The Solar System Doesn't Move By The Sun Mass Gravity (Revised) (2)

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
The Solar System Doesn't Move By The Sun Mass Gravity (Revised) (2)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –1st
September 2021
Abstract
Paper hypothesis
- The solar system is created out of one light beam its velocity (1.16 mkm/sec), and
moves depending on this light beam motion, And
- The light (1.16 mkm/sec) created the solar system distances in a network form.
The hypothesis explanation
- The existence proves of light supposed velocity (1.16 mkm/s) depend on the solar
system distances network proves.
- Because
- The solar system distances be created depending on each other by using the light
motion that caused the distances to be created in a network form, or based on one
geometrical design.
- Where (Distance = Energy). The distances creation process needed energy which
is provided by light motion. by that, light energy be registered in the created
distances, and by analysis of the distances values we can conclude that these
distances be created by energy provided by a light beam. And also we can discover
this light beam velocity be (1.16 mkm/s) because this light beam energy and
motion features are registered in the created distances.
Paper objective
- The paper proves the solar system distances network and based on this proof, the
paper proves the light supposed velocity (1.16 mkm/s) existence.

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Paper Conclusion
- Because the solar system be created out of light supposed velocity (=1.16mkm/s)
and the sun light velocity (= 0.3 mkm/s)
- Means, the light (0.3mkm/)be created as a side product from the original one (1.16
mkm/s)
- That proves
- The Sun Is Created After All Solar Planets Creation And Motion Which Disproves
Decisively Newton Theory Of The Sun Mass Gravity.
Please scan the figure (ORCID)

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Paper Contents
Subject Page No.
1- Introduction 4
2- Methodology 6
3-The Solar System Distances Be Created In A Network Form 8
3-1 Preface 9
3-2 Light Continuum Effect Description 12
3-3 Light Continuum Effect Proves 13
3-4 The Solar System Distances Network Description 22
3-5 Planets Motions Rates Of Time Effect On The Distances Distribution 36
3-6 Planets Motions Unification Points 40
3-7 The Solar System Distances Network Analysis 49
4- Light Beam (1.16 mkm/s) Existence Proves Discussion 52
4-1 Preface 53
4-2 The Light Beam (1.16 mkm/s) Proves Discussion 54
4-3 Jupiter Orbital Circumference Analysis 88
5- Mercury Jupiter Distance Analysis 106
5-1 The Main Idea 107
5-2 Venus Jupiter Distance Analysis 112
5-3 Jupiter and Pluto Motions For The Distance 720.7 mkm 120
5-4 Planets Motions Rates of Time 123
5-5 Planets Motions Interaction 128
5-6 Mars Motion For The Distance 720.7 mkm 143
6- Planets Unified General Motion 155
6-1 The Planets Unified General Motion Description 156
6-2 The Solar Planets Motions Are Complementary One Another 157
6-3 The Solar Planets Move An Unified Motion (A Team Motion) 162
7- The Sun Age Historical Proves 167
7-1 The Sun Circles The Earth 168
7-2 The Rate (1.0725) 169
7-3 The Sun Diameter Analysis 173
7-4 The Sun Rays Analysis 176
8- The Solar Planets Motions Depend On Different Rates of Time 181
8-1 Preface 182
8-2 Earth And Pluto Rate Of Time 183
8-3 Mercury Motion Rate Of Time 192
8-4 Saturn Motion Rate Of Time 195
8-5 Uranus And Jupiter Rate Of Time 197
9- The Solar Planets Motions Analysis 198
9-1 Preface 199
9- 2 The Equal Distances Method 200
9-3 The Inner And Outer Planets Motions Be Distinguished 206
Appendix No.1 The Solar System Equal Distances List 215
References and Biography 217

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1-Introdcution
- The paper hypothesis tells that
- The solar system is created out of one light beam its velocity (1.16 mkm/sec),
and moves depending on this light beam motion
- The hypothesis refers to a matter creation theory. Let's summarize it:
- The matter is created out of light
- The matter isn't separated from its light parent but the matter moves with the light
beam in one unified general motion.
- The matter and light motions use different rates of time.
- 1 second of light motion be equivalent to 1 solar day of planet motion.
- Or
- The energy of light motion for one second causes a planet to move for one solar
day.
- This is one more feature of the solar system motion which is strange from Newton
theory point of view.
- The rate (1 second = 1 solar day) is the general rate of light and matter motions.
- But
- The solar planets divide this rate among themselves into small rates. And by that,
the solar system works as a great clock. This clock input is an energy of light
motion for 1 second and its output is enough energy for a planet motion for a
period 1 solar day.
- The rates of time be distributed among the solar planets, for example
- 1 hour of Mercury motion = 1 second of light motion
- 1 hour of Mercury motion = 9.18 hours of Pluto motion
- 1 hour of Mercury motion = 24 hours of Jupiter motion
- 1 hour of Earth motion = 6.37 hours of Pluto motion

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- 1 hour of Earth motion = 29.53 hours of the moon motion
- We should discuss the planets motions rates of time in the paper discussion
- But
- This second feature of motion can be added to the first one (the distances network
form) and creates a vision concerning the solar system motion different from
Newton vision about it.
- The basic point is that, the planets motions analysis shows, the simple idea of
Newton Theory of The Sun Mass Gravity is an imaginary one, because the solar
system is so complex machine.
- I want to say,
- Not only the solar system distances are in network form or the planets motions
depend on different rates of time, but there are many other features in the solar
system disproves the simple idea of the sun mass gravity by Newton
- The basic proof against Newton theory should be the sun age, because, the planets
motions data analysis proves that the sun is created after all planets creation and
motion. this fact disproves Newton theory of The Sun Mass Gravity Decisively.

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2-Methodology
- I use the planets data analysis to discover the solar planets creation and motion.
- This method is so useful because it creates comparisons between planets motions
data and the theories which try to explain this planets motions data. Also the
method creates comparisons between planets motions data with each other.
- Let's use one example for explanation in following
- Example no. (1)
- Newton Theory of the planet motion depends on the sun mass gravity supposes
that the planet motion be independent from all other planets motions…
- We provide Planets data for a comparison. Then let's ask
- Can planets motions and distances be independent from one another? let's answer
in following
- Saturn Orbital Distance = 1433 km = Saturn Uranus Distance
= Mars Orbital Circumference
= Pluto Neptune Distance (error 1.5%)
= Pluto eccentricity Distance (error 1.5%)
= Neptune Orbital Distance/π
= Uranus Orbital Distance /2
= Mercury Jupiter Distance x 2
- If the planets motions be independent from one another how these distances be
equal?!
- Appendix no. (1) of this paper provides a complete list for the equal distances in
the solar system and proves that 50% of all distances in the solar system be equal
one another! why?
- Appendix no. 1 also provides another list shows that 40% of all distances in the
solar system be rated with one another by the same one rate (1.0725)!
- Can we ask why?
- It's a different vision
- Newton told us something has no proof in planets data…

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- Planet orbital and internal distances can't be independent from any other distances..
- The distances be created in a group and not individually. They are created based
on one geometrical design and not as independent distances from one another
- The distances creation in a network form is the first discussion in this paper, in
which we should prove by different data that the planets distances can't be created
independent from one another but dependent one each other and based on one
geometrical design.
- A direct proof for the network claim is the following data
- 50% of all distances in the solar system be equal one another and
- 40% of all distances in the solar system be rated with one another with the same
one rate (1.0725).
- This data we should discuss deeply because it proves directly that, the planets
distances be created based on one geometrical design and in network form. The
planets distances be created as a group based on a geometrical design where they
can't be created independently.

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3-The Solar System Distances Be Created In A Network Form
3-1 Preface
3-2 Light Continuum Effect Description
3-3 Light Continuum Effect Proves
3-4 The Solar System Distances Network Description
3-5 Planets Motions Rates Of Time Effect On The Distances Distribution
3-6 Planets Motions Unification Points
3-7 The Solar System Distances Network Analysis

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3-1 Preface
- The Solar Planets data analysis shows that, The Planets Distances Be Created In A
Network Form.
- That means,
- The solar system distances are considered as one geometrical design or one
geometrical system. There's no one distance defined as independent or created out
of this one geometrical design.
- Let's suppose, this geometrical design be a square. So all dimensions in this square
be defined geometrically based on this square data. means no one dimension can
be created independent from this square data because all of them are parts in the
same one geometrical design.
- Imagine we have a triangle has 2 angles (60 degrees and 80 degrees) what's the
third one? (40 degrees). Can this angle be any thing else than (40 degrees)? NO it's
obligatory value defined by the geometrical basic rules
- Similar to that, the solar system distances be created based on one geometrical
design. But
- By using this vision we will have surprises. Because this vision tells (for example)
Venus Jupiter Distance be= 671 mkm because Earth Jupiter distance = 629 mkm
- That creates another vision
- While we consider Venus is a planet and Earth is another planet and they move
independently from one another. We are astonished now with this fact that, their
distances to Jupiter be defined based on one another! why? and How?
- Before to answer these questions…
- The fact is proved strongly by the solar system distances analysis regardless any
explanation.
- I want to say that, there are 2 points here independent from one another
- (1st
Point) The Solar System Distances Network Discovery
- (2nd
Point) The Distances Network Explanation

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- Because
- The distances analysis proves clearly that, they are parts of one network or one
geometrical design, regardless any explanation…
- The point discussion provides analysis for the solar system distances proves
strongly that these distances are parts in one network or one geometrical design
- Based on this proof we should ask how these distances be created based on one
geometrical design or in a network form?
- Because
- These distances are created by light motion.
- The solar system be built depending on one light beam its velocity (1.16 mkm/s)
and this light beam (almost later) produced the light known velocity (0.3 mkm/s)
as its product.
- The solar system distances be created depends on these 2 light beam velocities.
- How Can We Know That?
- Light creates Planets and their distances
- Because
- Matter is created of energy and space (distance) is created of energy. Because of
that light motion provides the required energy to create the planet and its distance
- As a result
- This light motion features be registered in this planet and its distance data
- That's why I can claim that, A Light Beam Its Velocity =1.16 mkm/s Be Found
In The Solar System, because this light beam motion features are registered in the
solar system distances clearly
- How Does Light Motion Create The Distances Network?
- The light supposed velocity (1.16 mkm/s) moves a distance and uses it as a period
of time to move another distance and uses the second one to move a third one. by
that, the distances be created in a network form and depends on one geometrical
design.

