The Sun Gravity Concept is Incorrect (Newton was wrong)

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
The Sun Gravity Concept is Incorrect (Newton was wrong)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –2nd
July 2021
Abstract
Paper Hypothesis
- The Solar Planets Don't Move By The Sun Masses Gravity Force.
The Hypothesis Explanation
- Newton was wrong, There's no Gravity Of The Sun be used in the solar planets
motions. the machine works completely different from Newton Description.
- The Inner Planets depend on Electric Field in Their Motions.
- The Outer Planets depend On The Motion Transportation from The Inner planets.
- Specifically, The Inner Planets transport their motions to Jupiter, and Jupiter
transports this motion to the other outer planets.
- The Motion Transportation from Jupiter to the outer planets depends on Planet 8
Days Cycle.
- The Motion be Transported from Jupiter To Uranus depends on Planet 8 Days
Cycle Also (By Effect of Pluto Motion).
- Uranus Transport The Motion to Pluto
- Uranus effect on Pluto motion creates a unification for the solar group motion.
- The Solar Planets Motions be unified in One General Unified Motion.
- The solar planets motions be similar to the Train Carriages Motion. Because The
Planets motions be complementary with one another and create One General
Unified Motion.

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- The Planets One General Unified Motion obligates each planet motion to be
complementary with other planets motions. and by that the planet motion be an
obligatory motion.
- The planet creates its data to be in consistency with its motion. because the planet
can't change its motion.
- Because the planets motions be complementary with one another, and the planet
data be in consistency with its motion. As A Result, each Planet Data Be Created
Complementary with Other Planets Data. by that, the solar planets all data be
created based on One Geometrical Design.
- Newton was wrong basically because of three reasons, (1) The outer planets
motions features be different from the inner planets motions features, which proves
that the 2 types of motions can't be created from the same one force. (2) Newton
Description tells, the line between the sun and the planet is the main one, where
the planets data analysis shows that planet basic connections are found with other
planets and not with the sun, (3) the main disprove point of Newton description is
the sun mass gravity force, because the mass gravity force provides a description
depends on a Massive Mass creates a permanent obligatory motion. But the Solar
planets motions (special the outer planets) show that, their motions depend on a
geometrical tool. That means, the planets motions create a geometrical tool which
be used to cause the motion from one planet to another. that means, the machine
motor isn't the massive mass which creates a permanent obligatory motion, but the
motor is a geometrical tool we see its details in Planets Data. (the geometrical tool
is expression means a tool works by geometrical rule, as the lever or waterwheel)
- The main point of Newton Description disprove is that, this geometrical tool
details we see in planets motions data. and if the planet motion can't create this
geometrical tool by its motion, the effect can't be produced, so if this geometrical
tool will cause to transport the motion, the process will not be done, because the
geometrical tool is not produced. I want to say, there's No a permanent force

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causes the planets motion. This Is Newton Main Mistake. No permanent source
for the motion. the motion source is a tool be created by planet motion day after
day and after this geometrical tool be created the planet motion will be developed
into another phase.
- By that, Newton description (at end) can be refuted, because The Used Force Is
Different In Its Basic Description From The Real Used Force.
Please scan the figure (ORCID)

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Contents
Subject Page No.
1- Introduction 5
2- Methodology 7
3- A Complete Description For The Solar Planets Motions 9
3-1 Preface 9
3-2 The Inner Planets Motions 12
3-3 The Outer Planets Motions 15
4- The Description Proves Discussion 17
4-1 Planet Orbital Distance Equation 17
4-2 Jupiter motion depends on the inner planets motions 22
4-3 Jupiter transports the motion to the outer planets 36
4-4 Uranus Motion Effect on Pluto Motion 45
4-5 Jupiter Pluto Distance Analysis 48
5- The Inner And Outer Planets Motions Be Distinguished 50
5-1 Preface 50
5-2 The Inner And Outer Planets Motions Be Distinguished 51
6- The Motion Transportation Definition 53
7 -The Planets Motions Use Different Rates of time 56
7-1 Preface 56
7-2 Earth And Pluto Rate Of Time 58
7-3 Mercury Motion Rate Of Time 68
7-4 Saturn Motion Rate Of Time 72
8- The Sun Creation Details. 75
8-1 Preface 75
8-2 The Solar System Unified Motion 77
8-3 The Sun Rate Of Time 84
Appendix No.1 The Solar System Equal Distances List 87
Appendix No.2 (Planet Gravity Equation) 89
References and Biography 90

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1-Introduction
4900 mkm = 360 mkm + 680 mkm + 940 mkm + 1433 mkm +1433 mkm (1%)
- Where
- 4900 mkm = Jupiter Orbital Circumference
- 360 mkm = Mercury Orbital Circumference
- 680 mkm = Venus Orbital Circumference
- 940 mkm = Earth Orbital Circumference
- 1433 mkm = Mars Orbital Circumference
- If we accept that, The Earth moon orbital circumference around the sun = 1433
mkm = Mars orbital circumference (later we should discuss why?)
- If we accept that, So
Jupiter Orbital Circumference be = The Inner Planets Orbital Circumferences
Total, Why?
(II)
- Mercury moves during its day period a distance = 720.7 mkm = Mercury Jupiter
distance
- Venus orbital circumference =680 mkm = Venus Jupiter distance 671 mkm (1.2%)
- Earth orbital circumference =940 mkm =Earth Jupiter distance 928 mkm (1.2%)
(Earth and Jupiter should be on 2 different sides of the sun to create 928 mkm)
- So, let's ask
- Do The 3 Inner Planets Define Their Orbital Circumferences To Be Equal Or
Rated With Their Distances To Jupiter?
(III)
- Based on this data, let's provide the following suggestions: (1st
) The inner planets
define their orbital circumferences to be rated with their distances to Jupiter and
(2nd
) Jupiter orbital circumference = the inner planets orbital circumferences total
- By this data I try to prove that, Jupiter motion depends on the inner planets
motions. can this data prove this idea?

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- In fact there's one more strong data can support this idea greatly but we have to
discuss it in the paper discussion (because of its wide range of data).
- The paper claims that. Jupiter is the point to which the inner planets transport their
motions and from which the outer planets receive the transported motion.
- "The Motion transportation" we should define in the paper discussion. Because
the planets are not gears, so we need to define as clear as possible how the motion
be transported among them.
- The paper tries to prove one basic point, which is….
- Newton Description supposes a different motor for the machine from the real one.
an that makes the physics description be completely strange from the solar planets
real motions. and for that reason, the planets motions data be always strange data
and provides puzzles for our understanding. The reason is clear, because the motor
is a different one. imagine you drive a trailer but the used motor is a motorcycle.
While you try to drive it, you feel continuously that, something wrong is found and
this wrong can't be repaired or be hidden, it's a mistake in the main point and by
that nothing can be hidden.
- The solar system motion force is different in its features and geometrical effects
from the sun mass gravity force, and different from the mass gravity force
generally. By that, the gab between Newton description of the planet motion and
the planets motion real data be greater each time we try to understand.
- The motor geometrical features we discuss deeply with the definition of (Motion
Transportation)
- Paper Contents
- Point no. (2) Paper Methodology
- Point no. (3) A Complete Description For The Solar Planets Motions
- Point no. (4) The Description Proves Discussion (6 Proves)
- Point no. (5) The Motion Transportation Definition and the Motor Description

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2-Methodology
(I)
- I use the solar planets data analysis to discover the planets origin and motions.
- This method is so useful because it creates a comparison between the physics
theories and the planets data to show if the planets data follow the theories really.
- For example, we notice that, Jupiter is the 5th
planet in order to the sun, while the
gravitation equation tells (More Mass Needs Shorter Distance). Jupiter position
refers to a contradiction with the gravitation equation.
- That's the useful result of Planets Data Analysis Method using.
(II)
- I suppose the solar group is a machine of gears and each planet is a gear in it. or it's
one building and each planet is a part of it. this hypothesis leads us to conclude
that, the solar planets motions must create one unified motion. based on that the
solar planets motions can be similar to the train carriages move tougher one
unified motion we call it (Train Carriages Motion)
(III)
- Because the solar planets are parts in the same one building, their data be created
complementary with each and by that their motions be also complementary
creating together one unified motion.
- The best example to explain the (complementary data meaning) is the double
production experiment. Where an electron be created with a positron from gamma
ray, that shows the 2 particles charges are created depending on each other because
of the charge reservation law. But the 2 particles move depend on their charges,
means, the 2 particles motions are still controlled by (Gamma ray features) and
they move complementary motions.
(IV)
- Based on this hypothesis, the solar planets data should be created complementary
with each other. means, There's One Equation Controls All Solar Planets Data

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- Let's discuss an example for better explanation.
- The Diameter =12430
- There's no a planet in the solar group its diameter =12430km, this number I have
invented it. let's test it to know if it has any effect on the solar system motion.
o The (supposed) diameter 12430 km in the one middle value between Venus
diameter (12104 km) and Earth diameter (12756 km).
o (Earth diameter / moon diameter) = (Jupiter diameter) / (12430 x π)
o Mars (24.1 km/s) moves during (12430 seconds) a distance = 300000 km =
light (0.3 mkm/s) motion distance for 1 second.
o Saturn (13.1 km/s) moves during (12430 seconds) a distance = 120536 km
= Saturn Diameter
- We compare between 2 visions.
- The classical vision tells that, the solar planets are rigid separated bodies revolve
around the sun independent in their creation and motion data from one another.
- We provide a new vision…
- The solar system is created based on One Geometrical Design, the planets are
parts in one building and their data (must) be complementary one another, Because
they are created based on geometrical rules. As in a triangle we know 2 angles (60
deg and 80 deg) what's the third one?
- The diameter 12430 km proves this vision. It behaves perfectly as similar as any
planet (real) diameter. let's remember
o Jupiter (13.1 km/s) moves during 10921 sec a distance = 142984 km (=
Jupiter diameter) where (10921 km = the Earth moon circumference)
o Uranus (6.8 km/s) moves during 7510 sec a distance = 51118 km (=Uranus
diameter) where (7510 km = Pluto circumference)
- Based on that, the (supposed) diameter 12430 km is designed based on the solar
system geometrical design but be not created.

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3- A Complete Description For The Solar Planets Motions
3-1 Preface
3-2 The Inner Planets Motions
3-3 The Outer Planets Motions
3-1 Preface
- The solar planets motions description should be considered as a hypothesis.
- The hypothesis proves should be discussed in the next point (Point no. 4 of this
paper)
- I want to say, the description provides a new expression (The motion
Transportation) has no definition and new theories aren't proved. But, the
description isn't interrupted to explain these points, on the contrary, the description
completes its idea.
- Shortly
- This point no. (3) is dedicated for the complete description idea without proves
- The point no. (4) is dedicated for The Description Proves Discussion
- The point no. (5) is dedicated to prove the distinguish between the inner and outer
planets motions. (Point no. 5 provides more proves for the description)
- The point no. (6) is dedicated to define the expression (Motion Transportation)
and to describe the machine real motor features
Notice
- The idea can be clear by reading the paper all points. Because each point creates a
connection with the next one. I mean, the proves are seen clearly through the paper
points integration. For example
- I suppose Jupiter motion depends on the inner planets motions and some data of
Jupiter motion proves that, but, it's not all data. Because when we study the next
points we will discover that Jupiter provides energy for the outer planets. That

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creates more proves. Because Jupiter data shows that its motion depends on the
inner planet motions and also Jupiter data shows Jupiter provides energy for
Uranus and Pluto. the first idea (Jupiter depends on the inner planets) is concluded
from Jupiter and the inner planets data. but the last idea (Jupiter provides energy
for the outer planets) is concluded from Jupiter data with the outer planets. When
we put these all data beside each other, the conclusion must be that, (Jupiter
transport the motion from the inner planets to the outer planets). Whatsoever
the strange idea in this expression we have to analyze it as deep as possible
because 2 different sources of data tell this same information and we have to
understand what the data tells us.
- I want to say,
- The paper provides many proves for its description. but we need to read the
complete paper material because the picture will be clear by this reading. Let's
provide one more example
- Earth moves during its day period a distance = Pluto motion distance during
its day period.
- This data have no clear explanation to answer (why?)
- I claim,
- The equal distances create some geometrical effect on the planet motion. someone
thinks that, this data be found by pure coincidence and no geometrical reason or
effect causes this distances equality….
- I insert a list for the equal distances in the solar system in appendix no. (1) of this
paper. Around (50%) of all distances are equal. By that, we can't accept the pure
coincidence claim because 50% of all distances be created equal one another. and
by that we have to discover the geometrical reason and effect of this distances
equality.
- Earth and Pluto data shows that, something real must be found behind

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Earth and Pluto Data
(I)
- (Earth velocity / Pluto velocity) = (Pluto Day period/ Earth day period) = 6.37 (0.8%)
- Pluto orbital distance 5906 mkm = Earth orbital circumference 940 mkm x 2π
- Pluto orbital period 90560 days = Earth Cycle (1461 days) x 2π3
Also
- (Pluto motion distance daily406000 km/ the moon displacement daily88000 km)=4.61
- (The Moon Day Period 708.7 h / Pluto Day Period 153.3 h) = 4.61
- Tan (12.2) x 708.7 h (The Moon Day Period) = 153.3 hours (Pluto Day Period)
- Tan (13.17) x 655.7 h (The Moon rotation Period) = 153.3 hours (Pluto Day Period)
- (Where 13.17 deg = the moon daily motion degrees, and 12.2 deg =13.17 deg –
0.9856 deg Earth motion daily degrees)
And
- We know that, Earth moves during its day period a distance = Pluto motion
distance during its day period = the moon displacements total during its day period
(error 1%).
- I try to see that, the paper material can provide a proof for the claim, but not
always be possible to put all data together. For that the reading of all the paper
points will give better vision about the provided proof.

