We Should Refuse Newton Theory Of The Sun Mass Gravity.pdf

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
We Should Refuse Newton Theory Of The Sun Mass Gravity
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –29th
March 2022
Abstract
Paper Discovery
- Planets data be created based on exact equations and mathematical calculations
and doesn't depend on any (historical unknown factors or initial conditions)
- As a result, Planets creation and motion data can be concluded theoretically
without observation because it's created based on mathematical equations
- I provide 3 new equations and use one more equation based on Kepler law, by
these 4 equations using we can conclude All planets orbital distances, periods,
velocities, inclinations, rotation periods, diameters, masses and axial tilts…
- This Data Can Be Concluded Theoretically Without Observation.
- The paper tests these 4 equations and proves this discovery
Paper Theory
- The Solar system be created based on One Geometrical Design.
- Means, based on one design all planets creation and motion data be created and by
that the planets be parts in one building (or members in one body)
- Can one law control all planets creation and motion data?
- Let's suppose, The Planets Move A Unified Motion (as a machine of gears). This
unified motion will force each planet to move a complementary motion to others'
to enable the unified motion to be created.
- Planet data should be in consistency with its motion – otherwise – this planet will
be destroyed. Means, if planets motions be complementary one another that will

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cause these planets creation and motion data to be complementary one another, by
this vision, One Law controls all planets creation and motion data
- The paper theory tells, the solar system be created based on one geometrical design
and be controlled by one law, for that reason the planets data be created based on
exact equations – let's refer to these 4 equations in following
- My (1st
Equation) d2
= 4d0 ( d- d0)
- d = Planet Orbital Distance d0= Its Previous Planet Orbital Distance
- the equation tells each planet orbital distance depends on its neighbor
- (Kepler Law) Equation (v1/v2)2
= (d2/d1)
- v = Planet Velocity d= Planet Orbital Distance
- The equation tells planet orbit defines its velocity
- My (2nd
Equation) (v1/v2) = (s/r) = I
- v = Planet velocity and r= a diameter of one of the 2 planets
- s= the planet rotation periods number in its orbital period
- (The value "s" is belonged to the planet whose diameter is "r")
- I= Planet orbital inclination (of the planet whose diameter is "r")
- The equation tells based on planets velocities rate, planet diameter and its rotation
period be defined-
- My (3rd
Equation) (v1v2) = 322
- The equation tells Planets velocities are complementary one another based on the
rate 322 –
- The paper theory tells, the solar system depends on one geometrical design, in this
design Mercury be the origin point and Jupiter orbital circumference be the main
distance of the solar system – the paper explains that in details

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Paper Argument
- The paper argues, the solar planets matters and their distances be created of energy
of one light beam. The matter doesn't separate its light parent but move together by
using different rates of time, means, the solar system be created of one light beam,
and because of that, the solar system data depends on one geometrical design and
that causes Planets data to be created based on exact equations and mathematical
calculations.
- This light beam energy be registered in the planets matters and their distances data
by that this light beam can be discovered by planets data analysis
Paper hypotheses
- (1)
- Planet Motion Depends On Light Motion
- (2)
- A light beam its velocity 1.16 million km per second be found in the solar system
- (This velocity is registered in the planets and distances data)
- The paper proves these hypotheses
Paper question
- Why Should We Refuse Newton Theory Of The Sun Mass Gravity?
- Because
- No Planet moves by the sun mass gravity, the solar planets move depending on
light motion.
Paper theory applicability
- If Planets be created by collisions among themselves (as the moon case) how their
data can be created based on exact equations and mathematical calculations?
- The matter is created out of light beam. We see rigid body but this rigid body is
created out of light beam and moves with it. As in the double production, from
Gamma ray be produed electron and position, 2 particel equal in mass different in
charges – the data be defined before the experiment.

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Paper theory application
- In what can we use this theory of One Geometrical Design?
- We can use it to explain the moon orbital motion – let's summarize it here:
- The moon daily displacement =88000 km, during 29.53days (the moon day period)
the displacements total be =2.598 mkm = 2π x 413600 km This data tells 2 facts
- (1st
Fact), The moon orbital apogee radius should be 413600 km
- (2nd
Fact), The moon should revolve around the Earth through this apogee orbit
with radius (r= 413600 km) only and can't revolve through any more near orbit
because of the long displacement daily (88000 km).
- Both conclusions are unreal because
- The moon orbital apogee radius (r= 406000 km) only and the moon can revolve
around the Earth through more near orbits and can reach even to the perigee orbit
(r= 363000 km).
- How does the moon do that?
- The intelligent moon creates an angle (θ) between its motion direction and its orbit
horizontal level, by that the real displacement (L = 88000 cos θ) be shorter than
(88000 km) and that enable the moon to decrease its apogee radius from 413600
km to 406000 km and enable it to revolve around the Earth through more near
orbit. By that the moon can reach even to perigee radius (r= 363000km)
- 413600 km cos (θ) = 406000 km where (θ =10.96 degrees),
- Let's ask, If the moon has this intelligent technique why the apogee radius be
406000 km? Why not be shorter? From where the moon found this angle (θ =10.96
degrees)? (from Uranus!)
- The explanation of this data depends on the solar system one design and can't be
explained by any other theory. (the paper explains the moon motion)
(Please scan the figure (ORCID)

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Paper Contents
Subject Page No.
1- Introduction 8
2- Methodology 12
3- Planet Data Creation Description 14
3-1 Preface 15
3-2 How Be Planet Data Created? 17
3-3 Planet Orbital Distance Equation (My 1st
Equation) 20
3-4 Kepler Laws Analysis 24
3-5 Planet Rotation Period Equation (My 2nd
Equation) 25
3-6 Planet Velocity Equation (My 3rd
Equation) 46
3-7 More Analysis For My 3 Equations 48
3-8 More Discussion (Questions And Answers) 62
4- Can Light Motion Effect On Planet Motion? 71
4-1 Preface 72
4-2 The Main Data (Data No. 1) 74
4-3 Planet Velocity Proportionality (Data No. 2) 80
4-4 The Solar System One Design Description (Data No. 3) 83
4-5 The Solar System One Design Analysis (Data No. 4) (I) 85
4-6 Data No. (4) (Part II) 87
4-7 The Distances Be In Network Form (Data No. 5) (Part A) 93
4-8 Data No. (5) (Part B) 96
4-9 Planet Motion Data Depends On Light Motion (Data No. 6) 101
4-10 Planets Motions for 30 mkm (Data No. 7) 105
5- The Solar System One Geometrical Design Analysis 111
5-1 Preface 112
5-2 The Comparison between the Solar Day period and Mars rotation period 113
5-3 Jupiter Velocity More Analysis 114
5-4 Uranus Velocity Analysis 117
5-5 The Solar System One Geometrical Design Analysis 123
5-6 The Planets Unified General Motion 146
6- The Moon Orbital Apogee Radius Analysis 158
6-1 Preface 159
6-2 The Moon Orbital Motion Description (And Equation) 162
6-3 The Moon Orbital Apogee Radius Analysis 178
6-4 Can Uranus Motion Effect On The Moon Motion? 184
6-5 The Moon Daily Displacement Analysis 188
6-6 The Moon And Mercury Motions Data Analysis 193
6-7 The Moon And Pluto Motions Data Consistency 196
6-8 Uranus Motion Effect On Pluto Motion 204
6-9 The Moon Orbital Apogee Radius Decreasing Details 207
6-10- Jupiter Motion Effect On Earth And Venus Motions
6-10-1 Preface
6-10-2 Jupiter Motion Effect On Earth And Venus Motions
211
212
216

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6-10-3 Jupiter Orbital Circumference Analysis
6-10-4 Saturn Velocity Analysis
6-10-5 The Solar System Creation and Motion Theory
220
223
236
7- The Solar Planets Motions Use Different Rates Of Time 241
7-1 Preface 242
7-2 The Planets Motions Rates Of Time 244
8- The Solar Planets Rates Of Time Analysis 248
8-1 Preface 249
8-2 Venus Motion Rate of time 250
8-3 Earth Motion Rate of time 252
8-4 Mars Motion Rate of time 254
8-5 Jupiter Motion Rate of time 256
8-6 Saturn Motion Rate of time 258
8-7 Uranus Motion Rate of time 260
8-8 Neptune Motion Rate of time 262
8-9 Pluto Motion Rate of time 264
8-10 The Planets Orbital Distances Test 266
8-11 One Law Controls The Planets Orbital Periods And Distances 271
8-12 The General Discussion 272
9- The Planets Motions Rates Of Time Effect Analysis 275
9-1 Preface 276
9-2 Planets Motions Rates Of Time And Distances Data 277
9-3 The Data Equal Distances 281
9-4 The Data and the planets velocities. 289
9-5 The Data Distances And Rates Of Time Interaction 293
9-6 The Data General Discussion 303
9-7 Mars, Jupiter and Saturn Motions Analysis 305
9-8 Why Saturn And The Moon Use Equal Rates Of Time? 310
9-9 Why Mercury Use A Double Of Its Orbital Distance? 315
9-10 The Rate (4.61) be used between Pluto and the moon motion 316
10- Mars Migration Theory 320
10-1 Mars Migration Theory 321
10-2 Pluto Migration Theory 324
10-3 Planets Migration Theories Proves 326
10-4 Is There An Absent Planet In The Solar Group? 329
11-The Solar System Distances Be Created In A Network Form 332
11-1 Preface 333
11-2 The Continuum effect Through the Solar System Distances 335
11-3 The Solar System Distances Distribution 340
11-4 The Solar System Distances Dependency On One Another 344
12- The Continuum Effect Proof 346
12-1 The Continuum Effect Proof 347

