Earth Motion Disproves Newton Theory Of The Sun Mass Gravity

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Earth Motion Disproves Newton Theory Of The Sun Mass Gravity
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –30th
July 2021
Abstract
Paper hypothesis
- Earth Be Found Before The Sun Creation
The Hypothesis Explanation
- The hypothesis tells that, The Earth is Older Than The Sun
- The ages question provides an essential modification for the physics basic theories,
- Because,
- If Earth be found and moving before the sun creation, that disproves clearly and
decisively Newton Theory of The Sun Mass Gravity.
- As a result, Earth and all other solar planets must move by a force different from
the sun mass gravity.
- But, how to prove that, the Earth is older than the sun? The event be found before
millions of years!
- Because the sun circles Earth and gives it one face only, that may prove the sun
data be created depending on Earth orbital period (365.25 days) which proves that
the sun must be created after the Earth creation.
Paper Objective
- The paper analyzes Earth orbital period to know Why The Sun Circles Earth.
Please scan the figure (ORCID)

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Paper Contents
Subject Page No.
1- Introduction 3
2- Methodology 5
3- The Sun Position Analysis 7
3-1 Preface 7
3-2 Is There A Geometrical Structure Behind The Sun Position? 8
3-3 Can the Sun moves (in frequentation) form? 12
3-4 Can a Perpendicularity Be Found Between The Sun And Venus Positions 13
4- Earth Orbital Period Analysis 15
4-1 Preface 15
4-2 Saturn Orbital Period Analysis 16
4-3 Earth orbital period analysis 21
5- The Sun Rays Be Produced By Planets Motions Energies Total 28
5-1 Preface 28
5-2 The Solar System Unified Motion 30
5-3 The Sun Rate Of Time 35
Appendix No.1 The Solar System Equal Distances List 42
References and Biography 44

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1-Introduction
- The paper provides one more decisive proof against Newton theory of The Sun
Mass Gravity
- The situation is complex because
- Newton Theory of the sun mass gravity is formed since around 400 years. No one
doubted during this long period that Newton is Mistaken!
- The great efforts of scientists are paid to explain how the sun causes the solar
planet motion. But no doubt be provided against the concept that the sun is NOT
the Reason of the solar planets motions.
- Einstein provided his general theory of relativity to create the required machine by
which the sun mass gravity causes the solar planets motions.
- Again, while years be passed, no doubt that Newton was mistaken in principle
- But,
- The planets motions data analysis shows clearly that, the sun isn't the reason of the
planets motions. The Sun Is Created After All Planets Creation.
- The fact pushes Newton Theory clearly and strongly out of the physics book,
But what about The General Theory Of Relativity?!
- The fact is (The Sun is NOT The Planets Motion Reason)
- Where
- The Sun Be Created After All Planets Creations And Motions
-
- One proof should be the fact that, the sun circles Earth and gives one face only to
her. Why? does this happen with other planets motions? what's the relationship
between the sun and Earth orbital period (365.25 days)? Because
- According to Newton description, Earth is a planet similar to the others, all of
them revolve around the sun by the Sun mass gravity force, so, the sun deal with
all planets equally. And then why the sun interest for the period 365.25 days?

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- The sun circles Earth is similar to the moon behavior which also circles Earth and
gives always the same face.
- The paper tries to show that, some geometrical mechanism be found behind and
causes the sun circles Earth. And this geometrical mechanism shows that the Sun
creation and motion data depends on Earth orbital period (365.25 days) which
proves that, Earth found before the sun creation and disproves decisively Newton
Theory of the sun mass gravity.
- Notice
- The paper discussion interests for the question (Why Does The Sun Circle The
Earth?)
- Through this question we can discover the geometrical effect of Earth orbital
period (365.25 days) on the sun creation data and as a result we can disprove
Newton theory of the sun mass gravity.

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2-Methodology
(I)
- I use the solar planets data analysis to discover the planets origin and motions.
- This method is so useful because it creates a comparison between the physics
theories and the planets data to show if the planets data follow the theories really.
- For example, we notice that, Jupiter is the 5th
planet in order to the sun, while the
gravitation equation tells (More Mass Needs Shorter Distance). Jupiter position
doesn't disprove the equation but refers to a contradiction needs explanation.
- That's the useful result of Planets Data Analysis Method using.
(II)
- I suppose the solar group is a machine of gears and each planet is a gear in it. or it's
one building and each planet is a part of it. this hypothesis leads us to conclude
that, the solar planets motions must create one unified motion. based on that the
solar planets motions can be similar to the train carriages move tougher one
unified motion we call it (Train Carriages Motion)
(III)
- Because the solar planets are parts in the same one building, their data be created
complementary with each and by that their motions be also complementary
creating together one unified motion.
- The best example to explain the (complementary data) is the double production
experiment. Where an electron be created with a positron from gamma ray, that
shows the 2 particles charges are created depending on each other because of the
charge reservation law. But the 2 particles move depend on their charges, means,
the 2 particles motions are still controlled by (Gamma ray features) and they move
complementary motions.
(IV)
- Based on this hypothesis, the solar planets data should be created complementary
with each other. means, There's One Equation Controls All Solar Planets Data

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- Let's discuss an example for better explanation.
- The Diameter =12430
- There's no a planet in the solar group its diameter =12430km, this number I have
invented it. let's test it to know if it has any effect on the solar system motion.
o The (supposed) diameter 12430 km in the one middle value between Venus
diameter (12104 km) and Earth diameter (12756 km).
o (Earth diameter / moon diameter) = (Jupiter diameter) / (12430 x π)
o Mars (24.1 km/s) moves during (12430 seconds) a distance = 300000 km =
light (0.3 mkm/s) motion distance for 1 second.
o Saturn (13.1 km/s) moves during (12430 seconds) a distance = 120536 km
= Saturn Diameter
- We compare between 2 visions.
- The classical vision tells that, the solar planets are rigid separated bodies revolve
around the sun independent in their creation and motion data from one another.
- We provide a new vision…
- The solar system is created based on One Geometrical Design, the planets are
parts in one building and their data (must) be complementary one another, Because
they are created based on geometrical rules. As in a triangle we know 2 angles (60
deg and 80 deg) what's the third one?
- The diameter 12430 km proves this vision. It behaves perfectly as similar as any
planet (real) diameter. let's remember
o Jupiter (13.1 km/s) moves during 10921 sec a distance = 142984 km (=
Jupiter diameter) where (10921 km = the Earth moon circumference)
o Uranus (6.8 km/s) moves during 7510 sec a distance = 51118 km (=Uranus
diameter) where (7510 km = Pluto circumference)
- Based on that, the (supposed) diameter 12430 km is designed based on the solar
system geometrical design but be not created.