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3-2 The Inner Planets Motions
I- Data
(1)
Earth Mass = The Masses total of (Mercury + Venus + The Moon + Mars)
(2)
Earth Circumference = The 5 inner planets diameters total
(Means the diameters total of (Mercury + Venus + The Moon + Earth + Mars))
(3)
2 x Earth Circumferences = 2 Mars Circumferences + Venus Circumference
(4)
Earth Circumference = The moon freedom space of motion
(5)
Jupiter Orbital Circumference = The Inner Planets Orbital Circumferences Total
II- Discussion
- The double production experiment tells us
- From Gamma ray one electron and one positron be created, 2 particles equal in
mass and opposite in charge.
- Equation no. (1) tells, Earth Mass = The 4 Inner Planets Masses Total (error 1%)
- Can we imagine that, a great gamma ray be used to create the inner planets.
- Earth is (The Great Electron) (that means, Earth atom has a positive nucleus and
negative charges move around)
- The 4 Other Inner Planets Consist Together (The Great Positron) (means, the
inner planets " Mercury – Venus – Mars", Their atoms have negative nucleus and
positive charges move around)
- If these hypotheses be working, the inner plants can create One Electric Field to
cause their motions around the sun.
- The error (1%) refers to a part of mass be consumed to create the required energy
for these planets motions through their orbits.

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- By that the error (1%) is found for a physical necessity and not as an error in
measurements.
- If we accept these hypotheses, that will explain an important data which is
Equation no. (5)
Jupiter Orbital Circumference= The Inner Planets Orbital Circumferences Total
This data we have seen in the paper introduction, we should discuss it later in depth
but it tells shortly, Jupiter motion depends on the inner planets motions while the
inner planets motions depend on their own electric field. By that, we have a direction
of data.
Equation no. (2)
Earth Circumference = The 5 inner planets diameters total
(Means the diameters total of (Mercury + Venus + The Moon + Earth + Mars))
Equation no. (3)
2 x Earth Circumferences = 2 Mars Circumferences + Venus Circumference
- For what we search? For Electric Charge
- If we can prove that, some electric charge be found in the inner planets. That can
support this idea greatly
- Why these 2 equations refer to charges in the inner planets data?
- Because of Gauss Law!
- Gauss law tells that, The Charges Be On The Outer Surface, that means, the
outer surface be created geometrically by an effect of electric charges. Because
more wide outer surface will receive more charges. Because of that, the outer
surface be effected geometrically by the electric charges
- I want to say
- If some planet be charged its outer surface formation and dimension should be
effected geometrically because of the electric charge.

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- Because of that, the previous 2 equations can support this idea because the planets
circumference and diameter be considered as outer surfaces and the proportionality
of the inner planets refer to some effect of the electric field on their creation.
Equation no. (4)
Earth Circumference = The moon freedom space of motion
- The moon orbital period radius =363000 km
- The moon orbital apogee radius =406000 km
- The difference 43000 km
- But the space without the moon diameter =43000 km- 3475 km = 39500km= Earth
Circumference (error 1.3%)
- This data is used for the same argument, A geometrical effect be found on the
surface distances which can be used as a reference for an electric field effects on
the matter dimensions
- Notice
- We know the distance can't be charged unless under specific conditions, but I try
to show geometrical effects are found. It's not necessary for this effect to be
created directly, but it can be found through interactions.
- Notice
- 43000 km (the distance from perigee to apogee) x 3475 km (the moon diameter)
=149.6 mkm (Earth Orbital Distance). I try to show that, geometrical features are
found behind the dimensions and distances definition in the inner planets. And
these geometrical features supports the electric field claim.
- Notice
- The electric field is the best method to make the solar system motion as A Chess
Board Motions. And by that we gain the good result which is (any planet motion
effects on all other planets motions regardless the distance) which is a fact proved
frequently by the planets data.

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3-3 The Outer Planets Motions
- The outer planets motions depend on the motion transportation from Jupiter
- The motion transportation causes basic changes in the motion features, that means,
the outer planets motions be different in the geometrical features from the inner
planets motions.
- This difference also disproves Newton description. Because Newton description
supposed all planets motions be similar because they all depend on the sun mass
gravity force. but the solar planets real motion description show that there are 2
different types of motions which disproves Newton description.
- The outer planets motions have 2 basic different features from the inner planets
motions which are:
- (1st
Feature) The Outer Planet Motion Depends On (Planet 8 Days Cycle)
- (2nd
Feature) The Outer Planet Motion Distance During Its Day Period = Its
Circumference.
- We should discuss these features as deep as possible
- But
- The outer planets motions can't be different greatly from the inner planets motions
because
- (1st
Reason) The motion is transported from the inner planets to the outer planets
and by that the motion is the same one transported from a point to another.
- (2nd
Reason) The solar planets motions create one general unified motion. and
because of that, the planets motions can't have great differences in their features.
- We should prove the distinguished features between the inner and outer planets
motions in Point no. (5) of this paper.

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Notice
Please remember
- The Solar Planets Motions Create One Unified General Motion
- Because of that the planets motions be similar to Train Carriages Motion
- Also the planets motions be similar to Chess Pieces Motions
- This idea discovers One Law controls the solar system motion and data.
- The planets unified general motion forces each planet motion to be complementary
with other planets motions to perform The Unified General Motion. as a result,
The Planet motion be An Obligatory Motion.
- Based on that, The Solar Planet Can't Change Its Motion.
- The Solar Planet creates its data to be in consistency with its motion.
- Because, the planet can't change its motion, but can change its data to be in
consistency with its motion.
- Because the planet motion be complementary with other planets motions.
- The planet data be created complementary with other planets data
- Based On This Vision
- The solar planets data be created based on One Geometrical Design.
- And
- The Planets Creation And Motions Data Be Controlled By One Equation Only
- This idea we have discussed and proved in the previous paper
Please read my paper
The Solar Planets Motions Description (Revised)
https://www.researchgate.net/publication/352832717_The_Solar_Planets_Motions_Description_Revised
https://www.academia.edu/49464125/The_Solar_Planets_Motions_Description_Revised_
https://www.slideshare.net/Gergesfrancis/the-solar-planets-motions-description-revised
https://app.box.com/s/47fwd0gshir636xt0i3wpso8lvvl8vnv/file/827876365293

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4- The Description Proves Discussion
4-1 Planet Orbital Distance Equation
4-2 Jupiter motion depends on the inner planets motions
4-3 Jupiter transports the motion to the outer planets
4-4 Uranus Motion Effect on Pluto Motion
4-5 The inner and outer planets motions be distinguished
4-1 Planet Orbital Distance Equation
Gerges Equation For Planet Orbital Distance
d2
= 4do (d – do)
Where
d= A Planet Orbital Distance
do= The Previous Planet Orbital Distance
Earth depends on Mercury
Mars depends on Venus
Pluto depends on Uranus
Discussion
- Why Does A Planet Orbital Distance Depend On Its Previous Neighbor?
- That's one result of the solar planets motions real force. no planet depends on the
sun in its orbital distance definition. Each planet depends on its neighbor.
- We can see Newton description mistake clearly, the lines among the planets create
these planets data where the lines from these planets to the sun have no effect on
the planets data. The Solar Planets real motion is done from a point to another
point in the solar system creates an environment similar to a textile. As a woman
weaves a piece of cloth. By a needle moves from a point to another and then the
cloth will be created. Newton vision concentrated on the sun as the source of force
and by that the whole textile be out of the description.
- Also,

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- We see 3 planets violate the equation and depend on a planet (not a direct
neighbor)! (Why?)
- The data is so important, because it shows that planets motions effect on other
planets motions. that means, if the sun gravity effects on the planets motions and
orbital distances this effect should be seen in the planets data.
- And because the sun gravity has no registered data in the planets data we conclude
that the sun gravity has no effect on the planet motion.
- Someone should ask why 3 planets don't follow the rule?
- For example
- Pluto depends on Uranus and not on Neptune why?
- I can't answer here, we should keep in mind this question, and see how Uranus
depends on Pluto day period in (Plant 8 days cycle). Simply, Uranus uses Pluto
data always and frequently. There's a deep reason for this relationship, I can't
explain it in a short sentence. The fact is that, Uranus caused Pluto day period to be
so long (153.3 h) and uses Pluto day period in Uranus basic motion.
- No short explanation can answer the question. Pluto in fact depends on Uranus on
many other features of motion and this equation shows one side only
- We still have the positive result from the equation, because it tells the lines among
planets are so important than the lines between the planets and the sun. because
based on these lines, the planets data be created. Shortly, the lines among the
planets create the planets data and by that shows the effects from one planet on
another and show also NO Effect of The sun on the planet motion.
- Shortly
- If the effects aren't seen on the data, so the other planets effects shouldn't be seen
also which is wrong because the planets effects are seen in the effected planets
data. But no data shows the sun effect, means, no gravity is provided from the sun

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The Equation Application
Gerges Equation For Planet Orbital Distance
d2
= 4do (d – do)
d= A Planet Orbital Distance
do= The Previous Planet Orbital Distance
- (227.9 mkm)2
= 4 (108.2 mkm) (119.7 mkm)
- Where
- 227.9 mkm = Mars Orbital Distance
- 108.2 mkm = Venus Orbital Distance
- 119.7 mkm = Venus Mars Distance
- (108.2 mkm)2
= 4 (57.9 mkm) (50.3 mkm)
- Where
- 57.9 mkm = Mercury Orbital Distance
- 50.3 mkm = Mercury Venus Distance
- (149.6 mkm)2
= 4 (57.9 mkm) (91.7 mkm) (error 2.5%)
- Where
- 149.6 mkm = Earth Orbital Distance
- 91.7 mkm = Mercury Earth Distance
- (Earth depends on Mercury in place of its direct neighbor Venus)
- (227.9 mkm)2
= 4 (108.2 mkm) (119.7 mkm)
- Where
- 119.7 mkm = Venus Mars Distance
- (Mars depends on Venus in place of its direct neighbor The Earth )

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- (415 mkm)2
= 4 (227.9 mkm) (187.1 mkm)
- Where
- 415 mkm = Ceres Orbital Distance
- 187.1 mkm = Mars Ceres Distance
- (778.6 mkm)2
= 4 (415 mkm) (363.6 mkm)
- Where
- 778.6 mkm = Jupiter Orbital Distance
- 415 mkm = Ceres Orbital Distance
- 363.6 mkm = Ceres Jupiter Distance
- (1433.5 mkm)2
= 4 (778.6 mkm) (655 mkm)
- Where
- 1433.5 mkm = Saturn Orbital Distance
- 778.6 mkm = Jupiter Orbital Distance
- 655 mkm = Saturn Jupiter Distance
- (2872.5 mkm)2
= 4 (1433.5 mkm) (1439 mkm)
- Where
- 2872.5 mkm = Uranus Orbital Distance
- 1433.5 mkm = Saturn Orbital Distance
- 1439 mkm = Saturn Uranus Distance
- (4495.1 mkm)2
= 4 (2872.5 mkm) (1622.6 mkm) (error 4%)
- Where
- 4495.1 mkm = Neptune Orbital Distance
- 1622.6 mkm = Uranus Neptune Distance

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- (5906 mkm)2
= 4 (2872.5 mkm) (3033.5 mkm)
- Where
- 5906 mkm = Pluto Orbital Distance
- 3033.5 mkm = Uranus Pluto Distance
(Pluto depends on Uranus in place of its direct neighbor Neptune)

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4-2 Jupiter motion depends on the inner planets motions
4-2-1 The proof idea summary
- This Point provides the motions data of (Mercury – Mars and Jupiter). The data
shows that, the 3 planets motions are complementary with one another.
- The claim which we prove in this point is that (Jupiter Motion Depends On The
Inner Planets Motion)
- The data proves that, the 3 planets motions are complementary with one another.
- The complementary motions be near to the motions dependency more than the
motions independency.
- means,
- If the data proves that, the 3 planets motions are complementary with one another,
the data by that proves one feature of the motions dependency among the 3 planets
- Notice
- Newton description supposes, Each planet moves independently from the other
planets motions. Based on that if we prove 3 planets motions be complementary
with one another, That we disprove Newton description and move one step to the
motions dependency concept based on which Jupiter motion depends on the inner
planets motions.
- Notice
- The following data tries to prove the 3planets motions be complementary with one
another.
- Because of that, we keep this question in our mind (can these planets motions be
independent from one another? can any planet moves alone without the other 2
planets?)

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4-2-2 Mercury Day Period Analysis
I- Data
- 4900 mkm =1.16 mkm x 4222.6,
- where
- 4900 mkm = Jupiter Orbital Period
- 1.16 mkm = A distance Jupiter passes in =24.6 h (= Mars Rotation Period)
- 4222.6 hours = Mercury Day Period
II- Discussion
- The previous data tells that
(1)
- Jupiter (13.1 km/s) moves during 24.6 hours (Mars Rotation Period ) a distance =
1.16 million km.
(2)
- Jupiter orbital circumference 4900 mkm is divided on the distance 1.16 mkm by
the value 4222.6.
- That means
- Jupiter during 4222.6 Mars rotation periods move a distance = 4900 mkm = Jupiter
orbital circumference.
(3)
- 4222.6 hours = Mercury Day Period
- How to understand this data?
- The data tells,
- If 1 hour of Mercury Day Period = 24.6 hours of Jupiter motion, in this case,
Jupiter will pass its orbital circumference in a period = Mercury Day Period.
- Can we conclude that, some interaction be found among these 3 motions?
- The Following Data Proves This Motions Interaction (Or Complementarity)

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4-2-3 Jupiter Motion Data Analysis
(Point No. I) (Jupiter Orbital Circumference Analysis)
I- Data
(A)
- Jupiter orbital circumference = The inner planets orbital circumferences total
- In numbers,
- 4900 mkm = 360 mkm + 680 mkm + 940 mkm + 1433 mkm +1433 mkm (1%)
- Where
- The data considers the moon orbital circumference around the sun = Mars Orbital
Circumference 1433 mkm (and not equal Earth Orbital Circumference 940
mkm) (Later We Should Discuss Why?)
(B)
- Mercury moves during its day period (4222.6 h) a distance = 720.7 mkm =
Mercury Jupiter distance
- Venus orbital circumference 680 mkm = Venus Jupiter distance 671 mkm (error
1.2%)
- Earth orbital circumference 940 mkm = Venus Jupiter distance 928 mkm (error
1.2%) (Earth and Jupiter should be on 2 different sides from the sun to create the
distance 928 mkm).
- The 3 Inner Planets Define Their Orbital Circumferences To Be = Their
Distances To Jupiter.

