The Solar Planets Motions Description (Revised)

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
The Solar Planets Motions Description (Revised)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –29th
June 2021
Abstract
Paper Hypothesis
The Solar Planets Motions Create One Unified General Motion.
The Hypothesis Explanation
- The hypothesis tells the planets motions be similar to Train Carriages Motion
- Also the planets motions be similar to Chess Pieces Motions
- The hypothesis discovers One Law controls the solar system motion and data.
- The planets unified general motion forces each planet motion to be complementary
with other planets motions to perform The Unified General Motion. as a result,
The Planet motion be An Obligatory Motion.
- Based on that, The Solar Planet Can't Change Its Motion.
- The Solar Planet creates its data to be in consistency with its motion.
- Because, the planet can't change its motion, but can change its data to be in
consistency with its motion. and because of that, the planet data be created in
consistency with its motion.
- Because the planet motion be complementary with other planets motions.
- The planet data be created complementary with other planets data

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- Based On This Vision
- The solar planets data be created based on One Geometrical Design.
- And
- The Planets Creation And Motions Data Be Controlled By One Equation Only
- The paper hypothesis gives a different vision from the solar planets classical
description. because its tells that, (The Solar Planet Data Be Created Based On
Geometrical Calculations And Rules). The classical description tells planets data
be created by random process and without geometrical reasons behind.
- The Planets Unified General Motion proves discussion shows that, the hypothesis
tells the fact.
Paper Main Question
- Can The Planets Motions By Masses Gravity Forces Create The Planets Unified
General Motion?
Please scan the figure (ORCID)

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Contents
Subject Page No.
1- Introduction 4
2- Methodology 6
3- The Planets Unified General Motion Proves Discussion 9
3-1 The Planets Unified General Motion Meaning 10
3-2 The Planets Unified Motion 1st Feature (Complementary Motions) 12
3-3 The Planets Unified Motion 1st Feature Proves14
3-4 The Planets Unified Motion 2nd
Feature (Train Carriages Motions) 28
Feature Proves 29
3-6 The Planets Unified Motion 3rd
Feature (Different Rates of Time Using) 42
3-7 The Planets Unified Motion 3rd Feature Proves 44
4- Planet Motion Analysis 61
4-1 Preface 61
4-2 The Equal Distances Geometrical Effect 62
4-3 Can electric field control the inner planets? 64
4-4 The Planets Unified General Motion Effect 67
5- The Sun Creation Details. 68
5-1 Preface 68
5-2 The Solar System Unified Motion 70
5-3 The Sun Rate Of Time 77
6- The Moon Orbital Motion Description 80
6-1 Why Does The Moon Use Pythagorean Triangle In Its Motion? 81
6-2 How Does The Moon Use Pythagorean Triangle In Its Motion? 82
6-3 The Moon Orbital Motion Analysis 84
6-4 The Moon Orbital Motion Equation 88
Appendix No.1 The Solar System Equal Distances List 97
References and Biography 99

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1-Introduction
- The paper question provides a point of comparison in the solar planets motions.
- The question asks, (Can The Solar Planets Motions By Masses Gravity Forces
Create The Planets Unified General Motion?)
- I have 3 basic proves for The Planets Unified General Motion. these proves are
powerful and sufficient (as I consider).
- We discuss these 3 proves directly in Point no. (3) after Paper Methodology (point
no.2)
- The proves are sufficient and can prove the hypothesis. But what will happen
after? The Hypothesis Opens Another Universe Before Us.
- Planets data which we considered as data be created by unknown historical factors
and its reasons can't be discovered. This whole vision will be removed and in place
of it, the new vision tells, based on geometrical calculations and rules the planets
data be created complementary one another.
- We know in the double production experiment that, an electron and a positron be
created from Gamma ray, where the 2 particles charges be complementary with
one another because of Charge Reservation Law. Then we have to use this
experiment as example for the solar planets data which is created complementary
with one another to enable the planets to move complementary motions by which
the planets unified general motion will be created.
- It's completely another vision toward the universe
- If we can't accept this vision we have to remove the hypothesis and (again)
consider each planet moves an independent motion from the others.
- The Planets Unified General Motion 3 Basic Proves are discussed in around
(50 Pages). The fact is strong and has a massive effect.

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- The situation is complex because a great proof is found to support the planets
unified general motion on one side, but, on the other side there's no theoretical
description can explain how this motion be done.
- As a result we have to create a comparison between Planet motion and its theories.
- Let's take a look on this paper contents
- Point no. (3) (Planets Unified General Motion Proves Discussion)
- Point no. (4) (Planet Motion Analysis)
- Point no. (5) (The Sun Creation Details)
- Point no. (6) (The Moon Orbital Motion Description)
- The paper basic point is The Point No. (4) because
- After we prove strongly and clearly the planets unified general motion, we have to
answer the paper question (Can The Planets Motions By Masses Gravity Forces
Create The Planets Unified General Motion?)

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2-Methodology
- I use the solar planets data analysis to discover the planet creation and motion.
- This method creates a comparison between the solar planets data and the theories
which try to explain these planets motions. let's see examples of these comparisons
in following:
(I)
- The solar planets order contradicts the gravitation equation, because Jupiter the
greatest mass is in order no. (5), and the 3 planets (Mercury –Venus –Earth) shows
that greater mass needs longer orbital distance and not shorter. Also Uranus (less
mass) be more near to the sun than Neptune (greater mass).
- This data doesn't disprove the gravity concept nor the gravitation equation. But the
comparison is useful because it creates interesting questions.
(II)
- While the theory tells, The Solar Planet Velocity should be defined based on the
masses gravity forces, we find that,
- (Venus Velocity / Uranus Velocity) = (Mars Velocity / Pluto Velocity) = 5.1
- And
- (Mercury Velocity / Jupiter Velocity) = (Venus Velocity / Saturn Velocity) =3.6
- I don't disprove any theory by this data.
- I try to show, it's useful to use Planets data in comparison with the theory tries to
explain it.
(III)
- Earth Mass = The Masses total of (Mercury + Venus + The Moon + Mars)
- And
- Earth Circumference = The 5 inner planets diameters total
- (Means the diameters total of (Mercury + Venus + The Moon + Earth + Mars))
- The classical description tells, Planet data be created by random process and
without geometrical reasons behind. Can This Vision Explain This Data?

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- I have provided thousands of similar interesting data, and I tried to show that, this
data be created based on geometrical reasons. But the data be refused frequently
under the claims (Pure Coincidences Of Numbers).
- Why these are (Pure Coincidences of numbers)?
- The moon orbital period = the moon rotation period =27.3 days, this data be
created based on geometrical and physical reason… but
- The moon apogee orbital circumference (2.55 mkm) = Earth motion distance
during a solar day (2.574 mkm) (error 1%). This data be considered as pure
coincidence has no geometrical reason behind!
- Who can distinguish between the data which is created by pure coincidence and
those be created based on geometrical reasons? (Why pure coincidence claim is
found?!) because no available answers …let's tell the story details in following….
- The theory couldn't answer the first question (How The Matter Is Created?), So
the human imagination used the chance to create imaginary ideas. Every one
believes that, Planet data be created by unknown historical reasons which can't be
discovered and have no effect on this planet current motion. This illogical vision
deceives us. Where the fact is clear, because the planet moves depends on its data,
so whatsoever the historical events be, the planet motion still depend on its data.
By this Vision, Planet Data will be similar to (A Creature Genes). And when we
analyze the planets data we can discover how this planet be created and moving.
- (Where is the mistake?) The imaginary ideas
- Planets data be left and the theories be created without using Planet data as a
reference. By That a gab be created between the theory and the fact.
- And then the shock be the logical result… The following data shows that we know
a little about the solar system motion….

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o Jupiter (13.1 km/s) moves during 10921 sec a distance = 142984 km=Jupiter
diameter (where 10921 km = The Earth Moon Circumference)
o Uranus (6.8 km/s) moves during 7510 sec a distance = 51118 km= Uranus
diameter (where 7510 km = Pluto Circumference)
o Pluto (4.7 km/s) moves during 10921 sec a distance = 51118 km= Uranus
diameter
o Pluto (4.7 km/s) moves during 51118 sec a distance = 2 x 120536 km=
Saturn Diameter
o Pluto (4.7 km/s) moves during 2 x 120536 sec a distance = 1.1318 mkm=
Jupiter Motion Distance During A Solar Day
- This data is a few of similar tenths and may hundreds. I don't know how to use a
planet diameter as a period of time and have no explanation. But I know the basic
question is left behind (How The Matter Is Created?) and the shocks must be our
punishments as a result.
- The method of research put planets data on one side and the theory on the other
side trying to know if the theory explains planet data or left it behind.

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3- The Planets Unified General Motion Proves Discussion
3-1 The Planets Unified General Motion Meaning
3-2 The Planets Unified Motion 1st
Feature (Complementary Motions)
Feature Proves
Feature (Train Carriages Motions)
Feature Proves
Feature (Different Rates of Time Using)
Feature Proves

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3-1 The Planets Unified General Motion Meaning
- The paper hypothesis tells
- (The Solar Planets Motions Create One Unified General Motion)
- This Unified General Motion is consisted of the planets motions. By That, Each
Planet Motion Should Be Complementary With Other Planets Motions To Create
The One Unified General Motion. And that causes the planets motions to be
obligatory motions. means, no planet has the chance to change it motion because
that will effect negatively on the planets unified general motion.
- That means, the planet motion can't be defined based on this planet data. But be
defined based on the unified general motion. as in chess board. Any piece can
move only by defined obligatory motion depends on battle situations.
- Now, the planet found itself in an obligatory motion. let's suppose this planet data
isn't suitable for this obligatory motion, what would happen? The planet will
change its data to be in consistency with its obligatory motion. because the planet
data can be changed but the obligatory motion can't.
- The unified general motion idea creates one law controls the planets motions and
data. And That Creates One Direction Of Planets Data. means, the planets data
can't be created by a random process, because in this case the motion will be
random motion and the unified general motion will be destroyed.
- Because each planet motion be complementary with other planets motions, and
each planet data be created in consistency with this planet motion. the planets data
be created complementary with each other. based on that,
- The planets data be created based on One Geometrical Design. By that, the data
enables the planet to move its obligatory motion and to create a complementary
motion.
- The planets unified motion doesn't mean one typical motion be done by all planets.
But means, one motion is divided into several tasks and each task be done by one
planet motion and by that the tasks total create the unified motion.

