have discussed about the 3 planets, this all data has another
reading and we should discuss this same data once again by a new vision… this
process we can do only by Mercury motion analysis.
- Shortly
- The question (Why Mercury day period be = 2 Mercury Orbital Periods?) this
question we should discuss in Mercury Motion Data Analysis (Point No. 4)
- Notice (3)
- Neptune orbital inclination = 1.8 degrees! And
- 3.1 deg (Jupiter axial tilt) – 1.3 deg (Jupiter orbital inclination) = 1.8 deg

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- Because (1 Hour Of Mercury Motion =24.6 Hours Of Jupiter Motion)
- 175.94 solar days of Mercury Motion = 4331 solar days of Jupiter motion
- But
- Mercury moves during its day period (175.94 days) a distance = 720.7 mkm
- And
- Jupiter moves during it orbital period (4331 days) a distance = 4900 mkm
- Where
- 4900 mkm = 6.8 x 720.7 mkm
- 88 solar days of Mercury Motion = 2164.8 solar days of Jupiter motion
- But
- Mercury moves during (88 days) a distance = 360 mkm
- And
- Jupiter moves during (2164.8 days) a distance = 2450 mkm
- Where
- 360 mkm =Mercury Orbital Circumference
- 2450 mkm = π x 778.6 mkm (Jupiter Orbital Distance)
- 1407.6 h of Mercury Motion = 34627 h = 1442.8 solar days of Jupiter motion.
- But
- Mercury moves during its rotation period (1407.6h) a distance = 243mkm (1%)
- And
- Jupiter moves during (1442.8 solar days) a distance = 1622.7 mkm (0.6%)
- Where
- 243 days =Venus rotation period
- 1622.7 mkm = Neptune Uranus Distance

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More Discussion
- Let's summarize the data shortly
(1)
- Mercury moves during (175.94 days) a distance =720.7 mkm and Jupiter moves
during 4331 days a distance =4900 mkm
- Both passed distances are related to its planet motion because
- 720.7 mkm = Mercury Jupiter Distance
- 4900 mkm = Jupiter Orbital Distance
(2)
- Mercury moves during (88 days) a distance =360 mkm and Jupiter moves during
2165.5 days a distance = 2450 mkm = π x 778.6 mkm
- Both passed distances are related to its planet motion because
- 360 mkm = Mercury Orbital Circumference
- π x 778.6 mkm = Jupiter Orbital Distance
- 88 days = Mercury orbital period
(3)
- Mercury moves during (1407.6 h) a distance =243 mkm (1%)
- And Jupiter moves during (1407.6 h x 24.6=1442.8 days) a distance = 1622.7 mkm
- Both passed distances are NOT related to its planet motion because
- 243 days = Venus Rotation Period
- 1622.7 mkm = Uranus Neptune Distance
- In Brief
- We Should Return To The Argument Of The Discussion In Point No. (3-2)
- Because
- If these planets motions be independent from one another, the distances should be
Random Distances
- Similar to that,

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- If these rates if time are invented and not used by the planets real motions, the
passed distances should be random and not defined distances in the solar system
- Some question can be raised here tells that
- The distance 243 mkm isn't a distance but it's used as a period of time (243 Solar
days = Venus Rotation Period)?
- But
- Mars moves during Venus day period (116.75 solar days) a distance =243 mkm,
- The passed distance by Mars proves that, this distance be mentioned by the solar
system geometrical design because the same distance be passed by 2 planets
during (defined periods of time which are 1407.6 hours and 116.75 days)
- (1407.6 h = Mercury rotation period and 116.75 = the nodal year)
- That tells the distance is mentioned geometrically
- But
- Because the second planet is Mars
- That tells the distance 243 mkm isn't only designed geometrically but also
effective in our 3 planets motions data analysis..
- That makes the distance 243 mkm is similar to any defined distance (or even more
effective than the others)

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3-3-2 The Rate of time 24.6
I - Data
(1)
778.6 mkm x 24.6 =19153.6 = 2π x 3030 mkm (= Uranus Pluto Distance) (0.6%)
(2)
720.7 mkm x 24.6 =17730 = 2π x 2815 mkm (Mercury Uranus Distance)
(3)
671 mkm x 24.6 = 16506.6 = 2π x 2644 mkm (Mars Uranus Distance) (0.7%)
(4)
629 mkm x 24.6 = 15473.4 = π x 4900 mkm (Jupiter Orbital Circumference)
(5)
550.7 mkm x 24.6 = 13547.2 = π x 4331 mkm (Jupiter Orbital Period =4331 days)
(6)
2094 mkm x 24.6 = 51513 = 2π2
x 2644 mkm (Mars Uranus Distance) (1.3%)
(7)
3716.5 mkm x 24.6 = 91426 = (Pluto orbital period 90560 days error 1%)
(8)
5127 mkm x 24.6 =126124= 3.9 x 32000 mkm (=37100 mkm- 4900 mkm)
778.6 mkm = Jupiter Orbital Distance
720.7 mkm = Jupiter Mercury Distance
671 mkm = Jupiter Venus Distance
629 mkm = Jupiter Earth Distance
550.7 mkm = Jupiter Mars Distance
2094 mkm = Jupiter Uranus Distance
3716.5 mkm = Jupiter Neptune Distance
5127 mkm = Jupiter Pluto Distance
4900 mkm = Jupiter Orbital Circumference
37100 mkm = Pluto Orbital Circumference

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II – Discussion
- The previous data uses all distances between Jupiter and the other planets, and
shows that these distances be rated with (24.6) with other defined distances in the
solar system.
- Why?
- We can move step by step for better vision
- As we have seen,
- The planets move depend on the rate (24.6) and we have concluded that because
the planets move (defined distances) in (defined periods of time) which use the
rate (24.6) between them based on the rule (1 hour of Mercury Motion = 24.6
hours of Jupiter Motion)
- As A Result
- The planets move defined distances during defined periods of time use the rate
(24.6) between them.
- And we know that the distances be used as periods of time by the planets motions
- As a result
- The distances be rated based on the rate (24.6) as seen in the previous data
- I want to say that,
- The distances in the solar system are defined by some very complex method, based
on that the previous distances has a complex explanation.
- Means
- This discussion is so simple and can't explain clearly how these distances be
created or distributed … let's use one example for better understanding
- 720.7 mkm (Mercury Jupiter Distance) x 24.6 = 2π x 2815 mkm (Mercury
Uranus Distance)
- Both distances are Mercury distances, the rate (24.6) is found between 2 distances
of Mercury to Jupiter and Uranus
- Why?