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3- The Sun Position Analysis
3-1 Preface
3-2 Is There A Geometrical Structure Behind The Sun Position?
3-3 Can the Sun moves (in frequentation) form?
3-4 Can a Perpendicularity Be Found Between The Sun And Venus Positions
3-1 Preface
- In this point we analyze the sun position based on the available data.
- Because
- We test the current description about the solar planets motions
- For example
- We try to ask questions as the following
- Do all planets be on the same horizontal level relative one another?
- Is there any planet position be perpendicular on another planet position.
- We understand that, the planets orbital inclinations define these planets inclination
on the ecliptic
- But
- Is there no other factors can effect on the planets positions?
- This analysis aims to discover the sun position relative to the solar planets
motions.
- The paper supposes some modification may be required for the solar system
correct description and (its map) .

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3-2 Is There A Geometrical Structure Behind The Sun Position?
I-Data
(1)
150.6 mkm = 108.2 mkm (Venus Orbital Distance) x 1.392 mkm (The Sun Diameter)
(2)
57.63 mkm = 41.4 mkm (Venus Earth Distance) x 1.392 mkm (The Sun Diameter)
(3)
Sin (23.6 deg) x 257.8 mkm = 103.4 mkm
II-Discussion
Equation no. (1)
150.6 mkm = 108.2 mkm (Venus Orbital Distance) x 1.392 mkm (The Sun Diameter)
Earth Orbital Distance = 149.6 mkm (which is different from 150.6 mkm with 0.7%)
- Equation no. (1) tells that, Earth and Venus orbital distances are defined in
proportionality with the sun diameter. the equation tells clearly that, some
geometrical design must be found behind this data, and neither Earth orbital
distance nor Venus orbital distance can be created independent from one another.
also the sun diameter can't be independent accordingly.
- The meanings aren't easy to be explained, for that reason we move to the next
equation for better vision
Equation no. (2)
57.63 mkm = 41.4 mkm (Venus Earth Distance) x 1.392 mkm (The Sun Diameter)
- 57.9 mkm = Mercury Orbital Distance (different from 57.6 mkm with 0.5%)
- This equation confirms the same meaning…
- The orbital distances of Mercury, Venus and Earth are defined based on some
geometrical design takes into consideration the sun diameter (please remember,
these 3 planets define their orbital circumference to be = their distance to Jupiter)

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Equation no. (3)
Sin (23.6 deg) x 257.8 mkm = 103.4 mkm
- S= The Sun
- V = Venus
- E= The Earth
- ES = Earth Orbital Distance = 149.6 mkm
- SV = Venus Orbital Distance = 108.2 mkm
- EV = 103.4 mkm
- Notice
- The distance between Venus and Earth = 41.4 mkm and NOT 103.4 mkm. So how
this triangle be built?! We need to understand what's going on here….
- let's move step by step:
o Earth orbital distance 149.6 mkm + Venus orbital distance 108.2 mkm =
257.8 mkm (This distance be found when Earth and Venus be on 2 different
sides from the sun with an angle 180 degrees between the 3 players)
o 257.8 mkm x sin (23.6 deg) = 103.4 mkm (=EV distance In The Triangle)
o 23.45 deg = Earth axial tilt (has a difference with 23.6 deg be 1%)
o In our triangle (SEV) the angles be defined geometrically as following
o The Angle (S) = 43.6 degrees
o The Angle (V) = 90 degrees
o The Angle (E) = 46.4 degrees (= 2 x 23.2 deg = Earth Axial Tilt error 1%)
o Now let's analyze this triangle in following

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- Is this triangle (SEV) be an imaginary one? because the distance between Venus
and earth be 103.4 mkm and the real distance = 41.4 mkm?
- We see that, the distance between earth and Venus can be even = 257.8 mkm when
the 2 planets be on 2 different sides from the sun. So if the distance can be = 257.8
mkm, that means, it can be also 103.4 mkm. That means this triangle can't be an
imaginary one.
- Why this triangle is useful?
- Because the angle (E) = 2 x 23.2 degrees (Earth Axial Tilt) (error 1%)
- That tells, Earth axial tilt is produced by some interaction be found among Earth,
Venus and The Sun Data
- Notice
- One simple question we should ask, Why Venus angle =90 degrees? This
question is so hard to be answered now. We have to wait this answer later.
- What Useful Results We Get From This Triangle? 2 Basic Results
- (1st
Result)
- The triangle tells that, some geometrical design be used to produce the data of
Earth and Venus orbital distances in addition to the sun diameter. also Earth axial
tilt be defined in this interaction. The triangle tells some geometrical design be
found under this data. because of that this triangle is found as a part of this
geometrical design.
- (2nd
Result)
- The Sun Be Perpendicular On Venus Planet. Specially, the angle between the sun
position and Venus planet position is (90 degrees). By that the sun must be on
vertical axis (z-axis) while Venus moves on (x-y plain).
- This description of the sun position needs a deep analysis to know what's happened
or how this position be defined?

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Notice
41.6 mkm = 0.384 mkm x 108.2 mkm (Venus Orbital Distance)
- 41.4 mkm = Venus Earth Distance (different from 41.6 mkm with 0.4%)
- 0.384 mkm = The Earth Moon Orbital Distance
- The data tells, The Earth moon orbital distance also be defined accordingly
- The paper provides an interesting approach to explain the solar planets motions.
- While the solar planets motions description inherited from Newton Theory of the
sun mass gravity tells that each planet motion is independent from the other
planets motions. As a result each planet orbital distance be defined independently,
The suggested description tells that, each planet motion takes into consideration
the other planets motions.
- We here deal with a building found depending on one another. based on this
vision, because Venus orbital distance =108.2 mkm, that causes Earth orbital
distance to be 149.6 mkm
- And because of the 2 planets orbital distances be (108.2 mkm and 149.6 mkm) the
earth moon orbital distance be (0.384 mkm).
- The vision is completely different from what Newton told us. while Newton
supposed the space is limitless and can contain hundreds of planets moving with
effect on each other. the fact is the 9 planets motions effect on one another and
forces each planet to defined each motion in proportionality with the other planets.
The vision is different because Newton vision of (NO Effect) created separated
trajectories of motions. And based on this vision we see the planets as cars move in
track independently from one another (even the real cars can't be independent
because the track is the same one and all have to move in harmony otherwise they
will collide). The suggested description tells that, the motions be built as a building
and each motion depend on the other motions and by that they need one
geometrical design controls and manages all of them.