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- Let's summarize the planets unified general motion features in following
o The motions be complementary with each other as machine of Gears
Motions.
o The motions be unified with each other as Train Carriages Motion
o The motions be defined obligatory as Chess Pieces Motions
o The planets motions use different rates of time
- The Proves Of The Planets Unified General Motion proves the 3 basic features
which are
o The Motion Is A Complementary Motion
o The Motion Is A Unified Motion
o The Motion Uses Different Rates Of Time
Notice
After the proves discussion we should discuss the paper main question which is (Can
The Planets Motions By Masses Gravity Forces Create The Planets Unified
General Motion?)
This question is discussed in Point no. (4) (Planet Motion Analysis)

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Feature (Complementary Motions)
- What Does Mean "Complementary Motions"?
- Let's see the following data:
(I)
- 4900 mkm = 360 mkm + 680 mkm + 940 mkm + 1433 mkm +1433 mkm (1%)
- Where
- 4900 mkm = Jupiter Orbital Circumference
- 360 mkm = Mercury Orbital Circumference
- 680 mkm = Venus Orbital Circumference
- 940 mkm = Earth Orbital Circumference
- 1433 mkm = Mars Orbital Circumference
- The data uses (1433 mkm two times), (because the data considers the Earth moon
orbital circumference around the sun = Mars orbital circumference =1433 mkm)
(Later we should explain why)
- So, Let's ask
- Does Jupiter Orbital Circumference = The Inner Planets Orbital
Circumferences Total? And Why?
(II)
- Mercury moves during its day period a distance = 720.7 mkm = Mercury Jupiter
distance
- Venus orbital circumference =680 mkm = Venus Jupiter distance 671 mkm (1.2%)
- Earth orbital circumference =940 mkm =Earth Jupiter distance 928 mkm (1.2%)
(Earth and Jupiter should be on 2 different sides of the sun to create 928 mkm)
- So, let's ask
- Does The 3 Inner Planets Define Their Orbital Circumferences To Be Equal
Or Rated With Their Distances To Jupiter? And Why?

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- The data refers to one clear meaning, which is, The 3 inner planets define their
orbital circumferences based on their distances to Jupiter and Jupiter orbital
circumference be defined as the inner planets orbital circumferences total.
- It's A Mutual Effect
- Based on the previous data we have to consider complementary motions be found
between the inner planets on one side and Jupiter on the other side.
- The complementary motions means,
- The one motion data be distributed among many planets. And by that one planet
uses other planets motions data. This behavior contradicts Motion Independence
Concept.
- Let's Summarize The Situation In Following:
o Planet Motion uses other Planet Motion Data clearly and frequently. A
behavior contradicts Planet Motion Independence Concept.
o The data shows frequently such using as we will see in the proves
o If we believe in Planet motion independence concept, we have to consider
the data be found by (Pure Coincidence) which makes the planets data
useless
o Or
o We have to consider that, the planets motions be complementary motions
with one another and Planet Motion Independence Concept is incorrect.
o Let's discuss this point proves data in the next point.

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Feature Proves (Complementary Motions)
3-3-1 Mercury Day Period Analysis
I- Data
- 4900 mkm =1.16 mkm x 4222.6,
- where
- 4900 mkm = Jupiter Orbital Period
- 1.16 mkm = A distance Jupiter passes in =24.6 h (= Mars Rotation Period)
- 4222.6 hours = Mercury Day Period
II- Discussion
- The previous data tells that
(1)
- Jupiter (13.1 km/s) moves during 24.6 hours (Mars Rotation Period ) a distance =
1.16 million km.
(2)
- Jupiter orbital circumference 4900 mkm is divided on the distance 1.16 mkm by
the value 4222.6.
- That means
- Jupiter during 4222.6 Mars rotation periods move a distance = 4900 mkm = Jupiter
orbital circumference.
(3)
- 4222.6 hours = Mercury Day Period
- How to understand this data?
- The data tells,
- If 1 hour of Mercury Day Period = 24.6 hours of Jupiter motion, in this case,
Jupiter will pass its orbital circumference in a period = Mercury Day Period.
- Can we conclude that, some interaction be found among these 3 motions?
- The Following Data Proves This Motions Interaction (Or Complementarity)

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3-3-2 Jupiter Motion Data Analysis
(Point No. I) (Jupiter Orbital Circumference Analysis)
I- Data
(A)
- Jupiter orbital circumference = The inner planets orbital circumferences total
- In numbers,
- Where
- The data considers the moon orbital circumference around the sun = Mars Orbital
Circumference 1433 mkm (and not equal Earth Orbital Circumference 940
mkm) (Later We Should Discuss Why?)
(B)
- Mercury moves during its day period (4222.6 h) a distance = 720.7 mkm =
Mercury Jupiter distance
- Venus orbital circumference 680 mkm = Venus Jupiter distance 671 mkm (error
1.2%)
- Earth orbital circumference 940 mkm = Venus Jupiter distance 928 mkm (error
1.2%) (Earth and Jupiter should be on 2 different sides from the sun to create the
distance 928 mkm).
- The 3 Inner Planets Define Their Orbital Circumferences To Be = Their
Distances To Jupiter.

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(C)
(1)
778.6 mkm = 1.0725 x 720.7 mkm (Mercury Jupiter Distance)
(2)
720.7 mkm = 1.0725 x 671 mkm (Venus Jupiter Distance)
(3)
671 mkm = 1.0725 x 629 mkm (Earth Jupiter Distance)
(D)
(4)
778.6 mkm (Jupiter orbital distance) = 1.16 x 671 mkm
(5)
720.7 mkm = 1.16 x 629 mkm (error 1%)
(6)
671 mkm = 1.16 x 580 mkm
- The data shows, the distances between Jupiter and the inner planets are defined
based on Geometrical Calculations, because of that all distances are rated with
(1.0725) and (1.16).
- Means, these planets motions are not independent motions, on the contrary they
are (complementary motions) and be created based on One Geometrical Design.
By That each planet motion data is defined in proportionality with other Planets
motions data.
- Please Notice
- We deal with the same players, Jupiter on one side and the 3 inner planets on the
other side. Their data be used frequently in different rates and forms. If there's no
geometrical reason be found behind this data, We would have to suppose tenths of
data of the same players are found by (Pure Coincidences), which is a claim has no
a piece of logic.
- The fact is clear. Some geometrical mechanism or (complementarity of motions)
be found among these planets and as a result this geometrical mechanism be seen
in their different motions data.

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(E)
(i)
201467 mkm = 2 x The Planets Orbital Circumferences Total 100733.5 mkm
(ii)
201467 mkm = (Pluto Orbital Circumference – Jupiter orbital circumference) x 2π
(iii)
201467 mkm = 28255 mkm + 2 x 86400 mkm
- The data tells something very interesting…
- Jupiter Pluto Orbital Circumference x 2π = 2 x The Planets Orbital
Circumferences Total!
- And
- Jupiter Pluto Orbital Circumference x 2π = 28255 mkm (Neptune orbital
circumference) + 2 x 86400 mkm (Neptune Venus Orbital Circumference x 2π)
- 3 Distances in the solar system = Jupiter Pluto Orbital Circumference x 2π
- The 3 distances are (2 x The Planets Orbital Circumferences Total) and
(28255 mkm + 2 x 86400 mkm) and (Jupiter Pluto Orbital Circumference x 2π)
- The choices are known, we have to suppose (a geometrical reason behind) or (pure
coincidences). I choose a geometrical reason behind which proves that the solar
system data be created based on One Geometrical Design

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(Point No. II) (The Interaction between Mercury, Mars and Jupiter)
(Sub-Point No. 1) (Mercury and Mars Motions)
- Mercury moves during its day period (4222.6 h.) a distance = 720.7 mkm
- Mars moves during (2802 hours) a distance = 243 mkm
- Mercury moves during (1407.6 hours) a distance = 243 mkm (error 1%)
- Mars moves during 346.6 d. a distance =720.7 mkm (Mercury Jupiter Dis.)
- Mercury moves during 346.6 d. a distance =1419 mkm (with 1433 error 1%)
- Mars moves during 687 d. a distance = 1433 mkm (Mars orbit. Circum)
- Mercury moves during 687 d. a distance =2815mkm (Mercury Uranus Dis.)
- Mars moves during 4331d. a distance = 9010mkm (Saturn orbit. Circum)
- Mercury moves during 4331d. a distance = 2815 mkm x 2π
- Mars moves during 224.7 d. a distance = π x 149.6 mkm (Earth orb. Dis)
- Mercury moves during 224.7 d. a distance = 920 mkm (with 928 error 1%)
- Mars moves during 365.25 d. a distance = π x 243 mkm (0.5%)
- Mercury moves during 365.25 d. a distance = 2 x 748 mkm
- Mars moves during 5040s. a distance= 121464 km= Saturn Diameter (+1%)
- Mercury moves during 5040s. a distance= 238896 km= 2 Saturn Diameters (-1%)
Where
1407.6 h = Mercury Rotation Period 2802 h = Venus Day Period
346.6 days = the nodal year 224.7 days = Venus orbital period
687 days = Mars Orbital Period
4331 days = Jupiter orbital period = 2π x 687 days

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(Sub-Point No. 2) (Mars And Jupiter Motions)
- Mars moves during 636.7 days a distance =1325 mkm= (Venus Saturn Dis.)
- Jupiter moves during 636.7 days a distance =720.7 mkm
- Mars moves during 687 d. a distance= 1433 mkm= Mars Orbital Circumference
- Jupiter moves during 687 d. a distance= 778.6 mkm= Jupiter Orbital Distance
- Mars moves during 4331d. a distance= 9010 mkm= Saturn orbital circumference
- Jupiter moves during 4331 d. a distance= 4900 mkm= Jupiter Orbital Circum.
- Mars moves during 778.6 d. a distance = 1622 mkm = Uranus Neptune Dis.
- Jupiter moves during 778.6 d a distance= 881 mkm =58 days x 15.19 mkm.
- ( 15.19 mkm = the 9 solar planets motions distances total per a solar day).