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12-2 Saturn Motion Analysis 353
12-3 Planet Diameter Analysis 379
12-4 Why do the planets revolve around the sun if there's no sun gravity? 381
13- Planet Mass Effect On its Motion 382
13-1 Preface 383
13-2 Planet Mass effect on its Motion 385
13-3 Saturn and Earth Motions Interaction 396
13-4 Planets Velocities Proportionality 405
14- Saturn Motion Analysis 413
14-1 Preface 414
14-2 Saturn Diameter Analysis 416
14-3 Neptune Circumference Analysis 426
14-4 Neptune Day Period Analysis 435
14-5 Mercury Motion effect on Jupiter and Neptune Motions 444
14-6 Earth Motion Distance Daily Analysis 451
14-7 Uranus Day Period Analysis 455
14-8 The Inner Planets Motions Analysis 461
15- The Sun Age Description 469
15-1 Preface 470
15-2 The Sun Circles The Earth 471
15-3The Rate (1.0725) 472
15-4 The Sun Diameter Analysis 475
15-5 The Sun And Earth Motions Rate Of Time (1 day =365.25 days) 478
15-6 The Sun Rays Creation 486
16- Mercury Jupiter Distance Analysis 492
16-1 Mercury Jupiter Distance Analysis (720.7 mkm) 493
16-2 (Jupiter And Mercury Motions Analysis) 506
16-3 Jupiter Distances Analysis 510
Appendix No.1 The Solar System Equal Distances List 511
Claims Be Sent Against The Decision Of Nobel Prize For Physics 2021 513
References and Biography 518

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1- Introduction
- Again we have to ask
- Why Newton Theory of the sun mass gravity is mistaken?
- There are 4 reasons for that let's explain them in following:
- (1st
Reason) (The Gravitation Equation Is Wrong)
- The equation contradict the planets orbital distances for that reason the planets
order contradicts the equation – this is an old question – and its answer usually be
(because of the planets initial conditions)
- My (1st
) Equation defines each planet orbital distance simply and we can't find
these initial conditions – let's refer to my first equation in following:
- d2
= 4d0 (d-d0)
- d = A Planet Orbital Distance
- d0= Its Direct Previous Neighbor Planet Orbital Distance
- Example no. (1) Venus Motion
- d = 108.2 mkm (Venus Orbital Distance)
- d0 = 57.9 mkm (Mercury Orbital Distance)
- (108.2)2
= 4 x 57.9 x (108.2-57.9) Venus depends on Mercury
- The idea is clear
- The gravitation equation has only the 2 masses and the distance between them by
that the equation fails to define the distance between the 2 masses while other
equations can – that disproves the equation simply
- (Notice/ Bode law also defines 8 planets orbital distance correctly)
- The proof is strong proof because the equation fails to do the dimensions for which
it be created – so it's a wrong equation
- (2nd
Reason) (The Theory Logic Is Wrong)
- Newton told that, the planet be created by some unknown force by which the
planet data be created – and the sun gravity forces this planet to revolve around it

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- Here we have 2 forces
- The Creation Force And The Motion Force –
- Why these 2 forces are in harmony with one another? why don't they conflict one
another? and if they conflict one another why the planet doesn't break into pieces?
- It's a wrong logic to imagine that the creation force is different from the motion
force – If these 2 forces aren't unified into one force this planet will be destroyed-
- Here, again we catch a real point in logic against Newton theory of the sun gravity,
the planets motions harmony can't be performed unless one force only caused the
planet to be created and caused its motion –
- (3rd
Reason) (The Theory Contradicts The Planet Data Context)
- How be planet data created?
- I claim, Planet data be created based on Exact Equations!
- What does mean exact equations?
- My (1st
) equation proves that each planet orbital distance is a function in its
neighbor planet orbital distance
- Kepler laws proves that each planet velocity is a function in this planet orbital
distance (means, planet orbital distance defines its velocity)
- My (2nd
) equation proves that each planet diameter and rotation period (together)
be function in the rate of this planet velocity to another planet velocity and
- My (2nd
) equation also proves that each planet orbital inclination be a function in
the rate of this planet velocity to another planet velocity
- My (3rd
) equation proves that each planet velocity be complementary to another
planet velocity and their rate be a function in the distance 1.16 million km
- I want to say
- Planets data analysis gives different proves explaining how planet data be created
– let's summarize that in following:

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- Planet orbital distance be defined at first and based on it the planet velocity be
defined and based on the velocity planet orbital inclination, diameter and rotation
period be defined and based on planet orbital inclination the planet mass be
defined
- This context of data creation we should discuss in this paper (point no.3-2)
- Here we have a completely different vision from Newton Description because
Newton idea about (how planet data be created?) is typically similar to the big
bang theory – no one thinks that planet data be created based on exact equations –
they imagined that the planet data be created by some random factors and
historical unknown events – here's one more mistake we catch – because the
planets motions harmony can't be performed if the planets data be created by
random factors – in more clear words – if the planets data isn't created based on
exact equations and mathematical calculations the motions harmony can't be
performed – otherwise these planets will be destroyed –
- Newton didn't see at all planet data context – instead – he choose the mass and
decided it's the motion reason –
- I try to show that, planets data analysis gives a different vision for the solar system
creation – and even for the matter creation generally from Newton description and
many current visions – one new chapter in the physics book be opened by the
planets data analysis –
- The basic point on which the argument depends is planet data because we have to
ask at first how planet data be created? and where this question still had no answer
for long time many imaginary ideas be found as physics theories – planet data
analysis gives a real light to understand how the solar system be created and
moving.
- (4th
Reason) (Space Creation)
- How be the space created? is it created with matter or independently?
- The question can be asked in another form

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- Is the matter created in static or motion case?
- That makes the space belonged to the matter creation process – if we accept that –
the matter is created in motion –
- This meaning we conclude form planet data context, because planet orbital
distance be defined before the planet data by that the space be found before the
matter creation but for the matter creation –
- Let's take a look on the paper contents
- The Paper Discovery (3 equations) be discussed in point no. (3)
- Light motion effect on planet motion be discussed in points no. (4 and 5)
- Point No. (4) Provides the Data Only and Points No. (5) Provides The Discussion
- (The Solar System One Geometrical Design Be Discussed In Point No. 5-5)
- The Moon Orbital Apogee Radius Be Analyzed In Point no. (6)
- The Solar Planets Motions Use Different Rates Of Time
(Be discussed in points no. 7-8-9 of this paper)
- Mars Migration Theory (Be discussed in point no. 10 of this paper)
- The Solar System Distances Be Created In A Network Form
(Be discussed in point no. 11 and 12 of this paper)
- Planet Mass Effect On its Motion (Be discussed in point no. 13 of this paper)
- Saturn Motion Analysis (Be discussed in point no. 14 of this paper)
- The Sun Age Description (Be discussed in point no. 15 of this paper)

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2- Methodology
- I use the planets data analysis to discover the solar system creation and motion
facts – The method is so useful.
- The method simply put the planets data in comparison with the theory and tries to
know if there's a consistency between both – let's use one example to explain how
this method works
- An Example (Mars Migration Theory)
- Giant-Impact hypothesis tells that, a planet in Mars Size had collided with the
Earth and caused the moon creation.
- Can Mars Itself do that? NO
- The theory tells no hope Mars itself did this collision – So what does the data tell?
- If the planets be found in order –Mars position should be after Mercury –because
the 4 planets (Mercury – Mars – Venus – Earth) be in order for their diameters,
masses and orbital distances –this data suggests that Mars position was the second
planet between Mercury and Venus and Mars may be migrant from its original
orbital distance!
- Let's move with this hypothesis for a while
- Suppose Mars was the second planet after Mercury and had migrated to its current
point (227.9 million km) what would happen? Mars had collided with Venus and
then with Earth –
- Giant-Impact hypothesis asks why Venus has no its own moon spite it had suffered
of a collision similar to the Earth? the answer is a simple one
- Imagine Mars was the second planet after Mercury (84 mkm) and had migrated to
its current position (227.9 mkm), in its displacement, Mars was pushing by force
and had collided with Venus and pushed all debris with it in its motion direction
- Venus found no debris around – for that Venus couldn't create its own moon-

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- Another question asks about (the origin of the lunar magma ocean!) Venus, The
Lunar Magma Ocean is came from Venus, it's a part of Venus found by the
collision between Mars and Venus but Mars had pushed all debris with it in its
motion direction and left Venus without debris
- Earth gravity is greater than Venus and the debris lost some of their momentum
and by that the Earth could create its own moon where the moon rocks are
consisted of Venus, Earth and Mars debris
- The fact Mars has 2 moons is one more proof for this idea, because Mars with
small mass could attract 2 moons and Venus couldn't.
- The rest debris be attracted by Jupiter and consisted the asteroid belt
- The planets data analysis put the facts beside one another and by that the vision be
more clear
- (Mars Migration Theory be discussed in Point no. 10 of this paper)

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3- Planet Data Creation Description
3-1 Preface
3-2 How Be Planet Data Created?
Equation)
3-4 Kepler Laws Analysis
Equation)
3-6 Planet Velocity Equation (My 3rd
Equation)
3-7 More Analysis For My 3 Equations
3-8 More Discussion (Questions And Answers)

