Planets Data Analysis Curriculum

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Planets Data Analysis Curriculum
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –24th
February 2021
Abstract
1- Define And Discover The Directed Data
2- Suggest a hypothesis to explain how this directed data is created (the new
hypothesis should depend on old hypotheses in one feature at least).
3- Provide other data arranged according to this new hypothesis to prove its
credibility
4- Conclude the geometrical rule based on which the mentioned data is created
5- The concluded geometrical rules form the general geometrical design
6- Use all hypotheses to form one general hypothesis.
The Curriculum Explanation
- Planets data analysis method is a new discovered method can be used in the
solar system geometry study and analysis…
- I have suggested this method and used it for years, by which many important
results and correct explanations are produced
- The paper provides 10 examples, explain how to use the planets data analysis
method and shows this new method effect on the solar system motion
understanding improvement.

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Contents
Subject Page No.
Introduction 3
1- The Solar Planets form One Geometrical Structure 4
2- The Moon Motion depends on Pythagorean Rule 13
3- The moon is created by a collision between Mars and Earth 25
4- Uranus Motion effect on the Moon Motion 30
5- Eight Days Cycle Is Found In The Solar System 43
6- The inner planets orbital circumferences are created depend on Jupiter
Motion
51
7- There's a light velocity =1.16 million km/sec 55
8- Light motion features are discovered in Planets Motions. 59
9- The solar system Geometry uses the distances values as periods of time 64
10- There are different rates of time in the solar system motion 68
References 72

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Introduction
The 10 examples are:
1- The Solar Planets form One Geometrical Structure
2- The Moon Motion depends on Pythagorean Rule
3- The moon is created by a collision between Mars and Earth
4- Uranus Motion effect on the Moon Motion
5- Eight Days Cycle Is Found In The Solar System
6- The inner planets orbital circumferences are created depend on Jupiter Motion
7- There's a light velocity =1.16 million km/sec
8- Light motion features are discovered in Planets Motions.
9- The solar system Geometry uses the distances values as periods of time
10- There are different rates of time in the solar system motion
- The previous examples are concluded by planets data analysis – many of these
examples can be seen strange one – Specially – the light velocity 1.16 mkm/s
But the data gives no room for doubt – Jupiter all data is almost created
depending on this velocity of light and if it's not found Jupiter data can't be
created –
- For that, this paper provides an interesting approach by creation a comparison
between the planets data and the current theories which can easily provides a
chance to develop our understanding concerning the solar system motion.
- Each example will be discussed in a separated point – for that – this paper is
consisted of 13 points (please review the contents)

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1- The Solar Planets form One Geometrical Structure
1-1 The inner planets data is created complementary one another (directed data)
1-2 The hypothesis no. 1 (the solar group is one geometrical structure)
1-3 Planets data is created complementary one another (proves discussion)
1-4 The concluded geometrical rule (No. 1)
1-1 The inner planets data is created complementary one another (directed data)
I- Data
(1)
- Earth Circumference 40080 km = The 5 Inner Planets Diameters Total
(2)
- Earth Mass = The 4 Inner Planets Masses Total
II- Discussion
Data No. (1)
- Earth Circumference 40080 km = Mercury diameter 4879 km + Venus Diameter
12104 km + Earth diameter 12756 km + the moon diameter 3475 km + Mars
diameter 6792 km
(Error Zero)
Data No. (2)
- Earth Mass 5.97 (x 1024
km) = Mercury Mass 0.33 (x 1024
km)+ Venus Mass +
4.87 (x 1024
km) + the moon mass 0.073 (x 1024
km) + Mars Mass 0.642 (x 1024
km).
(Error 1%)
- This data is The directed one by which the hypothesis no.1 is suggested
- The data shows that, the inner planets diameters and masses can't be created as
independent values from each other, on the contrary, the data shows that, these
planets diameters and masses must be created complementary one another.
- Let's discuss the hypothesis no. 1 in following

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1-2 The hypothesis no. 1 (the solar group is one geometrical structure)
What does mean (data is created complementary one another)?
- The double production experiment is a good example to explain this meaning,
from Gamma ray (1.2 Mev), an electron and a positron can be produced. Without
observation I can easily expect that, a positron will be produced with the electron
because of the charge reservation law. That means, the positron charge is created
complementary with the electron charge, for that reason the electron charge is –e
but the positron chare is +e and not (+2e) where the 2 particles charges total =
Zero.
- This explanation gives us another vision concerning the solar system – No longer
the solar planets b considered as moving rigid bodies independent from one
another – the data tells some different vision – that – these planets data is created
complementary one another.
- That tells us, there's some geometrical necessity for which the Earth circumference
be = the 5 inner planets diameters total, and Earth mass = the 4 inner planets
masses total. and that means, these 5 planets data is created by some geometrical
force greater than them all.
- That shows one more force greater than the 5 inner planets plays behind and form
the data to be complementary one another –
- Based on this analysis the hypothesis no. 1 is created
The Explanation of the Hypothesis no. 1
- The hypothesis no. 1 (The Solar Group Is One Geometrical Structure)
- The hypothesis no. 1 tells us that
- The solar system is one geometrical structure, why? consider a triangle, its angles
total =180 degrees, by this rule each angle is created complementary to the others
- That's what we have seen in the directed data, where planets data is created
complementary one another
- The hypothesis no. 1 tells that…

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- The solar system is similar to one building and each planet is a part of this same
building because of that each planet data is created complementary with others to
enable the general building to be created. based on this description no planet data
can be created independently from other planets data, on the contrary, All planets
data are controlled by unified general rules to be complementary one another.
- Also the hypothesis no. 1 tells that,
- The solar system is similar to one body members, and by that all members are
created complementary one another and in proportionality with one another. As
the cow liver size be in proportionality to its brain size, similar to that, the planets
data is created in proportionality with each other.
- The solar planets moves together one unified motion. this motion is similar to a
train motion where the train moves with its carriages together one unified motion.
similar to that, the solar planets move one unified motion together, regardless their
velocities differences (where the mechanical clock has different gears which move
with different velocities but all gears move in one motion which is transported
from one gear to another).
- The solar system is consisted of one trajectory of Energy and each planet is a point
on this same trajectory of energy where this energy creates the planets matters and
their orbital distances, defining each planet motion and velocity.

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1-3 Planets data is created complementary one another (Proves discussion)
I- Data
(1) Planets diameters
The solar planets diameters total =2 Jupiter diameters + 1 Saturn diameter
(i.e. Jupiter diameter =8 planets diameters total)
(2) Planets velocities
(a)
(b)
(3) Planets Axial Tilts
(c)
(d)
(17.4 /17.2) = (23.6/23.4) = ((π/2) /28.3).
(4) Planets Orbital Circumferences
Jupiter orbital circumference = the inner planets orbital circumferences total + Mars
Orbital Circumference
(5) Planets orbital inclinations
(e)
1.8 deg (Neptune orbital inclination) = 3.1 deg -1.3 deg
(f)
5.1 deg (the moon orbital inclination) = 7 deg (Mercury orbital inclination) -1.9 deg
345
.
1
km/s
9.7
Velocity
Saturn
km/s
13.1
Velocity
Jupiter
km/s
13.1
Velocity
Jupiter
km/s
17.8
Velocity
Ceres
km/s
17.8
Velocity
Ceres
km/s
24.1
Velocity
Mars
km/s
35
Velocity
Venus
km/s
47.4
Velocity
Mercury
=
=
=
=
6
.
3
km/s
6.8
Velocity
Uranus
km/s
24.1
Velocity
Mars
km/s
9.7
Velocity
Saturn
km/s
35
Velocity
Venus
km/s
13.1
Velocity
Jupiter
km/s
47.4
Velocity
Mercury
=
=
=
0725
.
1
T.
Axail
Earth
23.4
T.
Axail
Mars
25.2
T.
Axail
Mars
25.2
T.
Axail
Satrun
26.7
Tilt
Axail
Satrun
26.7
Tilt
Axail
Neptune
28.3
=
=
=

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II- Discussion
- What proves can this previous data provide?
- The data tries to show The Mentioned Creation Of The Total Values
- i.e. The total values are planned to be created and not found by the small values
summation…
- As in the inner planets masses total, the solar system geometrical design
mentioned to create the 4 planets masses total = Earth mass with difference 1%
- I try to show that, the solar system is created by some geometrical design and not
by separated planets (rigid bodies) motions – by that –our discussion data be
understandable – let's discuss it in following
Data No. (1) (Planets diameters)
The solar planets diameters total =2 Jupiter diameters + 1 Saturn diameter
(i.e. Jupiter diameter =8 planets diameters total)
- I claim it's mentioned by the solar system geometrical design to create Jupiter
diameter = 8 planets diameters –which supports the 1st
hypothesis (The Solar
Group Is One Geometrical Structure) – but – can we consider that by some
random chance Jupiter diameter be = 8 planets diameters? But
(A)
2 Jupiter Circumferences - 2 Saturn Circumferences = 1 Jupiter Diameter (error 1.3%)
- This data tells, Saturn diameter also is created based on Jupiter diameter, it must be
another random chance!
(B)
- Jupiter (13.1 km/s) moves during 10921 seconds a distance = 142984 km = Jupiter
diameter (where 10921 km = the moon circumference), this data also tells that
Jupiter diameter is related to the moon circumference
- It’s hard to make all planets diameters as function in Jupiter diameter by random
chances – more logical – to consider that all planets diameters are created as
functions in Jupiter diameter based on the solar system geometrical design.

