The Solar System Motion Depends On A Light Beam Motion

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
The Solar System Motion Depends On A Light Beam Motion
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –29th
August 2021
Abstract
Paper hypothesis
- The Solar system motion depends on a light beam motion.
The hypothesis explanation
- There's a light beam its velocity =1.16 mkm/sec in the solar system
- The solar system is created out of this light beam energy. The light energy creates
The Solar Planets Matters And Their Distances
- Based on this vision
- The solar system motion depends on this light beam motion.
- As a result
- This light beam effects are seen frequently in the planets motions data. because the
planet is similar to a puppet on the puppets theater, the light motion is the main
player behind and by that the light moves by using planets motions data and the
light motion effects on these planets motions data.
- The hypothesis tells another universe be found behind the universe of matter and
the important news is that, the hidden universe causes the matter universe motion.
- By that, the solar planets don't move by the sun mass gravity. The solar planets are
similar to ships found on a sea they move by this sea waves. Where the sea is the
light motions, because of that the light motions define the planets motions range
and creates their motions data.

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Paper Objective
- The paper proves the light motion existence behind the planets motions and proves
also that the light motion cause the planets motions.
Please scan the figure (ORCID)

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Paper Contents
Subject Page No.
1- Introduction 4
2- Methodology 6
3-The Light Effect Is A Continuum 8
3-1 Preface 8
3-2 The Rate (1.0725) 9
3-3 The Light Continuum Effect Proves Discussion 12
4-The Light Causes A Unification Of Motion 18
4-1 Preface 18
4-2 The Motions Unifications Proves Discussion 19
5- Mercury Jupiter Distance Analysis 27
5-1 Preface 27
5-2 Mercury Jupiter Distance analysis 31
5-3 Planets Motions Interaction 47
References and Biography 62

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1-Introdcution
- How to prove that a light beam is found behind the planet and causes is planet
motion?
- The correct question is (how the matter is created)
- The matter is created out of light beam. But the produced matter doesn't leave its
parent light beam and separate from it. On the contrary, the matter moves with its
parent light beam together in one unified motion but by using different rates of
time.
- The basic rate of time is that (1 Second Of Light Motion Be Equivalent To 1
Solar Day Of A Planet Motion) this rate tells that, the light motion depends on
the second and solar day periods of time as its basic periods of motion in
accompanying with the matter motion.
- If this is the fact, How to prove it?
- By Analysis Of The Solar System Distances
- The Solar System distances be created by light motion and the light creates the
distances based on One Geometrical Design that because the player motion is one
motion which is the light motion and not the planets motion. by that one player
creates the map and not many players. As a result the map be created based on one
geometrical design.
- The useful result is the solar system distances creation because the distances be
created based on one geometrical design and because of that the analysis for the
distances will prove these distances can't be created individually as independent
distances from one another, On the contrary the analysis will prove that these
distances be crated based on one geometrical design and depend on one another.
- The solar system distances analysis will prove that thee distances be created in a
network distances and by that the distance analysis is a very good method to prove
the light motion existence behind the planets motions
- The paper uses the distances analysis to prove its hypothesis

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- The proof is still complex because the hypothesis tells that a light beam its velocity
=1.16 mkm /sec be found in the solar system…
- We need before to prove, (A light beam its velocity 1.6mkm/s is found generally)
- The distances analysis can help this proof also because the distances be created of
energy provided by a light beam motion. as a result this light beam motion features
be registered in the distances because of the light energy by which these distance
be crated
- Many new ideas the paper provides hoping that they help our discussion and not
causes more difficulties, for example
- The paper considers that (Distance = Energy). This rule has no proof, we use it as
a fact because the planets motions data depends on this rule heavily, and without
this rule a huge number of planets motions data can't be understood.
- Also
- The paper considers the light and supposes that the light uses the distances values
and the periods of time ass exchangeable values. This vision takes into account the
different rates of time. That means, because (1 second of light motion = 1 solar day
of planet motion). based on that, the light motion uses (1 mkm) as equivalent to
(1second) but planets motions use (1 mkm) as equivalent to (1 solar day) usually .
Notice
- This paper should be considered a part of the previous paper
The Solar System Doesn't Move By The Sun Mass Gravity
https://www.academia.edu/s/368b5bca6f?source=work
https://www.academia.edu/51070956/The_Solar_System_Doesnt_Move_By_The_Sun_Mass_Gravity
https://www.slideshare.net/Gergesfrancis/the-solar-system-doesnt-move-by-the-sun-mass-gravity
https://app.box.com/s/47fwd0gshir636xt0i3wpso8lvvl8vnv/file/852785502541

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2-Methodology
- I use the planets motions data analysis to discover the solar system creation and
motion rules.
- This method is so useful because it creates a comparison between planet motion
data and the theory which tries to explain these planets motions. let's use one
example for better explanation.
Example No. (1)
1.16 mkm/s x 580 s = 671 mkm (Venus Jupiter Distance)
1.16 mkm/s x 671 s = 778.6 mkm (Jupiter Orbital Distance)
1.16 mkm/s x 629 s = 720.7 mkm (error 1%) (Mercury Jupiter Distance)
1.16 mkm/s x 542 s = 629 mkm (Earth Jupiter Distance)
1.16 mkm/s x 5127 s = 5906 mkm (error 0.7%) (Pluto Orbital Distance)
(5127 mkm = Jupiter Pluto Distance)
- Newton theory of the sun mass gravity tells that, the planet moves by the sun mass
gravity and based on that each planet moves an independent motion from the other
planets motions.
- As a result we accept that (Planet Motion Independency Concept) is a correct one
- The research method brings the data in comparison with the theory
- Newton tells Planet Motion Is Independent
- And
- Let's ask, Do This Data Support Newton Claim?
- I suppose there's a light beam its velocity =1.16 mkm/s, this is my hypothesis, now
let's analyze the planets data
- Jupiter distances to Venus (671 mkm), Earth (629 mkm), and Pluto (5127 mkm)
all of them be used as periods of time (671s, 629s and 5127s) for light supposed
velocity (1.16 mkm/s) to pass distances respectively equal (778.6 mkm, 720.7mkm
and 5906 mkm) can that be created by pure coincidences of numbers?

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- The direct distances still depend on other distances use the same rule, for example
671 mkm be passed by light supposed velocity (1.16 mkm/s) during a period 580s
but light supposed velocity needs 500 s to pass 580 mkm (notice light known
velocity 0.3 mkm/s needs 500 s to pass Earth orbital distance)
- In the paper discussion we analyze tenths of similar data…
- Should All Data Be Created By Pure Coincidences Of Numbers?
- Simply the data contradicts the vision.
- Newton simple idea deceives us and covers the complexities and difficulties in the
solar system motion and because of that Newton theory of the sun mass gravity
contradicts the planets motions data frequently.
- Shortly
- The research methodology compare between the planets motions data and the
theory to test if the theory be sufficient to explain the planets motions

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3-The Light Effect Is A Continuum
3-1 Preface
3-2 The Rate (1.0725)
3-3 The Light Continuum Effect Proves Discussion
3-1 Preface
- The light effect creates a continuum, this feature is very effective one because it
shows it's an effect of light motion and not by a planet motion.
- Imagine we use a solar cell to create electricity… the light beam which is used by
the solar cell comes from the sun and can effect on the way till reach to the solar
cell. Also we can measure this light beam energy and discover what rang of
electricity can produce
- I want to say, the light motion isn't a point in space surrounded in some place.
Because the light nature is a continuum.
- By that the light effect on some point should be discovered in many other points
because the light can't be surrounded in very small area or in individual point. As a
result light effect be seen as a continuous effect through different data.
- This point of discussion provides 2 proves of the light continuum feature which is
discovered in the planets motions data
- As a result, planets motions data b seen in a continuum form as the next proves
discussion show
- The point no. (1) shows the rate 1.0724
- And
- The point no. (2) shows light supposed velocity contemn effect on planets motions
data
- Let's start these discussions immediately