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3-1 Preface
- In This Point We Have 3 Jobs Which Are:
- (1st
Job) Planets data be created based on exact equations and mathematical
calculations (My Claim)
- What does that mean?
- Means,
- If we know that (Mercury orbital distance = 57.9 million km) with this one data
only and by using my (3 equations) in addition to (Kepler laws) we can conclude
theoretically All Planets orbital distances, periods, velocities, inclinations, rotation
periods, diameters, masses and axial tilts…
- Shortly
- The planets all data should be concluded theoretically without observation by
using this one data only
- If we can do that – this will be a real proof for my claim (Planets Data Be
Created Based On Exact Equations And Mathematical Calculations)
- (2nd
Job) We discuss how each planet data be created – in its Context!
- What does mean "In Its Context"?
- I claim - For example - Planet orbital distance be defined before this planet
diameter be defined! – this is a context – how the process be done? And in what
order? How to prove this order is the real one?
- Shortly
- In this point, we put the proves beside each other to see how any planet data be
created and how to prove this data creation order
- And
- (3rd
Job) A New Vision Should Be Resulted Accordingly–
- because –

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- Planets data be created based on exact equations and mathematical calculations,
so, the physics book will remove (random unknown factors and initial conditions),
because these reasons have no effect on planet data creation – We need a new
vision explains why planet data be created based on exact equations and
mathematical calculations…
- What vision can explain this fact? Let's summarize this vision in following…
- The Solar Group is similar to a machine of gears each planet is a gear in it, or
- The Solar Group is similar to one building and each planet is a story in this same
building, or
- The Solar Group is similar to puppets theater, all puppets are connected together
by one force and causes their motions, or
- The Solar Group is similar to water moves through a canal and causes the rotation
of 9 waterwheels. The waterwheels Motion Direction is different from the water
motion direction but no waterwheel can rotate without the water motion, or
- The solar planets are similar to train carriages, they move together one unified
general motion, or
- The solar planets be similar to knots on one robe or similar to points on the same
one trajectory of energy – or
- The solar planets motions be similar to chess board pieces motions, each motion
depend on the other planets motions and be done by geometrical calculations
- Notice
- My Theory of The solar system creation and motion explains this vision, But
- I don't provide the theory and then try to prove it – instead – I analyze planets
creation and motion data, and by this analysis I try to prove that my theory can be
the suitable answer to explain how these planets data be created – by that – planets
data itself be the proves for my theory.

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3-2 How Planet Data Be Created?
- Let's summarize the idea in following…
- (1)
- Planet defines at first its orbital distance and
- Based on planet orbital distance this planet velocity be defined
- The rate between 2 planets velocities are so useful because, based on it
- (a)
- Planet orbital inclination be defined and
- (b)
- Planet diameter be rated to planet rotation period –
- Then
- Planet masses rate be defined based on these planets orbital inclinations
- This description of planet data creation depends on the theoretical understanding
of the equations based on which planet data be created –
- I have 3 equations and I use Kepler law in one more equation – by that – planet
data creation depends on 4 equations – one of them belong to Kepler law –
- Let's see these equations in following
- My (1st
Equation) d2
= 4d0 ( d- d0)
- the equation tells each planet orbital distance depends on its neighbor
- (Kepler Law) Equation (v1/v2)2
= (d2/d1)
- v = Planet Velocity d= Planet Orbital Distance
- The equation tells planet orbit defines its velocity
- My (2nd

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- The equation tells based on planets velocities rate, planet diameter and its rotation
period be defined-
- My (3rd
- The equation tells the planets velocities are complementary one another based on
the rate 322 – that needs a deep analysis to know why –
- (2)
- Let's try to conclude Neptune data based on these 4 equations
- (A)
- By My (1st
Equation) d2
= 4d0 ( d- d0)
- (4495 mkm)2
= 4 x 2872 mkm ( 4495 mkm – 2872 mkm) (error 4%)
- Where
- 4495 million km = Neptune Orbital Distance
- 2872 million km = Uranus Orbital Distance
- Neptune depends on Uranus
- Neptune is the greatest error in my equation (4%) and Earth is (2.8 %), any other
planet has an error less than (1%)
- (B)
- By Kepler Law equation (v1/v2)2
= (d2/d1)
- (4495 mkm /2872 mkm) = (6.8/5.4)2
- Where
- 6.8 km/s = Uranus Velocity
- 5.4 km/s = Neptune Velocity
- And Also
- (v1/v2)2
= (d2/d1) can be used as (4495 mkm /1433 mkm) = (9.7/5.4)2
(error 1.4%)
- 1433 million km = Saturn Orbital Distance
- 9.7 km /s = Saturn velocity

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- (C)
- My (2nd
- (89143 /49528) = (9.7 /5.4) =1.8
- Neptune Orbital Period (59800 days) has 89143 Neptune rotation periods (16.1 h)
- 49528 km = Neptune Diameter
- 9.7 km/s = Saturn Velocity
- The data follows the rule perfectly – error less than 1%
- Also
- 9.7 /5.4 = 1.8 where 1.8 degrees = Neptune Orbital Inclination
- These equations are discussed and tested deeply in the next points.
- (3) Notice
- The question –
- How can planet orbital distance be defined before this planet diameter to be
defined or created?
- We can't answer this question here – because we analyze the data –
- As in the detective stories, you can't tell who's the murder unless you analyze the
data, the point here concerns the vision – because – some people see the mirage
and think it's a water – Here we save our thinking from the imagination by analysis
of planet data itself – simply – if it's impossible to define planet orbital distance
before this planet diameter definition the data will show this inconsistency – but if
the data shows harmony – that may force us to find the relationship between planet
orbital distance and its diameter…
- Shortly – we analyze the data and after we provide answers – no prepared answers
are available

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Equation)
- d0= Its Direct Previous Neighbor Planet Orbital Distance
(1) Venus Motion
- d = 108.2 mkm (Venus Orbital Distance)
- (108.2)2
= 4 x 57.9 x (108.2-57.9)
- Venus depends on Mercury
(2) Earth Motion
- d = 149.6 mkm (Earth Orbital Distance)
- (149.6)2
= 4 x 57.9 x (149.6-57.9) (error 2.8%)
- Earth depends on Mercury and doesn't on Venus
(3) Mars Motion
- d = 227.9 mkm (Mars Orbital Distance)
- d0 = 108.2 mkm (Venus Orbital Distance)
- (227.9)2
= 4 x 108.2 x (227.9-108.2)
- Mars depends on Venus and doesn't on Earth
(4) Ceres Motion
- d = 415 mkm (Ceres Orbital Distance)
- d0 = 227.9 mkm (Mars Orbital Distance)
- (415)2
= 4 x 227.9 x (415-227.9)
- Ceres depends on Mars
)
(
4 0
0
2
d
d
d
d −
=

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(5) Jupiter Motion
- d = 778.6 mkm (Jupiter Orbital Distance)
- d0= 415 mkm (Ceres Orbital Distance)
- (778.6)2
= 4 x 415 x (778.6- 415)
- Jupiter depends on Ceres
(6) Saturn Motion
- d = 1433.5 mkm (Saturn Orbital Distance)
- d0 = 778.6 mkm (Jupiter Orbital Distance)
- (1433.5)2 = 4 x 778.6 x (1433.5- 778.6)
- Saturn depends on Jupiter
(7) Uranus Motion
- d = 2872.5 mkm (Uranus Orbital Distance)
- d0 = 1433.5 mkm (Saturn Orbital Distance)
- (2872.5)2
= 4 x 1433.5 x (2872.5- 1433.5)
- Uranus depends on Saturn
(8) Neptune Motion (error 4%)
- d = 4495.1 mkm (Neptune Orbital Distance)
- d0 = 2872.5 mkm (Uranus Orbital Distance)
- (4495.1)2
= 4 x 2872.5 x (4495.1- 2872.5)
- Neptune depends on Uranus
(9) Pluto Motion
- d = 5906 mkm (Pluto Orbital Distance)
- 4495.1 mkm (Neptune Orbital Distance)
- (5906)2
= 4 x 2872.5 x (5906- 2872.5)
- Pluto depends on Uranus
- Notice the error is less 1% for all planets except (Earth 2.8%) and Neptune (4%)

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Discussion
(1)
- Kepler laws tell, planet orbital distance defines its orbital velocity, this is a
description of the planet motion effect on its data -
- But
- Kepler laws create partitions between planets each other – Kepler didn't tell how
the planets orbital distances or periods be rated to one another
- My (1st
) Equation provides the required extension.
- And by this equation we can conclude theoretically all planets orbital distances
based on one data only which is (Mercury orbital distance = 57.9 million km), by
this one data only, and by using my (1st
Equation) we conclude theoretically all
planets orbital distances – as we have seen in the previous data
(2)
- My (1st
) Equation has 3 exceptions, (Earth depends on Mercury Not Venus, Mars
depends on Venus Not Earth and Pluto depends on Uranus Not Neptune)
- The equation works sufficiently with all planets orbital distances with errors be
less than (1%) except with the Earth (error 2.8%) and Neptune (error 4%)
- The equation depends on the planets order because (Each planet depends on its
previous direct neighbor Planet)
(3)
- The equation tells
- The distance from The Sun to Pluto be distributed geometrically based on (One
Design). This Distribution doesn't depend on any planet data, the equation simply
defines points for the planets positions regardless these planets data- each planet
depends on its neighbor (position) and not (any other data).
- The equation gives a reason for the idea (the solar system depends on one design)
because the planets distribution be done in one group and not individually
- By that

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- We can conclude simply that, Planets orbital distances be created together in one
network form and not individually – that's seen clearly from the equation -
- Notice
- The planets order doesn't follow the gravitation equation – we have noticed that
before- as example – the 3 planets (Mercury – Venus – Earth) show that greater
mass (or diameter) necessitates longer orbital distance and not shorter –
- When we have asked why the planets order doesn't follow the gravitation equation
– the answer was because of the initial conditions –
- Where are these initial condition? My Equation defines each planet orbital distance
simply.
- Also (bode law defined 8 planets orbital distances correctly) – I add this notice to
disprove the claim of (Planets Initial Conditions) –it's simply a wrong idea and it's
used to cover the gravitation equation which we can consider as a wrong equation
because it fails to conclude the dimensions for which it's created
- Shortly
- The proof of the sun gravity effect on planet motion should be (Planet orbital
distance) and (planet velocity), but both values contradict the gravitation equation
– why this equation is correct? – based on what proof? Where the used laws in the
planets motions explanation is Kepler laws – that raises the question (what role be
found for the gravitation equation?)