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3-3 Can the Sun moves (in frequentation) form?
- Let's discuss one interesting idea in following:
- Suppose the sun be found really on the axis (SV) with (90 degrees) on Venus
Planet Position.
- How Can The Sun Circle Earth In This Case?
- The sun can moves in (a frequentation form). That means, the sun moves forward
and backward (and not in circle). But because Earth in (under) the sun (vertically),
we see this motion as a circle motion.
- Specifically
- The sun moves forward and backward which can be considered as a rotation
around the sun axis with a percentage =63.7%
- As a result, this motion cause the sun pole declination to be =63.7 degrees
- That means, the sun moves a distance = 63.7% of its circumference 4.37 mkm
which be = 2.7836 mkm.
- This motion the sun does once every year and we see this motion as (the sun
circles the Earth).
- Notice (2.7836 mkm =1.0725 x 2.598 mkm)
- This idea depends on a hypothesis tells that, there's 90 degrees between the sun
and Venus. We should discuss if there's any proof for this perpendicularity.

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3-4 Can a Perpendicularity Be Found Between The Sun And Venus Positions
- This figure shows a suggested description for the solar planets positions
- S = The Sun
- V= Venus
- U = Uranus
- The line (180 degrees), means that,
- The sun and Uranus (both) are perpendicular on Venus on both 2 sides
and by that the 3 players be on one straight line.
- Based on what data this description be suggested? On the following
- Venus axial tilt 177.4 degrees + Venus orbital inclination 3.4 degrees =
180.8 degrees
- But
- 0.8 degrees = Uranus orbital inclination
- That means, the value (180.8 degrees = 0.8 deg +180 deg)
- And the 180 deg be shown on this line in the figure
- Can This Figure Shows Real Facts?
- I provide different data formed in geometrical forms trying to prove
that, a geometrical design must be found behind this data.
- I want to say that, the data which is found in different geometrical
forms can't be created by some pure coincidences but created based on
a geometrical design whose features are seen in different forms
- That's why this figure provides a support for the claim, some
perpendicularity is found between Venus and the sun potions.
V
U
S

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Notice
- The sun diameter 1.392 mkm = Venus diameter 12104 km x 115.2
- And
- The sun diameter 1.392 mkm = Mars diameter 6792 km x 205.2
- But
- 25.2 + 90 = 115.2 and 115.2 +90 =205.2
- That tells, the values (115.2 and 205.2) depends on 25.2
- Where
- 25.2 degrees = Mars Axial Tilt
- The important data here is that,
- In kepler third law in which (D3
= P2
x constant), the constant used for the solar
planets orbital distance and periods should be = 25
- I try to show that, a geometrical design be found behind this data.

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4- Earth Orbital Period Analysis
4-1 Preface
4-2 Saturn Orbital Period Analysis
4-3 Earth orbital period analysis
4-1 Preface
- In this point we analyze Earth orbital period to see f this period be used by any
other planet motion.
- For example
- 10747 Days (Saturn Orbital Period) = 365.25 Days x 29.53
- Where
- 29.53 days =The Earth Moon Day Period
- The data needs to be explained otherwise we should as pure coincidence of
numbers
- The paper idea is simple, it tries to now if the planets motions use the data
exchangeable and for what reason. If this conclusion is correct, the question will be
why Saturn orbital period depends on Earth orbital period?
- Let's try to answer in following…

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4-2 Saturn Orbital Period Analysis (10747 Days)
(I)
- The Earth Moon Displacement = 88000 km
- Earth Orbital Circumference = 940 mkm
- The data tells, the moon needs a periods =10747 days to pass a distance = 940
mkm by its daily displacement (88000 km) (error 0.6%)
- The data tells that, The Period 10747 Days Is Known Before Saturn Creation.
- We have to ask why, Saturn orbital period is a period known by the Earth moon
motion? we still search for a sufficient reason.
- But
- We know that, Earth is found before its moon, and the distance 940 mkm depends
on Earth orbital period (365.25 days). By that we know the period 10747 days
which is required from the moon to pass a distance =940 mkm by its daily
displacement (88000 km) must depend on Earth orbital period (365.25 days)
- I want to say,
- The period 365.25 days be used by Earth motion before the period 10747 days
using by the Earth moon displacement or by Saturn motion.
- I try to prove, the period 365.25 is created anciently and before the others periods
of time.
- The data tells, Saturn is created after the Earth moon creation. because of that
Saturn orbtioal period depends on the period (10747 days) required for the moon
motion distance 940 mkm.
(II)
- The moon motion daily distance = 2.4 mkm (later should be explained), means
- During 10747 days the moon motion distances total be =25920 mkm
- Where

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- Light known velocity (0.3 mkm/s) travels during one solar day (86400 sec) a
distance =25920 mkm
- Means,
- The moon during (10747 days =Saturn orbital period) moves a distance = 25920
mkm = light motion distance during a solar day! Why? But,
- Saturn motion distance during a solar day =0.838 mkm
- Saturn moves during (30589 days = Uranus orbital period) a distance =25920
mkm = light motion distance during a solar day (error 1%)
- Can we understand how this data be created? can we consider this data be created
as pure coincidence of numbers?!
- Let's try to see this data as deep as possible
Notice
- Why the moon motion distance per a solar day =2.4 mkm? Because
- The moon moves per a solar day a distance = earth motion distance during a solar
day because they aren't separated from one another.
- Means, the moon moves a distance = 2.574 mkm
- This distance be effected by the rate (1.0725) and became 2.4 mkm
- The rate 1.0725 effects on 40% of all distances in the solar system. So we doesn't
interest for the reason behind this rate (1.0725) effect because it's a fact regardless
its reason.
- If the moon motion distance during a solar day =2.4 mkm, that means the moon
velocity be (27.78 km/sec)

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I- Data
(a)
Mars (24.1 km/s) moves during 12430 seconds a distance =300000 km
(b)
Saturn (9.7 km/s) moves during 12430 seconds a distance =120536 km (Saturn
diameter)
(c)
The moon (27.78 km/s) moves during 10747 sec a distance = 298552 km (0.5%)
(d)
Saturn (9.7 km/s) moves during 30589 seconds a distance =296714 km (1%)
(e)
The moon circumference (10921 km) x 27.32 days = 298362 km (0.5%)
(f)
10747 days (Saturn orbit. Per.) x 24 h x 10 = 10.7 h (Saturn day period) x 2 x 120536
II- Discussion
Let's try to understand the previous data as possible!
Equation no. (c)
The moon (27.78 km/s) moves during 10747 sec a distance = 298552 km (0.5%)
- Equation no. (c ) tells, the moon moves during 10747 seconds a distance = 300000
km = light motion distance for 1 second.
Equation no. (e)
The moon circumference (10921 km) x 27.32 days = 298362 km (0.5%)
- Equation no. (e ) tells, if the moon rotates one time around its axis per a solar day,
as the Earth does, by this motion, the moon will pass (300000 km) in a period
=27.32 days = the moon orbital period.
- Means, the moon passes 300000 km by 2 motions by using 2 defined periods of
time, (defined periods of time means, periods be defined by a planet motion). the