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(C)
(1)
778.6 mkm = 1.0725 x 720.7 mkm (Mercury Jupiter Distance)
(2)
720.7 mkm = 1.0725 x 671 mkm (Venus Jupiter Distance)
(3)
671 mkm = 1.0725 x 629 mkm (Earth Jupiter Distance)
(D)
(4)
778.6 mkm (Jupiter orbital distance) = 1.16 x 671 mkm
(5)
720.7 mkm = 1.16 x 629 mkm (error 1%)
(6)
671 mkm = 1.16 x 580 mkm
- The data shows, the distances between Jupiter and the inner planets are defined
based on Geometrical Calculations, because of that all distances are rated with
(1.0725) and (1.16).
- Means, these planets motions are not independent motions, on the contrary they
are (complementary motions) and be created based on One Geometrical Design.
By That each planet motion data is defined in proportionality with other Planets
motions data.
- Please Notice
- We deal with the same players, Jupiter on one side and the 3 inner planets on the
other side. Their data be used frequently in different rates and forms. If there's no
geometrical reason be found behind this data, We would have to suppose tenths of
data of the same players are found by (Pure Coincidences), which is a claim has no
a piece of logic.
- The fact is clear. Some geometrical mechanism or (complementarity of motions)
be found among these planets and as a result this geometrical mechanism be seen
in their different motions data.

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(Point No. II) (The Interaction between Mercury, Mars and Jupiter)
(Sub-Point No. 1) (Mercury and Mars Motions)
- Mercury moves during its day period (4222.6 h.) a distance = 720.7 mkm
- Mars moves during (2802 hours) a distance = 243 mkm
- Mercury moves during (1407.6 hours) a distance = 243 mkm (error 1%)
- Mars moves during 346.6 d. a distance =720.7 mkm (Mercury Jupiter Dis.)
- Mercury moves during 346.6 d. a distance =1419 mkm (with 1433 error 1%)
- Mars moves during 687 d. a distance = 1433 mkm (Mars orbit. Circum)
- Mercury moves during 687 d. a distance =2815mkm (Mercury Uranus Dis.)
- Mars moves during 4331d. a distance = 9010mkm (Saturn orbit. Circum)
- Mercury moves during 4331d. a distance = 2815 mkm x 2π
- Mars moves during 224.7 d. a distance = π x 149.6 mkm (Earth orb. Dis)
- Mercury moves during 224.7 d. a distance = 920 mkm (with 928 error 1%)
- Mars moves during 365.25 d. a distance = π x 243 mkm (0.5%)
- Mercury moves during 365.25 d. a distance = 2 x 748 mkm
- Mars moves during 5040s. a distance= 121464 km= Saturn Diameter (+1%)
- Mercury moves during 5040s. a distance= 238896 km= 2 Saturn Diameters (-1%)
Where
1407.6 h = Mercury Rotation Period 2802 h = Venus Day Period
346.6 days = the nodal year 224.7 days = Venus orbital period
687 days = Mars Orbital Period
4331 days = Jupiter orbital period = 2π x 687 days

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(Sub-Point No. 2) (Mars And Jupiter Motions)
- Mars moves during 636.7 days a distance =1325 mkm= (Venus Saturn Dis.)
- Jupiter moves during 636.7 days a distance =720.7 mkm
- Mars moves during 687 d. a distance= 1433 mkm= Mars Orbital Circumference
- Jupiter moves during 687 d. a distance= 778.6 mkm= Jupiter Orbital Distance
- Mars moves during 4331d. a distance= 9010 mkm= Saturn orbital circumference
- Jupiter moves during 4331 d. a distance= 4900 mkm= Jupiter Orbital Circum.
- Mars moves during 778.6 d. a distance = 1622 mkm = Uranus Neptune Dis.
- Jupiter moves during 778.6 d a distance= 881 mkm =58 days x 15.19 mkm.
- ( 15.19 mkm = the 9 solar planets motions distances total per a solar day).

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(Sub-Point No. 3) (Mercury And Jupiter Motions)
- Mercury moves during 687 d. a distance= 2815 mkm= Mercury Uranus Distance
- Mercury moves during 1433 d. a distance =5848 mkm= Mercury Pluto Dis.
- Jupiter moves during 1433 d a distance =1622 mkm=Uranus Neptune Dis.
- Mercury moves during 4331d. a distance= 2815 mkm x 2π
- Mercury moves during 4222.6 h a distance = 720.7 mkm
- Jupiter moves during 4222.6 h a distance = 200 mkm = 629 mkm/π
- Mercury moves during 550.7 d a distance = π x 720.7 mkm (0.4%)
- Jupiter moves during 550.7 d a distance = 629 mkm (error 1%)
Please Remember,
Data Group No. (1)
- Mars moves during 687 d. a distance= 1433 mkm= Mars Orbital Circumference
- Mars moves during 4331d. a distance= 9010 mkm= Saturn orbital circumference
- Mars moves during 4331 x π d a distance= 28255 mkm= Neptune orbital circumference
Data Group No. (2)
- Mercury moves during 687 d. a distance= 2815 mkm= Mercury Uranus Distance
- Mercury moves during 4331d. a distance= 2815 mkm x 2π
Data Group No. (3)

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II-Discussion
- The planets move defined distances in defined periods of time.
- The Defined Distance means a distance is known in the solar system, as to be any
planet orbital distance or a distance between any 2 planets.
- The Defined Periods Of Time means a period of any planet cycle, as 365.25 days
(Earth orbital period) or any planet orbital period. Or any planet rotation period or
any planet day period. All these periods are defined periods of time
- The argument tells that
- If the solar planets move their motions independently from one another, based on
that, the planets motions during defined periods of time should pass (random)
distances. Because these Planets are independent in their motion from one
another. (For example) Mercury motion depends on its orbital period (88 days) and
doesn't interest for Mars orbital period (687 days) neither for Jupiter orbital period
(4331 days) and by that, Mercury during these periods (687 days and 4331 days)
should move some random distances (not defined in the solar system distances).
- The data disproves Planet Motion Independency Concept. because the (3)
planets move defined distances in defined periods of time. These planets motions
aren't independent from one another. These motions are done based on One
Geometrical Design. And these motions be are similar to Chess Board Pieces
Motions. Each Motion is calculated geometrically and be obligatory.

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Data Analysis
(I)
- 4331 days (Jupiter orbital period) = 687 days (mars orbital period) x 2π
- 2 x 346.6 days (the nodal year) = 693.2 days (different from 687 with 1%)
- 687 days (Mars Orbital Period) = 1.0725 x 636.7 days
- This data creates one thread for these 4 values (4331, 687, 346.6 and 636.7),
means,
- These 4 periods of time are created based on each other. they are created to be
used in one motion.
(II)
- Mars orbital period 687 days (24 h) = 671 Mars rotation period (24.6h)
- 671 mkm = Venus Jupiter Distance
- 680 mkm = Venus Orbital Circumference (different 1% with 687 mkm)
- The distances values be used frequently as periods of time
- This data tries to show the interaction (or complementarity of motions) still more
deep in the planets data.
(III)
(Why The Moon Orbital Circumference Be Considered =1433 mkm?)
Let's remember this question
- 4900 mkm = 360 mkm + 680 mkm + 940 mkm + 1433 mkm +1433 mkm (1%)
- Where
- The data considers the moon orbital circumference around the sun= (Mars orbital
circumference=1433 mkm), and Not = 940 mkm (Earth Orbital Circumference),
Why? Let's answer in following:

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I-Data
(1)
1433 mkm = 2.59826 mkm x 550.7
(2)
- Mercury moves during 346.6 d. a distance = 1433 mkm (1%)
- Mars moves during 346.6 d. a distance = 720.7 mkm
(3)
- Mercury moves during 135.5 d. a distance = 550.7 mkm (1%)
- The moon displacements total during 778.6 days x 2 = 135.5 mkm (1%)
- Mars moves during 831 d. a distance = 550.7 mkm x π
- The moon motion distance during 346.6 days = 831 mkm
- Jupiter moves during 2 x 243 d. a distance = 550.7 mkm (1%)
- 550.7 days x 2.574 mkm = 1417 mkm = 4.095 mkm x 346.6 days
- 550.7 days x 1.1318 mkm = 629 mkm (1%)
II-Discussion
- The data gives 3 reasons to consider the moon orbital circumference around the
sun = 1433 mkm = Mars Orbital Circumference and not equal Earth Orbital
Circumference 940 mkm, which are …
1st
Reason (Jupiter Orbital Circumference)
4900 mkm = 360 mkm + 680 mkm + 940 mkm + 1433 mkm +1433 mkm (1%)
o This data should be used as a proof. Why?
o Because
o The unified general motion depends on complementary motions. because of
that, this data should be used as a proof for this claim.
o The data shows, Jupiter and the inner planets orbital circumferences be
created complementary one another, and by that the total (4900 mkm) can
be used as a proof.

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2nd
Reason
Data no. (1)
1433 mkm = 2.59826 mkm x 550.7
- The moon daily displacement =88000 km, and the displacements total during the
moon day period (29.53 days) = 2.59826 mkm
- 550.7 mkm = Mars Jupiter distance and used here as a period of time
- This equation importance is the value (550.7 mkm) because, we have seen that, the
3 inner planets define their orbital circumferences to be equal (or rated) with their
distances to Jupiter.
- The distance 550.7 mkm is Mars Jupiter Distance and it's used to define Mars
Orbital Circumference (1433 mkm) by an effect of the moon motion. by that
Jupiter considers the 2 planets (Mars and the moon) at equal distances.
- The important point here is that, Jupiter orbital circumference is defined as the
inner planets orbital circumferences total, and on the other side, the inner planets
define their orbital circumferences to be rated with their distances to Jupiter, by
that the orbital circumferences of Jupiter and the inner planets are defined based on
one another mutually.
3rd
Reason
Data no. (2)
- Mercury moves during 346.6 d. a distance = 1433 mkm (1%)
- Mars moves during 346.6 d. a distance = 720.7 mkm
- Mercury moves during its day a distance = 720.7 mkm = Mercury Jupiter Distance
- During the nodal year 346.6 days, Mars moves a distance = 720.7 mkm = Mercury
Jupiter distance , and
- During the nodal year 346.6 mkm, Mercury moves a distance = 1433 mkm = Mars
Orbital Circumference (error 1%)

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- Means,
- During The Nodal Year 346.6 days, Mercury moves a distance belonged to Mars
motion and during the same period Mars moves a distance belonged to Mercury
motion.
- After the clear interaction we have seen between Mars and Mercury motions, we
should pay attention for this data, because it tells the moon is found inside this
interaction. And that means, Mercury and Mars motions interaction is done
almost by using the moon orbital motion. and this is one more reason to explain
why the moon orbital circumference around the sun be considered = Mars Orbital
Circumference = 1433 mkm.
Shortly
- Jupiter connects with the inner planets strongly (based on the previous data).
Jupiter connects with the inner planets in 2 points strongly which are Mercury (the
first inner planet) and Mars (the last inner planet) by this connection Jupiter creates
its connection with the inner planets.
- The point is that, Jupiter connection with the inner planets aims to provide the
environment in which the moon will move. That causes a strong connection
between Jupiter and the moon also.
- But
- Mercury is so far from the moon, and because of that, Jupiter considers the moon
Orbital Circumference Around The Sun =Mars Orbital Circumference =1433 mkm
- The data shows that

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Data No. (3)
- Mercury moves during 135.5 days a distance = 550.7 mkm (1%)
- The moon displacements total during 778.6 days x 2 = 135.5 mkm (1%)
- Mars moves during 831 days a distance = 550.7 mkm x π
- The moon motion distance during 346.6 days = 831 mkm
- Jupiter moves during 2 x 243 d. a distance = 550.7 mkm (1%)
- What does this data tell us?
- Mercury and Mars Motions pass equal distances = 550.7 mkm, by using periods of
time (135.5 days and 831 days respectively). And these periods can be defined as
distances passed by the moon motion during 2 different periods (2 x 778.6 days
and 346.6 days). That means, The moon uses Jupiter orbital distance (778.6 mkm)
as a period of time (778.6 days) and also use the nodal year (346.6 days) to pass
these 2 distances (135.5 mkm and 831 mkm) which will be used as periods of time
(135.5 days and 831 days) by Mercury and Mars respectively to pass the equal
distances =550.7 mkm! Why? What's The Important Idea Behind?
- The interaction we have seen in Mercury, Mars and Jupiter Data Clearly, is found
basically for the moon motion. by that, the moon is an essential player in this
interaction. And that may cause the moon orbital circumference around the sun to
be considered = 1433 mkm = Mars orbital circumference and not Earth orbital
circumference 940 mkm
Data No. (4)
- 550.7 days x 2.574 mkm = 1417 mkm = 4.095 mkm x 346.6 days
- Where
- 2.574 mkm = Earth motion Distance during A Solar Day
- Mercury moves during the nodal year (346.6 days) a distance = 1417 mkm (99%
of 1433 mkm = Mars Orbital Circumference)