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- I have no answer,
- I want to say, the understood general idea tells that (there's a rate of time 24.6
between Mercury and Jupiter Motions)
- And
- The distances be used as periods of time
- As result
- The rate 24.6 which controls the periods of time be used also as distances
distribution rate
- This is the general idea
- But each distance has its own story how to be created based on this rate (24.6)
- This idea is complex because
- Many other rates of time be used for the planets motions, and as a result, the
distance which is distributed based on the rate (24.6) will be redistributed based on
another rate for example (3.9)
- By that the distances be created in some a network form
- But
- This network can't be discovered clearly unless we discovered all planets motions
rates of time and form them in one general map
- This map which is designed by the planets rates of time will be the indicator for
the distances network map
- Let's discuss the second rate of time (3.9) which is found between Mars and
Mercury, where
- 1 Hour Of Mercury Motion Be = 3.91 Hours Of Mars Motion

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3-3-3 The Rate of time 3.91
I - Data
(1)
687 days (Mars orbital period) = 175.94 days (Mercury Day Period) x 3.91
(2)
227.9 mkm (Mars Orbital Distance) = 57.9 mkm (Mercury Orbital Distance ) x 3.91
(error 0.7%)
(3)
671 mkm (Venus Jupiter Distance) = 170 mkm (Mercury Mars Distance ) x 3.91
(error 1%)
(4)
360 mkm (Mercury Orbital Circumference) =91.7 mkm (Mercury Earth Distance ) x 3.91
(5)
2815 mkm (Mercury Uranus Distance) =720 mkm (Mercury Jupiter Distance ) x 3.91
(6)
2π x 2764 mkm (Venus Uranus Distance) = (4437.2 mkm Mercury Neptune Distance)
x 3.91
(7)
1407.6 mkm = 360 mkm (Mercury Orbital Circumference) x 3.91
(1407.6 hours = Mercury rotation period)
(8)
5378 mkm = 1375.6 mkm (Mercury Saturn Distance) x 3.91
Where
5378 hours =224.7 days = Venus Orbital Period

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II – Discussion
- Equations no (1 and 2) summarizes the idea clearly
- Because
- (227.9 mkm/ 57.9 mkm) = (687 days /175.94 days) =3.91 (error 0.8%)
- Where
- 227.9 mkm =Mars Orbital Distance
- 57.9 mkm =Mercury Orbital Distance
- 687 days = Mars Orbital Period
- 175.94 days = Mercury Day Period
- This data gives a clear reference for the rate (3.91) as a basic one between Mercury
and Mars Data
- If this data be found alone – no one can consider it be created resulting from pure
coincidence of numbers – but it must be created based on a geometrical reason
- The point is that,
- The basic data gives more extension for this one and proves that it be created as a
basic player in the planets motion – let's remember the basic data
- 4331 days (Jupiter Orbital Period) = 2π x 687 days ( Mars Orbital Period) =
24.6 x 175.94 days (Mercury day period) - And
- 24.6 hours = Mars Rotation Period - Simply
- The rate (3.91) is the rate of time between Mercury and Mars motions and based
on this rate the solar system distances be distributed and created…
- For that reason the rate (3.91) is found deeply and widely in the solar system
distances distribution as be seen in the data
- I want to say
- The discussion is so limited, Because many basic rules of the planets motions be
unknown for us – because of that the discussion can't reach to the data depth which
is the very rich point of discussion.
- The situation is complex because

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- Newton theory of The Sun Mass Gravity and planet motion independency is an
imaginary idea and completely mistaken
- The fact is that, the sun is created after all solar planets creation and motion, and
even the sun is created depending on the solar planets motions!
- I want to say
- We try to wake up from the imaginary dreams. We see the facts with difficulties
and can't see clearly the world around, but our situation now is better that when we
followed Newton theory because it's completely imaginary idea
- We now understand some of the planets motions facts (not all of them), but in
Newton Theory no facts be provided but some imaginary ideas
- Now, Let's ask, why not this paper provides an imaginary idea also? as Newton
one? why this paper provides facts?
- Because We Analyze The Planets Motions Data
- If someone asked Newton why the rate (24.6) be used frequently between the solar
system distances? Newton would answer telling that (Because of Pure Coincidence
of numbers!)
- Why did he tell this answer? Because he has no another explanation
- That means,
- Hundreds of Planets Motions Data will be considered as (Pure Coincidences of
numbers) and as a result we would have to remove Planets Motions Data and get
ride of them because no available explanations for any of them
- That's the point I fight for
- Because
- The theory be acceptable without reference for planets motions data. means, the
theory be acceptable spite its contradiction with planets motions data and by that
we lost our method to test the theory and know if it's a correct one or built on an
imaginary idea -
- Let's discuss equation no. (3)

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Equation no. (3)
671 mkm (Venus Jupiter Distance) = 170 mkm (Mercury Mars Distance ) x 3.91
- The equation is understood
- One question only we need to discuss let's provide it immediately
- (4222.6 h Mercury Day Period) = 24.6 h (Mars rotation period) =171.7
- (1407.6 h Mercury Rotation Period) = 24.6 h (Mars rotation period) =57.2
- But
- 170 mkm = Mercury Mars Distance (error 1%)
- 57.9 mkm = Mercury Orbital Distance (error 1%)
- Why the distances be used as rates in these 2 data?
- There's A Geometrical Machine Behind This Data, but how to discover it?