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Data No. (2) (Planets Velocities)
- The data shows, Planets velocities are created rated to one another – how to create
this result if the planets velocities are created independently from one another? We
have to consider that, some geometrical design mentioned to create one total
velocity and distributed this total velocity into participant for each planet,
otherwise how to explain the planets velocities data!
- I try to show, the solar system simple description which considers the planets as
rigid bodies revolve around the sun by masses gravity forces can't explain the most
part of the planets creation and motion data – basically- Because the solar system
is crated based on a geometrical design and by that each data is defined by
geometrical rules depending on the other planets data – simply the data analysis
shows that our simple description is insufficient.
- The conclusion we have to reach is, (Planets data is created by mentioned
geometrical design) and by this conclusion the simple description will be changed
accordingly.
Notice
- If the geometrical rules on which the planets data is created are known we don't
need to make a deep analysis – but the geometrical rules have 2 problems
1. Many geometrical rules are unexplainable by our physic book, for example, the
solar system geometry uses distances values as periods of time, where planets
velocities are very low in comparison with light velocity and can't perform that
– and we have no explanation how that’s happening – but such using is so
widespread between the solar planets
2. The rules are violated by some changes through history for example (Mercury
Diameter x 1092
= Mercury Orbital Distance) this rule is used by Earth and
Saturn but no other planet uses it because of Mars migration from its original
orbital distance which caused a confusion for the solar planet order and by that
the rule can't be used or discovered.

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Data No. (3) (Planets Axial Tilts)
Equation no. (c)
- Why 4 Planets Axial Tilts Are Rated With Each Other? If the solar planets are
rigid bodies their data is created independently from one another why this equation
is found? The data shows that they are created rated to each other by mentioned
design- this task is produced by some geometrical necessity
- (Notice the equation should use 23.6 deg in place of Earth axial tilt 23.4 deg to be
more accurate but I used the value 23.4 deg to explain the idea, where the value
23.6 deg we will discuss in following)
Equation no. (d)
(17.4 /17.2) = (23.6/23.4) = ((180/2π) /28.3). where
17.4 degrees = The Inner Planets Orbital Inclinations Total
17.2 degrees = Pluto orbital inclination
23.6 degrees = The outer Planets Orbital Inclinations Total
23.4 degrees = Earth Axial Tilt
28.3 degrees = Neptune Axial Tilt
- The data shows, the values are created rated to each other for some geometrical
necessities…
- What does this discussion try to do?
- I try to show that, it's incorrect to consider the solar planets as rigid bodies revolve
around the sun by gravity forces– the data tells that – we deal with one geometrical
design and structure – as when someone sees some columns and roof and consider
they are articles elements – but it's incorrect – this is one house – and these
columns are the souse columns and this roof is the house roof.
0725
.
1
T.
Axail
Earth
23.4
T.
Axail
Mars
25.2
T.
Axail
Mars
25.2
T.
Axail
Satrun
26.7
Tilt
Axail
Satrun
26.7
Tilt
Axail
Neptune
28.3
=
=
=

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Data No. (4) (Planets Orbital Circumferences)
- Mercury orbital circumference =360 mkm
- Venus orbital circumference =680 mkm
- Earth orbital circumference =940 mkm
- Mars orbital circumference =1433.5 mkm
- The 4 planets orbital circumferences total = 3413.5 mkm
- Jupiter orbital circumference =4900 mkm = 3413.5 mkm + 1433.5 mkm
- Shortly,
- The Jupiter orbital circumference= the inner planets orbital circumferences total +
Mars orbital circumference
(Means, Mars orbital circumference is used 2 times in addition to the other 3 inner
planets circumferences total to produce Jupiter planets circumference)
- Again the data shows the dependency between the planets
Notice
- We should consider all data because they shows different features for the same
relationship and by that we simply can conclude that this data is created by
mentioned geometrical design which we see its features in ach provided data –
proving that – the solar system is one geometrical building.

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Data No. (5) Planets orbital inclinations
(e)
1.8 deg (Neptune orbital inclination) = 3.1 deg -1.3 deg
(f)
(g)
97.8 deg (Uranus axial tilt) - 96.7 degrees =1.1 degrees
- The data tries to support the hypothesis (The Solar System Is One Geometrical
Structure)
Discussion
1.8 deg (Neptune orbital inclination) = 3.1 deg (Jupiter Axial Tilt) -1.3 deg ( Jupiter
orbital inclination).
And
Where (1.9 deg Mats orbital inclination)
But the most interesting data
97.8 deg (Uranus axial tilt) - 96.7 degrees =1.1 degrees
Where
6.7 degrees = The Moon Axial Tilt and 96.7 deg = 6.7 deg + 90 deg
- The data shows that the difference is 1.1 degrees where the moon uses this angle in
its motion as we have discussed before (review Pythagorean triangle using by the
moon motion)
- Notice, the proportionality between Uranus axial tilt and the moon axial tilt is
discussed deeply in previous paper which proves that these both axial tilts values
are crated based on geometrical necessities.

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2- The Moon Motion depends on Pythagorean Rule
2-1 The Moon motion basic points depend on Pythagorean rule
2-2 The hypothesis no. 2 (The moon uses Pythagorean triangle in its motion)
2-3 The moon motion equation depends on Pythagorean rule
2-1 The Moon motion basic points depend on Pythagorean rule
- The moon motion basic points are
o Perigee point (r=363000 km), the nearest point the moon can reach to Earth
o Pongee point (r=406000 km), the far point the moon can reach from Earth
o T.S. Eclipse (r=373000 km), the moon creates total solar eclipse at it
o The distance (r=384000 km) which is registered as the moon orbital distance
These 4 points are defined based on each other by Pythagorean rule:
o (363000 km)2
+ (86000 km)2
= (373000 km)2
o (373000 km)2
+ (86000 km)2
= (384000 km)2
o (384000 km)2
+ (86000 km)2
= (393000 km)2
o (393000 km)2
+ (86000 km)2
= (406000 km)2
(Error 1%)
- The previous data refers to that, the moon uses Pythagorean rule in its motion,
- But the question is
- Why and how the moon uses Pythagorean rule in its motion?

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2-2 The hypothesis no. 2 (The moon uses Pythagorean triangle in its motion)
- There are 2 questions :
- (1) Why does the moon use Pythagorean triangle in its motion?
- (2) How does the moon use Pythagorean triangle in its motion? let's answer
- (1) Why does the moon use Pythagorean triangle in its motion?
- The moon daily displacement =88000 km, during 29.53 days the total distance
became = 2598693 km,
- This distance 2598693 km should be the moon orbital circumference, but the
distance 2598693 km = 2π x 413600 km BUT
- The moon apogee radius = 406000 km
- That means, if the moon moves by its displacement 88000 km daily, the moon
apogee radius should be =413600 km, BUT that's not true, where the moon apogee
radius = 406000 km – how can that be done?
- This is a proof for the moon using of Pythagorean triangle in its motion.
- (2) How does the moon use Pythagorean triangle in its motion? let's answer
- The moon moves daily (88000 km) on the right triangle hypotenuse (AC).
- The moon creates an angle (θ) between its displacement motion direction (AC) and
its orbit horizontal level (BC)
- The real displacement through the moon orbit will be (L =88000 km cos (θ))
- By that the real displacement (L) will be shorter than 88000 km and the total
displacements through 29.53 days will be 2550973 km (= the circumference of the
apogee radius 406000 km).

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The Angle θ
- The angle (θ) should get our attention for its specific effect…let's summarize the
idea in following
o The angle (θ) changes the real displacement (L = 88000 cos (θ)), through the
moon orbit..
o We know that, when the real displacement (L) be shorter the moon can
move through near orbits to Earth and by that the moon can be near or at
Perigee radius (0.363 mkm)
o When the real displacement (L) be longer the moon has to move through
orbits far from Earth and by that the moon can be near or at apogee orbit
(r=0.406 mkm)
o That means, the angle (θ) changes the real displacement (L) and also
changes the distance between the moon to perigee or to apogee, shortly, the
angle (θ) defines the moon position (as a ship) between 2 river banks….
- The angle (θ) defines the moon orbital motion basic features and we have to
discuss is deeply with the moon orbital motion equation (θ1= θ0 + 1.7 degrees),
but before we need to analyze the moon orbital motion
Notice
o We know that (363000)2
+ (86000)2
= (373000)2
o In Pythagoras triangle with dimensions (363000 km, 373000km, 86000 km),
what's the angle (θ)? The angle (θ) = 13.33 degrees
o Also (396800)2
+ (86000)2
= (406000)2
the angle (θ) = 12.229 degrees
o I have used (363000 km and 406000 km) because they are the perigee and
apogee radiuses between which the moon moves.
o The difference between angles = 1.1 degrees
i.e.,
The angle (1.1 deg.) controls the moon motion from perigee to apogee.

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2-3 The moon motion equation depends on Pythagorean rule
The Moon Orbital Motion Equation
(θ1= θ0 + 1.7 degrees)
- The moon orbital motion equation is created depending on the concept we have
discussed, which is (the moon uses Pythagorean triangle in its orbital motion)
- The moon uses Pythagorean triangle and by this intelligent technique the moon be
under control of the angle (θ) change
- The angle (θ) defines almost all the moon motion features.…
- The moon uses this technique, aiming to create a real displacement shorter than its
actual displacement (88000 km) based on the equation (L =88000 cos (θ)) and by
that while the moon moves a displacement =88000 km but the real displacement
(L) through its orbit be shorter than 88000 km and by that the moon can revolve
around Earth through more near orbits than its apogee orbit (r=0.406 mkm).
- The moon orbital motion equation depends on this concept and, the equation
uses (the constant) 1.7 degrees as the moon daily motion degrees, and the equation
uses the previous day angle (θ0) to produce the today angle (θ1)
- We have 3 questions in this equation study which are:
o How does this equation work?
o Is this equation trustee and correct?
o Why does the equation use the angle 1.7 degrees for the moon daily motion?
Let's try to answer….