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(Sub-Point No. 3) (Mercury And Jupiter Motions)
- Mercury moves during 687 d. a distance= 2815 mkm= Mercury Uranus Distance
- Mercury moves during 1433 d. a distance =5848 mkm= Mercury Pluto Dis.
- Jupiter moves during 1433 d a distance =1622 mkm=Uranus Neptune Dis.
- Mercury moves during 4331d. a distance= 2815 mkm x 2π
- Mercury moves during 4222.6 h a distance = 720.7 mkm
- Jupiter moves during 4222.6 h a distance = 200 mkm = 629 mkm/π
- Mercury moves during 550.7 d a distance = π x 720.7 mkm (0.4%)
- Jupiter moves during 550.7 d a distance = 629 mkm (error 1%)
Please Remember,
Data Group No. (1)
- Mars moves during 687 d. a distance= 1433 mkm= Mars Orbital Circumference
- Mars moves during 4331d. a distance= 9010 mkm= Saturn orbital circumference
- Mars moves during 4331 x π d a distance= 28255 mkm= Neptune orbital circumference
Data Group No. (2)
- Mercury moves during 687 d. a distance= 2815 mkm= Mercury Uranus Distance
- Mercury moves during 4331d. a distance= 2815 mkm x 2π
Data Group No. (3)

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II-Discussion
- The planets move defined distances in defined periods of time.
- The Defined Distance means a distance is known in the solar system, as to be any
planet orbital distance or a distance between any 2 planets.
- The Defined Periods Of Time means a period of any planet cycle, as 365.25 days
(Earth orbital period) or any planet orbital period. Or any planet rotation period or
any planet day period. All these periods are defined periods of time
- The argument tells that
- If the solar planets move their motions independently from one another, based on
that, the planets motions during defined periods of time should pass (random)
distances. Because these Planets are independent in their motion from one
another. (For example) Mercury motion depends on its orbital period (88 days) and
doesn't interest for Mars orbital period (687 days) neither for Jupiter orbital period
(4331 days) and by that, Mercury during these periods (687 days and 4331 days)
should move some random distances (not defined in the solar system distances).
- The data disproves Planet Motion Independency Concept. because the (3)
planets move defined distances in defined periods of time. These planets motions
aren't independent from one another. These motions are done based on One
Geometrical Design. And these motions be are similar to Chess Board Pieces
Motions. Each Motion is calculated geometrically and be obligatory.

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Data Analysis
(I)
- 4331 days (Jupiter orbital period) = 687 days (mars orbital period) x 2π
- 2 x 346.6 days (the nodal year) = 693.2 days (different from 687 with 1%)
- 687 days (Mars Orbital Period) = 1.0725 x 636.7 days
- This data creates one thread for these 4 values (4331, 687, 346.6 and 636.7),
means,
- These 4 periods of time are created based on each other. they are created to be
used in one motion.
(II)
- Mars orbital period 687 days (24 h) = 671 Mars rotation period (24.6h)
- 671 mkm = Venus Jupiter Distance
- 680 mkm = Venus Orbital Circumference (different 1% with 687 mkm)
- The distances values be used frequently as periods of time
- This data tries to show the interaction (or complementarity of motions) still more
deep in the planets data.
(III)
(Why The Moon Orbital Circumference Be Considered =1433 mkm?)
Let's remember this question
- Where
- The data considers the moon orbital circumference around the sun= (Mars orbital
circumference=1433 mkm), and Not = 940 mkm (Earth Orbital Circumference),
Why? Let's answer in following:

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I-Data
(1)
1433 mkm = 2.59826 mkm x 550.7
(2)
- Mercury moves during 346.6 d. a distance = 1433 mkm (1%)
- Mars moves during 346.6 d. a distance = 720.7 mkm
(3)
- Mercury moves during 135.5 d. a distance = 550.7 mkm (1%)
- The moon displacements total during 778.6 days x 2 = 135.5 mkm (1%)
- Mars moves during 831 d. a distance = 550.7 mkm x π
- The moon motion distance during 346.6 days = 831 mkm
- Jupiter moves during 2 x 243 d. a distance = 550.7 mkm (1%)
- 550.7 days x 2.574 mkm = 1417 mkm = 4.095 mkm x 346.6 days
- 550.7 days x 1.1318 mkm = 629 mkm (1%)
II-Discussion
- The data gives 3 reasons to consider the moon orbital circumference around the
sun = 1433 mkm = Mars Orbital Circumference and not equal Earth Orbital
Circumference 940 mkm, which are …
1st
Reason (Jupiter Orbital Circumference)
4900 mkm = 360 mkm + 680 mkm + 940 mkm + 1433 mkm +1433 mkm (1%)
o This data should be used as a proof. Why?
o Because
o The unified general motion depends on complementary motions. because of
that, this data should be used as a proof for this claim.
o The data shows, Jupiter and the inner planets orbital circumferences be
created complementary one another, and by that the total (4900 mkm) can
be used as a proof.

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2nd
Reason
Data no. (1)
1433 mkm = 2.59826 mkm x 550.7
- The moon daily displacement =88000 km, and the displacements total during the
moon day period (29.53 days) = 2.59826 mkm
- 550.7 mkm = Mars Jupiter distance and used here as a period of time
- This equation importance is the value (550.7 mkm) because, we have seen that, the
3 inner planets define their orbital circumferences to be equal (or rated) with their
distances to Jupiter.
- The distance 550.7 mkm is Mars Jupiter Distance and it's used to define Mars
Orbital Circumference (1433 mkm) by an effect of the moon motion. by that
Jupiter considers the 2 planets (Mars and the moon) at equal distances.
- The important point here is that, Jupiter orbital circumference is defined as the
inner planets orbital circumferences total, and on the other side, the inner planets
define their orbital circumferences to be rated with their distances to Jupiter, by
that the orbital circumferences of Jupiter and the inner planets are defined based on
one another mutually.

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3rd
Reason
Data no. (2)
- Mercury moves during 346.6 d. a distance = 1433 mkm (1%)
- Mars moves during 346.6 d. a distance = 720.7 mkm
- Mercury moves during its day a distance = 720.7 mkm = Mercury Jupiter Distance
- During the nodal year 346.6 days, Mars moves a distance = 720.7 mkm = Mercury
Jupiter distance , and
- During the nodal year 346.6 mkm, Mercury moves a distance = 1433 mkm = Mars
Orbital Circumference (error 1%)
- Means,
- During The Nodal Year 346.6 days, Mercury moves a distance belonged to Mars
motion and during the same period Mars moves a distance belonged to Mercury
motion.
- After the clear interaction we have seen between Mars and Mercury motions, we
should pay attention for this data, because it tells the moon is found inside this
interaction. And that means, Mercury and Mars motions interaction is done
almost by using the moon orbital motion. and this is one more reason to explain
why the moon orbital circumference around the sun be considered = Mars Orbital
Circumference = 1433 mkm.

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Shortly
- Jupiter connects with the inner planets strongly (based on the previous data).
Jupiter connects with the inner planets in 2 points strongly which are Mercury (the
first inner planet) and Mars (the last inner planet) by this connection Jupiter creates
its connection with the inner planets.
- The point is that, Jupiter connection with the inner planets aims to provide the
environment in which the moon will move. That causes a strong connection
between Jupiter and the moon also.
- But
- Mercury is so far from the moon, and because of that, Jupiter considers the moon
Orbital Circumference Around The Sun =Mars Orbital Circumference =1433 mkm
- The data shows that
Data No. (3)
- Mercury moves during 135.5 days a distance = 550.7 mkm (1%)
- The moon displacements total during 778.6 days x 2 = 135.5 mkm (1%)
- Mars moves during 831 days a distance = 550.7 mkm x π
- The moon motion distance during 346.6 days = 831 mkm
- Jupiter moves during 2 x 243 d. a distance = 550.7 mkm (1%)
- What does this data tell us?
- Mercury and Mars Motions pass equal distances = 550.7 mkm, by using periods of
time (135.5 days and 831 days respectively). And these periods can be defined as
distances passed by the moon motion during 2 different periods (2 x 778.6 days
and 346.6 days). That means, The moon uses Jupiter orbital distance (778.6 mkm)
as a period of time (778.6 days) and also use the nodal year (346.6 days) to pass
these 2 distances (135.5 mkm and 831 mkm) which will be used as periods of time