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3-3-4 The Rate of time (2π)
I - Data
(1)
4331 days (Jupiter Orbital Period) = 687 days (Mars Orbital Period) x 2π
(2)
550.7 mkm (Jupiter Mars Distance) x 2 x 24.6 = 4331 mkm x 2π
(3)
4495.1 mkm (Neptune orbital distance) = 720.7 mkm (Mercury Jupiter distance) x 2π
II – Discussion
- No need to insert many data depends on the rate (2π), because
- It's the basic rate in the solar planets motions and tenths or even hundreds of data
depends on the rate (2π).
- And the solar system distances distribution equation depends on this rate, let's see
this equation in following
1.16 mkm/s x (2) x 86400 seconds =(2) x 100733 mkm = (37100 mkm – 4900
mkm) x 2π = 28255 mkm + (2) x 86400 mkm
- Where
- 100733 mkm = The 9 Planets Orbital Circumferences Total
- 37100 mkm = Pluto Orbital Circumference
- 4900 mkm = Jupiter Orbital Circumference
- This equation we should discuss later, where this is the main equation of the solar
system distances distribution (and the solar system energy distribution because
Distance = Energy)
- The rate (2π) creates a very important effect on this e equation discussion
- Shortly
- This equation discussion gives a new meaning for the rate (2π) but we have to wait
because this meaning depends on another reading for the data (be discussed in
point no.4 Mercury Motion Analysis

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- A Conclusion
- Many distances be distributed based on the rate (2π), and that tells the rate of time
between Jupiter and Mars motions is a general rate used in the solar system and
that tells it's not a rate between 2 planets, instead the 2 planets use one general rate
in the solar system
- i.e.
- We have 2 passengers decided to leave their own car and use the Metro
- It’s a general rate in the solar system and its effect beyond Jupiter and Mars
motions range
- As a result
- In Kepler (3rd
Law) (The distance3
= The Period2
x Constant)
- In this law, if we use the solar planets motions data, the constant will be (25)
- But
- Mars Axial Tilt =25.2 degrees
- Means,
- Mars axial tilt be used in kepler law as a constant for all planets because the rate
between Jupiter and Mars is (2π) which is a general rate in the solar system

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3-4 Earth and Pluto Motions Analysis
(Point No. 1) (Preface)
- We analyze Earth and Pluto Motions here because of 2 basic reasons:
- (1) The rate of time between Earth and Pluto = 2π
- (2) The rate of time between Pluto and The Earth moon = 4.61
- We remember that
- 1 hour of Mars Motion = 2π hours of Jupiter Motion
- And also
- 1 hour of Earth Motion = 2π hours of Pluto Motion
- By that we have one rate of time be used for 2 groups of planets motions
- That shows the basic reason behind the analysis of Pluto and Earth motion in out
discussion.
- The second reason is the rate (4.61) between Pluto and The Earth Moon Motions,
where this rate (4.61) effects and distribute 50% of all distances in the solar system
- That shows the rate (4.61) has a massive effect
- But
- The basic point is that,
- The rate (2π) between Jupiter and mars is a powerful rate and effects greatly on the
solar planets motions…
- Now this same rate be used again by Earth and Pluto
- And this rate using produced the rate (4.61) which effects on 50% of all distances
of the solar system
- All these reasons pushes to provide a deep analysis between Earth and Pluto
motions…

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(Point No. 2) (Earth, Its Moon And Pluto Rates Of Time)
(Earth And Pluto Rate of Time)
(A)
- Earth (29.8 km/s) moves during a solar day (24 h) a distance = 2574720 km
- Pluto (4.7 km/s) moves during its day (153.3) a distance = 2593836 km
- The moon displacements total during (29.53 days) = 2598693 km
- Pluto and the moon motion distances be equal but they are different from Earth
motion distance with (1%).
(B)
- (Earth velocity / Pluto velocity) = 2π (error 1%)
- (Pluto Day period/ earth day period) = 2π (error 1.7%)
- Pluto orbital distance 5906 mkm = Earth orbital circumference 940 mkm x 2π
- Pluto orbital period 90560 days = Earth Cycle (1461 days) x 2π3
(C)
- 1 hour of Earth motion= 29.53 hours of the moon motion (explained in discussion)
(Pluto And The Moon Rate Of Time)
(1)
(406000 km /88000 km) = (708.7 h/ 153.3 h) = 4.61
(2)
Tan (12.2) x 708.7 hours = 153.3 hours
(3)
Tan (13.17) x 655.7 hours = 153.3 hours
(4)
2 x 153.3 h = 4.61 x 66.8 But
(708.7 h /10.7 h) = (655.7 h /9.9 h) =66.23 (error 1%).
(5)
413600 km cos (10.96 deg) = 406000 km
(6)
(10.96 deg /1.7 deg) = (153.3 h /24 h) (error 1%)

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II- Discussion
- How to define the rate of time between 2 planets motions
- Let's remember how we have defined the 3 planets rates of time, we have used the
following equation
- 4331 days =175.94 x 24.6 = 2π x 687 days
- That means, the rate of time be defined as a rate between the planets cycles periods
- But
- Te difficulty is to know which cycle period be used. For example in this equation
if we use Mercury orbital period (88) in place of its day period (175.94) the
produced rate will not be working because it's not be used frequently as the day
period. That means, the planet uses its data for specific direction…
- For example, 1 hour of Mercury motion = 9.18 hours of Pluto motion. this rate of
time be produced as a rate between Mercury rotation period and Pluto day period.
Here Mercury doesn't use its day period with Pluto but used it with Jupiter. It's te
planet direction of motion…
- How can we discover that? the rate be used frequently in its direction –for example
– Mercury moves during its day period a distance = 720.7 mkm =Mercury Jupiter
distance, this data tells Mercury uses its day period with Jupiter motion interaction
- Let's return to Earth and Pluto Discussion
- 1 Hour Of Earth Motion = 2π Hours Of Pluto Motion
- How to know that?
- 153 hours (Pluto Day Period) = 24 hours(Earth day period) x 2π (error 1%)
- And
- Earth velocity 29.8 km/s = Pluto velocity 4.7 km/s x 2π (error 1.7%)
- The errors don't effect negatively because the planets motions distances are
different with rates (1% and 2%), by that we consider the errors found for
geometrical necessities.