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- This strategy be used also by light known velocity (0.3 mkm/sec) and sometimes
even be used by planets motions!
- As a result, The Solar System Distances Be Created In A Network Form
- What I try to do here is that, to persuade the respectful reader to look at the solar
system distances as total distances and not as individual distances.
- For example, 50% of all distances in the solar system are equal one another
(Appendix no.1 provides the list of these distances). Why these distances are
equal? Here we don't deal with individual distances. We deal with One Reason
caused 50% of all distances to be equal one another. that means we deal with one
machine where one reason can effect on many parts of this machine because these
parts are connected with each other and depend on one another.
- Notice
- Light motion uses the rate (1 mkm = 1 second) to use the distances as periods of
time… and
- Planet motions uses the rate (1 mkm = 1 day) to use the distances as periods of
time

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3-2 Light Continuum Effect Description
- Light motion in nature is different from planets motions (or from rigid body
motion), Basically because light moves in a continuum. This feature is discovered
in planets motions by analysis the solar system distances and this feature is the
reason why the distance be created in a network form.
- Matter Creation Theory provides explanation for planets motions facts
- The theory tells that
- Matter is created out of light, but the born matter doesn't separate its parent light
beam. On the contrary they move together in one unified motion by using different
rates of time between matter and light motions.
- (1 Second Of Light Motion Be = 1 Solar Day Of Planet Motion)
- This rule controls light and matter unified motion
- Light motion uses the distances as periods of time by the rate (1 mkm = 1 second)
and planet motion uses (1 mkm=1 day).
- The distances using as periods of time has a great effect on the distances
distribution as we should discuss in this point.
- Let's summarize the basic points we need to prove in the discussion
(1) Light motion causes a continuous effect through the distances.
(2) Light motion uses distances as periods of time and by that the distances be
created and distributed in a network and based on one geometrical design.
(3) The motions rates of time effect on the distances creation and distribution.
- Light continuous effect should be proved in point (3-3)
- The distances network form should be proved in point (3-4)
- The rates of time effect on the distances distribution be proved in point (3-5)

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3-3 Light Continuum Effect Proves
- The using of the rate (1.0725) shows clearly the continuum effect in the solar
system distances, we refer to it here before the point proves discussion.
I-Data
Data Group No. (A)
Why These Distances Are Equal?
(1)
Saturn Orbital Distance = Saturn Uranus Distance
= Mars Orbital Circumference
= Pluto Neptune Distance (error 1.5%)
= Pluto eccentricity Distance (error 1.5%)
= Neptune Orbital Distance/π
= Uranus Orbital Distance /2
= Mercury Jupiter Distance x 2
(2)
Mercury Neptune Distance = Saturn Pluto Distance
Jupiter Pluto Distance = Uranus Neptune Circumference
Earth Neptune Distance = Mercury Saturn Circumference (0.5%)
(3)
Jupiter Mercury Distance = 2 Mercury Orbital Circumference
Jupiter Venus Distance = Venus Orbital Circumference (1.5%)
Jupiter Earth Distance = Earth Orbital Circumference (1.2%)
(Earth and Jupiter at 2 different sides from the sun)
(4)
Jupiter Mercury Distance = Mars Orbital Distance x π (0.6%)
Jupiter Uranus Distance = Venus Jupiter Circumference (0.8%)
Pluto Orbital Distance = Earth Orbital Circumference x 2π

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Data Group No. (B
Why These Distances Are NOT Equal?
1. 0725
.
1
mkm
2.41
nce
Circumfere
Orbital
Moon
mkm
2.58
Motion
Daily
Earth
=
2. 1.0725
km)
(378500
radius
Eclipse
Solar
Total
km)
(406000
radius
orbital
Apogee
=
3. 0725
.
1
distance
Mercury
Jupiter
mkm
720.3
Distance
Orbital
Juppiter
mkm
6
.
778
= (Error 0.7%)
4. 1.0725
Distance
Venus
Jupiter
mkm
670
distance
Mercury
Jupiter
mkm
720.3
=
5. 1.0725
Distance
Earth
Jupiter
mkm
629
Distance
Venus
Jupiter
mkm
670
= (0.6%)
6. 1.0725
mkm)
(1325.3
Distance
Venus
Sarurn
mkm)
(1433.5
Distance
Orbital
Saturn
= (0.8%)
7. 1.0725
mkm)
(1205.6
Distance
Mars
Sarurn
mkm)
(1284
Distance
Earth
Saturn
= (0.7%)
8. 1.0725
mkm)
(2644
Distance
Mars
Uranus
mkm)
(2872.5
Distance
Orbital
Uranus
= (0.7%)
9. 1.0725
mkm)
(4495.1
Distance
Orbital
Neptune
mkm)
(4864
= (0.5 %)
(10)
0725
.
1
T.
Axail
Earth
23.4
T.
Axail
Mars
25.2
T.
Axail
Mars
25.2
T.
Axail
Satrun
26.7
Tilt
Axail
Satrun
26.7
Tilt
Axail
Neptune
28.3
=
=
=

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II- Discussion
- The previous data we have seen frequently before, so let’s summarize the idea in
following…
- The equal distances in group no. (A) are result because of the solar planets motions
system. where the solar planets motions depends on The equal distances method
- The equal distances method be discussed in the point no. (9-2)
- The Equal Distances Method Using causes the solar system distances to be created
equal one another. As a result 50% of all distances in the solar system be equal one
another (which is seen in Data group No. A)
- Then
- Let's ask
- Why the distances in group no. (B) aren't equal one another but rated with the
same one rate (1.0725)?
- The rate (1.0725) effects on 40% of all distances in the solar system, that means,
the effect of the rate (1.0725) is a fact regardless any reason for it.
- The observation we need to notice is that, the rate (1.0725) effects on 40% of all
distances in the solar system equally by the same force. why?
- It's A Continuum Feature
- The effect continues through the distances and nothing stop it. it's a feature proves
light motion found behind planets motions.
- The data proves that, a light beam must be found in motion behind planet motion.
and that means, the solar planets motions be accompanying with a light beam
motion.

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The Light Continuum Effect Proves Discussion
I- Data
Group No. (I)
1.16 mkm/sec x 671 sec = 778.6 mkm
1.16 mkm/sec x 778.6 sec = 903 mkm
1.16 mkm/sec x 903 sec x 2 = 2094 mkm
1.16 mkm/sec x 2094 sec x 2 = 4847 mkm
1.16 mkm/sec x 4847 sec = 5678.1 mkm (error 1%)
1.16 mkm/sec x 5678.1 sec = 6585.39 mkm
1.16 mkm/sec x 6585.39 sec = 7586 mkm
1.16 mkm/sec x 7586 sec = 8800 mkm
1.16 mkm/sec x 8800 sec = 32200 mkm (error 0.4%)
Group No. (II)
0.3 mkm/sec x 8554.3 sec x 2 = 5127 mkm (error 0.8%)
0.3 mkm/sec x 5127 sec = 763 mkm x 2
0.3 mkm/sec x 763 sec = 227.9 mkm (error 0.4)
Group No. (III) (A)
0.3 mkm/sec x 18048 sec = 2 x 2722.9 mkm (error 0.6 %)
0.3 mkm/sec x 2 x 2722.9 sec = 1622.7 mkm (error 0.7%)
0.3 mkm/sec x 1622.7 sec = 243 mkm x 2
0.3 mkm/sec x 243 sec x 2 = 146 mkm
Group No. (III) (B)
1.16 mkm/sec x 146 sec = 170 mkm
1.16 mkm/sec x 170 sec = 196.5 mkm
1.16 mkm/sec x 196.5 sec = 227.9 mkm

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1.16 mkm/sec x 227.9 sec = 264.4 mkm
1.16 mkm/sec x 264.4 sec = 306.6 mkm (306.6 x 0.3 = 91.7 mkm)
1.16 mkm/sec x 306.6 sec = 354.39 mkm
1.16 mkm/sec x 354.39 sec = 412.6 mkm
1.16 mkm/sec x 354.39 sec = 411 mkm
1.16 mkm/sec x 411 sec = 476.9 mkm
1.16 mkm/sec x 476.9 sec = 550.7 mkm (error 0.5%)

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II- Discussion
Group No. (I)
1.16 mkm/sec x 671 sec = 778.6 mkm
1.16 mkm/sec x 778.6 sec = 903 mkm
1.16 mkm/sec x 903 sec x 2 = 2094 mkm
1.16 mkm/sec x 2094 sec x 2 = 4847 mkm
1.16 mkm/sec x 5678.1 sec = 6585.36 mkm
1.16 mkm/sec x 6585.39 sec = 7586 mkm
1.16 mkm/sec x 7586 sec = 8800 mkm
1.16 mkm/sec x 8800 sec = 32200 mkm/π (error 0.4%)
- Where
- 671 mkm = Jupiter Venus Distance
- 778.6 mkm = Jupiter Orbital Distance
- 2094 mkm = Jupiter Uranus Distance
- 4847 mkm = Jupiter Orbital Circumference (error 1%)
- 5678.1 mkm = Mars Pluto Distance
- 32200 mkm = (37100 mkm Pluto orbital circumference) – (4900 mkm Jupiter
Orbital Circumference)
- 6585.36 days = Saros Cycle
- The data shows the idea clearly. The distances be created based on one another by
using the motion of light supposed velocity (1.16 mkm/s)
- As a result the distances be created based on one another creating one geometrical
design and form a network of distances
- The point we need to notice is that,
- The continuum feature be proved in the data clearly can't be performed by any
planet motion. It's a light beam motion found behind planets motions.