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- Earth moves an equal distance during the period (550.7 days), where the distance
(550.7 mkm = Mars Jupiter Distance) is used as a period of time.
- By a similar equation, the moon displacements total (2.5986 mkm) uses the period
(550.7 days) to pass 1433 mkm = Mars Orbital Circumference
- That shows the Earth is effected also by this interaction because the moon is the
main player inside and that connects the Earth with this interaction among the 3
planets.
Notice
Jupiter moves during (550.7 days) a distance =629 mkm = Earth Jupiter Distance.
(1.1318 mkm daily = Jupiter motion distance per a solar day)

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4-3 Jupiter Transports The Motion To The Outer Planets
4-3-1 Preface
(1)
- Planet 8 Days Cycle shows important features of the solar planets motions, let's
summarize them in following:
- Planet Independent Motion Is Incorrect. The data analysis shows that, the
planets move as one team. That means, many planet move in the same cycle to
create one result be created only by integration of these planets motions. let's use
example for explain.
- Uranus moves a distance (A) and Jupiter moves a distance (B), Now
- (A) – (B) = 141496 km (Jupiter Diameter) (error 1%)
- The difference (141496 km) be created between the 2 planets distances regularly
through the cycle motion, as we will see. That means, the motions can't be
considered independent motions because Jupiter mentioned to move (B) and
Uranus mentioned to move (A) to create the different distance (141496 km). by
that the 2planets motions express a motion of team. It's not an independent motion.
- It's A Motion Of Team
(2)
- Planet 8 days Cycle shows that, it's created by an effect of Jupiter
- Because, as we see in the cycle motion.
- The different distance (141496 km (Jupiter Diameter) be seen between Jupiter
motion distance and its circumference base on planet 8 days cycle
- And
- This same different distance (141496 km (Jupiter Diameter) be seen between
Uranus Motion distance and Jupiter motion distance based on planet 8 days cycle
- That tells Jupiter is the main player behind, because the difference between Uranus
and Jupiter = (141496 km (Jupiter Diameter)

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(3)
- Planet 8 days Cycle shows its creation depends on the difference between the
planet motion distance during it day period and this planet circumference.
- This feature is important because the outer planet motion is distinguish by this
feature which tells (the outer planet moves in its day period a distance = its
circumference) this feature is discussed widely in the point no. (5) of this paper
because of its massive effect.
- By that , planet 8 days cycle is created based on the difference between the planet
motion distance during its day period and this planet circumference.
- Specifically
- The error (4%) between Jupiter motion distance during its day period and Jupiter
Circumference causes to create Planet 8 Days Cycle.

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4-3-2 Planet 8 Days Cycle
(I)
- Jupiter (13.1 km/s) moves during its day period (9.9 h) a distance = 466884 km
- But
- 466884 km = 449197 km (Jupiter Circumference) + 17687 km
- Where
- (8 x 17687 km = 141496 km (Jupiter Diameter) (error 1%)
- Based on that, we have concluded that, Jupiter has a cycle of 8 days
- Jupiter (13.1 km/s) moves during 8 Jupiter days (79.2 h) a distance = 3735072 km
- (3735072 km= 8 Jupiter circumferences + 141496 km (Jupiter diameter) (1%)
(II)
- The distance 3735072 km be passed also by Saturn and Neptune with a rate 80%
depends on one another as following
- Saturn (9.7 km/s) moves during 10 Saturn days (107 h) a distance = 3736440 km
- (10 Saturn Circumferences = 3786750 km, the difference =50310 km = Uranus
Diameter error 1.3%)
- Neptune (5.4 km/s) moves during 12 Neptune days (193.2 h) a distance = 3755808
km
- (24 Neptune Circumferences = 3734323 km, the difference =21485 km = Mars
Circumference (error 0.6 %))
(III)
- Uranus (6.8 km/s) moves during Pluto day period (153.3 h) a distance = 3752784
km
- The distance 3752784 km = Jupiter motion distance during 8 days + 17687 km
- And because
- 17687 km x (8) = 141496 km (Jupiter Diameter) (error 1%)

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- That tells another Cycle is found between Uranus and Jupiter based on 8 Pluto
days
- That means, the distance be passed by Uranus during 8 Pluto days equal the
distance be passed by Jupiter during 64 Jupiter days and equal the distance be
passed by Saturn during 80 Saturn days and equal the distance be passed by
Neptune during 100 Neptune days
Let's see that in following
(1)
Jupiter (13.1 km/s) moves during (64 Jupiter days) a distance =29880756 km
(2)
Saturn (9.7 km/s) moves during (80 Saturn days) a distance =29891520 km
(3)
Neptune (5.4 km/s) moves during (100 Neptune days) a distance =31298400 km
(4)
Uranus (6.8 km/s) moves during (8 Pluto days) a distance =30022272 km
Comments
- Uranus motion distance (30022272 km) – Jupiter motion distance (29880756 km)
= 141496 km (Jupiter Diameter)
- The differences between these distances is 1 % (generally –except Neptune) and
based on that we consider them equal distances.
- There are still small differences are found for geometrical reasons for example the
difference between Jupiter and Saturn motions = 29880756 km – 29891520 km =
10921 = the moon circumference

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The Discussion
- Let's discuss the previous data
(A)
- The outer planets are 5 planets, they consist 2 teams,
- The first team is consisted of Jupiter, Saturn and Neptune, these 3 planets move
based on a cycle (8 days cycle) depends on Jupiter motion with the rate 80%,
- That means
- The distance be passed by Jupiter in 8 Jupiter days be equal the distance be passed
by Saturn in 10 Saturn days and equal the distance be passed by Neptune during 12
Neptune Days
- The (small) differences between these 3 distances have geometrical necessities, as
we have seen in the difference between Jupiter and Saturn motions distances which
= 10921 km = The Earth Moon Circumference
- The moon circumference itself tells that it's a cycle because if it's not a cycle we
would find a part of the moon circumference
(B)
- The second team is Uranus and Pluto….
- Uranus uses Pluto day period (153.3 hours), and by that, Uranus (6.8 km/s) moves
during Pluto day period (153.3 hours) a distance = 3752784 km
- Because
- 3752784 km = Jupiter motion distance during 8 Jupiter days +17687 km
- And that means
- During (8 Pluto Days), Uranus moves a distance = Jupiter motion distance during
64 Jupiter days + (141496 km (Jupiter Diameter) (1%)
- Which proves Uranus also uses Planet 8 days Cycle.
(C)
- The Planets 8 Days Cycle Proves The Motion Transportation Among
The Solar Planets

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How (Planet 8 Days Cycle) Can Prove The Unified Motion?
- Because
- Many planets motions be done to produce One Result
- This result be the different distance 141496 km (Jupiter Diameter) (1%)
- If we deal with planets independent motions this different distance can't be created
regularly and the Cycle can't be defined.
- Because (Planet 8 days Cycle) be defined, that means, the different distance
141496 km (Jupiter Diameter) be defined regularly which can be done only if
we deal with motions of a team and NOT Planets independent Motion.
A Conclusion
The Planet 8 days Cycle disproves The Planet Independent Motion
Concept.
Because
Planet Independent Motion Concept Can't Create Planet 8 Days
Cycle.
Notice
- Why does Uranus depend on Pluto Day Period?
- Pluto day period is so long (153.3 h) in comparison with the outer planets days
periods. We suppose that, Uranus Motion effect on Pluto motion causes Pluto day
extension. We know Uranus did this effect because Pluto orbital inclination = 17.2
deg but Uranus day period =17.2 hours, even if we can't catch the mechanism of this
process yet, but the data shows that's Uranus effect on Pluto motion.

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The Cycle Using Examples
Example No. (1)
We Use (8 Days Cycle) For The Previous Data
I- Data
(5)
Jupiter moves during (512 Jupiter days = 64 d x 8) a distance = 239.0446 mkm
(6)
Saturn moves during (640 Saturn days = 80 d x 8) a distance = 239.13216 mkm
(7)
Neptune moves during (800 Neptune d= 100 x 8) a distance = 250.3872 mkm
(8)
Uranus moves during (64 Pluto days = 8 d x 8 ) a distance =240.17818 mkm
(9)
Mercury (47.4 km/s) moves during (1407.6 h) a distance =240.192 mkm
(10)
Mars (24.1 km/s) moves during (2802 h) a distance =243.10152 mkm
(11)
Neptune (5.4km/s) moves during (12430 hours) a distance = 241.6392 mkm
Comments
- We used the (8 days Cycle) for the distances we have discussed before.
- The planets move a distance = 243 mkm (Approximately) (error in range 1%)
- But we know that,
- Mercury moves during its rotation period (1407.6 h) a distance = 240.2 mkm
- And
- Mars moves during Venus day period (2802 h) a distance = 243.1 mkm
- For that reason I have added them to our data to see what message is told by this
data…

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Data Analysis
No. 1
- The distance passed by Saturn during (80 Saturn days) = 29891520 km
- The distance passed by Jupiter during (64 Jupiter days) = 29880756 km
- The difference = 10921 km = the Earth moon circumference
But
- The distance passed by Saturn during (80 Saturn d x 8) = 239132160 km
- The distance passed by Jupiter during (64 Jupiter d x 8) = 239044608 km
- The difference = 87550 km
- Where
- The moon displacement per a solar day = 88000 km
- Simply 88000 = 10921 km x 8
No. 2
- The distance passed by Uranus during (8 Pluto days) = 30022272 km
- The distance passed by Jupiter during (64 Jupiter days) = 29880576 km
- The difference =141696 km (= Jupiter diameter error 1%)
But
- The distance passed by Uranus during (8 Pluto days x 8) = 240178176 km
- The distance passed by Jupiter during (64 Jupiter days x 8) = 239044608 km
- The difference = 1133568 km
- Where
- Jupiter motion distance per a solar day =1131800 km
- Simply 1131800 = 141696 km x 8
- This same feature be used for the Earth moon and Jupiter. Where the cycle
produces the planet diameter and by using (8 planet days cycle), the planet
diameter be changed into this planet motion distance during a solar day.

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Example Data Discussion
- Planet 8 Days Cycle is used to prove that, The motion be transported among the
solar planets and the solar planets motions are similar to Trains Carriages Motion.
- The data proves that (NO Independent Motion be Used)
- Planet 8 Days Cycle disproves Planet Independent Motion Concept
- That shows the useful result Of The Planets Data Analysis Method.
- The question should be, On What Basics depends (Planet Independent Motion
Concept)?
- Why Does Planet 8 Days Cycle Disprove Planet Independent Motion Concept?
- Because Of
- The Different Distance 141496 km (Jupiter Diameter) (1%)
- This distance is produced frequently as different distances between many planets
motions distances and this different distance can't be created if the planet motion
be independent.
- The fact is that, the planets move as one team and by their motions distances they
create this different distance regularly and cause Planet 8 days cycle to be created.
- Means Planet 8 days cycle can be created (only if) the planets move motions
dependent on one another and NOT Independent from one another.
Notice
2 Neptune Circumferences = Jupiter Diameter + Saturn Diameter + Neptune
Diameter.

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4-4 Uranus Motion Effect on Pluto Motion
Earth and Pluto Data
I- Data
- (Earth velocity / Pluto velocity) = (Pluto Day period/ Earth day period) = 6.37 (0.8%)
Also
- (Pluto motion distance daily406000 km/ the moon displacement daily88000 km)=4.61
- (The Moon Day Period 708.7 h / Pluto Day Period 153.3 h) = 4.61
- Tan (12.2) x 708.7 h (The Moon Day Period) = 153.3 hours (Pluto Day Period)
- Tan (13.17) x 655.7 h (The Moon rotation Period) = 153.3 hours (Pluto Day Period)
- (Where 13.17 deg = the moon daily motion degrees, and 12.2 deg =13.17 deg –
0.9856 deg Earth motion daily degrees)
And
- We know that, Earth moves during its day period a distance = Pluto motion
distance during its day period = the moon displacements total during its day period
(error 1%).
- The data shows that, clear dependency be seen for Pluto and Earth motions data.
- Pluto motions distances different (= Earth circumference)
- The data proves that, they are created based on Geometrical Reason
And
- Uranus Orbital Distance = 19 x Earth Orbital Distance, And
- The Moon Metonic Cycle extends For 19 Years
- Can Uranus effect on the Earth moon motion?
- The data tells because Uranus effect on the Earth moon and Pluto motions, the
previous data be created, let's discuss this data in following…

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Discussion
Equation no. (1)
(406000 km /88000 km) = (708.7 h/ 153.3 h) = 4.61
- Where
- 406000 km = Pluto motion distance per a solar day
- 88000 km = The moon displacement per a solar day
- 708.7 hours = The Moon Day Period
- 153.3 hours = Pluto Day Period
- Based on the rule (Equal distances creates different rates of time).
- 1 hour of Pluto motion = 4.61 hours of the moon motion.
- This rate of time be concluded because Pluto moves during its day period (153.3 h)
a distance = the moon displacements total during its day period (29.53 days). By
that 708.7 hours of the moon motion = 153.3 hours of Pluto motion. And So, the
rate of time be concluded (1 h of Pluto motion =4.61 h of the moon motion)
- Again the rates of time causes (all data) to be in proportionality with one another.
in following equations we see that Pluto and the moon motions data be in full
proportionality which must be considered as very interesting data.
Equation no. (2)
Tan (12.2) x 708.7 hours = 153.3 hours
- Where
- The angle 12.2 degrees = 13.177 deg – 0.98562 deg
- 13.177 degrees = The Moon Motion Degrees Per A Solar Day
- 0.98562 degrees = The Earth Motion Degrees Per A Solar Day
- Equation no. (2) shows that the moon and Pluto days periods are created based on
each other geometrically. The fact can't be denied. Pluto day period (153.3 h) is
created as a function in the moon day period (708.7 h).