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3-2 The Rate (1.0725)
I-Data
Data Group No. (A)
Why These Distances Are Equal?
(1)
Saturn Orbital Distance = Saturn Uranus Distance
= Mars Orbital Circumference
= Pluto Neptune Distance (error 1.5%)
= Pluto eccentricity Distance (error 1.5%)
= Neptune Orbital Distance/π
= Uranus Orbital Distance /2
= Mercury Jupiter Distance x 2
(2)
Mercury Neptune Distance = Saturn Pluto Distance
Jupiter Pluto Distance = Uranus Neptune Circumference
Earth Neptune Distance = Mercury Saturn Circumference (0.5%)
(3)
Jupiter Mercury Distance = 2 Mercury Orbital Circumference
Jupiter Venus Distance = Venus Orbital Circumference (1.5%)
Jupiter Earth Distance = Earth Orbital Circumference (1.2%)
(Earth and Jupiter at 2 different sides from the sun)
(4)
Jupiter Mercury Distance = Mars Orbital Distance x π (0.6%)
Jupiter Uranus Distance = Venus Jupiter Circumference (0.8%)
Pluto Orbital Distance = Earth Orbital Circumference x 2π

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Data Group No. (B
Why These Distances Are NOT Equal?
1. 0725
.
1
mkm
2.41
nce
Circumfere
Orbital
Moon
mkm
2.58
Motion
Daily
Earth
=
2. 1.0725
km)
(378500
radius
Eclipse
Solar
Total
km)
(406000
radius
orbital
Apogee
=
3. 0725
.
1
distance
Mercury
Jupiter
mkm
720.3
Distance
Orbital
Juppiter
mkm
6
.
778
= (Error 0.7%)
4. 1.0725
Distance
Venus
Jupiter
mkm
670
distance
Mercury
Jupiter
mkm
720.3
=
5. 1.0725
Distance
Earth
Jupiter
mkm
629
Distance
Venus
Jupiter
mkm
670
= (0.6%)
6. 1.0725
mkm)
(1325.3
Distance
Venus
Sarurn
mkm)
(1433.5
Distance
Orbital
Saturn
= (0.8%)
7. 1.0725
mkm)
(1205.6
Distance
Mars
Sarurn
mkm)
(1284
Distance
Earth
Saturn
= (0.7%)
8. 1.0725
mkm)
(2644
Distance
Mars
Uranus
mkm)
(2872.5
Distance
Orbital
Uranus
= (0.7%)
9. 1.0725
mkm)
(4495.1
Distance
Orbital
Neptune
mkm)
(4864
= (0.5 %)
(10)
0725
.
1
T.
Axail
Earth
23.4
T.
Axail
Mars
25.2
T.
Axail
Mars
25.2
T.
Axail
Satrun
26.7
Tilt
Axail
Satrun
26.7
Tilt
Axail
Neptune
28.3
=
=
=

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II- Discussion
- The previous data we have seen frequently before, so let’s summarize the idea in
following…
- The equal distances in group no. (A) are result because of the solar planets motions
system. where the solar planets motions depends on The equal distances method
- We have discussed thee equal distances method meaning before
- The Equal Distances Method causes the solar system distances to be equal one
another. as a result 50% of all distances in the solar system be equal one another
because the main method of motion depends on the equal distances method.
- The question is
- Why the distances in group no. (B) aren't equal but rated with the same one rate
(1.0725)?
- I attribute the rate (1.0725) for Lorentz Length Contraction Phenomenon. This is
my explanation for the using of the rate (1.0725) in the data group no. (B)
- But
- Regardless any explanation, the rate (1.0725) effects on 40% of all distances in the
solar system, that means, the effect of the rate (1.0725) is a fact regardless any
reason for it.
- The observation we need to notice is that, the rate (1.0725) effects on 40% of all
distances in the solar system equally by the same force. why?
- It's A Continuum Feature
- The effect continues through the distances and nothing stop it. it's a feature proves
the light motion found behind planet motions.
- The data proves that, a light beam must be found in motion behind planet motion.
and that means, the solar planets motions be accompanying with a light beam
motion.

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3-3 The Light Continuum Effect Proves Discussion
I- Data
Group No. (I)
1.16 mkm/sec x 671 sec = 778.6 mkm
1.16 mkm/sec x 778.6 sec = 903 mkm
1.16 mkm/sec x 903 sec x 2 = 2094 mkm
1.16 mkm/sec x 2094 sec x 2 = 4847 mkm
1.16 mkm/sec x 4847 sec = 5678.1 mkm (error 1%)
1.16 mkm/sec x 5678.1 sec = 6585.39 mkm
1.16 mkm/sec x 6585.39 sec = 7586 mkm
1.16 mkm/sec x 7586 sec = 8800 mkm
1.16 mkm/sec x 8800 sec = 32200 mkm (error 0.4%)
Group No. (II)
0.3 mkm/sec x 8554.3 sec x 2 = 5127 mkm (error 0.8%)
0.3 mkm/sec x 5127 sec = 763 mkm x 2
0.3 mkm/sec x 763 sec = 227.9 mkm (error 0.4)
Group No. (III) (A)
0.3 mkm/sec x 18048 sec = 2 x 2722.9 mkm (error 0.6 %)
0.3 mkm/sec x 2 x 2722.9 sec = 1622.7 mkm (error 0.7%)
0.3 mkm/sec x 1622.7 sec = 243 mkm x 2
0.3 mkm/sec x 243 sec x 2 = 146 mkm
Group No. (III) (B)
1.16 mkm/sec x 146 sec = 170 mkm
1.16 mkm/sec x 170 sec = 196.5 mkm
1.16 mkm/sec x 196.5 sec = 227.9 mkm

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1.16 mkm/sec x 227.9 sec = 264.4 mkm
1.16 mkm/sec x 264.4 sec = 306.6 mkm (306.6 x 0.3 = 91.7 mkm)
1.16 mkm/sec x 306.6 sec = 354.39 mkm
1.16 mkm/sec x 354.39 sec = 412.6 mkm
1.16 mkm/sec x 354.39 sec = 411 mkm
1.16 mkm/sec x 411 sec = 476.9 mkm
1.16 mkm/sec x 476.9 sec = 550.7 mkm (error 0.5%)

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II- Discussion
Group No. (I)
1.16 mkm/sec x 671 sec = 778.6 mkm
1.16 mkm/sec x 778.6 sec = 903 mkm
1.16 mkm/sec x 903 sec x 2 = 2094 mkm
1.16 mkm/sec x 2094 sec x 2 = 4847 mkm
1.16 mkm/sec x 5678.1 sec = 6585.36 mkm
1.16 mkm/sec x 6585.39 sec = 7586 mkm
1.16 mkm/sec x 7586 sec = 8800 mkm
1.16 mkm/sec x 8800 sec = 32200 mkm (error 0.4%)
- Where
- 671 mkm = Jupiter Venus Distance
- 778.6 mkm = Jupiter Orbital Distance
- 2094 mkm = Jupiter Uranus Distance
- 4847 mkm = Jupiter Orbital Circumference (error 1%)
- 5678.1 mkm = Mars Pluto Distance
- 32200 mkm = (37100 mkm Pluto orbital circumference) – (4900 mkm Jupiter
Orbital Circumference)
- 6585.36 days = Saros Cycle
- The data shows the idea clearly. The distances be created based on one another by
using the motion of light supposed velocity (1.16 mkm/s)
- As a result the distances be created based on one anther creating one geometrical
design and form a network form of distances
- The point we need to notice is that,
- The continuum feature which is proved in the data clearly can't be perfumed by
any planet motion. it's a light beam motion found behind the planets motions.

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Group No. (II)
0.3 mkm/sec x 8554.3 sec x 2 = 5127 mkm (error 0.8%)
0.3 mkm/sec x 5127 sec = 763 mkm x 2
0.3 mkm/sec x 763 sec = 227.9 mkm (error 0.4)
- Where
- 28255 mkm = Neptune Orbital Circumference
- 8554.3 mkm = π x 2722.9 mkm (Earth Uranus Distance)
- 5127 mkm = Jupiter Pluto Distance
- 227.9 mkm = Mars Orbital Distance
- Light known velocity (0.3 mkm/s) uses this same method. And creates the
distances based on one another in a network form
- For us, the good news is that, the motion be in a continuum form which can't be
performed by any planet motion. it's a light beam found clearly behind the planets
motions
- Newton Simple Theory is incorrect and imaginary Idea because the solar system is
so complex machine. No planet moves by the sun mass gravity instead the planets
are ships found on a sea and the sea is the light motions network
- The planets motions data analysis shows clearly that they are created based on a
continuum effect of motion which can be perform only by light motion.