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- The question should be
- How the rate (2π) be transported as a rate between Jupiter and mars to be a rate
between Earth and Pluto?
- Let's see the following data:
- Venus Velocity = Uranus Velocity x 5.1
- Mars Velocity = Pluto Velocity x 5.1
- The Moon Velocity = Neptune Velocity x 5.1
- That means,
- The rate (5.1) is a continuous force moves through the solar planets motions and
effects on planets according to its geometrical design effect
- We clearly deal with a system of data and a geometrical mechanism found behind
this data.
- The transportation process for the rate (2π) is done between Mars and Pluto
Motions.
- That may explain the deep interaction between Pluto and the Earth Moon Motions.
- The moon data analysis will show that the relationship with Pluto motion is so
strong one.
-
- Notice
- The 3 planets velocities total =112.2 km/sec
- (The 3 planets are Mercury 47.4 km/s + Venus 35 km/s + Earth 29.8 km/s)
- 112.2 km/sec = 24.1 km/s (Mars Velocity) x 4.61 (error 1%)
- But
- 1 hour of Pluto motion be = 4.61 hours of the moon motion
- That tells some complex machine be found behind the transportation of the rate
(2π)
- Specially because
- Mars orbital distance (227.9 mkm) x (2π) = 1433.5 mkm = Saturn orbital distance

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- That, again tells that, there's a geometrical reason for Mercury to move during
(5040 seconds) a distance = 2 Saturn diameter and Mars moves during this same
period (5040 seconds) a distance = Saturn diameter
- The definition of the distance to be = Saturn diameter is a choice based on a
geometrical reason.
- Why?
- Because the period 5040 seconds is engraved period inside Mercury day Period,
and Mercury day needs (5040 seconds) to be (176 solar days)
- The geometrical system created this period (5040 s) inside Mercury Day Period
because of its massive effect on the planets motions
- That tells Saturn diameter has a massive effect on planets motions, I don't catch yet
its effect, I can only add some data supports this idea
- More Data
- Pluto (4.7 km/s) moves during (51118 seconds) a distance = 2 x 120536 km
(Saturn diameter = 120536 km)
- (Uranus diameter = 51118 km)
- And
- Pluto (4.7 km/s) moves during (2 x 120536 seconds) a distance = 1.13184 mkm
- (1.13184 mkm = Jupiter Motion Distance During A Solar Day)
- Jupiter moves during 4495.1 days a distance =5127 mkm (Jupiter Pluto Distance)
- (4495.1 mkm = Neptune Orbital Distance = π x Saturn Orbital Distance)
- Now let's discuss the moon and Pluto motions data

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II- Discussion (Continued)
- In following we analyze the moon and Pluto motion data
- Notice
- No pure coincidences of number can be claimed here because Pluto data be in
proportionality with the Earth and its Moon. Means each planet motion be
interacted based on its position
- The question we try to solve is (How This Data Be Created?)
Equation no. (C)
1 hour of Earth motion = 29.53 hours of the moon motion.
- Because
- The Earth Day Period = 24 hours
- The moon Day Period = 708.7 hours
- And
- Pluto Day Period = 24 hours
- The moon Day Period = 708.7 hours
- Because of that
- 1 hour of Pluto motion = 4.61 hours of the moon motion.
- We can see that, the machine works with consistency, for example
o 1 hour of Earth motion = 2π hours of Pluto motion
o 1 hour of Pluto motion = 4.61 hours of the moon motion
o And
o 1 hour of Earth motion = 2π x 4.61 = 29.53 hours of the moon motion
o The rates of time are created based on each planet motion data and be in full
harmony as we see. That tells we deal with a geometrical mechanism works
consistency…
Let's discuss more data in following …

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Discussion (continued)
Equation no. (1)
(406000 km /88000 km) = (708.7 h/ 153.3 h) = 4.61
- Where
- 406000 km = Pluto motion distance per a solar day
- 88000 km = The moon displacement per a solar day
- 708.7 hours = The Moon Day Period
- 153.3 hours = Pluto Day Period
- 1 hour of Pluto motion = 4.61 hours of the moon motion.
- Again the rates of time causes (2 Planets All Data) to be in proportionality with
one another. in following equations we see that Pluto and the moon motions data
be in full proportionality which is very interesting data.
Equation no. (2)
Tan (12.2) x 708.7 hours = 153.3 hours
- Where
- The angle 12.2 degrees = 13.177 deg – 0.98562 deg
- 13.177 degrees = The Moon Motion Degrees Per A Solar Day
- 0.98562 degrees = The Earth Motion Degrees Per A Solar Day
- Equation no. (2) shows that the moon and Pluto days periods are created based on
each other geometrically. The fact can't be denied. Pluto day period (153.3 h) is
created as a function in the moon day period (708.7 h).
Equation no. (3)
Tan (13.17) x 655.7 hours = 153.3 hours
- Where
- 13.177 degrees = The Moon Motion Degrees Per A Solar Day
- 655.7 hours = The Moon Rotation Period.
- 153.3 hours = Pluto Day Period and (153.3- ) = Pluto Rotation Period

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- Equation no. (3) shows, Pluto rotation period is created depending on the moon
rotation period based on the angle (13.177 deg).
- The data of the 3 equations are strong and prove the idea clearly, because it's A
Directed Data. Means, this data be created based on geometrical mechanism be
found between Pluto and the moon motions. For that reason, the equations use (all)
data of the 2 planets. That shows the data is directed and can't be created by any
random process. It's data be created based on geometrical reasons and rules.
- The proportionality in data between Earth and its moon on one side and Pluto on
the other side shows that a geometrical mechanism must be found behind them.
Equation no. (4)
2 x 153.3 h = 4.61 x 66.8 But
(708.7 h /10.7 h) = (655.7 h /9.9 h) =66.23 (error 1%).
- 708.7 hours = The moon Day period
- 655.7 hours = The Moon Rotation Period
- 153.3 hours = Pluto Day Period
- 10.7 hours = Saturn Day Period
- 9.9 hours = Jupiter Day Period
- The rate (4.61) we have defined, where (1 hour of Pluto motion =4.6 hours of the
moon motion).
- Equation no.(4) tells that this rate (4.61) is known by Jupiter and Saturn motions.
- That tells, the rate (4.61) is transported among the solar planets and that explains
how this rate be created between the moon motion and Pluto motion.