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(135.5 days and 831 days) by Mercury and Mars respectively to pass the equal
distances =550.7 mkm! Why? What's The Important Idea Behind?
- The interaction we have seen in Mercury, Mars and Jupiter Data Clearly, is found
basically for the moon motion. by that, the moon is an essential player in this
interaction. And that may cause the moon orbital circumference around the sun to
be considered = 1433 mkm = Mars orbital circumference and not Earth orbital
circumference 940 mkm
Data No. (4)
- 550.7 days x 2.574 mkm = 1417 mkm = 4.095 mkm x 346.6 days
- Where
- 2.574 mkm = Earth motion Distance during A Solar Day
- Mercury moves during the nodal year (346.6 days) a distance = 1417 mkm (99%
of 1433 mkm = Mars Orbital Circumference)
- Earth moves an equal distance during the period (550.7 days), where the distance
(550.7 mkm = Mars Jupiter Distance) is used as a period of time.
- By a similar equation, the moon displacements total (2.5986 mkm) uses the period
(550.7 days) to pass 1433 mkm = Mars Orbital Circumference
- That shows the Earth is effected also by this interaction because the moon is the
main player inside and that connects the Earth with this interaction among the 3
planets.
Notice
Jupiter moves during (550.7 days) a distance =629 mkm = Earth Jupiter Distance.
(1.1318 mkm daily = Jupiter motion distance per a solar day)

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Feature (Train Carriages Motions)
- This proof depends on 2 planet motion cycles are discovered later. Which are
(planet 8 days cycles) and (planet 6 days cycles)
- Let's Summarize The Proof Idea In Following:
- The Cycles Show That Different Planets Motions Be Used In The Same One
Cycle To Create One Final Motion.
- Means,
- Many planets move relative one another to create one motion by all planets
motions distances.
- For Example
- Jupiter moves a distance (A) and Uranus moves a distance (B).
- The different between (A) and (B) = Jupiter Diameter
- Now
- This machine uses this behavior frequently, and (the different distance = Jupiter
Diameter) be created frequently while the cycle uses its different periods (means
for the periods 8 days, 16 days, 24 days….etc).
- Based on that,
- We can't consider these planets motions are independent from one another because
the different distance be defined by the 2 planets motions. we have to consider
these planets motions as team motion, or as Train Carriages motion. They move
relative to one another which proves The Unified General Motion Concept.
- (Planet 8 and 6 Days Cycle) disproves Planet Independent Motion Concept.

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Feature Proves
3-5-1 (Planet 8 Days Cycle)
(I)
- Jupiter (13.1 km/s) moves during its day period (9.9 h) a distance = 466884 km
- But
- 466884 km = 449197 km (Jupiter Circumference) + 17687 km
- Where
- (8 x 17687 km = 141496 km (Jupiter Diameter) (error 1%)
- Based on that, we have concluded that, Jupiter has a cycle of 8 days
- Jupiter (13.1 km/s) moves during 8 Jupiter days (79.2 h) a distance = 3735072 km
- (3735072 km= 8 Jupiter circumferences + 141496 km (Jupiter diameter) (1%)
(II)
- The distance 3735072 km be passed also by Saturn and Neptune with a rate 80%
depends on one another as following
- Saturn (9.7 km/s) moves during 10 Saturn days (107 h) a distance = 3736440 km
- (10 Saturn Circumferences = 3786750 km, the difference =50310 km = Uranus
Diameter error 1.5%)
- Neptune (5.4 km/s) moves during 12 Neptune days (193.2 h) a distance = 3755808
km
- (24 Neptune Circumferences = 3734323 km, the difference =21485 km = Mars
Circumference (error 0.6 %))
(III)
- Uranus (6.8 km/s) moves during Pluto day period (153.3 h) a distance = 3752784
km
- The distance 3752784 km = Jupiter motion distance during 8 days + 17687 km
- And because
- 17687 km x (8) = 141496 km (Jupiter Diameter) (error 1%)

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- That tells another Cycle is found between Uranus and Jupiter based on 8 Pluto
days
- That means, the distance be passed by Uranus during 8 Pluto days equal the
distance be passed by Jupiter during 64 Jupiter days and equal the distance be
passed by Saturn during 80 Saturn days and equal the distance be passed by
Neptune during 100 Neptune days
Let's see that in following
(1)
Jupiter (13.1 km/s) moves during (64 Jupiter days) a distance =29880756 km
(2)
Saturn (9.7 km/s) moves during (80 Saturn days) a distance =29891520 km
(3)
Neptune (5.4 km/s) moves during (100 Neptune days) a distance =31298400 km
(4)
Uranus (6.8 km/s) moves during (8 Pluto days) a distance =30022272 km
Comments
- Uranus motion distance (30022272 km) – Jupiter motion distance (29880756 km)
= 141496 km (Jupiter Diameter)
- The differences between these distances are less than 1 % (generally) and based on
that we can't consider they are different but we have to consider they are equal.
- Although still there are small differences which are found for geometrical reasons
for example the difference between Jupiter and Saturn motions distances =
29880756 km – 29891520 km = 10921 = the moon circumference
- The data shows Planets Motions Dependency, because the different distances are
defined geometrically and that means these aren't 2 different distances of 2 plants
independent motions. On the contrary, the 2 distances are planned geometrically
and the 2 planets are 2 players to perform this different distance.

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The Discussion
- Let's discuss the previous data
(A)
- The outer planets are 5 planets, they consist 2 teams,
- The first team is consisted of Jupiter, Saturn and Neptune, these 3 planets move
based on a cycle (8 days cycle) depends on Jupiter motion with the rate 80%,
- That means
- The distance be passed by Jupiter in 8 Jupiter days be equal the distance be passed
by Saturn in 10 Saturn days and equal the distance be passed by Neptune during 12
Neptune Days
- The (small) difference between these 3 distances have geometrical necessities, as
we have seen in the difference between Jupiter and Saturn motions distances which
= 10921 km = The Earth Moon Circumference
- The moon circumference itself tells that it's a cycle because if it's not a cycle we
would find a part of the moon circumference
(B)
- The second team is Uranus and Pluto….
- Uranus uses Pluto day period (153.3 hours), and by that, Uranus (6.8 km/s) moves
during Pluto day period (153.3 hours) a distance = 3752784 km
- Because
- 3752784 km = Jupiter motion distance during 8 Jupiter days +17687 km
- Because of this data, we have concluded that, these motions depends on (8 days
Cycle), because
- Uranus needs to move during a period (= 8 Pluto days) to cause this value (17687
km) be = (141496 km (Jupiter Diameter) (1%)
- Because of Jupiter diameter we conclude that Uranus has a cycle of (8 Pluto days)
- Based on that

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- Uranus motion distance during 8 Pluto days = Jupiter motion distance during 64
Jupiter days = Saturn motion distance during 80 Saturn days = Neptune motion
distance during 100 Neptune days.
- How (Planet 8 Days Cycle) Can Prove The Unified Motion?
- Because
- Many planets motions be done to produce One Result
- This result be the different distance 141496 km (Jupiter Diameter) (1%)
- If we deal with planets independent motions this different distance can't be created
regularly and the Cycle can't be defined.
- Because (Planet 8 days Cycle) be defined, that means, the different distance
141496 km (Jupiter Diameter) be defined regularly which can be done only if
we deal with a team motion and NOT Planets independent Motion.
- Why does Uranus depend on Pluto Day Period?
- Pluto day period is so long (153.3 h) in comparison with the outer planets days
periods. We suppose that, Uranus Motion effect on Pluto motion causes Pluto day
extension. We know Uranus did this effect because Pluto orbital inclination = 17.2
deg but Uranus day period =17.2 hours, even if we can't catch the mechanism of
this process yet, but the data shows that's Uranus effect on Pluto motion.
A Conclusion
Planet 8 days Cycle proves the planets motions can't be independent motions, on
the contrary, they are a team motion. (A Unified General Motion)

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The Cycle Using Examples
Example No. (1)
I- Data (Old Data)
(1)
Jupiter (13.1 km/s) moves during (64 Jupiter days) a distance =29880756 km
(2)
Saturn (9.7 km/s) moves during (80 Saturn days) a distance =29891520 km
(3)
Neptune (5.4 km/s) moves during (100 Neptune days) a distance =31298400 km
(4)
Uranus (6.8 km/s) moves during (8 Pluto days) a distance =30022272 km
We Use (8 Days Cycle) For This Data in following

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Example No. (2)
We Use (8 Days Cycle) For The Previous Data
I- Data
(5)
Jupiter moves during (512 Jupiter days = 64 d x 8) a distance = 239.0446 mkm
(6)
Saturn moves during (640 Saturn days = 80 d x 8) a distance = 239.13216 mkm
(7)
Neptune moves during (800 Neptune d= 100 x 8) a distance = 250.3872 mkm
(8)
Uranus moves during (64 Pluto days = 8 d x 8 ) a distance =240.17818 mkm
(9)
Mercury (47.4 km/s) moves during (1407.6 h) a distance =240.192 mkm
(10)
Mars (24.1 km/s) moves during (2802 h) a distance =243.10152 mkm
(11)
Neptune (5.4km/s) moves during (12430 hours) a distance = 241.6392 mkm
Comments
- We used the (8 days Cycle) for the distances we have discussed.
- The planets move a distance = 243 mkm (Approximately) (error in range 1%)
- But we know that,
- Mercury moves during its rotation period (1407.6 h) a distance = 240.2 mkm
- And
- Mars moves during Venus day period (2802 h) a distance = 243.1 mkm
- For that reason I have added them to our data to see what message is told by this
data…

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Data Analysis
No. 1
- The distance passed by Saturn during (80 Saturn days) = 29891520 km
- The distance passed by Jupiter during (64 Jupiter days) = 29880756 km
- The difference = 10921 km = the Earth moon circumference
But
- The distance passed by Saturn during (80 Saturn d x 8) = 239132160 km
- The distance passed by Jupiter during (64 Jupiter d x 8) = 239044608 km
- The difference = 87550 km
- Where
- The moon displacement per a solar day = 88000 km
- Simply 88000 = 10921 km x 8
No. 2
- The distance passed by Uranus during (8 Pluto days) = 30022272 km
- The distance passed by Jupiter during (64 Jupiter days) = 29880576 km
- The difference =141696 km (= Jupiter diameter error 1%)
But
- The distance passed by Uranus during (8 Pluto days x 8) = 240178176 km
- The distance passed by Jupiter during (64 Jupiter days x 8) = 239044608 km
- Where
- Jupiter motion distance per a solar day =1131800 km
- Simply 1131800 = 141696 km x 8
- This same feature be used for the Earth moon and Jupiter. Where the cycle
produces the planet diameter and by using (8 planet days cycle), the planet
diameter be changed into this planet motion distance during a solar day.