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How to use this equation?
- Perigee Radius =0.363 mkm, so Its Orbital Circumference =2.28 mkm
- Suppose the moon will revolve around Earth through perigee orbit only during
29.53 days, so
- (2.28 mkm /29.53 days) = 77237 km
- This is (the real displacement = L = 88000 km Cos θ = 77237 km),
- What's the angle θ value? the angle θ = 28.63 degrees
- Suppose the moon stand on this point yesterday with the angle (θ) =28.63 degrees,
where the moon will move today?
- From Perigee (the most near point to Earth) the moon will move in Ascending
motion because it moves from perigee (0.363 mkm) to apogee (0.406 mkm)
- In Ascending motion we use (-1.7 degrees) because the angle (θ) is decreased
where the real displacement (L) is increased, So let's do that in following
o (θ1= θ0 - 1.7 degrees)
o (θ1= 28.63 degrees - 1.7 degrees) = 26.93 degrees
o L = 88000 Cos (26.93 degrees) = 78454 km
o During 29.53 days so (78454 km x 29.53 days = 2.316 mkm)
o 2.316 mkm = 2π x 368722 km
That means
o The moon was (before motion) on Perigee radius (r=0.363 mkm) and started
its motion displacement 88000 km. For day motion the equation uses 1.7
degrees, that means, the moon on perigee uses Pythagorean triangle with
angle (28.63 degrees) and during one solar day the moon uses - 1.7 degrees
and by that the angle will be (26.93 degrees)…... The angle 1.7 degrees
expresses The Moon Daily Motion
o By using Pythagorean triangle its angle (θ) = 26.93 deg, the displacement
(88000 km) will create a real displacement through the moon orbit = 78454
km and the moon will finish its motion today at a distance 368722 km

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means the moon is far from perigee radius with (368722 km-363000 km
=5722 km )
o So, the moon after 1 day motion will be at the point 368722 km and will
have the Pythagorean triangle its angle 26.93 degrees.
The Descending Motion
o When the moon moves from apogee (0.406 mkm) to perigee (0.363 mkm),
so the angle (1.7 degrees) will be positive (+1.7 degrees) because the angle
(θ) is increased and the real displacement (L = 88000 Cos (θ)) be shorter.
So
o If the moon is in apogee radius (r=0.406 mkm), what's the angle (θ)?
o The apogee orbital circumference = 0.406 mkm x2π =2.55 mkm = 29.53
days x 86400 km, the angle (θ) = 10.96 degrees (=11 deg approx.)
o The moon moves from apogee to perigee (descending motion)
o (θ1= θ0 + 1.7 degrees) means (θ1= 11 degrees + 1.7 degrees) = 12.7 deg.
o L = 88000 Cos (12.7 degrees) = 85847 km
o During 29.53 days so (85847 km x 29.53 days = 2.535 mkm)
o 2.535 mkm = 2π x 403467 km
So
o After one day the moon will be on 403467 km far from apogee (406000 km)
with 2540 km
Now let's see this equation test and efficiency in following

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The Equation Test and Accuracy
- I have tested the Equation with real data for 2 months June 2020 and October 2020
- The results are very good and I provide the results here for better vision
concerning the equation efficiency
1st
Test June 2020
Day Registered Data The Results (1.7) Difference
6-6-2020 369418 km
7-6-2020 373729 km 374772.5 - 1044
8-6-2020 378917 km 378821.5 96
9-6-2020 384534 km 383667.7 867
10-6-2020 390096 km 388890 1206
11-6-2020 395156 km 394000 1156
12-6-2020 399345 km 398604.2 741
13-6-2020 402395 km 402361.3 34
14-6-2020 404153 km 405052.8 -900
15-6-2020 404574 km ---- ---
16-6-2020 403718 km 401848.5 1870
17-6-2020 401733 km 400876.1 857
18-6-2020 398840 km 398640.7 200
19-6-2020 395303 km 395417.4 115
20-6-2020 391409 km 391521.2 -113
21-6-2020 387432 km 387273.4 159
22-6-2020 383607 km 382968.4 639
23-6-2020 380110 km 378852 1258
24-6-2020 377044 km 375107 1937
25-6-2020 374451 km 371836.5 2615
26-6-2020 372338 km 369077 3262
27-6-2020 370703 km 366855.6 3847
[

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The 1st
Test Results Analysis:
- The Total Results Are 20 Values
(1st
Category)
o 15 values, defines the moon position in range 1300 km (Error 3%)
(2nd
Category)
o 2 values, defines the moon position in range 1300-2000 km (Error 4.6 %)
(3rd
Category)
o 3 values, defines the moon position in range 2000-3500 km (Error 8 %)
- The Results Explanation
- The distance from perigee to apogee =43000 km…
o 1st
Category of results defines the moon position in error range (1300 km) =
error (3%), that means, (15 values of 20) defines the moon position with
error (3%) only (Small Error Range)
o 2nd
Category of results defines the moon position in error range from (1300
km to 2000 km) = error (4.5%), that means (2 values of 20) defines the
moon position with error (4.5%) (Average Error Range)
o 3rd
km to 3500 km) = error (8%), that means (3 values of 20) defines the moon
position with error (8%) (Great Error Range)
- The Equation Accuracy
o The previous explanation shows that, the equation has a good range of
accuracy and its error is in the acceptable error range
The Conclusion
The Equation Is correct and trustee
And
It's a useful tool to define the moon position daily

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2nd
Test October 2020
Day Registered Data Results (1.7) Difference
5-10-2020 405,690 km --- ---
6-10-2020 404,171 km 403125.3 km 1046 km
7-10-2020 401,649 km 401390 km 259 km
8-10-2020 398,073 km 398545.6 Km - 473 km
9-10-2020 393,464 km 394568.8 km -1105 km
10-10-2020 387,944 km 389510 km -1567 km
11-10-2020 381,763 km 383520 km -1758 km
12-10-2020 375,302 km 376875.3km -1574 km
13-10-2020 369,063 km 369981km -919 km
14-10-2020 363,617 km 363363.4km 254 km
15-10-2020 359,530 km 357612 km 1918 km
16-10-2020 357,269 km 353307 km 3962 km
17-10-2020 357,105 km ---- --
18-10-2020 359,048 km --- --
19-10-2020 362,851 km 364979.7 km - 2129 km
20-10-2020 368,058 km 368579.3 km -522 km
21-10-2020 374,101 km 373492.4 km 609 km
22-10-2020 380,412 km 379168.3 Km 1244 Km
23-10-2020 386,497 km 385059.3Km 1438 km
24-10-2020 391,989 km 390694.3 km 1295 km
25-10-2020 396,659 km 395729.5 km 930 km
26-10-2020 400,395 km 399958.7 km 437 km
27-10-2020 403,181 km 403299 km 112 km
28-10-2020 405,059 km 405738.5 km -680 km
29-10-2020 406,104 km 407359.4 km -1256 km
[

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The Test Results Analysis:
- The Total Results Are 22 Values
(1st
Category)
o 15 values, defines the moon position in range 1300 km (Error 3%)
(2nd
Category)
o 5 values, defines the moon position in range 1300-2000 km (Error 4.6 %)
(3rd
Category)
o 2 values, defines the moon position in range 2000-3500 km (Error 8 %)
- The Results Explanation
- The distance from perigee to apogee =43000 km…
o 1st
Category of results defines the moon position in error range (1300 km) =
error (3%), that means, (15 values of 22) defines the moon position with
error (3%) only (Small Error Range)
o 2nd
km to 2000 km) = error (4.5%), that means (5 values of 22) defines the
moon position with error (4.5%) (Average Error Range)
o 3rd
km to 3500 km) = error (8%), that means (2 values of 22) defines the moon
position with error (8%) (Great Error Range)
- The Equation Accuracy
o The previous explanation shows that, the equation has a good range of
accuracy and its error is in the acceptable error range
The Conclusion
The Equation Is correct and trustee
And
It's a useful tool to define the moon position daily

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The Value 1.7 degrees
- The 3rd
question was, why the equation uses 1.7 degrees?
Because
1.7 degrees = 0.98562 degrees + 0.712 degrees
Where
- 0.98562 degrees = Earth motion daily degrees, and it equals the moon daily
motion degrees because the moon has to move an equal distance to Earth motion
daily distance to save their motions accompanying
- This question and the angle 0.712 degrees is discussed deeply in the previous
paper
The Moon Orbital Motion Geometry (II)
https://www.academia.edu/s/5069315c09
or
https://www.academia.edu/45181646/The_Moon_Orbital_Motion_Geometry_II_
or
https://www.slideshare.net/Gergesfrancis/the-moon-orbital-motion-geometry-ii

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The Moon Motion Difficulties
- There are 2 basic difficulties are observed in the moon orbital motions, let's refer
to them in following:
o (1st
Difficulty) The moon moves per day different distances from perigee to
apogee…..
o We know the moon moves from perigee to apogee (go and back) during
Anomalistic month (27.55 solar days)
o (43000 km x 2) / 27.55 days = 3122 km
o The moon doesn't use this rate (3122 km) in its motion, instead the moon
can move (6000 km) on one day only and on another day may move only
2500 km (or even less)!
o The moon orbital equation tries to solve this difficulty by using the rate 1.7
degrees in the equation (θ1 = θ0 + 1.7 degrees), the value 1.7 degrees is a
great number and enables the moon to move around (5000 km) per solar day
and by that if the moon moves per solar day 4000 km the different distance
will be 1000 km and if the moon moves 6000 km the different will be
– 1000 km, it’s the same difference, and by that, the error be minimized as
possible enabling the equation to be more efficient..
o (2nd
Difficulty) The moon stays in perigee and apogee points long time….
o That means, while the moon be on perigee or apogee, the moon doesn't use
the equation and doesn't change its distance to perigee or apogee for long
days…we may notice that in the equation tests, when the moon reach to
perigee or apogee the equation stops its work and stays 2 or 3 days to return
to its work… because the moon consumes long time to leave the points
(perigee and apogee)…

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3- The moon is created by a collision between Mars and Earth
3-1 Mars Position isn't suitable among the solar planets order (Directed Data)
3-2 hypothesis no. 3 (Mars had collided with Earth & Venus to create the moon)
3-3 The Moon and Mars Motions Interactions 3-4 Planets Data Analysis Logic
3-1 Mars Position isn't suitable among the solar planets order (Directed Data)
(I)
- The order (Mercury – Venus – Earth) shows that greater diameter (or mass) needs
greater orbital distance.
- The order (Jupiter – Saturn – Uranus – Neptune – Pluto) shows that greater
diameter (but not mass) needs shorter orbital distance (the order depends on Planet
diameter because Uranus diameter is greater than Neptune but less mass)
- Based on this data, If the planet orbital distance is in proportionality with its
diameter, Mars position must be the next planet after Mercury, and by that the
planets "original" order must be (Mercury – Mars – Venus – Earth)
- It tells Mars must changed its orbital distance during the solar system history.
(II)
- Mercury Orbital Distance 57.9 mkm = Mercury Diameter 4879 km x 1092
- Earth Orbital Distance 149.6 mkm = Earth Diameter 12756 km x 1092
- Saturn Orbital Distance 1433.5 mkm = Saturn Diameter 120536 km x 1092
- Mars "Original" Orbital Distance 84 mkm = Mars Diameter 6792 km x 1092
(4%)
- If this is a general rule (planet orbital distance = planet diameter x 1092
), which is
used by Mercury, Earth and Saturn. That may support the claim that Mars position
was the next planet after Mercury – but – based on this same equation Mars
original orbital distance = (6792 km Mars diameter x 1092
) =80.7 mkm But this
number is incorrect because other calculations necessitates that Mars original
orbital distance must be 84 mkm, the error is 4% and we may consider that, Mars
diameter is changed with 4% as a result of its original orbital distance change ….
- But why Mars diameter was changed because of its orbital distance change?