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Equation no. (3)
Tan (13.17) x 655.7 hours = 153.3 hours
- Where
- 655.7 hours = The Moon Rotation Period.
- 153.3 hours = Pluto Day Period and (153.3- h) = Pluto Rotation Period
- Equation no. (3) shows, Pluto rotation period is created depending on the moon
rotation period based on the angle (13.177 deg).
- The data of the 3 equations are strong and prove the idea clearly, because it's
directed data. Means, this data be created based on geometrical mechanism be
found between Pluto and the moon motions. For that reason, the equations use (all)
data of the 2 planets. That shows the data is directed and can't be created by any
random process. It's data be created based on geometrical reasons and rules.
- The proportionality in data between Earth and its moon on one side and Pluto on
the other side shows that a geometrical mechanism must be found behind them.
Equation no. (4)
2 x 153.3 h = 4.61 x 66.8 But
(708.7 h /10.7 h) = (655.7 h /9.9 h) =66.23 (error 1%).
- 708.7 hours = The moon Day period
- 655.7 hours = The Moon Rotation Period
- 10.7 hours = Saturn Day Period
- 9.9 hours = Jupiter Day Period
- The rate (4.61) we have defined, where (1 hour of Pluto motion =4.6 hours of the
moon motion).
- Equation no.(4) tells that this rate (4.61) is known by Jupiter and Saturn motions.
- That tells, the rate (4.61) is transported among the solar planets and that explains
how this rate be created between the moon motion and Pluto motion.

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4-5 Jupiter Pluto Distance Analysis
Equation no. (1)
201467 mkm = 2 x The Planets Orbital Circumferences Total 100733.5 mkm
Equation no. (2)
201467 mkm = 2 x 86400 seconds x 1.16 mkm/sec
Equation no. (3)
201467 mkm = (Pluto Orbital Circumference – Jupiter orbital circumference) x 2π
Equation no. (4)
201467 mkm = 28255 mkm + 2 x 86400 mkm
Equation no. (5)
201467 mkm = (Jupiter Circumference 449378.3 km)2
The Discussion
Equation no. (3)
201467 mkm =(Pluto Orbital Circumference –Jupiter orbital circumference) x2π
- Equation no. (3) summarizes the whole data meaning.
- The distance 201467 mkm can be passed in a period = 2 solar days (= 2 x 86400 s)
if the light velocity be (1.16 million per second).
- The distance 201467 mkm is the main data behind the paper hypothesis (a light
beam with velocity 1.16 mkm per second is found).
- The distance 201467 mkm is defined between Jupiter and Pluto orbits based on
Equation no. (3).
- Why can this distance prove the light supposed velocity (1.16 mkm/s) existence?
- Because,
- (1) Light needs 2 complete solar days to pass this distance, and the period 2 solar
days (2 x 86400 seconds) is a unit period and not part of any period, that tells some
cycle is found behind this period using.
- (2) The distance 201467 mkm = 2 x the solar planets orbital circumferences total
- That tells, the light supposed velocity (1.16 mkm/s) moves during 1 day a distance
= the solar planets orbital circumferences total, and this data shows a consistency.
- But Jupiter data shows using of 2 folds of these values, and that tells Jupiter
motion geometrical mechanism for geometrical necessities use the double value.

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Equation no. (4)
201467 mkm = 28255 mkm + 2 x 86400 mkm
86400 mkm=(Neptune Orbital Circumference –Venus orbital circumference) x π
- Equation no. (4) shows that, the distance 201467 km is used to built the distances
between Neptune and Venus (1st
Trajectory) and between Neptune and Earth (2nd
Trajectory). i.e.
- 201467 mkm is decreased by 28255 mkm (Neptune orbital circumference) and the
rest value is divided into 2 equal trajectories from Neptune to Venus and to Earth
(notice, Earth Equation be similar to Venus equation because the error is less 1%)
- I want to say that,
- The distance 201467 mkm, isn't defined only by Jupiter and Pluto data, but this
same distance (value) controls the distances between the outer and inner planets.
We deal here with a light beam which can be reflected from point to another
creating the same effect.
Notice
- 4495.1 mkm (Neptune orbital distance) = 78.3 mkm x 57.9 mkm
- = 108.2 mkm x 41.4 mkm
- = (149.6 mkm x 120 mkm)/4
- Where
- 149.6 mkm = Earth Orbital Distance 41.4 mkm = Earth Venus Distance
- 78.3 mkm = Earth Mars Distance 120 mkm = Venus Mars Distance
- The data shows that, the inner planets distances depend on (4495.1 mkm) because
of the data tells by Equation no. (4).
- The distance 201467 mkm is defined between Jupiter and Pluto, but used by
Neptune toward the inner planets according to equation no. (4), because of that the
inner planets distances depend on Neptune orbital distance.

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5- The Inner And Outer Planets Motions Be Distinguished
5-1 Preface
5-2 Saturn Moves A Distance = Its Circumference
5-1 Preface
- There are 2 features distinguish the outer planets from the inner planets motions
- (1st
Feature)
- The Outer Planet Moves During Its Day Period A Distance =Its Circumference
- Specifically
- Saturn moves During Its Day Period A Distance=Its Circumference (error 1.3%)
- Jupiter moves During Its Day Period A Distance =Its Circumference (error 4%)
- Jupiter error (4%) causes to create (Planet 8 Days Cycle). Because of that
- Uranus moves During Its Day Period A Distance =260% of Its Circumference
- Neptune moves During Its Day Period A Distance =200% of Its Circumference
- The rule is that,
- Outer Planet Moves During Its Day Period A Distance =Its Circumference
- But the rule is violated because of Planet 8 days cycle by which the motion be
transported from a planet to another.
- (2nd
Feature)
- Planet 8 Days Cycle
- The planet 8 days Cycle doesn’t use for the inner planets, but only with the outer
planets.
- These 2 features distinguish the outer planets motions from the inner planets.
- The basic point which is needed to be discussed is the motion transportation which
we should discuss in point no. (6) of this paper.

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5-2 Saturn Moves A Distance = Its Circumference
- Saturn (9.7 km/s) moves during its day period (10.7 hours) a distance = 373644 km
= 98.67 % of Saturn Circumference (378675 km).
- The difference between the distance (373644 km) and Saturn Circumference =
5031 km. (= 1.3%)
- Why this is interesting?
- Because if a planet moves during its day period a distance = its circumference that
will create a rate between this planet orbital period and day period
- Means
- (Planet Orbital Period/ Day Period) = (Planet Orbital Circumference / Planet
Circumference)
- For that reason, we interest in planet motion distance during its day period.
- Saturn motion performs this rate
- But
- It shows that, the rate in Saturn data be changed because of geometrical necessities
which I claim they are produced as a result for (planet 8 days cycle). Let's
summarize the idea in following
o The inner planets move under their electric field because of that their
motions be defined by this field effect, but
o The outer planets receive the motion by transportation of motion. because of
that, the outer planets have no a guide in their motion, they use their
circumference as a guide
o If this rule be working, the outer planet would move during its day period a
distance = its circumference - But
o Because planet 8 days cycles which causes the motion transportation among
the outer planets, that creates an interaction which changes the rule and
caused the outer planets to move during their days periods distances (NOT)
equal their Circumferences, but (rated with their circumferences)

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o Jupiter (8 day cycle) shows clearly that, the planet circumference is a player
in the cycle and proves the interaction which is found among the outer
planets as a result for planet 8 days cycle.
o This explanation details disproves clearly Newton Description because the
motion (here)is transported from one planet to another clearly an with strong
proves which disproves the sun masses gravity concept
o The point is that, the interaction among the outer planets motions cause the
change in the rule and creates planet 8 days cycle. But. The rule still wroks
spite the deviation.
o I want to say that,
o Saturn moves During Its Day Period A Distance=Its Circumference (error
1.3%), But the machine feels that no error in Saturn motion. because this
error is found as a result for the configuration with Planet 8 days cycle
o By this same explanation all outer planets motions be controlled. The errors
in the planets motions from the rule (Outer Planet moves during its day
period a distance = its circumference) still works sufficiently, the errors be
found as a result for planet 8 days cycle.

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6- The Motion Transportation Definition
- Through the whole paper, one or two questions be left behind frequently, let's
remember these questions in following
- How The Motion Be Transported Among The Solar Planet?
- Why is the machine real motor different from Newton Description Motor?
- What feature distinguish this motor an makes it different from Newton motor?
- In fact
- These Questions Are The Reason By Which Newton Description Be Refuted.
- Let's try to explain the idea as clear as possible in following:
- The solar system motion be transported from one planet to another. this feature is
seen clearly in the outer planets motions
- The motion transportation motor depends on one rule which is
- 2 Planets Move Equal Distances In Defined Periods Of Time
- This is the golden rule which controls the motion transportation among the solar
planets.
- Here, no question, how this feature works
- What we need to prove is that, This Feature Creates This Effect
- We have seen this feature be used in the solar planets motions frequently for
hundreds of times. For example in Planets 8 days cycle. Also in planets 6 days
cycle. In all planets motions. This rule be the used method frequently and
continuously –thousands of examples can be provided:
- Earth moves during its day period a distance = Pluto motion distance during its day
period = the moon displacements total during its day period (1%)
- Jupiter moves during its day period a distance = Neptune motion distance during
the solar day period.
- In this paper there are tenths of examples we have seen

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- What is the idea behind?
- The solar planets motions depend on a geometrical tool
- The geometrical tool is a tool works by a geometrical rule. s similar to any lever or
the waterwheel. It's a tool works based on a geometrical rule doesn't need a motor
or any force. it creates its own force based on this geometrical tool creation.
- The 2 planets motions equal distances create this geometrical tool by which the
planet can move. In this case no need for masses gravity or for any force.
- As in the waterwheel, it works without any motor because it depends on the water
motion and the geometrical rule
- I can't explain in more details how the geometrical rule works, because I still don't
discover how the equal 2 distances create the motion. because of that, I can't
explain in full details how the machine real motor works
- But
- Even if I don't discover how the 2 distances create planet motion. that doesn't give
Newton description any hope to still working. Basically because, the 2 equal
distances show clearly that, the motion be transported from a point to another point
through the solar system. This transportation of motion be seen clearly in different
data as we have seen in the planet orbital distance equation and planet 8 days cycle
and many other data. the motion transportation be done from a point to its
neighbor point. By that we see a clear motion progressing in a clear textile. It's a
process very similar to the weaving of cloth. And this process which is seen
through the planets data shows that the transportation be done from a near point to
its neighbor point, by that the line from the sun to the planet has no any effect on
any planet data.
- I want to say
- Even if I can't catch how the 2 equal distances cause the planet motion, but the 2
equal distances cause the planet motion. even if I can't catch the geometrical effect
found by the 2 equal distances but I surround them in a clear point. The 2 equal

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distances is the method by which the solar plant moves (specially the outer
planets). It's the main motor behind the solar system motion, or at least behind the
outer planets motions
- I confirm this conclusion time after time without any piece of doubt completely
because this feature is the one be used thousands of times in the solar system
motion. it's very famous method used in the solar system motion frequently and
continuously
- Based on this analysis, not only Newton description be refuted but also I define the
place in which the main motor is found. Because the main motor of the solar
system is the 2 equal distances and it needs only an intelligent engineer to catch
the geometrical effect by which the planet moves.
Notice
- Uranus effects on the Earth moon and Pluto motions, and by this effect Pluto day
period be extending (153.3 h) and the moon rotates Metonic Cycle. This effect is
so important because it connects the group because the energy which is sent from
Jupiter to Pluto through Uranus be connected with Earth and the moon motions
and we know that Jupiter motion depends on the inner planets. That shows the
necessity of Uranus effect on both planets.

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7 -The Planets Motions Use Different Rates of time
7-1 Preface
7-2 Earth And Pluto Rate Of Time
7-3 Mercury Motion Rate Of Time
7-4 Saturn Motion Rate Of Time
7-1 Preface
- The Solar Planets Motions Use Different Rates Of Time
For example
- 1 hour of Mercury Motion =9.18 hours of Pluto Motion
- And
- 1 hour of Earth Motion = 29.53 hours of The Moon Motion
- We don't provide any theoretical explanation to explain why or how the solar
planets motions use different rates of time.
- Because
- I want to show that, The Solar Planets Motions Data Proves The Different
Rates Of Time Using
- I hope to prove this fact by very powerful and strong data and arguments. After we
should to know why or how the solar planets motions use different rate of time.
-
- There Are 2 Useful Results For This Approach
- (1st
Result).
- When the planets motions data prove the different rates of time using. In this case
my ideas will not be a point of discussion. Because I provide the data and if my
ideas be refused the data will be stayed in waiting for someone to explain how this
data be created.
- (2nd
Result).

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- The data saves us from the imagination. And by that we may move toward the
facts with more safe way.
- But
- The different rates of time is a meaning we have learnt from the Special Theory of
relativity and Lorentz Transformations.
- Each time we talk about it, the minds thinks in high velocity motion
- The question should be
- If the nature creates (by high velocity motion) different rates of time. Can the
nature use other method to create different rates of time with low velocities
motions?
- I suppose the nature provides examples of methods and not restricted one.
- Any way
- I don't explain how the planet motion use different rate of time. I try to show that,
The Planet Motion Data Proves This Fact Regardless Any Explanation.
Notice
- The Planets Unified General Motion Creates One Unified Rate Of Time.