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Equation no. (5)
413600 km cos (10.96 deg) = 406000 km
- Where
- 406000 km = Pluto Motion Distance During A Solar Day
- Equation no. (5) shows that, the motions interaction between the moon and Pluto is
a deep interaction. And effects on the planet motion basic data. Because
- The moon displacements total during 29.53 days =2598693 km = 2π x 413600 km
- The distance (413600 km) should be the moon apogee orbital radius if the moon
apogee orbital circumference = the moon displacements total during 29.53 days.
- This is the fact which should be performed
- But
- The moon apogee orbital circumference be (2550973 km) less than the moon
displacements total during (29.53 days) with 2%. This fact arises the question
Why? the moon apogee circumference should be 2598693 km (surely). But for
some geometrical miracle this distance became =2550973 km!
- The radius 413600 km be changed into 406000 km and this change be done based
on the equation no. (5). The angle (10.96) caused this change. We have discussed
this angle before deeply because it's the main angle in the moon orbit geometrical
structure (we will review a short notice about it later). The angle (10.96 deg)
causes the radius 413600 km to be 406000 km – why?
Equation no. (6)
(10.96 deg /1.7 deg) = (153.3 h /24 h) (error 1%)
- The angle 10.96 deg be created based on the rate between Pluto Day Period
(153.3h) and Earth Day Period (24 h). this rate be used between the angle (10.96)
which causes to decrease the radius from 413600 km to 406000 km, and the angle
1.7 deg which is the moon daily motion angle in the moon orbital equation (θ1= θ0
+ 1.7 deg). (The moon orbital equation be in my previous paper)

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Notice (1)
- The moon displacements total 2598693 km should be the moon apogee orbital
circumference, by that, the moon apogee orbital radius should be =413600 km
- But
- It's not true, the moon apogee orbital radius =406000 km
- Why? because of the angle (10.96 degrees)
- Let's remember this angle in following:
o The moon orbital perigee radius =363000 km
o The moon orbital apogee radius = 406000 km
o If we draw these 2 radiuses in 2 circles as in the figure
o The tangent DB = 181843 km, also
o The perigee orbital circumference = 2.28 mkm
o (181843 km /2.28 mkm) = 0.08
o 137 degrees x 0.08 = (10.96 degrees)
o As we remember that 137 degrees = 95.1 deg x 1.44 deg where
o 95.1 deg =90 deg + 5.1 deg (the moon orbital inclination)
o 1.44 deg = the moon orbit regression degrees per month.
o We have supposed that the angle 137 degrees is created based on the moon
orbital inclination (degrees) and the moon orbit regression angle monthly.
And this angle (137 deg) is the basic angle in the moon orbital geometrical
structure (hypothesis).
o The calculations of the tangent DB = 181843 km aimed to explain one basic
idea which is, the moon orbit is built geometrically to create the rate (0.08)
by which the moon orbital inclination and regression will create the angle
(10.96 deg).
o Let's explain that more clearly

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o The moon orbit inclination and regression controls the moon orbital motion.
this is a hypothesis. Now, the moon orbital motion creates the moon orbit
based on a geometrical design, the moon orbital motion uses the moon orbit
geometrical design to create the angle (10.96 deg) from the basic one (137
deg). by that the original angle is (137 deg) which is created by the moon
inclination and regression unification, and the born angle is (10.96 deg)
which is the motor of the machine.
o What we need to refer to is that, the moon orbit geometrical design is used
in this process. That's why the distance 413600 be decreased and became
406000 km. By that, the main player is the angle (10.96 deg).
- This explanation answers the question,
- Why Pluto Motion Distance During A Solar Day = The Moon Apogee Orbital
Radius=406000 km?

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Notice
- The previous data still have another reading let's summarize it in following:
o Pluto day period is a very long day period in comparison with the outer
planets days periods, Why?
o We notice also that, Pluto Moves During Its Day Period A Distance =
Earth Motion Distance During Earth Day Period. That means, Pluto Day
Period be extending to perform this requirement.
o i.e.
o Pluto Day Period be extending to be 153.3 h to enable Pluto to move a
distance = Earth motion distance during Earth day period.
o Because of that,
o Pluto day period (and rotation period) be created as functions in the Earth
moon day and rotation periods as we have seen in the data discussion.
o i.e.
o The interaction between Pluto motion on one side with the Earth and its
moon motions on the other side caused the following results:
o (1st
Result) the moon apogee orbital radius be decreased from 413600 km to
be 406000 km
o (2nd
Result) Pluto Day Period be extending to be =153.3 days.
Notice
- Uranus effect is the main force behind the changes for the 2 planets data.
- Uranus effect on Pluto is proved by Planet 8 days Cycle where Uranus uses Pluto
day period in its motion.
- Uranus effect on the moon is proved by the fact, Uranus orbital circumference =
19.2 Earth orbital circumference. The moon moves a cycle called Metonic cycle
and extends for 19 years. Metonic Cycle is caused almost by Uranus effect on the
moon motion.

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The Rate of time 4.61
I- Data
778.6 mkm (Jupiter Orbital Distance) = 4.61 x 170 mkm
550.7mkm (Jupiter Mars Distance) = 4.61 x 119.7 mkm
2094 mkm (Jupiter Uranus Distance) = 4.61 x 2 x 227.9 mkm
2872.5 mkm (Uranus Orbital Distance) = 4.61 x 629 mkm
3033.5 mkm (Uranus Pluto Distance) =4.61 x 654.9 mkm
5127 mkm (Jupiter Pluto Distance) = 4.61 x 2 x 550.7 mkm
5906 mkm (Pluto Orbital Distance) =4.61 x 1284 mkm
1375.6 mkm (Mercury Saturn Distance) =4.61 x 2 x 149.6 mkm
3062 mkm (Saturn Neptune Distance) =4.61 x 671 mkm
4345.5 mkm (Earth Neptune Distance) =4.61 x 940 mkm
4267.2 mkm (Mars Neptune Distance) =4.61 x 929 mkm
Where
170 mkm = Mercury Mars Distance
119.7 mkm = Venus Mars Distance
227.9 mkm = Mars Orbital Distance
629 mkm = Jupiter Earth Distance
654.9 mkm = Jupiter Saturn Distance
550.7 mkm = Jupiter Mars Distance
1284 mkm = Earth Saturn Distance
149.6 mkm = Earth Orbital Distance
671 mkm = Jupiter Venus Distance
940 mkm = Earth Orbital Circumference
929 mkm = Earth Jupiter Distance when the 2 planets be on the sun 2 sides
(Max error 1%)