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Group No. (II)
0.3 mkm/sec x 8554.3 sec x 2 = 5127 mkm (error 0.8%)
0.3 mkm/sec x 5127 sec = 763 mkm x 2
0.3 mkm/sec x 763 sec = 227.9 mkm (error 0.4)
- Where
- 28255 mkm = Neptune Orbital Circumference
- 8554.3 mkm = π x 2722.9 mkm (Earth Uranus Distance)
- 5127 mkm = Jupiter Pluto Distance
- 227.9 mkm = Mars Orbital Distance
- Light known velocity (0.3 mkm/s) uses this same method. And creates the
distances based on one another in a network form
- For us, the good news is that, the motion be in a continuum form which can't be
performed by any planet motion. it's a light beam motion found clearly behind the
planets motions
- Newton Simple Theory is incorrect because the solar system is so complex
machine. No planet moves by the sun mass gravity instead the planets are ships
found on a sea and the sea is light motions network
- The planets motions data analysis shows clearly that they are created based on a
continuum effect of motion which can be perform only by a light motion.

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Group No. (III) (A)
0.3 mkm/sec x 18048 sec = 2 x 2722.9 mkm (error 0.6 %)
0.3 mkm/sec x 2 x 2722.9 sec = 1622.7 mkm (error 0.7%)
0.3 mkm/sec x 1622.7 sec = 243 mkm x 2
0.3 mkm/sec x 243 sec x 2 = 146 mkm
- Where
- 18048 mkm = Uranus Orbital Circumference
- 2722.9 mkm = Uranus Earth Distance
- 1622.7 mkm =Uranus Neptune Distance
- 243 days = Venus rotation period
- The data shows clearly the continuum feature. The light known velocity (0.3
mkm/s) uses the same method to create the distances in network form.
- The distances can be seen by us as periods of time simply because it's a light
motion. as we have seen with Saros cycle in the previous data. let's provide one
more example in following
- Example
- Light known velocity (0.3 mkm/s) travels during a solar day (86400 s) a distance =
25920 mkm
- But
- We see this distance (25920 mkm) in a period form because it's a light motion.
- Where
- (25920 years =The Precession Cycle)

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Group No. (III) (B)
1.16 mkm/sec x 170 sec = 196.5 mkm
1.16 mkm/sec x 196.5 sec = 227.9 mkm
1.16 mkm/sec x 227.9 sec = 264.4 mkm
1.16 mkm/sec x 264.4 sec = 306.6 mkm (306.6 x 0.3 = 91.7 mkm)
1.16 mkm/sec x 306.6 sec = 354.36 mkm
1.16 mkm/sec x 354.39 sec = 412.6 mkm
1.16 mkm/sec x 354.39 sec = 411 mkm
1.16 mkm/sec x 411 sec = 476.9 mkm
1.16 mkm/sec x 476.9 sec = 550.7 mkm (error 0.5%)
- Where
- 170 mkm = Mars Mercury Distance
- 227.9 mkm = Mars Orbital Distance
- 354.36 days = The Moon Synodic Year (29.53 days x 12)
- 550.7 mkm = Mars Jupiter Distance
- 91.7 mkm = Earth Mercury Distance
- The data importance is the period (146 sec) because Data Group (III) (A) ended
with the value (146 mkm) which is used in Data Group (III) (B) as (146 sec)
- The data shows clearly the continuum feature
- Also
- The data shows the unification of motion between light supposed velocity (1.16
mkm/s) and light known velocity (0.3 mkm/s)
- The data proves strongly the paper hypothesis
- Light beam moves in accompanying the planets motions and the planets motions
depend on this light beam motion.

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3-4 The Solar System Distances Network Description
I-Data
(1)
1.16 mkm/s x 500 s = 580 mkm
1.16 mkm/s x 580 s = 671 mkm (Venus Jupiter Distance)
1.16 mkm/s x 671 s = 778.6 mkm (Jupiter Orbital Distance)
1.16 mkm/s x 629 s = 720.7 mkm (error 1%) (Mercury Jupiter Distance)
1.16 mkm/s x 542 s = 629 mkm (Earth Jupiter Distance)
1.16 mkm/s x 5127 s = 5906 mkm (error 0.7%) (Pluto Orbital Distance)
(2)
1.16 mkm/s x 778.6 s x 2= 1806 mkm
1.16 mkm/s x 1806 s = 2094 mkm (Jupiter Uranus Distance)
1.16 mkm/s x 2094 s = 2 x 1205 mkm (error 0.8%) (Mars Saturn Distance)
(3)
1.16 mkm/s x 170 s = 197.2 mkm
1.16 mkm/s x 197.2 s = 227.9 mkm (error 0.4%) (Mars Orbital Distance)
0.3 mkm/ x 193 s = 57.9 (Mercury Orbital Distance)
(4)
1.16 mkm per second x 2 x 86400 seconds =2 x 100733 mkm = (37100 mkm – 4900
mkm) x 2π = 28255 mkm + 2 x 86400 mkm
(5)
1.16 mkm/s x 1980 s = 2296.8 mkm
1.16 mkm/s x 2296.8 s = 2644.6 mkm (error 0.7%) (Mars Uranus Distance)
1.16 mkm/s x 2644.5 s = 3033.5 mkm (error 1%) (Uranus Pluto Distance)

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(6)
0.3 mkm/s x 1980 seconds = 594 mkm
(7)
1.16 mkm/s x 361 s = 419 mkm
1.16 mkm/s x 419 seconds = 486 mkm = 243 mkm x 2
1.16 mkm/s x 282 seconds = 327.6 mkm
1.16 mkm/s x 327.6 seconds = 380 mkm
1.16 mkm/s x 440.8 seconds = 511.4 mkm
(8)

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II-Discussion
- I try to show that, the solar system distances are created as one group and not as
individual distances.
- Many features of the solar system distances support this conclusion. Not only the
data equations which we will discuss here (8 equations). But also the equal
distances (50% of all distances) and the rated distances (40% of all distances), this
data refers to that we deal with one geometrical design. No a single proof suggests
any distance can be considered as individual distance or be created independently
- It's one machine which is proved clearly and strongly
- Because
- One geometrical design be found behind this data,
- Equation no. (4) provides very clear proof for the distances distribution based on
one design. This equation is the solar system main energy distribution equation.
- In following we discuss the data equations one by one to see how these distances
be created by light supposed velocity (1.16 mkm/sec) motion.
- But
- The paper hypothesis tells that,
- The solar system be created out of one light beam its velocity =1.16 mkm/sec,
- Where
- The sun rays velocity =300000 km,
- We conclude that, the light known velocity (0.3 mkm/sec) be crated as a side
product from the original one (1.16 mkm/sec) and the proves the claim (the sun be
created after all planets creation and motion)
- That means,
- We have 2 light beams velocities in the solar system, one is ancient and one is
modern. That means, the ancient and modern distance can be built by light
supposed velocity (1.16 mkm/sec) but light known velocity (0.3 mkm/sec) created
the modern distances only.

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Equation no. (1)
1.16 mkm/s x 500 s = 580 mkm
1.16 mkm/s x 580 s = 671 mkm (Venus Jupiter Distance)
1.16 mkm/s x 671 s = 778.6 mkm (Jupiter Orbital Distance)
1.16 mkm/s x 629 s = 720.7 mkm (error 1%) (Mercury Jupiter Distance)
1.16 mkm/s x 542 s = 629 mkm (Earth Jupiter Distance)
1.16 mkm/s x 5127 s = 5906 mkm (error 0.7%) (Pluto Orbital Distance)
- Equation no. (1) shows one series of the distances be created by light motion based
on each other.
- Jupiter distances specifically are so distinguish and shows this fact clearly and
strongly… let's summarize the data in following
- Light supposed velocity (1.16 mkm/s) uses the period (500 seconds) to pass a
distance =580 mkm and uses this distance (580 mkm) as a period for time (580 s)
to pass a distance = 671 mkm (Venus Jupiter distance) and then uses this distance
as a period of time (671 s) to pass a distance = 778.6 mkm (Jupiter orbital
distance)
- Also, Light supposed velocity (1.16 mkm/sec) uses the distance between earth and
Jupiter (629 mkm) as a period of time (629 s) to pas a distance = 720.7 mkm (error
1%) (= Mercury Jupiter Distance)
- Also, Light supposed velocity (1.16 mkm/sec) uses the distance between Jupiter
and Pluto (5127 mkm) as a period of time (5127 s) to pass a distance = 5906 mkm
(= Pluto Orbital Distance)
- The distances are created in a network form depends on one another and based on
one geometrical design.
- If this explanation is wrong one, we have to explain why all distances be rated with
the rate (1.16) as seen clearly.
- Notice, light known velocity (0.3 mkm/s) needs 500 seconds to pass Earth orbital
distance (149.6 mkm)

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More Data
- 778.6 mkm (Jupiter Orbital Distance) = 1.0725 x 720.7 mkm (error 1%)
- 720.7 mkm (Jupiter Mercury Distance) = 1.0725 x 671 mkm
- 671 mkm (Jupiter Venus Distance) = 1.0725 x 629 mkm
- 629 mkm (Jupiter Earth Distance) = 1.0725 x 580 mkm (error 1%)
- This data also proves, these distances be created based on a geometrical design.
Because the same distances be rated on (1.0725 and 1.16).
- Please remember 1.16 =(1.077)2