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No. 3
- Mercury moves during its rotation period (1407.6hours) a distance = 240.192 mkm
- Mercury Jupiter Distance =720.7 mkm
- But
- 720.7 mkm = 3 x 240.192 mkm
- i.e.
- 2 x 720.7 mkm = 6 x 240.192 mkm
- But Mercury Jupiter distance (720.7 mkm) must be used in double value (2 x 720.7
mkm) because it creates 180 degrees through the sun (for a complete revolution)
- That means, the distances (2 x 720.7 mkm and 240. 19 mkm) are defined relative
to each other based on the rate (6) which shows the Cycle (6 periods).
No. 4
- The distance be passed by Uranus during (64 Pluto days) = 240178176 km
- The distance be passed by Mercury during (1407.6 hours) = 240192864km
- Where
- 88000 km (the moon daily displacement) = 6 x 14688 km
- That tells, a cycle of (6 days Period) is used to create the distance (88000 km)
depends on this difference (14688 km) (in next we study Planet 6 days cycle).

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Example Data Discussion
- Planet 8 Days Cycle is used to prove that, the solar planets motions are similar to
the Trains Carriages Motion.
- The data proves that (NO Independent Motion be Used)
- Planet 8 Days Cycle disproves Planet Independent Motion Concept
- That shows the useful result Of The Planets Data Analysis Method.
- The question should be, On What Basics depends (Planet Independent Motion
Concept)?
- What are the provided arguments to conclude that, Planet Motion is Independent
from other planets motions?
- The Concept is created simply without any piece of Planet Data. And by that, the
fact has a gab with the theory.
- Why Does Planet 8 Days Cycle Disprove Planet Independent Motion Concept?
- Because
- The Different Distance 141496 km (Jupiter Diameter) (1%)
- This distance is produced frequently as different distances between many planets
motions distances and this different distance can't be created if the planet motion
be independent.
- The fact is that, the planets move as one team and by their motions distances they
create this different distance and the cycle itself.
- Means Planet 8 days cycle can be created (only if) the planets move motions
dependent on one another and NOT Independent from one another.
- Planet 6 days Cycle support this same meaning… we study it in following.

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3-5-2 (Planet 6 Days Cycle)
(I)
- Uranus (6.8 km/s) moves during its day period (17.2 h) a distance = 421056 km
- Venus (35 km/s) moves during 12104 seconds a distance =423640 km
- Pluto (4.7 km/s) moves during 90560 seconds a distance =425632 km
- Where
- 12104 km = Venus Diameter
- 90560 days = Pluto orbital Period
- The previous data gives the base on which the (6 time units Cycle) is created – and
based on that, the provided data uses (6 Uranus days =103h) and (6 x 12104 s) and
(6 x 90560 s) to pass the mentioned distances.
- The previous distances are different with (1%) only. So we can't consider these
distances are different but we consider they are equal.
(II)
- Venus (35 km/s) moves during 12104 seconds (x 6) a distance = 2541840 km
- Uranus moves during 6 Uranus days period (103.2 h) a distance =2526336 km
- Pluto (4.7 km/s) moves during 90560 s x 6 a distance = 2553792 km
(III) (Please remember)
- Earth (29.8 km/s) moves during its day period (24 h)a distance = 2574720 km
- The Earth moon displacements total during (29.53 days) =2598693 km
- Pluto (4.7 km/s) moves during its day (153.3 h) a distance = 2593836 km
Where
- 2593836 km – 2553792 km = 40080 km (Earth Circumference)
- Again we see geometrical mechanism behind the data
- The harmony of data between The Earth and its moon motions Data on one side
and Pluto motion data on the other side shows that the previous calculation is
produced based on a geometrical reason. (let's remember this data in following)

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Earth and Pluto Data
(I)
- (Earth velocity / Pluto velocity) = (Pluto Day period/ Earth day period) = 6.37 (0.8%)
- Pluto orbital distance 5906 mkm = Earth orbital circumference 940 mkm x 2π
- Pluto orbital period 90560 days = Earth Cycle (1461 days) x 2π3
Also
- (Pluto motion distance daily406000 km/ the moon displacement daily88000 km)=4.61
- (The Moon Day Period 708.7 h / Pluto Day Period 153.3 h) = 4.61
- Tan (12.2) x 708.7 h (The Moon Day Period) = 153.3 hours (Pluto Day Period)
- Tan (13.17) x 655.7 h (The Moon rotation Period) = 153.3 hours (Pluto Day Period)
- (Where 13.17 deg = the moon daily motion degrees, and 12.2 deg =13.17 deg –
0.9856 deg Earth motion daily degrees)
And
- We know that, Earth moves during its day period a distance = Pluto motion
distance during its day period = the moon displacements total during its day period
(error 1%).
- The data shows that, clear dependency be seen for Pluto and Earth motions data.
- Pluto motions distances different (= Earth circumference)
- The data proves that, they are created based on Geometrical Reason
- And
- Planet 6 Days Cycle effects geometrically in the planet motion.
Notice
- Planet 6 Days Cycle provide an argument is similar to Planet 8 Days Cycle which
disproves (Planet Independent Motion Concept).

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The Cycle Using Examples
Example No. (1)
We use (6 Days Cycle) with the distance (243 mkm) which is produced by (8 days
Cycle) in the previous discussion.
I- Data
(A)
Jupiter moves during (512 Jupiter days x 6) a distance =1434.267648 mkm
(B)
Saturn moves during (640 Saturn days x 6) a distance = 1434.79296 mkm
(C)
Neptune moves during (12430 hours x 6) a distance = 1449.8352 mkm
(D)
Uranus moves during (64 Pluto days x 6) a distance =1441.069056 mkm
(E)
Mercury moves during (1407.6 h x 6) a distance = 1441.157184 mkm
(F)
Mars moves during (2802 h x 6) a distance = 1458.60912 mkm
(G)
Neptune moves during (778.6 x 16.1 h x 6) a distance = 1462.136055 mkm
II- Data Analysis
- 1433.5 mkm = Saturn Orbital Circumference
- Mercury moves during its rotation period a distance = 243 mkm (error 1%)
- But
- Mercury moves during its day period a distance = 720.7 mkm
- The distance 720.7 mkm between Mercury and Jupiter is the orbital radius and the
orbital diameter needs (2 x 720.7 mkm) which need 2 x 4222.6 hours (= 6 x 1407.6
hours Mercury rotation period)
- And during (6 Mercury rotation periods) Mercury moves a distance = 1433 mkm

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- III- Discussion
- Planet (8 days Cycle) And (6 days cycle) Discussion try to explain one basic idea,
let's summarize it in following…
(I)
o Planet Motion Can't Be Independent Motion
o Planet Motion Be dependent Motion On Other Planets Motions,
o Saturn Orbital Distance =1433.5 mkm, We consider this distance as data
be belonged to Saturn motion only. But the fact shows that,
o Many planets motions pass equal distance =1433.5 mkm
o That explains why many distances are =1433.5 mkm, for example
o Saturn Orbital Distance =1433.5 mkm = Mars Orbital Circumference =
Saturn Uranus Distance = Pluto Neptune Distance = Pluto Eccentricity
Distance= 0.5 Uranus Orbital Distance = Neptune Orbital Distance /π
o These distances are equal because many planets consider this distance by
their motions, and that because their motions be dependent on one another.
o The data shows that
o No Planet Independent Motion Can Be Found
o Planet Motion Is Dependent On Other Planets Motions. (which is the
requirement to produce The Planets Unified General Motion)
o In appendix no. (1) of this paper, I insert a list of all equal distances in the
solar system (50% of all distances be equal one another). the fact disproves
clearly and strongly Planet Independent Motion Concept.

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Feature (Different Rates of Time Using)
- The Solar Planets Motions Use Different Rates Of Time
For example
- 1 hour of Mercury Motion =9.18 hours of Pluto Motion
- And
- 1 hour of Earth Motion = 29.53 hours of The Moon Motion
- We don't provide any theoretical explanation to explain why or how the solar
planets motions use different rates of time.
- Because
- I want to show that, The Solar Planets Motions Data Proves The Different
Rates Of Time Using
- I hope to prove this fact by very powerful and strong data and arguments. After we
should to know why or how the solar planets motions use different rate of time.
-
- There Are 2 Useful Results For This Approach
- (1st
Result).
- When the planets motions data prove the different rates of time using. In this case
my ideas will not be a point of discussion. Because I provide the data and if my
ideas be refused the data will be stayed in waiting for someone to explain how this
data be created.
- (2nd
Result).
- The data saves us from the imagination. And by that we may move toward the
facts with more safe way.
- But
- The different rates of time is a meaning we have learnt from the Special Theory of
relativity and Lorentz Transformations.
- Each time we talk about it, the minds thinks in high velocity motion

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- The question should be
- If the nature creates (by high velocity motion) different rates of time. Can the
nature use other method to create different rates of time with low velocities
motions?
- I suppose the nature provides examples of methods and not restricted one.
- Any way
- I don't explain how the planet motion use different rate of time. I try to show that,
The Planet Motion Data Proves This Fact Regardless Any Explanation.
Notice
- The Planets Unified General Motion Creates One Unified Rate Of Time.