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II- Discussion
- 1 hour of Pluto motion =4.61 hours of the moon motion
- We have discussed that deeply before
- But
- The previous distances are (22 distances)
- And
- The solar system distances total be (45 distances)
- That means,
- These distances in the pervious data be considered as 50% of all distances in the
solar system. that shows the rate (4.61) between Pluto and the moon motions be so
important and interesting rate which controls around 50% of all distances
- I have no explanation why this is done or how the 2 planets rate of time can effect
so greatly on the solar system distances distribution and planets motions data
- What we need to do is that, to prove the following results:
o The solar system distances are created in a network form and not as
individual or independent distances
o The solar system distances be created based on a map uses the planets
motions rates of time to define and distribute the distances
o The data clearly provides another vision different from Newton Theory of
the sun mass gravity… we should see this data frequently and has a time to
think deeply in the question (how this data be created?)
o It's another vision…The eyes which see one distance (Mars Orbital Distance
for example) and think this distance be created by effect of the sun mass
gravity on Mars Mass! we try to tell them (please look at the other distances
in the same time) and then we will discover that (Mars orbital distance) is a

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part of some great machine be controlled by one geometrical design which
distribute the distances based on its geometrical rules
o It's one system of data and one machine mechanism which causes to create
and distribute the distances and because of that they be created in a network
form
o I try to show that, the solar planets motions data contradict the solar system
description inherited from Newton Theory of the sun mass gravity
o The features which we have concluded aren't so wide but they provide an
extending vision contradicts clearly and strongly Newton theory
o We have to adopt different rates of time for the planets motions which is a
strange feature from Newton theory
o We have to accept the distances using as periods of time and this feature
also is strange one
o And then
o We have to consider the solar system distances as distance be created in a
network form and has one geometrical design.
o The machine has different strange features are unknown by Newton Theory
of the sun mass gravity
o There are many other features we have to discover to provide a complete
description for the solar system motion.
- Notice
- Jupiter Data still need more analysis we should do that but with Mercury Motion
analysis because Mercury provides one more reading for the solar planets motions
data.

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4-Mercury Motion Analysis
4-1 Preface
4-2 The Theory basic Ideas
4-3 The Light Beam (1.16 mkm/s) Proves Discussion
4-4 Jupiter Orbital Circumference Analysis

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4-1 Preface
- Jupiter motion data analysis shows that, Jupiter Motion depends on Mercury and
Mars Cycles Periods because there's one great machine causes the 3 planets to
move in comparison with one another.
- And
- What's This Great Machine?
- The Fact is that,
- Matter is created out of light beam and the born matter doesn't separate from its
light parent but move together in one unified motion by using different rates of
time.
- Means,
- The planets are created out of one light beam which causes their motions
- The planets be similar ships on a sea and the sea is light motion network
- That caused the great difference between Newton Theory and the planets motions
data and facts. While Newton saw the planets are independent rigid bodies move
by the sun mass effect on them, the planets be in fact ships sail over a sea of light
motions which control and define the planets motions range.
- Mercury Data tells this story in details and explained clearly how the planet moves
accompanying with a light beam motion.
- Let's provide the complete theory of Planet motion depending on light motion and
then we should discuss The 3planets motions data (again) from Mercury Motion
Point of View to see that how the light beam creates this data we have discussed
before

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4-2 The Theory Basic Ideas
(I)
- The theory hypothesis
- The solar system be created out of one light beam its velocity =1.16 mkm/sec
-
- The hypothesis proves depends on planets motions data
- Because
- The Planets Matters are created out of energy, And
- The Planets Distances are created out of energy
- This energy is provided by one light beam its velocity (1.16 mkm/sec)
- As a result
- This light beam motion feature be registered in the planets dimensions and
distances…
- That's why I suppose there's a light beam its velocity =1.16 mkm/sec
(II)
- Planet and light motions rate of time is
- 1 Second Of Light Motion = 1 Solar Day Of Planet Motion
(one second of light motion energy causes planet to move for one solar day)
- The planets divide this general rate of time among their motions and by that small
rates of time be used for the planets motions (as we have examples of these small
rates of time)
- The planets motions unify their small rates of time to produce the general one.
- By that, the solar group works used as a great clock, its input is 1 second of light
motion and its output is 1 solar day of a planet motion.
(III)
- Light supposed velocity (1.16mkm/sec) started from Mercury its journey to Jupiter
directly and then Jupiter energy is sent to Pluto directly (1st
trajectory)
- There's one more trajectory started from Mercury also to Pluto directly

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- We analyze all motions to see as possible how they are done
- Saturn data be a parallel player found with the light motion data ….
- In Mercury Motion data analysis we should remember the question
- (why Mercury day period = 2 Mercury orbital periods?)

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4-3 The Light Beam (1.16 mkm/s) Proves Discussion
I - Data
(1)
1.16 mkm/s x 86400 s = 100733 mkm
And
0.3 mkm/s x 86400 s = 25920 mkm
(2)
1.16 mkm/s x 500 s = 580 mkm
1.16 mkm/s x 580 s = 671 mkm (Venus Jupiter Distance)
1.16 mkm/s x 671 s = 778.6 mkm (Jupiter Orbital Distance)
1.16 mkm/s x 629 s = 720.7 mkm (error 1%) (Mercury Jupiter Distance)
1.16 mkm/s x 5127 s = 5906 mkm (error 0.7%) (Pluto Orbital Distance)
(3)
1.16 mkm/s x 4224 seconds = 4900 mkm
(4)
1.16 mkm per second x 2 x 86400 seconds =2 x 100733 mkm = (37100 mkm – 4900
mkm) x 2π = 28255 mkm + 2 x 86400 mkm
(5)
1.16 mkm/s x 5040 seconds = 5848 mkm (Mercury Pluto Distance)
And
5848 mkm (Mercury Pluto Distance) – 4900 mkm = 948 mkm
(6)
1.16 mkm/s x 4900 seconds = 5678.1 mkm (Mars Pluto Distance)
And
1.16 mkm/s x 5687.1 seconds = 6585.4 mkm
(7)
193 seconds x 0.3mkm/sec = 57.9 mkm (Mercury Orbital Distance)
196.5 seconds x 1.16 mkm/sec = 227.9 mkm (Mars Orbital Distance)
(8)
5040 sec = 88 sec x 57.27 (this data answers why Mercury day = double its period)