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3-4 Kepler Laws Analysis
- v = Planet Velocity
- Example
- (108.2 mkm /57.9 mkm) = (47.4 /35)2
(error 1.8%)
- Where
- 108.2 million km = Venus Orbital Distance
- 57.9 million km = Mercury Orbital Distance
- 35 km/s = Venus Velocity
- 47.4 km/s = Mercury Velocity
- Kepler Law tells (Planet Orbit Defines Its Velocity), this meaning we can conclude
from Kepler 3rd
law – means– If we know that – Mercury orbital distance= 57.9
million km, by Kepler laws we can conclude its orbital period 88 days and its
velocity 47.4 km/s
- As a result
- We conclude this equation in which planets orbital distances and velocities be
rated
- Why do we need this equation? Because it's a simple treasure
(1)
- By My (1st
Equation) - we can conclude all planets orbital distances by using one
data only which is (Mercury Orbital Distance = 57.9 million km) – and
- By this equation (of Kepler Law) we can conclude all planets orbital periods and
velocities – it's a treasure
- We need one data by observation (Mercury Orbital Distance = 57.9 million km)
and based on this data (Theoretically without observation) we conclude 27 data -
- (2)
- The rate (v1/ v2) is the most important rate in the data because based on which
many important data be created – as be seen in my next equation
2
1
2
2
1
)
(
v
v
d
d
=

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Equation)
v1 = planet velocity in second
v2 = another planet velocity in second
r = Planet Diameter of one planet of the 2
s = The Planet Rotation Periods Number In Its Orbital Period
(This value is belonged to the planet whose diameter is "r")
I = Planet Orbital Inclination (of the planet whose diameter is "r")
Notice / The equation doesn't depend on the planets order
Example No. (1) (Neptune Equation)
(89143 /49528) = (9.7 /5.4) =1.8
- Neptune Orbital Period (59800 days) has 89143 Neptune rotation periods (16.1 h)
- 49528 km = Neptune Diameter
- The data follows the rule perfectly – error less than 1%
- Also
- 9.7 /5.4 = 1.8 where 1.8 degrees = Neptune Orbital Inclination
Example No. (2) (Earth Equation)
(366.77 /12756 km) = (4.7) / (29.8 x 5.6) =0.029 (error 2%)
- Where
- 366.77 = The Earth has 366.77 Rotation Periods In Its Orbital Period
- 12756 km = The Earth Diameter
- 29.8 km/s = Earth Velocity
- 4.7 km/s = Pluto Velocity
Example No. (3) (Mars Equation)
671/6792 = (4.7 /24.1 x 2) = 0.098 (error 1.3%)
I
r
s
v
v
=
=
2
1

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- 6792 km = Mars Diameter
- 24.1 km/s = Mars Velocity
- 671 = Mars Orbital Period (687 days) has 671 Mars rotation periods
- 24.6 hours = Mars Rotation Period
Example No. (4) (Uranus Equation)
(42683 /51118) = (5.4/6.8) = 0.8 (error 5%)
- Uranus Orbital Period (30589 days) has 42683 Uranus rotation periods (17.2h)
- 51118 km = Uranus Diameter
- 6.8 km/s = Uranus Velocity
- The data follows the equation sufficiently but with a great error (5%)
- 5.4/6.8 = 0.8 where 0.8 degrees = Uranus Orbital Inclination
Example No. (5) (Pluto Equation)
(14178 /2390) = (27.78/4.7) = 5.9
- Pluto Orbital Period (90560 solar days) has 14178 Pluto rotation periods (153.3 h)
- 2390 km = Pluto Diameter
- 27.78 km/s = The moon Velocity
- The data follows the rule perfectly
- The moon orbital inclination (5.1 degrees) is defined as a rate between its velocity
and Neptune velocity (27.78/5.4) = 5.1 = (Mars velocity / Pluto velocity)

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Jupiter and Saturn Equations
Example No. (6) (Saturn Equation)
(24106 x2 /120536) = (9.7 /24.1) =2.5
- Saturn Orbital Period (10747 solar days) has 24106 Saturn rotation periods (10.7h)
- 120536 km = Saturn Diameter
- 24.1 km/s = Mars Velocity
- 2.5 degrees = Saturn orbital inclination
- The equation uses the rate (2) for data configuration with more modification–
where this rate isn't used in the equation
Example No. (7) (Jupiter Equation)
(10500 / 142984) = (13.1/29.8 x 6) = 0.0734
- Jupiter Orbital Period (4331 solar days) has 10500 Jupiter rotation periods (9.9 h)
- 142984 km = Jupiter Diameter
- 13.1 km/s = Jupiter Velocity
- 29.8 km/s = Earth Velocity
- The data uses the rate (6) which isn't found in the equation!
- Notice
- The moon velocity = 27.78 km/s be proved in the moon orbital motion description
in point no. (6-2)

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Notice
(1) The Equation works from The Earth to Pluto Only
(2) The Equation Doesn’t Depend On The Planets Order
(3) I use Neptune data as first planet because it's a good example for the equation
using where Neptune uses no modification and causes no error – simply
accurate planet data.
(4) The five first planets (Earth, Mars, Uranus, Neptune, Pluto) follow the equation
perfectly and use the rate (s/r) as defined by the equation
(5) The five first planets (Earth, Mars, Uranus, Neptune, Pluto) cause a few
modifications for the equation which are, Earth uses the rate (5.6) Mars uses
the rate (2) and Uranus causes great error (5%)
(6) Earth equation produces the rate (0.029), Mars equation produces the rate
(0.098) and Pluto equation produces the rate (5.9) – all aren't planet orbital
inclinations (directly) and need more analysis
(7) The (2) last planets, Jupiter and Saturn cause modifications for the equation
and they use the rate (r/s) instead of (s/r)
(8) Also Saturn uses the rate (2) and Jupiter uses the rate (6) also Saturn data
produces 2.5 (Saturn orbital inclination) but Jupiter produces 0.073 which is
unknown value.
Questions
Why Does The Equation Work From The Earth To Pluto Only?
(This Question We Answer In The Following Discussion Of This Current Point)
Why do Jupiter and Saturn use a reflective equation (r/s) in place of (s/r)?
(This Question Be Answered In Point No. 3-7 in details)

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Discussion
- The equation analysis depends on the following questions:
- (1) How to explain the Planets Data Modification?
- (2) How Planet Rotation Period Be Defined?
- (3) Why does the equation use planet diameter as a player in it?
- (4) How Can Planet Diameter Be Defined Based On This Equation?
- (5) Why do Jupiter and Saturn equations use the rate (r/s) in place of (s/r)?
- (6) Why Mars and Pluto motions be related?
- (7) Why Earth and Pluto motions be related?
- Let's try to answer in following:
- (1) The Planets Data Modification Explanations
- For Earth
- The equation uses the rate (5.6) why?
- 5.6 degrees = 5.1 deg (the moon orbital inclination) + 0.5 deg (the moon diameter
angle) –
- The value 5.6 deg be = the moon orbital inclination when be measured above the
moon diameter.
- The data tells the rate (5.6) be used because of the moon motion effect on the Earth
motion –
- For Mars
- The equation uses the rate (2) why?
- Also for Saturn the equation uses this same rate (2), while we know, Mars orbital
circumference = 1433 million km = Saturn orbital distance – the rate (2) be created
for both planets by their motions interaction – where Mars velocity be used in
Saturn equation…
- For Jupiter
- The equation uses the rate (6) why? No available explanation yet

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- The Planets Orbital Inclinations
- For Earth
- The equation produces (0.029) why?
- (1/0.029) = 2 x 17.4
- 17.4 degrees = All Inner Planets Orbital Inclinations Total – please note
- (a)
- Earth Circumference = the total diameters of (Mercury + Venus+ Earth + the moon
+ Mars)
- (b)
- Earth Mass = The Masses total of (Mercury +Venus + Mars+ the moon) (error 1%)
- For Mars
- (1/0.098) = 2 x 5.1
- 5.1 degrees = The Moon orbital inclination – this data is useful for Mars because
- 7 deg (Mercury orbital inclination) = 1.9 deg (Mars orbital inclination) +5.1 deg
- For Pluto
- 5.6 deg x 2 + 5.9 deg = 17.1 deg (Pluto orbital inclination = 17.2 deg)
- Why Pluto data refers to the moon orbital inclination (5.6 deg = 5.1 +0.5)?
- Because a strong connection be found between Pluto motion on one side and the
Earth, its moon and Mars on the other side – as a proof for that – the moon
velocity be used in Pluto equation – and Pluto velocity be used in the Earth and
Mars equations
- The detailed discussion will show more interaction of data between these planets.
- I try to show, the equations produce planets orbital inclination but by indirect ways
which show the equation works sufficiently and be useful in the study.