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Group No. (III) (A)
0.3 mkm/sec x 18048 sec = 2 x 2722.9 mkm (error 0.6 %)
0.3 mkm/sec x 2 x 2722.9 sec = 1622.7 mkm (error 0.7%)
0.3 mkm/sec x 1622.7 sec = 243 mkm x 2
0.3 mkm/sec x 243 sec x 2 = 146 mkm
- Where
- 18048 mkm = Uranus Orbital Circumference
- 2722.9 mkm = Uranus Earth Distance
- 1622.7 mkm =Uranus Neptune Distance
- 243 days = Venus rotation period
- The data shows clearly the continuum feature. The light known velocity (0.3
mkm/s) uses the same method to create the distances in network form.
- The distances can be seen by us as periods of time simply because it's a light
motion. as we have seen with Saros cycle in the previous data. let's provide one
more example in following
- Example
- Light known velocity (0.3 mkm/s) travels during a solar day (86400 s) a distance =
25920 mkm
- But
- We see this distance (25920 mkm) in a period form because it's a light motion.
- Where
- (25920 years =The Precession Cycle)

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Group No. (III) (B)
1.16 mkm/sec x 170 sec = 196.5 mkm
1.16 mkm/sec x 196.5 sec = 227.9 mkm
1.16 mkm/sec x 227.9 sec = 264.4 mkm
1.16 mkm/sec x 264.4 sec = 306.6 mkm (306.6 x 0.3 = 91.7 mkm)
1.16 mkm/sec x 306.6 sec = 354.36 mkm
1.16 mkm/sec x 354.39 sec = 412.6 mkm
1.16 mkm/sec x 354.39 sec = 411 mkm
1.16 mkm/sec x 411 sec = 476.9 mkm
1.16 mkm/sec x 476.9 sec = 550.7 mkm (error 0.5%)
- Where
- 170 mkm = Mars Mercury Distance
- 354.36 days = The Moon Synodic Year (29.53 days x 12)
- 550.7 mkm = Mars Jupiter Distance
- 91.7 mkm = Earth Mercury Distance
- The data importance is the period (146 sec) because Data Group (III) (A) ended
with the value (146 mkm) which is used in Data Group (III) (B) as (146 sec)
- The data shows clearly the continuum feature
- Also
- The data shows the unification of motion between light supposed velocity (1.16
mkm/s) and light known velocity (0.3 mkm/s)
- The data proves strongly the paper hypothesis
- Light beam moves in accompanying the planets motions and the planets motions
depend on this light beam motion.

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4-The Light Causes A Unification Of Motion
4-1 Preface
4-2 The Motions Unifications Proves Discussion
4-1 Preface
- Let's summarize the idea in following
- Light motion uses one period of time to create different data which is used in
plants motions unification.
- The data discussion explains this meaning clearly
- Let's use one example in following
- Light supposed velocity (1.16 mkm/s) needs 50 seconds to pass Mercury orbital
distance (57.9 mkm)
- But
- Mercury rotation period =58.65 solar days
- If 1 mkm= 1 solar days
- The 2 values (58.65 mkm and 57.9 mkm will have a difference = 1.3%)
- That pushes us to guess that, there's some reason to create these 2values are so near
to one another
- It's the light motion effect
- The light needs to create different data based on equal periods of time to causes a
unification of planets motions.
- Let's explain that in more clear with the data discussion

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4-2 The Motions Unifications Proves Discussion
I- Data
(1)
Light known velocity (0.3 mkm/s) needs 500 s to pass (Earth orbital distance 149.6
mkm)
And
1.16 mkm/sec x 580 sec = 671 mkm (Venus Jupiter Distance)
But
100733 mkm = 929 mkm x 108.2 mkm = 671 mkm x 149.6 mkm
(2)
Light known velocity (0.3 mkm/s) during 193 s passes (57.9 mkm)
But
Light supposed velocity (1.16 mkm/s) during 196.5 s passes (227.9 mkm)
Between 193s and 196.5 s error (1.8%)
(3)
Light known velocity (0.3 mkm/s) during 586.6 s passes 176 mkm
But
Light supposed velocity (1.16 mkm/s) during 586.6 s passes (680 mkm)
(4)
Light known velocity (0.3 mkm/s) during 5127 s passes 1577.2 mkm (error 1%)
But
Light supposed velocity (1.16 mkm/s) during 5127 s passes (5906 mkm) (error 0.7%)
(5)
Light known velocity (0.3 mkm/s) during 3717 s passes 2 x 550.7 mkm (error 1%)
But

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(6)
Light known velocity (0.3 mkm/s) during 361 s passes 108.2 mkm
But
Light supposed velocity (1.16 mkm/s) during 361 s passes (419 mkm) and during
(419 s) passes a distance (2 x 243mkm)

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II- Discussion
Data No. (1)
Light known velocity (0.3 mkm/s) needs 500 s to pass (Earth orbital distance 149.6
mkm)
And
1.16 mkm/sec x 580 sec = 671 mkm (Venus Jupiter Distance)
But
- The data tells that, light known velocity and light supposed velocity both use equal
periods (500s) for Earth and Venus positions.
- Earth position is defined by Earth orbital distance but Venus position is defined by
Venus Jupiter Distance
- Why both light beams used equal periods of time (500s)? why this is useful?
- Let's discussion the equation
- Where
- 100733 mkm = light supposed velocity (1.16 mkm/s)motion distance during a
solar day
- 929 mkm = Earth Jupiter distance when the 2 planets be on the sun 2 sides
- 108.2 mkm = Venus Orbital Distance
- 149.6 mkm = Earth Orbital Distance
- 671 mkm = Venus Jupiter Distance
- The equation shows that, these 4 distances be created from the same one source
and because of that they are created in proportionality one another
- That explains why light uses equal periods of time (500 s) for the 2 planets
positions definition.

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Data No. (2)
Light known velocity (0.3 mkm/s) during 193 s passes (57.9 mkm)
But
Light supposed velocity (1.16 mkm/s) during 196.5 s passes (227.9 mkm)
Between 193s and 196.5 s error (2%)
- The difference 2% we should discuss at this point end. And we consider the 2
periods are equal
- By using equal periods, light supposed velocity (1.16 mkm/s) created Mars orbital
distance (227.9 mkm) but light known velocity (0.3 mkm/s) creates Mercury
orbital distance (57.9 mkm)
- That creates a unification of motion among Mercury, Mars (and Jupiter) because
Jupiter motion depends also on the period (196.5 s)
- The three planets show a deep harmony and by analysis we have proved that these
3 planets motions be integrated into one unified motion.
- Notice (1)
- The difference (2%) is found for geometrical necessity. This conclusion depends
on the data analysis because we have seen frequently the solar system values be in
(100%, 99% and 98%).
- For example
- Earth moves during a solar day a distance =2.574 mkm(100%) but the moon
displacements total during 29.53 days =2.598 mkm (101%) and the moon apogee
orbital circumference = 2.55 mkm (99%)
- Notice (2)
- 8 Jupiter days =79.2 hours = 285120 sec = π x 90756.5 sec
- 90756.5 sec – 90560 sec = 196.5 sec
- 90560 days = Pluto Orbital Period
- We remember (1 day of planet motion = 1 second of light motion)

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Data No. (3)
Light known velocity (0.3 mkm/s) during 586.6 s passes 176 mkm
But
Light supposed velocity (1.16 mkm/s) during 586.6 s passes (680 mkm)
- Where
- 175.94 Solar Days = Mercury Day period
- 680 mkm = Venus Orbital Circumference
- 687 days =Mars Orbital Period
The values 687 and 680 are different with 1%
- Based on equal periods of time (586.6 seconds) light known velocity travels 176
mkm and light supposed velocity travels 680 mkm
- Where (175.94 days and 687 days be the result values by these motions)
- We remember
- (1 mkm = 1 day for planet motion and 1 mkm = 1sec for light motion)
- Notice (1)
- 4222.6 h (Mercury Day Period)/ 24.7h (Mars Day Period) = 170
- Where
- 170 mkm = the distance between Mercury and Mars
- Notice (2)
- 687 days (Mars orbital period) x 24 h = 671 x 24.6 h (Mars rotation period)
- Where
- 680 mkm = Venus Orbital Circumference (different with 687 mkm with 1%)
- The analysis tries to show that, the equal periods using by both light velocities
motions produced an interaction of planets motions data which effect on these
planets motions.