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Equation no. (2)
1.16 mkm/s x 778.6 s x 2= 1806 mkm
1.16 mkm/s x 1806 s = 2094 mkm (Jupiter Uranus Distance)
1.16 mkm/s x 2094 s = 2 x 1205 mkm (error 0.8%) (Mars Saturn Distance)
- Equation no. (2) completes another part of this same series which we have
discussed in equation no. (1)
- Light supposed velocity (1.16 mkm/s) uses the distance 778.6 mkm (Jupiter orbital
distance) as a period of time (778.6 s x 2) to pass a distance = 1806 mkm
- And then
- Light supposed velocity (1.16 mkm/s) uses the produced distance 1806 mkm as a
period of time (1806s) to pass a distance =2094 mkm (= Jupiter Uranus Distance)
- Then
- Light supposed velocity (1.16 mkm/s) uses the distance 2094 mkm as a period of
time (2094s) to pass a distance = (2 x 1205 mkm) where (1205 mkm = Mars
Saturn Distance).
- Equation no.(2) started with the distance (778.6 mkm =Jupiter orbital distance) and
reach to (1205 mkm = mars Saturn distance).
- That makes the 2 equations consist one series

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Equation no. (3)
1.16 mkm/s x 170 s = 197.2 mkm
1.16 mkm/s x 197.2 s = 227.9 mkm (error 0.4%) (Mars Orbital Distance)
0.3 mkm/ x 193 s = 57.9 (Mercury Orbital Distance)
- Where
- 170 mkm = Mercury Mars Distance
- Equation no. (3) tells
- Light supposed velocity (1.16 mkm/s) travels during (170 seconds) a distance =
197.2 mkm) and then
- Light supposed velocity (1.16 mkm/s) uses the distance (197.2 mkm) as a period
of time (197.2 seconds) to pass a distance = 227.9 mkm(= Mars orbital distance)
- That means,
- Mars orbital distance depends on a period (=197.2 seconds) by light supposed
velocity (1.16 mkm/s) motion.
- But
- Mercury orbital distance (57.9mkm) depends on a period (193 seconds) by using
light known velocity (0.3 mkm/s) motion.
- The period (196.5 seconds) is used almost for Mercury, Mars and Jupiter Motions
as we discuss in point no. (5-5) of this paper. And because the 3 planets use equal
periods of time that cause their motions to be integrated in one unified general
motion.
- Equation no. (3) shows that, there's a reason behind the motions data consistency
between Mercury and Mars (and Jupiter also). We should prove this consistency of
motion in point no. (6) (Planets Unified General Motion)

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- Equation no. (4)
1.16 mkm per second x (2) x 86400 seconds =(2) x 100733 mkm = (37100 mkm –
4900 mkm) x 2π = 28255 mkm + (2) x 86400 mkm
- This equation is the main equation of the solar system energy distribution. And this
is the main equation in my papers. Let's summarize it shortly in following
- (Part no. 1)
- 1.16 mkm per second x 2 x 86400 seconds
- Light supposed velocity (1.16 mkm/s) travels during one solar day (86400 s)a
distance = 100733 mkm= The Solar Planets Orbital Circumferences Total
- The equation shows a double value is used (2 x 100733 mkm), means
- The equation shows energy = 2 x The Solar Planets Orbital Circumferences Total
- Why does light supposed velocity (1.16 mkm/s) motion during a day (86400s)
pass a distance = The Solar Planets Orbital Circumferences Total?
- We can answer that,
- The light supposed velocity (1.16 mkm/s) depends on the solar day as its basic
period of time and
- The solar planets orbital circumferences be built based on a light beam motion its
velocity (1.16 mkm/s) during one solar day.
- Means,
- It's not by chance that, The Solar Planets Orbital Circumferences Total = (100733
mkm) but because the total be created by light motion for 1 solar day.
- (Part no. 3)
- (37100 mkm – 4900 mkm) x 2π
- 37100 mkm = Pluto Orbital Circumference
- 4900 mkm = Jupiter Orbital Circumference
- Part no. (3) shows why the equation no. (4) be a real one and not imaginary
equation. Because the difference in distance between Pluto orbital circumference
(37100 mkm) and Jupiter orbital circumference (4900 mkm) creates this equation.

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- We know that,
- The rate (2π) distinguish between light motion and planet motion. and the
difference (37100 mkm – 4900 mkm) refers to the planets motions by that the
value (100733 mkm x 2) is a real one
- (Part no. 4)
- 28255 mkm + 2 x 86400 mkm
- Where
- 28255 mkm =Neptune Orbital Circumference
- This part of equation is the reason of its importance…
- The equation other parts can work without the rate (2) which is used frequently.
The only part needs this rate is this part no. (4) for Neptune orbital circumference.
The equation tells the total energy (2 x 100733 mkm) reach to Neptune and
Neptune seized 14% of it and sent the rest energy into 2 trajectories of energy each
one has 86400 mkm
- And where these 2 trajectories be sent? The distance 86400 mkm tells us
- 2 x 86400 mkm = (28255 mkm – 680 mkm) x 2π (Venus Equation)
- The energy is sent to Venus and Earth in 2 equal trajectories because the error
between the 2 planets equations be 1% at max.
- Equation no. (4) shows that,
- The distances between Jupiter and Pluto on one side and the distances from
Neptune to Venus with Earth on the other side, All these distances be created and
distributed based on One Geometrical Design which is seen in the equation no.
(4) clearly.
- That shows the equation importance because
- The distances be created in comparison with one another and by that their
distribution proves their dependency on one another clearly. We deal with a
geometrical system and not with individual or independent distances from one
another. (This equation is discussed in more details in point no. 4-2)

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Equation no. (5)
1.16 mkm/s x 1980 s = 2296.8 mkm
1.16 mkm/s x 2296.8 s = 2644.6 mkm (error 0.7%) (Mars Uranus Distance)
1.16 mkm/s x 2644.5 s = 3033.5 mkm (error 1%) (Uranus Pluto Distance)
- Where
- 1980 mkm = the orbital circumferences total of (Mercury +Venus + Earth)
- Equation no. (5) shows another series
- Light supposed velocity (1.16 mkm/s) uses the distance (1980 mkm) as a period of
time (1980 seconds) to pass a distance = 2296.8 mkm and then
of time (2296.8 seconds) to pass a distance =2644.6 mkm (Mars Uranus Distance)
- And Then
of time (2644.6 seconds) to pass a distance =3033.5 mkm (Uranus Pluto Distance)
- The data shows more distances be created in a network form by using light
supposed velocity (1.16 mkm/s) motion.
- But
- This analysis for the distances is so limited because we should explain why the
produced distance depended on the input distance…
- That needs more analysis for this data…
- Here we deal with the solar system distances as a group or a network. We don't
deal with each distance in its details, instead we deal with the whole distances as
one group to prove the network theory.
- But
- The detailed analysis will explain why Uranus Pluto distance be produced by using
Mars Uranus distance. In many detailed discussions we should answer similar
questions.

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Equation no. (6)
- Where
- 1980 mkm = the orbital circumferences total of (Mercury + Venus + Earth)
- Equation no. (6) shows one more series of the distances
- Light known velocity (0.3 mkm/s) uses the distance (1980 mkm) as a period of
time (1980 seconds) to pass a distance = 594 mkm
- Then
- (687 days = Mars orbital period where (689/687) = (361/360)
- Then
- Light supposed velocity (1.16 mkm/s) uses the period (687 seconds) to pass a
distance = 800 mkm
- Then
- The distance 929 mkm = Earth Jupiter distance when the 2 planets be on the sun 2
different sides.

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Equation no. (7)
1.16 mkm/s x 361 s = 419 mkm
1.16 mkm/s x 419 seconds = 486 mkm = 243 mkm x 2
- Light known velocity (0.3mkm/s) needs 361 seconds to pass Venus orbital
distance (108.2 mkm), and
- Mercury orbital circumference =360 mkm
- We can use any of the 2 values to start the series of the equation no.(7).
- Light supposed velocity (1.16 mkm/s) travels during (361sec) a distance = 419
mkm and then
time (419 sec) to pass a distance = 2 x 243 mkm
- (Where 243 days = Venus Rotation Period, and the motion rate 1mkm =1 day
for a planet motion but 1 mkm = 1 second for light motion, so 243 days can be
used by light motion as 243 seconds)
time (243 sec) to pass a distance = 282 mkm.
time (282 sec) to pass a distance = 327.6 mkm (where 327.6 days = the moon
sidereal year. the value be used by light motion as 327.6 seconds)

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of time (327.6 sec) to pass a distance = 380 mkm. And by one more motion light
passes 440.8 mkm and
of time (440.8 sec) to pass a distance = 511.3 mkm. (where 511.1 degrees = the
solar planets axial tilts total)
of time (511.3 sec) to pass a distance = 593 mkm. (the distance 594 mkm be used
in equation no. (6) that connects equation no. (6) with equation no. (7) and creates
from them one continuous series.
- Notice (1)
- Light known velocity (0.3 mkm/s) needs (1397 seconds) to pass 419 mkm
- But
- Light supposed velocity (1.16 mkm/s) travels during (1205 seconds) a distance =
1397 mkm (1205 mkm = Mars Saturn Distance)
- I try to show that, the network is connected depends on the light 2 velocities
- But
- Light known velocity (0.3 mkm/s) needs (1205 seconds) to pass 361 mkm
- Notice (2)
- Mercury moves during its rotation period (1407.6 h) a distance =243 mkm (-1%)
- Mercury moves during Venus day period (2802 h) a distance =243 mkm
- Means, the distance 243 mkm be used geometrically by planets motions also not
only by light motions. where we see it as (243 days = Venus rotation period)

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Equation no. (8)
- Where
- 4224 seconds be used based mercury day period (4222.6 hours)
- 5678.1 mkm = Mars Pluto Distance
- Equation no.(8) tells
- Light supposed velocity (1.16 mkm/s) uses the period (4224 mkm) to pass a
distance =4900 mkm (=Jupiter Orbital Circumference)
- Then
time (4900 seconds) to pass a distance = 5678.1 mkm (= Mars Pluto Distance)
- Equation no.(8) shows more distances be created in the same network form, by
using light supposed velocity (1.16 mkm/s) motion