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- (2) How Planet Rotation Period Be Defined?
- Let's try to guess
- Planet orbital velocity be defined by this planet orbital distance as proved by
Kepler laws
- Means, Planet orbital velocity be defined before its rotation period definition
- As a result,
- Planet rotation period should be a function in this planet circumference only, and
by this vision Earth rotation period should be 1345 s x 29.8 km/s = 40080 km
(40080 km = Earth Circumference)
- Not A Fact
- Earth rotation period is 23.9 hours = 64 x 1345 seconds (Why??)
- The only happy planet is Saturn
- Saturn (9.7 km/s) moves in its rotation period (10.7 hours) a distance = 373644 km
= Saturn Circumference 3786875 km (error 1.3%)
- Jupiter tries to use a similar behavior but the error Be (4%)
- Neptune behaves similarly but moves (2 x Neptune Circumferences) in a period =
Neptune rotation period
- Uranus moves a distance = (2.6 x Uranus Circumferences)
- There's a feeling that, these rates (1, 2 and 2.6) be found by geometrical reason and
not by pure coincidence!
- The question is, Why doesn't planet orbital velocity (v) equal this planet
rotational velocity (w)? – as in Saturn Case?

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- Some idea tells - Planet rotation period should be created by some random factors
and without any rule – for example – Earth and Venus data be almost very near but
their rotation periods are so different – that removes any hope to have a
mathematical rule controls the planets rotation period definition.
- My (2nd
) equation disproves this idea – on the contrary - By a mathematical
equation planet rotation period can be defined – and we should find explanation
for Venus rotation period (243 days) which is the most long rotation period in the
solar system.
- Notice
- Let's define the supposed rotation period for each planet
- Mercury needs 324 s to pass a distance = 15237 km = Mercury Circumference
- Venus needs 1087 s to pass a distance = 38025 km = Venus Circumference
- Earth needs 1345 s to pass a distance = 40080 km = Earth Circumference
- The moon needs 393 s to pass a distance = 10921 km = The moon Circumference
- Mars needs 886 s to pass a distance = 21346.6 km = Mars Circumference
- Jupiter needs 9.53 h to pass a distance = 44917 km = Jupiter Circumference
- Saturn needs 10.84 h to pass a distance = 378675 km = Saturn Circumference
- Uranus needs 6.56 h to pass a distance = 160592 km = Uranus Circumference
- Neptune needs 8 h to pass a distance = 155597 km = Neptune Circumference
- Pluto needs 1600 s to pass a distance = 7510 km = Pluto Circumference

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- (3) Why Does The Equation Use Planet Diameter?
- Planet diameter should be created as a function in this planet velocity (and motion
distance) because that will cause the diameter value to be in harmony with the
planet motion features –
- This is an important feature of planet motion – because – If planet creation data
contradicts its motion features – this planet will be destroyed
- That tells, The equation (v1/v2)= (s/r) is a very important one and it's used in the
planets creation process to create planet data in consistency with its motion
features –
- This analysis causes extension for our understanding about how the solar system
be created- where the big bang theory and historical records control any vision
concerning the planets creation details – our equation (v1/v2)= (s/r) gives more
light for our understating – where – a suggested question asks – why the planet
isn't destroyed after creation? why the planet motion be guaranteed in consistency
with planet creation data? or in more simple form, why planet circumference is in
consistency with its motion? –These questions can be solved by our equation
(v1/v2)= (s/r) where planet creation data be defined based on this planet motion
features and by that the child will be born in an environment can support its
growth.
- The facts give more extending vision, The planets are created almost by these
historical records- the moon creation is a good example– where the moon indeed
be created by a collision with The Earth –here – we don't refuse the historical
records - but –
- We have to correct the wrong conclusion
- While the historical records give us the feeling of the random creation of planets
data we have to notice the geometrical force be found in parallel and caused to
create the planets data based on exact equations and geometrical calculations.
- As a result

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- The moon diameter be 3475 km – not because of any historical records – but
- Because the moon diameter be created based on exact equations and mathematical
calculations-
- We shouldn't ask from where this geometrical force be found? because we need to
prove its existence before.
- Because this geometrical force causes to create one geometrical design for the
solar system and that caused to create the planets data based on exact equations
even if the planets be created resulting of planets collisions – as in the moon case-
- Notice
- The double production experiment can help our discussion – where – from Gamma
ray – an electron and a positron be created – the produced particles data be created
based on laws and not by any random process – and by that- each time the double
experiment be used the produced particles be electron and positron, 2 Particles
equal in Masses and different in charges.

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- (4) How Can Planet Diameter Be Defined Based On This Equation?
- (Notice/ this question be answered here but the answer be more clear in the point
3-7 discussion –by that –this answer should be considered a part of the point 3-7)
- I suppose the equation depends on one motion be designed geometrically. This
motion starts from the moon to Saturn –And
- I suppose the solar system motion be similar to a machine of gears each planet be a
gear in it – based on this vision – The motion be started from the moon to Saturn -
here the 2 planets be similar to 2 gears and the motion be transported between
these 2 planets. Let's explain this idea in details in following:
- (Point No. A)
- Because
- The Moon Orbital Period = The Moon Rotation Period
- (v/w) = (The Moon Orbital Distance / The Moon Radius) = 221
- v = The Moon Orbital Velocity
- w = The Moon Rotational Velocity - And - Because –
- Saturn (9.7 km/s) moves in its rotation period (10.7 h) a distance = Saturn
Circumference (1.3%)
- (v/w) =1
- The equation uses this rate (221) of the moon motion to make it (=1) for Saturn
motion – the rate is decreasing along the planets data reaching to Saturn! Why?
- Because
- (1) Planet Orbital Velocity Be = Planet Rotational Velocity and
- (2) Planet diameter be defined as a function in its velocity and motion distance
- The Equation Role
- The equation describes one motion be started by the moon and be completed by
Saturn – The motion be transported from a planet to another – and by this
transportation effect the equation causes planet diameter to be created as a function
in this planet velocity and motion distance.

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- (Point No. B) (The Moon and Saturn)
- The idea tells, the motion be started from the moon and be completed at Saturn,
Can That Refer To Specific Relationship Between The Moon And Saturn?
- The 2 planets motions data refer to this specific relationship
- The moon displacements total in a period 10747 days be = 940 mkm (Earth Orbital
Circumference) (error 0.6%) - Where
- The moon displacement daily = 88000 km
- Saturn Orbital Period = 10747 days
- That shows there's specific relationship between the moon and Saturn motions
because the 2 planets revolve each orbital circumference around the sun in this
period 10747 days.
- Also,
- The moon orbital inclination (5.1deg) = 2 x Saturn orbital inclination (2.5 deg)
(error 2%)
- Also,
- The moon and Saturn use equal rates of time, we discuss that in point no. (7 and 8)
of this paper
- (Notice Uranus motion analysis explain more interactions between Saturn and the
moon motions) (point No. 6)
- Notice : The idea supposes the motion be transported between the moon and
Saturn, here I don't try to prove the motion transportation among the planets or
how that be done- the point we discuss is that – the data be transported from a
planet to another – we don't discuss how (for now) but we discuss if it's a fact –
because the data passing through the planets motions cause the equation effect on
the planets rotation periods and diameters

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- (Point No. C)
- Now the motion starts from the moon to Saturn – as a result the solar group is
divided into 3 parts which are
- Part No. (1) (The moon – Venus – Mercury)
- Part No. (2) (Earth - Mars – Jupiter –Saturn)
- Part No. (3) (Uranus –Neptune – Pluto)
- Let's discuss each part individually
- Part No. (1) (The Moon – Venus – Mercury)
- Planet rotation period = (Planet Circumference)2
/ Planet Orbital Velocity
- Mercury rotation period 1407.6 hours = (15327 km)2
/47.4 (error 2%)
- Venus rotation period 5832.5 hours x 2 = (38025 km)2
/35 (error 1.6%)
- The moon rotation period 655.7 hours x 2 = (10921 km)2
/27.78 (error 10%)
- Where
- 47.4 km/s = Mercury velocity
- 35 km/s = Venus velocity
- 27.78 km/s = The moon velocity
- 15327 km = Mercury Circumference
- 38025 km = Venus Circumference
- 10921 km = The Moon Circumference
- Only the moon equation has an error (10%) but the 2 other planets data be defined
simply without great errors – We need to notice the following:
- (a)
- Venus Rotation Period 243 days = 1.0725 x 224.7 days (Venus Orbital Period)
- The moon day Period 29.53 days = 1.0725 x 27.3 days (the moon rotation Period)
- That tells
- (29.53/27.3) =(243/224.7)
- that connects The Moon And Venus Motions Data

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- (b)
- The Rate 1.0725 Be Used For 40% Of All Distances In The Solar System – and we
discuss this rate origin in details (Point no.6) and in appendix no. (1) of this paper.
(also this rate is the reason of the moon displacement) (Point no.6-2)
- This rate (1.0725) discussion tells the 2 values were equal –that means – the values
(224.7 days) and (243 days) were equal (243 days) and one of them be contracted
by this rate (1.0725) and be (224.7 days)
- Based on this vision, Venus Rotation Period Was = Venus Orbital Period
- And later, Venus orbital period be effected by the rate (1.0725) and that made it
=224.7 days only
- That tells Venus motion data be in consistency with the moon motion data, and
uses a similar behavior…
- Shortly, the moon and Venus behave a similar behavior their rotation periods=
their orbital periods, this feature be created here to be a starting point of the motion
which will be completed at Saturn…
- Means
- The equality of rotation period and orbital period doesn't depend on the moon
motion alone but supported also by Venus motion. that creates 2 gears (the moon
and Venus) to create this result (The 2 Periods Equality)
- Shortly/ the periods equality is a task be supported by the 3 planets motions data
(Mercury – Venus and The moon) -
- Notice
- 29.53 days = 27.32 days x 1.0725 that tells
- The moon day period 29.53 days was = the moon rotation period = the moon
orbital period – but – later the rotation and orbital periods be effected by the rate
(1.0725) and because of that their values be decreased to be (27.3 days) – both
values be under the effect of the rate (1.0725) and because of that they be equal –
while the moon day period be still out of this effect (29.53 days) -