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Data No. (4)
Light known velocity (0.3 mkm/s) during 5127 s passes 1577.2 mkm (error 1%)
But
- The data shows that, the equal periods (5127 seconds) by using light supposed
velocity passes a distance = 5906 mkm =Pluto orbital distance. And by using light
known velocity passes a distance = 2 x 778.6 mkm (Jupiter orbital distance)
- where
- 5127 mkm = Jupiter Pluto distance
- That shows, the deep interaction which is found between Jupiter and Pluto motions
data depends on the light motion using equal periods for the 2planets orbital
distances definition.
- The data tries to show that, a light beam is moving behind the planets motions and
accompanying these planets in their motions. where the light motion effects on the
planets motions data.

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Data No. (5)
Light known velocity (0.3 mkm/s) during 3717 s passes 2 x 550.7 mkm (error 1%)
But
- By using the period (3717 sec) light known velocity passes a distance = 2x 550.7
mkm (Mars Jupiter Distance)
- And
- By using the period (3717 sec) light supposed passes a distance = 4331 mkm
(Jupiter orbital period =4331 days)
- Where
- 3717 mkm = Jupiter Neptune Distance
- The data provides an interesting proof because the data is directed one and can't be
considered as a random data.

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Data No. (6)
Light known velocity (0.3 mkm/s) during 361 s passes 108.2 mkm
But
Light supposed velocity (1.16 mkm/s) during 361 s passes (419 mkm) and during
(419 s) passes a distance (2 x 243mkm)
- Where
- 108.2 mkm =Venus Orbital Period
- 243 days = Venus Rotation Period
- The using of equal periods of time is very useful to create a unification for planet
motion data. that means, based on Venus motion Venus orbital distance (108.2
mkm) be defined and Venus rotation period also be defined. Because both data
depends on Venus motion and because the main player behind is the light motion
and Venus is a puppet on the puppet theater
- The light motion has to depend equal periods of time to create a unification of
planet motion data

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5- Mercury Jupiter Distance Analysis
5-1 Preface
5-2 Mercury Jupiter Distance analysis
5-3 Planets Motions Interaction
5-1 Preface
- Mercury Day Period =4222.6 hours
- Mercury moves during its day period a distance = 720.7 mkm = (Mercury Jupiter
Distance)
(I)
- The hypothesis tells that, Mercury motion depends on a motion of light beam its
velocity (1.16 mkm/sec). that means,
- Light supposed velocity (1.16 mkm/s) motion effect on Mercury Motion causes
Mercury to move a distance 720.7 mkm during (4222.6 hours)
(II)
- The hypothesis tells, the light supposed velocity (1.16 mkm/s) started its motion
from Mercury to Jupiter to Pluto and through Pluto the light motion creates a
connection with Mars motion.
- Means, 8
- The light supposed velocity (1.16 mkm/s) effects on Mercury, Mars, Jupiter and
Pluto. light motion forces these 4 planets to move equal distances (720.7 mkm).
(III)
- That means, the 4 planets move equal distances (720.7 mkm) by effect of light
motion on the 4 planets motions
- Now let's ask
- What changes be done for these 4 planets motions resulting from the light motion
effect on them to move 720.7 mkm? Let's answer in following

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For Mercury
- Mercury (47.4km/) moves during its day period (4222.6 hours) a distance = 720.7
mkm. Mercury motion defines the distance (720.7 mkm).
For Mars
(A)
- Mars (2.082 km/day) moves during the nodal year (346.6 days) a distance = 720.7
mkm.
- The distance (720.7 mkm) is the target. So the result is the nodal year (346.6 days)
- (1)
- Light known velocity (0.3 mkm/s) during 346.6 sec passes a distance =104 mkm
- (2)
- Light supposed velocity (1.16 mkm/s) during 119.7 sec passes a distance =104
mkm (where 119.7 mkm = Venus Mars Distance)
- (3)
- Light supposed velocity (1.16 mkm/s) during 346.6 sec passes a distance =402
mkm (402 mkm = 2 x 201 mkm) (201 mkm a distance Jupiter moves in 4222.6
hours =mercury day period)
(B)
- The data shows that Mars orbital distance (227.9 mkm) depends on the period
196.5 seconds while Mercury orbital distance (57.9 mkm) depends on the period
193 sec.
- Mars and Mercury dependency on (196.5 sec and 193 sec respectively ) creates an
interaction of the 2 planets motions (in fact Jupiter also be a partner with the 2
planets) by that the 3planets motions be integrated and created one unified motion.
(C )
- Mercury day period needs 5040 seconds to be = (4224 hours)
- 5040 seconds = 84 minutes, But
- Mercury moves during 84 solar days a distance = 344 mkm

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- Mercury moves during 346.6 solar days a distance = 1419 mkm
- Mercury moves during 1433.5 solar days a distance = 5848 mkm (Mercury Pluto
Distance) (error 0.4%)
For Jupiter
(A)
- Jupiter (13.1 km/s) moves during 4222.6 h ) (Mercury day period) a distance = 201
mkm.
- 629 mkm = Earth Jupiter Distance = π x 201 mkm
- Jupiter (13.1 km/s) moves during 637 solar days a distance = 720.7 mkm.
- Based on this data
- Jupiter creates the period (637 days) in proportionality with Earth Jupiter distance
(629 mkm) (the 2 planets on one side from the sun) and Earth Jupiter distance (929
mkm) (the 2 planets are on the sun 2 sides). Mean based on Earth Jupiter distance
the period 637 days be created (these ideas be discussed here)
(B)
- Light known velocity (0.3 mkm/s) move during 778.6 seconds a distance = 201
mkm
- That shows the distance Jupiter moves in 4222.6 h (Mercury day period) which is
(201 mkm) defined by light motion during 778.6 seconds
- Where
- 778.6 mkm = Jupiter orbital distance
- That shows a great interaction is found in data and the light beam is the main
player effects on Planets Motions Data.

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For Pluto
- Pluto (0.406 mkm / day) moves a distance =720.7mkm in a period =1775 days.
- But
- Light known velocity (0.3 mkm/s) moves during 5848 seconds a distance = 1775
mkm
- Where (5848 mkm = Mercury Pluto Distance)
- (The distance 720.7 mkm depends on 5848 mkm as we will discuss)
-
- We remember that the distance 720.7 mkm is defined based on the distance 5848
mkm
- The data shows that, a light beam motion created planets motions data.
- In the next point we discuss in details the motion of the distance 720.7mkm.
- Notice
- Neptune (5.4 km/s) during 327.6 seconds moves a distance =1775 km
- Where
- 327.6 days = The Lunar Sidereal Year

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5-2 Mercury Jupiter Distance Analysis
I-Data
(a)
47.7 km/s (Mercury velocity) x 4222.6 h x 3600 s = 720.7 mkm
2.082 mkm/day (Mars velocity daily) x 346.6 days = 720.7 mkm
1.1318 mkm/ day (Jupiter velocity daily) x 636 days = 720.7 mkm
0.406 mkm/ day (Pluto velocity daily) x 1775.2 days = 720.7 mkm
Notice
720.7 mkm/ 196.5 mkm = 3.66
(b)
(929 mkm/629 mkm) = (940 mkm/636 mkm)
And
5848 mkm = 2π x 929 mkm
(c)
2.082 mkm/ day x 346.6 days =720.7 mkm
And
(5848 mkm x π) = 720.7 mkm x 25.2 (error 1%)
(d)
0.406 mkm/ day x 1775.2 days =720.7 mkm
But
(90560 days x 2) /1775 days = 102
(e)
(940 mkm/720.7 mkm) = (119.7 mkm/91.7 mkm) = (720.7/550.7) = (1557.2 mkm/
1205 mkm)=(2094 mkm/ 1622.7 mkm) = (5848 mkm/ 4495.1 mkm) = 1.3

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II-Discussion
- Why do we need to analyze the distance 720.7 mkm = Mercury Jupiter distance?
- Let's remember the theory ideas in following:
o The solar system is created out of one light beam its velocity (1.16mkm/s).
the light beam motion creates the planet matter and its orbital durance. By
that, the solar planets and their distances are created from one light beam
energy with supposed velocity (1.16mkm/s)
o The light motion creates one trajectory of energy for the solar system. and
the planets are points on this trajectory of energy
o Because of that, the theory tells, a planet motion covers a light motion. that
means, the planet is a puppet on the puppets theater, were the light motion
behind planet motion effects on the planets motion data.
o Light supposed velocity (1.16 mkm/s) travels during (4224 s) a distance =
4900 mkm (Jupiter Orbital Circumference). And the period (4224 s) caused
Mercury day period to be (4222.6 hours) because 1 second of light motion =
1 hour of Mercury Motion.
o Mercury moves during its day period (4222.6 h) a distance =720.7 mkm
o Now
o This story is a story and tells a part of the facts….
o Because
o Mercury is a name only. the light supposed velocity (1.16 mkm/sec) motion
is the basic player behind Mercury motion. that means, Mercury Motion
Distance during Mercury day period (720.7 mkm) is an effect of light
motion on Mercury motion. Mercury is a puppet and follower. Mercury
motion follows the light motion
o The theory creates another universe in parallel to the universe of matter. The
light motion creates this parallel universe. The light motion causes the
universe of matter to move.