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moon passes a distance = light motion distance during 1 second by using 2 defined
periods of time (why?)
- Now
- Saturn has found that, the moon behavior is interesting, so Saturn follows this
same behavior and uses the period (30589 seconds) to pass a distance = 300000
km, where 30589 days = Uranus orbital period! (why?)
- Let's get some help from Mars
- Mars moves during 12430 seconds a distance = 300000 km
- But Saturn has found the period (12430 sec) interesting and used it to pass a
distance = 120536 km = Saturn diameter.
- Why Saturn diameter is related to light motion distance during 1second?! I don't
know!
- But
- (300000 km /120536 km) =2.5 where 2.5 deg = Saturn orbital inclination!
- How this data is created? I don't know!
Notice
- Saturn Orbital Distance = 1433.5 Mkm = Mars Orbital Circumference
- How to understand this data? Saturn orbital period is defined by the moon motion.
and Saturn orbital distance is defined by mars motion. where the Moon and Mars
are the basic 2 players in the previous data. Can we understand what's happened?
Or how this data be created?
- With great effort I reach to one conclusion, that Saturn must be created after Mars
and the moon creations, and Saturn use their data in its own motion to create a
harmony in motions.
- I want to say, the data gives us a strong proof to reach to this conclusion spite we
can't discover clearly how this data be created but we can conclude that there's

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some historical order in this data creation. and by this historical order we can
conclude that Saturn be created after mars and the Earth moon creations.
- The point is that, Saturn uses 2 planets data and it’s illogical that the 2 planets be
created after Saturn creation. more logical to suppose that Saturn is created after
these 2 planets creation.
Equation no. (f)
10747 days (Saturn orbit. Per.) x 24 h x 10 = 10.7 h (Saturn day period) x 2 x 120536
- Where
- 120536 km = Saturn Diameter, the equation tells Saturn diameter (120536 km) b
used as a rate between Saturn orbital period and Saturn day period (for a package
of 10 orbital periods) (Why?!)
- How this data be created?!

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4-3 Earth Orbital Period Analysis (365.25 days)
I- Data
(1)
365.25 days = 2π x 58.1313 days (58.13 different from 58.66 with 1%)
(2)
365.25 days = (1407.6 h/24.6 h) x (153.3 h/24 h)
(3)
(112.2 /47.4) = (17.2 deg /7.25 deg) = (1.392 mkm/ 0.5875 mkm)
(4)
63.7 deg = 17.2 deg x 3.66 but (3.66 = 1392000 km /378675 km)
(5)
(58.66/ 57.9) = (10.844/10.7)
(6)
(63.7 x 60 x 365.25) / (1392000) = (361/360)
(7)
1392000 seconds = 7.1 x 194040 seconds (1 %)
(8)
24.7 mkm = 1.392 days x 17.75 mkm/days
But,
24.7 days x 1.392 mkm = 2 x 17.2 mkm
But
1.392 seconds x 0.3 mkm/sec = 0.4176 mkm = (0.4136 mkm error 1%)
(9)
(7.25 /7.1) the difference =2%
(10)
(687 days /88 days) = 7.8 (but 7.8 = 1.0725 x 7.25)
(11)
149.6 mkm = 1047.7 x 142984 km

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(The sun diameter 1.392 mkm = Jupiter diameter x π2
error 1.3%)
(Jupiter orbital circumference 4900 mkm = The sun diameter x the moon diameter)
(12)
142984 km = 11.8 x 12104 km
4331 days = 11.8 x 366.7
(13)
115.2 deg = 6.7 deg x 17.2 deg
And
63.7 deg x 1.8 deg = 113.4 deg (error 1%)
Notice
(339/243) = 1.392
Notice
365.25 = 24.7 x 14.77 but (Uranus diameter / the moon diameter) = 14.77
(14)
1.16 mkm = 0.838 mkm x 1.392 days

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II-Discussion
Equation no. (1)
365.25 days = 2π x 58.1313 days (58.13 different from 58.66 with 1%)
- Where
- 58.66 days = Mercury Rotation Period
- Equation no. (1) tells that, Earth orbital period is created depending in Mars
rotation period. This meaning may be logical because we have seen before Venus
Day period be defined depending on Mercury Day Period
- That tells, Mercury may be found before Earth, and Earth orbital period be created
based on Mercury rotation period.
- The geometrical mechanism by which this process is done must be so complex.
Because we know that, Mercury orbital circumference = 360 mkm but if we
account accurately the circle circumference based on the radius 57.9 mkm, the
circumference will be 363.8 mkm which is very near to 365.25. what happened is
that, 1 mkm be used as 1 solar day, and this using is usual using in Mercury
motions as we have seen before
- Another point is that, Mercury orbital period =88 days and if 1 day be = 1000 km,
this value will be 88000 km (the moon displacement per a solar day).
- I try to show that, the distances values be used as periods of time between mercury
on one side and the Earth with its moon on the other side. And this using is done
for 2 times
- Regardless if this using is proved as a fact or not. But I try to show that, the data be
created in proportionality for some geometrical reason which we still try to know.
- Notice
- Mercury moves during its rotation period a distance = 243 mkm (error 1%)
- Venus rotation period =243 solar days,
- Here the rate 1 mkm be = 1 solar day is used again.
- I try to prove that, some geometrical mechanism be found behind this data

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Equation no. (2)
365.25 days = (1407.6 h/24.6 h) x (153.3 h/24 h)
- Where
- 1407.6 hours = Mercury Rotation Period
- 24.6 hours = Mars Rotation Period
- 153.3 hours = Pluto Day Period
- 24 hours = Earth Day Period
- Equation no. (2) is very interesting one, because it shows 4 planets motions data be
interacted to produce the period 365.25 days (Earth orbital period), why?
- We remember that
- The planets motions distances total during a solar day =17.75 mkm and during
1461 days, the total passed distance be =25920 mkm
- We have discussed this value (25920 mkm) deeply before.
- The data tells, the orbital period (365.25 day) and the cycle (1461 days) be used
for all planets, that be explained by the fact that the period is defined by interaction
of 4 planets motions (all of them almost ancient planets)