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3-2 hypothesis no. 3 (Mars had collided with Earth & Venus to create the moon)
- The Giant –impact hypothesis tells, a planet equal Mars size had collided with
Earth and from this collision debris Earth had created its moon.
- Now let's use my hypothesis – Mars original orbital distance was 84 mkm and it
had changed to be 227.9 mkm – how that can be done?
- Mars had to move a displacement = 144 mkm from 84 mkm to 227.9 mkm- and
through this motion Mars passes beside Venus and also beside the Earth … So can
that be possible from Mars to collide with Venus and Earth?
- The giant –impact hypothesis, tells that Venus and Earth had collisions but Venus
couldn't create its own moon but Earth could, can my hypothesis explain that?
- Mars moved from 84 mkm to 227.9 mkm in a directed motion, through its motion
Mars had collided with Venus (at first) and after this collision, Mars pushed all
debris in its motion direction – for that reason – Venus had found no debris around
to attract them and create its own moon – after that – Mars had collided with Earth
– But Earth gravity is greater than Venus and the debris lost already part of their
motion momentum – for that reason – Earth attracted some debris and created its
own moon – that means the Earth moon is consisted of the three planets debris and
that explain the origin of The Lunar Magma Ocean (LMO) – where the ocean is
belonged to Venus debris.
- The rest debris had moved with Mars till its new position (227.9 mkm) and from
these debris Mars could create its 2 moons and the rest of debris is attracted by
Jupiter gravity an created The Asteroid Belt –
- This story can explain why The Iron Oxide (Feo) of the Moon= (13%)? because
The rate (13%) is a middle between Mars rate (18%) and the terrestrial mantle
(8%).

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3-3 The Moon and Mars Motions Interactions
- The previous story may explain the data dependency found between Mars and the
moon motions – let's see this data in following:
- (a) Mars orbital period 687 days = the moon orbital period 27.3 days x 25.2
- (b) Mars orbital period 687 days = Earth orbital period 365.25 days x 1.9
- (c) 25.2 degrees (Mars Axial Tilt) = 13.177 deg (the moon daily motion) x 1.9
- (d) 7 deg (Mercury orbital inclination) = 5.1 deg (the moon orbital inclination)
+1.9 deg (Mars orbital inclination)
- (e) 708.7 h (the moon day period) = 24.7 h (Mars day period) x (180/2π)
- The data shows clearly an interaction between Mars and the moon motions

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3-4 Planets Data Analysis Logic
- Mars orbital distance change is a good example to examine the planets data
analysis logic.
- As seen in the previous discussion – different data is gathered from different
sources – let's summarize this data in following
o (1) the solar planets order shows that Mars position is exceptional
o (2) the rule (planet orbital distance = planet diameter x 1092
), if it's a real
rule, supports the same conclusion, that, Mars position is exceptional (and
unsuitable)
o (3) Giant-impact hypothesis provides the details of Mars displacement
motion effects on the 2 planets (Venus and Earth). These effects can b used
as witnesses for Mars displacement (from 84 mkm to 227.9 mkm)
o These effects are seen in the Earth moon geological data and proved Mars
Migration.
- How does the planets data analysis method work?
- Let's summarize that in following:
o I suppose the solar system is a machine of gears and each planet is a gear in
it. or it's one building and each planet is a part of it
o This hypothesis tells, Planets data is created complementary to one another
– what does mean complementary one another?
o The double production experiment is a good example to explain this
meaning, where from Gamma rays electron and positron are produced, 2
particles equal in masses and different in charges – even without observation
I expect to catch a positron with the electron produced by Gamma rays
because of the charge law reservation. That tells the positron (charge) is
created complementary to the electron (charge) – their total is zero
o Based on this meaning, planets data is created complementary to each other,
if this idea is a fact what a good news behind?

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o The planets data will be similar to some children game. As a picture cut into
many pieces and request from a child to arrange these pieces in the correct
positions to create the picture again. That because the data is created
complementary to one another, we need (only) to rearrange the data in its
correct positions and to know (which electron) belongs to (which position)
by that the correct arrangement will be produced –
o When the correct arrangement be produced the geometrical rule based on
which the planets data is created will be discovered, by that we will have a
way to discover how the solar system is created and moving.

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4- Uranus Motion effect on the Moon Motion
4-1 Metonic Cycle is 19 years (Directed Data)
4-2 The hypothesis no. 4 (Uranus motion effect on the moon motion)
4-3 Data proves Uranus motion effect on the Earth, its moon and Pluto motions
4-1 Metonic Cycle is 19 years (Directed Data)
I-Data
(1)
Uranus orbital circumference 18048 mkm = 19 x Earth orbital circumferences (940
mkm) (error 1%)
(2)
Metonic Cycle is a cycle continues for 19 years.
II-Discussion
- The data shows that
- While Uranus revolves around the sun 1 revolution, Earth and its revolve around
the sun 19 revolutions (19 years), but this rate is done based on the distances and
not on the periods of time.
Accordingly
- If Uranus motion effect on Earth motion or on the Earth moon motion, the number
19 should be seen in this effect.
- But
- The moon Metonic Cycle is 19 years,
- This directed data provides a reason for the hypothesis no. 5 ( Uranus Motion
effects On The Moon Motion).

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4-2 The hypothesis No. 5 (Uranus motion effect on the moon motion)
- The hypothesis no. 5 (Uranus motion effect on the moon motion)
- Is the provided data sufficient to suggest this hypothesis?!
- And
- What's this hypothesis significance?
The Hypothesis Significance
- The hypothesis provides an extension in the solar system motion understanding
where we are limited in our consideration of any planet gravity effect by the
gravitation equation – we have no hope to find any effect of Uranus motion neither
on Earth nor on its moon because of the huge distance between Uranus and Earth
- Even Jupiter gravity effect is a trivial and insignificant on Earth and its moon spite
of Jupiter massive mass, for that reason, we can't expect a real effect of Uranus on
Earth motion
- Basically, there's no permission to create such hypothesis
- But
- The data is shown Uranus motion effect on Earth and its moon motions.
- That tells there's one more method by which the fat planet can effect on the inner
planets motions – also this method may have some selection – where Uranus effect
is so strong and clear than other planets – so if this hypothesis can be proved – we
should search after this method by which the fat planets can effect on the inner
planets motions…
- We here faces some argument – it's not decided battle – Not true – because The
Data Shows The Effect
- Now let's see if really the data shows this supposed effect of Uranus motion on
Earth and its moon motion.

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4-3 Data proves Uranus motion effect on the Earth, its moon and Pluto motions
Prove No. 1
Data No. 1
- The moon orbital circumference = 2550973 km (100%)
- Earth moves per solar day a distance = 2573482 km (101%)
- The moon displacements total during 29.53 days = 2598693 km (102%)
- Pluto motion distance during (153.3 h) = 2593836 km (102%)
(153.3 h = Pluto Day Period)
- We need this data to remember the error 1% in the Earth and moon motions.
Prove No. 2
Data No. 2
- Earth moves during (6939.75 solar days) a distance = 17860 mkm (-1%)
- Pluto moves during (6939.75) x (153.3 hours) a distance = 18000.57 mkm
- The moon displacements total during (6939.75) x (29.53 days) =18034.278 mkm
- Uranus Orbital Circumference = 18048.449 mkm
- Venus moves during (5906 days) a distance = 17860 mkm (-1%)
- We need this data to see that the error 1% is found also between Earth motion
distance during (19 years) and Uranus orbital circumference.
Discussion
- The data shows that, the error 1% in Earth, moon and Pluto motions is inherited to
these planets because they move equal distances (= Uranus orbital circumference)
in Meronic Cycle (6939.75) period multiply with their days periods –
- The data clearly show Uranus effect on the 3 planets.

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Prove No. 3
Data No. 3
- Sin (97.8 degrees) = 0.99074 (97.8 deg Uranus Axial Tilt)
- The data no (3) shows that, the error 1% is created as a result of Uranus Axial Tilt
effect on the other planets motions
- But
- There's one more important conclusion we can reach here, that, the solar system
structure is done based geometrical rules …
- means, Earth motion distance is less by 1% than Uranus orbital circumference,
because of some geometrical effect of Uranus axial tilt – it's simply another
description about the solar system motion – let's summarize it in following:
- While we consider each planet defines its orbital distance based on the gravity
forces, the data tells us some very different vision, where Earth motion distance
during (19 years) can't be greater than (17860 mkm) because Uranus axial tilt
causes category for each planet orbital distance and so forces the Earth to moves
only (17860 mkm) and not (18048 mkm)… that tells the planets are arranged
geometrically in their positions around the sun – it's NOT a position for each
planet defined based on masses gravity force – on the contrary – it's a general
design for all planets motions trajectories and this design taken into consideration
all data and Earth point is effected by Uranus axial tilt in this design.
- For that reason
- Uranus axial tilt (97.8deg) effect creates the error 1% in the planets motions data
which is seen in Earth and its moon motions – it's a proof for Uranus motion effect
on Earth and its moon motions – but the question is still more deep than the answer
– what geometrical effect is created by this 1% error?