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o I want to say
o The light motion is similar to a teacher and planet motion is similar to a
blackboard, by that, planet data be created by light motion effect on planet
motion.
o The light beam creates equal effects on the different planets. Because of
that, the light supposed velocity (1.16 mkm/sec) caused the 4 planets to
move equal distances (720.7 mkm) in the period (4222.6 hours) with
modifications required by the geometrical necessities
o This is a hypothesis and we try to prove it.
o That tells,
o The distance 720.7 mkm is a reference for light supposed velocity (1.16
mkm/sec) motion effect on the 4 planets motions.
o Now we have an information that
o The 4 planets (Mercury – Mars – Jupiter – Pluto) move equal distances
(720.7mkm) because of the light supposed velocity (1.16 mkm/sec) motion
effect on the 4 planets motions.
o How does the light supposed velocity do this task?
o By the distance 5848 mkm (Mercury Pluto Distance)
o That means,
o Through our discussion we should keep an eye on the distance 5848 mkm
because based on this distance the 4 planets move equal distances (720.7
mkm) in defined periods of time.
o That because the distance (5848 mkm) is a direct motion of light where light
supposed velocity (1.16 mkm/sec) travels during (5040 seconds) a distance
= 5848 mkm. By that the distance 5848 mkm shows a direct motion of light
supposed velocity and by this distance the light supposed velocity (1.16
mkm/sec) effects on the 4 planets motions to move 720.7 mkm in period
(=4222.6 hours) with the necessary modifications.

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Equation no. (b)
(929 mkm/629 mkm) = (940 mkm / 636 mkm)
- Where
- 629 mkm = Earth Jupiter Distance
- 929 mkm = Earth Jupiter Distance (The 2 Planets On The Sun 2 Sides)
- 940 mkm =Earth Orbital Circumference
- 5848 mkm = Mercury Pluto Distance
- The basic equation is the next one….
- 5848 mkm = 2π x 929 mkm
- Let's remember what we know,
- Light supposed velocity (1.16 mkm/sec) travels from Mercury to Pluto (5848
mkm) based on the period (5040 seconds) where Mercury day period (=4222.6 h)
and needs (5040 seconds) to be (=4224 h) = (=176 solar days).
- We conclude that, the light supposed velocity (1.16 mkm/sec) caused Mercury day
Period to be less than (4224 h) with the period (5040 seconds) (may be to create a
connection between Mercury and Pluto positions)
- By that, light supposed velocity (1.16 mkm/sec) travels a direct distance (5848
mkm = Mercury Pluto Distance)
- Now
- We have a light beam motion (5848 mkm)
- And we know that
- The rate (2π) distinguish between light motion and planet motion. the light motion
distance is (5848 mkm) and based on that the planet motion distance must be (929
mkm).
- The distance 929 mkm = the distance between Earth and Jupiter when the 2 planets
be on 2 different sides from the sun.

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- That creates a geometrical connection between the 2distances (5848 mkm) and
(929 mkm).
- We conclude that, while light moves (5848mkm) the planet moves (929 mkm)
depends on the light motion….
Equation no. (b) (continued)
(929 mkm/629 mkm) = (940 mkm / 636 mkm)
- Equation no. (b) shows that we deal with a relationship between the Earth and
Jupiter. The distance (629 mkm = earth Jupiter Distance) and (940 mkm = earth
orbital circumference) shows earth data relating to Jupiter motion data.
- The distance 929 mkm which is born from light motion distance (5848 mkm) be
found here basically to create the last one (636 mkm)
- But
- Jupiter (1.1318 mkm/day) moves during (636 days) a distance =720.7 mkm
- Means,
- The light motion distance (5848 mkm) effects on Jupiter motion to move the
distance (720.7 mkm) in a period (636 days)
- but
- This period be created in proportionality with Earth distances data! why?
- Because
- Jupiter moves during (4222.6 hours) a distance =200 mkm = (629 mkm /π)
- i.e.
- Jupiter motion during the period (4222.6 h = Mercury day period) passes a
distance =200 mkm which is related to (629 mkm = Earth Jupiter distance),
- now
- the machine of gears uses this distance (200 mkm) to perform the required distance
(720.7 mkm) by using Earth distances data in proportionality with Jupiter distances
data.

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Equation no. (c)
2.082 mkm/ day x 346.6 days =720.7 mkm
- where
- 2.082 mkm / day = Mars Velocity Daily
- 346.6 days = The Nodal Year
- Equation no. (c) tells, Mars moves during 346.6 days (the nodal year) a distance
=720.7 mkm = Mercury motion distance during Mercury Day Period (4222.6h)
- Why?
- The 2 numbers are mentioned because 346.6 days= the nodal year and 720.7 mkm
= Mercury motion distance…. That means, this distance be mentioned to be passed
by Mars during this defined period of time (346.6 days) but why?
-
- My answer is (the machine is A Complex One)
- The following data may help a little
o Mercury day period needs 5040 seconds to be = (4224 hours)
o 5040 seconds = 84 minutes
o But
o Mercury moves during 84 solar days a distance = 344 mkm
o Mercury moves during 346.6 solar days a distance = 1419 mkm
o Mercury moves during 1433.5 solar days a distance = 5848 mkm (Mercury
Pluto Distance) (error 0.4%)
o This system of motion we have seen before in light motion, when the light
passes a distance and then uses this distance as a period of time to move
another distance and then uses the second one to move a third one
o We notice
o The period 346.6 days be used in Mercury motion which concerning the
distance 5848 mkm. By that we conclude the period 346.6 days has a
relationship with the distance (5848 mkm)

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o Where
o The distance 5848 mkm expresses the light motion effect on the 4 planets
motions to pass equal distances (720.7 mkm)
o By that
o Mars uses (346.6 days) to pass the require distance (720.7 mkm)
o That proves Mars motion for the distance 720.7 mkm be found by an effect
of light motion to pass the distance (5848 mkm) as similar to the other
planets.
o Of this explanation be insufficient
o The difficulty is in the period (346.6 days) which is used by Mercury and by
Mars. This using creates an interaction between the 2 planets motions
o (Notice, the point no.3-3 explains in details the planets motions interaction).
Notice (1)
(1407.6 h / 24.6 h) = (180 /π)
But
(4222.6 h /24.7 h) =170
- Where
- 1407.6 hours = Mercury Rotation Period
- 24.6 hours = Mars Rotation Period
- 4222.6 hours = Mercury Day Period
- 24.7 hours = Mars Day Period
- 170 mkm = Mercury Mars Distance
Notice (2)
(5848 mkm x π) = 720.7 mkm x 25.2 (error 1%)
- Where
- 25.2 degrees = Mars Axial Tilt

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Equation no. (d)
0.406 mkm/ day x 1775.2 days =720.7 mkm
But
(90560 days x 2) /1775 days = 102 = (5848 mkm/57.9 mkm) (error 1%)
- Where
- 0.406 mkm / day = Pluto Motion Distance During A Solar Day
- 90560 days =Pluto Orbital Period
- 57.9 mkm =Mercury Orbital Distance
- 5848 mkm =Mercury Pluto Distance
- Equation no.(d) tells that,
- Pluto moves during 1775.2 days a distance =720.7 mkm
- This is the distance be required by light motion effect on the 4 planets motions
- Now
- The period 1775.2 days should be related to Mercury day period (4222.6 h)
- Equation tells that, the period 1775.2 days be rated with Pluto orbital period
(90560 days) by the same rate between (5848 mkm =Mercury Pluto distance) and
57.9 mkm (Mercury orbital distance)
- The equation tells, the period 1775.2 days is defined based on Pluto basic data in
proportionality with Mercury data.
- Shortly
- Pluto motion data be created takes into consideration the period 1775.2 day, that
tells the distance 720.7 mkm effects on Pluto motion also