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Equation no. (3)
(112.2 /47.4) = (17.2 deg /7.25 deg) = (1.392 mkm/ 0.5875 mkm) = 2.37
- Where
- 112.2 km/s = the 3 planets velocities total (mercury + Venus + Earth)
- 47.4 km/s = Mercury Velocity
- 17.2 deg = Pluto Orbital Inclination
- 7.25 deg = the sun inclination on the ecliptic
- 1.392 mkm = The Sun Diameter
- 0.5875 mkm = Uranus Motion Distance During A Solar Day
- Equation no. (3) tells that, the sun inclination on the ecliptic (7.25 deg) is created
in proportionality with Pluto orbital inclination (17.2 deg). this proportionality is
found by different planets motions interaction.
- We interest for Uranus motion in the equation because we have supposed that
Pluto day period be extending to 153.3 hours by an effect of Uranus motion. we
know this information because Pluto orbital inclination =17.2 degrees wile Uranus
day period =17.2 hours. We can't catch the geometrical mechanism but the data
tells that Uranus did this effect.
Equation no. (4)
63.7 deg = 17.2 deg x 3.66 but (3.66 = 1392000 km /378675 km)
- Where
- 63.7 deg = the sun pole declination
- 17.2 deg = Pluto orbital inclination
- 1392000 km = the sun diameter
- 378675 km = Saturn Circumference

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Equation no. (5)
(58.66/ 57.9) = (10.844/10.7)
- Where
- 583.66 days = Mercury Rotation Period
- 57.9 mkm = Mercury orbital distance
- 10.7 h = Saturn Day
- 10.84 h = It's A Supposed Period
- We have discussed the period 10.84 hours before, it tells if Saturn day period
=10.84 hours, in this case Saturn will move during its day period a distance = its
circumference
- But because Saturn day period =10.7 h and not 10.844 h, because of that, Saturn
moves during its day period a distance = 97.8 % of its circumference, that means,
the difference is 1.3%
- This same difference or error be found between (58.66) and (57.9) if 1 mkm be
used as 1 day, the error will be 1.3% which tells some geometrical mechanism is
found between Saturn and mercury motions.
- And because the period 365.25 days (Earth orbital period) be defined based on
Mercury motion data. Saturn orbital period be created depending on the period
365.25 days,
Equation no. (6)
(63.7 x 60 x 365.25) / (1392000) = (361/360)
- Where
- 63.7 deg = the sun pole declination
- 1392000 km = the sun diameter
- 361 deg = Metonic Cycle degrees (19 years x 19 degrees)
- 360 deg = the usual circle degrees.
- That tells, the moon regression effect on different data.

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Equation no. (7)
1392000 seconds = 7.1 x 194040 seconds (1 %)
- 1392000 km = the sun diameter where 1 km be used as 1 second
- 194040 second = 53.9 hours
- The value 53.9 h = (the total days of Jupiter 9.9 h + Saturn 10.7 h+ Uranus 17.2 h
+ Neptune 16.1 h)
- 7.1 is a rate effects on the solar system distances
- This rate 7.1 can be used also as (1.0725) and this last one controls 40% of all
distances in the solar system (appendix no. 1 provides these distances list)
- Equation no. (7) tells that, the 4 great planets days periods total have some effect
on the sun diameter creation
- Notice
- The paper tries to prove that, a geometrical mechanism be found behind the data
creation and by that the period (365.25 days) must be found before the sun creation
because this period is used by different planets. Based on that, the sun herself must
be created after all planets creation which disproves Newton theory of the sun
mass gravity.
- Let's remember the sun rays creation idea in following

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5- The Sun Rays Be Produced By Planets Motions Energies Total
5-1 Preface
5-2 The Solar System Unified Motion
5-3 The Sun Rate Of Time
5-1 Preface
- The Sun Is A Result For The Solar System Motion.
- The Sun Rays Is Created By The Solar Planets Motions Energies (This fact
disproves Newton Theory for The Sun Mass Gravity completely)
- The Sun Rays Energy Is Created By The Solar Planets Motions Energies Total
- That means, The Solar Planets Motions Energies Be Accumulated And Be Used
For The Sun Rays Creation.
- Based on this vision, the sun rays aren't created by any nuclear interactions found
inside the sun. the energy is provided by the solar planets motions energies.
- The Main Force In This Process Is The Sun Rate Of Time.
- Where
- 1 Day of The Sun Motion = 365.25 Days of Earth Motion.
- Based on this rate, The energy which is accumulated during one complete year be
consumed by the sun in one solar day only. And by that, the accumulated energy
be sufficient for the light production process.
- For better explanation, we should consider the Earth as the planets representative,
by that, the solar group motions energies be accumulated on Earth motion. and
Earth motion causes to create the rate of time 1 Day of the sun = 365.25 days of
Earth. And by that the energy which is accumulated on Earth motion will be sent
to the sun to be used in the sun rays creation.
- Based on this vision, The sun will be just a mirror reflects the light beams which
are emitted from the Earth motion. and this vision may effect negatively on the sun
science – But -

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- It's Not necessary to effect negatively on the sun science
- The whole sun science can be saved without change, but
- The sun science should replace the source of energy. Because the source of energy
is the solar planets motions energies total accumulated during a complete year. by
that, the source of energy isn't the nuclear interactions found inside the sun.
- We should notice that, because the matter is created almost out of light, the sun
matter and mass can be created by the energy of the planets motions energies total.
the point is that, The Energy Creates The Matter. And if the energy is available
the matter can be created regardless the creation method.
- By that, The sun matter and Mass can be created and all the sun science can be
saved but the source of energy is the planets motions energies total.
- We should notice that, the planets motions energies total be a weak energy, but
because of the accumulation for 1 complete year (365.25 days), this accumulation
gives the chance for this energy to be used to create the sun rays. And because this
rate of time is the sun rate of time, so, no one planet sees this energy. because this
energy is created depends on the sun rate of time which is different from all
planets rates of time. And by that, the energy be used by the sun only and not by
any other planet.
- In the following point we should discuss the details how the sun rays be created…

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5-2 The Solar System Unified Motion
- The solar system moves a unified motion. that means, the solar planets motions be
unified together and create One Unified General Motion. this motion which is
similar to the Train carriages Motions, where all planets motions be used to create
The One Unified General Motion.
- But
- Why does the solar system need this One Unified General Motion?
- Because by this unified motion The Sun Rays Be Created.
- Let's explain how that's happening in following:
- The 9 Solar Planets Velocities Total = 176 km/s
- But,
- We need to add the Earth moon velocity (29.8 km/s) and by that the total will be =
176 + 29.8= 205.8 km/s
- The moon velocity is = Earth velocity because they aren't separated from each
other through their motions.
- So, the 10 Planets velocities total be =205.8 km/s
- Why this total is required? Because
o The Sun Rays Energy Is Produced From The Solar Planets Motions
Energies Total.
o Means,
o The sun rays energy source is The Planets Motions Energies Total
o Because of that, the planets velocities total is required because based on this
total The Sun Rays Be Produced.
o In calculations, the velocities total (205.8 km/s) is the source of the sun
rays energy.
o Let's explain The Sun Rays Production Process in following:

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(Point No. 1) (The Sun Rate Of Time)
Equation no. A
10921 km (The Moon Circumference) x 86400 Seconds = 940 mkm
- Equation no. (A) tells. If Earth revolves around the sun a complete revolution
(=940 mkm = Earth Orbital Circumference) in one solar day only (86400 sec), in
this case, the moon circumference (10921 km) will be equal the Earth motion
distance during 1 second.
- But, because
- Earth revolves around the sun in one year (=365.25 days), so this equation may
refer to a rate of time is used by the sun herself.
- Based on that,
- We suppose, the sun uses a rate of time different from Earth rate of time which is
(1 Day Of The Sun = 365.25 Days Of Earth)
- We will suppose that, this rate is a real one and try to test if it's a fact.
- Now we have 2 hypotheses which are
- (1st
hypothesis) (The planets velocities total is used to create the sun rays)
- (2nd
hypothesis) (1 Day Of The Sun = 365.25 Days Of Earth)
- Let's use the planets data depending on these 2 hypotheses in following:
(1)
- The solar planets velocities total (=205.8 km/s) and during a solar day the total
passed distance be = 205.8 km/s x 86400 seconds = 17.75 mkm
(2)
- 1 day of the sun =365.25 days of Earth, means
- 1 day of Earth = 237 seconds of the sun
(3)
- The distance =17.75 mkm and the time =237 seconds, so the velocity =75000 km/s

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(4)
- 75000 km/s = a quarter of the light velocity (300000 km per second)
(5)
- Means,
- The solar planets velocities total based on the sun rate of time be = 0.25 of light
velocity (A Quarter Of Light Velocity)
(6)
- Earth has a cycle of 4 years (365 +365 +365 +366=1461 days).
- Earth Uses This Cycle To Create A Light Beam From The Solar Planets
Motions Energies Total.
(7)
- Means,
- The sun rate of time is (1 day of the sun = 365.25 days of Earth). This is the
unified rate of time which is produced for the solar planets unified motions. This
rate of time causes the solar planets velocities total to be = a quarter of light beam
velocity =75000 km /s
- But
- Earth created a cycle of 4 years, to use it in the energies accumulation process for
this (quarter of light velocity) to produce the light velocity (i.e. to produce The Sun
Rays.)
- Because The Light Beam Is Created Based On Quantization, The Sun Rays Can't
Be Created If Earth Has No This (4 Years) Cycle.
- Based on that,
- Although the sun rays is produced by the planets velocities total but without the
Earth nothing can be done because Earth uses its (4 years) cycle to produce the sun
rays (practically) from the available energy.
- But, If The Earth moon is partner in this process, that means, the moon should
have an effect on Earth (4 Years Cycle).

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(Point No. 2) The Distance 25920 mkm
(1)
- Light (0.3 mkm/s) travels during a solar day a distance = (25920 mkm)
- The solar planets velocities total per a solar day = 17.75 mkm per a solar day
- During 1461 days, the solar planets (17.75 mkm) move a distance =25920 mkm.
- Because there's a light motion behind this data, the distance 25920 mkm we see as
a period of time (25920 years = The Precession Cycle).
(2)
- The data tries to show that, the cycle 1461 days is used by all planets velocities
total, means, it's a cycle for the whole solar system and not Earth Cycle only.
(3)
(2 x 1461 days / 327.6 days) = (243 days /27.3 days) = (153.3 h/17.2h) = (224.7 days
/25.2 days) = (778.6 days /88 days) = (2722 mkm/306 mkm)
- Where
- 1461 days = Earth Cycle 327.6 days= The Lunar Sidereal Year
- 243 days = Venus Rotation Period 27.3 days = The moon orbital period
- 153.3 hours = Pluto Day Period 17.2 hours = Uranus Day Period
- 224.7 days = Venus Orbital Period 25.2 deg =Mars Axial Tilt
- 778.6 mkm = Jupiter orbital distance 88 days = Mercury Orbital Period
- 2722 mkm = Uranus Earth Distance 153mkm = Earth orbital distance (2%)
- The previous data aims to show that, the moon effects greatly on the cycle 1461
days. But because the cycle 1461 days is considered a cycle for all planets, the
moon effect is seen as one effect among many similar effects.
- But the following data can shows some specific effect of the moon motion on this
process.

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(4)
- 25920 mkm = 2.4 mkm x 10747 days
- Where
- 10747 days = Saturn Orbital Period
- 2.4 mkm = the moon motion distance per a day (before the displacement)
- The moon moves 25920 mkm during the period 10747 days. But we know that, all
planets (17.75 mkm daily) move a distance = 25920 mkm during the cycle 1461
days. That shows the moon effective role in the solar system motion. can the moon
move in behave of all the solar planets?! To answer we should know what's the
relationship between the period 10747 days and the moon motion.
o The moon displacements total during 29.53 days = 2598693 km
o Earth motion distance during a solar day = 2574720 km
o The difference is (1%), so we consider these 2 distances are equal
o We remember the rule (Equal distances causes different rates of time)
o i.e. because the distances are equal
o 1 Day Of Earth Motion = 29.53 Days Of The Moon Motion
o But
o 1 Day Of The Sun = 365.25 Days Of Earth Motion
o Based on that
o 1 Day Of The Sun = (365.25 x 29.53) of the moon motion
o 1 Day Of The Sun = 10747 Days Of The Moon Motion
o That means, Saturn orbital period (10747 days) is created to complete the
picture of the time rates cooperation. the data still gives surprises …
o The moon motion (2.4 mkm) during Saturn orbital period (10747 days)
passes a distance =25920 mkm which be passed by all planets during 1461
days and also be passed by the light beam in 1 solar day (86400 s). why?
Notice this discussion will be completed in details in point no. (13)

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4-3 The Sun Rate Of Time
Equation no. A
10921 km (The Moon Circumference) x 86400 Seconds = 940 mkm
- Equation no. (A) tells. If Earth revolves around the sun a complete revolution
(=940 mkm = Earth Orbital Circumference) in one solar day only (86400 sec), in
this case, the moon circumference (10921 km) will be equal the Earth motion
distance during 1 second.
- But, because
- Earth revolves around the sun in one year (=365.25 days), so this equation may
refer to a rate of time is used by the sun herself.
- Based on that,
- We suppose, the sun uses a rate of time different from Earth rate of time which is
(1 Day Of The Sun = 365.25 Days Of Earth)
- We will suppose that, this rate is a real one and try to test if it's a fact.
- Now we have 2 hypotheses which are
- (1st
hypothesis) (The planets velocities total is used to create the sun rays)
- (2nd
hypothesis) (1 Day Of The Sun = 365.25 Days Of Earth)
- Let's use the planets data depending on these 2 hypotheses in following:
(1)
- The solar planets velocities total (=205.8 km/s) and during a solar day the total
passed distance be = 205.8 km/s x 86400 seconds = 17.75 mkm
(2)
- 1 day of the sun =365.25 days of Earth, means
- 1 day of Earth = 237 seconds of the sun
(3)
- The distance =17.75 mkm and the time =237 seconds, so the velocity =75000 km/s
(4)