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Prove No. 4
Data No. 4
(1)
18048 mkm – 17860 mkm = 188 mkm
(2)
940 mkm = 188 mkm x 5 mkm
(3)
30589 days = 320 days x 95.6
(4)
(188/2.55) = (17860 /243)
Discussion
Equation (1)
18048 mkm – 17860 mkm = 188 mkm
- Equation no. (1) shows the difference between Uranus orbital circumference
(18048 mkm) and Earth motion durance during 19 years (17860 mkm) = 188 mkm
- This is the error 1% (the exact number for 1% should be 180.5 mkm but the real
value =188 mkm)
- This value expresses the error 1%
- But …..What effect this value can do? Let's see in following
Equation (2)
940 mkm = 188 mkm x 5 mkm
- 940 mkm = Earth Orbital Circumference
- 5 mkm =Earth motion freedom, where Earth Perihelion (147.1 mkm) and its
Aphelion (152.1 mkm) the difference = 5 mkm
- Equation no. (2) tells that, Earth motion freedom (5 mkm) is defined based on the
value 188 mkm which is the difference between Uranus and Earth motions

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Notice
- Earth orbital circumference is defined based on Jupiter position – this idea which
we have discussed so deeply with Jupiter effect on the inner planets where we have
found that , Earth orbital circumference is defined based on Earth Jupiter distance
when both be at different 2 sides from the sun by that the distance between them
will be (778.6 +149.6 =928 mkm) which is different from 940 mkm with 1%
- This behavior is similar to Venus, where Venus orbital circumference = Venus
Jupiter distance (error 1.3%)
- This also is similar to Mercury behavior where Mercury moves during its day
period a distance = Mercury Jupiter distance
- This data we have discussed deeply before, and we concluded that, these 3 inner
planets defined their orbital circumferences to be equal their distances to Jupiter
- That tells, Earth orbital circumference is defined by Jupiter effect
- And the value 188 mkm is the difference between Earth and Uranus motions
- By that, the Earth motion freedom (5 mkm) (from Perihelion to aphelion) is
defined based on this difference (188 mkm).
- That shows Uranus effect on the Earth motion but not only
- More important, that shows Uranus effect on Earth motion is done on a vertical
axis (z-axis) which supports the claim that Uranus effects on the solar planets
vertically.
- This explanation has importance beyond what's written already because its shows
the interaction between Uranus and Jupiter motions in their effects on the inner
planets (specially) on Earth.
- Shortly
- Equation no. (2) tells, Uranus motion effect on Earth motion and created a feature
in Earth motion proves Uranus effect which is the 5 mkm.

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Equation (3)
30589 days = 320 days x 95.6 (30589 days = Uranus Orbital Period)
- We remember, 188 mkm is the difference between Uranus orbital circumference
(18048 mkm) and Earth motion distance during 19 years (17860 mkm).
- Uranus moves 188 mkm during 320 solar days
- 95.6 degrees = 90 degrees +5.6 degrees
- But
- 5.1 deg (the moon orbital inclination) +0.5 deg (the moon diameter angle)=5.6 deg
- 5.6 degrees = the moon orbital inclination measured above its diameter
- Equation no. (3) tells that, the moon orbital inclination is defined based these 2
values (30589 days =Uranus orbital period) and (320 days the period Uranus needs
to pass 188 mkm).
- The data tries to prove that
- Motions features are found in Earth and its moon motions produced by Uranus
motion effect on Earth and its moon motions.
Equation (4)
(188/2.55) = (17860 /243)
- 188 mkm = The difference between Uranus orbital circumference and Earth
motion distance during 19 years
- 2.55 mkm = The Moon Apogee Orbital Circumference
- 17860 mkm = Earth motion distance during 19 years
- 243 days = Venus Rotation Period (is used as 243 mkm)
- The period 243 days is used as a distance 243 mkm, because Venus uses the
distance values periods of time – this using we have seen frequently for example

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- Mercury moves during its rotation period (58.66 days) a distance =243 mkm
- Mars moves during Venus day period (116.75 days) a distance =243 mkm
- This using shows that the period 243 days can be used as 243 mkm – as seen in the
equation no. (4)
- Also this using is done by Venus motion, where Venus moves during 365.25 days
a distance = 1103 mkm = 2π x175.94 mkm (where Mercury day period =175.94
days).
- Equation no. (4) tells that both values (17860 mkm and 188 mkm) are taken into
consideration in creation the values 243 mkm and 2.55 mkm which means the
moon orbital circumference at apogee radius (2.55 mkm) is defined by Uranus
effect through Venus motion.
Equation (5)
Venus moves during (5906 days) a distance = 17860 mkm (-1%)
- 1461 days x 4 = 5844 days (different from 5906 days with 1%)
- 1461 days = Earth 4 years cycle (365 +365 +365 +366 =1461 days)
- 5906 mkm = Pluto Orbital Distance
- Venus uses usually the distance values as periods of time
- The distance (17860 mkm) is exactly Earth motion distance during 19 years.
- Equation No. (4) shows that, Venus motion is effected by Uranus motion also but
this effect is seen through complex geometrical interactions.

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Prove No. 5
Data No. 5
(a)
(97.8 degrees / 5.1 degrees) = (2872.5 mkm/149.6 mkm)
(b)
97.8 deg – 96.7 deg =1.1
(c)
1.44 = 0.8 x 1.8
(d)
97.8 deg = 8 x 12.195 deg
(e)
180.8 deg = 177.4 deg +3.4 deg
(f)
254 x 5.08 degrees = 1290 degrees
(5.1 deg= the moon orbital inclination) (254 =6939.75 days /27.32 days)
13.177 x 97.8 = 1289 degrees
(g)
17.2 hours (Uranus Day) x 8.9 = 153 hours (Pluto day period =153.3 hours)
(h)
Tan (8.9 deg) x 153.3h (Pluto day period) = 24 hours
Tan (12.195 deg) x 708.7 hours (the moon day period) = 153.3 h (Pluto day period)
Tan (13.177 deg) x 655.7 h. (the moon rotation period) = 153.3 h (Pluto day period)
- What do we try to do here?
- I try to show that, the Earth and its moon motions data is created by an effect of
Uranus motion data. (also Venus motion data is effected by Uranus data)
- That supports the claim (Uranus effect on the Earth and its moon motions)

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Discussion
Equation No. (a)
(97.8 degrees / 5.1 degrees) = (2872.5 mkm/149.6 mkm)
- 97.8 deg = Uranus Axial Tilt
- 5.1 deg = The moon orbital inclination
- 2872.5 mkm = Uranus Orbital Distance
- 149.6 mkm = Earth Orbital Distance
- Equation no. (a) shows that Uranus motion data effects on the Earth and moon
motions data
Equation No. (b)
97.8 deg – 96.7 deg =1.1 deg
- 96.7 deg = 90 deg + 6.7 deg (The moon Axial Tilt)
- What's this angle 1.1 degrees? It's the moon angle in its motion let's remember it in
following (we remember that the moon uses Pythagorean triangle in its motion)
o We know that (363000)2
+ (86000)2
= (373000)2
o In Pythagoras triangle with dimensions (363000 km, 373000km, 86000 km),
what's the angle (θ)? The angle (θ) = 13.33 degrees
o Also (396800)2
+ (86000)2
= (406000)2
the angle (θ) = 12.229 degrees
o I have used (363000 km and 406000 km) because they are the perigee and
apogee radiuses between which the moon moves.
o The difference between angles = 1.1 degrees
i.e., the angle (1.1 deg.) controls the moon motion from perigee to apogee, we will
need this notice later in our discussion
Notice
95.6 deg +1.1 = 96.7 deg and 97.8 deg +1.1 = 98.9 deg (=90 +8.9 deg)

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Equation No. (c)
1.44 = 0.8 x 1.8
- 1.44 degrees = the moon orbit regression per month
- 1.8 degrees = Neptune Orbital Inclination
- 0.8 degrees = Uranus Orbital Inclination
- Equation no. (c) shows Uranus and Neptune effect on the moon orbit regression.
Equation No. (d)
97.8 deg = 8 x 12.195 deg
- 12.195 deg = the moon motion angle (13.177 deg – 0.98562 deg)
- 8 = refers to the cycle of 8 days which is used by Uranus & Jupiter
Equation No. (e)
180.8 deg = 177.4 deg +3.4 deg
- 177.4 deg = Venus Axial Tilt
- 3.4 deg = Venus Orbital Inclination
- 180.8 deg = 180 degrees + 0.8 degrees (Uranus Orbital Inclination)
Equation No. (f)
254 x 5.08 degrees = 1290 degrees
(5.1 deg= the moon orbital inclination) (254 =6939.75 days /27.32 days)
13.177 x 97.8 = 1289 degrees
- 13.177 deg = The moon daily motion degrees (= 360/27.3)
- Equation no. (f) shows Uranus effect on Metonic Cycle (6939.75 days)

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Equation No. (g)
17.2 hours (Uranus Day) x 8.9 = 153 hours (Pluto day period =153.3 hours)
- We remember the angle (8.9 degrees = 98.9 -90 but 98.9 =97.8 +1.1)
- Equation no. (g) shows that Pluto day period depends on Uranus day period based
on the interaction done with Earth and its moon motion – that explains why Pluto
moves during its day period a distance = Earth motion distance during its day
period = the moon motion distance during its day period (error 1%)
Equation No. (h)
Tan (8.9 deg) x 153.3h (Pluto day period) = 24 hours
Tan (12.195 deg) x 708.7 hours (the moon day period) = 153.3 h (Pluto day period)
Tan (13.177 deg) x 655.7 h. (the moon rotation period) = 153.3 h (Pluto day period)
- Equation no. (h) shows interactions between Earth and its moon days & rotations
periods with Pluto day and rotation periods – these interactions can be occurred
only through Uranus motion effect because these 3 planets moves during the
period 6939.75x (each planet day period) a distance= Uranus orbital circumference
where Earth motion has a difference 1% but their motions are effected by Uranus
motion because all of them move distances = Uranus orbital circumference.