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3-5 Planets Motions Rates Of Time Effect On The Distances Distribution
(1st
Point) The Solar Planets Motions Rates Of Time
- The paper hypothesis tells that, the solar system is created and moving based on
energy of one light beam its velocity (1.16 mkm/s),
- Where
- The matter is created out of light and doesn't separate from its parent light but the
matter and light move together one unified motion. logically matter and light
motions use different rates of time
- (1 Second Of Light Motion Be = 1 Solar Day Of Planet Motion)
- This is the basic rate of time in the solar system motion…. but the solar planets
divide this rate among their motions and by that they use small rates of time for
their motions to unify these small rates into the basic rate of time, As a result
- 1 Hour Of Mercury Motion = 1 second Of Light Motion,
- But
- 1 Hour Of Mercury Motion = 9.18 Hours Of Pluto Motion,
- 1 Hour Of Earth Motion = 6.37 Hours Of Pluto Motion,
- 1 Hour Of Pluto Motion = 4.61 Hours Of Pluto Motion,
- These rates of time should be discussed in this paper in point No.(8)
- Here
- We need to know if these rates of time can effect on the solar system distances
distribution. Let's use the rate (4.61) as example to see if any effect can be
produced on the distances distribution resulting of planets motions rate of time
- The idea here is that,
- Light uses the distances as periods of time by the rate (1 mkm = 1 second), but
planets motions use the distances as periods of time by the rate (1 mkm = 1 day),
these rates are found because (1 second of light motion = 1 solar day of planet
motion). means, the rate of time effects on the distances using, and We ask if the
rate of time effects also on the distances distribution?

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(2nd
Point) The Moon And Pluto Motions Rate Of Time (4.61)
- Shortly, we know that
- 1 Hour Of Pluto Motion = 4.61 Hours Of The Moon Motion
- Because
(1)
- Pluto motion distance during A Solar Day =406000 km
- The moon displacement during A Solar Day =88000 km
- 406000 km / 88000 km = 4.61
(2)
- 708.7 h (the moon day period) = 153.3 h (Pluto day period) x 4.61
- Based on this data we conclude that
- 1 hour of Pluto motion = 4.61 hours of the Earth moon motion
- More data supports this same conclusion let's refer to them in following:
More Data
(a)
Tan (12.2) x 708.7 hours = 153.3 hours
(b)
Tan (13.17) x 655.7 hours = 153.3 hours
Where
The angle 12.2 degrees = 13.177 deg – 0.98562 deg
13.177 degrees = The Moon Motion Degrees Per A Solar Day
0.98562 degrees = The Earth Motion Degrees Per A Solar Day
655.7 hours = The Moon Rotation Period.
- The data shows an interaction between the moon motion degrees, rotation period
and day period on one side with Pluto day period on the other side (notice Pluto
day period 153.3 h and Pluto rotation period -153.3 h)
- The rate (4.61) we discuss deeply in point no.(8)
- Here w try to discover if the rate (4.61) can effect on the distances distribution?

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(3rd
Point) The Rate (4.61) Effect On The Distances Distribution
I- Data
778.6 mkm (Jupiter Orbital Distance) = 4.61 x 170 mkm
550.7mkm (Jupiter Mars Distance) = 4.61 x 119.7 mkm
2094 mkm (Jupiter Uranus Distance) = 4.61 x 2 x 227.9 mkm
2872.5 mkm (Uranus Orbital Distance) = 4.61 x 629 mkm
3033.5 mkm (Uranus Pluto Distance) =4.61 x 654.9 mkm
5127 mkm (Jupiter Pluto Distance) = 4.61 x 2 x 550.7 mkm
5906 mkm (Pluto Orbital Distance) =4.61 x 1284 mkm
1375.6 mkm (Mercury Saturn Distance) =4.61 x 2 x 149.6 mkm
3062 mkm (Saturn Neptune Distance) =4.61 x 671 mkm
4345.5 mkm (Earth Neptune Distance) =4.61 x 940 mkm
4267.2 mkm (Mars Neptune Distance) =4.61 x 929 mkm
Where
170 mkm = Mercury Mars Distance
119.7 mkm = Venus Mars Distance
227.9 mkm = Mars Orbital Distance
629 mkm = Jupiter Earth Distance
654.9 mkm = Jupiter Saturn Distance
550.7 mkm = Jupiter Mars Distance
1284 mkm = Earth Saturn Distance
149.6 mkm = Earth Orbital Distance
671 mkm = Jupiter Venus Distance
940 mkm = Earth Orbital Circumference
929 mkm = Earth Jupiter Distance when the 2 planets be on the sun 2 sides
(Max error 1%)

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II- Discussion
- The solar system orbital and internal distances total be (45 distances)
- The previous data shows that (22 distances) are rated with the rate (4.61)
- Means
- 50% of all distances in the solar system be rated with one another based on this
same rate (4.61).
- The data proves the distances network claim
- And also
- The data proves that the solar system distances be distributed according to the rates
of time used by the planets motions.
- The data is strong and proves clearly the idea.
- But
- Why the rate of time between Pluto and the moon (4.61) is so effective in the solar
system distances distribution?
- The data proves the claim clearly and strongly but why the moon rate of time is so
important in the solar system distances distribution (50% of all distances!)
- If the distances percentage be (20%) I would consider this is a great proof but the
percentage (50%) tells that this rate (4.61) must be used by some planet more
important than the moon and Pluto otherwise these 2 planets have massive effect
on the solar system which we don't know yet!
- Any way
- The idea is proved strongly and no doubt can be raised against!
- But
- We keep the question in our minds (why this rate (4.61) is so important?)

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3-6 Planets Motions Unification Points
- Let's summarize the idea in following
- Light motion uses one period of time to create different data which is used in
plants motions unification.
- The data discussion explains this meaning clearly
- Let's use one example in following
- Light supposed velocity (1.16 mkm/s) needs 50 seconds to pass Mercury orbital
distance (57.9 mkm)
- But
- Mercury rotation period =58.65 solar days
- If 1 mkm= 1 solar days
- The 2 values (58.65 mkm and 57.9 mkm will have a difference = 1.3%)
- That pushes us to guess that, there's some reason to create these 2 values are so
near to one another
- It's the light motion effect
- The light needs to create different data based on equal periods of time to causes a
unification of planets motions.
- Let's explain that in more clear with the data discussion

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I- Data
(1)
Light known velocity (0.3 mkm/s) needs 500 s to pass (Earth orbital distance 149.6
mkm)
And
1.16 mkm/sec x 580 sec = 671 mkm (Venus Jupiter Distance)
But
100733 mkm = 929 mkm x 108.2 mkm = 671 mkm x 149.6 mkm
(2)
Light known velocity (0.3 mkm/s) during 193 s passes (57.9 mkm)
But
Light supposed velocity (1.16 mkm/s) during 196.5 s passes (227.9 mkm)
Between 193s and 196.5 s error (1.8%)
(3)
Light known velocity (0.3 mkm/s) during 586.6 s passes 176 mkm
But
Light supposed velocity (1.16 mkm/s) during 586.6 s passes (680 mkm)
(4)
Light known velocity (0.3 mkm/s) during 5127 s passes 1577.2 mkm (1%)
But
Light supposed velocity (1.16 mkm/s) during 5127s passes (5906mkm) (0.7%)
(5)
Light known velocity (0.3 mkm/s) during 3717s passes 2 x 550.7 mkm (1%)
But
Light supposed velocity (1.16 mkm/s) during 3717s passes (4331mkm) (0.7%)

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(6)
Light known velocity (0.3 mkm/s) during 361 s passes 108.2 mkm
But
Light supposed velocity (1.16 mkm/s) during 361 s passes (419 mkm)
and during (419 s) passes a distance (2 x 243mkm)

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II- Discussion
Data No. (1)
Light known velocity (0.3 mkm/s) needs 500 s to pass (Earth orbital distance 149.6
mkm)
And
1.16 mkm/sec x 580 sec = 671 mkm (Venus Jupiter Distance)
But
- The data tells that, light known velocity and light supposed velocity both use equal
periods (500s) for Earth and Venus positions.
- Earth position is defined by Earth orbital distance but Venus position is defined by
Venus Jupiter Distance
- Why both light beams used equal periods of time (500s)? why this is useful?
- Let's discussion the equation
- Where
- 100733 mkm = light supposed velocity (1.16 mkm/s)motion distance during a
solar day
- 929 mkm = Earth Jupiter distance when the 2 planets be on the sun 2 sides
- 108.2 mkm = Venus Orbital Distance
- 149.6 mkm = Earth Orbital Distance
- 671 mkm = Venus Jupiter Distance
- The equation shows that, these 4 distances be created from the same one source
and because of that they are created in proportionality one another
- That explains why light uses equal periods of time (500 s) for the 2 planets
positions definition.