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- Part No. (2) (Earth - Mars – Jupiter –Saturn)
- My Equation (v1/v2)= (s/r) starts from the Earth to Pluto – because it depends on
the rate (s) between planet orbital period and rotation period..
- We notice that
- Pluto velocity be used in Earth and Mars equations and
- The moon velocity be used in Pluto equation –
- That shows strong connection between the Earth, its moon and Mars motions on
one side and Pluto motion data on the other side-
- We notice that, the rest 3 planet (Uranus, Neptune and Pluto) be defined based on
Saturn data and by that the equation starts from the Earth to Pluto
- Jupiter and Saturn use reflected equation because they use (r/s) in place of (s/r) we
should discuss the reason of this using later ….
- Jupiter (13.1km/s) moves in its rotation period a distance = its circumference (error
4%)
- Saturn (9.7 km/s) moves in its rotation period a distance = its circumference (error
1.3%)
- Part No. (3) (Uranus –Neptune – Pluto)
- These 3 planets equations depend on Saturn equation – because of that
- Uranus orbital distance 2872 mkm = 2 x Saturn orbital distance 1433 mkm
- Neptune orbital distance 4495 mkm = π x Saturn orbital distance 1433 mkm
- Pluto orbital distance 5906 mkm = (1+π) x Saturn orbital distance 1433 mkm
- Saturn moves in its rotation period a distance = its circumference (error 1.3%)
- Uranus moves in its rotation period a distance = 2.6 x its circumference
- Neptune moves in its rotation period a distance = 2 x its circumference
- Pluto moves in its rotation period a distance =345.5 x its circumference

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- (Point No. D) (The Decreasing Rate)
- Where the moon orbital period= the moon rotation period, because of that,
- (v/w) =(The Moon Orbital Distance / The Moon Radius) =221
- Saturn (9.7 km/s) moves in its rotation period a distance = its circumference, and
because of that, (v/w =1)
- v= Planet orbital velocity w= Planet Rotational Velocity
- The idea supposes that the rate 221 be decreasing gradually to 1 through the
motion transportation between the moon and Saturn through the between planets
- BUT : the rate (Planet Orbital Distance / Planet Radius) isn't decreased,
specially because
- (Mercury Orbital Distance/ Mercury Radius) = (Earth Orbital Distance/
Earth Radius) = (Saturn Orbital Distance/ Saturn Radius)
- By that it's hard to find the mentioned decreasing rate!! But
- Another decreasing rate be found which is (Planet Motion Distance In Its Day
Period In Comparison With This Planet Circumference)
- let's see this data in following:
- Mercury moves in its day period 720.7 mkm =47020 x Mercury Circumference
- Venus moves in its day period 353 mkm = 9283 x Venus Circumference
- The moon moves in its day period 2.598 mkm = 238 x the moon Circumference
- Earth moves in its day period 2.574 mkm = 64 x Earth Circumference
- Mars moves in its day period 2.082 mkm = 100 x Mars Circumference
- Jupiter moves in its day period (= rotation period) a distance = its Circumference
(error 4%)
- Saturn moves in its day period (= rotation period) a distance = its Circumference
(error 1.3%) - this is the decreasing rate we search for but that tells
- Some interaction is found inside the planets to create its cycles based on one
equation- the proves the idea – but need more analysis to see correctly how the
decreasing rate cause each planet rotation period and diameter to be created.

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(5) Why do Jupiter and Saturn equations use the rate (r/s) in place of (s/r)?
- I can provide 3 data for help
- (a)
- Saturn and Jupiter are the only 2 planets which move during their rotation periods
distances equal each planet circumference
- (b)
- Saturn and Jupiter are the only 2 planets whose data be used correctly for the
gravitation equation
- (c)
- The 2 planets their data be in consistency (together) with the moon and Mars
- (708.7 h) / (10.7 h) = (655.7h) / (9.9 h) and
- 708.7 h = The Moon Day Period 655.7 h = The Moon Rotation Period
- 1.3 deg +0.6 deg = 1.9 deg but 1.9 deg + 0.6 deg = 2.5 deg
- 1.3 deg = Jupiter Orbital Inclination
- 1.9 deg = Mars Orbital Inclination 2.5 deg = Saturn Orbital Inclination
- This question we should answer in point no. (3-7) of this current paper

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(6) Why Mars and Pluto motions be related?
Let's Try To Answer In Following:
(a)
- The inner planets required periods total = 235.8 days
- The outer planets required periods total = 31469 days
- The solar planets required periods total = 31705 days
- 31469 days = 133 x 235.8 days (error 0.4%)
(b)
- The inner planets orbital periods total = 1480 days
- The outer planets orbital periods total = 196027 days
- The solar planets orbital periods total = 197027 days
- The total 197027 days = 1480 days x 133
(c)
- The solar planets orbital distances total = 16030 mkm
- 16030 mkm = 53.99 x 2 x 149.6 mkm (Earth orbital distance) (error 1%)
- Where
- 53.99 mkm = the distance be passed by Pluto in 133 days
(d)
- 100733 mkm (= the solar planets orbital circumferences total) = 2π x 16030 mkm
- 2 x 197392 days (= the solar planets orbital Periods total) = 24.6 x 16030 mkm
- And
- Light supposed velocity (1.16mkm/s) travels during 2x 16030 s a distance =37100
mkm (= Pluto Orbital Circumference)
- Light known velocity (300000km/s) travels during 16030 s a distance =4810 mkm
(= Jupiter Orbital Circumference 4900 mkm error 2%)
- 1 hour of Mars Motion = 133 hours of Pluto motion
- Be discussed in point no.(7 and 8)

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- (7) Why Earth and Pluto motions be related?
- There's a deep relationship between the moon and Pluto motions data let's explain
this relationship in following…
- (I)
- 366560 km = 2390 km x 153.3 = 3475 km x 655.7/2π
- Where
- 366560 km = The outer planets diameters total
- 2390 km = Pluto diameter 3475 km = The moon diameter
- 153.3 hours = Pluto rotation period 655.7 hours = the moon rotation period
- I don't know how this data be defined – but the previous equation tells us some
relationship be found between the planet rotation period and its diameter – our data
tells a similar meaning –
- The data tells that – no surprise that – we have found the moon velocity be used in
Pluto equation –
- I have tried by all means to prove that a strong relationship be found between Pluto
and the moon motions and this relationship needs a new definition for the distance
and its effect on the planets motions.
- (II)
- 5906 mkm (Pluto orbital distance) = 940 mkm (Earth orbital circumference) x 6.3
- 153.3 hours (Pluto day period) =24hours (Earth Day Period) x6.3 (error 1.4%)
- 90560 days (Pluto orbital period) = 1461 days (Earth Cycle) x 6.3 x π2
- Pluto (4.7 km/s) moves during a solar day = 406000 km = apogee radius
- Pluto (4.7 km/s) moves during Pluto day 153.3 h = 2.5986 km = the moon
displacements Total during 29.53 days
- Earth moves during a solar day =2.574 mkm is different with 2.598 mkm by 1%
- 406000 km (Pluto motion daily) / (88000 km the moon displacement) = 4.61
- (708.7h the moon day period /153.3h Pluto day period) = 4.61
- (Notice sin 4.61 deg = 0.08)

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- Pluto day be created as a function in the moon cycles – the data proves that -
- Tan (12.19) x 708.7 hours = 153.3 hours (708.7 h = the moon day period)
- Tan (13.17) x 655.7 hours = 153.3 hours (655.7 h = the moon rotation period)
- (10.96 deg /1.7 deg) = (153.3 h /24 h) (error 1%)
- 13.177 degrees = The Moon Daily Motion Degrees
- 12.19 degrees = 13.177 degrees – 0.9856 degrees (Earth motion daily degrees)
- Pluto (4.7 km/s) moves during 88000 seconds a distance 413600 km
- Pluto (4.7 km/s) moves during 10.7 h (Saturn day period) a distance 181800 km
- (III)
- We have one more player should be enter this vision – Saturn-
- Saturn moves during its rotation period a distance = Saturn circumference (error 1.3%)
- Now we have 3 points of this trajectory of energy
- First point is the moon where (the moon rotation period = the moon orbital period)
- Second point is Saturn where (Saturn in motion distance in its rotation period =
Saturn circumference - error 1.3%)
- Third point is Pluto where (14178 be equal 14547)
- I try to tell that, these three points caused the equation to be working and by these
3 points (all planets diameters) be defined based on my (3rd
) equation
- We need more proves for this idea
- (VI) (The Distance 406000 km
- This distance may help our investigation - We have 3 players
- (1st
) The moon
- The distance 406000 km = the moon orbital apogee radius
- (2nd
) Pluto
- Pluto move in a solar day a distance = 406000 km
- (3rd
) Saturn
- 406000 km = 1.0725 x 378675 km (Saturn Circumference)