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II- Discussion
Equation no. (1)
1.16 mkm/s x 86400 s = 100733 mkm
And
0.3 mkm/s x 86400 s = 25920 mkm
- Light known velocity (0.3 mkm/s) travels during a solar day (86400 s) a distance =
25920 mkm.
- Because it's a light motion we see this value (25920 mkm) as a period of time
(25920 years = the Precession Cycle)
- Also
- The distance 25920 mkm be = The Planets Motions Distances Total During A
Period =1461 days (where 1461 days =365 +365 +365 +366)
- Because the period 1461 days is (Earth Cycle) we consider that the distance 25920
mkm be mentioned by planets motions total
- Notice, the distances total added the Earth moon motion distance to the 9 planets
motions distance to create the total per a solar day (17.75 mkm) where the moon
motion daily distance be considered = Earth motion daily distance because they
aren't separated from one another through their motions.
- The light supposed velocity (1.16 mkm/s) travels during a solar day (86400 s) a
distance = 100733 mkm = The 9 Planets Orbital Circumferences Total
- Equation no. (1) tries to prove that, Light Motion Uses The Solar Day Period As
Its Basic Period Of Motion.
- Light known velocity and light supposed velocity both use the solar day as the
basic period of time. Because of that, both light beams passes essential distances in
the solar system geometry.
- The next discussions will prove that these distances (25920 mkm and 100733
mkm) are essential distances in the solar system geometry.

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- Notice
- The rule tells
- (Light Motion For 1 Second = Planet Motion For 1 Solar Day)
- This rule which is a supposed one and we should prove it through the paper
discussions…
- This rule tells that,
- The light motion depends on the solar day as a period of time as similar to its
dependency on the second as a period of time.
- That means,
- These 2 periods of time (the second and the solar day) are the 2 basic columns for
light and planet motions accompaniment.
- And by that, light motion doesn't use the solar day as similar to any other planet
day period. On the contrary, the solar day is the basic period of time for light
motion (For both velocities, the known and supposed).

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Equation no. (2)
1.16 mkm/s x 500 s = 580 mkm
1.16 mkm/s x 580 s = 671 mkm (Venus Jupiter Distance)
1.16 mkm/s x 671 s = 778.6 mkm (Jupiter Orbital Distance)
1.16 mkm/s x 629 s = 720.7 mkm (error 1%) (Mercury Jupiter Distance)
1.16 mkm/s x 5127 s = 5906 mkm (error 0.7%) (Pluto Orbital Distance)
- The data show specific features of motions which are:
- The light supposed velocity (1.16 mkm/s) uses the distances values as a periods of
time by the rate (1 mkm = 1 second).
- Based on that, the distances be created depends on one another and no distance be
created independent from the other distances. That means, the distances be created
in a network form of distances and not as independent distances from one another.
- The data shows how the solar system distances be created in a network form
- In details
- Light supposed velocity (1.16 mkm/s) uses the period (500 sec) to pass a distance
580 mkm, and
- Light supposed velocity (1.16 mkm/s) uses the distance (580 mkm) as a period of
time (580 sec) to pass a distance 671 mkm (= Venus Jupiter Distance), and
time (671 sec) to pass a distance 778.6 mkm (=Jupiter Orbital Distance), and
time (629 sec) to pass a distance 720.7 mkm (=Jupiter Mercury Distance), …etc
- We have discussed this data before but now we have another reading for this same
data
- Notice
- (The Distances Network Theory Be Discussed In Point No.5)

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The Motion 1st
Trajectory
- The Trajectory Summary
- Light supposed velocity (1.16 mkm/s) travels starting from Mercury to Jupiter,
creating Jupiter orbital circumference
- And, then
- Light supposed velocity (1.16 mkm/s) travels from Jupiter to Pluto (Directly) and
doesn't touch any other planet in the way.
- The motion trajectory is built on 2 basic equations and many other additional data.
because
- Mercury Motion uses light supposed velocity (1.16 mkm/s) because of that,
different data of Mercury motion be created based on this light supposed velocity
(1.16 mkm/s) energy
- Shortly
- The motion 1st
trajectory is defined based on Equation no. (3) and (4) as basic
equations. And through discussion many other data be added
Notice
Equation no. (4) is the solar system geometry main equation and it's the paper main
one we discuss it along the paper,

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Equation no. (3)
1.16 mkm/s x 4224 seconds = 4900 mkm
- Where
- 4900 mkm = Jupiter Orbital Circumference
- Equation no. (3) tells, the light supposed velocity (1.16 mkm/s) travels during
4224 seconds a distance = 4900 mkm = Jupiter Orbital Circumference.
- Now, let's suppose 1 second of light motion = 1 hour of Mercury Motion
- based on that, 4224 seconds be equivalent to 4224 hours (but 4222.6 hours =
Mercury Day Period).
- Equation no. (3) provides 3 braches of data! let's summarize them in following:
- (1st
Branch) Light supposed velocity (1.16 mkm/s) moves in (4224 s) a distance
=4900 mkm but Mercury moves during (4222.6 h) a distance = 720.7 mkm
(=Mercury Jupiter Distance) and we suppose that 1 second of light motion = 1
hour of Mercury Motion. Because of that we need to find some connection
between 4900 mkm and 720.7 mkm to create a comparison between light motion
and planet motion.
- The comparison is complex because, I suppose the rate (2π) distinguish between
light and planet motions. By that, if light moves 4900 mkm, a planet motion
should be 778.6 mkm but Mercury motion distance only be 720.7 mkm, where,
- 778.6 mkm (Jupiter orbital distance) =1.0725 x 720.7 mkm (Mercury Jupiter
Distance)
- The rate (1.0725) creates a negative effect on the rule of the value (2π). although
the rate (1.0725) be used between 40% of all distances in the solar system. But
because it be found here creates more complexity for the discussion and causes
some negative effect for the comparison between light and planet motions. because
always in other data we have found that the value (2π) distinguish clearly between
light and planet motions but in our equation the rate (1.0725) causes some
difficulty for this comparison vision.