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Data No. (2)
Light known velocity (0.3 mkm/s) during 193 s passes (57.9 mkm)
But
Light supposed velocity (1.16 mkm/s) during 196.5 s passes (227.9 mkm)
Between 193s and 196.5 s error (2%)
- The difference 2% we should discuss at this point end. And we consider the 2
periods are equal
- By using equal periods, light supposed velocity (1.16 mkm/s) created Mars orbital
distance (227.9 mkm) but light known velocity (0.3 mkm/s) creates Mercury
orbital distance (57.9 mkm)
- That creates a unification of motion among Mercury, Mars (and Jupiter) because
Jupiter motion depends also on the period (196.5 s)
- The three planets show a deep harmony and by analysis we have proved that these
3 planets motions be integrated into one unified motion.
- Notice (1)
- The difference (2%) is found for geometrical necessity. This conclusion depends
on the data analysis because we have seen frequently the solar system values be in
(100%, 99% and 98%).
- For example
- Earth moves during a solar day a distance =2.574 mkm(100%) but the moon
displacements total during 29.53 days =2.598 mkm (101%) and the moon apogee
orbital circumference = 2.55 mkm (99%)
- Notice (2)
- 8 Jupiter days =79.2 hours = 285120 sec = π x 90756.5 sec
- 90756.5 sec – 90560 sec = 196.5 sec
- 90560 days = Pluto Orbital Period
- We remember (1 day of planet motion = 1 second of light motion)

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Data No. (3)
Light known velocity (0.3 mkm/s) during 586.6 s passes 176 mkm
But
Light supposed velocity (1.16 mkm/s) during 586.6 s passes (680 mkm)
- Where
- 175.94 Solar Days = Mercury Day period
- 680 mkm = Venus Orbital Circumference
- 687 days =Mars Orbital Period
The values 687 and 680 are different with 1%
- Based on equal periods of time (586.6 seconds) light known velocity travels 176
mkm and light supposed velocity travels 680 mkm
- Where (175.94 days and 687 days be the result values by these motions)
- We remember
- (1 mkm = 1 day for planet motion and 1 mkm = 1sec for light motion)
- Notice (1)
- 4222.6 h (Mercury Day Period)/ 24.7h (Mars Day Period) = 170
- Where
- 170 mkm = the distance between Mercury and Mars
- Notice (2)
- 687 days (Mars orbital period) x 24 h = 671 x 24.6 h (Mars rotation period)
- Where
- 671 mkm = Venus Jupiter Distance
- 680 mkm = Venus Orbital Circumference (different with 687 mkm with 1%)
- The analysis tries to show that, the equal periods using by both light velocities
motions produced an interaction of planets motions data which effect on these
planets motions.

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Data No. (4)
Light known velocity (0.3 mkm/s) during 5127 s passes 1577.2 mkm (error 1%)
But
Light supposed velocity (1.16 mkm/s) during 5127 s passes (5906 mkm) (error 0.7%)
- The data shows that, the equal periods (5127 seconds) by using light supposed
velocity passes a distance = 5906 mkm =Pluto orbital distance. And by using light
known velocity passes a distance = 2 x 778.6 mkm (Jupiter orbital distance)
- where
- 5127 mkm = Jupiter Pluto distance
- That shows, the deep interaction which is found between Jupiter and Pluto motions
data depends on the light motion using equal periods for the 2planets orbital
distances definition.
- The data tries to show that, a light beam is moving behind the planets motions and
accompanying these planets in their motions. where the light motion effects on the
planets motions data.

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Data No. (5)
Light known velocity (0.3 mkm/s) during 3717 s passes 2 x 550.7 mkm (error 1%)
But
Light supposed velocity (1.16 mkm/s) during 3717 s passes (4331 mkm) (error 0.7%)
- By using the period (3717 sec) light known velocity passes a distance = 2x 550.7
mkm (Mars Jupiter Distance)
- And
- By using the period (3717 sec) light supposed passes a distance = 4331 mkm
(Jupiter orbital period =4331 days)
- Where
- 3717 mkm = Jupiter Neptune Distance
- The data provides an interesting proof because the data is directed one and can't be
considered as a random data.

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Data No. (6)
Light known velocity (0.3 mkm/s) during 361 s passes 108.2 mkm
But
Light supposed velocity (1.16 mkm/s) during 361 s passes (419 mkm) and during
(419 s) passes a distance (2 x 243mkm)
- Where
- 108.2 mkm =Venus Orbital Period
- 243 days = Venus Rotation Period
- The using of equal periods of time is very useful to create a unification for planet
motion data. that means, based on Venus motion Venus orbital distance (108.2
mkm) be defined and Venus rotation period also be defined. Because both data
depends on Venus motion and because the main player behind is the light motion
and Venus is a puppet on the puppet theater
- The light motion has to depend equal periods of time to create a unification of
planet motion data

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3-7 The Solar System Distances Network Analysis
- The data discussion proves clearly the distances network claim, and based on the
data discussion we can conclude that, the solar system distances be created
depends on one geometrical design in a network form
- But
- The distances still have many puzzled secrets can't be discovered yet. Let's provide
2 of them in following
- (1st
Point)
- The solar system motions be consisted of light motion and planets motions.
- The solar system motions use different rates of time, as we have seen in the
comparison between light and planet motion where (1 second of light motion be =
1 solar day of planet motion)
- The solar planets motions depend on different rates of time which we will discuss
in this paper. For example (1 h of Mercury motion =9.18 h of Pluto motion)
- That creates different rates for the distances using. Because light motion uses the
distance by the rate (1mkm =1sec) but planet motion uses the distance by the rate
(1mkm =1soalr day). Because of that, the solar system distances network should be
created based on one flexible geometrical design can be used in different rates.
This feature causes a difficulty to discover the solar system distances geometrical
design.
- (2nd
Point)
- The solar system motion depends on the equal distances.
- That means, the solar system motion causes to force the planets to move equal
distances in defined periods of time. Or the equal distances of planets motions
cause the solar system motion.
- In fact

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- I can't discover yet the geometrical effect of the equal distances, let's use one
example for better explanation
- Earth moves during a solar day (24 h) a distance = 2574720 km
- Pluto moves during its day period (153.3 h) a distance = 2593836 km
- The moon displacements total during (29.53 days) = 2598693 km
- These 3 distances are equal with max error only (1%)
- These distance can be considered equal distances, but can thi distances quality
effect on planets motions? yes
- Let's see the following data
- More Data
Group no. (1) (Pluto And Earth Rate Of Time)
- (Earth velocity / Pluto velocity) = (Pluto Day period/ earth day period) = 6.37 (0.8%)
- Pluto orbital distance 5906 mkm = Earth orbital circumference 940 mkm x 2π
- Pluto orbital period 90560 days = Earth Cycle (1461 days) x 2π3
Group no. (2) (Pluto And The moon Rate Of Time)
(1)
(406000 km /88000 km) = (708.7 h/ 153.3 h) = 4.61
(2)
Tan (12.2) x 708.7 hours = 153.3 hours
(3)
Tan (13.17) x 655.7 hours = 153.3 hours
- Where
- 406000 km = Pluto Motion Distance during a solar day
- 88000 km = The moon displacement daily
- 708.7 hours = The Moon Day Period
- 153.3 hours = Pluto Day Period
- And
- The angle 12.2 degrees = 13.177 deg – 0.98562 deg
- 13.177 degrees = The Moon Motion Degrees Per A Solar Day

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- 0.98562 degrees = The Earth Motion Degrees Per A Solar Day
- And
- 655.7 hours = The Moon Rotation Period.
- 153.3 hours = Also (153.3-) Pluto Rotation Period
- Shortly
- the 3 planets move equal distances in defined period of time and their motions data
be in proportionality with each other as seen clearly in data.
- Is the distances equality cause the data proportionality or vice verse? I can't
provide a decision.
- The fact is that, the distances are equal and the data is in proportionality.
- And
- This feature be repeated each time the planets move equal distance in define
periods of time
- And
- The planets uses the equal distances method frequently, and hundreds of times this
method using be observed
- How the machine works? I don't know? Of course Not by Newton theory
- But I can't discover the machine motor mechanism
- Because
- The equal distances works based on geometrical rule as a waterwheel or a lever.
The equal distances create basic geometrical effect on the planets motions. but
because I can't discover this effect the process be repeated before my eyes
hundreds of time but I understand nothing of its geometrical effect
- By that, the machine motor b out of our sight and because of that we can't
understand neither the distance role nor the machine motor mechanism
- The equal distances method is discussed in more details in point no.(8)

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4- Light Beam (1.16 mkm/s) Existence Proves Discussion
4-1 Preface
4-2 The Light Beam (1.16 mkm/s) Proves Discussion
4-3 Jupiter Orbital Circumference Analysis

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4-1 Preface
- What Do We Try To Do In This Point?
- We analyze the distances between Mercury and Pluto as deep as possible to prove
that, these distances are created by energy of a light beam its velocity =1.16 mkm/s
- Let's summarize the idea in following:
- The Light supposed velocity (1.16 mkm/sec) started its motion from Mercury, and
moves in 2 basic trajectories.
- The First trajectory be from Mercury to Jupiter where the light supposed velocity
(1.16 mkm/sec) created Jupiter orbital circumference.
- And then
- This light beam travels from Jupiter to Pluto
- The second trajectory be from Mercury to Pluto Directly
- There's also one more trajectory, which is Mercury motion trajectory.
- We should discuss each one in details..
- Our main task here is that, to analyze different distances to prove that these
distances can't be created except by a light beam its velocity = 1.16 mkm/sec.
- We should keep an eye on Jupiter motion data and distances because Jupiter data
gives a strong proof for the light supposed velocity (1.16 mkm/sec) existence

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4-2 The Light Beam (1.16 mkm/s) Proves Discussion
I - Data
(1)
1.16 mkm/s x 86400 s = 100733 mkm
And
0.3 mkm/s x 86400 s = 25920 mkm
(2)
(3)
1.16 mkm per second x 2 x 86400 seconds =2 x 100733 mkm = (37100 mkm – 4900
mkm) x 2π = 28255 mkm + 2 x 86400 mkm
(4)
1.16 mkm/s x 5040 seconds = 5848 mkm (Mercury Pluto Distance)
And
5848 mkm (Mercury Pluto Distance) – 4900 mkm = 948 mkm
(5)
1.16 mkm/s x 4900 seconds = 5678.1 mkm (Mars Pluto Distance)
And

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II- Discussion
Equation no. (1)
1.16 mkm/s x 86400 s = 100733 mkm
And
0.3 mkm/s x 86400 s = 25920 mkm
- Light known velocity (0.3 mkm/s) travels during a solar day (86400 s) a distance =
25920 mkm.
- Because it's a light motion we see this value (25920 mkm) as a period of time
(25920 years = the Precession Cycle)
- Also
- The distance 25920 mkm be = The Planets Motions Distances Total During A
Period =1461 days (where 1461 days =365 +365 +365 +366)
- Because the period 1461 days is (Earth Cycle) we consider that the distance 25920
mkm be mentioned by planets motions total
- Notice, the distances total added the Earth moon motion distance to the 9 planets
motions distance to create the total per a solar day (17.75 mkm) where the moon
motion daily distance be considered = Earth motion daily distance because they
aren't separated from one another through their motions.
- The light supposed velocity (1.16 mkm/s) travels during a solar day (86400 s) a
distance = 100733 mkm = The 9 Planets Orbital Circumferences Total
- Equation no. (1) tries to prove that, Light Motion Uses The Solar Day Period As
Its Basic Period Of Motion.
- Light known velocity and light supposed velocity both use the solar day as the
basic period of time. Because of that, both light beams passes essential distances in
the solar system geometry.
- The next discussions will prove that these distances (25920 mkm and 100733
mkm) are essential distances in the solar system geometry.