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7-2 Earth And Pluto Rate Of Time
I- Data
Group no. (1) (Earth and Pluto Rate Of Time)
(A)
- Earth (29.8 km/s) moves during a solar day (24 h) a distance = 2574720 km
- Pluto (4.7 km/s) moves during its day (153.3) a distance = 2593836 km
- The moon displacements total during (29.53 days) = 2598693 km
- Pluto and the moon motion distances be equal but they different from Earth motion
distance with (1%).
(B)
- (Earth velocity / Pluto velocity) = (Pluto Day period/ earth day period) = 6.37 (0.8%)
(C)
- 1 hour of Earth motion = 29.53 hours of the moon motion.
Group no. (2) (Pluto And The moon Rate Of Time)
(1)
(406000 km /88000 km) = (708.7 h/ 153.3 h) = 4.61
(2)
Tan (12.2) x 708.7 hours = 153.3 hours
(3)
Tan (13.17) x 655.7 hours = 153.3 hours
(4)
2 x 153.3 h = 4.61 x 66.8 But
(708.7 h /10.7 h) = (655.7 h /9.9 h) =66.23 (error 1%).
(5)
413600 km cos (10.96 deg) = 406000 km
(6)
(10.96 deg /1.7 deg) = (153.3 h /24 h) (error 1%)
Data Analysis

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(I)
- The data analysis shows that,
- The rate of time be defined based on the planets velocities rate
- For example
- Mercury velocity (47.4 km/s) = Venus velocity (35 km/s) x 1.35
- And
- Mercury velocity (47.4 km/s) = Earth velocity (29.8 km/s) x 1.6
- by that
- 1 hour of Mercury motion = 1.35 hours of Venus Motion
- And
- 1 hour of Mercury motion = 1.6 hours of Earth Motion
(II)
- If there's a difficulty to use the planets velocities, the next rule can be used instead.
- Equal Distance Creates Different Rates Of Time
- For example
- Earth moves during its day period (24 h) a distance = Pluto motion distance during
its day period (153.3 h) (error 1%)
- Because the distances are equal, the 2 periods create the rates of time, means
- 24 hours of Earth motion = 153.3 hours of Pluto motion.
(1 h of Earth motion = 6.37 hours of Pluto motion)
- Notice (1) (the error between distances should not be more than 1%)
- Notice (2) (when the velocities be difficult to be used?) As in the moon case. The
moon moves per a solar day a distance =2.574 mkm = Earth motion distance per a
solar day, otherwise they will be separated from each other. But the moon rate of
time is defined based the moon daily displacement (88000 km).

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II- Discussion
- The previous data is so interesting data.
- The proportionality of Earth and Pluto motions data always shows puzzle need
explanation.
- The Planets Unified General Motion creates the geometrical reason which can
explain the data. And now we know that, the same one law controls the 2 planets
motions and causes their data to be created in proportionality.
- I hour of Earth motion = 6.37 hours of Pluto motion
- This rate is concluded simply from Earth and Pluto velocities
Because
- Earth velocity (29.8 km/s) = Pluto velocity (4.7 km/s) x 6.37
- Also
- Pluto Day Period (153.3 h) = Earth Day Period (24 h) x 6.37
- The rate (6.37) which creates the rate of time between Pluto and Earth Motions,
effects greatly on the 2 planets motions data. As we have seen.
- Let's summarize the data idea in following:
o There's a proportionality between Pluto Data on one side and the other side
and its moon data on the other side. No Pure Coincidence can be claimed,
because the connection among the three planets be defined based on their
positions to one another. the question be (How This Data Be Created?)
o Even after we suppose (1 h o earth motion = 6.37 h of Pluto motion) this
idea can't explain simply how the data be created. the point is that, this rate
be used in the planets unified general motion, and through this general
motion the effect can be created. but the geometrical mechanism needs more
analysis to be caught.
o Let's discuss the data in following:

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Equation no. (C)
1 hour of Earth motion = 29.53 hours of the moon motion.
- Because
- The moon displacements total during the moon day period (29.53 days) = Earth
motion distance during a solar day Period. (error 1%)
- Because of that
- 1 Day Of Earth Motion =29.53 Days Of The Moon Motion.
- We can see that, the machine works with consistency, for example
o 1 hour of Earth motion =6.37 hours of Pluto motion
o 1 hour of Pluto motion = 4.61 hours of the moon motion
o And
o 1 hour of Earth motion = 6.37 x 4.61 = 29.53 hours of the moon motion
o The rates of time are created based on each planet motion data and be in full
harmony as we see. That tells we deal with a geometrical mechanism works
consistency…
- Let's see the rate of time of Pluto and the moon motions

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Group no. (2) (Pluto And The moon Rate Of Time)
Discussion
Equation no. (1)
(406000 km /88000 km) = (708.7 h/ 153.3 h) = 4.61
- Where
- 406000 km = Pluto motion distance per a solar day
- 88000 km = The moon displacement per a solar day
- 708.7 hours = The Moon Day Period
- Based on the rule (Equal distances creates different rates of time).
- 1 hour of Pluto motion = 4.61 hours of the moon motion.
- This rate of time be concluded because Pluto moves during its day period (153.3 h)
a distance = the moon displacements total during its day period (29.53 days). By
that 708.7 hours of the moon motion = 153.3 hours of Pluto motion. And So, the
rate of time be concluded (1 h of Pluto motion =4.61 h of the moon motion)
- Again the rates of time causes (2 Planets All Data) to be in proportionality with
one another. in following equations we see that Pluto and the moon motions data
be in full proportionality which is very interesting data.
Equation no. (2)
Tan (12.2) x 708.7 hours = 153.3 hours
- Where
- The angle 12.2 degrees = 13.177 deg – 0.98562 deg
- 0.98562 degrees = The Earth Motion Degrees Per A Solar Day
- Equation no. (2) shows that the moon and Pluto days periods are created based on
each other geometrically. The fact can't be denied. Pluto day period (153.3 h) is
created as a function in the moon day period (708.7 h).

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Equation no. (3)
Tan (13.17) x 655.7 hours = 153.3 hours
- Where
- 655.7 hours = The Moon Rotation Period.
- 153.3 hours = Pluto Day Period and (153.3- ) = Pluto Rotation Period
- Equation no. (3) shows, Pluto rotation period is created depending on the moon
rotation period based on the angle (13.177 deg).
- The data of the 3 equations are strong and prove the idea clearly, because it's A
Directed Data. Means, this data be created based on geometrical mechanism be
found between Pluto and the moon motions. For that reason, the equations use (all)
data of the 2 planets. That shows the data is directed and can't be created by any
random process. It's data be created based on geometrical reasons and rules.
- The proportionality in data between Earth and its moon on one side and Pluto on
the other side shows that a geometrical mechanism must be found behind them.
Equation no. (4)
2 x 153.3 h = 4.61 x 66.8 But
(708.7 h /10.7 h) = (655.7 h /9.9 h) =66.23 (error 1%).
- 708.7 hours = The moon Day period
- 655.7 hours = The Moon Rotation Period
- 10.7 hours = Saturn Day Period
- 9.9 hours = Jupiter Day Period
- The rate (4.61) we have defined, where (1 hour of Pluto motion =4.6 hours of the
moon motion).
- Equation no.(4) tells that this rate (4.61) is known by Jupiter and Saturn motions.
- That tells, the rate (4.61) is transported among the solar planets and that explains
how this rate be created between the moon motion and Pluto motion.

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Equation no. (5)
413600 km cos (10.96 deg) = 406000 km
- Where
- 406000 km = Pluto Motion Distance During A Solar Day
- Equation no. (5) shows that, the motions interaction between the moon and Pluto is
a deep interaction. And effects on the planet motion basic data. Because
- The moon displacements total during 29.53 days =2598693 km = 2π x 413600 km
- The distance (413600 km) should be the moon apogee orbital radius if the moon
apogee orbital circumference = the moon displacements total during 29.53 days.
- This is the fact which should be performed
- But
- The moon apogee orbital circumference be (2550973 km) less than the moon
displacements total during (29.53 days) with 2%. This fact arises the question
Why? the moon apogee circumference should be 2598693 km (surely). But for
some geometrical miracle this distance became =2550973 km!
- The radius 413600 km be changed into 406000 km and this change be done based
on the equation no. (5). The angle (10.96) caused this change. We have discussed
this angle before deeply because it's the main angle in the moon orbit geometrical
structure (we will review a short notice about it later). The angle (10.96 deg)
causes the radius 413600 km to be 406000 km – why?
Equation no. (6)
(10.96 deg /1.7 deg) = (153.3 h /24 h) (error 1%)
- The angle 10.96 deg be created based on the rate between Pluto Day Period
(153.3h) and Earth Day Period (24 h). this rate be used between the angle (10.96)
which causes to decrease the radius from 413600 km to 406000 km, and the angle
1.7 deg which is the moon daily motion angle in the moon orbital equation (θ1= θ0
+ 1.7 deg). (The moon orbital equation be discussed in the moon orbital motion
description point no.8** of this paper)

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Notice (1)
- The moon displacements total 2598693 km should be the moon apogee orbital
circumference, by that, the moon apogee orbital radius should be =413600 km
- But
- It's not true, the moon apogee orbital radius =406000 km
- Why? because of the angle (10.96 degrees)
- Let's remember this angle in following:
o The moon orbital perigee radius =363000 km
o The moon orbital apogee radius = 406000 km
o If we draw these 2 radiuses in 2 circles as in the figure
o The tangent DB = 181843 km, also
o The perigee orbital circumference = 2.28 mkm
o (181843 km /2.28 mkm) = 0.08
o 137 degrees x 0.08 = (10.96 degrees)
o As we remember that 137 degrees = 95.1 deg x 1.44 deg where
o 95.1 deg =90 deg + 5.1 deg (the moon orbital inclination)
o 1.44 deg = the moon orbit regression degrees per month.
o We have supposed that the angle 137 degrees is created based on the moon
orbital inclination (degrees) and the moon orbit regression angle monthly.
And this angle (137 deg) is the basic angle in the moon orbital geometrical
structure (hypothesis).
o The calculations of the tangent DB = 181843 km aimed to explain one basic
idea which is, the moon orbit is built geometrically to create the rate (0.08)
by which the moon orbital inclination and regression will create the angle
(10.96 deg).
o Let's explain that more clearly

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o The moon orbit inclination and regression controls the moon orbital motion.
this is a hypothesis. Now, the moon orbital motion creates the moon orbit
based on a geometrical design, the moon orbital motion uses the moon orbit
geometrical design to create the angle (10.96 deg) from the basic one (137
deg). by that the original angle is (137 deg) which is created by the moon
inclination and regression unification, and the born angle is (10.96 deg)
which is the motor of the machine.
o What we need to refer to that, the moon orbit geometrical design is used in
this process. That's why the distance 413600 be decreased and became
406000 km. By that, the main player is the angle (10.96 deg).
- This explanation answers the question,
- Why Pluto Motion Distance During A Solar Day = The Moon Apogee Orbital
Radius=406000 km?

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Notice (2)
- The previous data still have another reading let's summarize it in following:
o Pluto day period is a very long day period in comparison with the outer
planets days periods, Why?
o We notice also that, Pluto Moves During Its Day Period A Distance =
Earth Motion Distance During Earth Day Period. That means, Pluto Day
Period be extending to perform this requirement.
o i.e.
o Pluto Day Period be extending to be 153.3 h to enable Pluto to move a
distance = Earth motion distance during Earth day period.
o Because of that,
o Pluto day period (and rotation period) be created as functions in the Earth
moon day and rotation periods as we have seen in the data discussion.
o i.e.
o The interaction between Pluto motion on one side with the Earth and its
moon motions on the other side caused the following results:
o (1st
Result) the moon apogee orbital radius be decreased from 413600 km to
be 406000 km
o (2nd
Result) Pluto Day Period be extending to be =153.3 days.
o These 2 Results Are Produced Depends On One Another.
Notice (3)
- Uranus effect is the main force behind these changes in both planets data because
Uranus effects on the moon and Pluto motions.

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7-3 Mercury Motion Rate Of Time
I- Data
(1)
112.2 km/s = 4.7km/s x 23.9
(2)
1407.6 hours =153.3 hours x 9.18
(3)
90560 days = 4222.6 hours x 9.18 x 2.33 (error 2%)
(4)
(2 x 153.3 h x 3600 s) /5040 s =23.9 x 9.18
II- Discussion
Equation (1)
112.2 km/s = 4.7 km/s x 23.9
- Where
- 112.2 km/s = The 3 Planets Velocities Total
- 4.7 km/s = Pluto Velocity
- Let's suppose, the 3 planets velocities (Mercury, Venus and Earth) be unified in
one velocity =112.2 km/s, So this velocity works as one gear and Pluto velocity
works as another gear, move relative to one another.
- By this supposed motion of 4 planets, the rate (1 hour = 23.9 hours) be created and
that causes 1 hours of a planet motion be = 23.9 hours of another planet motion.
- This process has a great effect on the solar planets rates of time because if the
planets motions rates of time depend only on the planets velocities that makes the
max rate is (10.08). Means, 1 hour of a planet motion be = 10.08 hours of another
planet motion. And this is a very narrow range of the rates of time. The 3 planets
velocities total creates an extension for this process and enables the system to
create the rate (1h = 23.9 h).

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Equation (2)
1407.6 hours =153.3 hours x 9.18
- Where
- 1407.6 hours = Mercury Rotation Period
- 153.3 days = Pluto Day Period.
- (9.18) = The rate of time between Mercury and Pluto motions.
- We conclude that mercury and Pluto motions rates of time is (9.18) based on this
equation. Means
- 1 hour of Mercury Motion = (9.18) hours of Pluto Motion.
- By this same method we conclude the rate of time between Pluto and the moon
motions. It was the rate between the moon day period and Pluto day period. But
here the rate (9.18) is between Mercury Rotation Period and Pluto Day Period
(where Pluto day period =153.3 h and Pluto rotation period = -153.3 h)
Equation (3)
90560 days = 4222.6 hours x 9.18 x 2.33 (error 2%)
- Where
- 90560 days = Pluto Orbital Period
- 4222.6 hours = Mercury day period
- 2.33 = ??
- Mercury velocity (47.4 km/s) = 10.08 x Pluto velocity (4.7km/s). if the planets
rates of time depend on their velocities. That means 1 hour of Mercury motion =
10.08 hours of Pluto motion. and in this case 24 hours of Pluto motion = 2.37
hours of Mercury Motion.
- That because the equation uses (Pluto orbital period 90560 solar days) in
comparison with 4222.6 hours (Mercury day period). The equation proves that the
rate (9.18) is the used one between the 2 planets.