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- Notice
- The distance 720.7 mkm (Mercury Jupiter Distance) be discussed in point no. (9)
of this paper.
- (2nd
Branch) Mercury Day Period Creation.
- We have supposed that, 1 second of light motion be equivalent to 1 hour of
Mercury Motion. that means the period (4224 s ) be equivalent to (4224 h) and
Mercury Day Period = (4222.6 hours).
- This supposition suggests that, Light supposed velocity (1.16 mkm/) motion causes
to create Mercury Day Period be (= 4222.6 hours).
- The data is accurate and clear
- NOW
- The data tells that…
- Mercury is the source of the light supposed velocity (1.16 mkm/s)
- The light supposed velocity (1.16 mkm/s) started from Mercury and sent to Jupiter,
creating the distance (4900 mkm = Jupiter Orbital Circumference).
- This motion depends on Mercury Day Period.
- As a result, Mercury Day Period be defined by light supposed velocity (1.16
mkm/s) motion effect on Mercury Motion.
- i.e.
- Mercury Day Period = 4222.6 hours And
- 4900 mkm= 1.16 mkm/s x 4224 seconds
- We suppose that, 1 hour of Mercury Motion = 1 second of light motion… means
- The difference (4224 -4222.6 = 1.4) is created by the light supposed velocity (1.16
mkm/s) motion effect. that means,
- The light motion effected on Mercury Motion and caused Mercury day period to
be 4222.6 hours and less than 4224 hours with 1.4 hour = 5040 seconds
- Why? Because

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- Light supposed velocity (1.16 mkm/s) travels during (5040 s) a distance =5848
mkm = Mercury Pluto Distance
- The light supposed velocity (1.16 mkm/s) created a connection between Mercury
and Pluto motions by creating the period 5040 seconds as a difference between
Mercury Day period (4222.6 h) and 176 solar days (=4224 hours).
- We can't discover the geometrical machine behind this data. But the data clearly
shows that, the light supposed velocity (1.16 mkm/s) travels during 5040 seconds a
distance = 5848 mkm.
- We have 3 information we got based on this analysis which are:
- (1st
) Mercury Is The Origin Point Of The Light Supposed Velocity (1.16 mkm/s)
- (2nd
) light supposed velocity (1.16 mkm/s) motion created Jupiter orbital
circumference 4900 mkm.
- (3rd
) Mercury Day Period be (4222.6 h) and less than (4224 h) with (5040 s)
because of light supposed velocity (1.16 mkm/s) effect on Mercury motion, to
create a connection between Mercury and Pluto motions.
- Notice
- The accompaniment of The Light supposed velocity and Mercury Motions caused
Mercury day Period to be (4222.6 hours) to create a connection between Mercury
and Pluto based on the distance (5848 mkm = Mercury Pluto Distance)
- Is There any Proof for this conclusion?
- Yes, There's a proof in Mercury Motion data,
- Let's analyze Mercury Motion Data in following:

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Mercury Motion Data
- 5040 seconds = 84 minutes
- Mercury (4.095 mkm/ daily) moves during 84 solar days a distance = 344 mkm
- And
- Mercury (4.095 mkm/ daily) moves during 346.6 solar days a distance = 1419.5 mkm
- And
- Mercury (4.095 mkm/ daily) moves during 1419.5 solar days a distance = 5813 mkm
- But
- Mercury (4.095 mkm/ daily) moves during 1433.5 solar days a distance = 5870 mkm
Pluto Orbital Distance
- NASA Planetary Fact sheet had defined Pluto orbital distance as 5870 mkm
- And
- From 5 years NASA had modified this distance to be 5906 mkm
- In the theoretical calculations both distances are required!
- Let's explain that in following
o 5906 mkm – 57.9 mkm (Mercury orbital distance) = 5848 mkm
o This distance 5848 mkm accurately = 1.16 mkm/s x 5040 seconds
But
o Mercury motion during 1419.5 days passes a distance =5813 mkm = 5870
mkm – 57.9 mkm - And
o Mercury motion during 1433.5 days passes a distance =5870 mkm (Pluto
orbital distance)
Shortly
o Light motion depends on the distance (5906 mkm as Pluto orbital distance)
but Mercury motion depends on the distance (5870 mkm as Pluto orbital
distance).
o That tells both distances are found geometrically but also tells some
difference be found between light and planet motions.

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Mercury Motion Data Analysis
- The previous data shows that,
- Mercury uses light motion strategy. By that, Mercury moves a distance and then
uses this distance as a period of time to move another distance. By that the
distances be created in a network form.
- We don't know how a planet moves with low velocity can use distances values as
periods of time. The data needs more analysis to discover the rule on which this
using is done.
- Mercury motion aims to pass a distance = 5848 mkm= Mercury Pluto Distance,
this distance is the distinguish one in the 1st
trajectory of motion and also the 2nd
trajectory of motion. Many data be created in proportionality with this distance
which proves some geometrical machine be found behind these motions.
- Mercury moves the distance (5848 mkm) following light motion
- Mercury uses the rate (1 mkm= 1 solar day)
- Notice
- Jupiter Orbital Circumference (4900 mkm) is a very rich distance of discussions
and arguments. Because of that,
- Jupiter orbital circumference analysis be discussed in a separated point no. (4-4) .
- The idea is that, the light supposed velocity (1.16 mkm/s) creates a connection
between Mercury and Pluto by using Jupiter orbital circumference (4900). That
means, Jupiter orbital circumference be used as a central point in the light
trajectory of motion from Mercury to Pluto, because of that, the light supposed
velocity (1.16 mkm/s) created Jupiter orbital circumference (4900 mkm) by
different geometrical features which be required for this task. As a result we find
Jupiter orbital circumference is so complex distance and filled of questions.

Jupiter and mercury motions analysis (revised) (2)

Jupiter and mercury motions analysis (revised) (2)

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