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A General Comment
- This discussion has tried to arrange the motions data in the correct position
showing that Earth and its moon motions must have an effect of Uranus motion
because Uranus motion data is seen in different data of the Earth and its moon
motions
- The philosophical vision behind is that, Planets data is not created independently
from one another, on the contrary, they are created complementary each other,
based on this vision we can explain how the data is created –
- The geometrical mechanism is still more complex and beyond this discussion
scope, for example, Uranus axial tilt =19.2 x the moon orbital inclination but
Uranus orbital distance =19.2 Earth orbital distance, this equality in isn't created
by any random process on the contrary it's created by geometrical mechanism
which created all these data for one geometrical reason – means (Uranus axial tilt
and orbital distance on one side and Earth orbital distance and the moon orbital
inclination on the other side) All these data is created by one geometrical reason to
be rated each other as the data shows. The discussion can't reach this geometrical
mechanism or reason by which this data is created but limited its scope to show
that the data is created based on one another which proves that an effect of Uranus
motion is done on Earth and its moon motions and by this proof we may expect to
extend the planets forces (gravities) effect beyond the current range.

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5- Eight Days Cycle Is Found In The Solar System
5-1 Jupiter 8 days Cycle (Directed Data)
5-2 The hypothesis no. 5 (8 days cycle is found in the solar system)
5-3 Planets data proves the 8 days cycle.
5-1 Jupiter 8 days Cycle (Directed Data)
Data
(1)
Jupiter (13.1 km/s) moves during its day period (9.9 h) a distance = 466884 km
Where 466884 km = 449197 km (Jupiter Circumference) +17687 km
(2)
During 8 days of Jupiter days
Jupiter (13.1 km/s) moves during 8 of its days a distance = 3735072 km
Where 3735072 km = 8 x 449197 km (Jupiter Circumference) +141496 km
(141496 km = Jupiter diameter with error 1%)
- The conclusion tells that, the value (17687 km) aimed to be (141496 km) in 8 of
Jupiter days and that means Jupiter has a cycle in 8 of its days
- (This is similar to Earth cycle 1461 days = 365+365+365+366) Where the value
0.25 days (for each year) is accumulated in 4 years to be 1 day by that we know
Earth has a cycle of 4 days

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5-2 The hypothesis no. 5 (8 days cycle is found in the solar system)
- The hypothesis no. 5 tells that, this cycle is a general cycle for the solar system.
That means,
- If this cycle is a real one, it's not just Jupiter cycle based on 8 of its days, but it's a
cycle for the whole solar system, means, all planets follow this same cycle even in
different units
- Means, this cycle for Pluto is used in 8 days of Pluto days and for Earth is used as
8 years of Earth –
- Shortly
- It's a common cycle for the whole solar system
- Let's see the data which proves this hypothesis in the next point

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5-3 Planets data proves The 8 Days Cycle.
Jupiter 8 days Cycle
o Jupiter (13.1 km/s) moves during its day period (9.9 h) a distance = Jupiter
circumference (449197 km) + 17695 km
o During 8 of Jupiter days periods (9.9 x 8 =79.2 h), Jupiter moves a distance
= 8 Jupiter circumferences + Jupiter diameter (error 1%)
o Because of Jupiter diameter I concluded that, Jupiter has a cycle in 8 days
Then
o Jupiter motion distance during 8 of its days (79.2 h) which = 3735072 km,
this same distance = Saturn motion distance during 10 of Saturn days period
o Means, Saturn moves during 10 of its days a distance = 3735072 km,
o I have concluded that, Jupiter motion energy is transported to Saturn motion
energy by the rate 80% Because of that I expected that, Saturn should
transport its motion energy to Uranus by the same 80% (but it's incorrect!)
o Saturn transported the motion energy with this rate 80% to Neptune and that
means the distance Saturn passes during 8 of Saturn days period, Neptune
passes during 10 of Neptune days period (error 5%)
The question is why Saturn doesn't transport the motion energy to Uranus?!
- A surprise was in our waiting…
- Uranus (6.8 km/sec) moves during Pluto day period (153.3 h) a distance = Jupiter
motion distance during 8 of its days period (79.2 h) + 17695 km
- means, during 8 Pluto days period (153.3 h x 8) Uranus moves a distance = Jupiter
motion distance during 64 Jupiter days (9.9 h x 64) +Jupiter diameter (1%)
- Uranus Cycle behavior is very similar to Jupiter (8 days) cycle behavior.
- Why These Distances Are Equal?
- What's The Result Effect Of These Cycles?

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Uranus Cycle (depends on 8 of Pluto days)
I- Data
1. Uranus (6.8 km/s) moves during 8 days of Pluto days period (1226.4 hours) a
distance = (4415040 seconds x 6.8 km/s) = 30.022272 million km
2. Jupiter (13.1 km/s) moves during 64 days of Jupiter days period (64 x9.9 h =
633.6 hours) a distance = (2280960 seconds x 13.1 km/s) = 29.880576 million km
3. Saturn (9.7 km/s) moves during 80 days of Saturn days period (80 x10.7 h = 856
hours) a distance = (3081600 seconds x 9.7 km/s) = 29.891520 million km
4. Neptune (5.4 km/s) moves during 100 days of Neptune days period (100 x16.1 h =
1610 hours) a distance = (5796000 seconds x 5.4 km/s) = 31.298400 million km
5. Jupiter Circumference (449197 km) x 64 = 28.748639 million km
6. Saturn Circumference (378675 km) x 80 = 30.294001 million km
7. Neptune Circumference x 2 (311193.6 km) x 100 = 31.119360 million km
Notice (1)
- The equal distances are approximately passed by
o (1) Uranus during 8 Pluto days (2) Jupiter during 64 of its days
o (3) Saturn during 80 of its days (4) Neptune during 100 of its days
Notice (2)
- The data shows, Jupiter and Uranus are independent planets but Saturn and
Neptune depends on Jupiter motion–means- Uranus may have an interaction with
Jupiter but the other 2 planets are effected by this interaction through Jupiter.

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II-Discussion
(1st
Point)
- Uranus motion distance during 8 of Pluto days period (30.022272 mkm) – Jupiter
motion distance during 64 of Jupiter days period (29.880576 mkm) = 142984 km
(= Jupiter diameter) (error 1%)
- Because of Jupiter diameter value, I have concluded that, Uranus & Jupiter Creates
a cycle by their motions interaction.. Where Uranus uses 8 of Pluto days periods
and Jupiter uses 64 of its days period.
(2nd
Point)
- Jupiter motion distance during 64 of its days period (29.880576 mkm) – the total
of 64 Jupiter Circumferences (28.748639 mkm) = 1.1318 m km
- Jupiter moves per a solar day a distance = 1.1318 m km
- That means, these 2 values express 2 motions interacted together to produce this
value (1.1318 m km) which is considered as a value defined based on cycle
period (a solar day).
(3rd
Point)
- Saturn motion distance during 80 of its days (=29.891520 mkm) – Jupiter motion
distance during 64 of its days period (= 29.880576 mkm) = 10921 km
o 10921 km = The Earth Moon Circumference
o The 2 values are considered to be equal, and its almost correct because the
difference between both = 0.036%
o But this very small error = the moon circumference
o Please Note 29891520 km = 10921 x 2737
o But 29880576 km = 10921 x 2736
o Please remember the cycle 2737 years

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(4th
Point)
- Neptune motion distance during 100 of Neptune days periods (=31298400 km) –
Saturn motion distance during 80 of Saturn days periods (=29891520 km) =
1406880 km ………. But
o 1406880 km = The Sun Diameter 139200 km (Error 1%)
o The Sun Diameter 139200 km = 49528 km Neptune diameter x 28.1
o Neptune Axial Tilt =28.3 degrees
(5th
Point)
- Neptune motion distance during 100 of Neptune days periods (=31.298400 mkm)
– Uranus motion distance during 8 of Pluto days periods (=30.022272 mkm) =
1.276128 mkm = π x 406000 km
- Earth Moon Distance at apogee radius = 406000 km, where this is the most far
point the moon can reach from Earth.
Uranus 144 days Cycle
- 144 days of Uranus days periods = 144 x 17.2 hours = 2476.8 hours
- 16 days of Pluto days period = 16 x 153.3 hours = 2452.8 hours
- The Difference = 24 hours = 1 Solar Day
- The data shows these are 3 values (144 Uranus days, 16 Pluto days and the solar
day) they are 3 cycles
Notice
Pluto moves during 16 Pluto days a distance =41.5 mkm = Venus Earth Distance

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More Discussion
- We have one question to answer
- Are These Cycles Different Cycles Or One Cycle?
- In more clear words
- Jupiter has a cycle of 8 days, and Uranus has a cycle of 8 Pluto days, are these
2 different cycles are one cycle only?
- Let's answer in following
- First, we know that, Saturn and Neptune depends on Jupiter for that we will use
Jupiter as their head, so the question tells about 2 cycles which are Jupiter 8 days
cycle and Uranus cycle of 8 Pluto days…. The question again
- Are These 2 Cycles Different Cycles Or One Cycle Only?
- Let's move step by step in following:
o Uranus (6.8 km/sec) during Pluto day (153.3 hours) moves a distance =
3752784 km
o Uranus (6.8 km/sec) during 8 Pluto days (8 x 153.3 = 1226.4 hours) moves a
distance = 30022272 km (No.1)
o Jupiter (13.1 km/sec) during 64 Jupiter days period (=633.6 hours), moves a
distance = 29880576 km (No.2)
o No. (1) – No. (2) = 141515 km = Jupiter diameter (error 1%)
BUT
o 30022272 km= 64 Jupiter Circumferences+ 9 Jupiter diameters (1%)
o Why?
o During 8 Jupiter days, Jupiter moves a distance = 8 (Jupiter circumferences
449197 km ) + (1 Jupiter diameter 141515 km "error 1%")