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- Notice
- The rule tells
- (Light Motion For 1 Second = Planet Motion For 1 Solar Day)
- This rule which is a supposed one and we should prove it through the paper
discussions…
- This rule tells that,
- The light motion depends on the solar day as a period of time as similar to its
dependency on the second as a period of time.
- That means,
- These 2 periods of time (the second and the solar day) are the 2 basic columns for
light and planet motions accompaniment.
- And by that, light motion doesn't use the solar day as similar to any other planet
day period. On the contrary, the solar day is the basic period of time for light
motion (For both velocities, the known and supposed).

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The Motion 1st
Trajectory
- The Trajectory Summary
- Light supposed velocity (1.16 mkm/s) travels starting from Mercury to Jupiter,
creating Jupiter orbital circumference
- And, then
- Light supposed velocity (1.16 mkm/s) travels from Jupiter to Pluto (Directly) and
doesn't touch any other planet in the way.
- The motion trajectory is built on 2 basic equations and many other additional data.
because
- Mercury Motion uses light supposed velocity (1.16 mkm/s) because of that,
different data of Mercury motion be created based on this light supposed velocity
(1.16 mkm/s) energy
- Shortly
- The motion 1st
trajectory is defined based on Equation no. (2) and (3) as basic
equations. And through discussion many other data be added
- Notice
- Equation no. (3) is the solar system geometry main equation and it's the paper
main one we discuss it along the paper,

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Equation no. (2)
- Where
- Equation no. (2) tells, the light supposed velocity (1.16 mkm/s) travels during
4224 seconds a distance = 4900 mkm = Jupiter Orbital Circumference.
- Now, let's suppose 1 second of light motion = 1 hour of Mercury Motion
- based on that, 4224 seconds be equivalent to 4224 hours (but 4222.6 hours =
Mercury Day Period).
- Equation no. 3 provides 3 braches of data! let's summarize them in following:
- (1st
Branch) Light supposed velocity (1.16 mkm/s) moves in (4224 s) a distance
=4900 mkm but Mercury moves during (4222.6 h) a distance = 720.7 mkm (=
Mercury Jupiter Distance) and we suppose that 1 second of light motion = 1
hour of Mercury Motion. Because of that we need to find some connection
between 4900 mkm and 720.7 mkm to create a comparison between light motion
and planet motion.
- The comparison is complex because, I suppose the rate (2π) distinguish between
light and planet motions. By that, if light moves 4900 mkm, a planet motion
should be 778.6 mkm but Mercury motion distance only be 720.7 mkm, where,
- 778.6 mkm (Jupiter orbital distance) =1.0725 x 720.7 mkm (Mercury Jupiter
Distance)
- The rate (1.0725) creates a negative effect on the rule of the value (2π). although
the rate (1.0725) be used between 40% of all distances in the solar system. But
because it be found here creates more complexity for the discussion and causes
some negative effect for the comparison between light and planet motions. because
always in other data we have found that the value (2π) distinguish clearly between

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light and planet motions but in our equation the rate (1.0725) causes some
difficulty for this comparison vision.
- Notice
- The distance 720.7 mkm (Mercury Jupiter Distance) be discussed in point no. (5)
of this paper.
- (2nd
Branch) Mercury Day Period Creation.
- We have supposed that, 1 second of light motion be equivalent to 1 hour of
Mercury Motion. that means the period (4224 s ) be equivalent to (4224 h) and
Mercury Day Period = (4222.6 hours).
- This supposition suggests that, Light supposed velocity (1.16 mkm/) motion causes
to create Mercury Day Period be (= 4222.6 hours).
- The data is accurate and clear
- NOW
- The data tells that…
- Mercury is the source of the light supposed velocity (1.16 mkm/s)
- The light supposed velocity (1.16 mkm/s) started from Mercury and sent to Jupiter,
creating the distance (4900 mkm = Jupiter Orbital Circumference).
- This motion depends on Mercury Day Period.
- As a result, Mercury Day Period be defined by light supposed velocity (1.16
mkm/s) motion effect on Mercury Motion.
- i.e.
- Mercury Day Period = 4222.6 hours
- And
- 4900 mkm= 1.16 mkm/s x 4224 seconds
- We suppose that, 1 hour of Mercury Motion = 1 second of light motion… means

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- The difference (4224 -4222.6 = 1.4) is created by the light supposed velocity (1.16
mkm/s) motion effect. that means,
- The light motion effected on Mercury Motion and caused Mercury day period to
be 4222.6 hours and less than 4224 hours with 1.4 hour = 5040 seconds
- Why? Because
- Light supposed velocity (1.16 mkm/s) travels during (5040 s) a distance =5848
mkm = Mercury Pluto Distance
- The light supposed velocity (1.16 mkm/s) created a connection between Mercury
and Pluto motions by creating the period 5040 seconds as a difference between
Mercury Day period (4222.6 h) and 176 solar days (=4224 hours).
- We can't discover the geometrical machine behind this data. But the data clearly
shows that, the light supposed velocity (1.16 mkm/s) travels during 5040 seconds a
distance = 5848 mkm.
- We have 3 information we got based on this analysis which are:
- (1st
) Mercury Is The Origin Point Of The Light Supposed Velocity (1.16 mkm/s)
- (2nd
) light supposed velocity (1.16 mkm/s) motion created Jupiter orbital
circumference 4900 mkm.
- (3rd
) Mercury Day Period be (4222.6 h) and less than (4224 h) with (5040 s)
because of light supposed velocity (1.16 mkm/s) effect on Mercury motion, to
create a connection between Mercury and Pluto motions.
- Notice
- The accompaniment of The Light supposed velocity and Mercury Motions caused
Mercury day Period to be (4222.6 hours) to create a connection between Mercury
and Pluto based on the distance (5848 mkm = Mercury Pluto Distance)
- Is There any Proof for this conclusion?
- Yes, There's a proof in Mercury Motion data,
- Let's analyze Mercury Motion Data in following:

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Mercury Motion Data
- 5040 seconds = 84 minutes
- Mercury (4.095 mkm/ daily) moves during 84 solar days a distance = 344 mkm
- And
- Mercury (4.095 mkm/ daily) moves during 346.6 solar days a distance = 1419.5 mkm
- And
- Mercury (4.095 mkm/ daily) moves during 1419.5 solar days a distance = 5813 mkm
- But
- Mercury (4.095 mkm/ daily) moves during 1433.5 solar days a distance = 5870 mkm
Pluto Orbital Distance
- NASA Planetary Fact sheet had defined Pluto orbital distance as 5870 mkm
- And
- From 5 years NASA had modified this distance to be 5906 mkm
- In the theoretical calculations both distances are required!
- Let's explain that in following
o 5906 mkm – 57.9 mkm (Mercury orbital distance) = 5848 mkm
o This distance 5848 mkm accurately = 1.16 mkm/s x 5040 seconds
But
o Mercury motion during 1419.5 days passes a distance =5813 mkm = 5870
mkm – 57.9 mkm - And
o Mercury motion during 1433.5 days passes a distance =5870 mkm (Pluto
orbital distance)
Shortly
o Light motion depends on the distance (5906 mkm as Pluto orbital distance)
but Mercury motion depends on the distance (5870 mkm as Pluto orbital
distance).
o That tells both distances are found geometrically but also tells some
difference be found between light and planet motions.

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Mercury Motion Data Analysis
- The previous data shows that,
- Mercury uses light motion strategy. By that, Mercury moves a distance and then
uses this distance as a period of time to move another distance. By that the
distances be created in a network form.
- We don't know how a planet moves with low velocity can use distances values as
periods of time. The data needs more analysis to discover the rule on which this
using is done.
- Mercury motion aims to pass a distance = 5848 mkm= Mercury Pluto Distance,
this distance is the distinguish one in the 1st
trajectory of motion and also the 2nd
trajectory of motion. Many data be created in proportionality with this distance
which proves some geometrical machine be found behind these motions.
- Mercury moves the distance (5848 mkm) following light motion
- Mercury uses the rate (1 mkm= 1 solar day)
- Notice
- Jupiter Orbital Circumference (4900 mkm) is a very rich distance of discussions
and arguments. Because of that,
- Jupiter orbital circumference analysis be discussed in a separated point no. (4-3) .
- The idea is that, the light supposed velocity (1.16 mkm/s) creates a connection
between Mercury and Pluto by using Jupiter orbital circumference (4900). That
means, Jupiter orbital circumference be used as a central point in the light
trajectory of motion from Mercury to Pluto, because of that, the light supposed
velocity (1.16 mkm/s) created Jupiter orbital circumference (4900 mkm) by
different geometrical features which be required for this task. As a result we find
Jupiter orbital circumference is so complex distance and filled of questions.