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- 75000 km/s = a quarter of the light velocity (300000 km per second)
(5)
- Means,
- The solar planets velocities total based on the sun rate of time be = 0.25 of light
velocity (A Quarter Of Light Velocity)
(6)
- Earth has a cycle of 4 years (365 +365 +365 +366=1461 days).
- Earth Uses This Cycle To Create A Light Beam From The Solar Planets
Motions Energies Total.
(7)
- Means,
- The sun rate of time is (1 day of the sun = 365.25 days of Earth). This is the
unified rate of time which is produced for the solar planets unified motions. This
rate of time causes the solar planets velocities total to be = a quarter of light beam
velocity =75000 km /s
- But
- Earth created a cycle of 4 years, to use it in the energies accumulation process for
this (quarter of light velocity) to produce the light velocity (i.e. to produce The Sun
Rays.)
- Because The Light Beam Is Created Based On Quantization, The Sun Rays Can't
Be Created If Earth Has No This (4 Years) Cycle.
- Based on that,
- Although the sun rays is produced by the planets velocities total but without the
Earth nothing can be done because Earth uses its (4 years) cycle to produce the sun
rays (practically) from the available energy.
- But, If The Earth moon is partner in this process, that means, the moon should
have an effect on Earth (4 Years Cycle).
(Point No. 2) The Distance 25920 mkm

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(1)
- Light (0.3 mkm/s) travels during a solar day a distance = (25920 mkm)
- The solar planets velocities total per a solar day = 17.75 mkm per a solar day
- During 1461 days, the solar planets (17.75 mkm) move a distance =25920 mkm.
- Because there's a light motion behind this data, the distance 25920 mkm we see as
a period of time (25920 years = The Precession Cycle).
(2)
- The data tries to show that, the cycle 1461 days is used by all planets velocities
total, means, it's a cycle for the whole solar system and not Earth Cycle only.
(3)
(2 x 1461 days / 327.6 days) = (243 days /27.3 days) = (153.3 h/17.2h) = (224.7 days
/25.2 days) = (778.6 days /88 days) = (2722 mkm/306 mkm)
- Where
- 1461 days = Earth Cycle 327.6 days= The Lunar Sidereal Year
- 243 days = Venus Rotation Period 27.3 days = The moon orbital period
- 153.3 hours = Pluto Day Period 17.2 hours = Uranus Day Period
- 224.7 days = Venus Orbital Period 25.2 deg =Mars Axial Tilt
- 778.6 mkm = Jupiter orbital distance 88 days = Mercury Orbital Period
- 2722 mkm = Uranus Earth Distance 153mkm = Earth orbital distance (2%)
- The previous data aims to show that, the moon effects greatly on the cycle 1461
days. But because the cycle 1461 days is considered a cycle for all planets, the
moon effect is seen as one effect among many similar effects.
- But the following data can shows some specific effect of the moon motion on this
process.
(4)

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- 25920 mkm = 2.4 mkm x 10747 days
- Where
- 10747 days = Saturn Orbital Period
- 2.4 mkm = the moon motion distance per a day (before the displacement)
- The moon moves 25920 mkm during the period 10747 days. But we know that, all
planets (17.75 mkm daily) move a distance = 25920 mkm during the cycle 1461
days. That shows the moon effective role in the solar system motion. can the moon
move in behave of all the solar planets?! To answer we should know what's the
relationship between the period 10747 days and the moon motion.
o The moon displacements total during 29.53 days = 2598693 km
o Earth motion distance during a solar day = 2574720 km
o The difference is (1%), so we consider these 2 distances are equal
o We remember the rule (Equal distances causes different rates of time)
o i.e. because the distances are equal
o 1 Day Of Earth Motion = 29.53 Days Of The Moon Motion
o But
o 1 Day Of The Sun = 365.25 Days Of Earth Motion
o Based on that
o 1 Day Of The Sun = (365.25 x 29.53) of the moon motion
o 1 Day Of The Sun = 10747 Days Of The Moon Motion
o That means, Saturn orbital period (10747 days) is created to complete the
picture of the time rates cooperation. the data still gives surprises …
o The moon motion (2.4 mkm) during Saturn orbital period (10747 days)
passes a distance =25920 mkm which be passed by all planets during 1461
days and also be passed by the light beam in 1 solar day (86400 s). why?

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The Sun Rate Of Time (continued)
I - Data
(a)
365.25 = (180/π) x 6.38
(b)
(365.25/9.18) = (5906 mkm /149.6 mkm) (error 0.8%)
(c)
(2.598 mkm /4.37 mkm) = 0.594
But
63.7 = 1.0725 x 59.4
II – Discussion
- The data tells that the equal distances helps to create the sun rate of time (1 day =
365.25 days). Let's remember these equal distances in following
- Earth (29.8 km/s) moves during a solar day (24 h) a distance = 2574720 km
- Pluto (4.7 km/s) moves during its day (153.3) a distance = 2593836 km
- The moon displacements total during (29.53 days) = 2598693 km
- The rate (6.38) between Earth and Pluto is used frequently in the sun rate of time
creation (we remember that 1 h of Earth motion = 6.38 h of Pluto motion)
- Let's see the equations discussion in following …
Equation no. (a)
365.25 = (180/π) x 6.38
- The Rate (180/π) Is A Geometrical Rate, and it's found for geometrical necessity
- Equation no. (a) tells that, the period (365.25 day) is created depends on the rate of
time between Earth and Pluto motions.