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o During 64 Jupiter days, Jupiter moves a distance = 64 (Jupiter
circumferences 449197 km ) + (8 Jupiter diameter 141515 km "error 1%")
o But
o Uranus during 8 Pluto days moves a distance = Jupiter motion distance
during 64 Jupiter days + 1 Jupiter diameter 141515 km "error 1%")
o i.e.
o Uranus during 8 Pluto days moves a distance = 64 (Jupiter circumferences
449197 km ) + (8 Jupiter diameter 141515 km "error 1%") + (1 Jupiter
diameter 141515 km "error 1%")
o i.e.
o Uranus during 8 Pluto days moves a distance = 64 (Jupiter circumferences
449197 km ) + (9 Jupiter diameter 141515 km "error 1%")
o The error is 1%
o 9 Jupiter diameter = 1286856 km but the error 1% causes this total to be
1273987 km
o The difference = 1286856 km – 1273633 km= 12756 km (Earth Diameter)
Notice (1)
o The value is (13223 km) and it's different with Earth diameter with around
500 km (by error 3.5%) but this error is not true error – because this value is
a result of collection 9 Jupiter diameters and if Jupiter diameter has a very
small error this great error can be produced in Earth diameter – by that the
difference (500 km) should be attributed to the value (1273633 km) where
the error is only 0.04%)
A Conclusion
o Earth Diameter Proves That, These Cycles Are Only One Cycle

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6- The inner planets orbital circumferences are rated to Jupiter Motion
6-1 The Directed Data
6-2 The hypothesis no. 6 (Jupiter motion effect on the inner planets motions)
6-3 the hypothesis proves discussion
Mercury (47.4 km/s) moves during its day period (422.6 h) a distance = 720.7 mkm =
Mercury Jupiter Distance
6-2 The hypothesis no. 6 (Jupiter motion effect on the inner planets motions)
- The hypothesis tell the following meaning
o Jupiter is the inner planets parent
o The 3 inner planets (Mercury, Venus & Earth) define their orbital
circumferences to be equal their distances to Jupiter.
o Mars doesn't follow this same rule because of Mars Migration from its
original orbital distance (84 mkm) to its new orbital distance (227.9 mkm)
o Jupiter orbital circumferences is created as the inner planets orbital
circumferences total – this rule can be simply one if Mars didn't migrated –
o But
o Because of Mars Migration, Mars orbital circumference is used 2 times in
this relationship as the following data shows
Shortly
o Jupiter is the inner planets parent and source of energy
o Mars Migration causes a disturbance for this relationship and Mars has to
depend on Saturn in place of Jupiter
o Jupiter could repair the negative effect of Mars migration by support from
Saturn.

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6-3 The hypothesis Proves Discussion
I- Data
(I)
- Mercury moves during its day period a distance = Mercury Jupiter Distance
(No error)
- Venus moves during its orbital period a distance = Venus Jupiter Distance
(1.3%)
- Earth moves during its orbital period a distance = Earth Jupiter Distance
(778.6 mkm +149.6 mkm = 928 mkm has an error 1.2% with 940 mkm)
(II)
- Mercury orbital circumference =360 mkm
- Venus orbital circumference =680 mkm
- Earth orbital circumference =940 mkm
- Mars orbital circumference =1433.5 mkm
- The 4 planets orbital circumferences total = 3413.5 mkm
BUT
- Jupiter orbital circumference =4900 mkm …..And
- 3413.5 mkm + 1433.5 mkm = 4900 mkm ……Means
- Jupiter orbital circumference = the inner planets orbital circumferences total
+ Mars orbital circumference
- Means, Mars orbital circumference is used 2 times with the other 3 inner planets
circumferences to create Jupiter orbital circumference
- I try to show, the inner planets motions data is created as a function in Jupiter
motion data. Means, Jupiter is almost the inner planets parent, and by the energy
(4224) which is sent from Jupiter to Mercury the inner planets formed their orbital
motions and circumferences to be rated with Jupiter motion and orbital
circumference. (Notice Mars orbital circumference = Saturn orbital distance)

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The Distance 4224 mkm
- The following discussion is an old one – let’s summarize it:
o We have supposed that, a light velocity 1.16 mkm/sec is found, so we will
use this velocity as a real one because we have discussed its proves before.
o Also
o We know that, light motion can use the distance values as a periods of time
that because (x = ct and if c=1 so x=t)
o Based on that,
o The distance 4224 mkm will be used as a period of time (4224 seconds)
o Light with supposed velocity (1.16 mkm/sec) travels during 4224 seconds a
distance =4900 mkm = (Jupiter Orbital Circumference) (Result 1)
o Mercury day period =4222.6 hours which is very near to this value 4224
seconds and So, we suppose Mercury day period is created based on this
same value (4224 seconds), supposing that, light motion of a second causes
Mercury to move for an hour. (Result 2)
o Mercury moves during its day period (4222.6 hours) a distance = 720.7
mkm = Mercury Jupiter Distance. (Data No. 3)
o The previous explanation tries to prove that, the light beam (1.16 mkm) is
sent from Jupiter to Mercury and this light beam created Jupiter orbital
circumference and causes to make Mercury day period =4222.6 hours
Now
o Mercury moves during 1440 Uranus days a distance = (2 x Jupiter Uranus
distance), that shows Mercury as a point on which both 2 planets motions
effect greatly. Means, 2 strong forces (Jupiter and Uranus) connected each
other on Mercury (as if Mercury the land the 2 planets stand on it).

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The Value 4224 (More Discussion)
- The value 4224 shows Jupiter effect not only on Mercury but on all inner planets
- Let's see that in following
(1)
o 4224 mkm = 2π x 670.4 mkm (670.4 mkm = Jupiter Venus Distance)
(2)
o (5040 s/ 4224 s) = (928 mkm/778.6 mkm)
o Where
o 778.6 mkm = Jupiter orbital distance
o 928 mkm = Jupiter Earth distance = 778.6 mkm +149.6 mkm
o But
o Mercury day needs 5040 seconds to be 176 solar days
o And
o 4224 seconds which is equivalent to 4224 mkm
(3)
o (4222.6 hours /24.7 hours) =170
o Where
o 4222.6 hours = Mercury Day Period
o 24.7 hours = Mars Day Period
o 170 mkm = the distance between Mercury and Mars
- The data shows the number 4224 is inherited in all inner planets motions.

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7- There's a light velocity =1.16 million km/sec
7-1 The Directed Data (4224 sec x 1.16 mkm/sec = 4900 mkm)
7-2 The hypothesis no. 7 (light velocity 1.16 mkm/s is found in the solar system)
7-3 Light Velocity 1.16 mkm/sec Proves Discussion
7-1 The Directed Data (4224 sec x 1.16 mkm/sec = 4900 mkm)
The Directed Data
- Light supposed velocity (1.16 mkm/sec) travels during 4224 seconds a distance
=4900 mkm = Jupiter Orbital Circumference.
- The value 4224 seconds (or 4222.6 seconds) remind us by Mercury day period
4222.6 hours
- We may consider that, light motion during 1 second causes Mercury motion during
1 hour and the different rate of time is created because of the light motion (high
velocity motion)
- This data suggests the hypothesis (a light velocity =1.16 mkm/sec is found in the
solar system)
7-2 The hypothesis no. 7 (light velocity 1.16 mkm/s is found in the solar system)
- The hypothesis tells us a clear data, that
o A light beam its velocity is 1.16 mkm/sec is found in the solar system
and effective on its geometry
o The hypothesis is so heavy as any physicist may consider. And we need
to know if there's real data can prove or even support it
o let's discuss the proving data in following

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7-3 Light Velocity 1.16 mkm/sec Proves Discussion
(1st
Proof) Jupiter Energy Analysis
(1)
Jupiter sends energy to Pluto – Jupiter energy is sent in a light beam form, where this
light beam velocity =1.16 mkm/sec – Jupiter continued sending its energy for 2 full
solar days (2 x 86400 seconds)
(2)
During 2 solar days, light with velocity 1.16 mkm/s passes a distance = 200448 mkm
But
(Pluto orbital circumference – Jupiter orbital circumference) x 2π= 200448 mkm
(3)
This Energy reach to Pluto – but Pluto reflected this full energy again to Neptune –
That means Pluto didn't use any of this energy but Pluto reflected it to Neptune
completely
(4)
Neptune – in that time – had no an orbital circumference – for that reason – Neptune
used part of the sent energy to build its orbital circumference (28255 mkm)
Specifically Neptune used 14% of the total energy to build its orbital circumference
(3)
After Neptune Orbital Circumference Building
The rest of energy = 86% (= 2x 86400 mkm) ,
this energy Neptune reflected to the inner planets, into 2 equal trajectories of Energy,
Each Trajectory contains an energy =43% of the total =86400 mkm
(Neptune orbital circumference – Venus orbital circumference) x2π= 86400 mkm
x 2 (The explanation considers that Distance = Energy)
A Comment
- Planets motions data is in full harmony with this (imaginary) story, can that be
proof for this story to be considered as a fact?

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(2nd
Proof)
The value 4224 seconds or mkm
- We have discussed this value deeply in the previous point (the hypothesis no. 6
proves discussion)
- The discussion show that light supposed velocity (1.16 mkm) uses this period 4224
seconds in different forms to effect on the inner planets motions.
- This discussion should be considered a part of our proof for this hypothesis
(3rd
Proof) Light motion features are discovered in Jupiter data
- This is one basic feature of Jupiter motion, that clear light motion features are
discovered in its data let's see some of this data in following
(1)
- 778.6 mkm (Jupiter Orbital Distance) = 670 seconds x 1.16 mkm/sec
- 720.7 mkm (Mercury Jupiter Distance) =627 seconds x 1.16 mkm/sec
- 627 mkm (Earth Jupiter Distance) = 540 seconds x 1.16 mkm/sec
(670.4 mkm = Venus Jupiter Distance)
(2)
- 778.6 mkm / 720.7 mkm = 1.0725
- 720.7 mkm /670.4 mkm = 1.0725
- 670.4 mkm /629 mkm = 1.0725
Discussion
- This data should be analyzed with the data in point no. 6-3 (the proves discussion
of hypothesis no. 6), because this data shows 2 important features (1st
the deep
interaction between Jupiter & the inner planets motions data) and (2nd
light motion
features which is discovered in Jupiter data and seen also in the inner planets
motions data as a result of Jupiter effect on them).
Notice
- 5040 minutes x 0.99 = 4989.6 minutes = 299376 seconds
- During 299376 seconds light known velocity (0.3mkm/sec) travels 89812.8 mkm
- 89812.8 mkm –86400 mkm = 3413 mkm (the 4 inner planets circumferences total)

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(4th
Proof) Mercury Data
Data
5040 seconds x 1.16 mkm/sec = 5846 mkm (Mercury Pluto Distance)
(1)
5040 seconds x 1.16 mkm/sec = 5846.4 mkm (Mercury Pluto distance)
(2)
Mercury Day needs 5040 seconds to be 176 solar days
(3)
Mercury velocity /solar day 4.095mkm x346.6 days (Nodal Year) =1433.5 mkm (1%)
(4)
Mercury velocity 4.095 mkm x1433.5 days =5846.4 mkm (Mercury Pluto distance)
(Error 0.4%)
(5)
30589 days (Uranus orbital period) = 88 days (Mercury orbital period) x 347.6
Discussion
- The light supposed velocity (1.16 mkm/sec) is supposed to reach to Mercury and
Pluto by Jupiter Energy –
- The previous data (spite its complexity) but it tells that, the light 1.16 mkm/sec
connects between Mercury and Pluto Motions.
- This complex geometrical interaction causes Mercury day to be less than 176 solar
days with 5040 seconds.