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The Conclusions
- The data tells,
- Mercury is the origin point of the light supposed velocity (1.16mkm/s) motion. that
means, the light starts its motion from Mercury point. (A Conclusion No. 1)
- The light supposed velocity (1.16 mkm/s) passes the distance (4900 mkm = Jupiter
orbital circumference) in a period (4224 seconds). By that the light connects
between Mercury motion and Jupiter motion. (A Conclusion No. 2)
- Mercury Day Period be less than (4224 hours) by 5040 seconds because light
supposed velocity (1.16 mkm/s) travels during 5040s a distance = (5848 mkm) =
(Mercury Pluto Distance)
- Light supposed velocity (1.16 mkm/s) uses (5040s) to pass the distance (5848
mkm) and create a connection between Mercury motion and Pluto motion. (A
Conclusion No. 3)
- Notice
- 5848 mkm (Mercury Pluto Distance) –4900 mkm (Jupiter orbital circumference) =
946.5 mkm
- Where
- 940 mkm = Earth Orbital Circumference (error 0.7%)
- The value (946.5 mkm) is very important we will discuss in 2nd
Trajectory of
motion because it's related to Saturn motion data.

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Mercury Motion Data Analysis (Continued)
- The previous data analysis concluded that, Mercury is the source of light supposed
velocity (1.16 mkm/s).
- So, let's ask,
- Is Mercury Motion data in harmony with light supposed velocity (1.16 mkm/s)?
(I)
- Light suppose velocity (1.16 mkm/s) needs only 50 seconds to pass Mercury
orbital distance (57.9 mkm).
- Can this (50 s) be a data belong to Mercury Motion?
- Mercury (47.4 km/s) moves during 50.3 s a distance = 2390 km (Pluto diameter)
- Mercury (47.4 km/s) moves during 50.3 m x 60 s a distance = 142984 km (Jupiter
diameter)
- Mercury Venus Distance = 50.3 mkm ( 1mkm = 1 second)
- Mercury Neptune Distance (4437 mkm) = 50.3 mkm x 88
- (Mercury Orbital Period =88 days)
- Mercury Pluto Distance (5848 mkm) = 50.3 mkm x 116.2
- (57.9 mkm Mercury orbital distance x2 = 115.8 mkm)
- The data shows that, the period 50.3 seconds is a value be used frequently by
Mercury motion data. and mercury moves during (50.3 s) a distance = Pluto
diameter and moves during (50.3 m) a distance = Jupiter diameter, showing that
the 2 planets are the same planets mentioned by the 1st
trajectory motion.
- The basic difficulty is that, the light motion creates geometrical effects which we
can't discover because we don’t know neither their rule nor their effects. We have
only some data be transported from a point to another and that creates difficulties
for the analysis process.

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(II)
- Mercury Orbital Distance =57.9 mkm
- Mercury rotation period =58.65 solar days.
- The rate (1 mkm = 1 day) be used frequently in different motions data.
- The 2 values (57.9 mkm and 58.65 mkm) have an error (1%)
- Means, the 2 values (57.9 mkm and 58.66 days) can be created by the light
supposed velocity (1.16 mkm/s) motion during 50 seconds
- I try to show that, Mercury motion different data be in proportionality with light
supposed velocity (1.16 mkm/s) motion. which proves that Mercury is the origin
point of the light supposed velocity (1.16 mkm/s) motion.
- Because not only the period (5040 mkm) can be used or the period 4222.6 h
(which us equivalent to 4224 s) but also the period (50s)
- Notice
- 153.3 hours = Pluto day period
- 151.7 hours = 0.99 x 153.3 h (Pluto day period)
- But
- 176 mkm = 1.16 mkm/s x 151.7 seconds
- Where
- Mercury Day period =175.94 solar days (if 1 day = 1 mkm, the 2 values be
equivalent)

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- (3rd
Branch) Saturn Motion Effect.
- Saturn (0.838 mkm / daily) moves during = 5848 days, a distance = 4900 mkm
- This data shows Saturn motion effect on Mercury motion data
- And
- We have to discuss this data in separated point because Saturn creates another
reading for Mercury Motion Data.
- That means, the data be used by light motion for reasons but the same data be used
again by planet motion for different reasons.

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Equation no. (3)
1.16 mkm per second x 2 x 86400 seconds =2 x 100733 mkm = (37100 mkm –
4900 mkm) x 2π = 28255 mkm + 2 x 86400 mkm = 202318 mkm (error 1%)
- Where
- 100733 mkm = The 9 Solar Planets Orbital Circumferences Total
- 28255 mkm = Neptune orbital Circumference
- Equation no. (3) is the paper basic equation. Because it explains The Basic Energy
Trajectory Through The Solar System…
- First, We notice that,
- The equation uses the rate (2) because of Neptune orbital circumference. Where
the equation 3 parts can be used without the rate (2), But the last part (28255 mkm
+ 2 x 86400 mkm) needs the rate (2) because of Neptune orbital circumference
(28255 mkm). That explains why the equation uses the rate (2).
- Now let's divide the equation into 4 Parts.
(Part No. 1)
- 1.16 mkm per second x 2 x 86400 seconds = 2 x 100733 mkm
- Part no. (1) tells us a known information which is
- Light supposed velocity (1.16 mkm/s) travels during one solar day (86400s) a
distance = 100733 mkm = The 9 Solar Planets Orbital Circumferences Total
- The rate (2) is used for Neptune Orbital Circumference.
- This part of equation tells that, light motion depends on the solar day period. This
idea we have discussed in equation no. (1) of this discussion.
- Also we know that
- Light known velocity (0.3 mkm/s) travels during (86400 s) a distance = 25920
mkm

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- Where
- 25920 mkm = 17.75 mkm x 1461 days
- 17.75 mkm = the planets distances total during a solar day in addition to the Earth
moon motion distance during a solar day, and
- 1461 days = Earth Cycle (365 +365 +365 +366)
- The data tries to prove that, the light motion depends on the solar day period.
- Notice
- (25920 mkm x 2) =37100 mkm x 1.392
- Where
- The sun diameter =1.392 mkm
- The data uses the rate (2) because this rate be used in equation no. (4) which
expresses the solar system basic energy trajectory.
- That means the value (25920 mkm x 2) refers to the total energy according to light
known velocity (0.3 mkm/s) range of motion.
- The data tells the value (25920 mkm x 2) expresses really the total energy because
37100 km (Pluto orbital circumference) is the greatest orbit
- That means, when the total energy be expresses by the value (2 x 100733 mkm)
this energy be transported to the light known velocity based on the same rate
because it's one machine.
- The data proves the energy unification through the solar system spite of using 2
different velocities of light.

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(Part No. 3)
- 2 x 100733 mkm = (37100 mkm – 4900 mkm) x 2π =
- This part is very important because
- The data shows the energy motion (or light motion) started from 4900 mkm
- That means,
- To create Pluto orbital circumference 37100 mkm, the light starts from the point
4900 mkm and measures a distance = 100733 mkm by geometrical calculations.
- We have 3 points here
- The start point which is (4900 mkm =Jupiter orbital circumference)
- The direction of motion (toward Pluto)
- The measurement unit is 100733 mkm (defined by light supposed velocity motion
during a solar day)
- The data tells, Pluto orbital circumference is created depending on (4900 mkm )
Jupiter orbital circumference by using the light motion.
- We remember
- The distance 4900 mkm be passed by light supposed velocity (1.16 mkm/s)
depends on the period (4224 s) which is defined in comparison with Mercury day
Period (4222.6 hours)
- As A Result, we conclude that,
- Light supposed velocity (1.16 mkm/s) starts from Mercury to Jupiter and continues
from Jupiter to Pluto. that shows one clear trajectory of motion from Mercury to
Jupiter to Pluto.
- That means, the motion from Mercury to Jupiter considers Mercury is the head of
the inner planets and by that the connection between Mercury and Jupiter express
the connection between Jupiter and all inner planets.
- And
- The connection between Jupiter and Pluto doesn't contain any other planet. It’s one
directed motion from Jupiter to Pluto immediately

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- Shortly
- Jupiter and Pluto orbital circumferences be created by light supposed velocity
(1.16 mkm/s) motion depends on Mercury motion data by creating different steps
of motions to connect between Mercury and Pluto
- This data confirms that the distances be created based on network form and
according to one geometrical design.
Notice
- (2π) This rate distinguish between light motion and planet motion as we have
discussed before.
- The rate (2π) distinguishes here clearly between the planet and light motions.
where the difference (37100 mkm – 4900 mkm) refer to the planets motions where
the value 2 x 100733 mkm refers to the light motion and the rate (2π) distinguish
between the 2 motions.
- Venus equation which we will study with the part no. (4) of this equation uses also
the rate (2π) between the energy source and the planet received energy. we should
refer to this meaning in its discussion.

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(Part No. 4)
- 2 x 100733 mkm = 28255 mkm + 2 x 86400 mkm
- The total energy be reflected from Pluto to Neptune. The distances behave
perfectly as light beams.
- Neptune had seized 14% of the total energy and the rest of energy be reflected
toward the inner planets into 2 trajectories of energy each has (86400 mkm)
- We suppose that (Distance = Energy)
- The energy be sent from Neptune to Venus and Earth, let's see their equations in
following
- 2 x 86400 mkm = (28255 mkm – 680 mkm) x 2π (Venus Equation)
- Where
- 28255 mkm = Neptune Orbital Circumference
- 680 mkm = Venus Orbital Circumference
- Earth equation is perfectly similar to Venus equation where between both the error
is less than 1%
- Also we see the rate (2π) which distinguish between light and planet motion as we
have seen in our equation no. (2) (or it distinguish between the source of energy
and the planet received energy).
- Part (4) of the equation tells that, Neptune had seized 14% of the total energy and
the rest of energy is sent to Venus and Earth into equal trajectories of energy each
has (86400 mkm).
- That means, the inner planets energy be received from Neptune. And because of
that, the inner planets distance be controlled by Neptune orbital distance (4495.1
mkm) as the data shows that clearly.
- 4495.1 mkm (Neptune orbital distance) = 78.3 mkm x 57.9 mkm
- = 108.2 mkm x 41.4 mkm
- = (149.6 mkm x 120 mkm)/4

The Solar System Doesn't Move By The Sun Mass Gravity (Revised) (2)

The Solar System Doesn't Move By The Sun Mass Gravity (Revised) (2)

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