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Equation no. (b)
(365.25/9.18) = (5906 mkm /149.6 mkm) (error 0.8%)
- Where
- 9.18 is the rate of time between Mercury and Pluto Motions (it's effected also by
Uranus motion)
- 5906 mkm = Pluto Orbital Distance
- 149.6mkm = Earth Orbital Distance
- Equation no. (b) tells that, the period (365.25 days) is created based on orbital
distances of Earth and Pluto.
- The data tells that, the proportionality of data between Earth and Pluto
motions be effective greatly on the solar system motions.
(we discuss this proportionality in full details in point no. 13 of this paper).
Equation no. (c)
(2.598 mkm /4.37 mkm) = 0.594
But
63.7 = 1.0725 x 59.4
- Equation no. (c) tells something very interesting
- From the 3 equal distances (Earth, Pluto and the moon), the moon distance be selected.
- The moon displacements total during 29.53 days = 2598693 km
- 4.37 mkm = The Sun Circumference
- (2.598693 mkm/ 4.37 mkm) = 0.594 (1)
- That shows the moon motion effective on the sun data
- 63.7 = 1.0725 x 59.4
- Where, 1.0725 is the rate effected on 40% of all solar system distances
- 63.7 degrees = The Sun Declination
- What does that mean?
- The sun almost circles the Earth and gives the Earth the same one face always.
- This vision almost isn't accurate…

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- The sun does some action (as vibration) toward and backward in a range of angle
(=63.7 degrees).
- The sun is found on a vertical axis on Earth because of that we see this vibrating
motion as a circular motion.
- Accurately the sun rotates around its axis with a percentage =63.7% and return
back.
- By that the sun rotation around its axis be = 63.7% of its Circumference
- This motion the sun does one each year
- That means, the sun moves during 1year a distance = (63.7% x 4.37 mkm) =
2598693 km (= the moon displacements total during 29.53 days)
- That means,
- The sun moves during 1 year a distance = Earth motion distance during 1 day (1%)
- Because of that
- 1 Day Of The Sun Motion = 365.25 Days Of Earth Motion
- Because
- (Equal Distances Creates A Different Rate Of Time)
- means, The sun moves during 1year a distance = Earth motion for 1 day and the
rate between these 2 distances creates the rate of time (1 day of the sun =365.25
days of Earth)
Notice
This current paper discussion depend on the previous one (please review it)
The Refutation Of The Sun Mass Gravity Theory (Newton Theory) (Revised)
https://www.academia.edu/s/d20d569128
https://www.academia.edu/50325514/The_Refutation_Of_The_Sun_Mass_Gravity_Theory_Newton_Theory_Revised_
https://www.slideshare.net/Gergesfrancis/the-refutation-of-the-sun-mass-gravity-theory-newton-theory-revised-249877006
https://app.box.com/s/47fwd0gshir636xt0i3wpso8lvvl8vnv/file/839123297053

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Appendix No.1
The Solar System Equal Distances List
(A)
Why These Distances Are Equal?
(1)
Saturn Orbital Distance = Saturn Uranus Distance
= Mars Orbital Circumference
= Pluto Neptune Distance
= Pluto eccentricity Distance
= Neptune Orbital Distance/π
= Uranus Orbital Distance /2
= Mercury Jupiter Distance x 2
(2)
Mercury Neptune Distance = Saturn Pluto Distance
Jupiter Pluto Distance = Uranus Neptune Circumference
Earth Neptune Distance = Mercury Saturn Circumference (0.5%)
(3)
Jupiter Mercury Distance = 2 Mercury Orbital Circumference
Jupiter Venus Distance = Venus Orbital Circumference (1.5%)
Jupiter Earth Distance = Earth Orbital Circumference (1.2%)
(Earth and Jupiter at 2 different sides from the sun)
(4)
Jupiter Mercury Distance = Mars Orbital Distance x π (0.6%)
Jupiter Uranus Distance = Venus Jupiter Circumference (0.8%)
Pluto Orbital Distance = Earth Orbital Circumference x 2π
II- Discussion (A)
The previous distances form around 50% of all distances found in the solar system
(All orbital and internal distances)… Why These Distances Are Equal One Other?
We may notice that – the distances equality can be produced more easily by light
motion than the rigid body motion - for example – when we push a ball toward a wall
the ball after collision with the wall will return a distance (NOT) equal the original
one - because the collision causes to decrease the ball motion momentum – but the
light can be reflected at equal distances easily – means – equal distances can be
produced by light motion more easy than the Rigid Body Motion.

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(B)
Why These Distances Are NOT Equal?
1. 0725
.
1
mkm
2.41
nce
Circumfere
Orbital
Moon
mkm
2.58
Motion
Daily
Earth
=
2. 1.0725
km)
(378500
radius
Eclipse
Solar
Total
km)
(406000
radius
orbital
Apogee
=
3. 0725
.
1
distance
Mercury
Jupiter
mkm
720.3
Distance
Orbital
Juppiter
mkm
6
.
778
= (Error 0.7%)
4. 1.0725
Distance
Venus
Jupiter
mkm
670
distance
Mercury
Jupiter
mkm
720.3
=
5. 1.0725
Distance
Earth
Jupiter
mkm
629
Distance
Venus
Jupiter
mkm
670
= (0.6%)
6. 1.0725
mkm)
(1325.3
Distance
Venus
Sarurn
mkm)
(1433.5
Distance
Orbital
Saturn
= (0.8%)
7. 1.0725
mkm)
(1205.6
Distance
Mars
Sarurn
mkm)
(1284
Distance
Earth
Saturn
= (0.7%)
8. 1.0725
mkm)
(2644
Distance
Mars
Uranus
mkm)
(2872.5
Distance
Orbital
Uranus
= (0.7%)
9. 1.0725
mkm)
(4495.1
Distance
Orbital
Neptune
mkm)
(4894
nce
Circumfere
Orbital
Jupiter
= (1.5 %)
(10)
Discussion (B)
The same rate (1.0725) is used for all equations (around 18 distances = 40% of all
solar system distances) – why?
Suppose the equal distances are produced by light reflection and that cause these
distances to be equal – as I have supposed in the previous point (A).
Now suppose– part of these equal distances – is passed through another frame relative
to us – so this part of distances will suffer from Lorentz Length Contraction Effect
which is seen in the rate 1.0725
(Another frame can be found in the solar system because we deal with light motion) –
This explanation can answer why some distances are equal and others are rated with
the same rate (1.0725) – it's simply a feature of light motion.
0725
.
1
T.
Axail
Earth
23.4
T.
Axail
Mars
25.2
T.
Axail
Mars
25.2
T.
Axail
Satrun
26.7
Tilt
Axail
Satrun
26.7
Tilt
Axail
Neptune
28.3
=
=
=

I do this research
2nd
44
References and Biography
(Preprint No. 2) The Moon Orbital Motion Equation
https://www.academia.edu/49051029/_Preprint_No_2_The_Moon_Orbital_Motion_Equation
(Preprint No. 3) (Planet 8 Days Cycle)
https://www.academia.edu/49062055/_Preprint_No_3_Planet_8_Days_Cycle_
The Solar Planets Motions Description (Revised)
https://www.academia.edu/49464125/The_Solar_Planets_Motions_Description_Revised_
The Moon Orbital Motion Geometry (II)
https://www.academia.edu/45181646/The_Moon_Orbital_Motion_Geometry_II_
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944p=15209
Mr. Gerges Francis Tawdrous +201022532292
Physics Department- Physics Mathematics Faculty
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
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Earth Motion Disproves Newton Theory Of The Sun Mass Gravity

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