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- (The rate 1.0725 – this rate is the reason of the moon daily displacement 88000 km)
- (The rate 1.0725 be explained in this paper in point No.6)
- Notice
- 406000 km = the solar planets diameters total = 2 Jupiter diameters +1 Saturn
diameter
- But, 1 Jupiter diameter = 2 Jupiter circumferences – 2 Saturn circumferences
- Notice
- Many data can be concluded by using the planets orbital inclinations
- Because, the orbital inclinations be effected by 3 basic players which are
- (1) The Planets Masses Rates
- (2) The Planets Velocities Rates
- (3) The Planets Orbital Inclinations Configuration
- The point no. (3) can be understood by analysis of Mercury orbital inclination
- Mercury orbital inclination = 7 degrees = 1.9 degrees +5.1 degrees
- 1.9 degrees =Mars orbital inclination
- 5.1 degrees = The moon orbital inclination
- That means, the moon orbital inclination (5.1 deg) be created by effect of Mercury
and mars orbital inclinations configuration – that explains the idea –
- While the planets orbital inclinations be defined by effect of the planets velocities
rates and masses rates – the orbital inclinations themselves still need to create
configuration between each other to create a general harmony for planets motions
that causes the data to use the equation in distorted forms
- We discuss more details about the planets orbital inclinations and their masses
rates in point no. (13)

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3-6 Planet Velocity Equation (My 3rd Equation)
v1 = Planet Velocity
v2 = Another Planet Velocity
322 h = 1160000 seconds
The equation tells the planets velocities be created complementary one another
(The equation doesn't depend on the planets order)
- My (3rd
) Equation tells that
- Mercury (47.4 km/s) moves during 6.8 hours a distance = 1.16 million km
- Uranus (6.8 km/s) moves during 47.4 hours a distance = 1.16 million km
- Venus (35 km/s) moves during 2 x 4.7 hours a distance = 1.16 million km
- Pluto (4.7 km/s) moves during 2 x 35 hours a distance = 1.16 million km
- (error 2%)
- Earth (29.8 km/s) moves during 2 x 5.4 hours a distance = 1.16 million km
- Neptune (5.4 km/s) moves during 2 x 29.8 hours a distance = 1.16 million km
- Earth (29.8 km/s) moves during 2 x 5.4 hours a distance = 1.16 million km
- Neptune (5.4 km/s) moves during 2 x 29.8 hours a distance = 1.16 million km
- Mars (24.1 km/s) moves during 13.1 hours a distance = 1.16 million km
- Jupiter (13.1 km/s) moves during 24.1 hours a distance = 1.16 million km
- (Error 2%) (In fact Jupiter moves during 24.6 hours a distance 1.16 mkm)
- Venus (35 km/s) moves during 9.7 hours a distance = 1.16 million km
- Saturn (9.7 km/s) moves during 35 hours a distance = 1.16 million km
(error 5%)
322
2
1 =
v
v

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Discussion
- The equation creates a contradicting question, let's ask it in following…
- Kepler law tells, Planet orbital distance defines its velocity –that means – these
velocities are defined by their planets orbital distances!
- How can these velocities be complementary one another if they are defined based
on their orbital distances?
- Also
- Why they are complementary based on this distance 1.16 million km?
- That tells
- Because of this distance (1.16 million km), Kepler law be defined!
- means
- Because of this distance (1.16 million km) the planets motions law (P2
/d3
) = C is
defined. Why??
- Also we notice
- 322 x 2 = (25.4)2
- Where
- 25 = C in Kepler law when be used for the solar planets data
Notice
- I suppose that the solar planets and their distances be created of energy and this
energy be provided by one light beam its velocity 1.16 million km per second
- My (3rd
) equation tells, Kepler law ((p2
/d3
)= constant) be defined because the solar
system creation energy be provided by light beam its velocity 1.16 million km per
second – where this velocity be registered in the planets velocities data
- This discussion be completed in details in the point no. (3-7) in which I try to proe
that my three equations (ans also Kepler law) proves that planet motion depedns
on light motion.
- For that reason we have to complete this discussion in poinbt no. (3-7)

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3-7 More Analysis For My 3 Equations
- There are 4 questions we have left in my 3 equations discussions let's refer to them
in following
(I) The Left Questions
- My (1st
Equation) d2
= 4d0 ( d- d0)
- Why does each planet orbital distance depend on its neighbor planet orbital
distance?
- My (2nd
- Why Mercury, Venus and the moon rotation periods depend special equation
which is (planet circumference2
/ planet velocity) and doesn't depend on my 2nd
equation?
- And
- Why do Jupiter and Saturn data use a reflective equation by suing (r/s) in place
of (s/r)?
- My (3rd
- Why do planets velocities be complementary one another based on the rate 322?
- These three questions answers need to consider The Paper Hypotheses –
- Let's consider it in the next point

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(II) The Paper Hypotheses
- (1st
hypothesis)
- Planets Motions Depend On Light Motion –
- This hypothesis tells,
- Planet creation and motion data be created by light motion – and the planet motion
is what we see but it covers light motion found behind it –
- The planet itself is a point found on One Light Beam – and by that – the planet
creation and motion data depends on this light beam motion and be created by this
light beam motion
- Shortly
- The solar planets matters and their distances be created of energy and this energy
be provided by one light beam – and by that – the planet is a point on this light
beam (or trajectory of energy) – that's why the planet creation and motion data be
defined by this light beam motion –
- (2nd
hypothesis)
- There's a light beam its velocity = 1.16 million km per second
- The planets matters and distances are made of energy and this energy is registered
in the planets creation and motion data – the registered energy shows (frequently)
the velocity 1.16 million km per second –
- I want to say,
- The bank treasure is filled of money – but you need the key to open it –
- The solar system data key is the velocity 1.16 million km per second
- No planet data can be understandable without this velocity – I have no empirical
proof for this velocity – but – simply – the whole solar system data be built on it –
my job in this paper is to analyze the planets data to show that this data be created

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(by light motion) and this motion be done by (a velocity 1.16 million km per
second)
- Means,
- The objection against my hypothesis (a velocity 1.16 million km per second be
found) has no meaning – because – I have no another way to explain the source of
this velocity (1.16 mkm/s) which be found in all and any planet data – so – the
question isn't – if my hypothesis is a fact or not – the question should be if the
respectful reader has another method to explain the planets data in place of my
hypothesis of the velocity 1.16 mkm/s

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- A Comment
- In following we analyze the planets data to answer the four questions and prove
the hypotheses – this discussion be a summary for the point no. (4) of this current
paper – in that point (No. 4) the discussion be provided with more details but we
use this summary to answer the four questions.
- (1)
- Please note,
- The idea tells, planet creation and motion data be created by a light beam motion –
Now – we should notice that – we have to consider the light motion features side
by side with planets motions – as a result we can expect the distances values be
used as periods of time – also we can consider to use rates of time for motions –
- I want to say
- The planets data isn't so direct lead to light motion effect behind – it needs analysis
for the data – by that – we need to be patient with the data analysis to see how the
data be used for light motion and be used again for Planets motions –
- The good news is that – we should keep an eye on the velocity 1.16 mkm/sec, this
velocity is the key can lead us simply to the correct conclusions
- Means,
- 2 basic light velocities be used in the planets motions data which are (Light
supposed velocity 1.16 million km per second and light 0.3 million km per second)
- (2)
- Planets Data Analysis proves that, light motion be found behind planets motions,
by that,
- The planets be similar to ships sail over a sea, the ships are the planets and sea is
the light motion network – by that – the light motion causes the planets motions
- This picture needs more explanation, because
- The ships bodies are made of the sea water –we need to notice this fact because –
the planets matters are made of light beam energy –

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- Also
- The water passes through the ships bodies – as water passes through a glass bottle
and the bottle glass walls be created by the passing water through it- this is similar
to blood passes through a vein and this vein walls be created of this blood energy.
- The basic question behind this theory asks (how the matter be created?) and this
theory provides a good answer and it forces us to suppose that (No Space without
Matter) – because the matter is created out of light beam in motion and the space
be the necessary complementary component for the matter creation.
- (3)
- I summarize the ideas here before the discussion because the data analysis process
is a complex one and I don’t want the ideas be lost inside the data analysis process
- I want to say
- The solar system is a very rich and complex machine, the current theories are so
poor and unable to explain its motion – Light motion effect on planet motion
creates a new chapter in the solar system theory history – and this chapter will be a
sufficient one because light motion is so powerful and can provide the required
explanations for the solar system motion different features. Just we need to
discover the geometrical interactions between light and matter motions – where
these interactions depend on complex data we need to consider the data deeply.
- For example
- One second of light motion be equivalent = to one solar day of planet motion
- This rule I have concluded by Planets Data Analysis – based on it – All planets
orbital periods can be used in seconds units by light motion –
- I try to show that, light motion effect on planet motion, is a hypothesis creates a
change in the planets data reading and analysis, and we need to be patients as
possible because we have to conclude the rules of these interactions between light
and planet motions.