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Equation no. (e)
(940 mkm/720.7 mkm) = (119.7 mkm/91.7 mkm) = (720.7 mkm /550.7 mkm) =
(1557.2 mkm/ 1205 mkm)=(2094 mkm/ 1622.7 mkm)=(5848 mkm/ 4495.1 mkm) =
1.3
- Where
- 940 mkm = Earth Orbital Circumference
- 720.7mkm = Mercury Jupiter Distance (our examined distance)
- 119.7 mkm = Venus Mars Distance
- 91.7 mkm = Mercury Earth Distance
- 550.7 mkm = Mars Jupiter Distance
- 1557.2 mkm = Jupiter Orbital Distance (1557.2 mkm =2 778.6 mkm)
- 1205 mkm = Mars Saturn Distance
- 2094 mkm = Jupiter Uranus Distance
- 1622.7 mkm = Uranus Neptune Distance
- 5848 mkm = Mercury Pluto Distance
- 4495.1mkm = Neptune Orbital Distance
- 1.3 degrees = Jupiter Orbital Inclination
- Equation no. (e) shows that the planets distances be created in proportionality with
one another.
- Ion different many data I try to show that, no single distance be created
interpedently, we deal along time with one geometrical system, means the
distances be created based on one geometrical design.

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Earth Jupiter Distance Analysis
Equation no. (I)
- Where
- 108.2 mkm = Venus orbital distance
- 149.6 mkm = Earth orbital distance
- 929 mkm = Earth Jupiter Distance (The 2 Planets Be On The Sun 2 Sides)
- Light supposed velocity (1.16 mkm/s) travels during a solar day (86400 s) a
distance = 100733 mkm
- Equation no. (I) tells, from one source of Energy the 4 distances be created
- Specifically
- From the distance 100733 mkm, the 4 distances are created
- These 4 distances be created from the same one distance (100733 mkm) in
comparison with one another. that means these 4 distances are created based on
one geometrical design which proves the network theory of distances.
Equation no. (II)
(940 mkm/680 mkm) = (929 mkm / 671 mkm)
- Where
- 680 mkm = Venus Orbital Circumference
- The distances are created for geometrical reasons and based on geometrical
mechanisms.

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Equation no. (III)
(778.6 mkm / 929 mkm) = (5848 mkm/4900 mkm) = 0.838
- Where
- 778.6 mkm = Jupiter Orbital Distance
- 4900 mkm = Jupiter Orbital Circumference
- 5848 mkm =Mercury Pluto Distance
-
- I try to show, the distance 929 mkm is built based on a geometrical mechanism
which creates a system for the distances creation, or a network of distances
- That means,
- The distance 929 mkm be taken into consideration by the light motion from
Mercury to Pluto (5848 mkm) because it expresses the planet motion (929 mkm)
in comparison with the light motion (5848 mkm=2πx 929 mkm)
- In following we analyze the distance 929 mkm to see if this distance can be found
geometrically…

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Earth Jupiter Distance Analysis (More Discussion)
- The previous analysis tries to show that, the distance between Earth and Jupiter
across the sun (929 mkm = 778.6 mkm +149.6 mkm) is defined as a basic point for
Mercury Pluto Distance (5848 mkm) where
- 5848 mkm = 929 mkm x 2π
- Let's analyze this distance in following
- The figure shows the sun and the 3 planets (Mercury – Venus – Earth)
- The 3 planets be drawn on 2 sides of the sun. and Jupiter is the planet (J)
- Now let's start our analysis
- The distance between Earth and Jupiter (on one side) = 778.6 -149.6 = 629 mkm
- The distance between Earth and Jupiter (on 2 sides) = 778.6 +149.6 = 929 mkm
- The distance between Earth and Mercury (on 2 sides) =57.9 +149.6 = 207.5 mkm
- The distance between Earth and Venus (on 2 sides) =108.2 +149.6 = 257.8 mkm
- The question is
- Are The Distances Across The Sun Be Considered Geometrically For The
Planets Motions And Orbital Distances?
- Let's test that with Venus Earth Distance in the following example

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Example no. (1)
Additional Equation (i)
Sin (23.6 deg) x 257.8 mkm = 103.4 mkm
- S= The Sun
- V = Venus
- E= The Earth
- ES = Earth Orbital Distance = 149.6 mkm
- SV = Venus Orbital Distance = 108.2 mkm
- EV = 103.4 mkm
- Notice
- The distance between Venus and Earth = 41.4 mkm and NOT 103.4 mkm. So how
this triangle be built?!
- let's move step by step:
o Earth orbital distance 149.6 mkm + Venus orbital distance 108.2 mkm =
257.8 mkm (This distance be found when Earth and Venus be on 2 different
sides from the sun with an angle 180 degrees between the 3 players)
o 257.8 mkm x sin (23.6 deg) = 103.4 mkm (=EV distance In The Triangle)
o 23.45 deg = Earth axial tilt (has a difference with 23.6 deg be 1%)
o In our triangle (SEV) the angles be defined geometrically as following
o The Angle (S) = 43.6 degrees
o The Angle (V) = 90 degrees
o The Angle (E) = 46.4 degrees (= 2 x 23.2 deg = Earth Axial Tilt error 1%)
o Now let's analyze this triangle in following

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- Is this triangle (SEV) be an imaginary one? because the distance between Venus
and earth be 103.4 mkm and the real distance = 41.4 mkm?
- We see that, the distance between the Earth and Venus can be even = 257.8 mkm
when the 2 planets be on 2 different sides from the sun. So if the distance can be =
257.8 mkm, that means, it can be also 103.4 mkm. That means this triangle can't
be an imaginary one.
- Why this triangle is useful?
- Because of the angle (E) = 2 x 23.2 degrees (Earth Axial Tilt) (error 1%)
- That tells, Earth axial tilt is produced by some interaction be found among Earth,
Venus and The Sun Data
- Why Venus angle =90 degrees?
- What Useful Results We Get From This Triangle? 2 Basic Results
- (1st
Result)
- The planets distances across the sun are used geometrically in the solar system
geometrical design.
- (2nd
Result)
- The Sun Be Perpendicular On Venus Planet in this triangle, while Earth axial tilt
be defined. Can that effect geometrically on the sun position relative to Venus and
Earth positions?
Notice
41.6 mkm = 0.384 mkm x 108.2 mkm (Venus Orbital Distance)
- 41.4 mkm = Venus Earth Distance (different from 41.6 mkm with 0.4%)
- 0.384 mkm = The Earth Moon Orbital Distance
- The data tells, The Earth moon orbital distance also be defined accordingly
- The paper provides an interesting approach to explain the solar planets motions.

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- While the solar planets motions description inherited from Newton Theory of the
sun mass gravity tells that each planet motion is independent from the other
planets motions. As a result each planet orbital distance be defined independently,
The suggested description tells that, each planet motion takes into consideration
the other planets motions.
- We here deal with a building stories found depending on one another. based on
this vision, because Venus orbital distance =108.2 mkm, that causes Earth orbital
distance to be 149.6 mkm
- And because of the 2 planets orbital distances be (108.2 mkm and 149.6 mkm) the
Earth moon orbital distance be (0.384 mkm).
- The vision is completely different from what Newton told us. while Newton
supposed the space is limitless and can contain hundreds of planets moving
without effect on each other. the fact is the 9 planets motions effect on one another
and forces each planet to define each motion in proportionality with the other
planets. The vision is different because Newton vision of (NO Effect) created
separated trajectories of motions. And based on this vision we see the planets as
cars move through track independently from one another (even the real cars can't
be independent because the track is the same one and all have to move in harmony
otherwise they will collide). The suggested description tells that, the motions be
built as a building and each motion depend on the other motions and by that they
need one geometrical design controls and manages all of them.