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Feature Proves
3-7-1 Earth And Pluto Rate Of Time
I- Data
Group no. (1) (Earth and Pluto Rate Of Time)
(A)
- Earth (29.8 km/s) moves during a solar day (24 h) a distance = 2574720 km
- Pluto (4.7 km/s) moves during its day (153.3) a distance = 2593836 km
- The moon displacements total during (29.53 days) = 2598693 km
- Pluto and the moon motion distances be equal but they different from Earth motion
distance with (1%).
(B)
- (Earth velocity / Pluto velocity) = (Pluto Day period/ earth day period) = 6.37 (0.8%)
- Pluto orbital distance 5906 mkm = Earth orbital circumference 940 mkm x 2π
- Pluto orbital period 90560 days = Earth Cycle (1461 days) x 2π3
(C)
- 1 hour of Earth motion = 29.53 hours of the moon motion.
Group no. (2) (Pluto And The moon Rate Of Time)
(1)
(406000 km /88000 km) = (708.7 h/ 153.3 h) = 4.61
(2)
Tan (12.2) x 708.7 hours = 153.3 hours
(3)
Tan (13.17) x 655.7 hours = 153.3 hours
(4)
2 x 153.3 h = 4.61 x 66.8 But
(708.7 h /10.7 h) = (655.7 h /9.9 h) =66.23 (error 1%).
(5)
413600 km cos (10.96 deg) = 406000 km
(6)
(10.96 deg /1.7 deg) = (153.3 h /24 h) (error 1%)

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Data Analysis
(I)
- The data analysis shows that,
- The rate of time be defined based on the planets velocities rate
- For example
- Mercury velocity (47.4 km/s) = Venus velocity (35 km/s) x 1.35
- And
- Mercury velocity (47.4 km/s) = Earth velocity (29.8 km/s) x 1.6
- by that
- 1 hour of Mercury motion = 1.35 hours of Venus Motion
- And
- 1 hour of Mercury motion = 1.6 hours of Earth Motion
(II)
- If there's a difficulty to use the planets velocities, the next rule can be used instead.
- Equal Distance Creates Different Rates Of Time
- For example
- Earth moves during its day period (24 h) a distance = Pluto motion distance during
its day period (153.3 h) (error 1%)
- Because the distances are equal, the 2 periods create the rates of time, means
- 24 hours of Earth motion = 153.3 hours of Pluto motion.
(1 h of Earth motion = 6.37 hours of Pluto motion)
- Notice (1) (the error between distances should not be more than 1%)
- Notice (2) (when the velocities be difficult to be used?) As in the moon case. The
moon moves per a solar day a distance =2.574 mkm = Earth motion distance per a
solar day, otherwise they will be separated from each other. But the moon rate of
time is defined based the moon daily displacement (88000 km).

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II- Discussion
- The previous data is so interesting data.
- The proportionality of Earth and Pluto motions data always shows puzzle need
explanation.
- The Planets Unified General Motion creates the geometrical reason which can
explain the data. And now we know that, the same one law controls the 2 planets
motions and causes their data to be created in proportionality.
- I hour of Earth motion = 6.37 hours of Pluto motion
- This rate is concluded simply from Earth and Pluto velocities
Because
- Earth velocity (29.8 km/s) = Pluto velocity (4.7 km/s) x 6.37
- Also
- Pluto Day Period (153.3 h) = Earth Day Period (24 h) x 6.37
- The rate (6.37) which creates the rate of time between Pluto and Earth Motions,
effects greatly on the 2 planets motions data. As we have seen.
- Let's summarize the data idea in following:
o There's a proportionality between Pluto Data on one side and the other side
and its moon data on the other side. No Pure Coincidence can be claimed,
because the connection among the three planets be defined based on their
positions to one another. the question be (How This Data Be Created?)
o Even after we suppose (1 h o earth motion = 6.37 h of Pluto motion) this
idea can't explain simply how the data be created. the point is that, this rate
be used in the planets unified general motion, and through this general
motion the effect can be created. but the geometrical mechanism needs more
analysis to be caught.
o Let's discuss the data in following:

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Equation no. (C)
1 hour of Earth motion = 29.53 hours of the moon motion.
- Because
- The moon displacements total during the moon day period (29.53 days) = Earth
motion distance during a solar day Period. (error 1%)
- Because of that
- 1 Day Of Earth Motion =29.53 Days Of The Moon Motion.
- We can see that, the machine works with consistency, for example
o 1 hour of Earth motion =6.37 hours of Pluto motion
o 1 hour of Pluto motion = 4.61 hours of the moon motion
o And
o 1 hour of Earth motion = 6.37 x 4.61 = 29.53 hours of the moon motion
o The rates of time are created based on each planet motion data and be in full
harmony as we see. That tells we deal with a geometrical mechanism works
consistency…
- Let's see the rate of time of Pluto and the moon motions

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Group no. (2) (Pluto And The moon Rate Of Time)
Discussion
Equation no. (1)
(406000 km /88000 km) = (708.7 h/ 153.3 h) = 4.61
- Where
- 406000 km = Pluto motion distance per a solar day
- 88000 km = The moon displacement per a solar day
- 708.7 hours = The Moon Day Period
- 153.3 hours = Pluto Day Period
- Based on the rule (Equal distances creates different rates of time).
- 1 hour of Pluto motion = 4.61 hours of the moon motion.
- This rate of time be concluded because Pluto moves during its day period (153.3 h)
a distance = the moon displacements total during its day period (29.53 days). By
that 708.7 hours of the moon motion = 153.3 hours of Pluto motion. And So, the
rate of time be concluded (1 h of Pluto motion =4.61 h of the moon motion)
- Again the rates of time causes (2 Planets All Data) to be in proportionality with
one another. in following equations we see that Pluto and the moon motions data
be in full proportionality which is very interesting data.
Equation no. (2)
Tan (12.2) x 708.7 hours = 153.3 hours
- Where
- The angle 12.2 degrees = 13.177 deg – 0.98562 deg
- 13.177 degrees = The Moon Motion Degrees Per A Solar Day
- 0.98562 degrees = The Earth Motion Degrees Per A Solar Day
- Equation no. (2) shows that the moon and Pluto days periods are created based on
each other geometrically. The fact can't be denied. Pluto day period (153.3 h) is
created as a function in the moon day period (708.7 h).

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Equation no. (3)
Tan (13.17) x 655.7 hours = 153.3 hours
- Where
- 13.177 degrees = The Moon Motion Degrees Per A Solar Day
- 655.7 hours = The Moon Rotation Period.
- 153.3 hours = Pluto Day Period and (153.3- ) = Pluto Rotation Period
- Equation no. (3) shows, Pluto rotation period is created depending on the moon
rotation period based on the angle (13.177 deg).
- The data of the 3 equations are strong and prove the idea clearly, because it's A
Directed Data. Means, this data be created based on geometrical mechanism be
found between Pluto and the moon motions. For that reason, the equations use (all)
data of the 2 planets. That shows the data is directed and can't be created by any
random process. It's data be created based on geometrical reasons and rules.
- The proportionality in data between Earth and its moon on one side and Pluto on
the other side shows that a geometrical mechanism must be found behind them.
Equation no. (4)
2 x 153.3 h = 4.61 x 66.8 But
(708.7 h /10.7 h) = (655.7 h /9.9 h) =66.23 (error 1%).
- 708.7 hours = The moon Day period
- 655.7 hours = The Moon Rotation Period
- 153.3 hours = Pluto Day Period
- 10.7 hours = Saturn Day Period
- 9.9 hours = Jupiter Day Period
- The rate (4.61) we have defined, where (1 hour of Pluto motion =4.6 hours of the
moon motion).
- Equation no.(4) tells that this rate (4.61) is known by Jupiter and Saturn motions.
- That tells, the rate (4.61) is transported among the solar planets and that explains
how this rate be created between the moon motion and Pluto motion.

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Equation no. (5)
413600 km cos (10.96 deg) = 406000 km
- Where
- 406000 km = Pluto Motion Distance During A Solar Day
- Equation no. (5) shows that, the motions interaction between the moon and Pluto is
a deep interaction. And effects on the planet motion basic data. Because
- The moon displacements total during 29.53 days =2598693 km = 2π x 413600 km
- The distance (413600 km) should be the moon apogee orbital radius if the moon
apogee orbital circumference = the moon displacements total during 29.53 days.
- This is the fact which should be performed
- But
- The moon apogee orbital circumference be (2550973 km) less than the moon
displacements total during (29.53 days) with 2%. This fact arises the question
Why? the moon apogee circumference should be 2598693 km (surely). But for
some geometrical miracle this distance became =2550973 km!
- The radius 413600 km be changed into 406000 km and this change be done based
on the equation no. (5). The angle (10.96) caused this change. We have discussed
this angle before deeply because it's the main angle in the moon orbit geometrical
structure (we will review a short notice about it later). The angle (10.96 deg)
causes the radius 413600 km to be 406000 km – why?
Equation no. (6)
(10.96 deg /1.7 deg) = (153.3 h /24 h) (error 1%)
- The angle 10.96 deg be created based on the rate between Pluto Day Period
(153.3h) and Earth Day Period (24 h). this rate be used between the angle (10.96)
which causes to decrease the radius from 413600 km to 406000 km, and the angle
1.7 deg which is the moon daily motion angle in the moon orbital equation (θ1= θ0
+ 1.7 deg). (The moon orbital equation be discussed in the moon orbital motion
description point no.8** of this paper)

