What is the probability of having a boy, then a girl, then a boy, and then two girls in that birth order? Solution Probability of boy P(b) = 1/2 and probability of girl is also P(g) = 1/2 as they are the only 2 outcome possible and are equally likely So probability of having a boy, then a girl, then a boy, and then two girls = P(b)*P(g)*P(b)*P(g)*P(g) = 1/2 * 1/2 * 1/2 * 1/2 *1/2 = 1/32 =0.03125.