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Discussion
- This triangle I put here because it shows the distance between the earth and Venus
can be =257.8 mkm by put the 2 planets on 2 different sides from the sun.
- This behavior perfectly is similar to Earth Jupiter distance (929 mkm) while the 2
planets be on different 2 sides from the sun.
- I try to show that, it's part of the distances distribution system to use the planets
positions across the sun.
Notice
- The distance between Earth and Mercury across the sun be = 149.6 mkm + 57.9
mkm =207.5 mkm
- Pluto (0.406 mkm/day) moves during 511 days a distance = 207.5 mkm
- Where
- 511 degrees = The Solar Planets Axial Tilts Total
- A Summary
- The distances between Mercury and Pluto be distributed based on geometrical
design to create a proportionality between the 3 planets motions for periods (720.7
mkm). (the 3 planets are Mercury – Jupiter – Pluto)
- The distance distribution be performed by light motion effect on te planets
distances creation.

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5-3 Planets Motions Interaction
I- Data
(1)
8 x 9.9 x 3600 s = 285120 s = π x 90756.2 seconds
(90756.2 seconds – 90560 seconds) = 196.5 seconds
(2)
196.5 sec x 1.16 mkm/sc = 227.9 mkm (Mars Orbital Distance)
(3)
(90560 mkm x 2) = 227.9 mkm x 198.7
(4)
170 sec x 1.16 mkm/sec = 197.2 mkm
(5)
655.7 sec x 0.3 mkm/sec = 196.7 mkm
(6)
196.5 sec x 27.78 km/sec = 10921 km/2
(7)
194 sec x 35 km/sec = 6792 km
(8)
193 sec x 0.3 mkm/sec =57.9 mkm (Mercury Orbital Distance)
(9)
193.7 sec x 1.16 mkm/sec =224.7 mkm
224.7 sec x 1.16 mkm/sec =521.3 mkm
(10)
30589 days = 58.65 days =521.3
(11)
606.3 mkm = 193 mkm x π = 1.16 mkm/sec x 522 sec
(12)
643.3 sec x 0.3 mkm/sec = 193 mkm

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(13)
3735072 km = 196.5 x 19000
720.7 mkm =3.735 mkm x 193
And
(5687.1 mkm = 19000 sec x 0.3 mkm/sec)

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II –Discussion
- Let's summarize the analysis basic idea in following
- The theory tells, the light supposed velocity (1.16 mkm/s) started from Mercury
passing Jupiter, Pluto and Mars
- Light supposed velocity (1.16 mkm/s) motion effects on the 4 planets caused the 4
planets to move equal distances (720.7 mkm) in equal periods of time (4222.6h)
- Because of this motion
- 3 Planets motions depend on the period (196.5 seconds)
- The data discussion will explain the meaning of planet motion dependency on the
period of time 196.5 seconds.
- Because the 3 planets motions depend on equal periods of time (196.5 s) their
motions be integrated and unified into one general unified motion
- As A Result
- Mercury, Mars and Jupiter moves One Unified General Motion.
- This Unified Motion Be Proved in the 3 planets motions data.
- This point of discussion shows that, the 3 planets motions depend on the period
(196.5 seconds).

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Equation no. (1)
8 x 9.9 x 3600 s = 285120 s = π x 90756.2 seconds
(90756.2 seconds – 90560 seconds) = 196.5 seconds
- Where
- 9.9 hours = Jupiter day period
- 90560 days =Pluto orbital period
- (8 days of Jupiter motion creates Jupiter 8 days cycle)
- The equation uses Pluto orbital period (90560 days) in seconds unit (90560
seconds) why?
- We know this answer, and keep it by heart
- (Light Motion For 1 Second Causes A Planet Motion For 1 Solar Day)
- By that, all periods in solar day units for planets motions be considered in second
units for light motion.
- What we need from this equation?
- The period 196.5 seconds
- This period is the connection reason among the 4 planets motions (Mercury – Mars
– Jupiter and Pluto)
- In fact our discussion cornerstone is the period 196.5 seconds
- Why is this period 196.5 s important for the planets motions?
- Because it's created by interaction between Jupiter and Pluto motions. and the
paper main equation which we have discussed deeply before tells
Equation no. (I) (The Paper Main Equation)
1.16 mkm per second x 2 x 86400 seconds =2 x 100733 mkm = (37100 mkm –
4900 mkm) x 2π = 28255 mkm + 2 x 86400 mkm
- We have discussed this equation before

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- This equation shows, the solar system basic energy is sent from Jupiter to Pluto
and then reflected from Pluto to Neptune, means, the interaction between Jupiter
and Pluto deal with the solar system basic energy…
- This conclusion shows a great significance for the interaction between Jupiter and
Pluto motions. As a result, the value 196.5 seconds should be considered as a very
important period in the solar system motion.
- But
- 8 Jupiter days create (planet 8 days cycle for Jupiter). Can this period 196.5
seconds have any relationship with (Jupiter 8 days cycle?) we should in equation
no. (13) of this discussion.
- Notice
- The period 196.5 sec is defined by an interaction between Jupiter and Pluto
motions, and
- Light known velocity (0.3mkm/sec) needs 193 sec to pass Mercury orbital distance
(57.9 mkm).
- That means, Mercury orbital distance be defined by an effect of Jupiter and Pluto
motions interaction.
- That tells, Mercury Jupiter distance is defined at first and then the light beam built
Pluto orbital circumference and after that Mercury orbital distance be defined. (or
the sun position be defined)

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Equation no. (2)
Equation no. (8)
- The period 193 seconds is different from the period 196.5 seconds with (2%)
- We neglect this difference (2%) for now and consider the 2 periods are equal
- Now
- By equal periods of time (196.5 seconds), the 2 light beams defined the 2 planets
orbital distances…
- Light supposed velocity (1.16 mkm/sec) during (196.5 sec) travels a distance =
227.9 mkm = Mars orbital distance
- Light known velocity (0.3 mkm/sec) during (193 sec) travels a distance = 57.9
mkm = Mercury Orbital Distance
- By equal periods of time the 2 light different velocities defined the 2 planets
orbital distances.
- What Effect Can Be Produced By The Equal Periods Of Time?
- We deal with light motion…. let's use one example for help
- In light motion, if there's a phase between the light waves the experiment will
produce an interference but if there's no phase we will see light waves without
interference
- The phase creates the differences in motions
- But without phase
- The motions will be unified in one, means
- Mercury, Mars And Jupiter Move One Unified General Motion Because The
3 planets Use Equal Periods Of Time…

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- Let's summarize what we have…
- The 3 planets use equal periods of time (196.5 seconds) and by that their motions
will be unified in one unified general motion.
- The period 196.5 seconds is born by interaction between Jupiter and Pluto
motions. where this interaction express the solar system basic energy
- The unification of motions between Mercury, Mars and Jupiter can be produced by
Jupiter dependency on Mercury and Mars motions because they are the first and
last planets in the inner group and by that Jupiter creates a connection with the
inner planets through its connection with Mercury and Mars

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Equation no. (2) (Continued)
Equation no. (8)
- We know that mercury, Venus and Earth define their orbital circumferences to be
equal their distances to Jupiter.
- means, Mercury position is defined in the space relative to Jupiter position.
- Mars defined its orbital circumference to be equal Saturn orbital distance…
- That tells, Mercury and Mars positions are defined relative to Jupiter and Saturn
positions.
- And
- Their distances to the sun be defined by using equal periods of time (196.5 sec)
- Let's ask, if the 2 planets positions are defined, what result of their using of equal
periods of time?
- They almost define the sun position in the solar system
- The theory tells, the sun is created after all solar planets creation and motion. the
equal periods be used almost to define the sun position in the solar system relative
to Mercury and Mars positions relative to Jupiter position.
- The point is that,
- Mercury (4.095 mkm/day) moves during its rotation period (58.65 days) a distance
= 243mkm (error 1%)
- Mars (2.082 mkm/day) moves during Venus day period (116.75 days) a distance =
243 mkm
- Where, 243 mkm x 0.8 =196.5 mkm
- This motion is almost related to the sun creation process
Notice
- 243 mkm x 2 =40080 km (Earth Circumference) x 12104 km (Venus diameter)
- 29.8 km/sec x 12104 seconds = 3 x 120536 km

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Equation no. (3)
(90560 mkm x 2) = 227.9 mkm x 198.7
Equation no. (4)
170 sec x 1.16 mkm/sec = 197.2 mkm
- Where
- 90560 days = Pluto Orbital Period
- 170 mkm = The Distance Between Mercury And Mars
- Equation no.(4) we have discussed in the distances series discussion (point no. 3)
of this current paper.
- Equation no. (3) tries to show that Pluto orbital period be in proportionality with
the period (196.5s)
- Notice
- The error (2%) between 193 seconds and 197 seconds we don't discuss because,
the machine is so complex
- We usually find the data in rates (100%, 99%, and 98%) these rates are repeated
frequently, and these rates may be created because of one geometrical necessity,
- For example Earth moves during its day period a distance =2.574 mkm (100%) but
the moon displacement total during 29.53 days =2.598 mkm (101%) and the moon
apogee orbital circumference =2.550 mkm (99%)
- The rates (98%, 99% and 100%) are used frequently, I can't write all data which
use these rates and can't explain the reason of it.