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(III) The Questions Answers
My (1st
Equation) d2
= 4d0 ( d- d0)
- (1st
question)
- Why does each planet orbital distance depend on its neighbor planet orbital
distance?
- Because the planets are points on the same light beam (or trajectory of energy) and
by that each planet orbital distance depends on its previous direct neighbor because
the light beam reach its neighbor before the planet
- (The Supposed Motion Direction Be From The Sun To Pluto)
- My (2nd
- (2nd
question), Why Mercury, Venus and the moon rotation periods depend
special equation which is (planet circumference2
/ planet velocity) and doesn't
depend on my 2nd
equation?
- Because the light motion has a closed circle between Mercury, Venus and the
moon. – The 3 planets motions data show a closed circle for them (they have some
independency from the other planets) – the data analysis will show that clearly –
- (3rd
question),Why Jupiter and Saturn data uses the rate (r/s) in place of (s/r)?
because
- It's light beam motion and some reflecting of energy be done at Saturn almost –
that may cause Saturn orbital distance to be = Uranus orbital distance
- My (3rd
- (4th
question) ,Why do planets velocities be complementary one another based on
the rate 322? -Because -
- 1160000 seconds = 3600 seconds (one hour) x 322, means, the light beam velocity
is 1.16 million km per second, the planets velocities be complementary one
another by this rate 322 - this light beam travels for one second a distance =
1160000 km which we see as 1160000 seconds and be = 322 hours

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(IV) The Data Analysis
- (Point No. 1)
- 100733 mkm = 2π x 16030 million km
- 197392 days = 4π x 16030 days (error 2%)
- Where
- 100733 million km = The Solar Planets Orbital Circumferences Total
- 197392 days = The Solar Planets Orbital Periods Total
- But
- Light supposed velocity (1.16 million km per second) travels a distance = 100733
million km in one solar day (86400 seconds) (error 1%)
- We have 2 reasons to suppose that, this data depends on mathematical system
which are (1st
) the value (16030) and (2nd
) the solar day (86400 s)
- What's the relationship between my (1st
) equation and the solar day?
- d2
= 4 d0 (d- d0)
- this is the distances equation–but –if we uses light supposed velocity (1.16 mkm/s)
to pass these distances we can find the periods of time and the equation will be as
following
- T2
= 4 T0 (T- T0)
- Light supposed velocity (1.16 mkm/s) needs a complete solar day (86400 s) to pass
a distance = 100733 million km (The Solar Planets Orbital Circumferences Total)
- The value T2
should be rated with the solar day (86400 s), by that,
- T2
= 86400 seconds and based on that (T = 293 seconds)
- We need to keep an eye on this period (293 s = 586s/2)
- Notice (1)
- Light known velocity (0.3 mkm/s) travels during 293s a distance =88 million km,
this distance we see as 88 solar days (Mercury orbital period)
- Light (0.3 mkm/s) travels during a solar day a distance = 25920 million km,
This distance we see as 25920 years (The precession cycle)

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- Notice (2)
- Light supposed velocity (1.16 mkm/s) needs (310 s) to pass 360 mkm
- Light supposed velocity (1.16 mkm/s) needs (1236 s) to pass 1433.5 mkm
- Where
- 360 million km = Mercury Orbital Circumference
- 680 million km = Venus Orbital Circumference
- 940 million km = Earth Orbital Circumference
- 1236 million km = Mars Orbital Circumference

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- (Point No. 2) (Mercury Is The Origin Point)
- Light supposed velocity (1.16 mkm/s) needs (310 s) to pass 360 million km
- Light known velocity (0.3 mkm/s) travels during (310 s) a distance = 93 mkm
(Notice 93 mkm x 2π= 586 million km)
- But
- If 1 mkm = 1 hour that means
- 93 mkm = 93 hours
- 93 hours = 334800 seconds
- Light known velocity (0.3 mkm/s) travels during 334800s a distance =100733
mkm
- The data tells
- The Planets Orbital Circumferences Total be (=100733 million km), depending on
Mercury orbital distance (= 57.9 mkm) –
- means-
- If Mercury orbital distance be changed the whole planets orbital distances total
will be changed as a result –
- This meaning we can conclude from the distances equation d2
= 4 d0 (d- d0)

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- (Point No. 3) (The Distance 4900 million km)
- 4900 million km= Jupiter Orbital Circumference
- This distance is the solar system basic distance generally – because – based on this
distance the solar system geometrical design be created.
- Let's explain that in following:
- (Point 3-1)
- Light known velocity (0.3 mkm/s) travels during 16330 s a distance 4900 mkm
- We remember that
- 100733 mkm = 2π x 16030 million km
- 197392 days = 4π x 16030 days (error 2%)
- The value 16030 is mentioned geometrically to be found in the planets total
distances and periods –
- The error can be reach to (4%) - that explains the origin of Neptune equation error
– that will be more clear later
- (Point 3-2)
- 4900 mkm = 4.095 mkm x 1200 = 3.024 mkm x 1620 = 2.4 mkm x 2042
- Where
- 4.095 mkm = Mercury Motion Distance Per A Soar Day
- 3.024 mkm = Venus Motion Distance Per A Soar Day
- 2.4 mkm = The Moon Motion Distance Per A Soar Day
- 1200 should be 1200 days
- The point is that
- Light supposed velocity (1.16 mkm/s) travels during 1200 seconds a distance = 2 x
680 million km (error 2.5%)

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- And
940 million km
- And
1200 million km (error 1.3%)
- This is the value be used by Mercury as 1200 days (1 mkm = 1 day)
- The data shows there's a closed Circle among Mercury, Venus and the moon and
that explains why their rotation periods depend on another equation and doesn't use
my 2nd
equation as the other planets –
- The light motion is the reason behind
- (Point 3-3)
- 100733 million km = 940 million km x 108.2 million km = 680 mkm x 149.6 mkm
(error 1%)
- Where
- 100733 million km = The Solar Planets Orbital Circumferences Total
- 149.6 million km = Earth Orbital Distance
- 108.2 million km = Earth Orbital Distance
- The data shows, the Planets Orbital Circumferences Total depends on the Earth
and Venus orbital circumferences – that shows one geometrical design behind.

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- (Point 3-4)
- 1200 mkm = 4.095 mkm x 293
- 4900 mkm = (4.095 mkm)2
x 293
- 886 mkm = 3.024 mkm x 293 = 1.138 mkm x 778.6
-
- Where
- 4.095 million km = Mercury motion distance during a solar day
- 3.024 million km = Venus motion distance during a solar day
- 1.138 million km = Jupiter motion distance during a solar day
- 778.6 million km = Jupiter Orbital distance
- Notice (1)
- (16330/1620)=(108.2/10.7)=(30.5/3.024) = (47.4/4.7)= (1200/119) = (12104/1200)
- Notice (2)
- 88+224.7+365.25+687+4331+10747 = 16443
- But
- 687 days = 16488 hours
- (16488/16443) =(361/360)

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Discussion
- Jupiter orbital circumference 4900 million km is the main part of the solar system
geometrical design based on which many basic data be defined – because many
rules are unknown many data still need to be explained
- But we can conclude that – the distance 4900 mkm- is the basic part in the soar
system geometrical design
- Also
- Earth and Venus are the basic 2 columns in the solar system geometry – we
concluded that because
- 100733 mkm = 940 mkm x 108.2 mkm = 680 mkm x 149.6 mkm
- The interesting data is that
- Venus And Earth Distances To Jupiter = Their Orbital Circumferences
- Jupiter Venus Distance =671 mkm = Venus orbital Circumferences (680 mkm )
(error 1.3%)
- Jupiter Earth Distance =929 mkm = Earth orbital Circumferences (940 mkm )
(error 1.3%)
- Notice, Jupiter Earth distance be = 929 mkm when the 2 planets be on 2 different
sides from the sun by that 929 mkm = 778.6 mkm +149.6 mkm
- We discuss that later in details
- Shortly, the data tells
- Mercury is the origin point
- Jupiter orbital circumference is the main circumference in the solar system
- Venus and Earth are the 2 basic motors of the machine

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- Point No. (4) (The Moon Motion Effect)
- (A)
- 4900 million km = 0.3 mkm/ s x 16330 seconds = 449197 km x 10921 km
- 449197 km = 27.78 km/s x 16330 seconds
- 680 million km = 1.16 mkm/ s x 586 seconds
- 16330 km = 27.78 km/s x 586 seconds
- (B)
- 10921 km = 27.78 km/s x 394 seconds
- 155597 km = (394 km)2
- But
- (86400 s/ 16030 s) = 5.4
- Where
- 4900 million km = Jupiter Orbital Circumference
- 449194 km = Jupiter Circumference
- 10921 km = The Moon Circumference
- 27.78 km/s = The moon velocity (proved in point no. 6-2)
- Notice
- More detailed discussions be in point no. (4) of This Current Paper.

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3-8 More Discussion (Questions And Answers)
Question No. 1
Why Doesn't The Planet Break After Its Creation?
- This question deepens our understanding about how the solar planets be created –
because- it asks
- Why be Planet Diameter in harmony with this planet motion Features?
- If a planet circumference contradicts this planet motion features that will lead to
destroy this planet – it will be as a wall be built in water – the water will destroy it-
it doesn't happen – The planets live millions of years and still in life – how to
explain that?
- The planet dimensions and data be created depending on this planet motion
features –Means- the creation process be a part of this planet motion – means
Planet motion be defined before this planet creation-
- No Hope Planet Motion Depends On Its Mass
- That tells why Newton theory of the sun gravity is mistaken – because – Newton
imagined – Planets be created (by unknown process) and their data be created (by
some historical events and unknown factors) –
- Then
- Newton theory of the sun mass gravity works on the created planet – it tells- The
planet be forced by the sun mass to move a specific motion – this motion is
defined by factors (aren't related to the creation process) –
- Here we catch the Newton Mistake
- Because Newton told there are 2 players effect on the planet motion- means- 2
sources of force – the force which caused the planet creation and the sun gravity
force which caused the planet motion –
- That tells simply the planet motion be a conflict point between these 2 forces – the
result should be the planet destruction
- Newton Theory Is Mistaken In Its Original Logic

We Should Refuse Newton Theory Of The Sun Mass Gravity.pdf

We Should Refuse Newton Theory Of The Sun Mass Gravity.pdf

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