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Notice (1)
- The moon displacements total 2598693 km should be the moon apogee orbital
circumference, by that, the moon apogee orbital radius should be =413600 km
- But
- It's not true, the moon apogee orbital radius =406000 km
- Why? because of the angle (10.96 degrees)
- Let's remember this angle in following:
o The moon orbital perigee radius =363000 km
o The moon orbital apogee radius = 406000 km
o If we draw these 2 radiuses in 2 circles as in the figure
o The tangent DB = 181843 km, also
o The perigee orbital circumference = 2.28 mkm
o (181843 km /2.28 mkm) = 0.08
o 137 degrees x 0.08 = (10.96 degrees)
o As we remember that 137 degrees = 95.1 deg x 1.44 deg where
o 95.1 deg =90 deg + 5.1 deg (the moon orbital inclination)
o 1.44 deg = the moon orbit regression degrees per month.
o We have supposed that the angle 137 degrees is created based on the moon
orbital inclination (degrees) and the moon orbit regression angle monthly.
And this angle (137 deg) is the basic angle in the moon orbital geometrical
structure (hypothesis).
o The calculations of the tangent DB = 181843 km aimed to explain one basic
idea which is, the moon orbit is built geometrically to create the rate (0.08)
by which the moon orbital inclination and regression will create the angle
(10.96 deg).
o Let's explain that more clearly

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o The moon orbit inclination and regression controls the moon orbital motion.
this is a hypothesis. Now, the moon orbital motion creates the moon orbit
based on a geometrical design, the moon orbital motion uses the moon orbit
geometrical design to create the angle (10.96 deg) from the basic one (137
deg). by that the original angle is (137 deg) which is created by the moon
inclination and regression unification, and the born angle is (10.96 deg)
which is the motor of the machine.
o What we need to refer to that, the moon orbit geometrical design is used in
this process. That's why the distance 413600 be decreased and became
406000 km. By that, the main player is the angle (10.96 deg).
- This explanation answers the question,
- Why Pluto Motion Distance During A Solar Day = The Moon Apogee Orbital
Radius=406000 km?

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Notice (2)
- The previous data still have another reading let's summarize it in following:
o Pluto day period is a very long day period in comparison with the outer
planets days periods, Why?
o We notice also that, Pluto Moves During Its Day Period A Distance =
Earth Motion Distance During Earth Day Period. That means, Pluto Day
Period be extending to perform this requirement.
o i.e.
o Pluto Day Period be extending to be 153.3 h to enable Pluto to move a
distance = Earth motion distance during Earth day period.
o Because of that,
o Pluto day period (and rotation period) be created as functions in the Earth
moon day and rotation periods as we have seen in the data discussion.
o i.e.
o The interaction between Pluto motion on one side with the Earth and its
moon motions on the other side caused the following results:
o (1st
Result) the moon apogee orbital radius be decreased from 413600 km to
be 406000 km
o (2nd
Result) Pluto Day Period be extending to be =153.3 days.
o These 2 Results Are Produced Depends On One Another.
Notice (3)
- Uranus effect is the main force behind these changes in both planets data because
Uranus effects on the moon and Pluto motions.

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3-7-2 Mercury Motion Rate Of Time
I- Data
(1)
112.2 km/s = 4.7km/s x 23.9
(2)
1407.6 hours =153.3 hours x 9.18
(3)
90560 days = 4222.6 hours x 9.18 x 2.33 (error 2%)
(4)
(2 x 153.3 h x 3600 s) /5040 s =23.9 x 9.18
II- Discussion
Equation (1)
112.2 km/s = 4.7 km/s x 23.9
- Where
- 112.2 km/s = The 3 Planets Velocities Total
- 4.7 km/s = Pluto Velocity
- Let's suppose, the 3 planets velocities (Mercury, Venus and Earth) be unified in
one velocity =112.2 km/s, So this velocity works as one gear and Pluto velocity
works as another gear, move relative to one another.
- By this supposed motion of 4 planets, the rate (1 hour = 23.9 hours) be created and
that causes 1 hours of a planet motion be = 23.9 hours of another planet motion.
- This process has a great effect on the solar planets rates of time because if the
planets motions rates of time depend only on the planets velocities that makes the
max rate is (10.08). Means, 1 hour of a planet motion be = 10.08 hours of another
planet motion. And this is a very narrow range of the rates of time. The 3 planets
velocities total creates an extension for this process and enables the system to
create the rate (1h = 23.9 h).

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Equation (2)
1407.6 hours =153.3 hours x 9.18
- Where
- 1407.6 hours = Mercury Rotation Period
- 153.3 days = Pluto Day Period.
- (9.18) = The rate of time between Mercury and Pluto motions.
- We conclude that mercury and Pluto motions rates of time is (9.18) based on this
equation. Means
- 1 hour of Mercury Motion = (9.18) hours of Pluto Motion.
- By this same method we conclude the rate of time between Pluto and the moon
motions. It was the rate between the moon day period and Pluto day period. But
here the rate (9.18) is between Mercury Rotation Period and Pluto Day Period
(where Pluto day period =153.3 h and Pluto rotation period = -153.3 h)
Equation (3)
90560 days = 4222.6 hours x 9.18 x 2.33 (error 2%)
- Where
- 90560 days = Pluto Orbital Period
- 4222.6 hours = Mercury day period
- 2.33 = ??
- Mercury velocity (47.4 km/s) = 10.08 x Pluto velocity (4.7km/s). if the planets
rates of time depend on their velocities. That means 1 hour of Mercury motion =
10.08 hours of Pluto motion. and in this case 24 hours of Pluto motion = 2.37
hours of Mercury Motion.
- That because the equation uses (Pluto orbital period 90560 solar days) in
comparison with 4222.6 hours (Mercury day period). The equation proves that the
rate (9.18) is the used one between the 2 planets.

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Equation (4)
(2 x 153.3 h x 3600 s) /5040 s =23.9 x 9.18
- Where
- 5040 seconds are required for Mercury day period to be 176 solar days
- 153.3 h = Pluto Day Period.
- 23.9 = the rate between the 3 planets velocities total (112.2 km/s) and Pluto
velocity (4.7 km/s).
- This equation also proves that the rat of time between Mercury and Pluto is (9.18)
- The data proves that, 1 hour or Mercury motion = (9.18) of Pluto motion.
Notice
- Different data of Mercury and Pluto Motions shows that the rate of time between
them is (9.18)
- Because this rate is used in different data in the 2 planets motions data, we
conclude that it's a fact and real one.
- I wish the proves show its power clearly. Because we deal with geometrical data.
We find for example a rate (9.18) between Mercury and Pluto motions data and
this rate be used between them frequently. That happens also with Earth (6.37) and
with the moon (4.61).
- The point is that, the rate of time has a massive effect on planets motion but we
still need to discover this effect clearly.
- It's noticeable to take into consideration the method by which the rate of time
effect on Planet Motion.
Notice
- If Mercury and Pluto motions rate of time be defined based on their velocities
only, The rate will be 10.08 (means 1 h of Mercury motion = 10.08 h of Pluto
motion). the rate (9.18) effect only on Pluto and Mercury motions but no other
planets. For example (Mercury 1 hour =46.1 h of The Earth moon motion), in this
case (46.1 = 10.08 x 4.61) , the data doesn’t use (9.18) but (10.08).

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Notice
- How the rate (9.18) be created?
- Let's move step by step in following
o The 3 planets velocities total (112.2 km/s) = Pluto velocity (4.7 km/s) x 23.9
o By that (1 h of these 3 planets motion = 23.9 h of Pluto motion).
o And
o The 3 planets velocities total (112.2 km/s) be used again in face with a third
velocity which is (12.2 km/s) (= Uranus velocity + Neptune velocity)
o 112.2 km/s = (12.2 km/s) x (9.18)
o Means,
o The rate (9.18) between Pluto and Mercury motions be created by an effect
of the total velocity (112.2 km/s) in relative to (Uranus and Neptune
velocities total 12.2 km/s).
o Why?
o Because Uranus effects on Pluto day period and extends it to be 153.3 h
o Uranus effect on Pluto day period be found by Uranus using of Pluto day
period in (Planet 8 Days Cycle)
o On the other side, Uranus uses Pluto rate to the 3 planets. And by that 1 hour
of Mercury motion b = 24 hours of Uranus Motion, the next data will prove
that.

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3-7-3 Saturn Motion Rate Of Time
I- Data
(1)
Saturn moves daily 838080 km = the Earth moon displacement 88000 km x 9.52
(2)
Saturn diameter 120536 km = Earth diameter 12756 km x 9.5
(3)
Saturn orbital distance 1433.5 mkm = Earth orbital distance 149.6 mkm x 9.5
(4)
Earth axial tilt 23.4 deg = Saturn orbital inclination 2.5 deg x 9.4
(5)
Saturn Orbital Period 10747 days = 365.25 days x 29.53 days
(6)
2.4 mkm x 10747 days =25920 mkm = 17.75 mkm x 1461 days
II-Discussion
- The data shows that, the rate of time between Saturn and the Earth moon motions,
be used as a rate between many different data of Earth and Saturn.
- This feature is similar perfectly to Pluto data proportionality with Earth data.
- And also the data between Pluto and Mercury.
- The data tells that, the rate of time has a massive effect on the planets motions
data. This feature which we see frequently in different planets data.
- The data (1, 2 ,3 and 4) shows that the rate of time (9.5) creates a proportionality
between Saturn and Earth motions data.
- Equation. No.(5) shows that, Saturn Orbital Period be defined based on earth
orbital period and the moon orbital period. That means, the rate of time (9.5)
creates a proportionality between earth and Saturn motions data and this
proportionality causes Saturn orbital period to be produced as a result for this
proportionality.
Equation no. (6)
2.4 mkm x 10747 days =25920 mkm = 17.75 mkm x 1461 days

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2.4 mkm = (the moon motion distance daily) ( review the moon orbital motion)
10747 days = Saturn Orbital Period
17.75 mkm = the total distances be passed by the solar planets per solar day
(including the Earth moon motion distance)
1461 days = Earth Cycle (365 +365 +365 +366)
Notice
6.8 km/s x 59800 seconds =406000 km = 4.7 km/s x 86400 seconds
5.4 km/s x 59800 seconds = 2 x 160000 km (Uranus Circumference) (error 0.5%).