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Equation no. (5)
655.7 sec x 0.3 mkm/sec = 196.7 mkm
Equation no. (6)
196.5 sec x 27.78 km/sec = 10921 km/2
Equation no. (7)
194 sec x 35 km/sec = 6792 km
- Where
- 655.7 hours = The Moon Rotation Period
- 27.78 km/sec = The Moon Velocity
- 10921 km = The Moon Circumference
- 6792 km = Mars Diameter
- What do we need from these equations?
- Shortly
- We need equation no. (6) because it shows that, the moon circumference depends
on the period (196.5 seconds)
- We remember that,
- The 3 Planets (Mercury – Mars and Jupiter) depend on equal periods (196.5 sec) in
their motions. and these equal periods (196.5 sec) causes the 3 planets motions to
be unified in one general unified motion.
- Means, the period (196.5 seconds) is the cornerstone of these 3 planets motions.
- Now
- The moon circumference (10921 km) depends on the period (196.5 sec) also
- So, we have more players be under the same one unified general motion. because
the moon uses the same period, so no phase will be between the moon motion and
Jupiter motion, on the contrary, they move together one unified motion…
- That may explains the important following equations:
(NO. A)
- 4900 mkm (Jupiter orbital circumference) = 10921 km x 449197 km

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- Where
- 10921 km = The Moon Circumference
- 449197 km = Jupiter Circumference
(NO. B)
- Jupiter (13.1 km/sec) moves during 10921 sec a distance = 142984 km = Jupiter
diameter.
(NO. C)
- The moon (27.78 km/sec) moves during 5127 sec a distance = 142984 km =
Jupiter diameter.
- (where 5127 mkm = Jupiter Pluto distance)
- Notice
- Light supposed velocity (1.16mkm/sec) travels during 4900 sec a distance =
5678.1 mkm (Mars Pluto Distance)
- Notice
- The moon orbital apogee radius 406000km = 2jupiter diameters + 1 Saturn
Diameter.
Notice
- Why the moon velocity be =27.78 km/s? because the moon moves daily a
distance = Earth motion distance daily because they aren't separated from one
another. means the moon daily motion distance =2.574 mkm but this distance be
effected by the rate 1.0725. (we have referred to that frequently before). We don't
know why the distance 2.574 mkm be effected by the rate (1.0725) but 40% of all
distances in the solar system be effected by this same rate 1.0725 and appendix
no.1provides a list for these distances. By that the moon distance 2.574 mkm be
=2.4 mkm daily which =27.78 km/sec.

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Equation no. (8)
Equation no. (9)
193.7 sec x 1.16 mkm/sec =224.7 mkm
224.7 sec x 1.16 mkm/sec =521.3 mkm
Equation no. (10)
30589 days / 58.65 days =521.3
- Where
- 224.7 days = Venus Orbital Period
- 30589 days = Uranus Orbital Period
- 58.65 days = Mercury Rotation Period
- Equations (8), (9) and (10) show that, the rate between Uranus orbital period and
Mercury rotation period depends on the period (193 seconds) by light motion.
- The data shows that, the series creates a connection between the 2 planets
- But
- Mercury rotation period is related to Uranus motion by some complex geometrical
interaction because
- Mercury Uranus distance = 2814.6 mkm
- But
- 2815.2 hours = 2x 1407.6 h (Mercury rotation period)
- If 1 mkm = 1 hour that makes the distance 2815.2 mkm= 2 Mercury Rotation
Period, And
- Mercury moves during its rotation period a distance = 243mkm (error 1%)
- Where 243 days = Venus rotation period
- If 243 mkm be equivalent to 243 days that tells 1 mkm = 1 day
- By that Mercury creates with Uranus the rate of time (1 hour of mercury = 24
hours of Uranus) we discuss that in Planets motions use different rates o time point
no.(7) of this paper.

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Equation no. (11)
606.3 mkm = 193 mkm x π = 1.16 mkm/sec x 522 sec
- This equation gives 3 branches of data let's summarize each one in following
- (1st
Branch)
- 606.3 seconds x 1.16 mkm/sec = 703.3 mkm
- 703.3 seconds x 1.16 mkm/sec = 816 mkm
- 816 seconds x 1.16 mkm/sec = 946.6 mkm
- Where
- We remember that
- 5848 mkm (Mercury Pluto distance) – 4900 mkm (Jupiter orbital circumference) =
948 mkm (Earth Orbital Circumference) (error 1%)
- That means,
- The value (606.3 mkm) is connected with light supposed velocity (1.16 mkm/sec)
motion trajectory from Mercury to Jupiter and then to Pluto. This trajectory is the
1st
trajectory we have studied…
- (2nd
Branch)
- 193 seconds x 0.3 mkm/sec = 57.9 mkm (Mercury Orbital Distance)
- 193.7 seconds x 1.16 mkm/sec = 224.7 mkm (Venus orbital period 224.7 days)
- 224.7 seconds x 2 x 1.16 mkm/sec = 521 mkm
- (3rd
Branch)
- 30589 days (Uranus orbital period) = 58.65 days (Mercury rotation period) x 521
- Equation no. (11) connects many basic data together.

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Equation no. (12)
643.3 sec x 0.3 mkm/sec = 193 mkm
- Equation no. (12) is important because
- Jupiter moves during 636 days a distance = 720.7 mkm (where 636 days is
different from 643.3 days with 1%)
- The period (643.3 days) be used as (643.3 sec ) for light motion
- Equation no. (12) tells that, light known velocity (0.3 mkm/s) travels during (643.3
s) a distance = 193 mkm
- That causes the period 193 second be found related to the distance 720.7 mkm
- The basic difficulty is that the light creates geometrical interactions aren't clear for
our analysis and by that many geometrical effects be created but aren't known for
us because we don't realize perfectly how the machine works.

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Equation no. (13)
3735072 km = 196.5 x 19000
720.7 mkm =3.735 mkm x 193
And
(5687.1 mkm = 19000 sec x 0.3 mkm/sec)
- Where
- 3735072 km=the distance be passed by Jupiter during 8 Jupiter days (please
review Jupiter 8 days cycle)
- 19000 seconds the light known velocity (0.3 mkm/sec) needs to pass the distance
from Mars to Pluto (5678.1 mkm)
- We remember that
- 4900 sec x 1.16mkm/sec = 5687.1 mkm = (Mars Pluto Distance)
- The point is that,
- 720.7 mkm (Mercury Jupiter distance) = 3.735 mkm x 193
- That tells, the period (193 seconds) is defined by a geometrical mechanism takes
into consideration Mars Pluto Distance.
- Because, in fact
- Mars connection with Mercury and Jupiter be created through Pluto. where the
light supposed velocity (1.16 mkm/s) travels from Mercury to Jupiter directly and
doesn't touch Mars in the way.

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References and Biography
(Preprint No. 1) Mars Migration Theory
https://www.academia.edu/49051037/_Preprint_No_1_Mars_Migration_Theory
(Preprint No. 2) The Moon Orbital Motion Equation
https://www.academia.edu/49051029/_Preprint_No_2_The_Moon_Orbital_Motion_Equation
The Solar Planets Motions Description (Revised)
https://www.academia.edu/49464125/The_Solar_Planets_Motions_Description_Revised_
The Moon Orbital Motion Geometry (II)
https://www.academia.edu/45181646/The_Moon_Orbital_Motion_Geometry_II_
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944p=15209
Mr. Gerges Francis Tawdrous +201022532292
Physics Department- Physics Mathematics Faculty
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
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The Solar System Motion Depends On A Light Beam Motion

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