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Equation (4)
(2 x 153.3 h x 3600 s) /5040 s =23.9 x 9.18
- Where
- 5040 seconds are required for Mercury day period to be 176 solar days
- 153.3 h = Pluto Day Period.
- 23.9 = the rate between the 3 planets velocities total (112.2 km/s) and Pluto
velocity (4.7 km/s).
- This equation also proves that the rat of time between Mercury and Pluto is (9.18)
- The data proves that, 1 hour or Mercury motion = (9.18) of Pluto motion.
Notice
- Different data of Mercury and Pluto Motions shows that the rate of time between
them is (9.18)
- Because this rate is used in different data in the 2 planets motions data, we
conclude that it's a fact and real one.
- I wish the proves show its power clearly. Because we deal with geometrical data.
We find for example a rate (9.18) between Mercury and Pluto motions data and
this rate be used between them frequently. That happens also with Earth (6.37) and
with the moon (4.61).
- The point is that, the rate of time has a massive effect on planets motion but we
still need to discover this effect clearly.
- It's noticeable to take into consideration the method by which the rate of time
effect on Planet Motion.
Notice
- If Mercury and Pluto motions rate of time be defined based on their velocities
only, The rate will be 10.08 (means 1 h of Mercury motion = 10.08 h of Pluto
motion). the rate (9.18) effect only on Pluto and Mercury motions but no other
planets. For example (Mercury 1 hour =46.1 h of The Earth moon motion), in this
case (46.1 = 10.08 x 4.61) , the data doesn’t use (9.18) but (10.08).

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Notice
- How the rate (9.18) be created?
- Let's move step by step in following
o The 3 planets velocities total (112.2 km/s) = Pluto velocity (4.7 km/s) x 23.9
o By that (1 h of these 3 planets motion = 23.9 h of Pluto motion).
o And
o The 3 planets velocities total (112.2 km/s) be used again in face with a third
velocity which is (12.2 km/s) (= Uranus velocity + Neptune velocity)
o 112.2 km/s = (12.2 km/s) x (9.18)
o Means,
o The rate (9.18) between Pluto and Mercury motions be created by an effect
of the total velocity (112.2 km/s) in relative to (Uranus and Neptune
velocities total 12.2 km/s).
o Why?
o Because Uranus effects on Pluto day period and extends it to be 153.3 h
o Uranus effect on Pluto day period be found by Uranus using of Pluto day
period in (Planet 8 Days Cycle)
o On the other side, Uranus uses Pluto rate to the 3 planets. And by that 1 hour
of Mercury motion b = 24 hours of Uranus Motion, the next data will prove
that.

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7-4 Saturn Motion Rate Of Time
I- Data
(1)
Saturn moves daily 838080 km = the Earth moon displacement 88000 km x 9.52
(2)
Saturn diameter 120536 km = Earth diameter 12756 km x 9.5
(3)
Saturn orbital distance 1433.5 mkm = Earth orbital distance 149.6 mkm x 9.5
(4)
Earth axial tilt 23.4 deg = Saturn orbital inclination 2.5 deg x 9.4
(5)
Saturn Orbital Period 10747 days = 365.25 days x 29.53 days
(6)
2.4 mkm x 10747 days =25920 mkm = 17.75 mkm x 1461 days
II-Discussion
- The data shows that, the rate of time between Saturn and the Earth moon motions,
be used as a rate between many different data of Earth and Saturn.
- This feature is similar perfectly to Pluto data proportionality with Earth data.
- And also the data between Pluto and Mercury.
- The data tells that, the rate of time has a massive effect on the planets motions
data. This feature which we see frequently in different planets data.
- The data (1, 2 ,3 and 4) shows that the rate of time (9.5) creates a proportionality
between Saturn and Earth motions data.
- Equation. No.(5) shows that, Saturn Orbital Period be defined based on earth
orbital period and the moon orbital period. That means, the rate of time (9.5)
creates a proportionality between earth and Saturn motions data and this
proportionality causes Saturn orbital period to be produced as a result for this
proportionality.
Equation no. (6)
2.4 mkm x 10747 days =25920 mkm = 17.75 mkm x 1461 days

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2.4 mkm = (the moon motion distance daily) ( review the moon orbital motion)
10747 days = Saturn Orbital Period
17.75 mkm = the total distances be passed by the solar planets per solar day
(including the Earth moon motion distance)
1461 days = Earth Cycle (365 +365 +365 +366)
Notice
6.8 km/s x 59800 seconds =406000 km = 4.7 km/s x 86400 seconds
5.4 km/s x 59800 seconds = 2 x 160000 km (Uranus Circumference) (error 0.5%).

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Notice
II- Mercury Uranus Motions Rate of Time
- Mercury Uranus Distance = 2815.2 mkm
- Mercury rotation period = 1407.6 hours
- 2 x Mercury rotation periods = 2815.2 hours
- If 1 mkm = 1 hour, So the distance 2815.2 mkm be = 2 Mercury rotation periods
And
- Mercury (47.4 km/s) moves during its rotation period (1407.6 h) a distance = 243
mkm (error 1%)
- 243 solar days = Venus rotation period
- If each 1 mkm be =1 solar days, the distance 240 mkm be = 243 days (error 1%)
Based on that
- Mercury as a player uses (1 mkm = 1 hour) and (1 mkm = 1 day =24 hours)
- That creates the rate (1 hour = 24 hours)
- But between whom? Almost
- Between Mercury and Uranus, means
- 1 hour of Mercury Motion =24 hours of Uranus Motion.
- This rate also doesn't depend on the planets velocities rates (where Mercury
velocity = 7 Uranus velocity)
Notice (1)
1 hour of Pluto Motion = 2.62 hours of Uranus Motion - Because
1 h or Mercury motion = 24 h of Uranus motion =9.18 h of Pluto motion
Notice (2)
153.3 hours = 2.62 hours x 58.66 hours (153.3 hours = Pluto Day Period)
58.66 solar days = Mercury Rotation Period

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8- The Sun Creation Details.
8-1 Preface
8-2 The Solar System Unified Motion
8-3 The Sun Rate Of Time
8-1 Preface
- The Sun Is A Result For The Solar System Motion.
- The Sun Rays Energy Is Created By The Solar Planets Motions Energies Total
- That means, The Solar Planets Motions Energies Be Accumulated And Be Used
For The Sun Rays Creation.
- Based on this vision, the sun rays aren't created by any nuclear interactions found
inside the sun. the energy is provided by the solar planets motions energies.
- The Main Force In This Process Is The Sun Rate Of Time.
- Where
- 1 Day of The Sun Motion = 365.25 Days of Earth Motion.
- Based on this rate, The energy which is accumulated during one complete year be
consumed by the sun in one solar day only. And by that, the accumulated energy
be sufficient for the light production process.
- For better explanation, we should consider the Earth as the planets representative,
by that, the solar group motions energies be accumulated on Earth motion. and
Earth motion causes to create the rate of time 1 Day of the sun = 365.25 days of
Earth. And by that the energy which is accumulated on Earth motion will be sent
to the sun to be used in the sun rays creation.
- Based on this vision, The sun will be just a mirror reflects the light beams which
are emitted from the Earth motion. and this vision may effect negatively on the sun
science – But -
- It's Not necessary to effect negatively on the sun science
- The whole sun science can be saved without change, but

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- The sun science should replace the source of energy. Because the source of energy
is the solar planets motions energies total accumulated during a complete year. by
that, the source of energy isn't the nuclear interactions found inside the sun.
- We should notice that, because the matter is created almost out of light, the sun
matter and mass can be created by the energy of the planets motions energies total.
the point is that, The Energy Creates The Matter. And if the energy is available
the matter can be created regardless the creation method.
- By that, The sun matter and Mass can be created and all the sun science can be
saved but the source of energy is the planets motions energies total.
- We should notice that, the planets motions energies total be a weak energy, but
because of the accumulation for 1 complete year (365.25 days), this accumulation
gives the chance for this energy to be used to create the sun rays. And because this
rate of time is the sun rate of time, so, no one planet sees this energy. because this
energy is created depends on the sun rate of time which is different from all
planets rate of time. And by that, the energy be used by the sun only and not by
any other planet.
- In the following point we should discuss the details how the sun rays be created…
Notice
- Please review appendix no. 2 for more material of discussion.

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8-2 The Solar System Unified Motion
- The solar system moves a unified motion. that means, the solar planets motions be
unified together and create One Unified General Motion. this motion which is
similar to the Train carriages Motions, where all planets motions be used to create
The One Unified General Motion.
- But
- Why does the solar system need this One Unified General Motion?
- Because by this unified motion The Sun Rays Be Created.
- Let's explain how that's happening in following:
- The 9 Solar Planets Velocities Total = 176 km/s
- But,
- We need to add the Earth moon velocity (29.8 km/s) and by that the total will be =
176 + 29.8= 205.8 km/s
- The moon velocity is = Earth velocity because they aren't separated from each
other through their motions.
- So, the 10 Planets velocities total be =205.8 km/s
- Why this total is required? Because
o The Sun Rays Energy Is Produced From The Solar Planets Motions
Energies Total.
o Means,
o The sun rays energy source is The Planets Motions Energies Total
o Because of that, the planets velocities total is required because based on this
total The Sun Rays Be Produced.
o In calculations, the velocities total (205.8 km/s) is the source of the sun
rays energy.
o Let's explain The Sun Rays Production Process in following:

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(Point No. 1) (The Sun Rate Of Time)
Equation no. A
10921 km (The Moon Circumference) x 86400 Seconds = 940 mkm
- Equation no. (A) tells. If Earth revolves around the sun a complete revolution
(=940 mkm = Earth Orbital Circumference) in one solar day only (86400 sec), in
this case, the moon circumference (10921 km) will be equal the Earth motion
distance during 1 second.
- But, because
- Earth revolves around the sun in one year (=365.25 days), so this equation may
refer to a rate of time is used by the sun herself.
- Based on that,
- We suppose, the sun uses a rate of time different from Earth rate of time which is
(1 Day Of The Sun = 365.25 Days Of Earth)
- We will suppose that, this rate is a real one and try to test if it's a fact.
- Now we have 2 hypotheses which are
- (1st
hypothesis) (The planets velocities total is used to create the sun rays)
- (2nd
hypothesis) (1 Day Of The Sun = 365.25 Days Of Earth)
- Let's use the planets data depending on these 2 hypotheses in following:
(1)
- The solar planets velocities total (=205.8 km/s) and during a solar day the total
passed distance be = 205.8 km/s x 86400 seconds = 17.75 mkm
(2)
- 1 day of the sun =365.25 days of Earth, means
- 1 day of Earth = 237 seconds of the sun
(3)
- The distance =17.75 mkm and the time =237 seconds, so the velocity =75000 km/s

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(4)
- 75000 km/s = a quarter of the light velocity (300000 km per second)
(5)
- Means,
- The solar planets velocities total based on the sun rate of time be = 0.25 of light
velocity (A Quarter Of Light Velocity)
(6)
- Earth has a cycle of 4 years (365 +365 +365 +366=1461 days).
- Earth Uses This Cycle To Create A Light Beam From The Solar Planets
Motions Energies Total.
(7)
- Means,
- The sun rate of time is (1 day of the sun = 365.25 days of Earth). This is the
unified rate of time which is produced for the solar planets unified motions. This
rate of time causes the solar planets velocities total to be = a quarter of light beam
velocity =75000 km /s
- But
- Earth created a cycle of 4 years, to use it in the energies accumulation process for
this (quarter of light velocity) to produce the light velocity (i.e. to produce The Sun
Rays.)
- Because The Light Beam Is Created Based On Quantization, The Sun Rays Can't
Be Created If Earth Has No This (4 Years) Cycle.
- Based on that,
- Although the sun rays is produced by the planets velocities total but without the
Earth nothing can be done because Earth uses its (4 years) cycle to produce the sun
rays (practically) from the available energy.
- But, If The Earth moon is partner in this process, that means, the moon should
have an effect on Earth (4 Years Cycle).

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(Point No. 2) The Distance 25920 mkm
(1)
- Light (0.3 mkm/s) travels during a solar day a distance = (25920 mkm)
- The solar planets velocities total per a solar day = 17.75 mkm per a solar day
- During 1461 days, the solar planets (17.75 mkm) move a distance =25920 mkm.
- Because there's a light motion behind this data, the distance 25920 mkm we see as
a period of time (25920 years = The Precession Cycle).
(2)
- The data tries to show that, the cycle 1461 days is used by all planets velocities
total, means, it's a cycle for the whole solar system and not Earth Cycle only.
(3)
(2 x 1461 days / 327.6 days) = (243 days /27.3 days) = (153.3 h/17.2h) =5832.5 h/
655.7 h) = (224.7 days /25.2 days) = (778.6 days /88 days) = (2722 mkm/306 mkm)
- Where
- 1461 days = Earth Cycle 327.6 days= The Lunar Sidereal Year
- 243 days = Venus Rotation Period 27.3 days = The moon orbital period
- 153.3 hours = Pluto Day Period 17.2 hours = Uranus Day Period
- 224.7 days = Venus Orbital Period 25.2 deg =Mars Axial Tilt
- 778.6 mkm = Jupiter orbital distance 88 days = Mercury Orbital Period
- 2722 mkm = Uranus Earth Distance 153mkm = Earth orbital distance (2%)
- The previous data aims to show that, the moon effects greatly on the cycle 1461
days. But because the cycle 1461 days is considered a cycle for all planets, the
moon effect is seen as one effect among many similar effects.
- But the following data can shows some specific effect of the moon motion on this
process.