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8- Light motion features are discovered in Planets Motions.
8-2 hypothesis no. (8) (light motion features are discovered in planets motions)
8-3 the hypothesis proves discussion
Data
Light known velocity (0.3 mkm/sec) travels during a solar day (86400 seconds) a
distance = 25920 mkm
The Precession Cycle =25920 years
This data tells us that, the value 25920 is created by light motion as (a distance) and
we see it as a period of time –
That shows light motion effect on planets motions data
8-2 hypothesis no. (8) (light motion features are discovered in planets motions)
- Light motion features are discovered frequently in planets motions data…
- The hypothesis tells, If matter is created of light, so this light motion features are
still seen in the born matter and because of that the planets (matters) motions still
show light motion features
- The next point provides a list of these light motion features

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8-3 The Hypothesis Proves Discussion
1- Distances Equality And Proportionality
2- Matter and Space Dimensions Proportionality
3- Planets Data Dependency One Each Other
4- Relativistic Effects are discovered in Planet Motion Data
5- Distance and Time Equivalence In Planets Motion Data
6- Light motion relativistic effects are hidden behind planet motion geometrical
rules
7- Different rates of time are discovered in the solar system motion
8- Planets data depends on the rate 99%, showing light motion feature.
9- Planet Velocity Analysis proves light motion effect on planet motion.
10- Planet Circumference is proportional to light motion distance per second
11- Jupiter Data proves that (there's a light beam its velocity 1.16 mkm/sec)
12- Planets data integration (teamwork) to produce a specific phenomenon,
disproves the random creation concept and suggests the solar system planed
creation, necessitates to find its creator (the light).
13- Planet Masses Analysis shows light motion effect on planets creation data
We discuss some features as examples in following– the full discussion is found in
my previous papers
Please review the references.

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1- Distances Equality And Proportionality
I- Data (A)
Why These Distances Are Equal?
(1)
Saturn Orbital Distance = Saturn Uranus Distance
= Mars Orbital Circumference
= Pluto Neptune Distance
= Pluto eccentricity Distance
= Neptune Orbital Distance/π
= Uranus Orbital Distance /2
= Mercury Jupiter Distance x 2
(2)
Mercury Neptune Distance = Saturn Pluto Distance
Jupiter Pluto Distance = Uranus Neptune Circumference
Earth Neptune Distance = Mercury Saturn Circumference (0.5%)
(3)
Jupiter Mercury Distance = 2 Mercury Orbital Circumference
Jupiter Venus Distance = Venus Orbital Circumference (1.5%)
Jupiter Earth Distance = Earth Orbital Circumference (1.2%)
(Earth and Jupiter at 2 different sides from the sun)
(4)
Jupiter Mercury Distance = Mars Orbital Distance x π (0.6%)
Jupiter Uranus Distance = Venus Jupiter Circumference (0.8%)
Pluto Orbital Distance = Earth Orbital Circumference x 2π
II- Discussion (A)
The previous distances form around 50% of all distances found in the solar system
(All orbital and internal distances)… Why These Distances Are Equal One Other?
We may notice that – the distances equality can be produced more easily by light
motion than the rigid body motion - for example – when we push a ball toward a wall
the ball after collision with the wall will return a distance (NOT) equal the original
one - because the collision causes to decrease the ball motion momentum – but the
light can be reflected at equal distances easily – means – equal distances can be
produced by light motion more easy than the Rigid Body Motion.

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I-Data (B)
Why These Distances Are NOT Equal?
1. 0725
.
1
mkm
2.41
nce
Circumfere
Orbital
Moon
mkm
2.58
Motion
Daily
Earth
=
2. 1.0725
km)
(378500
radius
Eclipse
Solar
Total
km)
(406000
radius
orbital
Apogee
=
3. 0725
.
1
distance
Mercury
Jupiter
mkm
720.3
Distance
Orbital
Juppiter
mkm
6
.
778
= (Error 0.7%)
4. 1.0725
Distance
Venus
Jupiter
mkm
670
distance
Mercury
Jupiter
mkm
720.3
=
5. 1.0725
Distance
Earth
Jupiter
mkm
629
Distance
Venus
Jupiter
mkm
670
= (0.6%)
6. 1.0725
mkm)
(1325.3
Distance
Venus
Sarurn
mkm)
(1433.5
Distance
Orbital
Saturn
= (0.8%)
7. 1.0725
mkm)
(1205.6
Distance
Mars
Sarurn
mkm)
(1284
Distance
Earth
Saturn
= (0.7%)
8. 1.0725
mkm)
(2644
Distance
Mars
Uranus
mkm)
(2872.5
Distance
Orbital
Uranus
= (0.7%)
9. 1.0725
mkm)
(4495.1
Distance
Orbital
Neptune
mkm)
(4894
nce
Circumfere
Orbital
Jupiter
= (1.5 %)
I-Discussion (B)
The same rate (1.0725) is used for all equations (around 18 distances = 40% of all
solar system distances) – why?
Suppose the equal distances are produced by light reflection and that cause these
distances to be equal – as I have supposed in the previous point (A).
Now suppose– part of these equal distances – is passed through another frame relative
to us – so this part of distances will suffer from Lorentz Length Contraction Effect
which is seen in the rate 1.0725 (Another frame can be found in the solar system
because we deal with light motion) – this explanation can answer why some distances
are equal and others are rated with (1.0725) – it's simply a feature of light motion.

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2- Matter and Space Dimensions Proportionality
Why Do We See The Sun Disc = The Moon Disc? Because
Equation No. 1
Equation No. 1 tells that –
Matter Dimensions must be created in proportionality with Space Dimensions.
The equation gives us a new vision to answer how the matter and space are created –
and based on it– Space no longer be considered as found independently from matter –
because the equation tells – no matter can be created without space and no space can
be found without matter –
Both are created in proportional dimensions to each other…
But what depth can be behind this equation?
Matter is created of Energy (E= mc2
) – and based on this equation – We may
conclude that – Space is created of Energy –
So this new vision disproves the creation random concept–means- neither matter nor
space can be created by any random process.
On the contrary matter and space dimensions are created based on calculations taken
into considerations the other dimensions.
(A Conclusion)
Matter Dimensions Are Created In Proportionality With Space Dimensions.
Distance
Moon
Earth
Distance
Sun
Earth
Daimeter
Moon
The
Daimeter
Sun
The
=

I do this research
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64
9- The solar system Geometry uses the distances values as periods of time
9-2 hypothesis no. (9) (The solar system uses distances values as periods of time)
9-3 The hypothesis proves discussion
Data
(1)
Mercury moves during its rotation period (58.66 solar days) a distance = 243 mkm
(2)
Mars moves during Venus day period (116.75 solar days) a distance = 243 mkm
(3)
Venus moves during 365.25 days a distance = 2π x 175.94 mkm
Where
243 days = Venus Rotation Period
175.94 days = Mercury Day Period
9-2 hypothesis no. (9) (The solar system uses distances values as periods of time)
This hypothesis is suggested by its force – means – no current explanation is available
how this is done – the distances planets data is used as period of time by force and we
understand how that's happening, the data shows this feature but we can't catch the
light beam which causes this feature where the planet motion is low and can't perform
this feature..!
The data shows this fact

I do this research
2nd
65
9-3 The hypothesis proves discussion
(1)
o Jupiter (13.1 km/sec) moves during 10921 seconds a distance =142984 km
= Jupiter diameter (where 10921 km = the moon circumference)
(2)
o Uranus (6.8 km/sec) moves during 7510 seconds a distance =51118 km =
Uranus diameter (where 7510 km = Pluto circumference)
(3)
o Pluto (4.7 km/sec) moves during 10921 seconds a distance =51329 km
(where 51118 km= Uranus diameter and 7510 km = Pluto circumference)
o Pluto (4.7 km/sec) moves during 51118 seconds a distance = 2 x 120127 km
(Saturn diameter =120536 km)
o Pluto (4.7 km/sec) moves during 12756 seconds a distance = 59953 km
(Earth diameter =12756 km and Saturn Radius = 60268 km)
(4)
o Venus (35 km/sec) moves during 12104 seconds a distance = 421056 km
(421056 km = the distance passed by Uranus during its day period) (12104
km= Venus diameter)
(5)
o Venus (35 km/sec) moves during 10921 seconds a distance = 378675 km
(Saturn Circumference) (error 1%)
(6)
5040 sec. x 6.8 km /s (Uranus velocity) = 34309 km (= 10921 km x π)
34309 sec x 13.1 km/s (Jupiter velocity) = 449197 km = Jupiter Circumference
34309 sec x 4.7 km/s (Pluto velocity) = 160592 km = Uranus Circumference
34309 sec x 27.78 km/s (the moon velocity) = 943817 km
(943817 km = the perimeter of the moon orbital triangle ACE) (error 1%)

Planets Data Analysis Curriculum

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