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Notice
II- Mercury Uranus Motions Rate of Time
- Mercury Uranus Distance = 2815.2 mkm
- Mercury rotation period = 1407.6 hours
- 2 x Mercury rotation periods = 2815.2 hours
- If 1 mkm = 1 hour, So the distance 2815.2 mkm be = 2 Mercury rotation periods
And
- Mercury (47.4 km/s) moves during its rotation period (1407.6 h) a distance = 243
mkm (error 1%)
- 243 solar days = Venus rotation period
- If each 1 mkm be =1 solar days, the distance 240 mkm be = 243 days (error 1%)
Based on that
- Mercury as a player uses (1 mkm = 1 hour) and (1 mkm = 1 day =24 hours)
- That creates the rate (1 hour = 24 hours)
- But between whom? Almost
- Between Mercury and Uranus, means
- 1 hour of Mercury Motion =24 hours of Uranus Motion.
- This rate also doesn't depend on the planets velocities rates (where Mercury
velocity = 7 Uranus velocity)
Notice (1)
1 hour of Pluto Motion = 2.62 hours of Uranus Motion - Because
1 h or Mercury motion = 24 h of Uranus motion =9.18 h of Pluto motion
Notice (2)
153.3 hours = 2.62 hours x 58.66 hours (153.3 hours = Pluto Day Period)
58.66 solar days = Mercury Rotation Period

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4- Planet Motion Analysis
4-1 Preface
4-2 The Equal Distances Geometrical Effect
4-3 Can electric field control the inner planets?
4-4 The Planets Unified General Motion Effect
4-1 Preface
- In this point (Planet Motion Analysis) we should answer the paper main question,
let's remember it in following…
Paper Main Question
Can The Planets Motions By Masses Gravity Forces Create The Planets Unified
General Motion?
- This simple question hides behind the basic one (How does the planet move?) or
(Does The Solar Planet Move By Masses Gravity Forces Really?)
- I have nothing to write about the masses gravity force, I couldn't catch its effect on
planet motion data.
- What I have found is that? The Equal Distances
- In hundreds of data belonged to all planets and by different forms of data, the one
language which is found behind is (The Equal Distances)
- The system creates equal distances frequently and continuously. In appendix no.
(1) of this paper I insert a list for the equal distances in the solar system. Around
50% of all distances are equal one another.
- This list shows the final distances because they are planets orbital distances or
internal distances, but through planets motions other hundreds of distances be
defined to be equal one another.
- The question is (Why The Distances Be Equal One Another?) and
- (Why The equal distances feature be used hundreds of times through the solar
planets motions?)

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4-2 The Equal Distances Geometrical Effect
- No data be provided for the equal distances. Because we have hundreds of them
and all of them can be used as example.
- I want to say that,
- The Solar Planet Doesn't Move By The Masses Gravity Force And Move By
The Equal Distances!
- Because the theory is built without using the planets data as reference for that
reason the shock is our punishment….
- The basic description is incorrect…
- While the masses gravity force imagines the force is concentrated in the sun mass
and creates forces to move the planets by masses gravity. Where the idea creates
the basic force in the massive mass.
- The Truth Is A Different Vision Completely
- The Equal Distances Is A Geometrical Method To Cause The Planet Motion.
- Imagine one engineer creates a geometrical lever, for that he bring a long piece of
wood and one rock to create the lever. Let's suppose we don't understand the
geometrical rule. The engineer built the lever and caused to raise a great weight by
a small one. but (because we don't understand the geometrical rule) we look and
don't understand what's happening…
- The planet motion be done by a geometrical method which is (the equal distance
creation). And by this method the planet moves. Shortly
- No Masses Gravity In The Sun For The Solar Planets

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- How can the equal distances create the planet motion? I don't know
- Because
- I don't understand the geometrical effect of the equal distances.
- We concluded one feature only be produced by the equal distances which is the
different rates of time creation. And we have seen that, this effect create a massive
effect on all planets motions data in different details as we have seen in Earth and
Pluto rate of time, and Mercury and Pluto rate of time
- The massive effect isn't created by the rate of time. It's created by the equal
distances and the rate of time is created as a side product.
- I can suggest an idea to explain how the equal distances create the planet motion.
but this is an idea only and if it's not correct that does no effect on the concept (the
planet motion be done based on the equal distances feature).
- Let's summarize this idea in following
o The equal distance causes to transport the motion among the solar planets.
o That means,
o The geometrical effect of the equal distances is to transport the motion from
a planet to another through the solar system.
o By that we suppose and define a clear geometrical effect be produced by the
equal distances. (it causes the motion transportation).
o Now
o We need one planet moves and the equal distances will transport its motion
to other planets.
o The moving planets are the inner planets. They can use electric field to
create their motions. and the equal distances uses the inner planets motions
to transport the motion to the outer planets and by that, the inner planets be
as the train engine but the outer planets be as the train carriages
o In next point let's try to discover if the inner planets can create electric field.

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4-3 Can Electric Field Control The Inner Planets?
I- Data
(1)
Earth Mass = The Masses total of (Mercury + Venus + The Moon + Mars)
(2)
Earth Circumference = The 5 inner planets diameters total
(Means the diameters total of (Mercury + Venus + The Moon + Earth + Mars))
(3)
2 x Earth Circumferences = 2 Mars Circumferences + Venus Circumference
(4)
Earth Circumference = The moon freedom space of motion
(5)
Jupiter Orbital Circumference = The Inner Planets Orbital Circumferences Total
II- Discussion
- The double production experiment tells us
- From Gamma ray one electron and one positron be created, 2 particles equal in
mass and opposite in charge.
- Equation no. (1) tells, Earth Mass = The 4 Inner Planets Masses Total (error 1%)
- Can we imagine that, a great gamma ray b used to create the inner planets.
- Earth is (the great electron) (that means, Earth atom has a positive nucleus and
negative charges move around)
- The 4 Other Inner Planets Consist Together (The Great Positron) (means, the
4 inner planets " Mercury – Venus – The Moon – Mars", Their atoms have
negative nucleus and positive charges move around)
- If these hypotheses be working, the 5 inner plants can create one electric field to
cause their motions around the sun.
- The error (1%) refers to a part of mass be consumed to create the required energy
for these 5 planets motions through their orbits.

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- By that the error (1%) is found for a physical necessity and not a error in
measurements.
- If we accept these hypotheses, that will explain an important data which is
Equation no. (5)
Jupiter Orbital Circumference= The Inner Planets Orbital Circumferences Total
- This fact we have discussed frequently in the unified general motion proves. But
we had no explanation for it. it's a fact but we need to know why?
- Because
- The motion is done by the inner planets based on their electric field and this
motion be transported to Jupiter by the equal distance geometrical feature.
- By that we discover, The Solar System Motor Is The Inner Planets And The Outer
be moving depends on the inner planets motions.
- This interesting idea can be usual if we have some strong proof for it. because it's
hard to build the whole story because of equality of 2 masses
Let's test our proves data in following…
Equation no. (2)
Earth Circumference = The 5 inner planets diameters total
(Means the diameters total of (Mercury + Venus + The Moon + Earth + Mars))
Equation no. (3)
2 x Earth Circumferences = 2 Mars Circumferences + Venus Circumference
- For what we search? For electric charge
- If we can prove that, some electric charge be found in the inner planets. That can
support this idea greatly
- Why these 2 equations refer to charges in the inner planets data?
- Because of Gauss Law!
- Gauss law tells that, The Charges Be On The Outer Surface, that means, the
outer surface be created geometrically by an effect electric charges. Because more

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wide outer surface will receive more charges. Because of that, the outer surface be
effected geometrically by the electric charges
- I want to say
- If some planet be charged its outer surface formation and dimension be effected by
the electric field.
- Because of that, the previous 2 equations can support this idea hypotheses because
the planet circumference and diameter be considered the outer surface and the
proportionality of the inner planets refer to some effect of the electric field on their
creation.
Equation no. (4)
Earth Circumference = The moon freedom space of motion
- The moon orbital period radius =363000 km
- The moon orbital apogee radius =406000 km
- The difference 43000 km
- But the space without the moon diameter =43000 km- 3475 km = 39500km= Earth
Circumference (error 1.3%)
- I try to show that, there's a geometrical effect be found on the surface distances
which can be used as reference for the electric field effect on the matter
dimensions (I understand that the distance can't be charged unless under specific
conditions but I try to show geometrical effects are found. It's not necessary for
this effect to be a direct one, but it's found through the interactions).
- Notice
- The electric field is the best method to make the solar system as a chess board.
And by that we gain the good result which is (any planet motion effects on all
other planets motions regardless the distance) which is a fact proved frequently by
the planets data.

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4-4 The Planets Unified General Motion Effect
- Now this question became ripe at end, let's ask it in following?
- What's The Effect Of The Planets Unified General Motion?
- The planets unified general motion is used to create the sun,
- i.e.
- The sun rays is created by The Solar Planets Motions Energies Total
- So,
- Let's discuss the sun creation details in the next point.

The Solar Planets Motions Description (Revised)

The Solar Planets Motions Description (Revised)

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