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(4)
- 25920 mkm = 2.4 mkm x 10747 days
- Where
- 10747 days = Saturn Orbital Period
- 2.4 mkm = the moon motion distance per a day (before the displacement)
- The moon moves 25920 mkm during the period 10747 days. But we know that, all
planets (17.75 mkm daily) move a distance = 25920 mkm during the cycle 1461
days. That shows the moon effective role in the solar system motion. can the moon
move in behave of all the solar planets?! To answer we should know what's the
relationship between the period 10747 days and the moon motion.
o The moon displacements total during 29.53 days = 2598693 km
o Earth motion distance during a solar day = 2574720 km
o The difference is (1%), so we consider these 2 distances are equal
o We remember the rule (Equal distances causes different rates of time)
o i.e.
o because the distances are equal
o 1 Day Of Earth Motion = 29.53 Days Of The Moon Motion
o But
o 1 Day Of The Sun = 365.25 Days Of Earth Motion
o Based on that
o 1 Day Of The Sun = (365.25 x 29.53) of the moon motion
o 1 Day Of The Sun = 10747 Days Of The Moon Motion
o That means, Saturn orbital period (10747 days) is created to complete the
picture of the time rates cooperation. the data still gives surprises …
o The moon motion (2.4 mkm) during Saturn orbital period (10747 days)
passes a distance =25920 mkm which be passed by all planets during 1461
days and also be passed by the light beam in 1 solar day (86400 s).

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(5)
- 25920 mkm = 88000 km x 294545 days
- But
- 294545 = 4331 days x 68
- And
- 296545 mkm = 30589 days x 9.694 mkm
- Where
- 88000 km = The moon daily displacement
- 4331 days = Jupiter Orbital Period
- 30589 days = Uranus Orbital Period
- 9.694 mkm = The 3 Planets Velocities Total Per A Solar Day
- The data no (5) tries to know how the moon displacement (88000 km) can pass the
distance 25920 mkm
- We find that, the 3 planets velocities total be used as a motor inside this process
- The 3 planets velocities total depend on Uranus orbital period to perform the
required data. Why?
- Because Uranus and Jupiter are the 2 basic planets in the solar system, and the 3
inner planets are connected with Jupiter by their orbital circumferences, and here
they connect with Uranus by their velocities total to create a general unification
(Notice, Saturn is created after the moon creation).
Notice (1)
- 2.574 mkm x 1461 = 3762 mkm (where 3717 mkm = Jupiter Neptune 1.2%).
- Earth moves during (1461 days) a distance = Jupiter Neptune Distance
Notice (2)
- Light known velocity (0.3 mkm/s) travels during the period 14.61 seconds a
distance = 4.38 mkm = The Sun Circumference
- Light supposed velocity (1.16 mkm/s) uses the period 4.38 seconds to pass a
distance = 5.09 mkm (= 5.09 deg = The Moon Orbital Inclination)

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- Light (0.3 mkm/s) travels during the period 5.1 seconds a distance = 1.53 mkm
- Earth original orbital distance (153 mkm) is used here in a form (1.53 mkm). That
tells Earth orbital distance is defined by an effect of the moon orbital inclination
(5.1 degrees)

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8-3 The Sun Rate Of Time
I - Data
(a)
365.25 = (180/π) x 6.38
(b)
(365.25/9.18) = (5906 mkm /149.6 mkm) (error 0.8%)
(c)
(2.598 mkm /4.37 mkm) = 0.594
But
63.7 = 1.0725 x 59.4
II – Discussion
- The data tells that the equal distances helps to create the sun rate of time (1 day =
365.25 days). Let's remember these equal distances in following
- Earth (29.8 km/s) moves during a solar day (24 h) a distance = 2574720 km
- Pluto (4.7 km/s) moves during its day (153.3) a distance = 2593836 km
- The moon displacements total during (29.53 days) = 2598693 km
- The rate (6.38) between Earth and Pluto is used frequently in the sun rate of time
creation ( we remember that 1 h of Earth motion = 6.38 h of Pluto motion)
- Let's see the equations discussion in following …
Equation no. (a)
365.25 = (180/π) x 6.38
- The Rate (180/π) Is A Geometrical Rate, and it's found for geometrical necessity
- Equation no. (a) tells that, the period (365.25 day) is created depends on the rate of
time between Earth and Pluto motions.
-

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Equation no. (b)
(365.25/9.18) = (5906 mkm /149.6 mkm) (error 0.8%)
- Where
- 9.18 is the rate of time between Mercury and Pluto Motions (it's effected also by
Uranus motion)
- 5906 mkm = Pluto Orbital Distance
- 149.6mkm = Earth Orbital Distance
- Equation no. (b) tells that, the period (365.25 days) is created based on orbital
distances of Earth and Pluto.
- The data tells that, the proportionality of data between Earth and Pluto motions be
effective greatly on the solar system motions.
Equation no. (c)
(2.598 mkm /4.37 mkm) = 0.594
But
63.7 = 1.0725 x 59.4
- Equation no. (c) tells something very interesting
- From the 3 equal distances (Earth, Pluto and the moon), the moon distance be
selected.
- The moon displacements total during 29.53 days = 2598693 km
- 4.37 mkm = The Sun Circumference
- (2.598693 mkm/ 4.37 mkm) = 0.594 (1)
- That shows the moon motion effective on the sun data
- 63.7 = 1.0725 x 59.4
- Where
- 1.0725 is the rate effected on 40% of all solar system distances
- 63.7 degrees = The Sun Declination
- What does that mean?

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- The sun almost circles the Earth and gives the Earth the same one face always.
- This vision almost isn't accurate…
- The sun does some action (as vibration) toward and backward in a range of angle
(=63.7 degrees).
- The sun is found on a vertical axis on Earth because of that we see this vibrating
motion as a circular motion.
- Accurately the sun rotates around its axis with a percentage =63.7% and return
back.
- By that the sun rotation around its axis be = 63.7% of its Circumference
- This motion the sun does one each year
- That means, the sun moves during 1year a distance = (63.7% x 4.37 mkm) =
2598693 km (= the moon displacements total during 29.53 days)
- That means,
- The sun moves during 1 year a distance = Earth motion distance during 1 day (1%)
- Because of that
- 1 Day Of The Sun Motion = 365.25 Days Of Earth Motion
- Because
- (Equal Distances Creates A Different Rate Of Time)
- That means,
- The sun moves during 1year a distance = Earth motion for 1 day and the rate
between these 2 distances creates the rate of time (1 day of the sun =365.25 days
of Earth)

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Appendix No.1
The Solar System Equal Distances List
(A)
Why These Distances Are Equal?
(1)
Saturn Orbital Distance = Saturn Uranus Distance
= Mars Orbital Circumference
= Pluto Neptune Distance
= Pluto eccentricity Distance
= Neptune Orbital Distance/π
= Uranus Orbital Distance /2
= Mercury Jupiter Distance x 2
(2)
Mercury Neptune Distance = Saturn Pluto Distance
Jupiter Pluto Distance = Uranus Neptune Circumference
Earth Neptune Distance = Mercury Saturn Circumference (0.5%)
(3)
Jupiter Mercury Distance = 2 Mercury Orbital Circumference
Jupiter Venus Distance = Venus Orbital Circumference (1.5%)
Jupiter Earth Distance = Earth Orbital Circumference (1.2%)
(Earth and Jupiter at 2 different sides from the sun)
(4)
Jupiter Mercury Distance = Mars Orbital Distance x π (0.6%)
Jupiter Uranus Distance = Venus Jupiter Circumference (0.8%)
Pluto Orbital Distance = Earth Orbital Circumference x 2π
II- Discussion (A)
The previous distances form around 50% of all distances found in the solar system
(All orbital and internal distances)… Why These Distances Are Equal One Other?
We may notice that – the distances equality can be produced more easily by light
motion than the rigid body motion - for example – when we push a ball toward a wall
the ball after collision with the wall will return a distance (NOT) equal the original
one - because the collision causes to decrease the ball motion momentum – but the
light can be reflected at equal distances easily – means – equal distances can be
produced by light motion more easy than the Rigid Body Motion.

I do this research
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88
(B)
Why These Distances Are NOT Equal?
1. 0725
.
1
mkm
2.41
nce
Circumfere
Orbital
Moon
mkm
2.58
Motion
Daily
Earth
=
2. 1.0725
km)
(378500
radius
Eclipse
Solar
Total
km)
(406000
radius
orbital
Apogee
=
3. 0725
.
1
distance
Mercury
Jupiter
mkm
720.3
Distance
Orbital
Juppiter
mkm
6
.
778
= (Error 0.7%)
4. 1.0725
Distance
Venus
Jupiter
mkm
670
distance
Mercury
Jupiter
mkm
720.3
=
5. 1.0725
Distance
Earth
Jupiter
mkm
629
Distance
Venus
Jupiter
mkm
670
= (0.6%)
6. 1.0725
mkm)
(1325.3
Distance
Venus
Sarurn
mkm)
(1433.5
Distance
Orbital
Saturn
= (0.8%)
7. 1.0725
mkm)
(1205.6
Distance
Mars
Sarurn
mkm)
(1284
Distance
Earth
Saturn
= (0.7%)
8. 1.0725
mkm)
(2644
Distance
Mars
Uranus
mkm)
(2872.5
Distance
Orbital
Uranus
= (0.7%)
9. 1.0725
mkm)
(4495.1
Distance
Orbital
Neptune
mkm)
(4894
nce
Circumfere
Orbital
Jupiter
= (1.5 %)
(10)
Discussion (B)
The same rate (1.0725) is used for all equations (around 18 distances = 40% of all
solar system distances) – why?
Suppose the equal distances are produced by light reflection and that cause these
distances to be equal – as I have supposed in the previous point (A).
Now suppose– part of these equal distances – is passed through another frame relative
to us – so this part of distances will suffer from Lorentz Length Contraction Effect
which is seen in the rate 1.0725
(Another frame can be found in the solar system because we deal with light motion) –
This explanation can answer why some distances are equal and others are rated with
the same rate (1.0725) – it's simply a feature of light motion.
0725
.
1
T.
Axail
Earth
23.4
T.
Axail
Mars
25.2
T.
Axail
Mars
25.2
T.
Axail
Satrun
26.7
Tilt
Axail
Satrun
26.7
Tilt
Axail
Neptune
28.3
=
=
=

I do this research
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89
Appendix No.2 (Planet Gravity Equation)
Gerges Equation For Planet Gravity
I- Data
Table No. 1
Planet Equation Resulted Registered Error
The Sun (Earth/Sun diameters rate)2
(Sun Mass/
Earth Mass)* earth gravity
= (1/109)2
* 333000*9.8= 274
274 274 0
Moon (3.66)2
x (0.073 / 5.97) x 9.8 1.6 m/sec2
1.6 m/sec2
0
Mercury (2.61)2
x (0.23/5.97) x 9.8 3.7 m/sec2
3.7 m/sec2
0
Venus (1.0538)2
x 4.87 /5.97) x 9.8 8.9 m/sec2
8.9 m/sec2
0
Earth 9.8 9.8 9.8 0
Mars (1.878)2
x (0.642 / 5.97) x 9.8 3.7 m/sec2 3.7 m/sec2 0
Jupiter (0.0892)2
x (1898 / 5.97) x 9.8 24.7 m/sec2 23.1 m/sec2 6.9%
Saturn (0.10582)2
x (568/5.97) x 9.8 10.44 m/sec2 9 m/sec2 16%
Uranus (0.25)2
x (86.8/5.97) x 9.8 8.9 8.7 2.3%
Neptune (0.2575)2
x (102/ 5.97) x 9.8 11.1 m/sec2
11 m/sec2
0.9%
Pluto (5.337)2
(0.0131 / 5.97) x 9.8 0.6125 m/sec2
0.6 m/sec2
2%
II- Discussion
1. We can see that, the Equation is working sufficiently with all planets and even
the sun follows this same equation, Except With Jupiter And Saturn There
Are great Errors (6.9% and 16% respectively….because of the rate 1.0725?)
2. we need to observe and analyze deeply The Sun Equation in row No.1 of the
previous table, because this equation supports my claim that the sun is
originated from the same source from which the solar group is originated,
otherwise why the sun herself follows the same equation? That may support my
claim that, the sun rays is created depends on solar planets motions
accumulation….
3. that shows the sun is a result for the solar planets motions and not a reason
Please review
The Sun Gravity Concept is Unreal (Proves) http://vixra.org/abs/1903.0569
gravity
Earth
)
Mass
Earth
The
Mass
Planet
The
(
)
Diameter
Planet
The
Diameter
Earth
(
gravity
planet
The 2
×
×
=

I do this research
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90
References and Biography
The Solar Planets Motions Description (Revised)
https://www.researchgate.net/publication/352832717_The_Solar_Planets_Motions_Description_Revised
The Solar System Motion Analysis
https://www.researchgate.net/publication/352151822_The_Solar_System_Motion_Analysis
The Moon Orbital Motion Geometry (II)
https://www.academia.edu/45181646/The_Moon_Orbital_Motion_Geometry_II_
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944p=15209
Mr. Gerges Francis Tawdrous +201022532292
Physics Department- Physics Mathematics Faculty
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
Twitter https://twitter.com/GergesTawdrous1
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Researcherid https://publons.com/researcher/3510834/gerges-tawadrous/
ORCID https://orcid.org/0000-0002-1041-7147
Google https://scholar.google.com/citations?user=2Y4ZdTUAAAAJhl=en
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List of publications http://vixra.org/author/gerges_francis_tawdrous
Also https://www.slideshare.net/Gergesfrancis?utm_campaign=profiletrackingutm_medium=sssiteutm_source=ssslideview
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The Sun Gravity Concept is Incorrect (Newton was wrong)

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